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A Complete Resource Book in for JEE Main 2019 chemistry
U.K. Singhal
A.K. Singhal
Dedicated to my grandparents, parents and teachers
Published by Pearson India Education Services Pvt. Ltd, CIN: U72200TN2005PTC057128
No part of this eBook may be used or reproduced in any manner whatsoever without the publisher’s prior written consent.
This eBook may or may not include all assets that were part of the print version. The publisher reserves the right to remove any material in this eBook at any time.
ISBN: eISBN: 9789353062156 9789353063412
Head Office:15th Floor, Tower-B, World Trade Tower, Plot No. 1, Block-C, Sector-16, Noida 201 301, Uttar Pradesh, India.
Registered Office: 4th Floor, Software Block, Elnet Software City, TS-140, Block 2 & 9, Rajiv Gandhi Salai, Taramani, Chennai 600 113, Tamil Nadu, India.
A Complete Resource Book for JEE Main series is a must-have resource for students preparing for JEE Main examination. There are three separate books on Physics, Chemistry, and Mathematics; the main objective of this series is to strengthen the fundamental concepts and prepare students for various engineering entrance examinations. It provides class-tested course material and numerical applications that will supplement any ready material available as student resource.
To ensure high level of accuracy and practicality, this series has been authored by highly qualified and experienced faculties for all three titles.
About the Book
A Complete Resource Book in Chemistry for JEE Main 2018 is an authentic book for all the aspirants preparing for the joint entrance examination (JEE). This title is designed as per the latest JEE Main syllabus, where the important topics are covered in 34 chapters. It has been structured in user friendly approach such that each chapter begins with topic-wise theory, followed by sufficient solved examples and then practice questions.
The chapter end exercises are structured in line with JEE questions; with ample number of questions on single choice correct question (SCQ), multiple-type correct questions (MCQ), assertion and reasoning, column matching, passage based and integer type questions are included for extensive practice. Previous 15 years’ questions of JEE Main and AIEEE are also added in every chapter. Hints and Solutions at the end of every chapter will help the students to evaluate their concepts and numerical applications. Because of its comprehensive and in-depth approach, it will be especially helpful for those students who prefers self-study than going for any classroom teaching.
Series Features
• Complete coverage of topics along with ample number of solved examples.
• Large variety of practice problems with complete solutions.
• Chapter-wise Previous 15 years’ AIEEE/JEE Main questions.
• Fully solved JEE Main 2017 questions.
• 5 Mock Tests based on JEE Main pattern in the book.
• 5 Free Online Mock Tests as per the recent JEE Main pattern.
Despite of our best efforts, some errors may have crept into the book. Constructive comments and suggestions to further improve the book are welcome and shall be acknowledged gratefully. Kindly share your feedback with me at singhal.atul50@yahoo.com or singhal.atul1974@gmail.com.
Acknowledgements
The contentment and ecstasy that accompany the successful completion of any work would remain essentially incomplete if I fail to mention the people whose constant guidance and support has encouraged me.
I am grateful to all my reverend teachers, especially, late J.K. Mishra, D.K. Rastogi, late A.K. Rastogi and my honourable guide, S.K. Agarwala. Their knowledge and wisdom has continued to assist me to present in this work.
I am thankful to my colleagues and friends, Deepak Bhatia, Vikas Kaushik, A.R. Khan, Vipul Agarwal, Ankit Arora (ASO Motion, Kota), Manoj Singhal, Yogesh Sharma, (Director, AVI), Vijay Arora, (Director, Dronacharya), Rajneesh Shukla (Allen, Kota), Anupam Srivastav, Rajeev Jain (M V N), Sandeep Singhal, Chandan Kumar (Mentor, Patna), P.S. Rana (Vidya Mandir, Faridabad).
I am indebted to my father, B.K. Singhal, mother Usha Singhal, brothers, Amit Singhal and Katar Singh, and sister, Ambika, who have been my motivation at every step. Their never-ending affection has provided me with moral support and encouragement while writing this book.
Last but not the least, I wish to express my deepest gratitude to my wife Urmila and my little, —but witty beyond her years, daughters Khushi and Shanvi who always supported me during my work.
