Lightweight Steel Structures part.2

Page 1

Sabah Sabah Shawkat Sabah Shawkat Sabah Shawkat Shawkat

Sabah Shawkat

STRUCTURES STRUCTURES STRUCTURES STRUCTURES

LIGHTWEIGHT STEEL STRUCTURES

STEEL STEEL STEEL STEEL LIGHTWEIGHT LIGHTWEIGHT LIGHTWEIGHT LIGHTWEIGHT

LIGHTWEIGHT LIGHTWEIGHT LIGHTWEIGHT LIGHTWEIGHT LIGHTWEIGHT STEEL STEEL STEEL STEEL STEEL STRUCTURES STRUCTURES STRUCTURES STRUCTURES STRUCTURES

Sabah Shawkat © Sabah Sabah Sabah Sabah Sabah Shawkat Shawkat Shawkat Shawkat Shawkat


Reviewer: Cover Design: Editor: Software Support: Publisher:

Prof. Dipl. Ing. Ján Hudák, PhD. Ing. Peter Novysedlák, PhD, M.Eng. Mgr. art. Peter Nosáľ prof. Ing. arch. Zuzana Pešková, PhD, Mgr.art. Ing. Richard Schlesinger, PhD. asc. Applied Software Consultants, s.r.o., Bratislava, Slovakia Tribun EU, s.r.o., Brno, Czech Republic

Sabah Shawkat © All rights reserved. No part of this book may be reprinted, or reproduced or utilized in any form or by any electronic, mechanical or other means, including photocopying, without permission in writing from the author.

Lightweight Steel Structures ©

Assoc. Prof. Dipl. Ing. Sabah Shawkat, MSc, PhD. 1. Edition, Tribun EU, s.r.o. Brno, Czech republic 2019 ISBN 978-80-263-1458-5

Definitions


Connections in steel structures Bolt connections Welded connections Splices Slip resistance Calculate the tension resistance of the joint Bearing resistance of splice plates Shear resistance of bolts Resistant the welds Calculate the resistance of the shear joint Shear resistance of bolts Resistance of welds Calculate the bending resistance of the flange plate joint Calculate the bending resistance of the splice with end-plates Rotation capacity of the splice Design the joint Column Bracket Detail of attachment - Steel Beam to Steel Column Beam-to-column joint Resistance of the joint

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Sabah Shawkat ©


132 132

Connections in steel structures Connections in steel structures

condition at steel beam supports. contrast element may fixed in its plane to transmit be be fixed in its plane to transmit condition at steel beam supports. ByBy contrast thethe element may bending allow rotation about axis. Note if pinned fixed joints made between bending butbut allow rotation about its its axis. Note thatthat if pinned or or fixed joints areare made between

Joints between structural elements, in one plane, may classified simple connections, Joints between structural lineline elements, in one plane, may be be classified as as simple connections,

element immovable support then of the element may move translationally an an element andand an an immovable support then thatthat endend of the element may notnot move translationally

sliding connections, pinned connections fixed connections, also known rigid as as sliding connections, as as pinpin or or pinned connections as as fixed connections, also known as as rigid

rotate in space, distinct from a movement which is merely relative to the member or or rotate in space, as as distinct from a movement which is merely relative to the member on on thethe

connections. simple connection allows rotation movement direction except connections. AA simple connection allows rotation andand movement in in anyany direction except

other side joint. Fixed joints, nearly fixed joints, between members said other side of of thethe joint. Fixed joints, or or nearly fixed joints, between twotwo members areare said to to

downwards only transmits shear force downwards a support. sliding downwards andand only transmits shear force thatthat actsacts downwards at at a support. AA sliding

provide continuity there is little or no rotation between members at the joint provide continuity so so thatthat there is little or no rotation between thethe members at the joint andand thethe

connection allows movement along of the element rotation only transmits shear connection allows movement along thethe lineline of the element andand rotation andand only transmits shear

members behave as no if no joint existed. However, joint is not necessarily fixed in space members behave as if joint existed. However, thethe joint is not necessarily fixed in space andand

force. A pinned connection allows rotation translational movement, it transmits shear force. A pinned connection allows rotation butbut no no translational movement, it transmits shear

may rotate about a support example. A way of characterising degree of fixity or stiffness may rotate about a support forfor example. A way of characterising thethe degree of fixity or stiffness

axial forces bending moment. fixed connection does allow translational andand axial forces butbut notnot bending moment. AA fixed connection does notnot allow translational

provided a semi-rigid connection either a support another member is to measure provided by by a semi-rigid connection either to to a support or or another member is to measure thethe

movement or rotation transmits shear, axial forces, bending torsional moment. movement or rotation andand transmits shear, axial forces, bending andand torsional moment.

rotation at the joint as the bending moment joint is varied. rotation at the joint as the bending moment on on thethe joint is varied. Figure bellow defines strength, stiffness deformation capacity a beam-to-column Figure bellow defines thethe strength, stiffness andand deformation capacity of of a beam-to-column connection designed to transfer a moment from beam column. M-φ curves in general M-φ curves in general connection designed to transfer a moment from thethe beam intointo thethe column. non-linear, practical application, it necessary is necessary idealise M-φcurves. curves. rotation non-linear, forfor practical application, it is to to idealise thethe M-φ TheThe rotation capacity a measure deformation obtained before failure somewhere in the capacity is aismeasure of of thethe deformation thatthat cancan be be obtained before failure somewhere in the

Sabah Shawkat © connection causes a drop in the moment resistance. connection causes a drop in the moment resistance.

strength, following classes distinguished: ForFor strength, thethe following classes cancan be be distinguished:

M≤Rd0,25 ≤ 0,25 Mpl.Rd MRd Mpl.Rd

nominally pinned nominally pinned partial-strength partial-strength

0,25 Mpl.Rd < Rd M< < pl.Rd Mpl.Rd 0,25 Mpl.Rd <M RdM

full-strength full-strength

M≥RdM ≥ pl.Rd Mpl.Rd MRd

full-strength if rotation capacity full-strength if rotation capacity is is

≥ 1,2 Mpl.Rd M≥Rd1,2 Mpl.Rd MRd

checked notnot checked where where MRd MRd

is the design moment resistance of the connection is the design moment resistance of the connection

Mpl.Rd Mpl.Rd

is the design strength of the beam (full plastic moment). is the design strength of the beam (full plastic moment).

Column web in shear, compression tension Column web in shear, compression andand tension practice is often difficult to fabricate fixed connections some rotation may take place In In practice it isit often difficult to fabricate fixed connections andand some rotation may take place between element side joint other. Such a joint is known between thethe element on on oneone side of of thethe joint andand thatthat on on thethe other. Such a joint is known as as a a semi-rigid connection and, strictly speaking is the condition of most joints which described semi-rigid connection and, strictly speaking is the condition of most joints which areare described being fixed rigid. A moment connection could described which although only as as being fixed or or rigid. A moment connection could be be described as as oneone which although only semi-rigid approaches behaviour a fixed connection transfers a substantial bending semi-rigid approaches thethe behaviour of of a fixed connection andand transfers a substantial bending moment. Note connections may fabricated particular requirements that, moment. Note thatthat connections may be be fabricated forfor particular requirements so so that, forfor example, they may allow rotation plane elements prevent twisting about example, they may allow rotation in in thethe plane of of thethe elements butbut prevent twisting about thethe axis element thus allowing torsional moments transmitted. This a common axis of of thethe element thus allowing torsional moments to to be be transmitted. This is ais common

Moment-rotation characteristic a semi-rigid joint with enough plastic rotation capacity Moment-rotation characteristic of aofsemi-rigid joint with enough plastic rotation capacity stiffness, classification is follows: as follows: ForFor stiffness, thethe classification is as

Connectionsininsteel steelstructures structures Connections Connections Connectionsininsteel steelstructures structures


133

Sj ≤ 0,5 EIb/Lb

nominally pinned semi-rigid

be a design requirement in certain instances, e.g. when plastic design is employed with plastic

0,5 EIb/Lb < Sj < 8 EIb/Lb (braced frames) or 25 EIb/Lb

(unbraced frames) rigid

Sj ≥ 8 EIb/Lb (braced frames)

or

Sj ≥ 25 EIb/Lb (unbraced frames)

EIb Lb

The Moment is equal to the stiffness of the member times the modulus of elasticity times the curvature. where curvature is given by,

where Sj

hinges forming in the connections.

is the (secant) rotational stiffness of the connection is the bending stiffness of the beam

1

M

EI

Now, the moment is also equal to the load applied times the deflection at the centre of the

is the span of the beam

column due to buckling, which is the acting moment, For the determination of the forces on the connection, a static analysis must be carried out. Such

2

d y

analysis includes the determination of the design loads and the modelling of the structure. In

1

the schematization of the structure, the stiffness of the connections is an important element.

