Modern Day Mavericks

1 of 64 Modern Day Mavericks By Ian Beardsley © 2016

2 of 64 Dr. James C. Kemp

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Manuel

Page 7

Amarjit

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Dovid Krafchow

Page 49


3 of 64 Dr. James C. Kemp


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!

When I was a physics student at the University of Oregon, I had the good fortune of being taken in at the state observatory, Pine Mountain Observatory, and to work under its head, Professor James C. Kemp.

I have decided to write about him in this work, because of it being centered around people of vital character, and, if anyone was a man of dynamic character, it was Dr. Kemp.

First of all, to describe him, he was tall, thin, and handsome, and wore in the cold, snowy, sub-zero temperatures of Pine Mountain in the Winter, a parka, with wolverine fur around the hood, short pants, and went bare foot in the snow, with a corn cob pipe hanging out of his mouth. On one cold, Winter, starry night, standing between the telescope domes, looking at the starry sky, he told me: “We are not astronomers, we are physicists; the universe is a laboratory for energies higher than can exist on earth to be studied”. That was the field in which he got his Phd, high energy physics, at The University of Berkley. The amazing thing was that physics is not what he studied as an undergraduate—he studied Slavic Languages. How he managed to make the jump to graduate physics without first getting an undergraduate degree in the subject, is a mystery to me. But his study of Slavic Languages—He was fluent in Russian,-- began as early as high school, but not in America. As a child he and his mother moved to Mexico, and it was there that he went to the American School. His teacher there was Russian, and he told me she used to teach him Russian on their free time, that he had a great love for it. But it did not stop there. When as a young man, he came back to

5 of 64 America, and he joined the Navy, and it was there that he came to have a Russian girl friend, through whom he became even more fluent in the language. After leaving the Navy, his education was paid for by United States Government. Though he did put him self through school repairing people’s televisions, as well. He was studying Russian at Berkley and you might be wondering how he knew how to repair televisions. It goes back to his childhood in Mexico. He told me he loved doing electronics as a child in Mexico. He said he ran around the streets of Mexico, rummaging electronics components wherever he could find them so he could build a two-way radio for talking to North America. Which he did. He was then, as a child, a self-taught electronics engineer. Perhaps that had something to do with him being able to go out of Russian studies at Berkley, and directly into graduate level physics.

I always felt he much more enjoyed being at the observatory, which was some 200 miles east of the university in the high desert of Oregon, with its sage, ponderosa pine, herds of antelope, and pristine skies. When one left the university, one took a windy highway with no traffic, along a raging McKenzie River, that flowed through dense enchanted forests. Somewhere along that highway, there was one secluded restaurant called, Mom’s Homemade Pie. When I didn’t make the commute myself, in my 1976 Datsun pickup, and went with him, we would always stop there and he we buy me a cheeseburger and we would top it of with some of Mom’s Homemade Pie. The second we got to the observatory, he would take off his sandals, so he could go barefoot, whether there was snow or shine. He was told me he climbed the South Sister, barefoot. The south sister is one of the Mountains of the Cascade Mountain Range that you must drive over when leaving the University and heading to the observatory. He did not want to ever wear shoes at all— I think it was part of his free, childlike spirit— but had to when he was at his office at the department of physics. Well he didn’t exactly have to wear shoes, sandals would suffice and that was exactly what he did. However, there was only one kind of sandal he would wear, and that was leather sandals from Mexico, called Huarachis, and he always brought a few pairs back stateside when he went to Mexico on astronomy business. Huarachis are braided leather, but he told me the soles were made from car tires, and that you can get 200,000 miles on them.

What about music? Well on cloudy, snow nights, when we could not work with the telescopes, we would sit up all night in the warm residence, waiting for a break in the cloud cover, and he would play for me a record he liked a lot, it was by Joni Mitchell. It was not the only record we listened to, but he would play for me a record he bought at the airport in the Soviet Union. He worked with Russian astronomers, and when he was in Russia, I would stay behind and run the telescopes stateside. So, his earlier studies in Russian served him well in the sciences, as the Soviet Union is one of the leaders in astronomical sciences. He would explain to me the lyrics on the record, which was called Moscow Nights.

6 of 64 But when he was with the telescopes, at night, in the cold snow, he listened to only one composer that I can think of, and that was the Finnish composer Sibelius. In retrospect, I see it as a wise choice. Personally, when I hear his work, it is the only time I don’t feel I would rather be listening to Mozart, Bach, or Beethoven. I think he is perhaps not trumped by these geniuses because of his is bold, brave, and mysterious sound, like the ice lands of Finland that he depicted. His depictions of Finland perfectly described the snowy, Pine Mountain landscape where we worked.

Just what kind of work did we do at the observatory? While we studied the magnitude of light from a star, and its changes over time, what is known as photometry, the most important work was in something for which Professor Kemp built the measuring device, that was the most sensitive in the world at the time, because of his patented crystal, called polarimetry. Which is not just the study of how bright something is, but how its light is polarized, both in the directions of its vibration, and its percentage (how much is polarized, and in what direction). This enabled one to figure out the geometry of celestial systems. The amount of polarization is related to the reflective surface area of the object studied, and the direction of polarization, to the orientation of the object.

