P CH T C
2020
PH C
PH N II.
P MINH H
PH N III.
THI
PT
PH N I.
LUY N
T
A.H p ch
2O 3
; Al(OH)3 )
n: Al2O3 Al2O3
6H+
+
2OH-
+
Al(OH)3
+ 3H2O
2AlO2-
+ H2O
3H+
+
Al(OH)3
2Al3+
+
OH
-
B.M t s V im TH1:
Al3+
Al3+
+ 3H2O
AlO2-
+ 2H2O
th v 3+
Al2O3 Có tính luõng tính
p ch t ng OHOH- th
k tt
+
3OH-
Al(OH)3 t
3t Al3+
3OH-
+
a Al(OH)3 b TH2:
3a +
Al(OH)3 Có tính luõng tính
OHb
Al(OH)3 a Al[OH]4- (AlO2-.2H2O )
t = a- b
*D
th :
*D
th :
S mol k t t a n S mol k t t a n
(4a a
B
nt OH- =3t
(4a
A
t)
t + x)
a t
nOH- =3t + x
C D
nOH- =4a - t C
x - =4a - t + x nOH
0
0
3t
3a
S mol OH-
4a
th so v
(3t+x)
(3a+ x)
ng h O 2-
V im TH1: +
; Al3+ k tt
V im TH1:
H+ x Al3+
ng OHtr OH th
OHx
+
H2O
3OH-
+
+
OHx
H2O
Al3+ a
+
3OH-
Al(OH)3 a
+
OHb
*D
+
S mol OH-
i tr c t nx ng g p H2SO4 H+ th
+
; ho
)
Al(OH)3 t
H+ + H2O a
+
Al(OH)3 b TH2:
H+ x
3a
H+ + H2O t
+
AlO2-
Al(OH)3 t
3t
Al(OH)3 b TH2:
k tt
AlO2-
-
ng H+
(4a +x)
3H + 3b
Al(OH)3 a
t = a- b
Al3+ + 3 H2O
th :
S mol k t t a n
t = a- b
Al[OH]4- (AlO2-.2H2O ) B a A
C
nt H+ =t
D
nH+ =4a - 3t 0
t
a
(4a -3t)
4a
S mol H+
C cung BC =
cung AB)
-
; AlO2-
ng H+ (
PH N II. ng g p H2SO4
+
) H+ th
k tt
-
+
OH x
+
H x
H2O
AlO2-
+
H+ + H2O t
Al(OH)3 t
OH- + H+ x x AlO2 + H+ + H2O a a Al(OH)3 + 3H + 3b b TH2:
THI
n h p g m Na2 c dung d ch X.Cho t t
-2019).
V im TH1:
*D
P MINH H A
c
nghi Th Kh i c
c ghi
b ng sau: ch HCl (ml) ng k t t a(gam)
bi
:
300 a
2O3
(t l mol t qu
600 a+2,6
ng d n gi i
H2O Al(OH)3 a
t = a- b
4x Na2O 3x Al2O3
H2O
OHAlO2
Al3+ + 3 H2O
HCl
2x -
6x
Al(OH)3 (mol)
th :
S mol k t t a n
B
6x t+ 1 30
C
A t
0
a
2x
0,3
1 ) = (0,6 - 8x)/3 Ta dê có : 8x - (0,3 + 30
B A
0,6
8x
HCl (mol)
x = 0,05
C
t =0,2
a = 15,6 gam m = 27,7 gam
Ch n
t
+
nH =t
O
*
0 nH+ =4a - x3t
B
D
(202-2019). (t+x)
(a+x)
(4a+x -3t)
(4a+x) S mol H+
d
2
t qu
C Th cung
*
A)
c ghi
ch NaOH (ml) ng k t t a(gam)
Kh
nh pg 2O3 trong 200 ml dung ch X .Cho t t dung d ch NaOH 1 M b ng sau: 340 470 2a a- 0,78
c A.4,5.