1

M

Connections can be assumed rigid, as hinges or as having a stiffness between these two. The

EI

deformation capacity of the members (beams and columns) and of the connections plays an

2

dx

   1  

3

2   dy     dx     2

important role in the ultimate distribution of forces in the structure. All parts of the structure

Thus when you equate the acting and the reacting, that is the work done by the load and the

must be designed so that they can resist the calculated forces and have a deformation capacity

strain energy stored in the member and solve it you will get the Euler's formula which can be

that is consistent with the assumptions made in the global analysis.

written as below.

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The stiffness of the connection affects the level of loading for which it should be designed. A

M

F a

2

F

connection of low rotational stiffness does not attract major bending moments and therefore

non-braced frames the stiffness of the connections may have a major effect on the deflections

2

L

may be assumed as a pinned connection in the schematization of the structure.

Of course, the stiffness of the connections affects the deflections of the beams. Especially in

2

n    EI

Here n defines the mode shape of the column. Mode shape is the shape of the deformed structure. You will also find that the minimum value of F is when n =1.

of the structure as a whole and on its stability. If the connections are assumed rigid in the modelling for the static analysis of the structure, then consequently the form of the connections should be such that their deformations have a negligible influence on the load distribution and the deformations of the structure.

Connections may be bolted, riveted or welded. The principal design considerations are shear, tension and compression, and the calculations are relatively straightforward for the types of design covered.

On the other hand, if pinned connections are assumed, they should have sufficient flexibility to accommodate rotations without causing significant bending moments that may lead to premature failure of (parts of) the connection or connected members. The requirements for strength and stiffness are clear. They result from the static calculation. The requirement for deformation capacity is more qualitative. In practice it is sometimes difficult to check this requirement. Ductile connections that have a great deformation capacity contribute to the overall safety of the structure in the event that the connection becomes overloaded. Such connections may also

Connections in steel structures Connections in steel structures


134 132

Connections in steel structures

condition at steel beam supports. By contrast the element may be fixed in its plane to transmit bending but allow rotation about its axis. Note that if pinned or fixed joints are made between

Joints between structural line elements, in one plane, may be classified as simple connections,

an element and an immovable support then that end of the element may not move translationally

as sliding connections, as pin or pinned connections as fixed connections, also known as rigid

or rotate in space, as distinct from a movement which is merely relative to the member on the

connections. A simple connection allows rotation and movement in any direction except

other side of the joint. Fixed joints, or nearly fixed joints, between two members are said to

downwards and only transmits shear force that acts downwards at a support. A sliding

provide continuity so that there is little or no rotation between the members at the joint and the

connection allows movement along the line of the element and rotation and only transmits shear

members behave as if no joint existed. However, the joint is not necessarily fixed in space and

force. A pinned connection allows rotation but no translational movement, it transmits shear

may rotate about a support for example. A way of characterising the degree of fixity or stiffness

and axial forces but not bending moment. A fixed connection does not allow translational

provided by a semi-rigid connection either to a support or another member is to measure the

movement or rotation and transmits shear, axial forces, bending and torsional moment.

rotation at the joint as the bending moment on the joint is varied. Distinction between joint and connection Figure bellow defines the strength, stiffness and deformation capacity of a beam-to-column

Joints in portal frames

distinction between a joint from and athe connection shown in figure above ainconnection M-φ curves general connectionThe designed to transfer a moment beam intoisthe column.

Diagonal bracing is used to make framed walls and structures stiff. Long braces should

means a location at which two members are interconnected furthermore, therotation means of non-linear, for practical application, it is necessary to idealise and, the M-φ curves. The

preferably transfer the load with a tensile stress to avoid buckling.

interconnection (bolted connection). joint failure is as ansomewhere assembly in of the basic capacity is a measure of theconnection, deformationwelded that can be obtainedAbefore

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components (e.g.a drop bolt, in end-plate, stiffeners) that enables members to be connected together in connection causes the moment resistance. a waythe thatfollowing the relevant internal forces and moments can be transferred between them. Forsuch strength, classes can be distinguished: nominally pinned MRd ≤ 0,25 Mpl.Rd Bolt connections partial-strength 0,25 Mpl.Rd < MRd < Mpl.Rd Connections should be designed to transferM moments and/or shear forces and/or normal forces. full-strength Rd ≥ Mpl.Rd The next step in the capacity analysis is is to determine the distribution of forces within the connection, full-strength if rotation see figure below. It is not necessary andMoften not feasible to determine the real internal not checked Rd ≥ 1,2 Mpl.Rd distribution of forces. It is sufficient to assume a realistic distribution, provided that: where forcesmoment are in equilibrium with applied loading MRd 1. the internal is the design resistance of thethe connection

capableofofthe resisting the forces Mpl.Rd 2. each iscomponent the designisstrength beam (full plastic moment). 3. the deformations implied by the assumed distribution are within the deformation Column web in shear, compression and tension

capacity of the fasteners (bolts, welds) and of the connected parts.

In practice it is often difficult to fabricate fixed connections and some rotation may take place

Design forces can be assumed distributed according to the theory of elasticity, or according to

between the element on one side of the joint and that on the other. Such a joint is known as a

the theory of plasticity. The elastic distribution may always be used. Then the distribution of

semi-rigid connection and, strictly speaking is the condition of most joints which are described

the forces is proportional to the distance from the centre of rotation. The elastic distribution has

as being fixed or rigid. A moment connection could be described as one which although only

to be used, Slip-resistant connection at ultimate limit state, and in the case of those shear

semi-rigid approaches the behaviour of a fixed connection and transfers a substantial bending Joints in portal frames moment. Note that connections may be fabricated for particular requirements so that, for Braces are usually supplied in pairs, i.e. on both diagonals, so that one will always be in tension example, they may rotation in the plane of the elements but prevent twisting about the independently of allow the wind direction. axis of the element thus allowing torsional moments to be transmitted. This is a common

connections where the design shear resistance of the bolts is less than the bearing resistance (i.e. FvRd < FbRd). In other cases, the plastic distribution of internal forces may be used. Moment-rotation characteristic of a semi-rigid joint with enough plastic rotation capacity For stiffness, the classification is as follows:

Connectionsininsteel steelstructures structures Connections Connections Connectionsininsteel steelstructures structures


135

If the distance between the outermost bolts of a connection in the direction of the force is more than 15d (d being the nominal diameter), the shear resistance of the bolts shall be reduced by multiplying it by the following factor.

1

 Lf

 Lj  15d  200d

0.75   Lf  1.0

but

The bearing resistance shall be calculated as follows: 2.5  

FbRd

fu 

dt

Mb

 e1

min

 3 do

t

is the thickness of the relevant part

fu

is the ultimate tensile strength of the relevant part.

 1  fub   1.0 4 fu 

Distribution of forces between bolts

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Shear resistant of the bolt shall be calculated as follows:

Bearing resistance FbRd (kN) per bolt for t = 10mm

FvRd

FvRd

fub

0.6 

0.5 

fub 

Mb fub

Mb

As

for 8.8 grade

As

Distance

for 10.9 grade

Mb

is the partial safety factor 1,25

If the shear plane passes through the unthreaded shank of the bolt, the shear resistant of the bolt shall be calculated as follows:

fub 

M20

M24

18

22

26

M30 33

minim.

rec.

minim.

rec.

minim.

rec.

minim.

rec.

minim.

rec.

e1 mm

16

30

22

40

27

50

32

60

40

75

P1 mm

29

40

40

55

49

70

58

80

73

100

S235

35,4

66,5

46,9

85,3

58,9

109,1

70,9

132,9

87,3

163,6

S275

42,3

79,4

56,1

101,9

70,4

130,3

84,7

158,8

104,2

195,5

S335

50,2

94,2

66,5

120,9

83,5

154,5

100,4

188,3

123,6

231,8

S275N

38,4

72,0

50,8

92,4

63,8

118,2

76,8

144,0

94,5

177,3

S355N

48,2

90,5

63,9

116,1

80,2

148,5

96,5

180,9

118,8

222,7

S420N

51,2

96,0

67,8

123,3

85,1

157,6

102,4

192,0

126,1

236,4

S355M

46,3

86,8

61,3

111,4

76,9

142,4

92,6

173,5

113,9

213,6

S420M

49,2

92,3

65,2

118,5

81,8

151,5

98,5

184,6

121,2

227,3

S460M

52,2

97,8

69,1

125,6

86,7

160,6

104,4

195,7

128,5

240,9

spacing’s

is the tensile stress area of the bolt

0.6 

M16

13

and

is the ultimate tensile strength of the bolt

As

FvRd

M12

do mm

A

Mb Where A is the gross cross-section area of the bolt. The values have been calculated using value in EC2, Mb=1.25.

Connections in steel structures Connections in steel structures


136 132

The valuesininsteel this table have been calculated using the basic value in EC3, gMb = 1,25. For other Connections structures

condition at steel beam supports. By contrast the element may be fixed in its plane to transmit

thicknesses (but t<40mm) the values in the table shall be multiplied by a correction factor of

bending but allow rotation about its axis. Note that if pinned or fixed joints are made between

Joints between structural plane, may classified 1/10. The values in theline tableelements, are validinforone bolt grades 8.8beand 10.9. as simple connections,

an element and an immovable support then that end of the element may not move translationally

as sliding connections, as pin or pinned connections as fixed connections, also known as rigid Shear rupture resistance connections. A simple connection allows rotation and movement in any direction except A bolt group break down near theforce end ofthat profile. is called aatblock shear failure, which downwards andcan only transmits shear actsThis downwards a support. A sliding

or rotate in space, as distinct from a movement which is merely relative to the member on the

is causedallows by tensile rupture along holes on tension the holeshear group, connection movement along thethe linefastener of the element andthe rotation andface onlyoftransmits accompanied the grossallows sectionrotation yielding shear at the rowmovement, of the fastener holes along force. A pinned by connection butinno translational it transmits shearthe

members behave as if no joint existed. However, the joint is not necessarily fixed in space and

of the Themoment. block rupture mayconnection determine the the connection andshear axialface forces buthole notgroup. bending A fixed doesresistance not allowof translational where high-grade steels and bolts with small edge distances are used. movement or rotation and transmits shear, axial forces, bending and torsional moment.

provided by a semi-rigid connection either to a support or another member is to measure the

The shear rupture resistance of the profile end shall be calculated using the following formula:

Figure bellow defines the strength, stiffness and deformation capacity of a beam-to-column

VeffRd

 fy     3 

Aveff  M0

other side of the joint. Fixed joints, or nearly fixed joints, between two members are said to provide continuity so that there is little or no rotation between the members at the joint and the

may rotate about a support for example. A way of characterising the degree of fixity or stiffness

rotation at the joint as the bending moment on the joint is varied.

connection designed to transfer a moment from the beam into the column. M-φ curves in general

Aveff

t Lveff

Lveff

Lv  L1  L2

non-linear, for practical application, it is necessary to idealise the M-φ curves. The rotation Block shear-effective shear area capacity is a measure of the deformation that can be obtained before failure somewhere in the

Sabah Shawkat © connection causes a drop in the moment resistance.

but

 fu   a2  k d0t  f   y

L1  5 d

L2

but

 fu  L3  Lv  a1  a3  n  d0v    fy 

L3

Lv  a1  a3

is the effective shear area

t

is the thickness of the web or the plate

classified according to its rigidity as a nominally full-strength MRd ≥pinned, Mpl.Rd rigid or semi-rigid joint. According to its strength, it may be classified as a nominally pinned, full-strength or partial-strength joint. full-strength if rotation capacity is 1,2 they Mpl.Rdcannot develop significant moments notNominally checked pinned joints shall be so designed MRd ≥that where which might adversely affect members of the structure. The joint shall be capable of MRd thecalculated design moment of the connection transmitting isthe designresistance forces, and it shall be capable of accepting the resulting

Where AeffRd

For strength, the following classes can be distinguished: Welded connections nominally pinned MRd ≤ 0,25 Mpl.Rd Joints may be classified by0,25 either their rigidity of strength characteristics. A joint may be partial-strength Mpl.Rd <M Rd < Mpl.Rd

Mpl.Rd rotations.

d0t

is the design strength of the beam (full plastic moment).

is the hole size for the tension face (for horizontally slotted holes the slot length Column web in shear, compression and tension should be used) In practice it is often difficult to fabricate fixed connections and some rotation may take place

The design of semi-rigid joints for moment-resisting steel framed is based on the interaction

between the element onnumber one sideofoffastener the joint andon that the other. n is the holes theonshear face Such a joint is known as a

for nominally pinned joints of rigid joints are treated as semi-rigid joints.

semi-rigid connection and, strictly speaking is the condition of most joints which are described k = 0,5 for a single row of bolts as being fixed or rigid. A moment connection could be described as one which although only k =2,5 for rows ofofbolts. semi-rigid approaches the two behaviour a fixed connection and transfers a substantial bending

between members, i.e. on the moment-rotation characteristics. Joints not meeting the criteria

The design resistance of a full-strength joint shall not be less than that of the member connected. The rigidity of the full-strength joint shall be such that the rotation in any necessary plastic hinge does not exceed its rotation capacity at the ultimate limit state.

moment. Note that connections may be fabricated for particular requirements so that, for example, they may allow rotation in the plane of the elements but prevent twisting about the axis of the element thus allowing torsional moments to be transmitted. This is a common

A partial-strengthcharacteristic joint shall be of capable of resisting all internal and moments applied to Moment-rotation a semi-rigid joint with enoughforces plastic rotation capacity but its resistance may be less that of the member. Forit,stiffness, the classification is asthan follows:

Connectionsininsteel steelstructures structures Connections Connections Connectionsininsteel steelstructures structures


137

Connections made by welding on site should be avoided as far as possible, because welding is more awkward on site than in a workshop. Furthermore, the quality assurance of welding is

Nominal ultimate tensile strengths and correlation factors Steel grade

Nominal ultimate tensile strengths fu (MPa) for

more successful in a workshop. The resistance of a fillet weld per unit length shall be calculated from the following formula: fu

 FwRd

fvwd a

Correlation factor w

t<4mm

3

fvwd

 w 

EN 10025 S235

360

0,8

S275

430

0,85

510

0,9

S355

Mw

EN10113

Where fvwd

is the design shear strength of the weld

a

is the throat thickness of the weld

fu

is the nominal ultimate tensile strength of the weaker part joined

bw

is the appropriate correlation factor

Mw

is the partial safety factor

S275N

390

0,8

S355N

490

0,9

S420N

520

1,0

S355N

470

0,9

S420N

500

1,0

S460N

530

1,0

Sabah Shawkat © t<100mm

Welds with effective lengths shorter than 40mm or six times the throat thickness, whichever is

larger, should be ignored for transmission of forces. The throat thickness of a fillet weld should not be less than 3mm.

The design resistance of a fillet weld in a long lap connection shall be reduced by multiplying it by the following factor.:

for lap connections longer than 150a in the direction of the force transfer:  Lw

1.2 

0.2 Lj 150 a

 Lw

 1.0

And for fillet welds longer than 1.7 metres connecting transfer stiffeners in plated members:  Lw

1.1 

Lw 17

0.6   Lw  1.0

Where Lj

is the overall length of the lap connection in the direction of the force transfer

Lw

is the length of the weld (in metres) Weld length (mm) vs Force in (Tone)- resistance of a weld seam

Connections in steel structures Connections in steel structures


138 132

Connections structures Resistanceinofsteel the weld FwRd (kN) for weld length 100 mm

condition Splices at steel beam supports. By contrast the element may be fixed in its plane to transmit

Throat thickness of the 3 4 5 6 7 8 9 10 Joints between structural line elements, in one plane, may be classified as simple connections, weld (mm) as sliding connections, as pin or pinned connections as fixed connections, also known as rigid S235 62,4 83,1 103,9 124,7 145,5 166,3 187,1 207,8 connections. A simple connection allows rotation and movement in any direction except S275 70,1 93,5 116,8 140,2 163,6 186,9 210,3 233,7 downwards and only transmits shear force that acts downwards at a support. A sliding S335 78,5 104,7 130,9 157,0 183,2 209,4 235,5 261,7 connection allows movement along the line of the element and rotation and only transmits shear S275N 67,5 90,1 112,6 135,1 157,6 180,1 202,6 225,2 force. A pinned connection allows rotation but no translational movement, it transmits shear S355N 75,4 100,6 125,7 150,9 176,0 201,2 226,3 251,5 and axial forces but not bending moment. A fixed connection does not allow translational S420N 72,1 96,1 120,1 144,1 168,1 192,1 216,2 240,2 movement or rotation and transmits shear, axial forces, bending and torsional moment. S355M 72,4 96,5 120,6 144,7 168,8 193,0 217,1 241,2

a

S420M

69,3

92,4

115,5

138,6

161,7

184,8

207,8

230,9

S460M

73,4

97,9

122,4

146,9

171,4

195,8

220,3

244,8

therotate places of the possiblefornominally already at the thedegree structural modelling stage. It may about a support example.pinned A way splices of characterising of fixity or stiffness is worth locating a moment-resistant splice in design at the least loaded place if assembly of the provided by a semi-rigid connection either to a support or another member is to measure the spliceatisthe notjoint unduly awkward and if the lengths short enough. If the bending moment is rotation as the bending moment on the remain joint is varied. accompanied by shear and axial forceand at the place, the latter forces have to be taken Figure bellow defines theforce strength, stiffness deformation capacity of aalso beam-to-column into account. connection designed to transfer a moment from the beam into the column. M-φ curves in general the M-φ The rotation non-linear, forofpractical is necessary to idealise The design a splice application, in a member itsubject to compressive forces has tocurves. take the second-order capacity is ainto measure of the deformation can beisobtained before failure in thethe moments account if the strength ofthat the splice not at least equal to thatsomewhere of the member,