A.K. Singhal
Chemistry Trend Analysis (2007
JEE Mains 2018 PaPEr
1. For 1 molal aqueous solution of the following compounds, which one will show the highest freezing point?
(A) [Co(HO)ClO 23 3 ]. 2
(B) [Co(HO)] Cl 26 3
(C) [Co(HO)Cl] Cl .H 25 22 O
(D) [Co(HO)Cl] Cl 24 22.2HO
2. Hydrogen peroxide oxidizes [Fe(CN)] 6 4 to [Fe(CN )] 6 3 in acidic medium but reduces [Fe(CN)] 6 3 to [Fe(CN)] 6 4 in alkaline medium. The other products formed are, respectively:
(A) HO and (HO OH ) 22 + (B) (H O+ 22OO 2 )andH
(C) (H O) and(HO ) 22 2 ++OOH
(D) HO and (HO O) 22 2 +
3. Which of the following compounds will be suitable for Kjeldahl’s method for nitrogen estimation?
7. The increasing order of basicity of the following compounds is: (I)
(II)
4. Glucose on prolonged heating with HI gives: (A) 6-iodohexanal (B) n-Hexane (C) l-Hexene (D) Hexanoic acid
5. An alkali is titrated against an acid with methyl orange as indicator, which of the following is a correct combination?
BaseAcidEnd point
(A)StrongStrongPink to colourless (B)WeakStrongColourless to pink (C)StrongStrongPinkish red to yellow (D)WeakStrongYellow to pinkish red
6. The predominant form of histamine present in human blood is (pKa, Histidine = 6.0)
(A)
(A) (IV) < (II) < (I) < (III)
(B) (I) < (II) < (III) < (IV)
(C) (II) < (I) < (III) < (IV) (D) (II) < (I) < (IV) < (III)
8. Which of the following lines cor rectly show the temperature dependence of equilibrium constant K, for an exothermic reaction?
9. How long (approximate) should water be electrolyzed by passing through 100 amperes current so that the oxygen released can completely burn 27.66 g of diborane?
10. Consider the following reaction and statements:
[C Br ][Co(NH) Br ]NH o(NH 34)Br23 33 3 +−+ → +
(I) Two isomers are produced if the reactant complex ion is a cis-isomer.
(II) Two isomers are produced if the reactant complex ion is a trans-isomer.
(III) Only one isomer is produced if the reactant complex ion is a trans-isomer.
(IV) Only one isomer is produced if the reactant complex ion is a cis-isomer.
The correct statements are:
(A) (II) and (IV) (B) (I) and (II) (C) (I) and (III) (D) (III) and (IV)
11. Phenol reacts with methyl chlorofor mate in the presence of NaOH to form product A. A reacts with Br2 to for m product B. A and B are respectively:
13. At 518°C the rate of decomposition of a sample of gaseous acetaldehyde initially at a pressure of 363 Torr, was 1.00 Torr s-1 when 5% had reacted and 0.5 Torr s -1 when 33% had reacted. The order of the reaction is:
(A) 0 (B) 2
(C) 3 (4) 1
14. The combustion of benzene (1) gives CO2 (g) and H2O (l). Given that heat of combustion of benzene at constant volume is -3263.9 kJ mol-1 at 25°C; heat of combustion (in kJ mol-1) of benzene at constant pressure will be: (R = 8.314 JK-1 mol-1)
(A) -3267.6 (B) 4152.6 (C) -452.46 (D) 3260
15. The ratio of mass percent of C and H of an organic compound (CxHyOz) is 6 : 1. If one molecule of the above compound (CxHyOz) contains half as much oxygen as required to burn one molecule of compound CxHy completely to CO2 and H2O, then empirical formula of compound CxHyOz is:
(A) C2H4O3 (B) C3H6O3 (C) C2H4O (D) C3H4O2
16. The trans-alkenes are for med by the reduction of alkynes with:
(A) BCl3 and AlCl3 (B) PH3 and BCl3 (C) AlCl3 and SiCl4 (D) PH3 and SiCl4
18. When metal ‘M’ is treated with NaOH, a white gelatinous precipitate ‘X’ is obtained, which is soluble in excess of NaOH. Compound ‘X’ when heated strongly gives an oxide which is used in chromatography as an absorbent. The metal ‘M’ is:
(A) Fe (B) Zn (C) Ca (D) Al
19. According to molecular orbital theory, which of the following will not be a viable molecule?
(A) H 2 2 (B) He 2 2 +
12. An aqueous solution contains an unknown concentration of Ba2+. When 50 mL of a 1 M solution of Na2SO4 is added, BaSO4 just begins to precipitate. The final volume is 500 mL. The solubility product of BaSO4 is 1 × 10-10. What is the original concentration of Ba2+?
(A) 1.0 × 10-10 M (B) 5 × 10-9 M (C) 2 × 10-9 M (D) 1.1 × 10-9 M
(C) He 2 + (D) H 2
20. The major product formed in the following reaction is:
21. Phenol on treatment with CO2 in the presence of NaOH followed by acidification produces compound X as the major product. X on treatment with (CH3CO)2O in the presence of catalytic amount of H2SO4 produces: (A)
25. The compound that does not produce nitrogen gas by the thermal decomposition is:
(A) (NH4)2SO4
(B) Ba(N3)2
(C) (NH4)2Cr2O7
(D) NH4NO2
26. An aqueous solution contains 0.10 M H2S and 0.20 M HCl. If the equilibrium constant for the formation of HS- from H2S is 10 10 7 . × and that of S2 from HSions is 12 10 13 × then the concentration of S2 ions in aqueous solution is:
(A) 510 19 × (B) 510 8 ×
(C) 310 20 × (D) 610 21 ×
27. The oxidation states of Cr in Cr(H O) Cl Cr(C H) 26 36 62 [] [] , Cr(H O) Cl Cr(C H) 26 36 62 [] [] , and KCr(CN) (O)(O )(NH) 22 22 3 [] respectively are:
(A) +3, 0 and +4
(B) +3, +4 and +6
(C) +3, +2 and +4
(D) +3, 0 and +6
22. Which of the following compounds contain(s) no covalent bond(s)?
24. The major product of the following reaction is:
28. The recommended concentration of fluoride ion in drinking water is up to 1 ppm as fluoride ion is required to make teeth enamel harder by converting 3Ca(PO ).Ca(OH) 34 22 [] to:
(A) 3Ca(OH) .CaF 22{}
(B) CaF2 []
(C) 3 2 ()CaFCa(OH) 2 []
(D) 3Ca(PO ). CaF 34 22 []
29. Which of the following salts is the most basic in aqueous solution?
(A) Pb(CHCOO)32 (B) Al(CN) 3
(C) CH COOK 3 (D) FeCl3
30. Total number of lone pair of electron in I 3 ion is:
(A) 12 (B) 3
(C) 6 (D) 9
Answer keys
Hints and solutions
1. As DTf ∝ mi. Here m is same so decide by using i The complex giving least number of ions will have lowest depression in freezing point and therefore highest freezing point. Hence, option (A) is correct. (Van’t Hoff factor = 1) Hence, the correct option is (A).
2. In acidic medium, HO22 acts as an oxidant as follows
Oxidation number decreases
Oxidation number
In alkaline medium, HO22 acts as reducing agent as follows
Oxidation number increases
Oxidation number decreases
Hence, the correct option is (D).
3. Kjeldahl’s method cannot be not used in the case of nitro, azo compounds and also to the compounds containing nitrogen in the ring, e.g., Pyridine. Hence, here only CH NH 65 2 is suitable for the test.
Hence, the correct option is (C).
4. Glucose on heating with HI gives n-hexane as followed CHO (CHOH)4 (CH2)4 CH3 CH3 CH2OH
Glucose n-hexane Δ HI
Hence, the correct option is (B).
7. Order of basicity in increasing order is as follows
5. As methyl orange is weak organic base. So it is used in the titration of weak base (NH4OH) vs strong acid (HCl)
MeOH Me OH
Unionized form (Yellow)
Ionized form (Red) +− +
In basic medium, equilibrium lies in backward direction and therefore it shows yellow colour.
In acidic medium, equilibrium shifts in forward direction and therefore, colour changes from yellow to red.
Hence, the correct option is (D).
6. NH3 + N
H N
In it, the N-atoms present in the ring will have same pKa values (6.0), while N atom outside the ring will have different pKa value (pKa > 7.4).
Hence, two N-atoms inside the ring will remain in unprotonated from in human blood as their pKa(6.0) < pH of blood (7.4), while the N-atom outside the ring will remain in protonated from because its pKa > pH of blood (7.4).
Hence, the correct option is (A).
Here (III) is most basic because its conjugate acid is stabilized by equivalent resonance. Out of (I) and (IV), (IV) is more basic due to + I effect of -CH3 group (II) is less basic than (I) and (IV) because N atom is sp2(more s%) hybridized. Hence, the cor rect option is (D).
