Exam review answers 2015

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Francis Libermann Catholic High School Science Department

Grade 11 University Chemistry SCH 3U1 – Exam Review Answers


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Grade 11 University Chemistry – Exam Review Unit 1: Matter & Chemical Bonding Significant Digits & Rounding 1. Identify how many significant digits are in the following numbers. 1205

_________________

600 000

_________________

0.0003

_________________

600 001

_________________

78.0

_________________

0.00800

_________________

4.0×10–3

_________________

9.000

_________________

2. Convert the following values to show the correct number of significant digits stated. 400

Round to 3 significant digits

_________________

2 589

Round to 3 significant digits

_________________

1 900 000

Round to 1 significant digit

_________________

0.0399

Round to 2 significant digits

_________________

3. Calculate the following in accordance to the rules applied by the question. Questions with the *, answers must be kept in scientific notation. a.) 5.2×6.14

b.)

(4×105)(3.7×10–7)*

d.) (3.9×103)÷(8.3×10–8)*

e.) 10.8 – 3.5 × 2.49

c.) 545.0 + 7.29 – 30

f.) 10.5 – 8.5 + 17.3 – 2.3

4. Identify if a physical or chemical change is taking place. a.) _____ glass breaking

j.) _____ mixing salt and water

b.) _____ hammering wood together

k.) _____ mixing oil and water

c.) _____ a rusting bicycle

l.) _____ water evaporating

d.) _____ melting butter

m.) _____ cutting grass

e.) _____ separate sand from gravel

n.) _____ burning leaves

f.) _____ bleaching your hair

o.) _____ fireworks exploding

g.) _____ frying an egg

p.) _____ cutting your hair

h.) _____ squeeze oranges for juice

q.) _____ crushing a can

i.) _____ melting ice

r.) _____ boiling water FRANCIS LIBERMANN CATHOLIC HIGH SCHOOL Chemistry Unit – Exam Review – Science Department 1


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5. Classify each of the following as an element (E), compound (C), solution (S), mechanical mixture (M) or an alloy (A) a.) ____ sodium phosphate

b.) ____ xenon

c.) ____ sugar

d.) ____ Gatorade

e.) ____ sugar water

f.) ____ skim milk

g.) ____ beach water

h.) ____ gold

i.) ____ 14kt gold

Understanding the Periodic Table 6. What is the trend in atomic radius: a.) Across a period? Explain.

b.) Down a group? Explain.

7. What is the trend in ionization energy: a.) Across a period? Explain.

b.) Down a group? Explain.

Isotopes & Isotopic Abundance 8. Complete the following table Chemical Symbol

Charge

Number of Electrons

Atomic Number

0

37

+2

24

–3

18

33

–1

54

130

+1

18 FRANCIS LIBERMANN CATHOLIC HIGH SCHOOL Chemistry Unit – Exam Review – Science Department 2

Neutrons

Mass Number 85

30

22


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9. Draw a Bohr-Rutherford diagram for each of the following: a.) oxygen – 18

b.)

c.) chlorine – 35

10. Find the average atomic mass of calcium given the following information about its isotopes: Mass (u)

% Abundance

40

96.97

42

0.64

43

0.15

44

?

48

0.18

11. Boron exists as two naturally occurring isotopes, with atomic masses 10.01 u and 11.01 u. Calculate the relative abundance of each isotope.

FRANCIS LIBERMANN CATHOLIC HIGH SCHOOL Chemistry Unit – Exam Review – Science Department 3


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Covalent Bonding 12. For each of the following: i.

Determine whether the bonding is ionic, polar covalent or non-polar covalent

ii.

Draw an electron dot diagram to illustrate the bonding

iii.

Draw a structural formula with polarity for the covalently bonded molecules only.

a.) NH3

b.) Na2O

c.) MgS

d.) CCl4

e.) PF3

f.) CS2

g.) CaI2

h.) K2S

FRANCIS LIBERMANN CATHOLIC HIGH SCHOOL Chemistry Unit – Exam Review – Science Department 4


