Environmental Control Technical Drawings

Page 1

Study No: 01

Subject of Study

Name of Group Head: Gülten Manioğlu

Student Name: Mehmet Kalyoncu

Proposed Plan

Existing Plan

ROOM

ROOM

LIVING ROOM

LIVING ROOM

ROOM

BEDROOM

KITCHEN

KITCHEN

KITCHEN

ROOM

BEDROOM

ROOM

Student No: 020110701

ROOM

BEDROOM LIVING ROOM

FLOOR PLAN 1/200

FLOOR PLAN 1/200

Building is rotated 180 degrees because living rooms and bedrooms were facing north. Fire escape is added against to existing stairs One more elevator is added next to the existing one because 1 elevator is not considered enough for a 7 storey building Room 1 is moved towards outside so the space for guest toilet and a closet for the room is created A toilet for parents room is added

Page No: 01


Study No: 02

Subject of Study

Name of Group Head: Gülten Manioğlu

Student Name: Mehmet Kalyoncu

Student No: 020110701

Page No: 01

This building has 10 storeys. h: 10 x 3 + 0.8 + 0.7 = 31.5

10:00

h: 31,5 m.

11:00

12:00

13:00

14:00

h: 31,5 m.

h: 31,5 m.

h: 31,5 m.

h: 31,5 m. h: 31,5 m.

SITE PLAN

Scale: 1/1000

From East / West

Time

From South

10:00

31,5 x 1,15 = 36,225 m. 31,5 x 1,96 = 61,74 m.

E

11:00

31,5 x 0,51 = 16,065 m. 31,5 x 1,8 = 56,7 m.

E

12:00

31,5 x 1,73 = 54,495 m.

S

13:00

31,5 x 0,51 = 16,065 m. 31,5 x 1,8 = 56,7 m.

W

14:00

31,5 x 1,15 = 36,225 m. 31,5 x 1,96 = 61,74 m.

W


Study No: 03

Evaluation of Noise Pollution

Name of Group Head: Gülten Manioğlu

Student Name: Mehmet Kalyoncu

Physical environmental factors affecting the building façade

Student No: 020110701

Evaluation

Source-Reciver Distance (will be read from the plan), a (m) Hard Covers (concrete, Ground asphalt, etc. ) Cover Soft Covers (grass, forests, green plants.)

Barrier Barriers or walls between the selected façade and the traffic road (Fig 2.)

Page No: 01

Outdoor noise levels affecting building façade

Frequency, Hz 125

500

2000

11,4 m.

a.

Existing noise level Interruğpted traffic flow noise level (L1)

85

72

68

+

b.

Distance attenuation, Dat, dB (From Figure 1)

0,4

0,4

0,4

+

c.

Barrier attenuation A

10,41

13,69

19,5

d.

Lout = L1 - Dat - A dB

74,19

57,91

48,1

+

Table 2

Table 1

Source Receiver Distance : 11,4 -> Dat =0,4 Db Found from figure 1 σ = (X+Y-Z) σ = (4,5+8,7-12,7) = 0,5 c=λxf

c = 344 m/s λ = c / f

λ(125) = 344/125 = 2,7 λ(500) = 344/500 = 0,7 λ(2000) = 344/2000 = 0,2 N=2σ/λ Factors that effects the noise pollution at building site were found and analized such as the height of the barrier wall, the distance between source and receiver etc.

N(125)= 2x0,5/2,7= 0,37 N(500)= 2x0,5/0,7= 1,42 N(2000)= 2x0,5/0,2= 5 A (Barrier Attenuation) Found from figure 2

160 degrees

The conditions are provided for a good quality of noise environment were seen.

A(125)= 10,41 A(500)= 13,69 A(2000)= 19,5 Lout = L1 - Dat - A Db Lout(125)= 85 - 0,4 - 10,41 = 74,19 Lout(500)= 72 - 0,4 - 13,69 = 57,91 Lout(2000)= 68 - 0,4 - 19,5 = 48,1

x

Example Site Plan - 34

Scale: 1/1000

h

z

Acoustic Green Barrier

y x= 4,5 m. y= 8,7 m. z= 12,7 m. h= 6 m. l = 11,4 m.

l Scale = 1/200


Study No: 04

Window Design

Name of Group Head: Gülten Manioğlu

Student Name: Mehmet Kalyoncu

60

60

Student No: 020110701

Page No: 01

100

N 240

B

360,03

100

60

173,68

200,01

136,33

ROOM 4

ROOM 7 ROOM 6 ROOM 5

175

ROOM 7

ROOM 4 ROOM 5

ROOM 8

35 °

ROOM 6

ROOM 8

A

A

315

ROOM 3

ROOM 2

ROOM 3

ROOM 2

480

ROOM 1

360

480

AA SECTION 1/2000

ROOM 1

250 400

21 °

250

100 250

B-B SECTION 1/2000 FLOOR PLAN 1/200

B

Room Name

SITE PLAN

Scale: 1/2000

Room Width (m)

