Cmjv01i06p0766

Page 1

J. Comp. & Math. Sci. Vol. 1 (6), 766-768 (2010)

Fourier Series of log (sin x) in (-L, L) where 0<L<π π RENE RANJAN WILLIAM, N. Ch. S. N. IYENGAR and *CHANDRA SEKHARA REDDY C. School of Computing Science and Engineering, * School of Advanced Sciences VIT University, Vellore -632014,T.N,India nchsniyengar48@gmail.com ,csreddy@vit.ac.in ABSTRACT In this paper we obtain the Fourier Series of log (sin x) in (-L, L), 0<L<π. The properties of the Fourier coefficients so obtained are also highlighted. = log(|sinx|+iβ(x))

INTRODUCTION log(sin x) is a function of special interest since real values of x can generate complex values in log(sin x). For a given value of x, there can be more than one value for log(sin x) other than it’s principle value. The graph of log(sin x) requires four dimensions. The Fourier Series of log(sin x) in (-L, L), 0<L< π is the representation of the function in a periodic form with a period length of 2L. The real and imaginary parts of the function are periodic with the same period and their Fourier Series can be found separately. Preliminaries:

∑ n =0

β nt n n!

=

0<x<L

m∈N

We derive a Fourier Series for the real and imaginary parts separately. First we consider the real part log(| sin x |) . Let the Fourier Series be of the form

f ( x) =

a0 ∞   nπ x   nπ x  + ∑an cos   + bn sin   2 n=1   L   L 

Let a0 = p0+iq0, an = pn+iqn, bn = rn+isn, where po, pn, rn are the Fourier coefficients of log(| sin x |) in (-L, L), 0<L< π and qo ,qn. sn are the Fourier coefficients of β(x) in (-L, L), 0<L< π.

t . The series representation of e −1

1 P0 = ∫ log(| sin x |)dx . L −L since log(| sin x |) is an even function, L

P0 =

t

cot(x) which is convergent in |x| < π, can be expressed with the help of the Bernoulli numbers. cot( x ) =

−L < x < 0

L

Bernoulli numbers Bn can be obtained with the help of the generating function ∞

( 2 m − 1 )π where β ( x ) =  0 

( −1 )n 2 2 n B2 n x 2 n −1 . ( 2n )! n =0 ∞

=

L  2 L  x log(sin x )|0 − ∫ x cot( x )dx  L 0 

=

L ∞ ( −1 )n 22 n B2 n x 2 n −1  2 L log(sin L ) − ( dx   ∫0 ∑ L ( 2n )! n=0 

Solution:

log(sin x ) = log(| sin x | eiβ x )

2 log(sin x )dx L ∫0

Journal of Computer and Mathematical Sciences Vol. 1, Issue 6, 31 October, 2010 Pages (636-765)


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