Alpha 1 Notes Relations & Functions

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Relations & Functions

Notes # Alpha 1

Relation:

a pairing of elements of one set with elements of a second set. This is usually expressed as a set of ordered pairs.

Domain:

the set of all abscissas (the first value in the ordered pair) of the ordered pairs.

Range:

the set of all ordinates (the second value in the ordered pair) of the ordered pairs.

Function:

a function is a relation in which each element of the domain is paired with exactly one element in the range.

Ex A: State the domain and range of each relation. Then state whether the relation is a function. Circle yes or no.

#1)

{(-1, 4), (3, -5), (6, 2)}

#2)

{(0, 5), (5, 7), (-3, -6), (0, 0)}

domain =

domain =

range =

range =

Function? Yes

No

Function? Yes

Note: If an element is repeated, you need to only write it once.

No

Ex B: Given that x is an integer, state the relation representing each of the following by listing a set of ordered pairs. Then state whether the relation is a function by circling yes or no. Note: Substitute #1) y = 2x – 2 and 0 < x < 5 #2) y = 1.5x and 5 < x < 7 each number from the domain into the equation. Make sure you show all work.

Relation = Function?

Relation = Yes

No

Function?

Yes

No

Linear Relationships & Functions Page 1 of 5


Relations & Functions Function Notation: a function is commonly denoted by f. In function notation, the symbol f(x) is read “f of x”. f(x) = y, therefore the ordered pairs of a function are in the form (x, y) or (x, f(x)). Ex C: Given f(x) = |x2 – 11|, find each value.

#1)

f(0) =

#2)

f(-4) =

#3)

f(-

13 )

=

Note: You must simplify inside the absolute value before getting rid of abs value symbols.

Vertical Line Test: If every vertical line drawn on the graph of a relation passes through no more than one point on the graph, then the relation is a function. Ex D: Use a graphing calculator to determine whether each equation is a function. Note: When graphing, you must label all x- and y-int. You must also label vertices.

#1)

y = 5x2 + 1

Function?

Yes

#2)

No

y = (x – 3)½

Function?

Yes

No

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Relations & Functions

Notes # Alpha 1

Ex D: Use a graphing calculator to determine whether each equation is a function.

#3)

x2 + y2 = 49

Function?

Yes

No

Ex E: The symbol [x] means the greatest integer not greater than x. If f(x) = [x] + 6, find each value.

#1)

f(-4) =

#2)

Excluded values:

f (2.5) =

#3)

f(-6.3) =

Note: [x] basically means round down to the nearest integer.

real numbers when substituted in for “x” will give an imaginary number for “y” or be undefined.

Note: Excluded values usually come in two varieties. #1) values that make the denominator = 0. #2) values that make the radicand negative. Linear Relationships & Functions Page 3 of 5


Relations & Functions Ex F: Name all values of x that are not in the domain of the given function.

#1)

f ( x) =

x +8

Excluded values = #3)

f ( x) =

#2)

x 2 − 18 f ( x) = 32 − x 2

Excluded values = 4

x2 − 9

#4)

7 f ( x) = | 3 x | −5

Note: Since this has a radicand and a denominator, you have to make sure you do work for both. The excluded values are the union of the two answers.

Excluded values =

Note: To find excluded values, set the denominator = 0. Solve. The result is what x cannot be.

Note: When solving an absolute value you need to get the absolute value by itself. Then break the equation into two equations.

Excluded values = Linear Relationships & Functions Page 4 of 5


Relations & Functions

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