Room Depth (m)

Obst. Angel (°)

Trans Ratio (%)

Total Facade Area (m2)

Window Area (m2)

Window Height (m)

Window Lenght (m)

Window Type

Room 1

3

5

21 °

30

8.5

2.55

1.2

2.1

W2

Room 2

3

4

21 °

20

6.7

1.34

1.2

1.1

W1

Room 3

4

5

21 °

30

10.8

3.24

1.2

Room 4

3

4

21 °

20

5.4

1.08

1.2

2.7 0.9

W2 W1

Room 5

3

4

20

3.5

0.7

1.2

0.5

W3

Room 6

4 4

4.5 6.4

0.9 1.28

0.7

W3

20 20

1.2

Room 7

3 3

0° 0°

1.2

1

W1

Room 8

3

3

20

4.5

0.9

1.2

0.7

W3

The selected building consists of 8 rooms. It has obstacles from south façade and west façade While calculating the total façade area dimensions of the rooms were taken originally from the plan and the height was taken 2.7 m. Room 1-2-3-4 are facing south. Room 5-6-7-8 are facing north. Dimensions of windows were found. 3 types of windows were designed by analyzing the dimensions of windows and optimal dimensions for 3 types were identified.

WINDOW DRAWINGS

75

100

75

60

120

100

1/50

W1

W2

W3


Name of Group Head: Gülten Manioğlu

Student Name: Mehmet Kalyoncu

Gypsum plaster

Lighteight concrete

Polystrene extruded foam XPS

For this calculation Trabzon is choosen. (Region 2)

Building Envelope Design Cement screed

Study No: 05

Student No: 020110701

Page No: 01

Carpet Cement screed Polystrene extruded foam XPS

Granite Glue Cement screed

Cement screed

Polystrene extruded foam XPS

Dense concrete (reinforced)

Cement screed

Natural porous crushed stones

Lightweight concrete (reinforced) Gypsum plaster

DETAIL OF OPAQUE COMPONENT

(WALL)

DETAIL OF CEILING (FLAT ROOF)

DETAIL OF FLOOR 1/5

1/5

1/αi = 0,17 m2°C/W 1/αd = 0 m2°C/W

1/αi = 0,13 m2°C/W 1/αd = 0,04 m2°C/W

1/αi = 0,13 m2°C/W 1/αd = 0,08 m2°C/W UT

Ut

UD

1/ i + d/ 1 + d/ 2 + d/ 3 + d/ 3 + d/ 4 + d/ 5 + d/ 5 + d/ 6 + d/ d

1/ i + d/ 1 + d/ 2 + d/ 3 + d/ 3 + d/ 4 + d/ 5 + d/ 5 + d/ 6 + 1/ d

1/ i + d/ 1 + d/ 2 + d/ 3 + d/ 3 + d/ 4 + 1/ d

1

1

1

1

1

= 0,57948 W/m2°C

0,13 + 0,02/1,4 + 0,04/0,04 + 0,2/0,39 + 0,01/0,35 + 0,04

0,17 + 0,01/0,07 + 0,03/1,4 + 0,03/0,04 + 0,04/1,4 + 0,1/2,1 + 0,15/0,22 + 0

Ucalculated < Uregulation

Ucalculated < Uregulation

0,57948 < 0,6

0,5428 < 0,6

1/5

= 0,5428 W/m2°C

1

= 0,37229 0,13 + 0,02/3,5 + 0,04/1,4 + 0,08/0,04 + 0,04/1,4 + 0,15/0,39 + 0,01/0,35 + 0,08 W/m2°C

Ucalculated < Uregulation 0,37229 < 0,4


Study No: 06

Sound Transmission Calculation

Name of Group Head: Gülten Manioğlu

Outdoor noise levels affecting building façade

Student Name: Mehmet Kalyoncu

Student No: 020110701

Page No: 01

Frequency, Hz 125

500

2000

a.

Existing noise level Interruğpted traffic flow noise level (L1)

85

72

68

b.

Distance attenuation, Dat, dB (From Figure 1)

0,4

0,4

0,4

c.

Barrier attenuation A

10,41

13,69

19,5

d.