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i.) OCl2

j.) C3H8

k.) CHBr3

l.) H2S

Electron Configuration 13. Write out the simplified electron configuration of the following atoms/ions a.) Oxide ion

b.) Silver

c.) Terbium

d.) Xenon

14. Draw Lewis dot diagrams for the following atoms/ions a.) Sulfide ion

b.) Boron

FRANCIS LIBERMANN CATHOLIC HIGH SCHOOL Chemistry Unit – Exam Review – Science Department 5

c.) Silicon


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VSEPR Theory 15. Draw Lewis dot structures for the following compounds and state their shape. a.) ammonium ion

b.) BF3

Shape: ________________________________

Shape: ________________________________

c.) carbon dioxide

d.) sulfur hexafluoride

Shape: ________________________________

Shape: ________________________________

e.) sulfate ion

f.) phosphorus pentachloride

Shape: ________________________________

Shape: ________________________________

FRANCIS LIBERMANN CATHOLIC HIGH SCHOOL Chemistry Unit – Exam Review – Science Department 6


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Nomenclature Elements Most elements on the periodic table are monatomic in their natural state, meaning that they exist as individual atoms. i.e.

helium He(g)

sodium Na(s)

silicon Si(s)

Hydrogen, nitrogen, oxygen and the halogens (Group VII) are diatomic elements, meaning that the molecules of these elements exist as pairs of identical atoms i.e.

Tip:

hydrogen H2(g)

nitrogen N2(g)

oxygen O2(g)

fluorine F2(g)

chlorine Cl2(g)

bromine Br2(g)

iodine I2(g)

In Florida, Brad Never Cleans His Oranges.

Binary Compounds All binary compounds consist of only two different elements. Names of binary compounds end in “-ide”. Some examples of binary compounds are: Sodium chloride – made up of sodium and chlorine – ionic compound Carbon dioxide – made up of carbon and oxygen – covalent compound

Ionic Compounds – aka salts Binary compounds that are composed of a metal and a non-metal are called Ionic Compounds and are named using IUPAC System (created by the International Union of Pure and Applied Chemistry) **Generally speaking, elements that lie to the left of the “Aluminum staircase” on the periodic table are metals and those to the right of the “staircase” are non-metals. An important exception is hydrogen, which is a non-metal even though it lies to the left of the “staircase”. a.) Colour the metals RED and the non-metals BLUE. b.) What kind of charge do the metals exhibit? What do we call metal ions?

c.) What kind of charge do the non-metals exhibit? What do we call non-metal ions?

FRANCIS LIBERMANN CATHOLIC HIGH SCHOOL Chemistry Unit – Exam Review – Science Department 7


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i.e. sodium chloride •

sodium is the metal & chloride is the non-metal

To write the formula for an ionic compound follow the following steps • 1. 2. 3. 4. 5.

Identify metal/non-metal Write the symbol Write out the charge as shown on the Periodic Table Cross over the charges from top-to-bottom Remove the charge Simplify the charges that were crossed over and REMOVE any 1’s.

When naming Binary Ionic Compounds, name the metal first and the non-metal second, changing the ending of the non-metal to “-ide” i.e. CaCl2 is called calcium chloride Transition Metals If the metal has more than one possible charge, the actual charge must be shown either using Roman Numerals (Stock System for naming Transition Metals) or using their Latin name (Classic System for naming Transition Metals) with the appropriate ending Stock System – Roman Numerals • I, II, III, IV, V, VI • Roman numeral follows the metal and is enclosed in brackets (i.e. copper (II) chloride) • In the above example the Roman numeral (II) states that we are using the Oxidation number +2 of Copper.

Classic System – Latin Names • Pb – Plumbum (Lead) • Cu – Cuprum (Copper) • Fe – Ferrum (Iron) • Sn – Stannum (Tin) • Au – Aurum (Gold) • If you are using the lower (charge) oxidation number drop the “-um” ending of the Latin name and replace it with “-ous” (i.e. plumbum becomes plumbous if we are using the +2) • If you are using the higher (charge) oxidation number drop the “-um” ending of the Latin name and replace it with “-ic” (i.e. plumbum becomes plumbic if we are using the +4)

Examples: • Cu2O = copper (I) oxide • CuO = copper (II) oxide

Examples: • Cu2O = cuprous oxide • CuO = cupric oxide

• •

FeO = iron (II) oxide Fe2O3 = iron (III) oxide

• •

FeO = ferrous oxide Fe2O3 = ferric oxide

****NOTICE: We NEVER, EVER, mix and match Stock and Classic at the same time such as cupric (II) oxide. • THIS IS INCORRECT!!!!!! FRANCIS LIBERMANN CATHOLIC HIGH SCHOOL Chemistry Unit – Exam Review – Science Department 8


