Physics Tutor In Surat Gujarat-IIT JEE MAIN 27 JULY 2022 EVENING SHIFT SOLVED PHYSICS PAPER by KUMAR SIR PHYSICS

PHYSICS JEE-MAIN (July-Attempt) 27 July (Shift-2) Paper Solution PFz-tIt =10 (1+ (DT) 4: 1T, =mar.CSTJE.N = IIT H * no (Ch T. T = 2 (Tv.

1. An expression of energy density is given by u = , where are constants x is displacement, k is Boltzmann constant and t is the temperature. The dimesnsions of will be : (A) (B) (C) (D) -SinC CP Mp 520-1 40L" TO MOLO +0 v = <3m (1) 704FO 4= 1 CF Re = e UIE EP=TLTY L B 17. 2 = L B = 40470

2. A body of mass 10 kg is projected at an angle of 45° with the horizontal. The trajectory of the body is observed to pass through a point (20,10). If T is the time of ﬂight, then its momentum vector, at time = , is ________. T 8=10m5" ⑭ 2U" Jog 20 ↑= mucos 10 =20 tan 450 = 10x (2074 + m CSinO-gt)g & U" (osus) " 10 20 = 10x400 - 20-4000 5 =10/2010345 [+10(20Sn950 *U2(yy) 1: -10x2).) 000 = 20 -1054 = 20 nt/sec = 1005 + D005-200) j LL T = 20 31n95 =2x20 x /5E = 252, g 10 Momentum of t = T/n = 2sec

3. A block of mass M slides down on a rough inclined plane with constant velocity. The angle made by the incline plane with horizontal is . The magnitude of the contact force will be : (A) Mg (B)Mgcosθ (C) Mg sinθ+Mg cosθ (D) Mgsin0 If le Magnitude ofcontact force &> mgsine)"+ (my cos0)" a N ma magiosos mgo,it

4. A block ‘A’ takes 2 s to slide down a frictionless incline of 30° and length ′l′ kept inside a lift going up with uniform velocity ′′. If the incline is changed to 45°, the time taken by the block, to slide down the incline, will be approximately : & " Max my sing-a gsO I =0 + CgSuo)" -Ezmeo myno. i 10 igco the tellas th = 252=1314 CUly = 14 x 12 = 1:60 sec

5. The velocity of the bullet becomes one third after it penetrates 4 cm in a wooden block. Assuming that bullet is facing a constant resistance during its motion in the block. The bullet stops completely after traveling at (4+x) cm inside the block. The value of x is : (A) 2.0 (B) 1.0 (C) 0.5 (D) 1.5-" = U" + 2 a s 10) = 0 - 2 a (4) NOW 107 = 5 "2 a (4+ce) -U'= 2 a (4 tc)C o-u = > a (3) " = x2 a (4) 9 400=18x*xa. 29 (42) =9a) Of 22 = 9 22 = 1= =

conservation of

6. A body of mass m is projected with velocity in vertically upward direction from the surface of the earth into space. It is given that is escape velocity and < 1. If air resistance is considered to be negligible, then the maximum height from the centre of earth, to which the body can go, will be : * e # & =l A boly Law of

energy ITE) A =CTE)B ↳We? _ amt = tm (0)" Emm C ** -# a = = te = =-* (1-X") Le =4N-5

7. A steel wire to length 3.2 (Y = 2.0 × 10 Nm) and a copper wire of length 4.4 m (Y = 1.1 × 10 Nm) and a copper wire of length ( = 1.1 × 10 ), both of radius 1.4 Are connected end to end. When stretched by load, the net elongation is found to be 1.4 mm. The load applied, in Newton, will be : ( = ) (A) 360 (B) 180 (C) 1080 (D) 154 2 My x * I A X - = ?S m m # = EEM A l+ Dlz = 14x153mE Des+ D1o = 14x183m # (32) (ex 183) 2x1011 FEXSSouc ↑ (*) + + (44) -> 14x103 - 14 x 14 x 1.4x105X3 11 T # (5.6) 0.6 x10 F =154N

In Ist case, Carnot engine operates between temperatures 300 K and 100 K. In 2 nd Case, as shown in the ﬁgure, a combination of two engines is used. The efﬁciency of this combination in 2 case will be:

(A) same as the 1st case.

(B) always greater than the 1st case.

(D) may increase or decrease with respect to the 1st case.

cases.

M=> 7 = (1.)x100 4 = (-2) x100 =5x100 = 33% 72 = (1-1) x100 =5x100 50%

9) Which statements are correct about degrees of freedom ?

(A) A molecule with n degrees of freedom has different ways of storing energy.

=RT-

(B) Each degree of freedom is associated with average energy per mole.

(C) A monatomic gas molecule has 1 rotational degree of freedom where as diatomic molecule has 2 rotational degrees of freedom.

(D) has a total of 6 degress of freedom.

