Manish Kumar Mishra et al. / (IJAEST) INTERNATIONAL JOURNAL OF ADVANCED ENGINEERING SCIENCES AND TECHNOLOGIES Vol No. 1, Issue No. 2, 123 - 129
An application of Fixed Point Theorems in Fuzzy Metric Spaces ( AFPTFMS) Manish Kumar Mishra and Deo Brat Ojha
mkm2781@rediffmail.com, deobratojha@rediffmail.com
T
Department of Mathematics R.K.G.Institute of Technology Ghaziabad,U.P.,INDIA
Abstract— The aim of this paper is to present common fixed point theorem in fuzzy metric spaces, for four self maps, satisfying implicit relations with Integral Type Inequality. Also, the application of fixed points is studied for the Product spaces.
Recently in 2006, Jungck and Rhoades [13] introduced the concept of
Keywords- Fuzzy metric space, -chainable fuzzy metric space, compatible mappings, weakly compatible mappings, implicit relation and common fixed point.
Grabiec[14] followed Kramosil and Michalek[9] and he obtained the
.
the concept of
weakly compatible maps which were found to be more generalized than compatible maps.
ES
INTRODUCTION
version of
Banach contraction principle.
Recently in 2000, B.Singh and M.S.Chauhan[15] brought forward proved some
I.
fuzzy
compatibility in fuzzy metric space. Popa[16]
fixed point
theorems
for
weakly compatible
noncontinous mappings using implicit relations. His work was
Fuzzy set has been defined by Zadeh [1]. Kramosil and Michalek
extended by Imdad[17] who used implicit relations for coincidence
[2],introduced the concept of fuzzy metric space, many authors
commuting property. Singh and Jain[18] extended the result of
extended their views as some George and veera mani [3], Grabiec
Popa[16] in fuzzy metric spaces and Rana[21] proved fixed point
[4], Subramanyan [5],Vasuki[6]. Pant and Jha [7] obtained some
theorems in fuzzy metric space using implicit relation. This paper offers the fixed point theorems on fuzzy
was developed extensively by many authors and used in various
metric spaces, which generalize, extend and fuzzify several known
fields. In 1986 Jungck [8] introduced the notion of compatible maps
fixed point theorems for compatible maps on metric space, by
for a pair of self maps. Several papers have come up involving
making use of implicit relations with Integral Type Inequality . The
compatible maps in proving the existence of common fixed points
condition of - chainable fuzzy metric are characterized to get
both in the classical and fuzzy metric space.
common fixed points. One of its corollaries is applied to obtain
The theory of fixed point equations is one of the preeminent basic
fixed point theorem on product of FM spaces.
IJ A
analogous results proved by Balasubramaniam et al. subsequently, it
tools to handle various physical formulations. Fixed point theorems in
II.
fuzzy mathematics has got a direction of vigorous hope
and vital trust with the study of Kramosil and Michalek[9], who introduced the concept of fuzzy metric space. Later on, this concept of fuzzy metric space was modified by George and Veeramani[10 ]. Sessa[11]
initiated
the
tradition of
improving commutative
condition in fixed point theorems by introducing the notion of weak commuting
property
.
Further,
Jungck[12]
gave
a
more
generalized condition defined as compatibility in metric spaces.
ISSN: 2230-7818
PRELIMINARIES
Definition 2.1 A binary operation :[0,1] [0,1] [0,1] is a continuous t – norm if it satisfies the following conditions:
is communicative and associative; II. is continuous; I.
III. a a = a for all a 0,1 ;
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Manish Kumar Mishra et al. / (IJAEST) INTERNATIONAL JOURNAL OF ADVANCED ENGINEERING SCIENCES AND TECHNOLOGIES Vol No. 1, Issue No. 2, 123 - 129
a b c d whenever a c a, b, c, d [0,1]
IV.
and
b d and
Examples of continuous t-norm are
such that
a b ab and
I.
c)
II. a b min a, b . X , M ,
Definition 2.2 A 3-tuple metric space, if X is an arbitrary set,
is called a fuzzy
is a continuous t2 X (0,) . Satisfying the norm and M is a fuzzy set on following conditions for each x,y,z X,s,t 0 , M x, y, t 0
I.
III.
