PHYSICS JEE-MAIN (JulyAttempt) 27 July (Shift-1) Paper Solution one V = rdm At =KAd du didO is
1. A torque meter is calibrated to reference standards of mass, length and time each with 5% accuracy. After calibration, the measured torque with this torque meter will have net accuracy of : (A) 15 % (B) 25 % (C) 75 % (D) 5%Dimension oftorque -> *" loox A = (1+ + 21L + 21) x100; -> 5%.+ 2 (5%) +25%) -> I5
A bullet is shot vertically downwards with an initial velocity of 100 m/s from a certain height. Within 10s, the bullet reaches the ground and instantaneously comes to rest due to the perfectly inelastic collision. The velocity-time curve for total time t = 20s will be : (Take g = 10m/s2).
will
inelastic collision
2.
= velocity of bullet after 20 sec IOS 20S. f v = 100 x 510) ( 10) I > 200 mt/sec -loom;" After
ball
stick to ground. I 200 m51
3. Sand is being dropped from a stationary dropper at a rate of 0.5 kgs–1 on a conveyor belt moving with a velocity of 5 ms–1. The power needed to keep the belt moving with the same velocity will be : (A) 1.25W (B) 2.5W (C)6.25W (D)25.5W -I M= 0.5kg/see 0 0.0 0 F = of from equation o = Vam - Er.am = V" dm = (5)" (0.5) = 12.5 watt
4. A bag is gently dropped on a conveyor belt moving at a speed of 2 m/s. The coefficient of friction between the conveyor belt and bag is 0.4. Initially, the bag slips on the belt before it stops due to friction. The distance travelled by the bag on the belt during slipping motion, is : [Take g = 10 m/s–2] (A) 2m (B)0.5m (C)3.2m (D)0.8mshung-ma a = ug v= U" + 2 q (s) 10) =(2)" 2 (mg) S. S: tas= Ax 2 COY) (Io = 05mt
5. Two cylindrical vessels of equal cross-sectional area 16 cm2 contain water upto heights 100 cm and 150 cm respectively. The vessels are interconnected so that the water levels in them become equal. The work done by the force of gravity during the process, is [Take, density of water = 103 kg/m3 and g = 10 ms–2] : (A) 0.25J (B)1J (C)8J (D)12J ⑱ W 150cm) 3 100 cmr M. ISABx 16 x 150x102.nkg mu =S(A) (l) = 103x16 x 100 -> lokg WINMM* 2kg.v i= mgt)comtMgRaCom. US = (M) gC2)Om) X2. =24x10x15 + 10 x 10 x 10 =2x2 x10 x 12.5=253 Worldone by the gravity = DV=-Uf + UC 25+ 26 = 15
41im
ITE) A MA Us
ITE) B MB UA
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Now let us talk about the students who are preparing for NEET and their aim is to take admitted to Government Medical colleges in Delhi, which All India Institute of Medical Science Medical College New Delhi, Maulana Azad Medical College New Delhi, Vardhman Mahavir Medical College New Delhi, University New Delhi, Lady Hardinge Medical College for Women New Delhi, Army College of Medical Sciences New Delhi Jamia Hamdard New Delhi, Guru Gobind Singh Indraprastha University Delhi, Jamia Millia Islamia New Delhi, Dr Ram Manohar Lohia Hospital and Postgraduate Medical Education and Research, Sahib Ambedkar Medical College and Hospital New Delhi, NDMC Medical College New Delhi, Maulana Azad Institute of Dental Sciences New Delhi are included.
Now let's talk about the students who want to take admitted to all these medical schools and are residents of Delhi, then they have an 85% quota in these Delhi medical colleges and the students of Delhi should take advantage of this 85% reservation.
Now let's talk about how to prepare for the NEET exam As you all know that in the NEET exam physics, chemistry and zoology, botany comes in which chemistry, botany, ZOOLOGY comes from NCERT but students face problem in physics. Physics never comes directly from NCERT and students face a lot of problems in physics because many medical students whose maths is weak don't understand physics much and finally because of physics in their NEET exam their score reduces.
