unit 15 for issuu march 10 2012

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105 10 3

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Molarity of unknown =

vinegar Molarity =

molarity of known x liters of known liters of unknown

(NaOH Molarity)(NaOH volume) vinegar volume


60 grams acetic acid 180 g acetic acid 3 moles acetic acid 1 liter solution x x = = 18% Liter solution 1 mole acetic acid 1000 grams solution 1000 g solution





common name stomach acid

name hydrochloric acid

HF

hydrobromic acid

HBr

milk of magnesia

HI

nitric acid

HNO3

sulfuric acid

H2SO4

phosphoric acid lye

HCl

hydrofluoric acid hydrioidic acid

vinegar

formula

acetic acid sodium hydroxide

H3PO4 CH3CO2H NaOH

magnesium hydroxide

Mg(OH)2

calcium hydroxide

Ca(OH)2

ammonia triethylamine

NH3 (CH3CH2)3N



[H+][OH-] = 10-14 Enter 10^-14/1.66E-4

pH 3.78 [H+] = 10-pH

Enter 10^-3.78

[H+]

pOH

[OH-]

Acid or base? Example

1.66 x 10-4

10.22

6.0 x 10-11

Acid Orange juice

pH + pOH = 14 Enter 14-3.78

Use the change sign (-) button, not the subtract button

pH>7 = base pH<7 = acid



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