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The IIT Foundation Series class 7

Trishna Knowledge Systems

A division of

Triumphant Institute of Management Education Pvt. Ltd.

Assistant Production Editor: Akanksha Joseph

The aim of this publication is to supply information taken from sources believed to be valid and reliable. This is not an attempt to render any type of professional advice or analysis, nor is it to be treated as such. While much care has been taken to ensure the veracity and currency of the information presented within, neither the publisher nor its authors bear any responsibility for any damage arising from inadvertent omissions, negligence or inaccuracies (typographical or factual) that may have found their way into this book.

Copyright © 2012 Dorling Kindersley (India) Pvt. Ltd.

Licensees of Pearson Education in South Asia

This eBook is licensed subject to the condition that it shall not, by way of trade or otherwise, be lent, resold, hired out, or otherwise circulated without the publisher’s prior written consent in any form of binding or cover other than that in which it is published and without a similar condition including this condition being imposed on the subsequent purchaser and without limiting the rights under copyright reserved above, no part of this publication may be reproduced, stored in or introduced into a retrieval system, or transmitted in any form or by any means (electronic, mechanical, photocopying, recording or otherwise), without the prior written permission of both the copyright owner and the above-mentioned publisher of this book.

This eBook may or may not include all assets that were part of the print version. The publisher reserves the right to remove any material present in this eBook at any time, as deemed necessary.

ISBN 9788131763131

e-ISBN 9789332513167

Head Office: A-8(A), Sector 62, Knowledge Boulevard, 7th Floor, NOIDA 201 309, India

Registered Office: 11 Local Shopping Centre, Panchsheel Park, New Delhi 110 017, India

Compositor: AGWAYS Publishing Services, Chandigarh

Preface

As the old adage goes, “nothing succeeds like success.” The truth in this maxim cannot be overstated in today’s competitive world. The present-day student is under immense pressure to thrive and emerge triumphantly in examinations. Students aspire to get into pre-eminent educational institutes to pursue the best courses–be it in engineering, medicine, arts or sciences–to enable them to prepare for careers at the global level. Their performance in entrance examinations are often the cornerstones that determine if they would be admitted into these hallowed halls of learning.With most of these exams being designed to challenge the innate talent and ingenuity of students, it is only natural that they find these tests most demanding and that they find themselves competing with the country’s best minds for those few coveted seats. Only those students with a thorough understanding of the fundamental concepts and exceptional problem-solving skills pass out with flying colours in these tests.

The “IIT Foundation Series” books are designed to provide students with a comprehensive understanding of the fundamental concepts, to teach them the application of these concepts and to hone their problem-solving skills.

The objective of the IIT Foundation Series books is to ensure that students are able to delve beyond the restrictions of their regular school syllabus and get a fundamental understanding of Mathematics, Physics and Chemistry. The books are designed to kindle student interest in these subjects and to encourage them to ask questions that lead to a firm grip on the principles governing each concept.

Irrespective of the field of study that the student may choose to take up later, it is imperative that he or she develops a sound understanding of Mathematics and Science, since it forms the basis for most modern-day activities. Lack of a firm background in these subjects may not only limit the capacity of the student to solve complex problems but also lessen his or her chances to make it into top-notch institutes that provide quality education.

This book is intended to serve as the backbone of the student’s preparation for a range of competitive exams, going beyond the realms of the usual school curriculum to provide that extra edge so essential in tackling a typical question paper.

A distinctive feature of this book is that it has been written by a team of well-qualified teachers experienced in imparting the fundamentals of Mathematics and Science, and their applications to active learners at T.I.M.E. (Triumphant Institute of Management Education Pvt. Ltd). They have also been instrumental in developing high-quality study material for IIT Foundation courses for Classes 7 to 10. We are sure that you will find this book, prepared by such stalwarts, to be very useful in your preparation for entrance examinations.

About the IIT Foundation Series

This book is a perfect companion not only for the students of 7th Grade, but also for higher grades. It will help them achieve the much-needed conceptual clarity in the topics which form the basis for their higher study.

Some of the important features of the book are listed below:

• Builds skills that will help students succeed in school and various competitive examinations.

• The methodology is aimed at helping students thoroughly understand the concepts in Mathematics, Physics and Chemistry.

• Helps develop a logical approach to Mathematics, Physics and Chemistry, thereby enabling more effective learning.

• Lays stress on questions asked by board/school examinations as well as application of concepts.

• The concepts are explained in a well structured and lucid manner, using simple language. This aids learning.

• A large number of examples have been included to help reinforce the concepts involved.