Sabah Shawkat ©

connection a drop in the moment additionalcauses moments have their origin resistance. in the eccentricity of the compressive force and in the Forinitial strength, the following classes can be distinguished: curvature of the profile. The additional second-order moment can be calculated as

e1 e2 2

2

e1  e2

tg

bending but allow rotation about its axis. Note that if pinned or fixed joints are made between Beam splices are necessary, for example, in long rafters because it is often more economical to an element and an immovable support then that end of the element may not move translationally transport a beam in short parts and make splices with bolted connections than to transport it as or rotate in space, as distinct from a movement which is merely relative to the member on the an oversized load. Although a bolted connection is normally preferable to a welded connection other side of the joint. Fixed joints, or nearly fixed joints, between two members are said to of bridge girders and crane runway girders. provide continuity so that there is little or no rotation between the members at the joint and the It is possible make either asHowever, pinned orthe as moment resistant. The designer to decide members behavetoas if nosplices joint existed. joint is not necessarily fixed in has space and

0 5 

1 2

 e2



e2 e1

e1

 

2

V

0.75 2 a  h w

MRd ≤ 0,25 Mpl.Rd

not checked

MRd ≥ 1,2 Mpl.Rd

0,25 Mpl.Rd < MRd < Mpl.Rd  Weff   M 1 x  ≥ Mpl.Rd   full-strength M sd Nsd   1    sin   Rd  Aeff l      is  full-strength if rotation capacity

e1  e2

nominally follows:pinned partial-strength

where Where

 e

MRd  Mpl.Rd

V-is shear force hw is the web depth

is the design moment resistance of the connection is the reduction factor in plane buckling is the design strength of the beam (full plastic moment).

Aeff

is the effective area of the cross-section

Weff

is the effective section modulus of the cross-section

x

is the distance between the nearest inflection point in the buckled state and splice

Column web in shear, compression and tension In practice it is often difficult to fabricate fixed connections and some rotation may take place between the element on one side of the joint and that on the other. Such a joint is known as a

or end fastening

semi-rigid connection and, strictly speaking is the condition of most joints which are described as being fixed or rigid. A moment connection could be described as one which although only

l

is the buckling length of the member.

semi-rigid approaches the behaviour of a fixed connection and transfers a substantial bending moment. Note that connections may be fabricated for particular requirements so that, for example, they may allow rotation in the plane of the elements but prevent twisting about the Usefultorsional thicknessmoments of asymmetrical cords axis of the element thus allowing to be transmitted. This is a common

Moment-rotation characteristic of a semi-rigid joint with enough plastic rotation capacity For stiffness, the classification is as follows:

Connectionsininsteel steelstructures structures Connections Connections Connectionsininsteel steelstructures structures


139

Riveted and bolted assemblies working in shear

Bolts working at double shear

Thin-element assemblies, in the case of mild steel, the graphs below give the admissible value

Unsheared threaded part

of shearing force for each bolts according to its diameter ϕ and the thickness e of the assembled part, in the zone of these graphs located at left of interrupted line, it is necessary to check the longitudinal clamp condition. The longitudinal clamp condition we determine as follow: V l  0.8 e 

e

Bolts working with simple shear Unsheared threaded portion

Sheared threaded part

Sabah Shawkat ©

In the zone of the graph located at left of solid line, it is necessary to check the longitudinal clamp condition. Bolts assembling with double shear thicknesses less than 13mm without shearing of the threaded part or 8mm with shearing of the threaded part.

Connections in steel structures Connections in steel structures


140 132

Connections in steel structures

Bolts working at double shear

condition at steel beam supports. By contrast the element may be fixed in its plane to transmit Rivets

Sheared threaded part Joints between structural line elements, in one plane, may be classified as simple connections,

bending but allow rotation about its axis. Note that if pinned or fixed joints are made between Simple shear an element and an immovable support then that end of the element may not move translationally

as sliding connections, as pin or pinned connections as fixed connections, also known as rigid

or rotate in space, as distinct from a movement which is merely relative to the member on the

connections. A simple connection allows rotation and movement in any direction except

other side of the joint. Fixed joints, or nearly fixed joints, between two members are said to

downwards and only transmits shear force that acts downwards at a support. A sliding

provide continuity so that there is little or no rotation between the members at the joint and the

connection allows movement along the line of the element and rotation and only transmits shear

members behave as if no joint existed. However, the joint is not necessarily fixed in space and

force. A pinned connection allows rotation but no translational movement, it transmits shear

may rotate about a support for example. A way of characterising the degree of fixity or stiffness

and axial forces but not bending moment. A fixed connection does not allow translational

provided by a semi-rigid connection either to a support or another member is to measure the

movement or rotation and transmits shear, axial forces, bending and torsional moment.

rotation at the joint as the bending moment on the joint is varied. Figure bellow defines the strength, stiffness and deformation capacity of a beam-to-column connection designed to transfer a moment from the beam into the column. M-φ curves in general non-linear, for practical application, it is necessary to idealise the M-φ curves. The rotation capacity is a measure of the deformation that can be obtained before failure somewhere in the

Sabah Shawkat © connection causes a drop in the moment resistance.

For strength, the following classes can be distinguished:

MRd ≤ 0,25 Mpl.Rd

nominally pinned partial-strength

0,25 Mpl.Rd < MRd < Mpl.Rd

MRd ≥ Mpl.Rd

full-strength

full-strength if rotation capacity is

MRd ≥ 1,2 Mpl.Rd

not checked where MRd

is the design moment resistance of the connection

Mpl.Rd

is the design strength of the beam (full plastic moment).

Column web in shear, compression and tension

In practice it is often difficult to fabricate fixed connections and some rotation may take place

In the the zone of the on graph of and solidthat line, is other. necessary longitudinal between element onelocated side of at theleft joint onitthe Suchtoacheck joint isthe known as a

Rivets simple shear it is necessary to check and not check the longitudinal clamp condition

clamp condition. semi-rigid connection and, strictly speaking is the condition of most joints which are described

In the zone of the graph located at left of solid line, it is necessary to check the longitudinal

as being fixed or rigid. A moment connection could be described as one which although only

clamp condition. Rivets assembling at simple shear thicknesses less than 4mm and at double

semi-rigid approaches the behaviour of a fixed connection and transfers a substantial bending

shear splicer less than 14mm

moment. Note that connections may be fabricated for particular requirements so that, for example, they may allow rotation in the plane of the elements but prevent twisting about the axis of the element thus allowing torsional moments to be transmitted. This is a common

Moment-rotation characteristic of a semi-rigid joint with enough plastic rotation capacity For stiffness, the classification is as follows:

Connections Connectionsininsteel steelstructures structures Connections Connectionsininsteel steelstructures structures


141

Rivets

Slip resistance In slip resistance connections, the preloaded bolts clamp the contact surfaces together and the

Double shear

contact surfaces cannot slip with respect to each other. The resistance of the connection depends on the preloading force in the bolt as well as the slip factor of the contact surfaces in addition to the material properties of the connected parts. The design value of the slip resistance is obtained from the following formula:

FsRd

ks n  

FpCd 

Ms

Where =1,0

ks

is standard hole clearances are used

n

is the number of slip planes

is the slip factor

Sabah Shawkat © FpCd

= 0,7 fub As

is the preloading force

Ms,ult and gMs,ser are partial safety factors.

The contact surfaces are classified according to their slip factors into four classes. The

slip factors corresponding to the classes and slip resistance are obtained from table below. Contact surfaces in slip-resistant connections Class

Slip factor

A

0,50

Treatment of contact surfaces Surfaces blasted with shot or grit, with any loose rust removed, no pitting Surfaces blasted with shot or grit, and spray-metallized with aluminium Surfaces blasted with shot or grit, and spray-metallized with zincbased coating certified to provide a slip factor not less than 0.5

B

0,4

Rivets double shear it is necessary to check and not check the longitudinal clamp condition In the zone of the graph located at left of solid line, it is necessary to check the longitudinal

Surfaces blasted with shot or grit, and painted with an alkali-zinc silicate paint to produce a coating thickness of 50-80 m

C

0,3

clamp condition.

