M
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14
0
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14
105 103 3
6
Molarity of unknown =
vinegar Molarity =
molarity of known x liters of known liters of unknown
(NaOH Molarity)(NaOH volume) vinegar volume
60 grams acetic acid 180 g acetic acid 3 moles acetic acid 1 liter solution x x = = 18% Liter solution 1 mole acetic acid 1000 grams solution 1000 g solution
common name stomach acid
name hydrochloric acid
lye milk of magnesia
HCl
hydrofluoric acid
HF
hydrobromic acid
HBr
hydrioidic acid
vinegar
formula
HI
nitric acid
HNO3
sulfuric acid
H2SO4
phosphoric acid
H3PO4
acetic acid sodium hydroxide
CH3CO2H NaOH
magnesium hydroxide
Mg(OH)2
calcium hydroxide
Ca(OH)2
ammonia triethylamine
NH3 (CH3CH2)3N
[H+][OH-] = 10-14 Enter 10^-14/1.66E-4
pH 3.78 [H+] = 10-pH
Enter 10^-3.78
[H+]
pOH
[OH-]
Acid or base? Example
1.66 x 10-4
10.22
6.0 x 10-11
Acid Orange juice
pH + pOH = 14 Enter 14-3.78
Use the change sign (-) button, not the subtract button
pH>7 = base pH<7 = acid