The First Order Stark Effect in Hydrogen for n=3

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The First Order Stark Effect In Hydrogen For n = 3 Johar M. Ashfaque University of Liverpool

May 11, 2014

Johar M. Ashfaque

String Phenomenology


Introduction

I will briefly mention the main result that was covered in my undergraduate dissertation titled “Time-Independent Perturbation Theory In Quantum Mechanics�, namely the first order Stark effect in hydrogen.

Johar M. Ashfaque

String Phenomenology


What is the Stark Effect? The splitting of the spectral lines of an atom in the presence of an external electric field is known as the Stark effect. Table shown below, corresponding to the Stark effect in the hydrogen atom provides a summary in the case of n = 2, 3, and 4: n

l

m

Matrix

Total Elements

2 3 4

0, 1 0, 1, 2 0, 1, 2, 3

0, ±1 0, ±1, ±2 0, ±1, ±2, ±3

4×4 9×9 16×16

16 81 256

Off-Diagonal Elements By Symmetry 6 36 120

Table: Stark effect corresponding to the cases where n = 2, 3, and 4.

Johar M. Ashfaque

String Phenomenology


The Case: n = 3 For n = 3, the degeneracy of the energy level of the hydrogen atom is 9. We can see this degeneracy more clearly in the form of nlm representation as 300,

310,

320,

311,

321,

31-1,

32-1,

322,

32-2,

where l = 0, 1, 2 and m = 0, ±1, ±2. We conclude that we are dealing with a 9 × 9 matrix and set out to compute the elements of this matrix. Due to symmetry, we only need to compute n2 (n2 − 1) 2 off-diagonal elements. In our case, we need to compute only 36 off-diagonal elements. Johar M. Ashfaque

String Phenomenology


The Case: n = 3 Contd.

Definition The perturbation produced by the electric field ξ = (0, 0, ξ) is Ĥ 0 = eξz = eξr cos(θ) where e is the electron charge. It is clear, that the eξz has odd parity since eξr cos(π − θ) = −eξr cos(θ).

Johar M. Ashfaque

String Phenomenology


The Case: n = 3 Contd. Denote the 9 states as ψ300 , ψ310 , ψ320 , ψ311 , ψ321 , ψ31−1 , ψ32−1 , ψ322 , ψ32−2 . Definition A general matrix element is defined as D

E

nlm Ĥ 0 n0 l 0 m0

ZZZ =

=

∗ r 2 dr sin(θ)dθdφψnlm r cos(θ)ψn0 l 0 m0

Z

r 3 drRnl (r )Rn0 l 0 (r ) ZZ 0 ∗ 0 (θ, φ) sin(θ) cos(θ)dθdφYlm (θ, φ)Ylm Z ∞ Z π eξ r 3 drRnl (r )Rn0 l 0 (r ) sin(θ) cos(θ)dθ 0

=

0

0 2π

Z

dφYl

m∗

m0

(θ, φ)Yl 0 (θ, φ).

0

Johar M. Ashfaque

String Phenomenology


The Case: n = 3 Contd. Definition The integral Z

r 3 drRnl (r )Rn0 l 0 (r )

0

is the radial part. Definition The integral Z π

Z sin(θ) cos(θ)dθ

0

0

0

dφYlm ∗ (θ, φ)Ylm 0 (θ, φ)

is the angular part. The integral over all space of any odd function is zero. Johar M. Ashfaque

String Phenomenology


The Case: n = 3 Contd.

The integral, as n = 3 is constant, gives Z 0

∞

r 3 drRnl (r )Rn0 l 0 (r ) =

Z 0

∞

( 0, if l = l 0 , r 3 drR3l (r )R3l 0 (r ) = K , if l 6= l 0

where K is a constant to be determined.

Johar M. Ashfaque

String Phenomenology


The Radial Wave Function Plots Of The Hydrogen Atom Maple plots of the radial wave function |rR(r )|2 for the hydrogen atom for n = 3 and l = 0, 1, 2 are presented:

R30

R31

R32

Figure 9: Maple plots of the radial wave function |rR(r )|2 , for the hydrogen atom for n = 3 and l = 0, 1, 2. Johar M. Ashfaque

String Phenomenology


The Probability Density Plots Of The Hydrogen Atom Maple plots of the probability density |ψ|2 in polar coordinates, for the normalized wave-functions of the hydrogen atom for n = 3 with Z = 1 are presented:

ψ310

ψ31±1

ψ320

ψ32±1

Figure 10: Maple plots of the sections through the probability density |ψ|2 in polar coordinates, for the normalized wave-functions of the hydrogen atom, illustrating the relative probability of finding the electron at a given distance r /a. Johar M. Ashfaque

String Phenomenology


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