B.1,65.
C.3,3.
D.3,9.
ng d n gi i Al Al2O3
Al3+
HCl
H+ x
0,4 mol
Al
NaOH
Cl0,4
H2SO4 0,2mol
Al3+ SO42-
NaOH
0,2
H+ x H2
H2 0,075 H2O
Al(OH)3 (mol)
Al(OH)3 (mol)
2t + 0,06 2t + 0,02
(2t + 0,02) 2t
t
t - 0,01 0 0
3(t - 0,01 ) + x
x
Ta dê có: 0,4 - 3(t-0,01) - x = 3.( 0,47 - 0,4) 0,34 = x + 6t
B
nAl2O3
0,34 0,4
0,47
NaOH (mol)
nAl
a 1,56 gam
0,05mol
A.
0,48
NaOH (mol)
0,1mol
3
nh pg
l t qu
c dung d ch X.Cho t t
ch X .Cho t t dung d c ghi b ng sau: ch NaOH (ml) 140 ng k t t a(gam) 2a + 1,56
a 0,2 mol H2SO4 t qu
2
Kh c
; nAl
0,4
x= 0,1 t = 0,02
Ch n D (206-2019).
0,05mol
Ch n D (203-2019). nghi Th
0,28
x + 3t
Ta dê có: 0,4 - (x+3t) = 3.( 0,48 - 0,4) 0,28 = x +3(2t + 0,02)
x= 0,1 t = 0,04
0, 025mol ; nAl
x
.
C. 2 . ng d n gi i
240 a
c ghi b ng sau: Th ch HCl (ml) Kh ng k t t a(gam) c a m A.6,69. B.11,15. 5x 4x
Na Al
Na+
H2O
OHAlO2-
5x x
210 a
ng m
430 a+1,56
C.6,15. ng d n gi i
D.9,80.
HCl
4x
Al(OH)3 (mol)
4x t t - 0,02
0
x
0,21
Ta dê có : 5x -(0,21 - 0,02) = (0,43 - 5x)/3
0,43
5x x = 0,05
HCl (mol)
t =0,16 m = 11,15 gam
Ch n B
A.0,5.
B.1,5.
x =0,1 y = 0,1 t = 0,05
x =0,1 x + 3t = 0,25 x + 4y - t =0,45
5.(201 -2017): nh m Al2O3 trong 200ml dung d ch HCl n a mol/lit c dung d ch X.Cho t t dung d ch NaOH ng k t t a Al(OH)3 (m gam ) ph thu c bi u V di n b th 0 c
100
C.1,0.
250
: a = 2 ch n D
450
6(202 -2017): X g m Al2O3 2 Y.Cho t t dung d Al(OH)3 (m gam ) ph thu c bi u di n b c
D.2,0.
ng d n gi i
nh p c dung d ch m ng k t t a ch
V
th 0
150 350
750
H 2O HCl 0,2.a
Al
H+ x mol NaOH Al3+ y mol Cl- 0,2.a
Al2O3 H2
*D
A.14,40.
B.19,95.
C.29,25.
ng d n gi i
X
th
D.24,60.
Na2O
c:
H 2O
Al2O3
-x
mol
OH AlO2- y mol
H+
X
*D
th
c:
S mol k t t a n
B
S mol k t t a n y t
C A O*
(4y
0
y t
nOH- =3t + x 0
x
nOH- =4a - t + x
(3t+x)
(3y+ x)
(4y +x)
D
t + x) x
(t+x)
(y+x)
(4y+x) S mol H+
(4y+x -3t)
C
S mol OH-
*
Ta di n t
0
th v d ng s mol quen thu
0,1 th so v
s mol OH 0,45
0,25
di n bi
th v d ng s mol quen thu Ta di n t bi n cho NaOH : th so v c
-
A)
di n n V
c 0 .
