Math Long Division Math Long Division In mathematics, polynomial long division is a process that is used to dividing a polynomial value by another polynomial value. The value that is divided is of same or lower degree. This process is said to be polynomial long division. Polynomial Long Division is denoted as the term that is added, subtract and multiplied. The representation of polynomial Long Division is 8xy2 + 4x â&#x20AC;&#x201C; 9. So the combination of both the word gave the meaning many terms. Polynomial can also have constant, variables, and exponent values. Consider a polynomial p (s), D (s) where degree (D) < degree (p), then the quotient polynomial Q (s) and remainder polynomial R (s) with degree(R) < degree(D), P (s) = Q (s) + R (s) â&#x2021;&#x2019; P (s) = D (s) Q (s) + R (s), D (m) D (m) Some steps are given to find the polynomial Long Division. Step 1: To find the long division first of all we we will see the higher coefficient term that is present in the given equation. Step 2: Then we multiply the divisor to the leading term so that we get the exact coefficient term. Know More About :- Define Rational Expression
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Step: Then getting the coefficient term we just change the sign of the variable. If positive sign is present in the expression, then change it into negative sign and vice-versa. Step4: At last cancel the term that has same coefficient or variable. Now we will apply all these steps in the example to solve the polynomial long division. Example: Divide 3s3 – 2s2 + 4s – 20 s2 + 3s + 3 Solve the example by long division polynomial? Solution: - 3s3 – 2s2 + 4s – 20 s2 + 3s + 3 Firstly we set the given expression in the division form: s2+ 3s + 3) 3s3 – 2s2 + 4s – 20 Then divide the first term of the numerator by the highest term of the denominator. or firstly solve the higher coefficient term. s2 + 3s + 3) 3s3 – 2s2 + 4s – 20( 3s 3s3 + 9s2 + 9s Now we apply the sign change rule, if there is positive sign then change into negative or vice-versa. And subtract all the variables. s2 + 3s + 3) 3s3 – 2s2 + 4s – 20(3s 3s3 + 9s2+ 9s -11s2 – 5s – 20 After solving the equation we get, and now multiply the divisor by the value -11 s2 + 3s + 3) 3s3 – 2s2 + 4s – 20 (3s - 11 3s3 + 9s2 + 9s Read More About :- Subtracting Rational Numbers
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