Professor Kemp once told me a secret: “You could in theory detect planets around a star with polarimetry, because they shine by reflected light and reflected light is polarized. Not only can you detect them, but you can determine their size and orbital orientation. Our telescopes are too small to do it, but my polarimeter would be sensitive enough to do it with a 200 inch telescope. With that, I can get down to a part in one million; that is just what is needed, observe: “For a Jupiter sized planet (radius = 71880000 meters) at earth orbit (radius = 1.5E11 meters) we have R squared/(r squared) = (71880000^2)/(1.5E11)^2=5E15/2.25E22 = 0.000,000,222”

7 of 64 Manuel’s Cave: An Archaeological Study In Space Science By Ian Beardsley

© 2016

8 of 64 Manuel

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Gypsy Shamanism And The Universe I wrote a short story last night, called Gypsy Shamanism and the Universe about the AE-35 unit, which is the unit in the movie and book 2001: A Space Odyssey that HAL reports will fail and discontinue communication to Earth. I decided to read the passage dealing with the event in 2001 and HAL, the ship computer, reports it will fail in within 72 hours. Strange, because Venus is the source of 7.2 in my Neptune equation and represents failure, where Mars represents success.

Ian Beardsley August 5, 2012 

10 of 64 Chapter One It must have been 1989 or 1990 when I took a leave of absence from The University Of Oregon, studying Spanish, Physics, and working at the state observatory in Oregon -- Pine Mountain Observatory—to pursue flamenco in Spain.

The Moors, who carved caves into the hills for residence when they were building the Alhambra Castle on the hill facing them, abandoned them before the Gypsies, or Roma, had arrived there in Granada Spain. The Gypsies were resourceful enough to stucco and tile the abandoned caves, and take them up for homes.

Living in one such cave owned by a gypsy shaman, was really not a down and out situation, as these homes had plumbing and gas cooking units that ran off bottles of propane. It was really comparable to living in a Native American adobe home in New Mexico.

Of course living in such a place came with responsibilities, and that included watering its gardens. The Shaman told me: “Water the flowers, and, when you are done, roll up the hose and put it in the cave, or it will get stolen”. I had studied Castilian Spanish in college and as such a hose is “una manguera”, but the Shaman called it “una goma” and goma translates as rubber. Roll up the hose and put it away when you are done with it: good advice!

So, I water the flowers, rollup the hose and put it away. The Shaman comes to the cave the next day and tells me I didn’t roll up the hose and put it away, so it got stolen, and that I had to buy him a new one.

He comes by the cave a few days later, wakes me up asks me to accompany him out of The Sacromonte, to some place between there and the old Arabic city, Albaicin, to buy him a new hose.

It wasn’t a far walk at all, the equivalent of a few city blocks from the caves. We get to the store, which was a counter facing the street, not one that you could enter. He says to the man behind the counter, give me 5 meters of hose. The man behind the counter pulled off five meters of hose from the spindle, and cut the hose to that length. He stated a value in pesetas, maybe 800, or so, (about eight dollars at the time) and the Shaman told me to give that amount to the man behind the counter, who was Spanish. I paid the man, and we left.

I carried the hose, and the Shaman walked along side me until we arrived at his cave where I was staying. We entered the cave stopped at the walk way between living room and kitchen, and he said: “follow me”. We went through a tunnel that had about three chambers in the cave, and entered one on our right as we were heading in, and we stopped and before me was a collection of what I estimated to be fifteen rubber hoses sitting on ground. The Shaman told me to set the one I had just bought him on the floor with the others. I did, and we left the chamber, and he left the cave, and I retreated to a couch in the cave living room.

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Chapter Two Gypsies have a way of knowing things about a person, whether or not one discloses it to them in words, and The Shaman was aware that I not only worked in Astronomy, but that my work in astronomy involved knowing and doing electronics.

So, maybe a week or two after I had bought him a hose, he came to his cave where I was staying, and asked me if I would be able to install an antenna for television at an apartment where his nephew lived.

So this time I was not carrying a hose through The Sacromonte, but an antenna.

There were several of us on the patio, on a hill adjacent to the apartment of The Shaman’s Nephew, installing an antenna for television reception.

Chapter Three I am now in Southern California, at the house of my mother, it is late at night, she is a asleep, and I am about 24 years old and I decide to look out the window, east, across The Atlantic, to Spain. Immediately I see the Shaman, in his living room, where I had eaten a bowl of the Gypsy soup called Puchero, and I hear the word Antenna. I now realize when I installed the antenna, I had become one, and was receiving messages from the Shaman.

The Shaman’s Children were flamenco guitarists, and I learned from them, to play the guitar. I am now playing flamenco, with instructions from the shaman to put the gypsy space program into my music. I realize I am not just any antenna, but the AE35 that malfunctioned aboard The Discovery just before it arrived at the planet Jupiter in Arthur C. Clarke’s and Stanley Kubrick’s “2001: A Space Odyssey”. The Shaman tells me, telepathically, that this time the mission won’t fail.

Chapter Four I am watching Star Wars and see a spaceship, which is two oblong capsules flying connected in tandem. The Gypsy Shaman says to me telepathically: “Dios es una idea: son dos”. I understand that to mean “God is an idea: there are two elements”. So I go through life basing my life on the number two.

Chapter Five

12 of 64 Once one has tasted Spain, that person longs to return. I land in Madrid, Northern Spain, The Capitol. The Spaniards know my destination is Granada, Southern Spain, The Gypsy Neighborhood called The Sacromonte, the caves, and immediately recognize I am under the spell of a Gypsy Shaman, and what is more that I am The AE35 Antenna for The Gypsy Space Program. Flamenco being flamenco, the Spaniards do not undo the spell, but reprogram the instructions for me, the AE35 Antenna, so that when I arrive back in the United States, my flamenco will now state their idea of a space program. It was of course, flamenco being flamenco, an attempt to out-do the Gypsy space program.