0,15 0,35
0,75
bao
x =0,1 y = 0,1 t = 0,05
x =0,1 x + 3t = 0,25 x + 4y - t =0,45
Al
Al 0,02 Fe Al2O3 0,045
t0
FexOy
NaOH du
X
toan Al H2 0,03 mol NaAlO2 (Y) 0,11 mol
CO2
Fe (Z) H2SO4
Fe2+
: a = 2 ch n D 7(203 -2017): n ch H2SO4 2 O3 c dung d H2 t dung d ng k t t a Al(OH)3 (m gam ) ph thu c bi u di n b th c
Al(OH)3 0,11 SO2 0,155 mol
h
A.2,34.
B.7,95.
20,76 gam Fe
n
V 0 0,56 C.3,87.
0,24
0,36 D.2,43.
nh pXg m c dung d m t dung d ch HCl 2 ng k t t a Al(OH)3 (m gam ) ph thu c bi u di n b
th
V 0
150 350
750
c
H2 0,022 mol 0,0125.m Al2O3 H O 3 2 x K y Ba m gam
A.10,08. B.3,36. C.1,68. D.5,04. 9 -2018): Th c hi n ph n ng nhi nh pg oxit s c h n h p ch t r c dung d ch Y, ch 2 2 c 8,58 gam k t t a. Cho Z tan h ch H2 SO4 c dung d ch ch a 20,76 gam mu t SO2 n ph m kh 2 6
bi
n ng x B. 8,04. c:
c C. 6,96. ng d n gi i
D. 6,80
+ 96.t = 20,76
Fe = 5, 88 gam m = mFe + mO = 5,88 + 0,045.3.16 = 8,04 gam 10 -2018): H n h p X g m Al2 O3 m 20% kh i ng c c dung d n h t dung d ch g m 0,018 mol H2 SO4 2 . Cho t t c dung d ch Z (ch ch mu h nh pk tt c A. 3,912. B. 3,600. C. 3,090. D. 4,422. ng d n gi i
8(204 -2017): Al2O3
duy nh t c a S A. 7,28.
SO42t mol
Fe3+
Ba2+ AlO2- 0,018 mol H2 SO4 K+ OH0,038 mol HCl
BaSO4
y
Al(OH)3 t mol
2,958 gam
Al3+ SO42K+
Cl- 0,038
Ta d : 233y + 78. t = 2,958 ; 39x + 137 y = 0,575.m x + 2y = 0,044 133,975. m + 4602.t =574,35 (1) n(+) = 0,022.2 + nO. 2 = 0,018.2 + 0,038.1 + 3.t 0,025m 3t = 0,03 (2) T (1)(2) gi i m= 3,6 gam 11 -2018): H n h p X g c dung d n h t dung d ch 2 . Cho t t ch a 0,018 mol H2SO4 c 1,089 gam h n h p k t t dung d ch Z ch ch a 3,335 gam h n h n ng c a kim lo A. 42,33%. B. 37,78%. C. 29,87%. D. 33,12%. ng d n gi i
H2 0,0405 mol
Al Ba
H2O
Na K
Ta d : n(+) = 0,0405.2 = n(-) M nBaSO4 = nBa 29,87 % 12 -2018): Nh t t n ch Ba(OH)2 ch g m Al2 (SO4 )3 3 . S ph thu c c a kh ng k t t mol Ba(OH)2 c bi u di n th ng k t t a c c b c A. 10,11. C. 11,67.
1,089 gam
Al(OH)3 t mol
Ba2+ AlO2- 0,018 mol H2 SO4 K+ OH0,03 mol HCl Na+
m gam
23
BaSO4
Al3+ SO42K+ Cl- 0,03 Na+
0,03 mol H2SO4 Z ch ch a 7,43 gam h n h A. 2,79. B. 3,76.