8. DG° = -RT ln K
DH° -TDS° = -RT ln K
° + ° ∆∆ H RT S R ln K
Here ln K vs 1 T graph will be a straight line with slope equal to °∆ H R . As reaction is exothermic, so°∆ H itself will be negative resulting in positive slope. Hence, the cor rect option is (B).
9. BH OB OH O 26 22 3332+ → +
As according to the balanced equation: Here 2766 26 ., gB H i.e., 1 mole BH26 requires 3 mole of O2. Here this oxygen is produced by electrolysis of water as follows.
22 2 4 22 HO HO F →+
As 1 mole O2 is produced by 4 F charge So 3 mole O2 will be produced by 12 F charge
11. The sequence of the reaction is as follows
Hence, the cor rect option is (D).
12. Ba Na SO BaSO Na mL 2 mL,1M 4 ++ + → + 2 450 4 50 2
For BaSO4 Ksp is given as K(BaSO ) = [Ba ][SO] sp 4 2 4 2+− 10 01 10 2 −+=× [Ba]
Now, calculate [Ba+2] in original solution (450 mL) as follows
10-9 × 500 = 450 × M
MM = × =× =× 10500 450 10 9 10 11110 9 99
Hence, the correct option is (D).
13. CHCHOCOCH
PTorr i 3 363 4 = →+
As we know that, rPRn ∝ (1)
Here PR = reactant pressure n = order of reaction
Now rate of reaction is 1.00 torr s-1, when reactant pressure is 363363 5 100 −×
torr = 344.85 torr.
Similarly rate of reaction is 0.5 torr s-1, when reactant pressure is 363363 33 100 −×
torr = 243.21 torr.
So, applying equation (1) 1 05 34485 24321 =
n 2 = (1.418)n ⇒ 21 418 1 n = ∴ n
2
Hence, the correct option is (B).
14. C6H6 (l) + 15 2 O2 (g) → 6CO2 (g) + 3H2O (l)
Dng = 6 15 2 = 3 2
DH = DU + DngRT
DH = ××
3263900 3 2 8314298.J = -3267616 J = -3267.616 kJ
Hence, the correct option is (A).
15. As ratio of mass percent of C and H in CxHyOz is 6 : 1. So, ratio of mole percent of C and H in CxHyOz will be 1 : 2. Hence, x : y = 1 : 2, which is possible in options (A), (B) and (C).
Now oxygen needed to burn CxHy
CxHy + x y +
4 O2 → xCO2 + y 2 H2O
Now z is half of oxygen atoms needed to burn CxHy here.
2 2 24
Putting on the values of x and y from the given options:
Option (A), x = 2, y = 4 z =+
= 2 4 4 3
Option (B), x = 3, y = 6
=+
= 3 6 4 45 .
Hence, the correct option is (A) (C2H4O3).
16. Na/liq. NH3 reduces alkynes into trans alkene (trans or anti addition).
R C C R C = C R R Na/liq. NH3 trans alkene H H
Hence, the correct option is (D).
17. Here BCl3 and AlCl3 are Lewis acids as both ‘B’ and ‘Al’ has vacant p-orbitals and are e- deficient. SiCl4 is also a Lewis acid as silicon atom has vacant 3d-orbital, so it can accept eHence, the correct option is (A) or (C).
18. Here metal is Al and the reactions are as follows 26 23 22 3 Al HO AlOH H + x +→ () ↓ ()
AlOHNaOHNa Al(OH (Soluble) () () ) 34 +→ []
Hence, the correct option is (D).
19. Species Bond order
(A) H 2 2 B.O. =−[] = 1 2 22 0 (does not exists)
(B) He 2 2 + B.O. =−[] = 1 2 20 1 (exists)
(C) He 2 + B.O. = 1 2 21 05 [] = (exists)
(D) H 2 B.O. =−[] = 1 2 21 05 (exists)
As H 2 has bond order as zero, so it cannot exist. Hence, the correct option is (A).
29. CH3COOK is most basic among the given salts as it gives strong base KOH and weak acid CH3COOH.
Hence, the correct option is (C).
30. I 3 has 3 lone pair e- as follows
Hence, the correct option is (D).