Chapter Six I am back in the United States and I am at the house of my mother, it is night time again, she is asleep, and I look out the window east, across the Atlantic, to Spain, and this time I do not see the living room of the gypsy shaman, but the streets of Madrid at night, and all the people, and the word Jupiter comes to mind and I am about to say of course, Jupiter, and The Spanish interrupt and say “Yes, you are right it is the largest planet in the solar system, you are right to consider it, all else will flow from it.�

I know ratios, in mathematics are the most interesting subject, like pi, the ratio of the circumference of a circle to its diameter, and the golden ratio, so I consider the ratio of the orbit of Saturn (the second largest planet in the solar system) to the orbit of Jupiter at their closest approaches to The Sun, and find it is nine-fifths (nine compared to five) which divided out is one point eight (1.8).

I then proceed to the next logical step: not ratios, but proportions. A ratio is this compared to that, but a proportion is this is to that as this is to that. So the question is: Saturn is to Jupiter as what is to what? Of course the answer is as Gold is to Silver. Gold is divine; silver is next down on the list. Of course one does not compare a dozen oranges to a half dozen apples, but a dozen of one to a dozen of the other, if one wants to extract any kind of meaning. But atoms of gold and silver are not measured in dozens, but in moles. So I compared a mole of gold to a mole of silver, and I said no way, it is nine-fifths, and Saturn is indeed to Jupiter as Gold is to Silver.

I said to myself: How far does this go? The Shaman’s son once told me he was in love with the moon. So I compared the radius of the sun, the distance from its center to its surface to the lunar orbital radius, the distance from the center of the earth to the center of the moon. It was Nine compared to Five again!

Chapter Seven I had found 9/5 was at the crux of the Universe, but for every yin there had to be a yang. Nine fifths was one and eight-tenths of the way around a circle. The one took you back to the beginning which left you with 8 tenths. Now go to eight tenths in the other direction, it is 72 degrees of the 360 degrees in a circle. That is the separation between petals on a five-petaled flower, a most popular arrangement. Indeed life is known to have five-fold symmetry, the

13 of 64 physical, like snowflakes, six-fold. Do the algorithm of five-fold symmetry in reverse for six-fold symmetry, and you get the yang to the yin of nine-fifths is five-thirds.

Nine-fifths was in the elements gold to silver, Saturn to Jupiter, Sun to moon. Where was fivethirds? Salt of course. “The Salt Of The Earth” is that which is good, just read Shakespeare’s “King Lear”. Sodium is the metal component to table salt, Potassium is, aside from being an important fertilizer, the substitute for Sodium, as a metal component to make salt substitute.

The molar mass of potassium to sodium is five to three, the yang to the yin of nine-fifths, which is gold to silver. But multiply yin with yang, that is nine-fifths with five-thirds, and you get 3, and the earth is the third planet from the sun.

I thought the crux of the universe must be the difference between nine-fifths and five-thirds. I subtracted the two and got two-fifteenths! Two compared to fifteen! I had bought the Shaman his fifteenth rubber hose, and after he made me into the AE35 Antenna one of his first transmissions to me was: “God Is An Idea: There Are Two Elements”.

It is so obvious, the most abundant gas in the Earth Atmosphere is Nitrogen, chemical group 15 and the Earth rotates through 15 degrees in one hour.

14 of 64 The atmosphere and functionality of the cave is built around two chairs, a hose, and an

Hibachi. 

15 of 64 The tunnel actually branches off at several points leading to other chambers. But the chamber

of hoses is actually the first one on the right. 

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The hoses rest on the floor of the chamber of hoses, somewhat like this: 

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This is a completely accurate version of Manuel’s Antenna:

18 of 64 Spanish Hoses

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A Japanese Hibachi

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At some point, Manuel revealed to me I was a polarimeter. This is how they work:

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All of this lead me to discover the marvelous work of Robert Conroy and his three elemental lengths:

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I later made my own derivation of the elemental lengths, and decided to include the square root of three:

23 of 64 But before that, to know Manuel was to come to find myself under the wing of a California Sikh (Amarjit), who spoke of the same mathematical ideas as Manuel. It would seem the Sikhs of India today know the same things the Gypsies know today, even though they were in India 1500 years ago. 

24 of 64 Amarjit


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An Indian Tabla Set

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I found myself in the medioambiente (atmosphere) of an Indian ethnomusicologist from the University of Delhi, taking tabla lessons. First he explained to me that he was not an idle man, that he had many students and taught from five in the morning to 6 in the evening, and that during that time he prepared a special soup for all those that were his students. One of the first things he told me was that in India there are many false gurus, that will not really teach you, but that this was not his consciousness, that he would really teach me. He said he would put me on a program of learning to play Bahjrans and Kirtans, rhythms of 6 and 7 which fall under the category of Guzals, or Indian romantic music, but that he would be playing and composing temple music, called tin tal, which was the cycle of 16 considered the highest and most spiritual form of North Indian Classical music.