;
is continuous.
by
a b ab or t M x, y , t t d x, y
be a metric space and let
a, b min{a, b} and let
.
x, y X and t 0. Then X , M , is a fuzzy metric M, induced by d is called the standard fuzzy metric. Definition 2.5 : Let a)
X , M ,
be a fuzzy metric space. Then
x a sequence n in
X is said to converges to x in X if for each 0 and each t 0 , there exists M xn , x, t 1 n0 N n n0 .
such that
for all
It was proved by George and Veeramani[4] that a sequence
xn in fuzzy metric space X , M , converges to a point x X , if and only if M xn , x, t 1 , for all t 0 .
ISSN: 2230-7818
n
for some
If the self mapping
A and
X , M , are compatible , then
but its converse is not true.
X
such
that
x in X .
B of a fuzzy metric space they are weakly compatible
Example 2.1: Let X [0,8] and a * b min{a, b} . Let M be the standard fuzzy metric induced by d, where
d ( x, y) x y
IJ A
Let
X , M , are called compatible if n xn is a sequence in whenever
B of a fuzzy metric space X , M , are called weakly compatible if ABx BAx, when Ax Bx for some x X .
0 r 1 , defined B x, r , t { y X ; M x, y, t 1 r}.
X,d
f and g of a fuzzy metric space lim M fgx, gfx, t 1
ES
an
Two self mappings
Two self maps A and
X , M , be a metric space. For t 0 there exists B x, r , t open ball with center x X and radius Let
Definition 2.7
n
;
M x, y,. : 0, [0,1]
V.
A fuzzy metric space in which every Cauchy sequence is convergent is said to be complete.
Definition 2.8 :
M x, y, t M y, z, s M x, z, t s
IV.
.
T
M x, y, t M y, x, t
for all
lim fxn lim gxn x
M x, y, t 1if and only if x y
II.
xn in
X is said to be Cauchy if for n N each 0 and each t 0 , there exists 0 M xn , xm , t 1 n, m n0
b) a sequence
for
x, y X .
Define two self maps
X , M , as follows:
A and
8 x 0 x 4 Ax , 4 x8 8
B of a fuzzy metric 0 x4 4 x8
x Bx 8
x 1 1/ n
Let us consider n , then [A,B] is proved to be not compatible but is weakly compatible. Let
X , M , is called
finite sequence
a metric space and let
x x0 , x1 , x2 , x3 ......xn y
0. A
is called to be
- chain from x to y if M xi , xi 1 , t 1 t 0, and i 1, 2,3.......n . A fuzzy metric space
if for all
X , M , is called as - chainable
x, y X , there exists a - chain from x to y.
Lemma 2.9
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for all
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Manish Kumar Mishra et al. / (IJAEST) INTERNATIONAL JOURNAL OF ADVANCED ENGINEERING SCIENCES AND TECHNOLOGIES Vol No. 1, Issue No. 2, 123 - 129
X , M , be a fuzzy metric space. If there exists k 0,1 M x, y, qt M x, y, t such that for all
Example 2.2
Let
x, y X and t 0 , then x y .
Then for all
Let
u, v 0, F u, v, u, v,1 0
F u, v, u, v,1 0
b)
F u,1, u,1, u 0
or
implies that
2. 3. 4.
d ( x, y )
(t )dt (t )dt , y x , 0 0 X , Where ; R R is a lebesgue integrable mapping which is nonnegative
0, (t )dt 0 0
and
such
that,
for
each
. Then f has a unique common fixed
lim f x z.
IJ A
z X such that for each x X ,
n
n
Rhoades[20], extended this result by replacing the above condition by the following d ( fx , fy )
0
1 max{d ( x , y ), d ( x , fx ), d ( y , fy ), [ d ( x , fy ) d ( y , fx )] 2 0
(t )dt
(t )dt
Ojha et al.[19] Let ( X , d ) be a metric space and let f : X X , F : X CB( X ) be a single and a f and F are multi-valued map respectively, suppose that occasionally weakly inequality
The pairs compatible.
T X
commutative (OWC) and satisfy the
J ( Fx , Fy )
0
(t ) dt
ad ( fx , fy ) d P1 ( fx , Fx ), ad ( fx , fy ) P1 P 1 max d ( fy , Fy ), ad ( fx , Fx ) d ( fy , Fy ), cd P1 ( fx , Fy ) d ( fy , Fx )
0
for all x , y in X ,where p 2 is an integer a 0 and 0 c 1 then f and F have unique common fixed point in X.