Al Na x BaO
H2 0,085 mol
BaSO4
H2O Ba2+ AlO2- 0,03 mol H2 SO4 Na+OH0,1 mol HCl
y
m gam
m 0,03 Bao toan S BaSO4 0,03 Al(OH)3
AlCl3
0,03
0,08
x
16x + 51t = 4,11 (2) 233x + 78t = 3,11 (3) ( Kh T 14. -2018): Cho t t n ch Ba(OH)2 ch ch a m gam h n h p Al(NO3 )3 2 (SO4 )3 . S ph thu c c a kh ng k t t mol Ba(OH)2 (x mol) c bi u di n b th c A. 7,68. B. 5,55. C. 12,39. D. 8,55.
m 0,08
AlCl3 0,02
m 6,99 BaSO4 0,03 Al(OH)4-
Bao toan OH
Bao toan OH
V y m = mAl(OH)3 + mBaSO4 = 10,11 gam
3,11 gam
Al3+ SO427,43 gam
ng k t t a ) y 9,33 6,99
0
ng d n gi i
0,01 Al2(SO4)3
Al(OH)3 t mol
Ta d : n(+) = 0,085.2 + 2x = n(-) = 0,03.2 + 0,1 + 3t 2x 3t = - 0,01 (1) : m 16.x + 0,03.96 + 0,1.35,5 + 51.t =3,11 + 7,43 ( kh M
m
ng d n gi i
Ba(OH)2 0,08
x
K+ Cl- 0,1 Na+
0
Ba(OH)2 0,03
2
3,335 gam
B. 6,99. D. 8,55.
0,01 Al2(SO4)3
nh pXg . Cho t t n h t dung d ch ch a c 3,11 gam h n h p k t t ch c C. 6,50. D. 3,60. ng d n gi i
-2018): c dung d ch Y
0,01 Al2(SO4)3 Al(NO3)3
0,04
m 9,33
Ba(OH)2
BaSO4 0,03
x
0,01 Al2(SO4)3
ng d n gi i
BaSO4 0,03
Ba(OH)2
*D
Al(OH)3 0,03
Al(NO3)3 0,01
th
S mol k t t a n
B
Bao toan Al
V y m = mAl2(SO4)3 + mAl(NO3)3 = 5,55 gam 15. -2018): H n h p X g m Al, K, K2 m 10% ng c c dung d kh n h t dung d ch ch a 0,04 mol H2SO4 2 . Cho t t c 4,98 gam h n h p k t t ch Z ch ch a 6,182 gam h n h p c A. 9,592. B. 5,760. C. 5,004. D. 9,596. ng d n gi i Al Na x BaO
H2 0,085 mol
BaSO4
H2O
2
SO4
0
D
0,4
0,55
(4b+0,4 -3.0,15)
*
Ta d thi t l
a = 0,375 b = 0,2 Ch n B
7,43 gam
n h p X g m Ba, ch Y. c 4,302 gam k t t a. 2 c dung d ch Z ch ch a m t ch t tan. M nt t c 3,12 gam k t t c B. 7,09. C. 2,93. D. 5,99.
minh h a 2018]: 2O3
H p th L ck tt CO2 A. 6,79.
ng d n gi i ng k t t a )
bi Ba BaO Al Al2O3
nAl(OH)3
H2O
Ba(HCO3) 2 x
H2 0,04 mol CO2 0,054
OHAlO2- 0,04 Ba2+
0,15
CO2
. B. 0,375..