• Different levels of practice exercises have been provided which help students develop the necessary application and problem-solving skills.

• The exercises have been designed keeping in mind the various board/school examinations and competitive examinations, such as the NTSE, NLSTSE, Science Olympiad and Cyber Olympiad.

• The book will not only help the students in better understanding of what is taught in regular school classes (and hence enable them to do well in board examinations) but will also help in developing the acumen, resulting in a distinctive edge ovr their peers.

• Given below are a few examples that demonstrate how the course will help students in understanding the fundamentals:

How does a kingfisher catch fish?

The kingfisher flies vertically over the position of the fish, then plunges into the water at a 900 angle. The concept here is that the normally incident rays do not undergo refraction, hence the fish lies exactly where it appears to be. At any other angle, the apparent location of the fish would be different from its real location.

Why do we normally swing our arms while walking, and why not when we carry a load in our hands?

The center of gravity of a body depends on the distribution of mass in the body. As we walk, the movement of the legs tends to cause a shift in the centre of gravity. To compensate for this shift we swing our arms. When we are carrying a load in the hands, however, the effective C.G is lower, making it easier to maintain balance.

Why does salt become damp when kept exposed during the rainy season and not when kept exposed during summer?

In the rainy season humidity in the atmosphere is very high, i.e., there is a lot of moisture in the atmosphere. Thus, calcium chloride, which is the impurity present in common salt, absorbs this moisture and makes the salt damp. In summer, however, as the temperature is high, calcium chloride tends to loose moisture through the process of evaporation, and the salt is left free-flowing.

Structure of the IIT Foundation Series

The IIT Foundation Series is available in Mathematics, Physics and Chemistry. Each chapter in the book is divided into three parts, namely, theory, test your concepts and concept application.

➤ Theory:

The theory part deals with the various concepts in Physics/Chemistry/Mathematics, which is a part of the syllabus prescribed by major boards for Class X. The concepts are explained in a lucid manner, and diagrams have been provided, wherever necessary, to illustrate these concepts.

➤ Test your Concepts:

This exercise is provided at the end of the theory section of each chapter. These exercises are a collection of very short answer, short answer and essay type of descriptive questions. It is intended to provide students with model questions that they may face in the board examination.

Students are expected to prepare for these questions before they attempt any examination based on that particular chapter. Towards the end of the book, the students will find key points for selected questions of the exercise. These key points provide students with an idea of the points that should be a part of an answer for such a question.

➤ Concept Application:

This is a collection of exercises in four different classes: Class 7, Class 8, Class 9 and Class 10.

Class 8 consists of basic objective questions. These questions test the basic knowledge of students and enable them to gauge their understanding of concepts when they start solving this exercise. The key for this exercise is provided at the end of the respective chapter.

Classes 9 and 10 consist of descriptive questions of a higher level of difficulty. These questions help students to apply the concepts that they have learnt. Key points for selected questions of these exercises have been provided at the end of each chapter in order to help students solve these questions.

These books are available for 7th, 8th, 9th and 10th classes separately for Mathematics, Physics and Chemistry.

Series Content List

Class 7

Chapter 1 Measurements

Chapter 2

Kinematics

Chapter 3

Heat

Chapter 4

Light

Chapter 5

Sound

Chapter 6

Electricity

Chapter 7

Machines and Tools

Chapter 8

Our Universe

Class 8

Chapter 1

Measurements

Chapter 2

Kinematics

Chapter 3

Dynamics

Chapter 4

Hydrostatics

Chapter 5

Wave Motion and Sound

Chapter 6

Heat

Chapter 7

Light

Chapter 8

Electricity

Chapter 9

Magnetism

Chapter 10

Electromagnetism

Chapter 11

Sources of Energy

Class 9

Chapter 1

Measurements

Chapter 2

Kinematics

Chapter 3

Dynamics

Chapter 4

Simple Machines

Chapter 5

Gravitation

Chapter 6

Hydrostatics

Chapter 7

Heat

Chapter 8

Wave Motion and Sound

Chapter 9

Light

Chapter 10

Electricity

Chapter 11

Magnetism

Chapter 12

Modern Physics

Class 10

Chapter 1

Kinematics

Chapter 2

Dynamics

Chapter 3

Heat

Chapter 4

Light

Chapter 5

Hydrostatics

Chapter 6

Wave Motion and Sound

Chapter 7

Electricity

Chapter 8

Electromagnetism

Chapter 9

Modern Physics

Chapter 10

Sources of Energy

Chapter 11

Electronics

This page is intentionally left blank

Measurements 1

IntroductIon

What is physical science?