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6. Two satellites A and B, having masses in the ratio 4:3, are revolving in circular orbits of radii 3r and 4r respectively around the earth. The ratio of total mechanical energy of A to B is : (A) 9:16 (B)16:9 (C)1:1 (D)4:3
a TF
- **9
7. If K1 and K2 are the thermal conductivities, L1 and L2 are the lengths and A1 and A2 are the cross sectional areas of steel and copper rods respectively such that K2/k1 = 9, A1/A2 = 2, L1/L2 = 2. Then, for the arrangement as shown in the figures, the value of temperature T of the steel - cooper junction in the steady state will be : (A) 18°C (B)14°C (C)45°C (D)150°C=450°C =00C =KoAnSYo-T) = kz A, 2o 12 Kuan (50 -TC=K2 As (700) lo 12 so-- K2AzlI = (9) (F) (44) Ks All. 450-7=97-450 = 107 += 450C
8. Read the following statements : A. When small temperature difference between a liquid and its surrounding is doubled, the rate of loss of heat of the liquid becomes twice. B. Two bodies P and Q having equal surface areas are maintained at temperature 10° C and 20° C. The thermal radiation emitted in a given time by P and Q are in the ratio 1 : 1. 15. C. A Carnot Engine working between 100K and 400K has an efficiency of 75% D. When small temperature difference between a liquid and its surrounding is quadrupled, the rate of loss of heat of the liquid becomes twice. Choose the correct answer from the options given below : (A) A, B, C only (B) A, B only (C) A, C only (D) B,C,D Only(A) GK (T-To) here T -To =DT CKDP If it is twice then do will be 2 times. (B) FCT6, 1 = 173+10)= Gzos.0.92. (273 +20) 4 () 4=7.= 1.10= *4% = x100 75% (PC CDT TATENANT A @@ correct
Same gas is
The
The
in two
of gas
the
the
the
of the
of
The ratio of
The
the
9.
filled
vessels of
same volume at
same temperature. If
ratio
number of molecules is 1 : 4, then A.
r.m.s. velocity
molecules in two vessels will be the same. B.
ratio
pressure in these vessels will be 1 : 4. C.
pressure will be 1 : 1. D.
r.m.s. velocity of gas molecules in two vessels will be in the ratio of 1 : 4. Choose the correct answer from
options given below : (A) A and C only (B) B and D only (C) A and B only (D) C and D onlyT, V T,V No N2 ⑱ A B (A) -> Orms =to -> Orms same B) Ocu O.C. NNA A M -St AB.
10. Two identical positive charges Q each are fixed at a distance of ‘2a’ apart from each other. Another point charge q0 with mass ‘m’ is placed at midpoint between two fixed charges. For a small displacement along the line joining the fixed charges, the charge q0 executes SHM. The time period of oscillation of charge q0 will be : ⑭ ⑭ ⑭#> fn Q ① e.iit" @@ FNet = f2 -f. " =k9&19Q=499 lanes" cate) " ((a+a): (a-2e)2. 192-193) 2 A: -voice= 198 (49x) >>CC. m (A) (9"-18)2 A k90 54qx) -traces, as *m cures a " a4 W" te s = Pr T= 44" ma3 to 9 R.
11. Two sources of equal emfs are connected in series. This combination is connected to an external resistance R. The internal resistances of the two sources are r1 and r2 (r1 > r2). If the potential difference across the source of internal resistance r1 is zero, then the value of R will be : (A) r1 –r2 (B) r1r2 (C)r1+r2 (D)r2–r1 filz Mntri VAB = F JUn N. ↑ I onsider Mesh NKLHN ↑ RHIU. -E+1U -F=0 K L ↑ a 2 E Rt Up tUr 2VAB =0 = > E Un - E( + UntUz I RtUetUnow,so &= UntU2 0 R = VC-Un
12. Two bar magnets oscillate in a horizontal plane in earth’s magnetic field with time periods of 3s and 4s respectively. If their moments of inertia are in the ratio of 3 : 2, then the ratio of their magnetic moments will be : (A) 2:1 (B)8:3 (C)1:3 (D)27:16=IT H -> I = 1 = 1 => (t) E) # x Et =ExE -> x50-gy
lano Los
(tand")
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13. A magnet hung at 45° with magnetic meridian makes an angle of 60° with the horizontal. The actual value of the angle of dip is(A) tan–1 (√3/2) (B) tan–1(√6) (C) tan–1 (√2/3) (D) tan–1 (√1/2)
⑮ tand' =
O tano =
(00) d ↑RVE A POA RENT ANGL of ANGLG a O of DDO tan8 = ran(60%) Cos 450 3/52 = 731 d = tai' (51)
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14. A direct current of 4 A and an alternating current of peak value 4 A flow through resistance of 3 and 2 respectively. The ratio of heat produced in the two resistances in same interval of time will be : (A) 3:2 (B)3:1 (C)3:4(D)4:3 Physics
Physics
Physics
Physics
· ⑧DO A @ Ro= 3-oh m 12 = 4 A (oeak) o =4 AmP I (2)oms = * = 25 A =" = F*Ro t (4) "(3) -AxesF2F Ra (t). 32 5a) " () rus
15. A beam of light travelling along X-axis is described by the electric field Ey = 900sin (t – x/c). The ratio of electric force to magnetic force on a charge q moving along Y-axis with a speed of 3 × 107 ms–1 will be : (Given speed of light = 3 × 108 ms–1) (A) 1:1 (B)1:10 (C)10:1 (D)1:2+ + N =Eo= Bo=E900 =300 x 108 3x1563x108 o -> 8 I -> 900 -900 = 10 Am qUB 3x10x3x186 90 T
16. A microscope was initially placed in air (refractive index 1). It is then immersed in oil (refractive index 2). For a light whose wavelength in air , calculate the change of microscope’s resolving power due to oil and choose the correct option.