A)
c:
2.b = 0,4 2.a = 4.b + 0,4 - 3.0,15 17:
AlO2
A. 0,325.
(4b+0,4) S mol H+
C
Al3+ SO42-
Ta d : n(+) = 0,085.2 + 2x = n(-) = 0,03.2 + 0,1 + 3t 2x 3t = - 0,01 (1) M : m 16.x + 0,03.96 + 0,1.35,5 + 51.t =3,11 + 7,43 ( kh
16:
C A O*
3,11 gam
K+ Cl- 0,1 Na+
16x + 51t = 4,11 (2) 233x + 78t = 3,11 (3) ( Kh T
b 0,15
x
Al(OH)3 t mol
Ba2+ AlO2- 0,03 mol H2 SO4 Na+OH0,1 mol HCl
m gam
c:
0 C. 0,400.
0,2
a D. 0,350..
du
nH2SO4
BaCO3
y
Al(OH)3 0,04 4,302 gam Al(OH)3 0,04 mol 3,12 gam
Ta d
c y =0,006 mol ;
B OH
B
H2O
= 0,05 mol ; B
-
= 0,02 mol ng m =5,99 Ch n D
8(MH -2018): dung
n
A. 1,56. (
0,2 V
A. 1,2 0
A. 0,30..
.
B.0,30
.
150 .
C.
c m gam k t t B. 0,39. - 2007)
D. 1,17 3
B .1,8. :(
750 D.
c C. 0,78.
-
C .2. - KA 2008
D.2,4.
A. 0,05 B .0,25 : Cho 3,42 gam Al
C .0,35.
D.0,45.
A. 0,6
C .2,4.
D.3,6.
ng d n gi i th
*D
c:
B .1,2. :
S mol k t t a n
: B y 0,2
C A O* 0
x= 0,15
D 0,55
(4y+0,15 -3.0,2)=0,75
(4y+0,15) S mol H+
C *
Ta d thi t l
c : x = 0,15 ; y = 0,3
PH N III.
A)
Ch n D
PT
: Cho 500 ml dung d ch Ba(OH)2 ch Al2(SO4)3 0,1M; n ng k c 12,045 gam k t t c A. 300. B. 75. C. 200. D. 150 2: Dung d ch X ch a 0,15 mol H2SO4 Al2(SO4)3 . Cho V ml dung d c m gam k t t p 450ml dung d n ng x c 0,5m gam k tt c A. 550,0 ml B. 500,0 ml C. 450,0 ml D. 600,0 m (MH 2018): A. 15,6. B. 7,8 C. 3,9. D. 19,5 (THPTQG 2016): t 0,54 gam Al trong 70 ml dung d ch HCl 1M, thu c dung d ch X. Cho 75 mldung d n ng x y ra
tr l n nh t c t : k tt
- KA n khi ph n c kh i l ng k t
tc : l ng k t t a tr ng A: 200 ml B: 120 ml : n khi ph n c l ng k t t
ch ch a 0,1M c 7,8 gam k t t
ng v i 300 ml dung d ch AlCl3 1 M, l ng t ng v i 150 ml dung d ch Al(NO3)3 0,2 M, tc C: 240 ml D: 180 ml. ch ch c 7,8 gam k t t l n nh t c a V
: Cho 500 ml dung d c m gam ch c B: 1,56 gam C: 2,34 gam D: 1,17 gam. 14: dung d ng v ch AlCl3 0,1 M, l ng k tt n nh : c 15,6 gam k t t n nh tr : Cho 200ml dung d ca gam k t t c A: 7,8 gam B: 1,56 gam C: 2,34 gam D: 1,17 gam. 17 -2007): Nh t t ch AlCl3. Hi ng x t t a keo tr t t a tan. B. ch t t a keo tr ng. t t a keo tr tt k tt