Surfaces blasted with wire brushing or flame cleaning, with any loose rust removed

D

0,2

Surfaces not treated

Connections in steel structures Connections in steel structures


142 132

Connections in steel Slip resistance FsRdstructures (kN) in Class D per slip plane

condition at steel beam supports. By contrast the element may be fixed in its plane to transmit

Bolt M12 M16 M20 M24 M30 Joints between structural line elements, in one plane, may be classified as simple connections, Slip resistance at the serviceability limit state as sliding connections, as pin or pinned connections as fixed connections, also known as rigid Grade 8,8 8,6 16 24,9 25,9 57,1 connections. A simple connection allows rotation and movement in any direction except 10,9 10,7 20 31,2 44,9 71,4 downwards and only transmits shear force that acts downwards at a support. A sliding Slip resistance at the ultimate limit state connection allows movement along the line of the element and rotation and only transmits shear Grade 8,8 7,6 14,1 22 31,6 50,3 force. A pinned connection allows rotation but no translational movement, it transmits shear 10,9 9,4 17,6 27,4 39,5 62,8 and axial forces but not bending moment. A fixed connection does not allow translational If a slip-resistance connection is subject to an applied tensile force in addition to the shear force, movement or rotation and transmits shear, axial forces, bending and torsional moment. the slip resistance shall be calculated as follows: in Category B

F sRdser

k s n  

 F pCd

 0.8  F tSdser 

Msser

bending but allow rotation about its axis. Note that if pinned or fixed joints are made between an element and an immovable support then that end of the element may not move translationally or rotate in space, as distinct from a movement which is merely relative to the member on the other side of the joint. Fixed joints, or nearly fixed joints, between two members are said to provide continuity so that there is little or no rotation between the members at the joint and the members behave as if no joint existed. However, the joint is not necessarily fixed in space and may rotate about a support for example. A way of characterising the degree of fixity or stiffness provided by a semi-rigid connection either to a support or another member is to measure the rotation at the joint as the bending moment on the joint is varied. Figure bellow defines the strength, stiffness and deformation capacity of a beam-to-column connection designed to transfer a moment from the beam into the column. M-φ curves in general non-linear, for practical application, it is necessary to idealise the M-φ curves. The rotation capacity is a measure of the deformation that can be obtained before failure somewhere in the

Sabah Shawkat ©

in Category C

FsRd

ks  n   

 FpCd  0.8 FtSd 

Msult

connection causes a drop in the moment resistance.

For strength, the following classes can be distinguished:

MRd ≤ 0,25 Mpl.Rd

The stiffness of the splice in a compression member has to be at least equal to that of the

nominally pinned

member with respect to both principal axes even if the member is axially loaded only and

partial-strength

abutting ends are provided at the splice. Furthermore, the parts of the splice must be able to

full-strength

carry 2,5% of the compressive force in any direction perpendicular to the axis of the member.

full-strength if rotation capacity is

0,25 Mpl.Rd < MRd < Mpl.Rd

MRd ≥ Mpl.Rd

MRd ≥ 1,2 Mpl.Rd

not checked where MRd

is the design moment resistance of the connection

Mpl.Rd

is the design strength of the beam (full plastic moment).

Column web in shear, compression and tension In practice it is often difficult to fabricate fixed connections and some rotation may take place between the element on one side of the joint and that on the other. Such a joint is known as a semi-rigid connection and, strictly speaking is the condition of most joints which are described as being fixed or rigid. A moment connection could be described as one which although only Some types of splices - continuity semi-rigid approaches the behaviour of a fixed connection and transfers a substantial bending It is worth the splice of a column as nearfor to aparticular support asrequirements possible, where the lateral moment. Notelocating that connections may be fabricated so that, for

deflection small. Thenrotation the inner andof of the second-order moments as small effect example, theyismay allow in forces the plane elements but preventhave twisting about the on the resistance of the joint as possible. axis of the element thus allowing torsional moments to be transmitted. This is a common

Moment-rotation characteristic a semi-rigid jointhollow with enough rotation capacity from square sectionplastic profiles Plane truss of beam, For stiffness, the classification is as follows:

Connections Connectionsininsteel steelstructures structures Connections Connectionsininsteel steelstructures structures


143

Calculate the tension resistance of the adjacent joint. The dimensions of the hollow section are

 Mb

is the partial safety factor of the bolt joints

200x200x8, and the steel designing used is S355J2H. The steel grade used in splices is S355J2. The strength grade of the M30 bolts is 8.8. The parameters of the joint geometry are:

Resistance of the splice plate net cross-section The splice plates can be taken as tension cross-section. Thus, the resistance of a cross-section containing holes can be obtained from:

Data t1  22mm

 t2  12 mm

dM30  30 mm

d0  0.0324 m

hp  240 mm

a1  50 mm

p1  Lv

p2  Lv

a2  Lv

 e2  50 mm

 M2

 1.25

n1  2

n  6

 M0

 1.1

 d0  1.08 dM30  Lv  140 mm  e1  50 mm  Mb

The tension resistance of the cross-section is the smallest of the following: Anet  t1  hp  n1 d0

 Anet 3854.4 mm

A  v  t1 hp

 Av 5280 mm

2

 1.25

k  2.5

 fub  800 MPa  fu  490 MPa fy  355 MPa The resistance of the joint is determined separately for the bolts and splices. The bolts transfer

2

F tRd  Av 

fy

FtRd  1704 kN

 M0

 FtRdnet  0.9 Anet 

fu  M2

FtRdnet  1359.83 kN

Sabah Shawkat ©

the force affecting on the joint by their shear resistance. The bolts shear resistance per shear plane is determined from the following formula, assuming the shear plane does not pass through

Anet

is the net area (the area of the holes subtracted from the gross area)

fu

is the ultimate strength of the material

NtRd

is the design value of tension resistance

the threaded portion of the bolts.

Bearing resistance of splice plates

The tension resistance of the splice plates is calculated by taking into account both the net crosssection and the bearing resistance. The resistance of the net cross-section can be calculated by the same principle as that of a hollow section in tension. The bearing resistance of a splice plate depends on the positioning of the holes and the strength of the bolts. This relationship is

FvRd

0.6 fub A

illustrated by the parameter α, obtained as the minimum value from the following equation: 

 Mb

fub

is the ultimate strength of the bolt

A

is the cross-section of the bolt

fub fu

p1 1 fub      3d 3d 4 fu  0 0 

 e1

min

 1.63265

Connections in steel structures Connections in steel structures

e1 3d0

 0.5144

p1 3d0

1 4

 1.19033


144 132

Connections e1in steel structures     0.5144 3 d 0

condition at steel beam supports. By contrast the element may be fixed in its plane to transmit Shear resistance of bolts

Joints structural elements, in one may betoclassified is the distanceline of the bolt from the plane, edge parallel force as simple connections, e1 between as sliding connections, as pin or pinned connections as fixed connections, also known as rigid is the diameter of the bolt hole d0 connections. A simple connection allows rotation and movement in any direction except is the distance between bolts parallel to force p1 downwards and only transmits shear force that acts downwards at a support. A sliding is the ultimate strength fub connection allows movement along of thethe linebolt of the element and rotation and only transmits shear force. allowsofrotation but no translational movement, it transmits shear is theconnection ultimate strength the splice fu A pinned andWhen axial the forces butarenotsituated bending A fixedthe connection does not allow translational holes as moment. in the example, bearing resistance of splice plates is as follows: or rotation and transmits shear, axial forces, bending and torsional moment. movement FbRd 