The word science means to know. It is derived from Latin word “scire”. The Science attempts to know the unknown and during this process great discoveries are made. Physical sciences deal with the study of inanimate objects in nature. Physics and chemistry are its main branches.

Physics deals with the properties of matter. For example, it talks about how dense and elastic a matter is. It deals with external behaviour of matter. For example, how a matter behaves when force is applied on it. It also deals with interaction between matter and energy.

Physics explains the day-to-day phenomena happening around us. It explains, why lightning occurs during rainy days. Why we wear light coloured cotton clothes in summer and woollen clothes in winter. It also helps us to know the working of various electrical devices such as incandescent bulb, fluorescent tubes, electric motors and how X-rays can be used to detect fracture in a bone. It explains how ventilation in a room is achieved. Chemistry deals with transformation of substances. It classifies the substances into elements and compounds. It studies the process involved when compounds are formed from elements. It also studies the decomposition of compounds into simpler substances.

Method of application of science: Science attempts to find the cause of an event. This is called the aim. To achieve this aim, various phenomena taking place in inanimate and living world are observed. The reasons behind a given phenomenon is determined and its correctness is verified in different situations. The science is applied through the following steps.

Aim: A phenomenon is chosen to determine its cause.

Observation: It involves noticing the phenomenon attentively in different conditions. For observation, sense organs as well as different instruments are used. In most cases, a phenomenon similar to the one observed in nature is created in the laboratory, which is called an experiment.

Measurement: It involves a comparison with a standard measure known as unit. There are two systems of standard units, one is CGS (centimetre, gram, second) and the other is SI system (System International). In CGS system, the unit of length, mass and time is centimetre (cm), gram (g) and second (s) respectively, and in SI system they are measured in meter (m), kilogram (kg) and second (s) respectively.

Measurement of volume: The volume of a body is the space occupied by it. The volume of regular shaped solid bodies can be determined easily by applying appropriate formula. For determining the volume of an irregular solid, a measuring cylinder is used. The measuring cylinder is also used to measure the volume of a liquid.

A measuring cylinder is a cylindrical vessel with graduations in millilitre or cubic centimetre. In order to measure the volume of a given liquid, it is poured in an empty cylinder and the marking corresponding to the upper surface of the liquid is noted, which gives the volume of the liquid.

The volume of an irregular shaped solid can be determined by immersing it into water, contained in a measuring cylinder. For example to measure the volume of a stone, the stone is tied with the thread and is lowered into the measuring cylinder. The water level rises. The volume of the stone equals the difference between the volume of water before and after the stone is immersed.

Systematization: After measuring the physical quantities, they are arranged in a specific way. This is called systematization. A conclusion is then drawn after studying the measurements, which is called inference. The following table gives the CGS and SI units of some of the physical quantities.

Area Square centimetre (cm2)

Volume Cubic centimetre (cm3 or cc)

Density gram per cubic centimetre (g cm–3)

Velocity or speedcentimetre per second (cm s–1)

Acceleration centimetre per second per second (cm s–2)

Square metre (m2)

Cubic metre (m3)

kilogram per cubic metre (kg m–3)

metre per second (m s–1)

metre per second per second (m s–2)

Force dyne newton (N)

Weight gram weight (gwt) or gram force (gf)

Pressure

dyne per square centimetre (dyne cm–2) or gram weight per square centimetre (gwt cm–2)

kilogram weight (kgwt) or kilogram force (kgf)

newton per square meter (N m–2) or kilogram weight per square metre (kgwt m–2)

TemperatureDegree centigrade (°C) kelvin (K)

Energy erg joule (J)

A simple example where the method of science is applied

Aim: To show that the volume of a liquid displaced by a solid, which is insoluble and completely immersed in a liquid, increases with increase in the volume of the solid.

Observation: Different objects such as stone, glass, plastic etc., of different volumes are immersed in different liquids (taken in overflowing jars) such as water, kerosene, alcohol etc. The phenomenon is observed at different places and different times.

Measurement: The displaced liquid is collected in a beaker and its volume is measured with the help of measuring cylinder.

Systematization: The volume of displaced liquid of each kind is arranged in increasing or decreasing order.

Inference: From studying the measurements arranged systematically, it is concluded that the liquid displaced by a solid increases with increase in the volume of the solid. This holds good for all kinds of liquids.

Measurement of some physical quantities

Measurement of mass: Mass is defined as the amount of matter contained in a body. In SI system, the unit of mass is kilogram (kg). The multiple units of mass are quintal and metric tonne and submultiple units are gram (g) and milligram (mg) where,

1 quintal =100 kg; 1 tonne = 1000 kg; 1 gram = 1 1000 kg

1 milligram = 1 1000 g = 1 1000000 ,, kg

Mass of a body does not change with place or time. It remains constant. Mass is measured by using a physical balance or a beam balance.

The weight of a body is the force of gravity exerted by the Earth on it. The weight of a body depends on its mass as well as acceleration due to gravity.The weight of a body changes from one place to another place as acceleration due to gravity on the Earth changes from place to place.

The weight of a body also changes with altitude as acceleration due to gravity changes with the altitude. The SI unit of weight is newton (N) and the CGS unit is dyne. One newton of force is approximately equal to the force of gravity on a body of mass 100 g. The other units of weight are called gravitational units. They are kilogram force (kgf) and gram force (gf).

One kilogram force is the force exerted by the Earth on a body of mass 1 kg. One gram force is the force exerted by the Earth on a body of mass 1 gram. The weight of a body is measured by a spring balance.

Differences between mass and weight

S.no.

1. It is the amount of matter contained in a body. It is the gravitational force exerted by the Earth on a body.

2. It is a constant anywhere in the universe. It varies according to the variation in the acceleration due to gravity.

3. Its SI unit is kilogram. Its SI unit is newton.

4. It is measured using a common balance.It is measured using a spring balance.

5. The mass of a given body cannot be zero. The weight of a body can be zero when no gravitational force acts on it.

Density: If we compare the masses of different substances of the same volume, we find the mass to be different. For example, the mass of a certain volume of iron is greater than the mass of the same volume of wood.Why is it so? This is because the atoms in iron are more densely packed than the atoms in wood. In other words, density of iron is more than the density of wood. The density is defined as the mass per unit volume of a substance. Thus

Density (D) = mass(m) volume (V) The SI unit of density is kg m–3 and CGS unit is g cm–3

Determination of density of a solid by using a measuring cylinder: Dividing the mass of a solid by its volume gives its density. The mass of a solid can be determined accurately by using a physical balance. The volume of an irregular shaped solid can be determined by using a measuring jar (cylinder).

To measure the volume of a solid, note the initial reading in the measuring jar and immerse the solid into the jar. Note down the final reading. The difference between the final and the initial readings give the volume of the solid. Divide the mass by the volume and find out the density.

Determination of density of a liquid by using a density bottle: A density bottle is a specially designed glass bottle available in different capacities. Generally, a density bottle of capacity 50 ml is used for finding the density of various liquids.

A density bottle is a long necked bottle provided with a ground glass stopper as shown in Fig 1.1.

The stopper has a capillary tube. When the bottle is filled with a given liquid and the stopper is inserted, the liquid rises through the capillary tube and overflows. This ensure the accurate volume of a liquid being taken in the density bottle, whenever it is filled with different liquids. In order to find the density of a given liquid, the density bottle is washed with the distilled water and dried in hot air. The mass of density bottle with the stopper is determined by using a physical balance. The density bottle is then filled with distilled water and the stopper is inserted. The water that overflows is wiped and the mass is determined (using a physical balance). After determining the mass of the bottle with distilled water, the distilled water is poured out and the bottle is dried in hot air. Now the bottle is filled with the liquid and the stopper is inserted. The liquid that overflows is wiped out and the mass of the density bottle, filled with the liquid is measured, using a physical balance.

We can find the mass of a liquid and the distilled water, by subtracting the mass of empty density bottle from the mass of density bottle filled with liquid and distilled water.

The volume of liquid is equal to the volume of water. Since the density of water is 1 g cm–3, its volume in CGS system is equal to its mass in CGS system.

The density of liquid can be found as follows:

Relative density = mass of liquid volume of liquid ÷ mass of water volume of water = mass of liquid mass of water

Figure 1.1

Variation in density of liquids and gases with temperature: The expansion of solids with rise in temperature is small so that it is negligible. As volume remains almost constant, the density of solid (d = m/V) does not change with minor changes in temperature (from 20 °C to 40 °C).

The liquids and gases, however, expand appreciably with a rise in temperature so that the change in their density with change in temperature is large.

Consequences of change in density of liquids with temperature: When water filled in a beaker is heated it is hot at the bottom than at the top. The hot water at the bottom, being lighter rises up and the cold water at the top, being heavier sinks in. This creates a sort of current called convection current. The liquids heat up due to convection current.

Consequences of change in density of gases with temperature: On being heated, gases behave in the same way as liquids. Convection currents are set up in gases also. The convection currents in gases are responsible for formation of the sea and the land breezes, the monsoon and the westerlies. The ventilation in a room is possible due to the convection current in the air. The convection current also explains why a flame point is in the upward direction.

the triangulation method

We use triangulation method to measure large distances such as the distance between planets and stars, width of river, height of hills etc., where survey chains or big tapes cannot be used. Such huge distances are found out by constructing triangles and therefore, this method is known as triangulation method. Let us see how the triangulation method can be applied to measure the distance between the corner of a table (A or B) and the toy placed on the table (C), as shown in the Fig 1.2.

Take a white sheet of paper and place it along the edges of the table. Now look at the toy (placed at C). Fix two pins on the paper at p1 and p2 (at the corner of table) such that the two pins and the toy are in a straight line. Remove the two pins and join p1, p2 with a straight line. Now move to the other corner of the table and place the same paper along the two edges of the table. Fix two pins (at the corner of the table) at p3 and p4 such that the two pins and the toy are in the straight line. Remove the pins and join p3 and p4. After producing, the two straight lines meet at certain point, say p as shown in the Fig 1.3.

1.2

1.3

Let the distance between A and B on the table be 1 m. Measure the distance between p1 and p3 in the diagram (Fig 1.3). Let it be 5 cm. This implies that 1 cm length in the diagram is equal to the actual distance of 20 cm. To know the distance between you (you are at p1) and the toy, measure the length p1p in the diagram. To get the actual distance, multiply the length p1p by 20 cm.

Figure
Figure

Important Points to Remember

The word science is derived from the Latin word “scire”.

Physics and chemistry are the two main branches of physical sciences.

The main steps in the method of application of science are: •

(a) aim (b) obervation (c) measurement (d) systematization (e) inference.

Volume of a body is the space occupied by it. •

A measuring cylinder is used to measure the volume of irregular solids. •

Mass is defined as the amount of matter contained in a body. •

The SI unit of mass is kg. Its CGS unit is gram (g).

The weight of a body is the force of gravity exerted by the Earth on it. •

The SI unit of weight is newton. The CGS unit of weight is dyne. •

Density is defined as the mass per unit volume of a substance. The unit of density in SI system is kg m • −3 . CGS unit is g cm−3

Density of a liquid is measured by using a density bottle.

Density of liquids and gases changes with temperature.

• width of river, height of hills etc.

Triangulation method is used to measure large distances such as distances between planets and stars,

test your concepts

Directions for questions 1 to 10: Fill in the blanks.

1. 10 g of water occupies ___________ cm3 of volume.

2. The mass of a body does not change with change in _________.

3. The CGS unit of pressure is ___________.

4. As the temperature of the gas decreases, its density __________.

5. The smallest length that can be accurately measured by using a metre scale is _____ cm.

6. Density of water is _____ than the density of cooking oil.

7. Weight of a body varies according to the variation in the ___________.

8. The CGS unit of volume is __________.

9. The density of a body is 500 kg m−3. Then its equivalent value in CGS system is _____.

10. The area of a square plot is 100 m2. Then the value of its perimeter is _________ m.

Directions for questions 11 to 29: For each of the questions, four choices have been provided. Select the correct alternative.

11. The smallest measurement that can be measured by using a wall clock is _________.

(1) 1 second (2) 1 minute (3) 1 hour (4) 2 second

12. The length and breadth of a rectangle are 2 m and 5 m respectively, the area of the rectangle is _______.

(1) 10 m2 (2) 100000 cm2 (3) 1 km2 (4) Both (1) and (2)

13. If the density of a substance is 2 × 103 kg m–3, then the mass of 5 m3 of this substance is ______.

(1) 1000 kg (2) 10000 g (3) 10000 kg (4) Both (1) and (2)

14. The mass of a body of weight 200 gf is ______ g.

(1) 200 (2) 300 (3) 400 (4) 20

15. A pile of identical one rupee coins are placed over a metre scale as shown in the figure. The thickness of a one rupee coin is ________.

(1) 1.56 mm (2) 1.56 cm

(3) 1.67 mm (4) 1.67 cm

16. 5 litre of a liquid weighs 5 kgf. The density of the liquid is ________.

(1) 1 kg m–3 (2) 1 g cm–3 (3) 100 kg m –3 (4) 100 g m–3

17. 1 kilogram is equal to _________. (1) 1000 gram (2) 100 gram (3) 1000 milligram (4) 100 milligram

18. Mass is measured by using a _________. (1) spring balance (2) physical balance (3) measuring jar (4) metre scale

19. 1 kg m–3 = _________

(1) 1000 g m–3 (2) 1 1000 g cm–3 (3) 10000 kg cm–3 (4) 1 g cm–3

20. The distance between two cities A and B in a map is 7.5 cm. The scale taken for drawing this map is 1 cm = 1,50,000 m. The actual distance between A and B is _________ km.