The training began with the history of the tabla which has its origins in the mridangam. It was the Muslim King in India, Amir Kusuro, who took the mridangam, which was closed on both ends, the left side played with the left hand and the right side played with the right hand, and broke it into two, the Dayan and Bayan, with the Dyan being the high tones and the Bayan being the low tones played with right and left hands respectively. In the center of each is a circle of dry ink that allows the drums to be tuned to precise pitches. The ink is rubbed into the tabla, as was explained to me, with a stone that floats on water and glows like a cat’s eye and only exists in a few secret, undisclosed locations, only known to tabla makers. Amarjit, that was his name, had made it a point of telling me that among the rhythms I would be learning was a cycle of seven and one half and a cycle of 13 1/2. I find that interesting. If a person considers each beat of one half a beat of one, then that is a cycle of 15. It was the Gypsy Shaman, Manuel, who first pointed out to me that 15 was of primary importance, and as a scientist, I can’t help but think in reference to that, the earth rotates through 15 degrees in an hour, and the most abundant element in the earth’s atmosphere is nitrogen which is in chemical group 15 in the periodic table. Let us multiply Amarjit’s 7 1/2 by the 16 of his tin tal. It is 120. 120 are the degrees in the angles of a regular hexagon, an equal angled, equal sided polygon with six sides. Let us subtract 120 from the 360 degrees that are in a circle and divide the result by that same 360 and then add the result to one: 360-120 = 240 240/360 = 2/3 2/3+1 = 5/3 This is the value that represents the yang of the cosmic yin and yang that came to us from the Gypsy Shaman, Manuel, that represents six-fold symmetry, or the physical aspects of nature, like snowflakes. The biological aspects are in five-fold symmetry, derived as above: 360/5 = 72 360-72 = 288 288/360 = 4/5 4/5 + 1 = 9/5 = 1.8 Let us divide Amarjit’s stressed cycle 13.5 by 7.5. We find it is 1.8, which equals the yin of 9/5 that is representative of the organic aspects of nature to which the Gypsy Shaman, Manuel

27 of 64 guided us in my story Gypsy Shamanism and the Universe, which I will present following the story we are telling now.

After my tabla lesson, I left the room and just as I came out, several people from India were coming into the house. I noticed in the living room was lots of clothing and art from India. I was introduced to these people, who obviously ran a store, and they told me they were just coming back from an interactive convention between Indians and Mexicans. The interchange was one between ideas in the cooking of Indian food and Mexican food. They were all wearing name tags that said on them, “Friendly Amigo”.

Later I met with Amarjit and he took me to a music store to give me a lesson in buying instruments. On our way back, with his student driving, me in the front seat, Amarjit laid stretched out on the back back seat telling me that the store owner’s refusal of our price offer for a crude guitar indicated that he was “A very greedy man and would not get far in life”. At some point I told Amarjit that I had dreams of him giving me tabla lessons. He told me he could communicate with me in this way.

Upon learning that God told me the Gypsy Shaman, Manuel, always second guesses him, and Manuel telling me that because of this, he goes out into the world to do God’s work for him at his request, Amarjit and his students were going to change their course from one of merging with God, to one of merging with Manuel.

Ian Beardsley May 15, 2015

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”The ink is rubbed into the tabla head by a stone that floats on water and glows like a cat’s eye.”

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One of Amarjit’s innovations was to use neoprene pants when playing tabla. He asked me to be his guide and we went on a quest in my truck to find such pants at the various outlets of outdoor outfitters.

30 of 64 The Bronze Age

Often the one thing you are looking for is the one thing that was left out of the story.

If you are an archaeologist you understand that gold and silver were important to early civilizations, especially to be used for ceremonial jewelries. But, you would also know that copper was used earlier and more as it is a soft and malleable metal that can be worked without being heated, pounded out into flat sheets.

Copper (Cu) used tin (Sn) as an alloying metal to make bronze, which was the beginning of the Bronze Age in Mesopotamia around 3500 BC. These elements are the elements left out of Manuel’s and Amarjit’s stories, and so are just what are being suggested. Today the alloying metal for bronze is zinc (Zn). Let us look at the ratio of the molar masses of tin to zinc: Sn/Zn = 118.71/65.39 = 1.8154 ~ 1.8 = 9/5 It is the nine-fifths around which our stories have been centered.

Ian Beardsley May 15, 2015

!

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Hand pounded copper ashtray demonstrating its malleability.

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Two works in silver, one in gold, demonstrating its use for ceremonial and spiritual purposes. 

33 of 64 The Sequence We considered the ratio nine to five, then the proportion and found it in Saturn Orbit to Jupiter orbit, Solar Radius to Lunar Orbit, Gold to Silver and if flower petal arrangements. It is left then to consider the whole number multiples of nine-fifths (1.8) or the sequence: 1.8, 3.6, 5.4, 7.2,‌ in other words, and we look to see if it is in the solar system and find it is in the following ways: 1.8 Saturn Orbit/Jupiter Orbit Solar Radius/Lunar Orbit Gold/Silver 3.6 (10)Mercury Radius/Earth Radius (10)Mercury Orbit/Earth Orbit (earth radius)/(moon radius)= 4(degrees in a circle)(moon distance)/(sun distance) = 3.7 ~ 3.6 There are about as many days in a year as degrees in a circle.

(Volume of Saturn/Volume Of Jupiter)(Volume Of Mars) = 0.37 cubic earth radii ~ 3.6 The latter can be converted to 3.6 by multiplying it by (Earth Mass/Mars Mass) because Earth is about ten times as massive as Mars.