2.5  fu dM30t1  Mb

FbRd  332.71605 kN

dM30

is the diameter of the bolt

t1

is the thickness of the splice

bending but allow rotation about its axis. Note that if pinned or fixed joints are made between The shear resistance of bolts is determined by assuming that the shear plane does not pass an element and an immovable support then that end of the element may not move translationally through the threaded portion of the bolts: or rotate in space, as distinct from a movement which is merely relative to the member on the 2 other side of the two members are said to  djoint. M30 Fixed joints, or nearly fixed joints, between 2 AM30   AM30 706.86 mm provide continuity4 so that there is little or no rotation between the members at the joint and the

members behave as if no joint existed. However, the joint is not necessarily fixed in space and 0.6 fub AM30  271.43361 kN the degree of fixity or stiffness mayFrotate characterising vRd of vRd about a support for example. AFway  Mb

provided by 6a bolts semi-rigid connection either to aplanes, supportsoortheanother member is: is to measure the shear bolt resistance There are and the joint has two rotation at the joint as the bending moment on the joint is varied.  12 FvRd FvRdtot  3257.20326 kN FvRdtot Figure bellow defines the strength, stiffness and deformation capacity of a beam-to-column connection designed to transfer a moment from the beam into the column. M-φ curves in general Resistant the welds non-linear, for practical application, it is necessary to idealise the M-φ curves. The rotation Designisthe fillet welds with a throat thickness of obtained 10 mm, the axial forcesomewhere introduced in into capacity a measure of the deformation that can be before failure thethe

weld is assumed equalintothethe hollowresistance. section plastic tension resistance. The plastic tension connection causes a drop moment resistance of a hollow section with dimensions 200x200x8 is: For strength, the following classes can be distinguished:

Sabah Shawkat ©

 Mb

is the partial safety factor of the bolt joints

Now there are 6 bolts per plate, so the bearing resistance is: FbRdtot  n FbRd

FbRdtot  1996.2963 kN

nominally pinned MRd ≤ 0,25 Mpl.Rd 2 2 A200.200.8  52.84 10 mm  w  0.9 a  10 mm partial-strength 0,25 Mpl.Rd < MRd < Mpl.Rd

fy full-strength NplRd  A200.200.8  M0 full-strength if rotation capacity is

Block shear failure resistance of splice plates

First, calculate the effective shear area from the formula:

 fu  Lveff  2  Lv  a1   a2  k d0    fy   fu  2  Lv  5 d0   a2  k d0    685.43662 mm  fy 

not checked where Lw  MRd

 Mw

 1.25

MRd ≥ Mpl.Rd NplRd  1705.29 kN

3  w  Mw NplRd

MRd ≥ 1,2 Mpl.Rd

Lw  169.53 mm 4 fu a is the design moment resistance of the connection

Mpl.Rd is the design strength of the beam (full plastic moment). Resistance of joints

 fu  Column web in shear, compression and tension Lveff  2  Lv  5 d    a2  k d0    Lveff 461.44 mm In practice it is often difficult to fabricate fixed connections and some rotation  fymay  take place 2 between the that on the other. Such a joint is known as a Aveff   element t1 Lveff on one side of the joint Aveff and  10151.61 mm

semi-rigid connection and, strictly speaking is the condition of most joints which are described

resistance for block shear failure of the splice in be checked. as Additionally, being fixed orthe rigid. A moment connection could be described asthe onemiddle which must although only The design value forthe block shear failure is determined from formula: semi-rigid approaches behaviour of a fixed connection andthe transfers a substantial bending moment. Note that connections may be fabricated for particular requirements so that, for fy Aveff VeffRdthey  may allow rotation in theVplane  1891.51 kN but prevent twisting about the example, the elements effRd of 3  M0 axis of the element thus allowing torsional moments to be transmitted. This is a common

The entire resistance of the joint is then determined by the resistance of the net cross-section: FtRdnet  1359.83232 kN

where fu

is the ultimate strength of the hollow section

fy

is the yield strength of the hollow section

Moment-rotation characteristic of a semi-rigid joint with enough plastic rotation capacity For stiffness, the classification is as follows:

Connections Connectionsininsteel steelstructures structures Connections Connectionsininsteel steelstructures structures


145

Calculate the resistance of the adjacent shear joint. The dimensions of the hollow sections are 250x250x8, and the steel grade used S355J2H. At the end of the hollow section, the joint is subjected to a force Fsd. The thickness of the splice plate is 20mm, and the strength grade of the

Bearing resistance of the splice plates The bearing resistance of the splices is calculated as:

M22 bolts is 8.8. Data

Fsd  250 kN 

Nsd  450 kN

 fyk  355 MPa

fu  490 MPa

 M1

The axial force of the column is Nsd

 1.1

 Mj

 1.1

 M0

dM22  22 mm  d0  26 mm

Lv  160 mm   a1  50 mm  Msd  Fsd a2

p1  Lv

 1.1

 Mw

 1.25

k  0.5

a3  50 mm

fu  Mb

p1 1 fub      3d 3d  0 0 4 fu 

 1.63265

 1.25

FbRd 

tp  20 mm

 a2  50 mm

fub

fub  800 MPa

 e1

e1

min



3d0

e1 3  d0

2.5  fu dM22tp

 0.64103

p1 3d0

1  1.80128 4

 0.64103

FbRd  276.41026 kN

 Mb

Now there are 2 bolts per plate, so the bearing resistance is: e1  50 mm

FbRdtot  n FbRd

n  2

FbRdtot  552.82051 kN

FbRdtot  Fsd

Sabah Shawkat © Msd  12.5 m kN

Block shear failure resistance of splice plates

First, calculate the effective shear area from the formula:

 fu    fyk 

Lveff   Lv  a1   a2  k d0 

2

 Aveff 5221.41 mm

 tp Lveff Aveff f

 Lv  a1  a3  n d0  f u

yk

a1  5 dm22

Lveff  261 mm

 0.2871 m

Lveff   Lv  a1  a3  n d0 

5 dM22  110 mm

a1  50 mm

Obtain the block shear failure resistance by substituting in formula: Joint of steel hollow section

VeffRd 

fyk Aveff 3  M0

VeffRd  Fsd

VeffRd  972.89 kN Fsd  250 kN

Connections in steel structures Connections in steel structures

fu fyk


146 132

Connections in steelofstructures Shear resistance bolts

condition at steel beam supports. By contrast the element may be fixed in its plane to transmit Resistance of welds

The shear resistance of bolts is determined by assuming that the shear plane passes through the Joints between structural line elements, in one plane, may be classified as simple connections, threaded portion of the bolt: as sliding connections, as pin or pinned connections as fixed connections, also known as rigid

bending but allow rotation about its axis. Note that if pinned or fixed joints are made between The weld between the column and the splice must transfer the force Fsd vertically and the tensile an element and an immovable support then that end of the element may not move translationally force due to moment Msd horizontally. Therefore, determine the stress components of the weld: or rotate in space, as distinct from a movement which is merely relative to the member on the   4 of  L  260 mmor nearly fixed joints, between two members are said to a side mm other the joint. Fixed joints,

2 connections. A  dsimple M22 connection allows rotation and 2movement in any direction except AM22   AM22 380.13 mm downwards and 4only transmits shear force that acts downwards at a support. A sliding

connection allows movement along the line of the element and rotation and only transmits shear 0.6 fub AM22 FvRd but 145.97096 kN FvRd  force. A pinned connection allows rotation no translational movement, it transmits shear  Mb

and axial forces but not bending moment. A fixed connection does not allow translational movement or rotation and transmits shear, axial forces, bending and torsional moment. There are 2 bolts and the joint has two shear planes, so the bolt resistance is:

 2 FvRd FvRdtot

FvRdtot  291.94192 kN

FvRdtot  Fsd

Fsd  250 kN

provide continuity so that there is little or no rotation between the members at the joint and the Fsd  II   240.38462 MPa the joint is not necessarily fixed in space and members behave as if no II joint existed. However, a L The weldabout strength is checked with formulae in characterising Ec3 may rotate a support for example. A way of the degree of fixity or stiffness provided by a semi-rigid connection either to a support or another member is to measure the fu fu  par at the joint as the bending  392 MPa rotation moment on the joint is varied.  Mw

 Mw

Figure theofstrength, stiffness and capacity of a(fillet beam-to-column Try abellow throat defines thickness 4 mm, which gives thedeformation following weld stresses welds on both connection designed faces of the plate):to transfer a moment from the beam into the column. M-φ curves in general non-linear, for practical application, it is necessary to idealise the M-φ curves. The rotation Fsd capacity that can be obtained before failure somewhere in the  II is a measure of the deformation  II  120.19231 MPa 2 a L connection causes a drop in the moment resistance. The same throat thickness can be used in the weld between the hollow section and plate and the For strength, the following classes can be distinguished: splice. nominally pinned MRd ≤ 0,25 Mpl.Rd Resistance of the joint partial-strength 0,25 Mpl.Rd < MRd < Mpl.Rd

Sabah Shawkat ©

Resistance of the column wall

The resistance of the column wall is calculated as: 250x250x8

 hc  250 mm 2

2

Ac250.250.8  75.24 10 mm

n 

 M0  Mj

1.1

bc  250 mm 3

 tc  8 mm

3

Wel  578.3 10 mm

Nsd Msd      A  f W c250.250.8 yk el fyk  

n  0.2523

full-strength Mpl.Rd Rd ≥ Compare the calculated resistance values toMthe force quantities: full-strength if rotation capacity is FvRdtot  291.94192 kN not checked

