Ijeas0210002

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International Journal of Engineering and Applied Sciences (IJEAS) ISSN: 2394-3661, Volume-2, Issue-10, October 2015

On CR-Structure And F-Structure Satisfying Fp1p2 + F = 0 Lakhan Singh, Shailendra Kumar Gautam 

II. NIJENHUIS TENSOR:

Abstract— In this paper, we have studied a relationship

Fpp

1 2 between CR-structure and F-structure satisfying + F=0, where p1 and p2 are twin primes. Nijenhuis tensor and integrability conditions have also been discussed.

Index Terms— Projection operators, distributions, Nijenhuis tensor, integrability conditions and CR-structure.

(2.1)

(2.2) N  X ,Y    FX , FY   F  FX ,Y   F  X , FY   F 2  X ,Y 

I. INTRODUCTION

Theorem (2.1) A necessary and sufficient condition for the F-structure to be integrable is

Let M be an n-dimensional differentiable manifold of class

1.1

N  X ,Y   0

C  . Let F be a non-zero tensor of type (1, 1) and  class C defined on M, such that F p1 p2  F  0 where p1 and p2 are twin primes. Let

 F   r

rank

1.2

l   F p1 p2 1 , m  F p1 p2 1  I

(1.3)

where I is the identity operator on M. Theorem (1.1) Let M be an F- structure satisfying (1.1) Then (a) lmI

 F

Dm

be

the

(2.5)

complementary

2

 F

p1 p2  2

 on both the sides of

F p1 p2 1 l   l ,

Proof: Operating m on both the sides of (2.2) and using (1.4) (a) we get (2.5) (a). Replacing X by

m

Proof: From (1.1), (1.2), (1.3)(a), (b), we get the results.

m N F p1 p2 2 X ,Y  m  F p1 p2 1 X , FY 

 D   n  r F p1 p2 1m  0

m N  X , Y   m  FX , FY 

(a) (b)

Theorem (1.2) Let M be an F-structure satisfying (1.1). Then (a) lF  Fl  F , mF  Fm  0

F p1 p2 2 X

(2.6)

F  1 2  acts on Dl as an almost complex structure and on Dm as a null operator. From (1.4) (b), it is clear that

  FX , FY   F  X ,Y   l  FX ,Y    X , FY .

(2.4) and using (1.2), we get the result. Theorem (2.3) On the F-structure satisfying (1.1)

dim   Dl    r , dim

(b)

p1 p2 2

 FX , FY   F 2  X ,Y   F  FX ,Y    X , FY 

distributions corresponding to the operators l and m respectively. then

(1.4)

vector

& Y on M.

Operating by

Proof: From (1.1) and (1.2), we get the results. and

two

Proof: using theorem (2.1) in (2.2), we get

m m lm  ml  0

Dl

any

(2.4)

2

(d)

for

Theorem (2.2) Let the F-structure satisfying (1.1) be integrable, then

l2  l

(c)

Let

fields X

,

(2.3)

, which is constant

everywhere. We define the operators on M as

(b)

Definifion (2.1) Let X and Y be any two vector fields on M, then their Lie bracket [X, Y] is defined by [X, Y] = XY- YX, and Nijenhuis tensor N(X,Y) of F is defined as

p p 1 / 2

in (2.5) (a), we get (2.5) (b). Theorem (2.4): On the F-structure satisfying (1.1), the following conditions are all equivalent (a) m N  X ,Y   0 (b) m  FX , FY   0

0

(c)

m N F p1 p2 2 X , Y

(d)

m F

(e)

m  F p1 p2 1 lX , FY   0

p1 p2 1

X , FY  0

Proof: Using (1.4) (a), (b) in (2.5) (a), (b), we get the results.

Lakhan Singh, Department of Mathematics, D.J. College, Baraut, Baghpat (U.P.) Shailendra Kumar Gautam, Eshan College of Engineering, Mathura(UP)

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