5.4 Jupiter Orbit/Earth Orbit Saturn Mass/Neptune Mass 7.2 10(Venus Orbit/Earth Orbit)

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O for Earth = 1.495979E13 cm R for Earth = 6,378 km M for Earth = 5.976E27 g Earth-Moon Separation: 3.84E10 cm Solar Radius: 6.9599E10 cm Molar Mass of Gold: Au = 196.97 Molar Mass of Silver: Ag = 107.87 Saturn (minimum distance from sun) = 9.014 AU = 1.348E9 km Jupiter (minimum distance from sun) = 4.951 AU = 7.409E8 km Jupiter (maximum distance from the sun): 5.455 AU ~ 5.4 Astronomical Units

35 of 64 The Neptune Equation If we consider as well the sequence where we begin with five and add nine to each successive term: 5, 14, 23, 32…Then, the structure of the solar system and dynamic elements of the Universe and Nature in general are tied up in the two sequences: 5, 14, 23, 32,… and 1.8, 3.6, 5.4, 7.2,…

How do we find the connection between the two to localize the pivotal point of the solar system?

We take their difference, subtracting respective terms in the second sequence from those in the first sequence to obtain the new sequence: 3.2, 10.4, 17.6, 24.8,…

Which is an arithmetic sequence with common difference of 7.2 meaning it is written 7.2n – 4 = a_n The a_n is the nth term of the sequence, n is the number of the term in the sequence.

This we notice can be written: [(Venus-orbit)/(Earth-orbit)][(Earth-mass)/(Mars-mass)]n – (Mars orbital #) = a_n We have an equation for a sequence that shows the Earth straddled between Venus and Mars.

Venus is a failed Earth. Mars promises to be New Earth.

The Mars orbital number is 4. If we want to know what planet in the solar system holds the key to the success of Earth, or to the success of humans, we let n =3 since the Earth is the third planet out from the Sun, in the equation and the result is a_n = 17.6. This means the planet that holds the key is Neptune. It has a mass of 17.23 earth masses, a number very close to our 17.6.

Not only is Neptune the indicated planet, we find it has nearly the same surface gravity as earth and nearly the same inclination to its orbit as earth. Though it is much more massive than earth, it is much larger and therefore less dense. That was why it comes out to have the same surface gravity.

36 of 64 The Uranus Equation I asked what needs to be done to solve My Neptune Equation, by going deep with the guitar in Solea Por Buleras. I found the answer was that I didn’t have enough information to solve it.

Then I realized I could create the complement of the Neptune equation by looking at the Yang of 5/3, since the Neptune equation came from the Yin of 9/5.

We use the same method as for the Neptune equation: Start with 8 and add 5 to each additional term (we throw a twist by not starting with 5) 5/3 => 8, 13, 18, 23,…

List the numbers that are whole number multiples of 5/3: 5/3n = 1.7, 3.3, 5, 6.7,…

Subtract respective terms in the second sequence from those in the first: 6.3, 9.7, 13, 16.3,…

This is an arithmetic sequence with common difference 3.3. It can be written: (a_n) = 3 + 3.3n This can be wrttten: Earth Orbital # + (Jupiter Mass/Saturn Mass)n = a_n Letting n = 3 we find a_n = 13 The closest to this is the mass of Uranus, which is 14.54 earth masses. If Neptune is the Yin planet, then Uranus is the Yang planet. This is interesting because I had found that Uranus and Neptune were different manifestations of the same thing. I had written: I calculate that though Neptune is more massive than Uranus, its volume is less such that their products are close to equivalent. In math: N_v = volume of Neptune N_m = mass of Neptune U_v = volume of Uranus U_m = mass of Uranus (N_v)(N_m) = (U_v)(U_m)

37 of 64 Europia We now connect the first four points of the Neptune equation and integrate from one to four, the equation: F(x) = 7.2x –4 The inner terrestrial planets.

We take the derivative of the Uranus equation: F(x) = 3 + 3.3x So that F’(x) = 3.3 We consider the integral the mass of a planet in earth masses, which comes out to be 42. We consider the 3.3 to be the acceleration at its surface in earth gravities. Knowing these two quantities we determine the planet is about three and a half times larger than the Earth. Knowing its mass and size, we can determine its density, and from that its composition, which turns out to be Europium, element 63, which is phosphorescent. We will call the planet, Europia. notice that: 3+3.3 =6.3 and 6.3(10) = 63 63 is the ASCII value for the question mark on the computer keyboard (63=?). 

38 of 64 Indeed that the discovery that F(x) = 3 + 3.3x not only points to the density of Europium in its integral from one to four, the terrestrial planets, but that it points to Europium (Eu) because 10(3+3.3)=63 and Europium is element 63, is an incredible thing. But how do we explore this when 3 is velocity and 3.3 is acceleration? Simple. Substitute i for x, and it it becomes a complex number: 3+3.3i This has meaning in the imaginary plane: its value is expressed as its amplitude with the theorem of Pythagoras:

This presents an intriguing mystery. Let us do the Europium calculation again, but take care in rounding our numbers more accurately, to get a more accurate value for the density of the mystery element and see exactly how close it is to the actual density of Europium at standard temperature and pressure (STP).

We will say r=4.460 which is only two ten thousandths from the actual value. 




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44 of 64 Manuel Incorporated - Excerpt Manuel, was not just any man of business. He maintained a business relationship with some off world, interstellar societies. He was not just a politician, but an exopolitician: He was often an ambassador for humanity to worlds beyond our solar system, despite humans having never built a craft that could leave it and go to the stars. He saw no reason why off earth intelligent life should not be included in his business domain. Gypsies never have known borders since that day they left India and went west, however, few people have ever known that the space surrounding the earth was not a border to them either.