-2007): Tr n dung d ch ch a a mol AlCl3 v i dung d ch ch a b mol NaOH. ck tt l A. a : b = 1 : 4. B. a : b < 1 : 4. C. a : b = 1 : 5. D. a : b > 1 : 4. -2007): Cho 200 ml dung d ch AlCl3 ng v ch ng k t t l n nh t c A. 1,2. B. 1,8. C. 2,4. D. 2. -2007): H n h p X g ch NaOH n ph ng c u ki n, 2 -2008): nh pg ch c a mol h n h ch X. S ch ng k t t c A. 0,40. B. 0,45. C. 0,55. D. 0,60. 2 -2008): ch ch a 0,1 mol n khi ph n c 7,8 gam k t t tr l n nh t c ng k t t A. 0,05. B. 0,45. C. 0,25. D. 0,35. 2 -2008): Cho h n h p g l s n ng x gam ch t r c A. 5,4. B. 7,8. C. 10,8. D. 43,2. -2010): Cho 150 ml dung d ng v i 100 ml dung d ch AlCl3 n c dung d t t a. Lo i b k t t ti p 175 ml dung d c 2,34 gam k t t c A. 1,2. B. 0,8. C. 0,9. D. 1,0 -2010): Dung d ch X ch s mol c a ion Cl ch X ph n ng v i dung d c 2 gam k t t a. Cho 1/2 dung d i ph n ng v i dung d c 3 gam k t t a. M n c n dung d c m gam ch t r c A. 9,21. B. 9,26. C. 8,79. D. 7,47. -2011) Chia h n h p X g n b ng nhau. - Cho ph - Cho ph nh p kim lo d Kh a K, Al, Fe trong m i ph n h n h p X l A. 0,39; 0,54; 1,40. B. 0,78; 1,08; 0,56. C. 0,39; 0,54; 0,56. D. 0,78; 0,54; 1,12. 27 -2011) Cho 400 ml dung d ch E g m AlCl3 2(SO4)3 ng v i 612 ml dung d n ng k c 8,424
gam k t t a. M ng v i dung d ch BaCl2 c 33,552 gam k t t a. T l A. 3 : 4. B. 3 : 2. C. 4 : 3. D. 7 : 4. 28 -2012)Cho 500 ml dung d ch Ba(OH)2 ch Al2 (SO4)3 n ng k c 12,045 gam k t t c A. 300. B. 75. C. 200. D. 150. 29 -2012) n h p g m Na2 c thu 2 O3 c dung d ch X trong su t dung d t u xu t hi n k t t a; khi h t 300 ml ho c a gam k t t a. c 30 -2013)H n h p X g ph n ng x gam X b ng dung d c A. 16,4. B. 29,9. C. 24,5. D. 19,1. 31 -2013) H n h p X g m Na, Ba, Na2 Ba(OH)2. H p th tr c A. 15,76. B. 39,40. 32 -2013)Th
c m gam k t t
C. 21,92. D. 23,64. ch NaOH 0,25M c ng k t t a l n nh A. 210 ml. B. 60 ml. C. 90 ml. D. 180 ml. -2014)Cho m gam h n h p g x tr c A. 3,70. B. 4,85. C. 4,35. D. 6,95. 34 -2014): Khi t t dung NaOH dung a mol HCl b mol AlCl3 q m i mol Al(OH)3 0,4 mol N
l 2,0
2,8
ch
n ng
h u:
A. 4 : 3. B. 2 : 1. C. 1 : 1. D. 2 : 3. 35 -2015): Dung d X g m Al2(SO4)3 0,75M v H2SO4 0,75M. Cho V1 ml dung d KOH 1M v 100ml dung d X, thu c 3,9 gam k t a. M kh khi cho V2 ml dung d ch KOH 1M v 100 ml dung d X c ng thu c 3,9 gam k t a. c ph n ng x y ra ho to n. T V2 : V1 A. 4 : 3. B. 25 : 9. C. 13 : 9. D. 7 : 3. 36 (THPTQG-2015): X CaC2 x mol Al4C3 y mol. Cho X thu H2O 2H2, CH4 3 A. 1 : 2.