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Covalent Compounds Binary compounds that are composed of two different non-metal elements are called Covalent Compounds and are named using the Greek PREFIX method mono = 1 hexa = 6

di = 2 hepta = 7

tri = 3 octa = 8

tetra = 4 nona = 9

penta = 5 deca = 10

i.e. dinitrogen tetroxide N2O4 • Note that an –o– or an –a– at the end of the prefix may be dropped for ease of pronunciation CO2 = carbon dioxide Polyatomic Ions & Polyatomic Variations To help remember a handful of commonly used polyatomic ions, think about the following phrase

Nick the Camel ate a Clam for Supper in Phoenix • •

Consonants = number of oxygens Vowels = negative charge Gains 1 Oxygen from the Normal

Nick

NORMAL

Loses 1 Oxygen From the Normal

Loses 2 Oxygen’s From the Normal

Formula Name

Camel

nitrate Gains 1 Oxygen from the Normal

NORMAL

Loses 1 Oxygen From the Normal

Loses 2 Oxygen’s From the Normal

Gains 1 Oxygen from the Normal

NORMAL

Loses 1 Oxygen From the Normal

Loses 2 Oxygen’s From the Normal

Gains 1 Oxygen from the Normal

NORMAL

Loses 1 Oxygen From the Normal

Loses 2 Oxygen’s From the Normal

Gains 1 Oxygen from the Normal

NORMAL

Loses 1 Oxygen From the Normal

Loses 2 Oxygen’s From the Normal

Formula Name

Clam Formula Name

Supper Formula Name

Phoenix Formula Name

FRANCIS LIBERMANN CATHOLIC HIGH SCHOOL Chemistry Unit – Exam Review – Science Department 9


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Hydrogen Polyatomic We can derive 3 of the hydrogen polyatomics using the above rules. When adding “hydrogen” to carbonate, sulfate and phosphate, drop 1 of the charges Carbonate = CO3–2

Sulfate = SO4–2

Phosphate = PO4–3

Hydrogen Carbonate = CO3–1

Hydrogen Sulfate = SO4–1

Hydrogen Phosphate = PO4–2

Naming Rules Gain 1 oxygen from the Normal

per____________ate

Normal

_____________ate

Lose 1 oxygen from the Normal

_____________ite

Lose 2 oxygen’s from the Normal

hypo_________ite

*** Halogens Bromine and Iodine follow the same pattern as chlorine with regards to their polyatomic ion

bromate = BrO3–1

iodate = IO3–1

Other Polyatomics that you must memorize NH4+ ammonium CH3COO– or C2H3O2– acetate SCN– thiocyanate

OH–

hydroxide

CN–

cyanide

MnO4–

permanganate

H2PO4–

dihydrogen phosphate**

OCN– cyanate

H2PO3–

dihydrogen phosphite**

BrO3– bromate

IO3–

oxalate

CrO4–2

HS– hydrogen sulfide**

O2–2 peroxide** silicate AsO4–3 arsenate

dichromate

S2O3–2

thiosulfate

AsO3–3

arsenite**

** these Polyatomics can be derived from previous rules

Chemistry Unit – Exam Review – Science Department 10

chromate

Cr2O7–2

BO3–3 borate

FRANCIS LIBERMANN CATHOLIC HIGH SCHOOL

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Acids When naming acids, it is very important to first identify what type of acid you have. There are two types of acids: Binary Acids & Oxyacids (a.k.a Polyatomic Acids) i.)

Binary Acids – These acids are aqueous (aq) binary compounds that contain hydrogen and one non-metal only. To name these acids, start the name with the prefix “hydro–“, then name the non-metal using its elemental name but make sure the ending is changed to “ –ic acid”. On a side note, these binary compounds must be dissolved in water in order to exhibit acidic properties (i.e. HCl = hydrogen chloride and HCl(aq) = hydrochloric acid). • • •

ii.)

HF(aq) = hydrofluoric acid H2S(aq) = hydrosulfic acid H3P(aq) = hydrophosphic acid

HF = hydrogen fluoride H2S = hydrogen sulfide H3P = hydrogen phosphide

Oxyacids (Polyatomic Acids) – These acids consist of hydrogen combined in the appropriate ratio with any of the polyatomics studied. The ending “–ate” is changed to “–ic acid” and the ending “–ite” is changed to “–ous acid”. NOTE: there is NO prefix for these acids!! NO4– pernitrate

forms

HNO4(aq) pernitric acid

NO3–2 nitrate

forms

HNO3(aq) nitric acid

NO2– nitrite

forms

HNO2(aq) nitrous acid

NO– hyponitrite

forms

HNO(aq) hyponitrous acid

Hydrates Some salts form crystals containing water molecules in definite proportions. A prefix is used to indicate the number of water molecules associated with the salt. 16. Name the following hydrate compounds a.) CuSO4•5H2O

