Additional problems ebook

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For isothermal compressible flow through tubes, the mass flow rate G has been shown to be : đ??ş = The 2đ??ş

đ?‘‘đ??ş đ?‘‘đ?‘?2

maxima =

in

this

function

đ?‘€ đ?‘? 2đ??żđ?‘“ 1 ��đ?‘™đ?‘› 1 + ďż˝.[−2đ?‘?2 ]âˆ’ďż˝đ?‘?12 −đ?‘?22 ďż˝(− )ďż˝ 2đ?‘…đ?‘‡ đ?‘?2 đ?‘‘ đ?‘?2 đ?‘? 2đ??żđ?‘“ ďż˝đ?‘™đ?‘› 1+ ďż˝ đ?‘?2 đ?‘‘

=0

is

obtained

by

differentiating

which on simplification gives : G2 = p 2 2.(M/RT) = V s2 . Ď 2 , and the tube is choked. Can you do the same development for adiabatic reversible flow ?

đ?‘€ ďż˝đ?‘?2 −đ?‘?22 ďż˝ 2đ?‘…đ?‘‡ 1 đ?‘?1 2 đ??ż đ?‘“ ďż˝đ?‘™đ?‘› + ďż˝ đ?‘?2 đ?‘‘

w.r.t.

p2

:


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