(A) Resolving power will be 1/4 in the oil than it was in the air. 4
A N
(B) Resolving power will be twice in the oil than it was in the air.
(C) Resolving power will be four times in the oil than it was in the air.
(D) Resolving power will be 1/2 in the oil than it was in the air.
o = F= Chmed)x(xari
1) (am) tms"
&
=
--
is constant.If at t=0 de Broglie wavelength is 0 = h ,then its de Broglie wavelength after times t is given by
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17. An electron (mass m) with an initial velocity v = v0î (v0 > 0) is moving in an electric field E = E0î (E>0) where E0
⑭ a ⑭ noo Ia x = No? * = Fo > 9FO = ma, a = to 0: Ut att v = cos + efo ? (t)in 1 Ko + fot I x = "mDteenot)
half-life period of a radioactive material if its activity drops to 1/16th of its initial value in
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18. What is the
30 years ? (A) 9.5 years (B) 8.5 years (C) 7.5 years (D) 10.5 years
A no (t)"v # to (1) (1)": (1) "*4 4 total time =(9) (T) 30 =4 (T) Ys = 3015 = 7.5 years
A logic gate circuit has two inputs A and B and output Y. The voltage waveforms of A, B and Y are shown below.
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(A) AND gate (B) OR gate (C) NOR gate (D) NAND gate
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19.
P & & O : O A B Y O O O 1 N I O A O This is the a A O O true th O O ⑧ ↑ able of AN D GATE
20. At a particular station, the TV transmission tower has a height of 100 m. To triple its coverage range, height of the tower should be increased to (A) 200 m (B) 300 m (C) 600 m (D) 900 md = =I do:d 2 = 3d o = '* = L* I = a i 12 = 9x100 =900 mt
-
21. In a meter bridge experiment, for measuring unknown resistance ‘S’, the null point is obtained at a distance 30 cm from the left side as shown at point D. If R is 5.6 k , the value of unknown resistance ‘S’ will be ________ .
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SECTION - B
2.4 Kom · : => (%) (5.0km) = (5.6Kn) = 2.7k
the
of
. The one division of main scale of Vernier calipers reads 1 mm and 10 divisions of Vernier scale is equal to the 9 division on main scale. When the two jaws of the instrument touch each other, the zero of the Vernier lies to
right
zero of the main scale and its fourth division coincides with a main scale division. When a spherical bob is tightly placed between the two jaws, the zero of the Vernier scale lies in between 4.1 cm 4.2cm and 6th Vernier division coincides with a main scale division. The diameter of the bob will be ______ × 10–2 cm. 22) 412 X MSD = 1 mm IOV SD=9HSP L.D = IMSD-IVSO = 1MM -09mm = 01mm = "ON<m. Tevo evrov = 4(01mm) = 04mm=0ncm. Reading for spherical bob = main reading+h (1.a) GGROR - () + 6 (01) = on = 4+ 02 4: Cm = 412x10m
beams of light having intensities I and 4I interfere to produce a fringe pattern on a screen. The phase difference between the two beams are /2 and /3 at points A
B respectively. The difference between the resultant intensities at the two points is
The
23. Two
and
xI.
value of x wil be _____. 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24. To light, a 50 W, 100 V lamp is connected, in series with a capacitor of capacitance 50 μF, /π√x with 200V, 50Hz AC source. The value of x will be ______. ·I 3 &= 1=(00"i ceser C & NoXu *x*xE, 200-ohm = 100 volt l v=250 x 50 x 10 Sad= 200 feet / 50 Hz ① = 608=.TR tanso=1 x 100 voet U Rx (=60 I = X18E2005 X* = 200 tanso V " ->R = 2XSTos = 2005 Va C00U C=3
25. A 1 m long copper wire carries a current of 1 A. If the cross section of the wire is 2.0 mm2 and the resistivity of copper is 1.7 × 10–8 m, the force experienced by moving electron in the wire is _____ × 10–23 N. (charge on electorn = 1.6 × 10–19 C) ⑱ =23 X - 13 6 x* ⑭ & ⑪ R= Sl A 17x108 x1 = 1.7x108 2 x 156 2. v = lD = FX1" x18 = t, xio" voet E = T = 1x1 F=98, f = 16x109 x 17 x 15" > 136 x1821 : 136x1833 N
charge
density
26. A long cylindrical volume contains a uniformly distributed
of