JEE Mains 2017 PaPErs
1. Which of the following compounds will give significant amount of meta product during mono-nitration reaction?
Oxygen (61.4%); carbon (22.9%); hydrogen (10.0%); and nitrogen (2.6%). The weight which a 75 kg person would gain if all 1H atoms are replaced by 2H atoms is:
(A) 15 kg (B) 37.5kg
(C) 7.5 kg (D) 10 kg
8. Which of the following, upon treatment with ter tBuONa followed by addition of bromine water, fails to decolourize the colour of bromine?
2. ∆U is equal to:
(A) Isochoric work (B) Isobaric work (C) Adiabatic work (D) Isothermal work
3. The increasing order of the reactivity of the following halides, for the SN1 reaction is:
(I) CH3CHCH2CH3
Cl
(II) CH3CH2CH2Cl
(III) p—H3CO—C6H4—CH2Cl
(A) (III) < (II) < (I) (B) (II) < (I) < (III) (C) (I) < (III) < (II) (D) (II) < (III) < (I)
4. The radius of the second Bohr orbit for hydrogen atom is:
(Plank’s constant, h = 6.6262 × 10-34 Js; mass of electron = 9.1091 × 10-31 kg; charge of electron, e = 1.60210 × 10-19 C; permittivity of vaccum, ∈0 = 8.854185 × 10-12 kg-1 m -3 A2)
(A) 1.65Å (B) 4.76Å (C) 0.529Å (D) 212Å
5. pKa of a weak acid (HA) and pKb of a weak base (BOH) are 3.2 and 3.4, respectively. The pH of their salt (AB) solution is:
(A) 7.2 (B) 6.9
(C) 7.0 (D) 1.0
6. The formation of which of the following polymers involves hydrolysis reaction?
7. The most abundant elements by mass in the body of a healthy human adult are:
9. In the following reactions, ZnO is respectively acting as a/an:
(a) ZnO + Na2O → Na2ZnO2
(b) ZnO + CO2 → ZnCO3
(A) Base and acid (B) Base and base
(C) Acid and acid (D) Acid and base
10. Both lithium and magnesium display several similar proper ties due to the diagonal relationship; however, the one which is incorrect is:
(A) Both form basic carbonates
(B) Both form soluble bicarbonates
(C) Both form nitrides
(D) Nitrates of both Li and Mg yield NO2 and O2 on heating
11. 3-Methyl-pent-2-ene on reaction with HBr in presence of peroxide forms an addition product. The number of possible stereoisomers for the product is:
(A) Six (B) Zero
(C) Two (D) Four
12. A metal crystallises in a face centred cubic structure. If the edge length of its unit cell is ‘a’, the closest approach between two atoms in metallic crystal will be:
(A) 2a (B) 22a
(C) 2a (D) a 2
13. Two reactions R1 and R2 have identical pre-exponential factors. Activation energy of R1 exceeds that of R2 by 10 kJ mol-1. If k1 and k2 are rate constants for reactions
R1 and R2 respectively at 300 K, then ln(k2/k1) is equal to (R = 8.314 J mol-1K-1):
(A) 8 (B) 12
(C) 6 (D) 4
14. The correct sequence of reagents for the following conversion will be: O CHO CHO HO CH3 CH3 HO
15. The Tyndall effect is observed only when following conditions are satisfied:
(a) The diameter of the dispersed particles is much smaller than the wavelength of the light used.
(b) The diameter of the dispersed particle is not much smaller than the wavelength of the light used.
(c) The refractive indices of the dispersed phase and dispersion medium are almost similar in magnitude.
(d) The refractive indices of the dispersed phase and dispersion medium differ g reatly in magnitude.
(A) (a) and (d) (B) (b) and (d) (C) (a) and (c) (D) (b) and (c)
16. Which of the following compounds will behave as a reducing sugar in an aqueous KOH solution?
(A) CH2OH OCOCH3 HO OH HOH2C O
(B) CH2OH HO OH HOH2C O
(C) CH2OH OCH3 HO OH HOH2C O (D) CH2OH OH OH OH HOH2C O
∆° =− r . HkJmol 1 2858
C; Og HO lCHg Og 22 42 () + () → () + () 22
∆° =+ r 1 HkJm ol8903.