Fsd  250 kN MRd ≥ 1,2 Mpl.Rd

where M1Rd  14.47376 m kN

Msd  12.5 m kN

ok

MRd

is the design moment resistance of the connection

Mpl.Rd

is the design strength of the beam (full plastic moment).

compression and tension  km  1.3 ( 1  n ) Column web km in  shear, 0.97201 In practice it is often difficult to fabricate fixed connections and some rotation may take place between the element on one side of the joint and that on the other. Such a joint is known as a 2 fyk tc hc  2 hc tp  1 of most joints which are described semi-rigid connection M1Rd  0.5 km  and, strictly  speaking  4  is1 the  condition  M1Rd  14.47376 m kN tp  bc bc   Mj  M0 as being fixed or rigid.1A moment connection could be described as one which although only bc semi-rigid approaches the behaviour of a fixed connection and transfers a substantial bending moment. that connections may M1Rd Note  Msd Msdbefabricated 12.5 m kNfor particular OK requirements so that, for example, they may allow rotation in the plane of the elements but prevent twisting about the axis of the element thus allowing torsional moments to be transmitted. This is a common

Moment-rotation characteristic of a semi-rigid joint with enough plastic rotation capacity Incorrect production and installation of a steel column that was carried out on site For stiffness, the classification is as follows:

Connections Connectionsininsteel steelstructures structures Connections Connectionsininsteel steelstructures structures


147

Calculate the bending resistance of the flange plate joint. The column dimensions are 250x250x10 and those of the hollow section are 350x250x10. The steel grade used is S355J2H.

Usually the joint also includes shear force, which must be taken into account in the joint design.

The flange thickness is 22mm. The steel grade used in the flanges is S355J2. The strength grade

Resistance of hollow sections subjected to shear force

of the M24 bolts is 8.8. fu  490 MPa   M1

 1.1

 m  50 mm w

 0.9

The design criterion for hollow section subject to shear force is:

 fyk  355 MPa  Mj

 1.1

 M0

 e  50 mm

 1.1

tp  22 mm

 Mw

Vsd  VRd

 1.25

p  300 mm

Vsd

is the design value for the shear force

VRd

is the design value for the shear resistance

 hr  350 mm

 Lw  300 mm d24  24 mm The method for calculating the shear resistance depends on slenderness of the web of the

The bending and shear resistance values of the joint components are:

hb  400 mm   bb  200 mm

tb  10 mm

Beam

cross-section as follows: 400x200x10

h t

 69 

235 MPa fyk

3

calculate the plastic shear resistance

Sabah Shawkat © 2

2

Ab400.200.10  112.6 10 mm

Vb.plzRd  1398 kN

Vb.plyRd  699.1 kN

Mb.cyRd  462.7kN m

Mb.czRd  236.2 kN m

h t

 69 

69 

235 MPa fyk

235 MPa fyk

3

calculate the resistance to shear buckling

hb

 3  59.13954

tc

 40

Shear buckling need not be considered for square and rectangular hollow sections for which h/t < 59,1 and the yield strength of the material fy < 355 MPa. In practice, shear buckling governs only for a very few hollow section.

Shear resistance of the column web plastic shear resistance of the column web is:

Column

hc  200 mm

200x200x10 2

bc  200 mm  tc  10 mm

fyk Av 3  M0

Av

A

h bh

2

Ac200.200.10  72.57 10 mm McRd  164.0 kN m

Vpl.Rd

Vc.plRd  676.1 kN

 NcRd  2342 kN

h

in this case is the dimension parallel to shear force

Connections in steel structures Connections in steel structures


148 132

2 Connections in steel structures column Ac200.200.10  7257 mm hc  0.2 m bc  0.2 m hc 2  Avc 3628.5 mm A  Ac200.200.10 Jointsvc between structuralbcline in one plane, may be classified as simple connections,  helements, c

condition at steel beam supports. By contrast the element may be fixed in its plane to transmit By multiplying the shear resistance by the height of the hollow section, the moment resistance bending but allow rotation about its axis. Note that if pinned or fixed joints are made between for the column web is obtained: an element and an immovable support then that end of the element may not move translationally

as sliding connections, fyk Avc as pin or pinned connections as fixed connections, also known as rigid VplRd  VplRd  676.08635 kN connections. A 3simple  M0 connection allows rotation and movement in any direction except

or rotate to themmember on the MRd in  space, VplRd as  hdistinct MRd relative  263.67368 kN b  tb  from a movement which is merely other side of the joint. Fixed joints, or nearly fixed joints, between two members are said to

downwards and only transmits shear force that acts downwards at a support. A sliding

provide continuity so that there is little or no rotation between the members at the joint and the Resistance of flanges and bolts members behave as if no joint existed. However, the joint is not necessarily fixed in space and The resistance of flanges and bolts can be estimated by calculating the resistance of the joint may rotate about a support for example. A way of characterising the degree of fixity or stiffness between the flange and hollow section using equivalent T models. Equivalent T models consist provided by a semi-rigid connection either to a support or another member is to measure the of a column and flange, and hollow section and flange. There are three potential failure modes rotation at the joint as the bending moment on the joint is varied. for a T model. According to these modes, the tension resistance values of the bolt row are as Figure bellow defines the strength, stiffness and deformation capacity of a beam-to-column follows. connection designed to transfer a moment from the beam into the column. M-φ curves in general

connection allows movement along the line of the element and rotation and only transmits shear force. A pinned connection allows rotation but no translational movement, it transmits shear and axial forces but not bending moment. A fixed connection does not allow translational movement or rotation and transmits shear, axial forces, bending and torsional moment.

Shear buckling resistance of square and rectangular hollow sections

the M-φ curves. The rotation non-linear, for practical application, it the is necessary to idealise 1. flange yield at the location of bolt row and at the hollow section webs

The shear buckling resistance of hollow sections is calculated using the following formula:

capacity is a measure of the deformation that can be obtained before failure somewhere in the 4 MplRd connection FrRdcauses a drop in the moment resistance. m For strength, following be at distinguished: 2. boltthe failure as theclasses flangescan yield the hollow section webs nominally pinned MRd ≤ 0,25 Mpl.Rd

Sabah Shawkat ©

VbaRd

2  hc  3tc tc 

 ba

 M1

The web shear buckling stress τba depends on the slenderness of the web λw as follows: hc 3  tc

w

 ba



tc

w

235 MPa 86.4  fyk

 1  0.625   w  0.8 

 0.24183

fyk

 0.8   w  1.2

for

3  ba

as being fixed or rigid. A moment connection could be described as one which although only Bending resistance of the column web semi-rigid approaches the behaviour of a fixed connection and transfers a substantial bending The resistance of the column web determined from: moment. Note that connections mayis be fabricated for particular requirements so that, for example, they may allow rotation in the 1.1 plane of the elements but prevent twisting about the 2 M  326.76136 m kN Mip1Rd  0.5 fyk tc  hb  5 tc  axis of the element thus allowing torsional moments to beip1Rd transmitted. This is a common  Mj  M0

2

full-strength if rotation capacity is not checked 3. bolt or flange failure

VbaRd  854.51372 kN  276.46032 MPa VbaRd  2  hc  3tc tc   M1tension Column web in shear, compression and The resistance to shear buckling is calculated according to the instructions in reference: In practice it is often difficult to fabricate fixed connections and some rotation may take place  on one side of the joint and that on the other. Such a joint is known as a between If the element  w  1.2 semi-rigid connection and, strictly speaking is the condition of most joints which are described  ba

0.25 Leff fyk tp partial-strength 0,25 Mpl.Rd < MRd < Mpl.Rd 2 MplRd  e 2 BtRd MplRd FtRd  M0 me full-strength MRd ≥ Mpl.Rd

where FtRd MRd

Mpl.Rd where

MRd ≥ 1,2 Mpl.Rd

2 BtRd is the design moment resistance of the connection is the design strength of the beam (full plastic moment).

FtRd

is the tension resistance of the bolt row

Leff

is the effective length of the bolt row

tp

is the thickness of the flange

m

is the bolts distance from the outer edge of the hollow section

e is the bolts distance from the edge of the flange, e < 1,25m Moment-rotation characteristic of a semi-rigid joint with enough plastic rotation capacity is the tension resistance of the bolt or the punching resistance of the flange BtRd For stiffness, the classification is as follows:

Connections Connectionsininsteel steelstructures structures Connections Connectionsininsteel steelstructures structures


