2
For isothermal compressible flow through tubes, the mass flow rate G has been shown to be : đ??ş = The 2đ??ş
đ?‘‘đ??ş đ?‘‘đ?‘?2
maxima =
in
this
function
đ?‘€ đ?‘? 2đ??żđ?‘“ 1 ��đ?‘™đ?‘› 1 + ďż˝.[−2đ?‘?2 ]âˆ’ďż˝đ?‘?12 −đ?‘?22 ďż˝(− )ďż˝ 2đ?‘…đ?‘‡ đ?‘?2 đ?‘‘ đ?‘?2 đ?‘? 2đ??żđ?‘“ ďż˝đ?‘™đ?‘› 1+ ďż˝ đ?‘?2 đ?‘‘
=0
is
obtained
by
differentiating
which on simplification gives : G2 = p 2 2.(M/RT) = V s2 . Ď 2 , and the tube is choked. Can you do the same development for adiabatic reversible flow ?
đ?‘€ ďż˝đ?‘?2 −đ?‘?22 ďż˝ 2đ?‘…đ?‘‡ 1 đ?‘?1 2 đ??ż đ?‘“ ďż˝đ?‘™đ?‘› + ďż˝ đ?‘?2 đ?‘‘
w.r.t.
p2
: