The Program Discover: Biomeans, Electrophi, And The Stellar Mystery

1 of 15 The Program Discover: Biomeans, Electrophi, And The Stellar Mystery by Ian Beardsley August 10, 2015 copyright © 2015 by Ian Beardsley

2 of 15 I am writing a program in C and Python called Discover. It searches for hidden nuances in Nature and the Universe. The first program is called add. It is based on:

The arithmetic mean is the midpoint, c, between two extremes a, and c:

!

b=

a+ c 2

€

The harmonic mean is not necessarily the midpoint between two extremes but is the value that occurs most frequently:

!

b=

2ac a+ c

€

The geometric mean, b, between a and c, is the side of a square that has the same area as a rectangle with sides and c: ! b = ac The following relationship holds:

€ !

€

a:

a + c 2ac :: :c 2 a+ c

3 of 15 The Program add.c

#include <stdio.h> #include <math.h> int main(void) { int n; do { printf("How many numbers do you want averaged? "); scanf("%d", &n); } while (n<=0); float num[n], sum=0.0, average; for (int i=1; i<=n; i++) { printf("%d enter a number: ", i); scanf("%f", &num[n]); sum+=num[n]; average=sum/n; } printf("sum of your numbers are: %.2f\n", sum); printf("average of your numbers is: %.2f\n", average); float a, b, product, harmonic; printf("enter two numbers (hint choose P and B): \n"); printf("give me a: "); scanf("%f", &a); printf("give me b: "); scanf("%f", &b); product = 2*a*b; sum=a+b; harmonic=product/sum; printf("harmonic mean: %.2f\n", harmonic); double geometric; geometric=sqrt(a*b); printf("geometic mean: %.2f\n", geometric); }

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Running Discover jharvard@appliance (~): cd Dropbox/pset2 jharvard@appliance (~/Dropbox/pset2): ./add transistors are Silicon doped with Phosphorus and Boron Artificial Intelligence would be based on this the golden ratio conjugate is basic to life The Golden Ratio Conjugate Is: 0.618 Molar Mass Of Phosphorus (P) Is: 30.97 Molar Mass Of Boron (B) Is: 10.81 Molar Mass Of Silicon (Si) Is: 28.09 How many numbers do you want averaged? 2 1 enter a number: 9 2 enter a number: 5 sum of your numbers are: 14.00 average of your numbers is: 7.00 enter two numbers (hint choose P and B): give me a: 30.97 give me b: 10.81 harmonic mean: 16.03 geometic mean: 18.30 geometric mean between P and B divided by Si: 0.65 harmonic mean between P and B divided by Si: 0.57 0.65 + 0.57 divided by 2 is: 0.61 those are the the first two digits in the golden ratio conjugate jharvard@appliance (~/Dropbox/pset2):

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Here we have run the program for phosphorus, boron, and silicon because if artificial intelligence (AI) is to have the golden ratio conjugate in it, this is where it should be found. The guess proved successful. This immediately results in the relationship between artificial intelligence and biological, or organic, life.

Essentially we are saying (The sum of the geometric mean between P and B by Si with the harmonic mean of P and B by Si, their arithmetic mean is the first two digits in the golden ratio conjugate : \frac { \sqrt { PB } }{ Si } =\frac { (30.97)(10.81) }{ (28.09) } =0.65\\ \frac { 2PB }{ P+B } /Si=\frac { 2(30.97)(10.81) }{ (30.97+10.81) } /28.09=0.57\\ \frac { 0.65+0.57 }{ 2 } =0.61

6 of 15 The Golden Ratio Let us draw a line and divide it such that the length of that line divided by the larger section is equal to the larger section divided by the smaller section. That ratio is The Golden Ratio, or phi:

a b = b c a = b+ c c = a− b a(a − b) = b2 a2 − ab = b2 a2 − ab− b2 = 0 2

" a% a $ ' − −1 = 0 # b& b 2

" a% a $ ' − =1 # b& b 2

" a% a 1 5 $ ' − + = # b& b 4 4 2

"a 1% 5 $ − ' = #b 2& 4 a 5 +1 = = 1.618...

2 !b

7 of 15 That is, we have found the following, where Au is gold, Ag is silver, He is helium, H is hydrogen and 3/10 is 0.3 is the albedo of the earth. The sun fuses hydrogen into helium and, Au/Ag is about 9/5, which is the ratio of the solar radius to the lunar orbital radius: \frac { \sqrt { PB } (P+B)+2PB }{ 2(P+B)(Si) } \approx \phi \\ \phi =0.618=golden\quad ratio\quad conjugate \frac { \sqrt { PB } (P+B)\quad +2PB }{ 2(P+B)(Si) } \left[ \frac { 3 }{ 10 } \frac { Au }{ Ag } +\frac { He }{ H } \right] =\frac { COOH }{ { NH }_{ 2 } }

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This immediately results in the connection between artificial intelligence and biological life. The building blocks of life are amino acids, which are composed of an amino, NH3 and an acid COOH with an R Group. We found above that the building blocks of artificial intelligence are Silicon doped with phosphorus and boron, or diodes, transistors, and IC in other words.

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10 of 15 The next part of the program Discover is a program in C and Python that determines the surface temperature of a planet given the luminosity of the star it orbits, the distance of the planet from the star, and the albedo of the planet. It is based on the following simple model:

The luminosity of the sun is: 26

! L0 = 3.9 ×10 J /s The separation between the earth and the sun is: €

! 1.5 ×1011 m The solar luminosity at the earth is reduced by the inverse square law, so the solar constant is:

€

!