(1) 1125000 (2) 20000 (3) 200 (4) 1125

21. 1 m3 = ______ litre.

(1) 1 (2) 10 (3) 100 (4) 1000

22. The whole length of a metre scale is divided into 500 equal parts then the smallest measurement that can be measured by using the scale is _______.

(1) 0.5 m (2) 0.005 m (3) 50 mm (4) 2 mm

23. Which among the following is (are) the unit of pressure?

(1) N m–2 (2) gwt cm–2 (3) kgwt m–2 (4) All the above

24. Which of the following statements is/are incorrect?

(1) The weight of a body can be zero.

(2) The weight of a body can be greater than zero.

(3) The mass of a body can be zero.

(4) Both (1) and (3)

25. Volume of an irregular shaped solid can be measured by using a ________.

(1) density bottle (2) spring balance

(3) measuring cylinder (4) physical balance

26. Which of the following statements is incorrect?

(1) As the temperature of a gas increases, its volume increases.

(2) As the temperature of a gas increases, its density decreases.

(3) As the temperature of a gas increases, its density increases.

(4) Both (1) and (3)

27. An atlas of a country is shown in the figure, the distance between cities A and B is ______. (1) 35 km (2) 3500 m (3) 350 km (4) Both (1) and (2)

28. Arrange the following steps in a sequence to find the volume of an irregular shaped solid body.

(a) The irregular shaped solid is tied with the thread and is lowered into the measuring cylinder.

(b) A measuring cylinder with graduations in millilitre or cubic centimetre is taken.

(c) The level of water in the measuring cylinder rises after immersion of the solid. (say V2).

(d) First, it is filled with water to a certain level or volume. (say V1).

(e) The volume of the stone is equal to the difference between the volume of the water before and after the immersion of the stone. (V2 – V1).

(1) abcde (2) bcade (3) bdace (4) edacb

29. Density of the material of a paper is given as 0.5 g cm−3. The mass of the paper is 1 g and its length and breadth are 10 cm and 5 cm respectively. Arrange the following steps in a sequence to find the thickness of the paper.

(a) The thickness of the paper is = volume (V)ofthe paper length breadth ×

(b) The density (d) of the material of the paper is = mass of thepaper(m) volume of thepaper(V)

(c) Then the volume (V) of the paper = mass of thepaper (m) density(d) of thepaper

(d) The volume (V) of the paper is = length × breadth × thickness of the paper.

(1) abcd (2) badc (3) abdc (4) bcda

Directions for questions 30 to 32: Match the entries given in column A with the appropriate ones in column B. 30.

column A

column B

A.Science ( )a.Gravitational pull by Earth

B. The volume of cube of side ‘S’ ( ) b. Due to convection current

C. CGS unit of temperature ( ) c. The atoms packed within the substance

D. Density of liquid ( )d.Latin word “Scire”

E.Weight ( ) e. S3

F. Liquids heat up ( ) f.

Mass of liquid of volume V

Mass of water of same v olume V

G. The difference in densities of substances( )g.Degree centigrade (°C)

column A

A.1 g cm–3

column B

( )a.1000 kg m−3

B. Convection current ( ) b. cm3

C. Volume

( ) c. Measurement of large distances

D. Triangulation method( )d.Mass/volume

E.Mass ( ) e. Change in density

F. Density ( ) f. kg

column A

A.Physics

B. X-rays

C. Aim of science

column B

( )a.To detect fracture in a bone

( ) b. 1000 litres

( ) c. Weight of body of mass 10−3 g

D. The volume of 1 m3 is( )d.Triangulation method

E.1 dyne

( ) e. Convection current in air

F. Ventilation in a room( ) f. Deals with interaction between matter and energy

G. The distance between the moon and the Earth ( )g.To find cause of an event

Very short answer type questions

33. What is the meaning of the word science?

34. Express the density 2 g cm–3 in SI system.

35. How does the density of a solid change with minor changes in temperature?

36. Name the device used to measure the volume of an irregular solid.

37. How is the volume of a regular solid determined?

38. What is the consequence of change in density of liquids with temperature?

39. Name the method used to measure the distance between stars.

40. Define one kilogram weight.

41. Define one gram force.

42. Will mass of the solid body changes with change in its volume?

43. What is a convection current? When is it formed?

44. What are the common multiple and submultiple units of mass? Express them in terms of kg.

45. Write CGS units of area, force, temperature and heat.

46. What are the main branches of physical sciences?

47. Name the steps through which science is applied.

48. What causes the formation of the land and sea breezes?

49. How does the weight of a body change with the change in altitude?

50. Convert 1 m s−2 into cm s−2.

51. Why is the density of solid remains constant for minor changes in temperature?

52. What is systematization?

Short answer type questions

53. The mass of a bottle filled with water is found to be 150 g. The mass of the empty bottle is 50 g and the external volume of the container is 125 cm3. Find out the density of the material of the bottle.

54. Ten identical metallic balls of density 5 g cm–3 when dropped into water, the volume of the water displaced is found to be 500 cm3. Determine the mass of each metallic ball.

55. When 20 drops of water is added to a graduated cylindrical container filled with water, the level of the liquid rises from 10 ml to 20 ml. Calculate the mass of each water drop.

56. The density of a substance is 5 kg per litre. Express it in g cm–3

57. Give few examples from day to day life, where physics is employed.

58. How is the volume of an irregular shaped solid determined? Explain.

59. A density bottle weighs 100 g when filled with liquid and 80 g when filled with water. If the weight of an empty density bottle is 20 g, find the density of the liquid.

60. The volume of mercury and water is 50 ml each. What is the ratio of their mass, if their densities are in the ratio 68 : 5?

61. Find the density of cuboid of dimensions 3 cm × 5 cm × 7cm and having mass 1 kg in SI system.

62. Is it possible to find density of a given liquid using a density bottle of unknown capacity and physical balance? Explain.

63. What are the uses of triangulation method?

64. Explain how the ventilation in a room is possible.

65. Explain why a flame point is in the upward direction.

66. Find the mass of 1 m3 of gold in kg when density of gold is 19 g cm–3

67. If 5 kg of glycerine occupies 0.004 m3. Determine the density of glycerine in g cm–3 and kg m–3

68. Take two cubes each of side 4 cm made up of iron and aluminium. Why is there difference in masses of two spheres inspite of having same volume?

Essay type questions

69. Explain the steps through which science is applied.

70. Describe how triangulation method is used to measure large distances, by taking suitable example.

71. With the help of suitable example, explain how science is applied.

72. When half of the total volume of an empty beaker of mass 100 g is filled with water, its mass is found to be 500 g and when the remaining volume of the beaker is filled with a liquid, its mass is found to be 1 kg. Calculate the density of the liquid.

73. Bring out the differences between the mass and the weight of a body.

74. What is a density bottle? Explain how it is used to determine the density of a liquid.

75. Test tube ‘A’ contains 10 ml of liquid ‘X’ and test tube ‘B’ contains a liquid ‘Y’ of volume 50 ml. The ratio of the density of ‘Y’ to ‘X’ is 2 : 5. Compare the mass of liquids A and B.

76. Write CGS unit and SI unit for given following physical quantities:

(a) Area (b) Volume (c) Density (d) Velocity or Speed

(e) Acceleration (f) Force (g) Weight (h) Pressure

(i) Temperature (j) Energy

concept application

Concept Application Level-1

Directions for questions 1 to 7: State whether the following statements are true or false.

1. SI unit of volume is cubic metre.

2. 1 ml = 1000 cm3

3. Mass of a given substance does not change with change in position or location.

4. SI unit of weight is Newton.

5. Mass of a body cannot be zero.

6. As the temperature of gases increases its density also increases.

7. kg l 1 is a unit of density.

8. Triangulation method is used for measuring very long distances.

9. Density of kerosene is less than the density of water.

Directions for questions 10 to 17: Fill in the blanks.

10. The method of measuring distance by forming a _______ is called the triangulation method.

11. SI unit of area is __________.

12. SI unit of density is _________.

13. The weight of a body can be zero when ________ acts on it.

14. The SI unit of energy is _________.

15. Mass of 1 ml water is ________ g.

16. _______ is the force with which the earth pulls a body towards its centre.

17. Density of a liquid can be measured by using _______.

Directions for questions 18 to 38: For each of the questions, four choices have been provided. Select the correct alternative.

18. An atlas of India is drawn by taking scale 10 cm = 15000 km. If the actual distance between the cities of Bhopal and Cochin is 1500 km, the distance between the two places in the atlas will be _____ cm.