Based on the above ther mochemical equation, the value of DrH° at 298 K for the reaction CH gCHg graphite () () () +→ 2 24 will be:
(A) +74.8 kJ mol-1 (B) +144.0 kJ mol-1
(C) -74.8 kJ mol-1 (D) -144.0 kJ mol-1
18. Which of the following reactions is an example of a redox reaction?
(A) XeFO FXeF O 42 26 2 +→ +
(B) XeFPFXeF PF 25 6 +→ []+
(C) XeFH OXeOFHF 62 4 +→ + 2
(D) XeFH OXeO F4HF 62 2 +→ + 2 2
19. The products obtained when chlorine gas reacts with cold and dilute aqueous NaOH are:
(A) ClOand ClO3
(B) ClOand ClO 23
(C) Cl andClO
(D) Cl andClO 2
20. The major product obtained in the following reaction is: Δ BuOK Br H C6H5 C6H5
(A) () () ± CH CH OBuCHCHH 65 t 26 5
(B) CH CH=CHCH 65 65
(C) + () CH CH OBuCHH 65 t 25 ()
(D) () () CH CH OBuCHC H 65 t 26 5
21. Sodium salt of an organic acid ‘X’ produces effervescence with conc. H2SO4.‘X’ reacts with the acidified aqueous CaCl2 solution to give a white precipitate which decolouriszes acidic solution of KMnO4.‘X’ is:
(A) C6H5COONa (B) HCOONa (C) CH3COONa (D) Na 22CO 4
22. Which of the following species is not paramagnetic?
(A) NO (B) CO (C) O2 (D) B2
23. The freezing point of benzene decreases by 0.45°C when 0.2 g of acetic acid is added to 20 g of benzene. If acetic acid associates to form a dimer in benzene, percentage association of acetic acid in benzene will be:
(Kf for benzene = 5.12 K kg mol-1)
(A) 64.6% (B) 80.4% (C) 74.6% (D) 94.6%
24. Which of the following molecules is least resonance stabilized?
(A) (B) O
(C) N (D) O
25. On treatment of 100 ml of 0.1 M solution of COCl3 6H2O with excess AgNO3; 1.2 × 1022 ions are precipitated. The complex is:
1. Nitration is carried out in presence of concentrated HNO3 and concentrated H2SO4. Here, aniline acts as base, in presence of H2SO4 its protonation takes place and anilinium ion is formed.
Anilinium ion is strongly deactivating group and meta directing in nature so it gives meta nitration product in significant amount. (≈ 97%).
2. Using 1st law:
∆U = q + w
For adiabatic process:
q = 0
So, ∆U = w
Hence work involved in adiabatic process is at the expense of change in internal energy of the system.
3. For SN1 reaction, reactivity is decided by ease of dissociation of alkyl halide
R − X R⊕ + X
Higher the stability of R⊕ (carbocation) higher would be reactivity of SN1 reaction.
As stability of cation follows order.
CH3——CH2——CH2
< CH3——CH——CH2 ——CH3 < p—— H3CO——C6H4——CH2
Hence, the correct order is
II < I < III
(A)
4. Radius of nth Bohr orbit in H-atom = 0.53 n Z 2 Å
Radius of second Bohr orbit = 0532 1 2 .( ) × = 2.12 Å
6. Formation of Nylon6 involves hydrolysis of its monomer (caprolactum) in initial state as follows:
Hydrolysis
Caprolactum
H3N——CH2——CH2——
Δ /Polymerization
Nylon6
7. Mass in the body of a healthy human adult has: Oxygen = 61.4%, carbon = 22.9%, Hydrogen = 10.0% and Nitrogen = 2.6%
Total weight of person = 75 kg
Mass due to 1H is =× = 75 10 100 75.kg
1H atoms are replaced by 2H atoms. Hence, mass gain by person = 7.5 kg
8. Br
tert-BuONa
(fails to decolorize the colour of bromine) (no unsaturation)
tert-BuONa
C6H5 Br O
tert-BuONa Br
C6H5
(it decolorizes bromine solution)
(it decolorizes bromine solution due to unsaturation)
tert-BuONa
(it decolorizes bromine solution due to unsaturation)
9. ZnO is an amphoteric oxide but in given reaction it acts as follows:
(a) ZnO + Na2O → Na2ZnO2 acid base salt
(b) ZnO + CO2 → ZnCO3 base acid salt
10. Mg can form basic carbonate like, 56 7 45 2 2 3 2 2 32 23 Mg CH O MgCO Mg OH HO HCO +−++ →⋅ ⋅↓ + ()
While Li can form only carbonate (Li2CO3) not basic carbonate.