___________________________________

b.) Na2SO4•10H2O

___________________________________

FRANCIS LIBERMANN CATHOLIC HIGH SCHOOL Chemistry Unit – Exam Review – Science Department 11


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17. Nomenclature Practice: Elements and Binary Compounds Name

Formula

Formula

Magnesium bromide

HgCl2

Tin (IV) oxide

CaO

Ferrous chloride

MnBr4

Manganese (II) sulfide

Na2O

Mercury (II) chloride

Mg3N2

Lead (IV) iodide

AgCl

Potassium nitride

P 2O 5

Cupric fluoride

CoCl3

Diphosphorus trioxide

K 2S

Arsenic (V) oxide

SnO2

Silver oxide

H3P(aq)

Sulfur trioxide

SO3

Nitrogen dioxide

BO3

Aluminum sulfide

PbO2

Hydrogen bromide

SnCl2

Iron (III) oxide

CuI2

Copper (II) nitride

HCl

Nitrogen gas

Br2

Dinitrogen tetroxide

HF(aq)

Carbon oxide

SF6

Hydroiodic acid

UO3

Barium chloride

IF5

Hydrogen sulfide

H 2O

Silicon dioxide

C 2H 6

Sodium oxide

Li3N

FRANCIS LIBERMANN CATHOLIC HIGH SCHOOL Chemistry Unit – Exam Review – Science Department 12

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18. Nomenclature Practice: Polyatomic Compounds Name

Formula

Formula

Magnesium hydroxide

SO4

plumbic carbonate

In(NO)3

Iron (II) sulfate

CoSiO3

Calcium carbonate

(NH4)2CrO4

Ammonium acetate

Cu(HSO4)2

Potassium sulfite

PbSO27H2O

Sodium hydrogen carbonate

H2SO2(aq)

Copper (II) pernitrate

Bi2(S2O3)5

Arsenic (V) phosphite

V(HS)2

Ammonium carbonate

Fe3(AsO3)2

Calcium sulfate trihydrate

CO2–2

Chloric acid

LiOCN

Hypophosphorous acid

Pb(CN)2

Calcium thiosulfate

CrC2O4

Ammonium oxalate

Ca(MnO4)2

Lead (IV) peroxide

FeAsO4

Iron (III) chlorate

Pd(S2O3)2

sulfurous acid

Zr(O2)2

Potassium cyanate

H3PO2(aq)

Silver dihydrogen phosphite

Sr3(PO3)24H2O

Sodium peroxide

Cu(CN)2

Calcium arsenate

TiAsO3

Cobalt (III) chromate

HCH3COO(aq)

Stannous hydrogen sulfide

Cd(H2PO4)2

Ferric cyanate

Rb2SiO3

FRANCIS LIBERMANN CATHOLIC HIGH SCHOOL Chemistry Unit – Exam Review – Science Department 13

