Previous Year Question Answers - SSC CGL TIER - I (Paper -2)

Page 1

MOCK TEST

SSC CGL TIER- I

01. While working 7 hours a day, A alone can complete a piece of work in 6 days and B alone can complete a piece of work in 8 days. How many days do they require to complete a piece of work while working together for 8 hours a day ? a) 3 days b) 4 days c) 2.5 days d) 3.6 days

3

7×6=42 (A)

7×8=56 (B)

Work done by A+B in one hour=7units Whole work is completed by A+B in = =3 days. 02. Find the value of  3+2 2  +  3-2 2  . -3

a) 198 c) 108

-5

 = - 5

2 2  7- 5 × 7 + 5  7 - 5 

III.

=

2- 7

2 2

 7- 5

7-5

 = 2

7- 5

from I-II+III we get

b) 180 d) 189

+

1

27-16 2-54 2 +72+27+16 2 +54 2 +72

Ans. (a) Sol. Let the speed of the truck be x km/hr. ATQ. D=S×T

(27) + (72)2 54+144 = 198. 3 7 5 5 2 2 + 5+ 2 2+ 7 7+ 5

a) 1 c) 2 3

150=(45-x)

b) 0 d) 7

06. When the radius of a circle is reduced by x, the area of the circle decreases to half of the previous area. Find the radius of the circle.

3 7 5 5 2 2 + 5+ 2 2+ 7 7+ 5

=

5 5  2- 7  × 2 + 7  2 - 7 

3 7

5- 2 5-2

=

5 ×30 18

45-x =18 x=27 km/hr.

Ans. (b)

3 7 5- 2 × 5+ 2 5- 2

200 meter

05. A bus moving at a speed of 45km/hr overtakes a truck 150 meters ahead going in the same direction in 30 seconds. The speed of the truck in (km/hr) is a) 27km/hr b) 24km/hr c) 25 km/hr d) 28 km/hr

 3-2 2 3 + 3+2 2 3

03. Simplify

10km/hr thief

100 mt. 6 in 6 minutes = 100 mt. distance b/w them after 6 minutes. 200-100=100 meters

 3+2 2   3-2 2 3 3

11km/hr Police

1 minute =

 3+2 2  -3 + 3-2 2  -3 is equal to 1

168 56

Ans. (a) Sol.

Vrel =11-10 = 1km/hr 60 minutes = 1000 meters

-3

Ans. (a)

II.

2- 7

= 0.

4

I.

04. A policeman follows a thief who is 200m ahead of the policeman. If the policeman and the thief run at the speed of 10 km/hr and 11 km/hr respectively then what is the distance between them after 6 seconds? a) 100m b) 190m c) 200m d) 150m

Total Work 168 units

Sol .

5 5

7× 5- 7× 2 + 5× 2- 5× 7 + 2× 7 - 2× 5

And. (a) Sol.

Sol .

1

5 5

 = 7

2- 7 2-7

5- 2

a) x 2

b)

x 2 2 -1

c) x  2-1

d)

x 2 +1

Ans. (b)

Tilak Nagar-9311566241, Karol Bagh-8376934679, Pitampura-8376934648, Munirka-9650549487, Laxmi nagar-9953283708

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