11. +H2O2
5 2 3 4
3-methyl pent-2-ene Anti markownikov product (4 stereo isomers possible due to 2 chiral centres as molecule is asymmetric )
12. In FCC unit cell atoms are in contact along face diagonal.
So, 24aR =
Hence, closest distance (2R) = 2 2 2 aa =
13. Using arrhenius equation, KA e Ea RT =⋅ KA e 1 ERT a 1 =⋅ (1) KA e 2 ERT a 2 =⋅ (2)
So, equation (2)/(l) ⇒= K K e 2 1 (E E RT a1 a 2 )
(As Pre-exponential factors of both reactions in same)
Hence, ln ) , K K (E E RT 2 1 aa 1
= = × = 2 10000 8314300 4
14. O O
[Ag(NH3)2]OH Tollens reagent O C
H+/CH3OH (esterification)
15. It is factual.
16. (i) Ester in presence of aqueous KOH solution give SNAE reaction so following reaction takes place.
Aq. KOH Reagent Tollen’s Ring opening
+ Me—C—O
HOCH2 O ⊕ ve silver mirror test
(ii) In above compound, in presence of aq. KOH (SNAE) reaction takes place and a-Hydroxy carbonyl compound is formed which gives ⊕ve Tollen’s test. So this compound behaves as a reducing sugar in an aqueous KOH solution.
17. C; ? r Og HO lCHg Og H H 22 42 f () + () → () + () ∆° = ∆° 22 8903 3935285 80 ∆∆ ∆ rr products rreactant HH H °= °− ° ∑ ∑ ()() 890 31 20 1393 52 2858 ..
∆° () =− =− f CH HkJ/mol 4 8903965 1748
18. XeFO FX eF O 42 26 2 ++ + +→ + 41 6 0
Here, xenon undergoes oxidation while oxygen undergoes reduction. (Redox Process)
NO(15e-) ⇒ One unpaired electron is present in π * molecular orbital. (Paramagnetic)
CO(14e-) ⇒ No unpaired electron is present (Diamagnetic)
O2 (16) ⇒ Two unpaired electrons are present in π * Molecular orbitals. (Paramagnetic)
B2(10) ⇒ Two unpaired electros are present in π bonding molecular orbitals. (Paramagnetic)
23. In benzene acetic acid dimerises as follows: 2 2 CH COOH CH COOH 33()
Percentage degree of association = 94.5%
24. (D) O is nonaromatic (non-planar) and hence least reasonance stabilized.
(A) Benzene is aromatic (6πe -) (B) O furan is aromatic (6πe -)
(C) N pyridine is aromatic (6πe -)
25. Moles of complex Molarity volumeml = × () 1000 = × = 100 01 1000 001 . .mole Moles of ions precipitated with excess of AgNO3 = × × 12 10 60210 22 23 . = 002.moles
C6H5
C6H5
C6H5
C6H5
Number of Cl present in ionization sphere =
Mole of ionprecipitatedwith exessAgNO Mole of complex 3 = 002 0011 2 =
It means 2Cl ions present in ionization sphere. Hence, complex is [CO(H2O)5Cl]Cl2 . H2O
26. DIBAL–H is electrophilic reducing agent which reduces cynide, esters, lactone, amide, carboxylic acid into corresponding aldehyde (partial reduction).
27. NO3 : The maximum limit of nitrate in drinking water can be 50 ppm. Excess nitrate in drinking water can cause diseases like methemoglobinemia, etc.
SO 4 2 : above 500 ppm of SO 4 2 ion in drinking water causes laxative effect otherwise at moderate levels it is normally harmless.
F : Above 2 ppm concentration of F in drinking water causes brown mottling of teeth.
Hence, the concentration given in question of SO 4 2 and NO3 in water is suitable for drinking but the concentration of F (i.e., 10 ppm) makes water unsuitable for drinking purpose.
28. Given chemical equation MCO2HCl2MClH OCO 23 22 +→ ++ 1 gm 0.01186 mol
⇒ from the balanced chemical equation. 1 M 0.01186 =
⇒=M84.3 gm/mol
29.
As Cr+3 is having least reducing potential, so Cr is the best reducing agent here.
30. ions O-2 F- N
+ Mg+2 Atomic number = 8 9 11 12
Number of e = 10 10 10 10
O, F, Na ,Mg 2+ +2 are isoelectronic species here.
