January 2006
6677 Mechanics M1 Mark Scheme
Question Number
1.
Scheme
Distance after 4 s = 16 x 4 – ½ x 9.8 x 42
(a)
= – 14.4
Marks
M1 A1
h = (+) 14.4 m
A1 (3)
v = 16 – 9.8 x 4
(b)
M1 A1
= –23.2 speed = (+) 23.2 m s–1
A1 (3) 6
2.
(a)
CLM:
3 x 4 + 2 x 1.5 = 5 x v v = 3 m s–1
M1 A1 A1 (3)
(b) (i)
CLM:
3 x 4 – m x 4 = –3 x 2 + m (x 1)
M1 A1
m = 3.6
A1 (3)
(ii)
I = 3.6(4 + 1) [or 3(4 + 2)]
M1 A1
= 18 Ns
(2) 8
1