S0 =

3.9 ×10 26 = 1,370Watts/meter 2 11 2 4π (1.5 ×10 )

That is the effective energy hitting the earth per second per square meter. This radiation is equal to the temperature, ! Te, to the fourth power by the steffanbolzmann constant, sigma ! (σ). ! Te can be called the effective temperature, the temperature entering the earth.

€

€ 2 S ! 0 intercepts the earth € disc, ! πr , and distributes itself over the entire earth € surface, ! 4πr 2, while 30% is reflected back into space due to the earth’s albedo,

a, which is equal to 0.3, so €

S σTe€ = 0 (1− a) 4 πr 2 (1− a)S0 4πr 2 !

€

4

€

But, just as the same amount of radiation that enters the system, leaves it, to have radiative equilibrium, the atmosphere radiates back to the surface so that the 4 4 radiation from the atmosphere, ! σTa plus the radiation entering the earth, ! σTe is the 4 radiation at the surface of the earth, ! σTs . However, €

€ €

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! σTa = σTe

4

and we have: €

4

4

4

σTs = σTa + σTe = 2σTe

4

1 4

Ts = 2 Te S 4 σTe = 0 (1− a) 4 σ = 5.67 ×10−8 S0 = 1,370 a = 0.3 1,370 (0.7) = 239.75 4 239.75 4 Te = = 4.228 ×10 9 5.67 ×10−8 ! Te = 255Kelvin

So, for the temperature at the surface of the Earth: €

1 4 ! Ts = 2 Te = 1.189(255) = 303Kelvin

Let’s convert that to degrees centigrade: €

Degrees Centigrade = 303 - 273 = 30 degrees centigrade

12 of 15 The Program In C #include<stdio.h> #include<math.h> int main(void) { float s, a, l, b, r, AU, N, root, number, answer, C, F; printf("We determine the surface temperature of a planet.\n"); printf("What is the luminosity of the star in solar luminosities? "); scanf("%f", &s); printf("What is the albedo of the planet (0-1)?" ); scanf("%f", &a); printf("What is the distance from the star in AU? "); scanf("%f", &AU); r=1.5E11*AU; l=3.9E26*s; b=l/(4*3.141*r*r); N=(1-a)*b/(4*(5.67E-8)); root=sqrt(N); number=sqrt(root); answer=1.189*(number); printf("The surface temperature of the planet is: %f K\n", answer); C=answer-273; F=(C*1.8)+32; printf("That is %f C, or %f F", C, F); printf("\n"); float joules; joules=(3.9E26*s); printf("The luminosity of the star in joules per second is: %.2fE25\n", joules/1E25); float HZ; HZ=sqrt(joules/3.9E26); printf("The habitable zone of the star in AU is: %f\n", HZ); printf("Flux at planet is %.2f times that at earth.\n", b/1370); printf("That is %.2f Watts per square meter\n", b); }

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The Program In Python print("We determine the surface temperature of a planet.") s=float(raw_input("Enter stellar luminosity in solar luminosities: ")) a=float(raw_input("What is planet albedo (0-1)?: ")) au=float(raw_input("What is the distance from star in AU?: ")) r=(1.5)*(10**11)*au l=(3.9)*(10**26)*s b=l/((4.0)*(3.141)*(r**2)) N=((1-a)*b)/(4.0*((5.67)*(10**(-8)))) root=N**(1.0/2.0) number=root**(1.0/2.0) answer=1.189*number print("The surface temperature of the planet is: "+str(answer)+"K") C=answer-273 F=(9.0/5.0)*C + 32 print("That is " +str(C)+"C") print("Which is " +str(F)+"F") joules=3.9*(10**26)*s/1E25 lum=(3.9E26)*s print("luminosity of star in joules per sec: "+str(joules)+"E25") HZ=((lum/(3.9*10**26)))**(1.0/2.0) print("The habitable zone is: "+str(HZ)) flux=b/1370.0 print("Flux at planet is "+str(flux)+" times that at earth") print("That

14 of 15 We run the program for the golden ratio and its conjugate and find we get near equivalence for the fahrenheit-centigrade scales, as well as near to the golden ratio conjugate of the flux at earth for the Sun. This is strange because that means our scales for temperature, which are fahrenheit and centigrade, as well as our scales for energy, distance, and time (joules, meters, seconds) have been defined such that they are in jive with stellar dynamics and climate dynamics, even though they evolved through a random and complex history. That is a mystery: Case 1 jharvard@appliance (~/Dropbox/descubrir): ./stelr We determine the surface temperature of a planet.

What is the luminosity of the star in solar luminosities? 1.618 What is the albedo of the planet (0-1)?0.618 What is the distance from the star in AU? 1.618 The surface temperature of the planet is: 231.462616 K That is -41.537384 C, or -42.767292 F The luminosity of the star in joules per second is: 63.10E25 The habitable zone of the star in AU is: 1.272006 Flux at planet is 0.62 times that at earth.

That is 852.66 Watts per square meter jharvard@appliance (~/Dropbox/descubrir):

The foot-pound system was not derived from any relationship to nature that we know of. The Metric system was: one gram is the mass of a cube of water at STP one centimeter on each side.

A centimeter is a hundredth of a meter, and a meter is a thousandth of a kilometer. One kilometer is one ten thousandth of the distance from the pole to the equator. Centigrade is derived such that there are 100 units between freezing and boiling points of water, freezing being zero and boiling, 100. Fahrenheit is not derived from anything natural: It stars at freezing of water at 32 degrees and who knows why? We do know the foot-pound system has earth gravity at 32 feet per second per second. Let us find the temperature where centigrade and Fahrenheit are the same: F=(9/5)C + 32 F=C C=(9/5)C+32 (25/25)C-(45/25)C=32 (-20/25)C=32 C=-32(25)/20=-800/20=-40 Degrees C -40 degrees C = -40 degrees F

15 of 15 The Author