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Types of Reactions Synthesis reaction: This is a reaction in which two or more elements or compounds combine to form a single product. This type of reaction follows the general equation: A + B  C, where A and B may be either elements or compounds. Here are some examples: 2Na(s) + Cl2(g)  2NaCl(s) MgO(s) + H2O(l)  Mg(OH)2(aq) (NOTE: metal oxide + water  bases) SO2(g) + H2O(l)  H2SO3(aq) (NOTE: non-metal oxide + water  acids) Decomposition reaction: In this type of reaction, a single reactant, a compound, breaks into two or more parts. Often these are the most difficult to predict. Here is the general equation: AB  A + B, where A and B may be either elements or compounds. Here are some examples of decomposition reactions: 2H2O(l)  2H2(g) + O2(g) H2CO3(aq)  H2O(l) + CO2(g) CaCO3(s)  CaO(s) + CO2(g) 2KClO3(s)  2KCl(s) + 3O2(g) LiHCO3  Li2CO3 + CO2(g) + H2O(l) (metal hydrogen carbonates  metal carbonate + CO2 + H2O) Single displacement reaction: In this type of reaction, a more active element replaces a less active element in a compound (use the Activity Series of Metals). Among the halogens, F2 is the most active halogen, and the activity of the halogens decreases as you go down the group. For the metals, you will need to be given an activity series. General equation: A + BC  AC + B, where A is a metal. Here is an example of a displacement reaction in which a metal is involved: Cu(s) + 2AgNO3(aq)  2Ag(s) + Cu(NO3)2(aq) General equation: A + BC  BA + C, where A is a nonmetal. Here is an example of a displacement reaction where a nonmetal is involved: Cl2(g) + 2NaI(aq)  2NaCl(aq) + I2(s) Double displacement reaction: In this type of reaction, two compounds react to form two new compounds. The formation of a molecular compound such as water, the formation of a gas, or the formation of a precipitate usually drives these reactions. Here’s the general equation: AB + CD  AD + CB And here are a couple of examples: Pb(NO3)2(aq) + 2KI(aq)  2KNO3(aq) + PbI2(s) HCl(aq) + NaOH(aq)  H2O(l) + NaCl(aq) Complete and Incomplete combustion reaction: In this type of reaction, often a hydrocarbon is burned in the presence of oxygen gas to form carbon dioxide (in a complete combustion) or carbon monoxide (in an incomplete combustion, due to a limited amount of oxygen). Here is the general equation in the presence of plenty of oxygen: CxHy + O2(g)  CO2(g) + H2O(l) or (g) An example of this is seen when methane gas is burned in the presence of excess oxygen – complete combustion (Bunsen burner reaction): CH4(g) + 2O2(g)  CO2(g) + 2H2O(g) Here is the general equation for when a hydrocarbon is burned in an incomplete combustion (oxygen is in limited supply): CxHy + O2(g)  CO(g) + H2O(l) + CO(g) + C(s) FRANCIS LIBERMANN CATHOLIC HIGH SCHOOL Chemistry Unit – Exam Review – Science Department 14


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Unit 2 – Chemical Quantities 19. Complete the following Zinc + Sulfur  zinc sulfide Mass of crucible

18.41 g

Mass of crucible + zinc

19.72 g

Mass of crucible + zinc sulfide

20.36 g

Calculate the percent of sulfur in zinc sulfide

20. Determine the percent composition of sodium sulfate.

21. Determine the empirical formula of a compound with the composition 27.7% magnesium, 23.6% phosphorus, 48.7% oxygen.

22. A compound has a molar mass of 50.5 g/mol. Its percent composition is 23.8% carbon, 5.99% hydrogen and 70.2% chlorine. What is its molecular formula?

FRANCIS LIBERMANN CATHOLIC HIGH SCHOOL Chemistry Unit – Exam Review – Science Department 15


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The Mole A mole is used to express very large number of particles (atoms, molecules, ions, etc.,). A mole (with the symbol “n”) is equal to 6.02×1023 particles of a substance (which is known as the Avogadro Constant NA)

N = n × NA Molar mass is the mass of one mole of a substance. The molar mass (in grams) of each element is recorded on the periodic table. To determine the molar mass of a compound, add the molar masses of each atom in the compound. Example: M of Ca(NO3)2

=

(M of “Ca”) + 2(M of “N”) + 6(M of “O”) (40.08 g/mol) + 2(14.01 g/mol) + 6(16.00 g/mol) = ______________

Several equations (or ratios) relate the number of moles in a sample to other quantities.

Number'of'moles'

You can determine the mass of the sample by multiplying the number of moles by the molar mass

To find the number of particles in a sample, multiply the number of moles by 6.02×1023

Molar'

Number'of''

Volume''

Mass'(M)'

Particle'(N)'

(for'a'gas'at'STP)'

If the sample is a gas at STP (T=0˚C, P=101.3kPa), you can determine the volume of the sample by multiplying the number of moles by 22.4 L

Similarly, you can use several quantities to determine the number of moles in a sample: Pure Substances ONLY

Number of Particles (molecules, atoms

N = n × NA m' n'

M'

FRANCIS LIBERMANN CATHOLIC HIGH SCHOOL Chemistry Unit – Exam Review – Science Department 16

Molar Volume 22.4 L/mol


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Practice 23. Determine the molar mass of: a.) water

d.) aluminum hydroxide

b.) sodium sulfate

e.) cupric hypochlorite

c.) calcium carbonate tetrahydrate

f.) ammonium hydrogen phosphate

24. Calculate the mass of 0.25 mol of magnesium hydroxide.

25. Determine the number of moles in 11.7 g of calcium arsenite.

FRANCIS LIBERMANN CATHOLIC HIGH SCHOOL Chemistry Unit – Exam Review – Science Department 17


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26. Find the number of moles in 22.2 g of potassium dichromate.

