Final Exam Solution, eece 413
1. + 4θ =Tc +Td θ x1 =θ, x 2 =θ = −4 x1 +Tc x 1 =θ = x 2, x 2 =θ
a)
x1 0 x 2 = −4 y = [1
1 x1 0 + Tc 0 x 2 1
x1 0 ] x 2
x = Fx + Gu , y = Hx + Ju
where
1 0 0 F = , G = 1 − 4 0 H = [1 0], J = 0