Math bac ex 3

Page 1

‫ا ا ر م‬ 2x + x − 1 x2 1 • f ( x) = 2 x + 4x + 5 x2 • f ( x) = 4 x + 2x2 + 2 3

• f ( x) =

x+2

x2 + 4x 1 x • f ( x) = + x x2 + 1 4

• f ( x) = • f ( x) =

x2 + 1 +

x2 x2 + 1

• f ( x) = sin x − sin x • f ( x) = cos 2 x + sin 3 x

•

f ( x) = tan 2 x

• f ( x) = sin x + x cos x

•

f ( x) =

• f ( x) =

• f ( x) = f ( x) =

1

x5 + 4 x 2 − 2 3 x

3

: ‫ د ا ÙˆاÙ„ ا ــ ÙˆاÙ„ ا‬ • f ( x) = tan x + tan 3 x

3

•

: ‫ د ا ÙˆاÙ„ ا ــ ÙˆاÙ„ ا‬ x+3 • f ( x) = ( x + 2) 5 x • f ( x) = 4 x +1 x2 + x + 1 • f ( x) = 2 ( x + 1) 2

: ‫ د ا ÙˆاÙ„ ا ــ ÙˆاÙ„ ا‬2 3x + 1 • f ( x) = x +1

• f ( x) = ( x − x ) 2 • f ( x) =

2

‫ا ـــــ Ùˆا Ù„ ا ــ ـــــــ‬

x cos x − sin x x2

• f ( x) =

3

tan 2 x − 2 tan x + 5 cos 2 x 2 x − sin x x 2 + cos x

: ‫ د ا ÙˆاÙ„ ا ــ ÙˆاÙ„ ا‬4 1 • f ( x) = x +1 + x −1 1 1 • f ( x) = − ( a ∈ IR + * ) ax − 1 ax + 1

9− x 3+ x x x + x2 + 1

4x : ‫ ا‬x ‫ ا‬f ‫ ا ا ا د‬5 ( x − 1) 2 a b ∀ x∈ IR − {− 1,1 } f ( x) = + : b ‫ و‬a ‫( د ا د ا‬1 2 ( x − 1) ( x + 1) 2 f ‫ " دا Ø£ ا‬# $‫( ا‬2 f ( x) =

2

2 x3 + 2 x − 3 f ( x) = : ‫ ا‬x ‫ ا‬f ‫ ا ا ا د‬6 x2 + 1 b f ( x) = ax + 2 : b ‫ و‬a ‫( د ا د ا‬1 x +1 0 + # ‫ ا‬#, 1 & '( )* ‫ ا‬f ‫ دا Ø£ ا‬%‫( Ø£ و‬2

‫ ز‬/‫ ــ هـ ــ‬1 : ‫ ـــ) ذ‬$ ‫ا‬


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