27. How many atoms are in 5.5 mol of strontium hydroxide?

28. Determine the mass of 0.50 mol of sulfur trioxide.

29. How many molecules are present in 9.0 g of hydrogen nitride?

30. How many atoms are present in 9.0 g of ammonium thiosulfate?

FRANCIS LIBERMANN CATHOLIC HIGH SCHOOL Chemistry Unit – Exam Review – Science Department 18


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31. Determine the number of oxygen atoms in 0.05 g of stannic hydroxide.

32. Determine the molar mass of a compound if 2.70 g of compound contains 4.55×1022 molecules.

Stoichiometry, Limiting Reactants & Percent Yield In these types of problems, quantitative information is given about one or more species in a chemical reaction and you are asked to calculate the information about another. To answer these problems, use the following steps: i.

Write a balanced chemical equation

ii.

Set-Up a table of data showing your unknown and given (as shown below) moles Unknown

coefficient

x

Known Known #2 (ONLY for Limiting Reactant Questions) iii.

Find the number of moles of unknown that will be formed based on your mole ratio

iv.

Find the mass of the unknown substance (if applicable to the question)

v.

Write a concluding statement

FRANCIS LIBERMANN CATHOLIC HIGH SCHOOL Chemistry Unit – Exam Review – Science Department 19


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33. Determine the mass of oxygen produced in the decomposition of 25.0 g of potassium chlorate which would also yield the formation of potassium chloride.

34. Calculate the mass of ferrous sulfide produced when 160.0 g of ferrum reacts with a molecule that contains 8 atoms of sulfur.

35. What mass of chlorine gas could be obtained by heating 70.0 g of manganese (IV) oxide in excess hydrochloric acid? The remaining products formed are water and manganese (II) chloride.

36. Find the mass of aluminum chloride produced by 40.0 g of aluminum reacting with excess hydrochloric acid.

FRANCIS LIBERMANN CATHOLIC HIGH SCHOOL Chemistry Unit – Exam Review – Science Department 20


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37. Ammonia gas readily combines with hydrogen chloride to produce a white solid of ammonium chloride. Determine the mass of ammonium chloride produced when 1.00 g of ammonia is reacted with 1.00 g of hydrogen chloride.

38. Find the mass of zinc bromide produced when 1.00 g of zinc reacts with 1.00 g of bromine gas.

39. Sodium reacts violently with chlorine gas to produce solid sodium chloride. What mass of sodium chloride is produced when 0.460 g of sodium is allowed to react with 0.426 g of chlorine gas?

FRANCIS LIBERMANN CATHOLIC HIGH SCHOOL Chemistry Unit – Exam Review – Science Department 21


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Unit 3 – Solutions & Solubility A solution is prepared by dissolving a solute in a solvent. Unless otherwise stated, all solutions are assumed to be aqueous (i.e. the solvent is water). The concentration of a solution is expressed in terms of mol/L or molarity (M). C = concentration (mol/L or M)

C'

n = number of moles V = volume of solution (L)

n'

V'

**This equation ONLY applies to SOLUTIONS!!

When DILUTING a solution, the number of moles of solute remains constant. Only the concentration changes and may be calculated as follows: C iV i = C f V f

**This equation ONLY applies to the DILUTION of a solution!!

A mass/volume percent gives the mass of solute dissolved in a volume of solution, in a percent

A mass/mass percent gives the mass of a solute divided by the mass of solution (expressed as a percent) – also referred to as percent (m/m)

A volume/volume percent (v/v) gives the volume of solute divided by the volume of the solution (expressed as a percent).

The concentration of a very small quantity of a substance in the environment, or the human body, can be expressed in ppm or ppb •

ppm – parts per million (106)

ppb – parts per billion (109)

FRANCIS LIBERMANN CATHOLIC HIGH SCHOOL Chemistry Unit – Exam Review – Science Department 22


(brine) conduct electricity, while a sugar solution does not? 5

6

name: K/U Dissolving

date: a certain solute in water releases heat. Dissolving a different solute in water absorbs heat. Explain why.

40. graph The graph below shows solubilityofofvarious varioussubstances substances plotted against the temperature of the The below shows the the solubility solution. plotted against the temperature of the solution. I

a.) Which substance decreases in solubility as

(a) Which the substance decreases in solubility as the temperature increases?

100

(b) Which substance is least soluble at room

temperature? Which substance is most soluble at room temperature?

b.) Which is least soluble room (c) The solubility ofsubstance which substance is leastataffected temperature? Which substance is most soluble by a change in temperature? at room temperature?

(d) At what temperature is the solubility of potassium

chlorate equal to 40 g/100 g of water?

Solubility (g/100 g H2O)

temperature increases?

(e) 20 mL of a saturated solution of potassium nitrate

at 50˚C is cooled to 20˚C. Approximately what mass of solidc.)will solution? Why is Theprecipitate solubility offrom whichthe substance is least it not possible the graph to interpolate an affectedtobyuse a change in temperature? accurate value? 7

8

NaNO3

90 80

KNO3

70 60

KCI

50 40

NaCI

30 20

KCIO3

10

Ce2(SO3)3 0

I A saturated solution of potassium nitrate was prepared at 70˚C and then cooled to 55˚C. Use your graph from 8-A to predict the fraction d.)Investigation At what temperature is the solubility of of the dissolved solute thatpotassium crystallized out of the to solution. chlorate equal 40 g/100 g of

10 20 30 40 50 60 70 80 90 100 Temperature (˚C)

Unit Issue Prep

water?

Think about how the properties of water affect its behaviour in the environment. Look ahead to the Unit 3 Issue. How could water’s excellent ability as a solvent a problem? what e.) 20 mL of a saturated solution of potassium nitrate at 50°C is cooled to 20°C.become Approximately

Would you expect to find more mineral deposits near a thermal spring or near a cool mountain spring? Explain. MC

mass of solid will precipitate from the solution? Why is it not possible to use the graph to interpolate an accurate value? Chapter 8 Solutions and Their Concentrations • MHR 301

41. A pharmacist adds 2.00mL of distilled water to 4.00g of a powdered drug. The final volume of the solution is 3.00mL. What is the concentration of the drug in g/100mL of solution? What is the percent (m/v) of the solution?

FRANCIS LIBERMANN CATHOLIC HIGH SCHOOL Chemistry Unit – Exam Review – Science Department 23


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42. Many people use a solution of sodium phosphate (Na3PO4 – commonly called TSP), to clean walls before putting up wallpaper. The recommended concentration is 1.7% (m/v). What mass of TSP is needed to make 2.0 L of solution?

43. CaCl2 is used to melt ice on roads. To determine how much CaCl2 has been used, you take a sample of slush to analyze. The sample had a mass of 23.47g. When the solution was evaporated, the residue had a mass of 4.58g. What was the mass/mass percent of CaCl2 in the slush?

44. Rubbing alcohol is commonly used as an antiseptic for small cuts. It is sold as 70.0% (v/v) solution of isopropyl alcohol in water. What volume of isopropyl alcohol is used to make 500.0 mL of rubbing alcohol?

45. A fungus that grows on peanuts produces a deadly toxin. When ingested in large amounts, this toxin destroys the liver and can cause cancer. Any shipment of peanuts that contains more than 25ppb of this dangerous fungus us rejected. A company receives 20t of peanuts to make peanut butter. What is the maximum (in g) of fungus that is allowed?

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46. Calculate the concentration of each of the following solutions: a.) 45.0 g of sulfuric acid in 1.00 L of solution.

b.) 13.0 g of calcium hydroxide in 5.0 L of solution.

c.) 18.0 g of hydrogen nitride dissolved in 75.0 mL of solution.

47. Determine the mass of solute in each of the following solutions: a.) 1.50 L of 0.850 M nitric acid.

b.) 500.0 mL of 0.600 mol/L sucrose.

48. What volume of 0.10 M potassium sulfate solution would contain 57 g of solute?

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49. Complete the following a.) What volume of 0.500 M sulfuric acid would be required to completely neutralize 150.0 mL of 0.200 M magnesium hydroxide?

b.) What is the mass of the salt that is produced by this reaction?

50. Hydrochloric acid is commonly prepared by bubbling gaseous hydrogen chloride into distilled water. How many litres of hydrogen chloride gas at STP are required to prepare 2.00 L of 2.00 M hydrochloric acid?

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51. Determine the volume of 12.0 M phosphoric acid required to prepare 1.0 L of 0.1 M phosphoric acid?

52. 0.150 M sulfuric acid is prepared by adding 5.00 mL of concentrated sulfuric acid to 200.0 mL of distilled water. What was the concentration of the concentrated sulfuric acid?

