M1 MS Jun 2009

Page 1

June 2009 6677 Mechanics M1 Mark Scheme Question Number

Scheme

Marks

Q1

45 = 2u + 12 a2 2

45 = 2u + 2a

165 = 6u + 12 a6 2

165 = 6u + 18a

A1 A1

u = 20 and a = 2.5

(a)

tan θ =

p 2p

M1 A1 M1

eliminating either u or a

Q2

M1 A1

[7]

⇒ θ = 26.6°

M1 A1 (2)

R = (i - 3j) + (pi + 2pj) = (1 + p)i + (-3 + 2p)j

M1 A1

(b) DM1

R is parallel to i ⇒ (-3 + 2p) = 0 ⇒ p=

Q3

A1

3 2

(4) [6]

(a)

For A:

(b)

For B:

7mu = 2m(vA − 2u) 2 u vA = 4

M1 A1 A1

7mu = m(vB − −3u) 2 u vB = 2

(3)

M1 A1 A1

(3)

OR

OR CLM: 4mu − 3mu = 2m vB =

u + mvB 4

M1 A1

u 2

8371_9374 GCE Mathematics January 2009

A1

(3) [6]

93


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M1 MS Jun 2009 by The de Ferrers Academy - Issuu