Manuel Incorporated was set up in the Alpha Centauri Star System about four point two light years away. It was there that he negotiated the construction of a sphere, called the Europium Sphere, in orbit around Alpha Centauri, at Lagrange point, as a source for the element europium, because it had great value as a phosphorescent substance that can be used as the source of red and blue in computer screens and fluorescent lights. Those were the colors that this phosphorescent substance would radiate, or glow, in other words.

It must be understood that the Element Europium, is highly reactive: That is, it combines with anything it comes in contact with. It cannot exist isolated. Therefore, the Europium sphere was combined with oxygen to make the compound ((Eu_2)(O_3)) that is, the compound Europium (III) Oxide (Europium Three Oxide).

The answer to the construction of Europia was simple. Consider the Summary written in Volume One of Cosmic Archaeology:‌.

The moon is about three times larger than the Europium Sphere, or about pi times larger.

Manuel Incorporated – Excerpt Thus the size of the Europium Sphere in Orbit around Alpha Centauri was 565 kilometers. The density of Europium Three Oxide is: 7.40 grams per cubic centimeter. The volume of the Europium Sphere in cubic centimeters is: (4/3)(3.141)(565 km)^3 = 7.55 E 08 cubic kilometers or (565)(1000)(100) = 5.65E7 cm (4/3)(3.141)(5.65E7 cm)^3 = 7.55E23 cubic centimeters That corresponds to: (7.55E23)(7.4) = 5.587E24 grams of Europium Three Oxide (5.587E24 g)/(1000) = 5.587E21 kilograms of Europium Three Oxide 5.587E18 metric tons.

45 of 64 The stuff was made out of common substances from dead worlds, in a process of nuclear chemistry, not yet an available technology on Earth.

The stuff sold for far more than a euro per metric ton in galactic denomination, and Manuel Incorporated was thus worth well more than 18 figures.

Manuel Incorporated In France - Excerpt Among his on Earth businesses, he had a restaurant in Paris, France on the Rue Di Bazaar that sold one thing: chocolate truffles. However each truffle was served in the sun on a patio, wrapped in foil made of gold. You can imagine the prices on the menu, and the clientele…

Manuel’s Intergalactic Cargo Industry - Excerpt Manuel distributed his Europium Three Oxide throughout the Galaxy by employing Free Traders throughout the Galaxy who piloted cargo ships. The only currency he accepted was bricks of pure gold. He then employed Gypsy artisans, many of them family, to pound out the gold into thin, flat sheets of gold foil that he used to wrap his truffles for his Parisian truffle business. His earnings went towards funding his research institute, Manuel’s Genesis Project which did research for turning dead worlds into life supporting paradises inspired by the Project Genesis that was a theme of a Star Trek movie. He actually sent me a document that was part of the research produced. It was the following:…

By Ian Beardsley Copyright by Ian Beardsley February 2013

46 of 64 Rue De Bazaar

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Chocolate Truffles


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All That Can Be Said They originated in the Far East, and passed some through the south, and others through the north over a period of A Thousand Years through deserts. They became Artists, and camped where there was no one else, and went unseen and unknown during all that time, only to unite and settle at Land’s End, in neighborhoods, barrios, or quarters of western construct, and to let out only one verse of one of their poets, who is anonymous: “If there is someone in the street, he is familiar with it. If there is someone in the street, he knows him.”

49 of 64 Ian Beardsley on Dovid Krafchow by Ian Beardsley © 2016

50 of 64 Richard Feynman said calculus is the language of God. Let’s explain it so non-scientific intuitive types can understand it. Acceleration is the change in velocity with time: a = meters /sec/sec = meters /sec

2

The time over which an object accelerates is its velocity: €

meters meters ⊗ sec = = velocity 2 sec sec dx velocity = v = dt

at =

Velocity is the change in distance over time. €

We write: dx = at dt

€

Take the dt from the bottom left and throw it to the top right and put an elongated “s” on both sides of the equation evaluated from 0 to x on the left and 0 to t on the right: ∫

x

t

dx = a ∫ 0 tdt 0

Remove the elongated s on each side and dx becomes x and dt becomes t: €

€

1 x = at 2 2

That is distance in terms of acceleration. Calculus is the mathematics of change. The factor of one half comes in because if the acceleration is that of earth gravity, which is 9.81 meters per second squared, the falling object is traveling 9.81 meters per second after one second, but will have traveled half of 9.81 meters after that time. Remember a falling object starts at rest and speeds up over time.

Ian Beardsley April 15, 2014

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Equations of Light


52 of 64 Dovid Krafchow says: “Faster Than The Speed of Light” 365 squared times 2000 equals 266,450,000 He says: “The thing about this number is it is the approximate number of years the scientists say that the stars blinked on after the big bang,…

That, there was a thing that happened and there were no stars. Then, after about a quarter of a billion (two hundred and fifty million years) all the sudden the stars went on, …”

And this has a reverse meaning in the Kabbalah. Instead of the big bang, the Zohar explains that there was a big evacuation,…”

Because in the beginning, all there was was called hard light. Light without any space, … therefore there is no time,… just hard light” And, if God wanted creation - time and space - there had to be a hole made inside of the hard light,…and that is where creation is, …”

So instead of there being,.. instead of light coming to us for millions of years, it was really the opposite: that the shards, the stars, moved from this place. And, that is why we see that the stars are moving away from us in every direction that we look,… because we’re actually at the center of creation. This is how the Zohar explains it.”

