Tensile testing

Tensile Testing Name: JesĂşs Alfredo Guardia Ogliastre ID: V26493748 Prof: Milexa de Vargas Subject-matter: Science Of Materials Diameter (d) = 12.8 mm

Radius (r) = d/2 = 6.4 mm

Area (đ??´) = đ?œ‹đ?‘&#x; = 128.67 mm2 2

lo = 50.800 mm

đ??š đ?œŽ= A

Stress Mpa

Strain(Îľ) mm/mm

0 99 197 296 395 592 692 720 797 838 928 997 1163 1236 1247 1240 1177 969

0,0000 0,0005 0,0010 0,0015 0,0020 0,0030 0,0040 0,0050 0,0075 0,0100 0,0150 0,0200 0,0400 0,0600 0,0700 0,0800 0,1000 0,1150

Stress (Ďƒ) vs. Strain (Îľ)

Ďƒ

1400

ĎƒTS

1200

STRESS

1000 800 Ďƒy 600 400 200 0.1100

0.002

0 0,0000

0,0200

0,0400

0,0600

0,0800

STRAIN

0,1000

0,1200

Îľ 0,1400

(b) Compute the modulus of elasticity

đ??¸=

∆đ?œŽ 400 − 0.0 = = 2000 đ?‘€đ?‘ƒđ?‘Ž ∆đ?œ€ 0.002 − 0.0 (b):

E = 200 GPa

(c):

Ďƒy = 760 MPa

(c) Determine the yield strenght at a strain offset of 0.002.

(d) Determine the tensile strenght of this alloy

(d): ĎƒTS = 1260 MPa (e) What the approximate ductility, in percent elongation?

đ?‘™đ?‘“ = đ?œ€ ∗ đ?‘™đ?‘œ + đ?‘™đ?‘œ

đ?‘™đ?‘“ = 0.1100 ∗ 50.800 + 50.800

�� = 56.388 ��

%đ??¸đ?‘™đ?‘œđ?‘›đ?‘”đ?‘Žđ?‘Ąđ?‘–đ?‘œđ?‘› =

đ?‘™đ?‘“ − đ?‘™đ?‘œ 56.388 − 50.800 ∗ 100 = ∗ 100 = 11 % đ?‘™đ?‘œ 50.800 (e):

11 %