Lout = L1 - Dat - A dB

74,19

57,91

48,1

3 mm glass 13 mm air 3 mm glass

ROOM 4

ROOM 7 ROOM 6

ROOM 5

ROOM 8

ROOM 1

ROOM 2

ROOM 3

Floor Plan 1/500

(Bedroom)

Room Info = Bedroom (Dead Room) TL required = Lout - L criteria - 4 dB Transparency Info = Transparency Ratio = %30 Total Facade Area = 8.5 m2 Window Area = 8.5 x 30/100 = 2.5 m2 Solid Wall Area = 8.5 - 2.5 = 6 m2 Area Ratio = S window / S solid wall = 2.5/6 = 0,4166 = 1/2,4 TL composite = TL solid wall - X (X is found from Figure 1) 20 cm ligthweight concrete is selected from Table 2 Cement Screed (2cm)

3mm glass + 13 mm air + 3 mm glass is selected from Table 3

Polystrene extruded foam XPS (4cm) Lightweight Concrete (20cm)

For this exercise the room which has the worst conditions is selected. Lout value is taken from the application no.3. Selected room is a bedroom so while calculating TL required dead room is choosen. In calculation 4dB is subtracted. The values of solid wall is taken from Table 2. The characteristics of window such as window area, transparency ratio is taken from the application no.4. Area ratio is found. X value is found from the Figure 1 by the dividing Area ratio to TL solid wall TL window. Finally TL composite is found by subtracting X value from TL Solid wall. In all frequencies TL composite is bigger than TL required

Gypsum Plaster (1cm)

(Selected building)

Site Plan 1/200 Window and Wall Section 1/5


Study No: 07

Design of Building Facades

WEST FACADE

1/200

Name of Group Head: Gülten Manioğlu

Student Name: Mehmet Kalyoncu

Student No: 020110701

SOUTH FACADE

Page No: 01

1/200

ROOM 4

ROOM 7 ROOM 6

ROOM 5

ROOM 8

ROOM 1

ROOM 2

ROOM 3

Floor Plan 1/500


Study No: 08 Calculation of the Heating Load

Name of Group Head: Gülten Manioğlu

Student Name: Mehmet Kalyoncu

Student No: 020110701

A

Q6 Q3

Q4

Q2

Q1

A

Q5

A-A SECTION

FLOOR PLAN 1/200

W

Heat Loss By Conduction :

W Heat Loss By Infiltration :

W

W

1/50

Page No: 01


Study No: 09 Designing the heating center

Name of Group Head: Gülten Manioğlu

Student Name: Mehmet Kalyoncu

Student No: 020110701

Page No: 01

Space 05 Bathroom 5 m2 24 °C 105 W

Space 06 Bathroom 7m2 24 °C 147 W

F Smoke= 267 cm2

Space 07 Bedroom 9 m2 20 °C 139 W

Aluminium / 102W / 450 / 110

Aluminium / 102W / 450 / 110

Space 08 Bathroom 4m2 24 °C 84 W

Aluminium / 102W / 450 / 110

F Fresh Air = 133 cm2

F Exhaust Air = 67 cm2

Aluminium / 102W / 450 / 110 Aluminium / 102W / 450 / 190

Boiler Room

Space 04 Kitchen 7 m2 20°C 162 W

Aluminium / 102W / 450 / 270

Space 09 Corridor 11 m2 15 °C 283 W

Storage Space 01 Bedroom 15m2 20 °C 347 W

Aluminium / 102W / 450 / 270

Entrance

Space 03 Living Room 19 m2 22 °C 419 W

Space 02 Bedroom 9m2 20 °C 208 W Aluminium / 102W / 450 / 190

Aluminium / 102W / 450 / 350 Aluminium / 102W / 450 (height) / 270 (lenght)

FLOOR PLAN 1/200

BASEMENT FLOOR PLAN 1/200

BOILER SELECTION

CALCULATION OF FLUE SECTION

Qbuilding=59 KW Qk= Qbuildingx1,3 Qk=59x1,3= 76,7

Fsmoke= 0,02 x Qk/√h h=31,5 + 1 + 0,8 = 33,3 m. Fsmoke= 0,02 x 77235,6/√33,3 = 267 cm2 F Fresh Air = Fsmoke/2 = 267/2 F Fresh Air = 133 cm2

First Boiler capacity= 25,5 Second Boiler Capacity=51,2 Wall Type Condenser Boilers First Boiler = Width:0,56m Second Boiler = Width:0,90m

Length:0,43m Lenght:0,43m

Height:0,68m Height:1,28m

F Exhaust Air = Fsmoke/4 = 267/4 F Exhaust Air = 67 cm2

Storage


Study No: 10 Design of the water installation system

Name of Group Head: Gülten Manioğlu

Student Name: Mehmet Kalyoncu

Student No: 020110701

Page No: 01

Population Calculation Number of bedroom per flat = 3 Number of inhabitants per flat = 4 Number of flats per floor = 2 Number of inhabitants per floor = 8 Number of floors = 10 Total Inhabitants = 80 Water Requirement Calculation 80 x 100 lt = 8.000 lt Tank Volume Calculation 80 x 90 lt x 3 days = 21.600 lt 21600 lt x 0,30 x12000 = 77.760.000 lt = 77.760 m3

PLAN 1/50 R

R

R

R

R

R

Boiler Room

P

R Storage

Entrance

R

Tank h: 2,5 m.