Choose the correct answer from the options given below :

(A) (B) and (C) only

(B) (B) only (D) Only

Correct option is (B) B and D only

Methane molecule is tetrahedron Degree of freedom due to rotation = 3 Degree of freedom due to translation = 3

** -

10. A charge 4 is to be divided into two parts. The distance between the two divided charges so that the force between them is maximum, will be : (A) 1 3 (B) 2 2 (C) 0 4 (D) 1.5 2.5 * -sueR= 4O < x (a)9 F = * (G-9) 82 a frac = 0 Ld [9Q-94)= 9 D-29=0 =8=91 9 = 3 = 200 2M0G2MC

the

The drift velocity of electrons decreases with the increase in the temperature of conductor.

velocity is inversely proportional to the area of cross-section of given conductor.....

The drift velocity does not depend on the applied potential difference to the conductor.

The

velocity of electron is inversely proportional to the length of the conductor.

velocity increases with the temperature of conductor.

correct

from

given

when temp

Relaxation time decreases henceDa=eve it

y face

11. (A)

(B)

drift

(C)

(D)

drift

(E)

drift

Choose the

answer

the option

below : (A) (A) and (B) only (B) (A) and (D) only (C) (B) and (E) only (D) (B) and (C) only Sol. B By Theory v Ma = CE m ) 0d) = ef Pd= Fe

12. A compass needle of oscillation magnetometer oscillates 20 times per minute at a place P of dip 30°. The number of oscillations per minute become 10 at another place Q of 60° dip. The ratio of the total magnetic ﬁeld at the two places ∶ is : N & *> - ITT I ↑Bp L02, 22 = 24T Qc = Ba CoC2 Bo Jos 2n = 1) *F= BECCEt = O=

13. A cyclotron is used to accelerate protons. If the operating magnetic ﬁeld is 1.0 and the radius of the cyclotron ‘dees; is 60 cm, the kinetic energy of the accelerated protons in MeV will be: [use m = 1.6 × 10 kg, e = 1.6 × 10CJ] (A) 12 (B) 18 (C) 16 (D) 32 ⑭x 10"Kg.a =to OeBr K = me" tm J9Br) " -myalBor" 9"ur" C15X1o's)"XCDUx(o)" 2 x 16 x 1527 -> If MeV.

14. A series LCR circuit has L = 0.01 H, R = 10 Ω and C = 1 μF and it is connected to ac voltage of amplitude (V)50 V. At frequency 60% lower than resonant frequency, the amplitude of current will be approximately : (A) 466 mA (B) 312 mA (C) 238 mA (D) 196 mA n w=60%. (Ts) == R4 + (42 -xe)" <10) "+ (0.65 55)" = 50 100 +100x100.0%)" 0.238 OU 238 m A

Identify the correct statements from the following descriptions of various properties of electromagnetic waves.

(A) In a plane electromagnetic wave electric field and magnetic field must be perpendicular tO each other and direction of propagation of propagation of wave should be along electric field or magnetic field.

(B) The energy in electromagnetic wave is divided equally between electric and magnetic ﬁelds.

(C) Both electric ﬁeld and magnetic ﬁeld are parallel to each other and perpendicular to the direction of propagation of wave.

(D) The electric ﬁeld, magnetic ﬁeld and direction of propagation of wave must be perpendicular to each other.

(E) The ratio of amplitude of magnetic ﬁeld to the amplitude of electric ﬁeld is equal to speed of light.

Choose the most appropriate answer from the options given below :

(A) (D) only

(B) (B) and (D) only (C) (C) and (E) only (D)(A), (B) and (E) only

propogation

15.

a If

-> se direction V =UF + UB F-<> 3 or 2 dvection 6 =2 B 2 or 3 direction

16. Two coherent sources of light interfere. The intensity ratio of two sources is 1 ∶ 4. For this interference pattern if the value of is equal to , then wil be : (A) 1.5 (B)2 (C)0.5 (D)1 +Ime e * ⑭Bt 3 ~ ↑ mar = (JF, + 52) = (+2)29 ↑ muen = (Jr-5n)" = C1-2)"=1 ImaxtImin 1052ct I Iman- Emen Bt 3 5 Bt 15=0+ 4 5 (B+3) = 4(2d + 1) 32d + 1) = (t 3) from above equation we notice a = 2. B=1, G =

With reference to the observations in photo-electric effect, identify the correct statements from below

(A) The square of maximum velocity of photoelectrons varies linearly with frequency of incident light.

(B) The value of saturation current increase on moving the source of light away from the metal surface.

(C) The maximum kinetic energy of photo-electrons decreases on decreasing the power of LED (light emitting diode) source of light.

The immediate emission of photo-electrons out of metal surface can not be explained by particle nature of light/ electromagnetic waves.

Existence of threshold wavelength can not be explained by wave nature of light/ electromagnetic waves.

the correct answer from the options given below

(A) and (B) only

(A) and (E) only

and (E) only

17.

