Muhamad Akmal Bin Mohd Yazit 0312531
Building Science 2 (ARC 3413) Project 2 : Integration with Design Studio 5 Calculation Booklet
Artificial Lighting Factor Calculation
Floor Plan : Mini Market
Mini Market Type of bulb
Phillip Essential Energy Saver 1100Lm[18W]
No of lamps required : Total floor area (m2)
41.29
Standard Illuminence required(lux)
200
Assumption of reflection Room Index ( K)
White ceiling , Dark grey walls 70 , 30 1.20
Utilization factors
0.51
Maintenance factors
0.9
Luminous flux from each lamps (Lm)
1100
RI = L x W H x (L + W) = =
7.27m x 5.68m 3.55m-0.85(7.27m+5.68m) 41.29m 2.7m(12.95m)
= 1.20
N=ExA F x UF x MF = 200 x 41.63m 1100 x 0.51 x 0.9 = 15 Lamps
Section of Mini Market
Spacing to Height Ratio : SHR = 1 Hm =
= 0.370 = 0.614 Fitting Layout : 0.614 =
0.614 = Spacing = 0.616 x 2.7 = 1.66m Calculation for rows : =
= 3.42 = 3 Rows Number of lamps each row : =
= 5 lamps each row Longitudinal spacing between each lamps : =
= 1.45m Half spacing at both end : Longitudinal =
Latitude =
= 0.725m
= 0.83m
Ceiling plan of Mini Market
2). Second is Office :
Floor Plan : Office
OFFICE : Type of bulb
Phillip Genie Energy Saver 610Lm [11W]
No of lamps required : Total floor area (m2)
57.25
Standard Illuminence required(lux)
300
Assumption of reflection Room Index ( K)
White ceiling , Dark grey walls 70 , 30 1.46
Utilization factors
0.57
Maintenance factors
0.9
Luminous flux from each lamps (Lm)
610
RI = L x W H x (L + W) = =
9.19m x 6.23m 3.4m-0.85(9.19m+6.23m) 57.25m 2.55m(15.42m)
= 1.46
N=ExA F x UF x MF = 300 x 57.25m 610 x 0.57 x 0.9 = 55 Lamps
Section of office
Spacing to Height Ratio : SHR = 1 Hm =
= 0.392 = 0.4 Fitting Layout : 0.4 =
0.4 = Spacing = 0.4 x 2.55 = 1.02m Calculation for rows : =
= 6.11 = 6 Rows Number of lamps each row : =
= 9 lamps each row Longitudinal spacing between each lamps : =
= 1.02m Half spacing at both end : Longitudinal =
Latitude =
= 0.51m
= 0.51m
Ceiling plan of Office
3). Third is Viewing Deck
Floor plan : Viewing Deck
Viewing Deck Type of bulb
Phillips Eco Classic 1200Lm (70W)
No of lamps required : Total floor area (m2)
16.96
Standard Illuminence required(lux)
150
Assumption of reflection Room Index ( K)
White ceiling , Dark grey walls 70 , 30 0.68
Utilization factors
0.40
Maintenance factors
0.9
Luminous flux from each lamps (Lm)
1200
RI = L x W H x (L + W) = =
5.47m x 3.1m 3.4m-0.5(5.47m+3.1m) 16.96m 2.9m(8.57m)
= 0.68
N=ExA F x UF x MF = 150 x 16.96m 1200 x 0.40 x 0.9 = 6 Lamps
Section for Viewing Deck
Spacing to Height Ratio : SHR = 1 Hm =
= 0.345 = 0.580 Fitting Layout : 0.580 =
0.580 = Spacing = 0.580 x 2.9 = 1.682m Calculation for rows : =
= 1.84 = 2 Rows Number of lamps each row : =
= 3 lamps each row Longitudinal spacing between each lamps : =
= 1.82m Half spacing at both end : Longitudinal = Latitude =
= 0.91m = 0.841m
Ceiling Plan of Viewing Deck
Acoustic Calculation Reveberation Time Material and absorption Coefficient Value (1kHz) Formula : RT = Where V = Volume of room (m2) and Abs = Total absorption in room (m2) Indoor Calculation Zone 1. Square Court
Spaces for acoustic(reverberation time) Material at (1kHz) Material Flooring – wood parquet on concrete Wall – Brickwall Wall – Timber Block Furniture – Timber Ceiling - Plaster
Absorption coefficient value 0.06 0.02 0.10 0.96 0.03
Surface material
Area , m2
Flooring – wood parquet on concrete Wall – Brickwall Wall – Timber Block Furniture – Timber Ceiling – Plaster
117.2
Absorption coefficient value 0.06
Surface absorption, m2 7.032
80.9 27.3 22.61 117.2
0.02 0.10 0.96 0.03
1.618 2.73 21.70 3.516
Total Abs = 7.032 + 1.618 + 2.73 + 21.70 + 3.516 = 36.596 Volume of room = 117.2 m2 x 3.4m = 398.5 RT = RT = RT = 1.74s
Transmission Loss Using formula of Transmission Loss TL = 10 log10 Tav = ( S1 *Tc1 + S2 *Tc2 + .. Sn *Tcn) Total Surface Area Tcn = The transmission coefficient of material Sn
= The surface area of material n
Spaces for acoustic(Transmission Loss) Surface Materials
Area, S(m2)
Wall - Brickwall
9.81
42
1.613 x 10 -3
Wall - Window
45.46
26
2.512 x 10 -1
Wall - Door
7.14
28
1.587 x 10 -1
Sound Reduction Index, SRI (dB)
Transmission coefficient, Tav
For Brick wall Using SRI = 10 log10 42 = 10 log10 anti log 4.2 =
T=
4
T brick wall = 1.613 x 10 -3
For Window Using SRI = 10 log10 26 = 10 log10 anti log 2.6 =
T=
2
T window = 2.512 x 10 -1
For Door Using SRI = 10 log10 28 = 10 log10 anti log 2.8 =
T=
2
T door = 1.587 x 10 -1
Toverall = (1.613 x 10 -3) + (2.512 x 10 -1) + (1.587 x 10 -1) 9.81 + 45.46 + 7.14 = 6.601 x 10-3 SRI overall = 10 log = 10 log 1.614 x102 = 22.1 dB Total noise entering the bleachers area Road noise (50 dB) Therefore : 50dB – 22.1 dB = 27.9 dB
SPL L = 10 log10 The total SRI is = 22.1dB from the Meeting Area. So the calculation for power addition are as follow Noise from external = 50dB
L = 10 log10 50 = 10 log10 Anti log 5.0 = I = (1 x 105) x (1x 10-12) = 1 x 10-7 Noise from external = 22.1dB
L = 10 log10 22.1 = 10 log10 Anti log 2.21 = I = (1.621x 102) x (1x 10-12) = 1.621 x 10 -10 Total Intensities = (1 x 10-7) + (1.621 x 10 -10) = 1.00 x 10-7 Combined Spl = L = 10 log10 = 10 log10 -5
= 10 log (1 x 10 )
= 50 dB