ISSN: 2230-7818
SX
or
0
are
weakly
is complete.
k 0,1
such that
F M Ax , By , qt , M Sx ,Ty ,t , M Ax , Sx ,t , M By ,Ty ,t , M Ax ,Ty ,t
(t )dt 0
x , y X and t 0 , then A, B, S and T have a unique common fixed point in X .
for every
x0
Proof:Let
be
any
arbitrary
point.
As,
AX TX , BX SX x , x X , such that Ax0 Tx1 and so, there exists 1 2 yn Bx1 Sx2
xn
Inductively, we construct the sequences
and
X , such that y2 n Ax2 n Tx2 n1 and y2n1 Sx2n2 Bx2 n1 for n 0,1, 2,.... now , using in
condition (iv) with
x x2 n , y x2 n1 , we get
F M Ax2 n , Bx2 n1 , kt , M Sx2 n ,Tx2 n1 ,t , M Ax2 n , Sx2 n ,t , M Bx2 n1 ,Tx2 n1 ,t , M Ax2 n ,Tx2 n1 ,t
0
(t )dt 0
That is
F M y2 n , y2 n1 , kt , M y2 n1 , y2 n ,t , M y2 n , y2 n1 ,t , M y2 n1 , y2 n ,t , M y2 n , y2 n ,t
0
(t )dt 0
That is
F M y2 n , y2 n1 , kt , M y2 n1 , y2 n ,t , M y2 n , y2 n1 ,t , M y2 n1 , y2 n ,t
0
(t )dt 0
Using condition (a), we have M y2 n , y2 n1 , kt
(t ) dt
B, S
and
there exists
0
P
-chainable fuzzy metric
ES
d ( fx , fy )
AX TX and BX SX A, T
1.
u 1.
implies that
be a complete
satisfying the following conditions:
or
(X,d ) be a complete metric space, [0,1], f : X X a mapping such that for each
X , M ,
uv
F u, u,1,1, u 0
MAIN RESULTS
space and let A, B, S and T be self-mappings of X ,
Let
summable,
,then
Theorem 3.1 : Let
A Class of implicit relations: be the set of all real 5 F: R R and continuous functions: , nondecreasing in first argument satisfying the following conditions: For
III.
T
X , M , be a fuzzy metric space. x, y X , M x, y,. is non-deceasing. Let
a)
f t1 , t2 , t3 , t4 , t5 20t1 9t2 6t3 7t4 t5 1
F .
Lemma 2.9
Let’s consider
(t )dt
0
M y2 n , y2 n1 , kt
That is, 0 Similarly, we have
M y2 n , y2 n1 ,t M y2 n , y2 n ,t
M y2 n , y2 n2 , kt
0
(t )dt
(t )dt
M y2 n , y2 n1 ,t
0
M y2 n1 , y2 n ,t
0
(t )dt
(t ) dt
(t )dt
There fore, for all n even or odd, we have
M yn , yn1 , kt
0
(t )dt
M yn , yn1 ,t
0
(t ) dt
Thus, for any n and t, we have
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Manish Kumar Mishra et al. / (IJAEST) INTERNATIONAL JOURNAL OF ADVANCED ENGINEERING SCIENCES AND TECHNOLOGIES Vol No. 1, Issue No. 2, 123 - 129
(t )dt
0
M yn , yn1 ,t
0
Hence
(t ) dt
z Bu{ B S , z Bu S , z Bu Su say } Therefore, z Bu Su Tu .
