College Algebra Problems College Algebra Problems In mathematics, the term algebra is most widely used to solve various kind of problem. Basically the word algebra is come from Arabic word ‘al-jebr’ which simple mean refer to the “rejoin of broken parts”. Algebra can be considered as a branch of mathematics, in which we generally include the topic to study the rules and regulations of relations and operations. In the simple we can say that algebra is a mathematical concept which solve the problem in the form of mathematical statement by describing the relationship between the different things that are vary over time. In a more understandable form we can say that the concept of algebra is popular for finding the unknown variables in the form of equation. In basic mathematics, the concept of algebra describes the relationship between the variables and numbers. In the same aspect we can say that variables of algebra are used with mathematical operations to get the value of unknown variables. There is an algebraic equation are given below that helps you in understanding the concept of algebra. a+3=5
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In the above mathematical notation we can say that ‘a’ is an unknown variable, which value’s we have to find by applying the various algebraic rules and the above given notation are also known algebraic expression. To solve the algebraic expression and to understand the concept of algebra we need to follow the some of the steps that are given below: a) When we solve the algebraic problem then we first need to identify those variables that are given into the expression. b) form. c)
After completing the above step, we need to translate word problem into mathematical Now we can apply the various mathematical operations to solve the equations.
d) When we solve the algebraic equations, at that time we get the value of unknown variable through which we can determine other unknown values of the problem. e) This step is a optional step which is used for check the correctness of the obtained variables by applying them into algebraic expression. The above given step helps to solve the college algebra problems in a standard manner. Now we are going to solve the algebraic expression by the following given example: Example: Solve the following given algebraic statement to get the value of unknown variable ‘y’? 2 ( y + 3) –y = 2y + 8 Solution: In the above given step we can see that there is an unknown variable ‘y’ which values we need to find out to solve the algebraic expression.
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In the process of solving the college algebra problems we first solve the brackets of the algebraic expression: 2 ( y + 3) –y = 2y + 8 2y + 6 – y = 2y + 8 (here we use the distributive property on the left side of algebraic y + 6 = 2y + 8
expression)
Now we transform the like terms on one side and remaining other side: y + 6 = 2y + 8 Now we perform the subtraction of y in both side: y + 6 – y = 2y + 8 – y 6=y+8 Now we perform the subtraction of 8 in both side, then solution will be: 6–8=y+8-8 -2 = y It means to say that the value of y equal to the value of -2.
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