CD
C
AB A
B A.B + C.D A.B + C.D A.B = C.(A.B + D) B.C.D + C.D B.(C + D) + B.C.D
D
B.(C.(D + D) + C.D) X +X =1
B.(C + C.D)
¯ Y¯ ) = (X + Y ) (X.
B.(C.(C.D)) B.(C.(C + D)) B.(C.C + C.D) X.X = 0
B.(C.D) B B.C.D.
B.(C + D)
B.(C + D) + B.C.D
B
B.(C.D + C.D + CD)
B.(C.D + C.D + C.D)
" " " "
0
Q0
0
Q0
0
Q0
0
Q0 Q0
0 0
IB
IC