y To prove that n is a Cauchy sequence, we have M yn , yn1 , t
0
M
(t )dt
yn1 , yn2 ,t / k 2
0
M yn , yn1 , t / k
0
Now
(t )dt
(t ) dt
M
y1 , y0 ,t / k n
0
yn , yn p1 , t
0
(t ) dt
M
(t ) dt 1
yn , yn p , t / 2 *M yn1 , yn p1 ,t / 2
0
(t ) dt 1*1 1
Thus, the result holds for m p 1 . Hence,
yn
is a Cauchy
yn
sequence in X, which is complete. Therefore converges y z n , for some z X . So, it follows that to z, such that Ax2n ,Sx2n ,Bx2n1 and Tx2n1 also converges to z. To xn is a Cauchy sequence. prove
M ym , ym1 , t
0
(t )dt 1
we have
M xn , xn1 ,t
0
(t )dt
for all t 0 and i 1, 2,.......m . Thus
M y1 , y2 ,t / l M y2 , y3 ,t / l .......M ym1 , ym ,t / m
0
m n,
0
(t )dt
F M z , Bz , kt , M z ,Tz ,t , M z , z ,t , M Bz ,Tz ,t , M z ,Tz ,t
0
(t )dt 0
Since, F is nondecreasing in the first argument, as well as
z Tz , since z T X , so we have
F M z , Bu ,t , M z , z ,t ,1, M Bz , z ,t , M z , z ,t
0
F M z , Bu ,t ,1,1, M Bz , z ,t ,1
0
That is ,
(t )dt 0
(t ) dt 0
F M z , Bz ,t
0
(t )dt 1
by (b)
Hence , z Bz Therefore, z Bz Tz . Step III: As,
BX SX let there exists v X , such
z Bz Sv x v, y z in (iv), Put
that
F M Av , Bz , kt , M Sv ,Tz ,t , M Av , Sv ,t , M Bz ,Tz ,t , M Av ,Tz ,t
0
(t )dt 0
That is,
F M Av , z , kt ,1, M Av , z ,t ,1, M Av , z ,t
0
(t )dt 0
Since, F is nondecreasing in the first argument, we have
M xn , xn1 ,t / m n M xn1 , xn2 ,t / m n .......*M xm1 , xm ,t / m n
IJ A
M xn , xm ,t
(t )dt
1 * 1 * 1 .........* 1 1
For
Step II : Put x x2n and y z we get taking Lim n ,we get
ES
-chainable, so -chain Since X x x from n to n 1 that is, there exists a finite sequence xn y1 , y2 ,......... yn xn 1 such that
B, S is weakly compatible, so BSu SBu , thereby,
Bz Sz.
as n . Thus, the result holds for m=1. By introduction hypothesis suppose that result holds for m p. Now, M
,
T
M yn , yn1 , kt
0
(t )dt
1 * 1 * 1 .........* 1 1
xn is a Cauchy sequence in X, which is complete. xn converges to z X . Hence its subsequences Therefore Ax2n ,Sx2n ,Bx2n1 and Tx2n1 also converges to z.
Hence,
T X
F M Av , z ,t ,1, M Av , z ,t ,1, M Av , z ,t
0
That is,
F M Av , z ,t
0
(t )dt 0
(t )dt 1
…{by (b)}.
z Av So, . Now A T z Av T or z Av Tv .
Therefore, Now as, such
since,
z Av Tv .
A, T is
weakly compatible, so
ATv TAv ,
is complete. z T X If we take , so there exists u X , such that z Tu . x x and y u in (iv), so 2n Step I : Put
that Az Tz . So, combining all the results, we have
Step IV: Put x Sz and in (iv), we get As F is non decreasing in the first argument, we have
Case I:
F M Ax2 n , Bu , kt , M Sx2 n ,Tu ,t , M Ax2 n , Sx2 n ,t , M Bu ,Tu ,t , M Ax2 n ,Tu ,t
0
taking Lim
(t )dt 0
n ,we get
F M z , Bu , kt , M z ,Tu ,t , M z , z ,t , M Bz ,Tz ,t , M z ,Tz ,t
0
0
So,
F M z , Bu ,t
0
(t ) dt 0
yz
F M ASz , Bz , kt , M SSz ,Tz ,t , M ASz , SSz ,t ,M Bz ,Tz ,t ,M ASz ,Tz ,t
(t )dt 0
Since, F is nondecreasing in the first argument, so F M z , Bu ,t ,1,1, M Bu ,u ,t ,1
Az Tz Bz Sz z .
F F 0
M Az , z , kt , M Sz , z ,t , M Az , Sz ,t , M z , z ,t , M Az , z ,t
0
M Az , z , kt , M z , z ,t , M Az , z ,t , M z , z ,t , M Az , z ,t
0
(t ) dt 1
ISSN: 2230-7818
by (b)
(t )dt 0
(t )dt 0
(t )dt 0
Since, F is nondecreasing in the first argument, we have
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Manish Kumar Mishra et al. / (IJAEST) INTERNATIONAL JOURNAL OF ADVANCED ENGINEERING SCIENCES AND TECHNOLOGIES Vol No. 1, Issue No. 2, 123 - 129 F M Az , z ,t ,1, M Az , z ,t ,1, M Az , z ,t
F M Az , z ,t
0
0
(t ) dt 0
0
by b
(t ) dt 1
Therefore,
Az z . Similarly, we can show that Bz z, Tz z, and Sz z Hence Az Tz Bz Sz z Case II:
SX
If we take
is complete.
