Materia método de gauss jordán

Page 1

INVESTIGACIÓN OPERATIVA I

Dr. Marlón Villa

MÉTODO DE GAUSS-JORDÁN EJERCICIO 1 2x1+3X2+4X3=5 2x1+X2-5X3= 6

-4 -6 -8 = -10

3x1-2X2+4X3=1

4 +1 -5 = 6

-3 -9/2 -6 = -15/2 3 -2 1 - 3/2 + 2= 5/2

4

7

0 - 3/2 -39/2 =-6/5

0 – 5 – 13 = -4

1 +3/2 +2

= 5 /2

0- 13/2 -2 = -1/2

00 - 13/2 -169/10 =26/5 0 19/10 = +893/1490

1 + 0 - 19/10 = 13/10

11 +13/2 +2 = 13/10 =-1 /2 0 -19/10

0 + 1 + 13/5 = 4/5 0 + 0 – 149/10 =47/10

0

0

-13/5 =-611/745

0

1

13/5 = 4/5

1 + 0 + 0 = 283/149 0 + 1 + 0 = -3/149 0 + 0 + 1 = 47/149

X= 283/149

COMPROBACIÓN

Y= -3/149

2x1+3X2+4X3=5

Z= 47/149

2(283/149)+3(-3/149)+4(47/149) 5=5

pág. 2

Srta. Paola Meza


INVESTIGACIÓN OPERATIVA I

Dr. Marlón Villa

EJERCICIO 2 2x+5y-2z= 10 5x-2y+3z= 7

-5 -25/2 5 = -25

4x+6y+8z=1

5

-4 4 1 + 5/2 - 1= 5

-2

3= 7

-10 4 = -20 6

8

= 1

0 - 5/2 40/29 =-20/29

0 – 29/2 – 8 = -18

1 5/2 -1

= 5

0 - 4 12 = -19

1 + 0 + 11/29 = 55/29 0 + 1 + 16/29 = 36/29

0

4

1

-4

-64/29 =144/29 12

=

-19

0 0 16/29 = -1628/2059

0 + 0 – 284/29 =-407/29

1 0 -16/29 = 36/29

1 + 0 + 0 = 693/149

0

0

-11/29 = 4477/8236

1

0

11/29 = 55/29

0 + 1 + 0 = 32/71 0 + 0 + 1 = -407/284

X= 693/284

COMPROBACIÓN

Y= 32/71

2x+5y-2z= 10

Z=-407/284

2(693/284)+3(32/71)+4(-407/284) 10 =10

pág. 3

Srta. Paola Meza


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