B. 5 : 6. (THPTQG-2015): Cho X Ba CuCl2 0,1M.
C. 4 : 3. Na
200 ml dung
D. 3 : 2. Y
HCl 0,1M
A. 1,28. B. 0,64. C. 1,96. D. 0,98. 38.(THPTQG-2016): t 0,54 gam Al trong 70 ml dung d ch HCl c dung d ch X. Cho 75 ml dung d ph n ng x c m gam k t t c A. 1,56. B. 0,39. C. 0,78. D. 1,17. 39.(THI THU QUYNH LUU -2016): Nh t t dung d ch Ba(OH)2 ch A ch a Al2(SO4)3 xM. M i quan h gi a kh ng k t t mol OHc bi u di n b th sau:
N u cho 100ml dung d ch h n h p Ba(OH)2 dung d ch A ng k t t ? A. 5,44 gam B. 4,66 gam C. 5,70 gam 40. (THI THU BGD -2016): Cho m ng h n h ch h n h Al2(SO4)3 c dung d ch X, m gam k t t c A. 14,77. B. 17,1. C. 13,98.
D. 6,22 gam it l n ph n 2 ( D. 13,99.
41: ch HCl 2M thu c dung d ch X. Cho dung d ng v i 320 ml dung d ch NaOH 1M c 4,68 gam k t t c A. 1,89 gam B. 2,7 gam C. 1,62 gam D. 2,16 gam 42.(THI THU DHSPHN -2016): nh pg m c dung d ch ch X b i Yg dung d ch Y, t ng kh c t o ra l A. 12,78g. B. 14,62g. C. 13,70g. D. 18,46g. 43.(THI THU BEN TRE -2016): H n h p X g h nh ng v 2 ch t r nh ng v i dung d ch NaOH c 2 A. 11,36 B. 11,24 C. 10,39 D. 10,64 : Cho 7,65 gam h n h d ch g c dung d 850 ml dung d n ng x c 16,5 gam k t t a g m 2 ch t. M t dung d ch h n h p KOH n khi ng k t t a l n nh t, l c l y k tt n kh c m gam ch t r c a m g n nh t v A. 27,4. B. 46,3. C. 38,6. D. 32,3 .(THI THU BEN TRE -2016): d ch ch c dung d ch Y ch a 2 ch t dung d th sau :
ng v i dung d ch h n h p ch a 0,15b mol FeCl3 mol CuCl2. Sau khi ph n ng k c x gam ch t r c A. 10,874 B. 11,776 C. 12,896 D. 9,864
.(THI THU NGUYEN HUE -2016): 100 ml dung d ch HCl 0,1M, H2SO4 dung d ch NaOH 0,1M; Ba(OH)2 A. 220
2O3
c dung d
trong t ng k t t a l n nh t
2,496
B. 250 12,976 C. 250 14,146 D. 220 12,748 -2018): Th c hi n ph n ng nhi nh pg m gam hai oxit s c h n h p ch t r d c dung d ch Y, ch 2 c 8,58 gam k t t a. Cho Z tan h 2 dung d ch H2 SO4 c dung d ch ch a 20,76 gam mu i sunfat 6
n ph m kh duy nh t c a S
n ng x c A. 7,28. B. 8,04. C. 6,96. D. 6,80 48 -2018): H n h p X g m Al2 O3 m 20% kh ng c c dung d n h t dung d ch g m 0,018 mol 2 . Cho t t H2 SO4 c dung d ch Z (ch ch i mu nh pk tt c A. 3,912. B. 3,600. C. 3,090. D. 4,422. . -2018): H n h p X g c dung d 2 . Cho t t n h t dung d ch ch a 0,018 mol H2SO4 c 1,089 gam h n h p k t t ch Z ch ch a 3,335 gam h n h mu ng c a kim lo i Ba 2
t SO2
A. 42,33%.
B. 37,78%. -2018): Nh t t ch Ba(OH)2 d ch g m Al2 (SO4 )3 3 .S ph thu c c a kh ng k t t a (y mol Ba(OH)2 (x mol) c bi u di n b th i ng k t t a c tr c A. 10,11. B. 6,99. C. 11,67. D. 8,55.
C. 29,87%.
D. 33,12%.
y
m
0
0,03
0,08
x