zS X
, so there exists w X w X , such
that, z Tw . The proof is likewise as in Case I. So, similarly, we can
Az z , Bz z, Tz z, and Sz z . Hence Az Tz Bz Sz z . Thus, z is the common fixed point of A, B, S and T . show that
Uniqueness: Let w and z be two common fixed points of maps get
A, B, S and T . Put x z and y w in (iv), we
F M Az , Bw , kt , M Sz ,Tw ,t , M Az , Sz ,t , M Bw ,Tw ,t ,M Az ,Tw ,t
0
(t )dt 0
x, y X and t 0 .Then A and T have a unique common fixed point in X . X , M , Corollary 2.2 Let
be a complete
F M z , w , kt , M z , w ,t , M z , z ,t , M w , w ,t , M z , w ,t
0
(t )dt 0
Since, F is a nondecreasing, in the first argument, therefore, we have
F M z , w,t , M z , w,t ,1,1, M z , w,t
0
(t )dt 0
exists
, such that
F M Ax , By , kt , M Sx ,Ty ,t , M Ax , Sx ,t , M Sx , By ,2t , M By ,Ty ,t , M Ty , Ax ,t
0
x, y X and t 0 .Then A, B, S and T have a unique common fixed point in X . Proof: From definition, we have
F M Sx ,Ty ,t , M Ax , Sx ,t , M By ,Ty ,t , M By , Sx ,2 t , M Ax ,Ty ,t
0
F M Sx ,Ty ,t , M Ax , Sx ,t , M By ,Ty ,t , M Sx ,Ty ,t , M Ty , By ,t , M Ax ,Ty ,t
F M Sx ,Ty ,t , M Ax , Sx ,t , M By ,Ty ,t , M Ax ,Ty ,t
0
Corollary 2.3:
says that the pair
for every ,
IJ A
Axn Txn1 .
Remark 2.2: If S = T and A = B, then conditions (i)- (iii)
A, T and B, S are weakly says that the pairs A X B X T X compatible and so, and hence the Ax2n Tx2 n 1
sequences exists as follows: and Bx2n 1 Sx2n 2 . Theorem 2.1 with S = T = Identity map is: Corollary 2.1: Let
X , M ,
be a complete
-chainable
A, B, S and T be self-mappings of fuzzy metric space and let X , satisfying (i), (ii) and (iii) of Theorem 2.1 and there k 0,1 exists
, such that
, such that
M Ax , By , kt
0
(t )dt
M Sx ,Ty ,t
0
(t )dt
x, y X and t 0 .Then A, B, S and T have a unique common fixed point in X . Proof: As , we have
M Sx ,Ty ,t
0
(t ) dt
M Sx ,Ty ,t *1
0
M Sx ,Ty ,t *M Ax , Ax ,5 t
0
(t ) dtM
(t ) dt
M Sx ,Ty ,t *M Ax , Sx ,t *M Sx , By ,2 t *M By ,Ty ,t , M Ty , Ax ,t
0
and hence from Corollary 2.2, unique common fixed point in X. Corollary 2.4:
(t )dt
A, B, S and T , we have a
A and B be self-mappings of X , k 0,1
which satisfies the condition M Ax , By , kt
(t ) dt
X , M , be a complete -chainable
Let
fuzzy metric space and let
0
ISSN: 2230-7818
A, B, S and T be self-mappings of
X , satisfying (i), (ii) and (iii) of Theorem 2.1 and there k 0,1
AX TX . In such a situation, the sequence occurs as
(t ) dt
X , M , be a complete -chainable
Let
fuzzy metric space and let
weakly compatible and
(t ) dt
A, B, S and T , we have a
and hence from Theorem 2.1, unique common fixed point in X.
Remark 2.1: If S = T and A = B, then conditions (i)- (iii) is
(t ) dt
exists
A, T
(t )dt 0
for every ,
z w . So, z is the unique common fixed point of A, B, S and T .
Thus,
-chainable
fuzzy metric space and let A, B, S and T be self-mappings of X , satisfying (i), (ii) and (iii) of Theorem 2.1 and there k 0,1
0
(t )dt 0
for every ,
ES
F M Ax , By , kt , M x , y ,t , M x , Ax ,t , M y , By ,t , M y , Ax ,t , M x , By ,t
T
M x , y ,t
0
@ 2010 http://www.ijaest.iserp.org. All rights Reserved.
