THE FIRST CONSTANT OF SMARANDACHE

Page 1

THE FIRST CONSTANT OF SMARANDACBE

by

Ion Cojocaru and Sonn Cojocaru In this note we prove that the series

f

.,.2

S(I)1 is convergent to a real number s e (0.717 • n.

1.253) that we call the first constant constant of Smarandache. It appears as an open problem, in [1], the study of the nature of the series

f

.,.2

S(1 )1. We n.

can write it as it follows :

-1 + -1 + -1 + -1 + -1 + ... 2!

3!

4!

5!

3!

= -2!1

2 4 14 +-+ -+ -8 + + ...

3!

4!

5!

6!

=

= _2 f a(~) , where a(n) is the number of the equation Sex) = n, n e N, n ~ 2 solutions. n. It results from the equality Sex) = n that x is a divisor ofn!, so a(n) is smaller than den!).

So,

a(n) < d(n!).

(1)

Lemma 1. We have the inequality :

d(n) :5 n - 2, for each n e N, n

Proof. Be n

= P~1 p;2 ... P:"

~

(2)

7.

with P1 • P1' ... , Ilk prime ~umbers, and a, ~ 1 for each i e

e{ 1, 2 •... , k}. We consider the function f: [1, 00) derivable on [1, 00) and f(x) aX In a ~ 2 In a

~

R. £(x) = aX - x - 2, a

= aX In a-I. Because a ~ 2, and x ~

= In al ~ In 4 > In e = 1, i.e., f(x)

~

2, fixed. It is

1 it results that aX

= Pi' i e

Ifn = 2", s e N*, then den)

{1, 2, ... , k}, we obtain p~ ~ aj + 2 for each Pi ~ 3.

= s + 1 < 2" - 2 = n - 2 for s ~ 3.

So we can assume k ~ 2, i.e. P: ~ 3. It results the inequalities : 118

2,

so

> 0 for each x e [1, 00) and a ~ 2, fixed. But

£(1) = a - 3. It results that for a ~ 3 we have £(x) ~ 0, that means all ~ x + 2. Particularly, for a

~


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