MAIN WATER

SEWER SYSTEM

MANHOLE

R

PLAN 1/200

R


Study No: 11 Architectural drawings for a typical wet space

Name of Group Head: Gülten Manioğlu

Student Name: Mehmet Kalyoncu

Student No: 020110701

38

C

B

+ 3.10

+ 2.55 36

15

37

A

A

48 18

8

170

560

200

BA

+ 0.05

BATHROOM Floor = Ceramic Tile 20x20 Wall = Wall Tile 20x20 Ceiling = Alu.Suspended Ceiling

42

+ 0.00

A-A SECTION

+ 0.05 + 0.00

PLAN

1/20 C

B

30

40

117

9

1/20

Page No: 01


Study No: 11 Architectural drawings for a typical wet space

Name of Group Head: Gülten Manioğlu

Student Name: Mehmet Kalyoncu

+ 3.10

Student No: 020110701

38

38

+ 3.10

+ 2.55

940

84

83

117

150

170

28

200

22

60

+ 2.55

+ 0.05

C-C SECTION

+ 0.00

1/20

+ 0.05

B-B SECTION

+ 0.00

Page No 02


Design of the artificial lighting system

Name of Group Head: Gülten Manioğlu

Student Name: Mehmet Kalyoncu

Student No: 020110701

Page No: 01

457

500

DETERMINATION OF THE GIVEN VALUES

DETERMINATION OF THE VARIOUS VALUES

Width (a) = 9,66 m. Lenght (b) = 9,62 m the shaft in the middle was selected Height (H) = 5 m.

Required illumination of the workplane = 500 lx

Colors

Characteristic of lighting system = direct-indirect

Ceiling = White, ρC = 80-85 Walls = Beige, ρW = 48 Floor = Brown , ρF= 13

Luminaire type and efficiency =

Aluminum suspended ceiling 60x60 A-A SECTION 1/100

CALCULATIONS Room index (k) k = 0,8a + 0,2b h

k = 0,8 x 9,66 + 0,2 x 9,62 = 2,29 4,2

Utilization factor (η) ρC is selected 70, ρW is selected 50, k is selected 2,5 η was found = 0,46 Total luminous (Φ) Φtotal =E x S / η

A

A

Φtotal = 500 x 35,6 / 0,46 = 38695 lm

n : number of the lamps n= 38695 / 1800 = 21

180

n= Φtotal/Φ1 Φ1 = 1800 lm

110

P.S = For a more balanced distribution n was selected 22 for the plan

LIGHTING PLAN 1/100

Lamp type = Fluorescent

Height of the luminaire = 5 - 0,8 = 4,2 m.

Structure of the ceiling

42

80

455

70

Study No: 12


Study No: 14

Design of HVAC System

Name of Group Head: Gülten Manioğlu

Student Name: Mehmet Kalyoncu

Student No: 020110701

140

470

S

83 10

S I

1000

S

I

S S

PLAN 1/200

B-B SECTION 1/100

A

PLAN 1/200

140

915,42

84,58

S

1000

B

B

S I

S

I

I

S

S

S

A

910

A-A SECTION 1/100

S

I

PLAN 1/100

Page No: 01


Name of Group Head: Gülten Manioğlu

B

Study No: 13 Acoustical Design

C

A C

D A

B

D PLAN 1/100

Student Name: Mehmet Kalyoncu

Student No: 020110701

Page No: 01


Study No: 13 Acoustical Design

Name of Group Head: Gülten Manioğlu

Gypsum, rough finishing on metal lath

A-A SECTION STAGE WALL 1/100

Plywood panelling

C-C SECTION SIDE WALL 1 1/100

Student Name: Mehmet Kalyoncu

Student No: 020110701

Perforated wooden panel

B-B SECTION BACK WALL 1/100

Plywood panelling

D-D SECTION SIDE WALL 2 1/100

Page No: 02


Student Name: Mehmet Kalyoncu

Student No: 020110701

A

Integration of Systems Name of Group Head: Gülten Manioğlu

140

915,42

84,58

S

1000

S I

S

I

I

S

S

S

A

910

A-A SECTION 1/100

Study No: 15

PLAN 1/100

Page No: 01


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