(D)

(E)

Choose

: (A)

(B)

(C)

(D)(D)

# h0:Wo + SKE) man Lu = Wo + momac "Tons rant 0 x (Uman)" Option A-correct Existence ofthreshold (x) can not be↳explanted by wave nature of ligh TRVE - CORRECT

18. The activity of a radioactive material is 6.4 × 10 curie. Its half life is 5 days. The activity will become 5 × 10 curie after : (A) 7 days (B) 15 days (C) 25 days (D) 35 days 4 us x v A =no (t)" 5 x10 = 64x1"(*) " 5 x 156 on x15s"(*)" · =1)" Total time = 7x5= 35 days = (*)"*n =

"Currentgan-

current

reached

19. For a constant collector – emitter voltage of 8 V, the collector

of a a transistor

to the value of 6 mA from 4 mA, whereas base current changed from 20 25 value. If transistor is in active state, small signal current gain (current amplication factor) will be : (A) 240 (B) 400 (C) 0.0025 (D) 200 ⑧w

*ono

20. A square wave of the modulating signal is shown in the ﬁgure. The carrier wave is given by () = 5 sin(8) Volt. The modulation index is : (A) 0.2 (B) 0.1 (C) 0.3 (D) 0.4 *A :Am= 0.2.

In an experiment to determine the Young’s modulus steel wires of

different lengths (1,2,3,34 and 5m) but of same cross section (2

) were taken and curves between extension and load were obtaibed. The slope (extension / load) of the curves were plotted with the wire length and the following graph is obtained. If the young’s modules of given steel

Section - B 21.

ﬁve

wires is x x 1011 NM-2 Then the value of x is _________. ⑭a p 2Y=Eyee is no &A - E) (e). low Y= () = , Y10.5X15 (A) = 10"=1100x10 ↳ We consider -2x10 1=2

In the given ﬁgure of meter bridge experiement, the balancing length AC corresponding to null deﬂection of the galvanometer is 40 cm. The balancing length, if the radius of the wire AB is doubled will be

meter bridge

22.

______cm. 40

Does not depend on cosssection area

Hence null point will remain same.

.23) A thin prism of angle 6° and refractive index for yellow light (ny) 1.5 is combined with another prism of angle 5° and ny = 1.55. The combination produces no dispersion. The net average deviation () produced by the combination is °. The value of x is _______.t O a so n 18 A= 50 ONET = 0-82, = (.5-1) 60(155-1750 = 30-2,750 = 0.250 I 5 =525 x =4

24. A conducting circular loop is placed in plane in presence of magnetic ﬁeld B = (3t J + 3tk) in SI unit. If the radius of the loop is 1 m, the induced emf in the loop at time = 2 . The value of n is _______. I =+ 3") - SGTV.12. ↓ component ofmagnetic ②= A dp field Ince-5 plane = TC1)"x (3t ? ) ? = (6 +) = TC2)= UT Noet 2 = 12

25. As shown in the ﬁgure, in steady the charge stored in the capacitor is ____________× 10 10 COV v = l0-Oh m Tr x = 100- ohm Trur I'll f If the 200-ohm In steady state capacitor will act as a open circuit. ⑪ VI I * a = 14x100 x =10%-loxiog 00 A B # Am P VaB =100x100 tovoet

26. A parallel plate capacitor with width 4 cm, length 8 cm and separation between the plates of 4 mm is connected to a battery of 20 . A dielectric slab of dielectric constant 5 having length 1 cm, width 4 cm and thickness 4 mm is inserted between the plates of parallel plate capacitor. The electrostatic energy of this system will be ________. ⑭ 248 v (9) "P v = l) GAz + KAl nch Srcm (xx10" +5x1X18?] 30cm. 4mmox1." (28 +20702. onaTg x (20 "Fore= Gox1%x6 x 400/ V - to X240·5

27. A wire of length 30 cm. stretched between rigid supports, has it’ and ( + 1) harmonics at 400 and 450 respectively. If tension in the string is 2700 , it’s linear mass density is ____________kg/m. = s - ⑤ Ctl = 40 = 30 = 44= 34 + 3 2 = 3 300=352 F0o l =3

A spherical soap bubble of radius 3 cm is formed inside another spherical soap bubble of radius 6 cm. If the internal pressure of the smaller bubble of radius 3

in the above system is equal to internal pressure of the another single soap bubble of radius r cm. The value of r is

2 cm

28.

_________. *

: A+E d = 5+ &= "x= 2 cm

29. A solid cylinder length is suspended symmetrically through two massless strings, as shown in the ﬁgure. The distance from the initial rest position, the cylinder should by unbinding the strings to achieve a speed of 4, is ___________cm. (take = g = 10 ms-2)120 & 25 (R) = = (9), a RC2) 8 x a/R. n + a T my. 2T = m (a) 25 (R) 1((R) (D) (D) my- x (E):ma T= La r my = a (m+2) a: mFF Emer Put I: MR3 =,a ==28 V=nt at 4: 0+ 3x10xt-> t= 3 sec 5 = o+ 110x1 =1.2 M = 120<m.

30. Two inclined planes are placed as shown in ﬁgure. A block is projected from the point A inclined plane AB along its surface with a velocity just sufﬁcient to carry it to the top point B at a height 10 m. After reaching the Point B the block sides shown on inclined plane BC. Time it takes to reach to the point C from point A is √2 + 1. The value of t is _________.) 2 B In upward motion 8 Sin 95+ = 1051 th =105 *-=2sec In downward motion ↓ Sin30t = 20 2 x = 20 tc = 252 see Total time = 2 CH+ J), =2 => + (l + 3)

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