Dovid’s Constant (D) = 266,450,000 Einstein’s Constant (C=186,282) This means since, 266,450,000/186,282 = 1430 That Dovid’s Speed is 1,430 times faster than the speed of light.

The speed of light in meters per second is 2.998E8 meters per second (2.998E8 m/s)(1,430) = 4.28714E11 m/s = 4.28714E8 km/s (365 days/year)(24 hours/day)(60 minutes/year)(60 seconds/minute) = 3.1536E7 seconds per year (4.2871E8 km/s)(3.1536E7 seconds/year)=1.35E16 km/year = Dovid’s Velocity The closest star system is Alpha Centauri = 4.367 light years away There are 9.461E12 kilometers in one light year (9.461E12 km/ly)(4.367 ly)=4E13 kilometers to Alpha Centauri

53 of 64 Distance = (Velocity)(Time) Or, Time = (Distance)/(Velocity)=(4E13 km)/(1.35E16 km/year)=0.003 years to reach Alpha Centauri at Dovid Velocity, which takes about 4.367 years at Einstein Velocity.

4/0.003 =1,333 times faster which is right (1,430 above because we rounded numbers making the output slightly different). The key numbers here suggest to predict the future, we make 3 jumps away from the star system and 4 towards is, meaning we make it in 3+4=7 jumps instead of the 10 jumps of Einstein’s Velocity, which means human development will be quicker and so we will develop hyperdrive sooner. Let us see what the results are with Dovid’s Constant by running my program, ModelFuture. First we Run it for Einstein, then Dovid, so we can compare the two and see how much Dovid speeds up human progress, if he is right.

54 of 64 Using Einsteins Constant (p^n1)(q^n2)[W=N!/(n1!)(n2!)] x=e^(c*t) W is the probability of landing on the star in N jumps.

N=n1+n2, n1=number of one light year jumps left, n2=number of one light year jumps right.

What is 1, the nearest whole number of light years to the star, and 2, what is the star's name?

Enter 1: 4 Enter 2: alphacentauri Star name: alphacentauri Distance: 4 What is n1? 3 What is n2? 7 Since N=n1+n2, N=10 What is the probability, p(u), of jumping to the left? 1 What is the probability, p(v), of jumpint to the left? 2 What is the probability, q(y), of jumping to the right? 1 What is the probability, q(z), of jumping to the right? 2 p=u:v q=y:z N factorial = 1.000000 N factorial = 2.000000 N factorial = 6.000000 N factorial = 24.000000 N factorial = 120.000000 N factorial = 720.000000 N factorial = 5040.000000 N factorial = 40320.000000 N factorial = 362880.000000 N factorial = 3628800.000000 n1 factorial = 1.000000 n1 factorial = 2.000000 n1 factorial = 6.000000 n2 factorial = 1.000000 W=59062.500000 percent W=59063.00 percent rounded to nearest integral n2 factorial = 2.000000 W=29531.250000 percent W=29531.00 percent rounded to nearest integral n2 factorial = 6.000000 W=9843.750000 percent W=9844.00 percent rounded to nearest integral n2 factorial = 24.000000 W=2460.937500 percent W=2461.00 percent rounded to nearest integral n2 factorial = 120.000000

55 of 64 W=492.187500 percent W=492.00 percent rounded to nearest integral n2 factorial = 720.000000 W=82.031250 percent W=82.00 percent rounded to nearest integral n2 factorial = 5040.000000 W=11.718750 percent W=12.00 percent rounded to nearest integral What is t in years, the time over which the growth occurs? 40 log(W)=1.079181 loga/t=0.026980 growthrate constant=0.062136 log 100 = 2, log e = 0.4342, therfore T=2/[(0.4342)(growthrate)] T=74.13 years What was the begin year for the period of growth? 1969 Object achieved in 2043.13

56 of 64 Using Krafchow’s Constant (p^n1)(q^n2)[W=N!/(n1!)(n2!)] x=e^(c*t) W is the probability of landing on the star in N jumps.

N=n1+n2, n1=number of one light year jumps left, n2=number of one light year jumps right.

What is 1, the nearest whole number of light years to the star, and 2, what is the star's name?

Enter 1: 4 Enter 2: alphacentauri Star name: alphacentauri Distance: 4 What is n1? 3 What is n2? 4 Since N=n1+n2, N=7 What is the probability, p(u), of jumping to the left? 1 What is the probability, p(v), of jumpint to the left? 2 What is the probability, q(y), of jumping to the right? 1 What is the probability, q(z), of jumping to the right? 2 p=u:v q=y:z N factorial = 1.000000 N factorial = 2.000000 N factorial = 6.000000 N factorial = 24.000000 N factorial = 120.000000 N factorial = 720.000000 N factorial = 5040.000000 n1 factorial = 1.000000 n1 factorial = 2.000000 n1 factorial = 6.000000 n2 factorial = 1.000000 W=656.250000 percent W=656.00 percent rounded to nearest integral n2 factorial = 2.000000 W=328.125000 percent W=328.00 percent rounded to nearest integral n2 factorial = 6.000000 W=109.375000 percent W=109.00 percent rounded to nearest integral n2 factorial = 24.000000 W=27.343750 percent W=27.00 percent rounded to nearest integral What is t in years, the time over which the growth occurs? 40 log(W)=1.431364 loga/t=0.035784 growthrate constant=0.082414 log 100 = 2, log e = 0.4342, therfore

57 of 64 T=2/[(0.4342)(growthrate)] T=55.89 years What was the begin year for the period of growth? 1969 Object achieved in 2024.89 We see that with Einstein’s constant we reach the stars in 2043, but with Dovid’s constant we reach the stars in 2024. We get there 19 years sooner.