(1) 102 (2) 1 (3) 10000 (4) 1000

19. Sea breeze is due to the change in density of air with ____.

(1) change in temperature

(3) change in wind

20. The density of liquid can be measured by using a _____.

(1) spring balance

(3) density bottle

21. The area of a circle whose radius is 10 cm is ______.

(2) change in pressure

(4) change is whether condition

(2) measuring cylinder

(4) physical balance

(1) 314 cm2 (2) 314 m2

(3) 3.1415 m2 (4) Both (1) and (2)

22. If the area of a square field is 100 cm2 then the length of the side is ________.

(1) 1 cm (2) 1 m (3) 0. 1 m (4) 10 m

23. Density of water at 4 °C is _________.

(1) 1 g cm–3 (2) 100 kg m–3 (3) 1000 g cm–3 (4) 1 kg m–3

24. Which among the following is the unit of density?

(1) kg m–3. (2) g m–3. (3) kg cm–3. (4) All the above

25. Unit of weight is (are) _______.

(1) N (2) g f (3) kg f (4) All the above

26. A ball is placed between two wooden blocks as shown in the figure. The volume of the sphere is ________.

(1) 6.54 cm3

(2) 1.15 cm3

(3) 2.14 m3

(4) 2.14 cm3

27. The density of a substance in CGS system is 4 g cm–3. Its density in SI system is ___ kg m–3.

(1) 4 (2) 40 (3) 400 (4) 4000

28. The volume of a body having density 1 g cm–3 and mass 100 g is _______ cm3 (1) 100 (2) 50 (3) 1 100 (4) 1 50

29. A cylinder of height 1 m and radius 10 cm is fully filled with water, the volume of water is ______ m3 (1) 3.14 (2) 0.314 (3) 0.0314 (4) 314

30. 1000 kg of water occuplies

(1) 1 l (2) 0.5 l (3) 1000 l (4) 0.75 Kl

31. 1 hectare = ______ m2 (1) 102 (2) 103 (3) 104 (4) 105

32. 1 kg m–3 = _____ g cm–3 (1) 100 (2) 1/100 (3) 1000 (4) 1/1000

33. If the smallest measurement that can be measured by using scale is 0.1 mm, then the length of 1 m in the scale is divided into ____ equal parts.

(1) 1000 (2) 5000 (3) 10000 (4) 50000

34. Which of the following scale gives more accurate reading?

(1) One metre in a scale is divided into 1000 equal parts.

(2) One cm in a scale is divided into 100 equal parts.

(3) One mm in a scale is divided into 2 equal parts.

(4) One mm in a scale is divided into 5 equal parts.

35. Which among the following is the unit of heat?

(1) Calorie (2) Kelvin (3) Degree centigrade (4) All the above

36. Which of the following statement is wrong?

(1) The mass of a body can be measured by using a beam balance.

(2) The weight of a body can be measured by using a spring balance.

(3) The mass of a body can be measured by using a spring balance.

(4) The weight of a body cannot be measured by using a beam balance.

37. The width of a stream is determined with the help of triangulation method. Arrange the following steps in a sequence to explain the process to find the width.

(a) Fix a certain stationary object like tree on the other bank of the stream.

(b) Take two pins (P1 and P2) and fix P1 and P2 at one vertex of the drawing board such that pins and tree are on the same straight line.

(c) Select two positions (say A and B) on the ground and the horizontal distance between them is noted. Let it be ‘D’ m.

(d) Repeat the same process at position “B” with other two pins (P3 and P4) at other vertex of the drawing board.

(e) Take a drawing board and paste a white paper on it.

(f) Fix the board at position “A” such that one edge is directed along “AB”.

(g) Now, produce two straight lines and let them meet at point ‘P’. Complete the triangle with P, P1 and P3 Measure the distance between P1 and P3 say “d”. Then D d gives the actual distance on ground for every one cm on the drawing board.

(h) Now the width of the river will be equal to the distance from midpoint of P1 and P3 (let it be P5) and P multiplied by D d .

(1) eacfbdgh

(3) edcbafgh

(2) eabcdfhg

(4) abcdefgh

38. A density bottle weighs 120 g and 100 g when filled completely with oil and water respectively. If the weight of an empty density bottle is 40 g, then arrange the following steps in sequence meant to solve the problem to get the density of oil.

(a) The density of the oil, D = mass of theoil volume of theoil = mass of theoil mass of thewater = weight ofoil weight of thewater = W-W W-W 31 21

(b) Let the weight of the bottle + oil = W3 = 120 g and the weight of the bottle + water = W2 = 100 g. Where, bottle is completely filled with liquid i.e., oil or water.

(c) Let the weight of the empty bottle = W1 = 40 g

(d) Then the weight of the oil and water would be equal to (W3 − W1) and (W2 − W1) respectively.

(1) cbda

(3) badc

(2) abcd

(4) dcba

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