, such that
(t ) dt
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Manish Kumar Mishra et al. / (IJAEST) INTERNATIONAL JOURNAL OF ADVANCED ENGINEERING SCIENCES AND TECHNOLOGIES Vol No. 1, Issue No. 2, 123 - 129
x, y X and t 0 .Then A, B, S and T have a unique common fixed point in X . for every ,
M A x , y , B u , y , kt , M A x , y , x ,t , M B u ,v ,u ,t , M x ,u ,t , M y , v ,t , M A x , y ,u ,t
0
Proof: In corollary 2.3, if we take A=B, so the equation reduces to Grabiec’s fuzzy Banach Centration theorem (see[5])
for all ,
Corollary 2.5:
exactly
X , M , be a complete -chainable
Let
fuzzy metric space and let A be self-mappings of X , which k 0,1
0
(t )dt
M x , y ,t
0
x, y X and t 0 .Then A, B, S and T have a unique common fixed point in X . X , M , be a complete
Let
-chainable fuzzy
metric space. For any x, y X and t 0 , assume that M x , y ,t sup M x0 , x1 ,t *M x1 , x2 ,t *...........*M xn1 , xn ,t M x , y ,t
0
(t )dt
Whenever
M x , y ,t
0
M x , y ,t
0
A w, w w B w, w
M
(t )dt and
(t )dt 1
w
in
X
,such
that
.
M x , y ,t
0
(t )dt
M x , y ,t
0
M A x , y , B u , y , kt , M A x , y , x ,t , M B u , y ,u ,t , M x ,u ,t , M A x , y ,u ,t
0
for all ,
(t )dt
X , M , is complete. Consider x be a To show that X , M , . Then, for m n , such Cauchy sequence in
z y
in
X such that
A z y , y z y B z y , y For any
.
(t )dt 0
x, y, u, v in X . Therefore by Corollary 2.1, we have,
for each y in X, there exists one and only one
is a fuzzy metric satisfying
ES
Then, it is to be prove that
point
Proof: From above relation (i) we have,
(t ) dt
for every , Proof: :
one
T
M Ax , By , kt
x, y, u, v in X and t 0 .Then there exists
, such that
satisfies the condition
(t )dt 0
…………………(iii)
y, y ' X by (i), and using relation
M z y , z y ', kt
0
(t )dt
M A ( z y , y ), B ( z y ' , y ),t
0
(t )dt
n
that
M ym1 , ym ,t / m
0
(t )dt
hence, we have
IJ A M xn , xm ,t
0
X , M ,
Since
M xn , z ,t
0
0
(t )dt
M xn , z ,t
0
M xn , xm , t
0
(t ) dt
is complete, there exists
(t )dt 1
M xn , z ,t
and
(t )dt
F M z y , z y ', kt ,1,1,1, M y , y ',t , M z y , z y ',t
0
1 * 1 * 1 .........* 1 1
we get
M xn , z ,t
0
and
hence
(t )dt
(t )dt 1
X , M , is complete.
z X , such that
. Hence
xn converges
Since, F is nondecreasing in the first argument, therefore
we have
F M z y , z y ', kt ,1,1,1, M y , y ',t , M z y , z y ',t
0
M z y , z y ' , t
0
So,
to z and
(t )dt
M z y , z y ' ,t / k
n
A and B be two self-mappings on X X product , with values in X . If there exists a constant k 0,1
M y , y ',t *M z y , z y ' ,t / k
0
n
(t )dt
Therefore, Corollary 2.4 yields that the map z (.) of X into
w z w . w z w a w, w B w, w
itself has exactly one fixed point w in X i.e. Hence, by (ii),
. It
is easily observed that A and B can have only one such common fixed point w in X. REFERENCES [1]
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, such that (i)
ISSN: 2230-7818
,
1, as n
X , M , be a complete -chainable
fuzzy metric space and let
(t )dt 0
which implies that
IV. AN APPLICATION Now, we shall apply the corollaries 2.1 and 2.4 to establish the following results: Theorem 3.1: : Let
(t )dt 0
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Manish Kumar Mishra et al. / (IJAEST) INTERNATIONAL JOURNAL OF ADVANCED ENGINEERING SCIENCES AND TECHNOLOGIES Vol No. 1, Issue No. 2, 123 - 129 [3]
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