53. 25.0 mL of a 0.22 mol/L magnesium sulfate solution is diluted to 500.0 mL. Find the new concentration of the solution.

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54. Aqueous solutions that contain silver ions are usually treated with chloride ions to recover silver chloride. What is the minimum volume of 0.25 mol/L magnesium chloride, needed to precipitate all the silver ions in 60.0mL of 0.30 mol/L silver nitrate? Assume that silver chloride is completely insoluble in water.

55. What mass of sodium chloride is formed when 2.8 g of sodium nitrate reacts with 250.0 mL of 0.100 M magnesium chloride?

56. Hydrogen bromide is a gas at room temperature. It is soluble in water, forming hydrobromic acid. Identify the conjugate acid-base pairs.

57. Ammonia is a pungent gas at room temperature. Its main use is in the production of fertilizers and explosives. It is very soluble in water. It forms a basic solution that is used in common products, such as glass cleaners. Identify the conjugate acid-base pairs in the reaction between aqueous ammonia and water.

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58. Write the total ionic equation, net ionic equation and identify the spectator ions for the reaction between magnesium chloride and silver nitrate.

59. For each of the following acids, identify the conjugate base: H2CO3 conjugate base = _______________

HSO3– conjugate base = ________________

60. For each of the following bases, identify the conjugate acid: NO2–

conjugate acid = ________________

F– conjugate acid = ________________

61. Determine the pH of 0.00625 mol of nitric acid dissolved in 250 mL of water.

62. Determine the pH value of the following concentrations: a.) [H3O+] = 2.93×10–10M pH = __________

b.) [H3O+] = 8.04×10–4M pH = __________

63. Determine the [H3O+] of the following solutions: a.) solution with a pH of 2.35 = _____________

b.) solution with a pH of 9.25 = ______________

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Unit 4 – Gases & Atmospheric Chemistry The combined gas law is a combination of Boyle’s Law, Charles’ Law and Gay-Lussac’s Law. Boyle’s Law

Charles’ Law

Gay-Lussac’s Law

P = pressure (atm, kPa, Pa, mmHg, torr.)

V = volume (mL, L, cm3, m3)

T = temperature in Kelvin ALWAYS T = ˚C + 273

Combined Gas Law Where Pressure should be in kPa, Volume in L and Temperature in Kelvin

When there is only one set of conditions given for a gas, use the Ideal Gas Law:

PV = nRT

where R = 8.31 kPa•L/mol•K

STP = Standard Temperature and Pressure, where T = 0˚C and P = 101.3 kPa SATP = Standard Ambient Temperature and Pressure, where T = 25˚C and P = 100 kPa If you have a gas that is NOT at STP, use the following equation:

PV = nRT

where P = pressure in kPa R = 8.31 L•kPa/K•mol

V = volume in L, T = temperature in Kelvin

64. Calculate the molar volume of a gas at 300.0˚C and 450.0kPa.

65. A gas occupies 25.0 L at a pressure of 150.0 kPa and temperature of 205˚C. At what temperature, in in ˚C, will this gas have a volume of 3.6 L and a pressure of 520.0 kPa?

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66. At 25.0˚C, a gas occupies 4.80 L. To what temperature, in ˚C, must the temperature be raised to produce a volume of 6.40 L for this gas?

67. A gas whose volume is 25.0 L at 0˚C and 100.0 kPa has a temperature rasied to 303 K and its pressure lowered to 80.0 kPa. What is the new volume of the gas?

68. If a sample of gas occupies 500.0 mL at STP, what is its volume at 50.0 kPa and 34.0˚C?

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69. What is the pressure of 3.00 mol of a gas in a 2.00 L container at a temperature of 10.0 K?

70. What volume of ammonia gas at 25C and 98.0 kPa is produced when 30.0 g of ammonium phosphate is titrated with 20.0 mL of 2.10 M sodium hydroxide?

71. Calculate the mass of calcium oxide produced when 0.480 g of calcium is reacted with 224 mL of oxygen gas at STP.

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72. A glass bulb contains 1.24 g of a compound in its gaseous phase. At 100.0˚C, it has a volume of 248 mL and an internal pressure of 101.0 kPa. Calculate the molar mass of the gas.

73. Determine the number of moles in 1.2 L of CO2 gas at STP.

74. What is the volume of 9.6 g of H2(g) at STP?

FRANCIS LIBERMANN CATHOLIC HIGH SCHOOL Chemistry Unit – Exam Review – Science Department 33


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