To clarify, we said Dovid's constant is 1,430 times faster than the speed of light. Therfore 4-3= 1 and 4+3=7. So input in program is n1 =3 n2=4 landing at plus 1 and n1+n2=7.

We say landing at alpha centauri which is 4, is like landing at 1, because we are traveling faster.

To clarify, we said Dovid's constant is 1,430 times faster than the speed of light.

Therefore 4-3= 1 and 4+3=7. So input in program is n1 =3 n2=4 landing at plus 1 and n1+n2=7. We say landing at alpha centauri which is 4, is like landing at 1 in 7 jumps instead of landing at 4 in 10 jumps, because we are traveling faster.

Ian Beardsley August 17, 2016 

58 of 64 Star System: Alpha Centauri Spectral Class: Same As The Sun Proximity: Nearest Star System Value For Projecting Human Trajectory: Ideal


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The probability of landing at four light years from earth at Alpha Centauri in 10 random leaps of one light year each (to left or right) is given by the equation of a random walk:

{ W }_{ n }({ n }_{ 1 })=\frac { N! }{ { n }_{ 1 }!{ n }_{ 2 }! } { p }^{ n1 }{ q }^{ n2 }\\ N={ n }_{ 1 }+{ n }_{ 2 }\\ q+p=1

To land at plus four we must jump 3 to the left, 7 to the right (n1=3, n2 = 7: 7+3=10): 

60 of 64 Using our equation:

!

We would be, by this reasoning 12% along in the development towards hyperdrive.

Having calculated that we are 12% along in developing the hyperdrive, we can use the equation for natural growth to estimate when we will have hyperdrive. It is of the form: ! t is time and k is a growth rate constant which we must determine to solve the equation. In 1969 Neil Armstrong became the first man to walk on the moon. In 2009 the European Space Agency launched the Herschel and Planck telescopes that will see back to near the beginning of the universe. 2009-1969 is 40 years. This allows us to write: ! log 12 = 40k log 2.718 0.026979531 = 0.4342 k k=0.0621 We now can write: ! ! log 100 = (0.0621) t log e t = 74 years 1969 + 74 years = 2043 Our reasoning would indicate that we will have hyperdrive in the year 2043.

61 of 64 Study summary: 1. We have a 70% chance of developing hyperdrive without destroying ourselves first.

2. We are 12% along the way in development of hyperdrive.

3. We will have hyperdrive in the year 2043, plus or minus.

Sierra Waters was handed the newly discovered document in 2042. 

62 of 64 modefuture.c #include <stdio.h> #include <math.h> int main (void) { printf("\n"); int N, r; double u, v, y, z; double t,loga, ratio; int n1, n2; char name[15]; float W,fact=1,fact2=1,fact3=1,a,g,rate,T,T1; double x,W2; printf("(p^n1)(q^n2)[W=N!/(n1!)(n2!)]"); printf("\n"); printf("x=e^(c*t)"); printf("\n"); printf("W is the probability of landing on the star in N jumps.\n"); printf("N=n1+n2, n1=number of one light year jumps left,\n"); printf("n2=number of one light year jumps right.\n"); printf("What is 1, the nearest whole number of light years to the star, and\n"); printf("2, what is the star's name?\n"); printf("Enter 1: "); scanf("%i", &r); printf("Enter 2: "); scanf("%s", name); printf("Star name: %s\n", name); printf("Distance: %i\n", r); printf("What is n1? "); scanf("%i", &n1); printf("What is n2? "); scanf("%i", &n2); printf("Since N=n1+n2, N=%i\n", n1+n2); N=n1+n2; printf("What is the probability, p(u), of jumping to the left? "); scanf("%lf", &u); printf("What is the probability, p(v), of jumpint to the left? "); scanf("%lf", &v); printf("What is the probability, q(y), of jumping to the right? "); scanf("%lf", &y); printf("What is the probability, q(z), of jumping to the right? "); scanf("%lf", &z); printf("p=u:v"); printf("\n"); printf("q=y:z"); printf("\n"); for (int i=1; i<=N; i++)

63 of 64 { fact = fact*i; printf("N factorial = %f\n", fact); a=pow(u/v,n1)*pow(y/z,n2); } for (int j=1; j<=n1; j++) { fact2 = fact2*j; printf("n1 factorial = %f\n", fact2); } for (int k=1; k<=n2; k++) { fact3 = fact3*k; printf("n2 factorial = %f\n", fact3); x=2.718*2.718*2.718*2.718*2.718; g=sqrt(x); W=a*fact/(fact2*fact3); printf("W=%f percent\n", W*100); W2=100*W; printf("W=%.2f percent rounded to nearest integral\n", round(W2)); } { printf("What is t in years, the time over which the growth occurs? "); scanf("%lf", &t); loga=log10(round(W*100)); printf("log(W)=%lf\n", loga); ratio=loga/t; printf("loga/t=%lf\n", ratio); rate=ratio/0.4342; //0.4342 = log e// printf("growthrate constant=%lf\n", rate); printf("log 100 = 2, log e = 0.4342, therfore\n"); printf("T=2/[(0.4342)(growthrate)]\n"); T=2/((0.4342)*(rate)); printf("T=%.2f years\n", T); printf("What was the begin year for the period of growth? "); scanf("%f", &T1); printf("Object achieved in %.2f\n", T+T1); } }

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Ian Beardsley