149

we see that the failure mode to be used in the design is therefore bolt failure with flange yielding FtRd. It is normally recommended to design the flange joint so that the flanges yield before the bolts fail. The failure mode is then ductile. For flanges and bolts, the joint bending resistance is: MRd  FtRd hr 

MRd  204.8238 m kN

Design of welds The effective length of the bolt row depends on the shape of the flanges yield line pattern. From

The welds must transfer the tensile force due to bending moment into the hollow sections upper

the following equations, select the one giving the smallest result:

flange

 Leff1  2  m

Leff1  314.15927 mm

Leff2  4 m  1.25 e  Leff2 262.5 mm

Nsd 

MRd

Nsd  512.0595 kN

hb

since the letter formula gave the smallest value, it is used as the effective length of the bolt row The fillet weld is provided across the width of the entire column 200mm, which gives a required

Leff2  0.2625 m

Sabah Shawkat © throat thickness of:

Then substitute the effective length of the bolt row in the failure mode equations for the T stub:

MplRd 

0.25 Leff2fyk tp

a 

2

3  w  Mw Nsd  6.7876 mm fu Lw

fu Lw

MplRd  10.251 m kN

 M0

Flange yield at the location of the bolt row and at the hollow section web FrRd 

3  w  Mw Nsd

The bending resistance of the joint is obtained by multiplying the tension resistance values of

the horizontal bolt rows by the distance of the bolt rows from the centre of compression. Only

4 MplRd

FrRd  820.05 kN

m

the bolt rows in the tension zone are considered. The tension zone of the joint is located above the neutral axis of the hollow section. The following value for bending resistance is therefore

bolt failure as the flanges yield at the hollow section webs: BtRd  0.6  0.75 d24tp 

fu  M2

BtRd  292.605 kN

obtained: MRd

  R  h  tRd

i

r

i

i

where

FtRd 

2 MplRd  e 2 BtRd me

FtRd  497.61793 kN

bolt or flange failure FtRd  2 BtRd

FtRd

is the design value for the bolt rows tension resistance

hr

is the distance of the bolt row distance from the compression centre

MRd  204.8238 m kN

FtRd  585.21085 kN

Connections in steel structures Connections in steel structures


150 132

Connections in steel structures Calculate the bending resistance of the splice with end-plates shown in the adjacent picture. It

condition at widths steel beam supports. yield-line By contrast the element may be fixed in its plane to transmit Effective (non-circular patterns):

is assumed that the requirement of rotation capacity as a provision for a plastic global analysis

bending but allow rotation about its axis. Note that if pinned or fixed joints are made between  Leffnc  4 mx  1.25 ex Leffnc  278.79613 mm an element and an immovable support then that end of the element may not move translationally Leffncinspace, e  2as mxdistinct  0.625from ex a movement Leffncwhich  204.39807 mm or rotate is merely relative to the member on the

Joints between structural line elements, in one plane,the may be classified simple connections, is not set. The beam profile is WI600-8-20x300. thickness of theasend-plate is 25mm. The as steel sliding connections, as pin or bolts pinned grade is S355J2G3. The areconnections 6xM24 8.8.as fixed connections, also known as rigid connections. A simple connection allows rotation and movement in any direction except

connection allows movement along the line of the element and rotation and only transmits shear

otherL side  of 0.5 the w joint. joints,eor nearly joints, between  2 Fixed mx  0.625 Leffncfixed  199.39807 mm two members are said to effnc x provide continuity so that there is little or no rotation between the members at the joint and the Leffnc  0.5 bp Leffnc  150 mm members behave as if no joint existed. However, the joint is not necessarily fixed in space and

force. A pinned connection allows rotation but no translational movement, it transmits shear

mayleff1 rotate a support for example. A way the degree of fixity or stiffness  about 2 Leffnc leff1of characterising 0.3 m

and axial forces but not bending moment. A fixed connection does not allow translational

provided by a semi-rigid connection either to a support or another member is to measure the

movement or rotation and transmits shear, axial forces, bending and torsional moment.

rotation at the joint as the bending moment on the joint is varied. The tension resistance of the T-stub: Figure bellow defines the strength, stiffness and deformation capacity of a beam-to-column Use boltsdesigned M24 8.8to transfer a moment from the beam into the column. M-φ curves in general connection

downwards and only transmits shear force that acts downwards at a support. A sliding

non-linear, for practical application, it is 2necessary to idealise the M-φ curves. The rotation from the table 3.3  fu  800 MPa  As  353 mm capacity is a measure of the deformation that can be obtained before failure somewhere in the

Sabah Shawkat ©

connection causes a drop in the moment resistance. The resistance BtRd is determined by the tensile resistance of the bolt, the punching shear For strength, the following classes can be distinguished: resistance is not decisive. nominally pinned MRd ≤ 0,25 Mpl.Rd

The dimensions of the splice

 Msd  350 kN m  fyw  355 MPa

tf  20 mm  h  600 mm 

 e  65 mm

e min  60 mm w  120 mm

 mmax  1.25 mx

 M0

 1.1

bp  300 mm tp  25 mm  af  8 mm ex  60 mm

m x  s  e x  0.8  a f  n  emin

fyp  355 MPa

2

tw  6 mm s  120 mm 

mx  50.949 mm

mmax  63.686 mm

z  h  tf

z  0.58 m

< MRd < Mpl.Rd partial-strength 0,25 fMpl.Rd  BtRd1  203.3 kN ub  fyp Mb  1.25 full-strength MRd ≥ Mpl.Rd BtRd  4 BtRd1 B  813.2 kN full-strength if rotation capacity is tRd

 M2

 1.25

not checked MRd ≥ 1,2 Mpl.Rd  2 fyp  M Mpl1Rd  15.12784 m kN  pl1Rd  0.25  leff1 tp  where  M0   is the design moment resistance of the connection MRd  2 fyp  Mpl.Rd thedesign (full plastic moment). M 0.25 leff1 tp strength  Mpl2Rd  15.12784 m kN  of the beam pl2Rd  is

 M0 

Column web in shear, compression and tension In The practice it is often to fabricate fixedaccording connections rotation may take place resistance of difficult the splice is calculated to and EC3.some A simplified method is used

Failure mode 1 (yield of the end-plate):

between thethe element on one side the joint and thatare onasthe Suchabove. a joint is known as a whereby bolt forces and theofequivalent T-stub inother. the figure semi-rigid connection strictly is the condition of mostregion, joints which are described This method is validand, when there speaking are two bolt rows on the tension the resistance FRd does as not being fixed3,8 or rigid. A momentlater connection could be force described one which on) and the axial in theassplice is lessalthough than 10%only of the exceed BtRd (presented semi-rigid approaches theofbehaviour plastic axial resistance the beam.of a fixed connection and transfers a substantial bending moment. Note that connections may be fabricated for particular requirements so that, for example, they may allow rotation in the plane of the elements but prevent twisting about the axis of the element thus allowing torsional moments to be transmitted. This is a common

Ft1Rd  4 

Mpl1Rd mx

Ft1Rd  1187.68424 kN

Failure mode 2 (combined bolt failure and yield of the end-plate): Moment-rotation characteristic of a semi-rigid joint with enough plastic rotation capacity 2 Mpl2Rd  n BtRd Ft2Rd  the classification is as follows:Ft2Rd  712.46841 kN For stiffness, m n x

Connections Connectionsininsteel steelstructures structures Connections Connectionsininsteel steelstructures structures


151

Rotation capacity of the splice:

Failure mode 3 (bolt failure): Ft3Rd  BtRd

The following criteria have to be valid in order that the forces in the splice may be distributed

Ft3Rd  813.2 kN

according to the theory of plasticity: Tension resistance of the equivalent T-stub is Ft2Rd

Bending in the end-plate sets the bending resistance of the splice.

In addition to the resistance of the T-stub, the resistance of the compression flange and web as

tp  0.36 d 

well as that of the tension region of the web have to be checked.

fub fyp

Resistance of the compression flange and the web of the beam:

In this example, neither of these criteria is valid. However, the plastic resistance may be taken

McRd  729.5 kN m

FcfRd 

McRd

as the resistance of the splice, because the splice in this example is not subject to further rotation capacity requirements due to additional plastic hinges appearing later on.

FcfRd  1257.75862 kN

h  tf

The plastic bending moment:

In the formula above, McRd is the resistance of the beam. In this case the cross-section is

Sabah Shawkat ©

Class2, and its plastic bending resistance is 729.5kNm.

M  jRd  FRd z

MjRd  336.92727 m kN

Resistance of the tension region of the beam web: befftw  leff1 fyw 355 MPa 

befftw  0.3 m

 FtwRd  befftw tw 

fyw

 M0

tw  0.006 m

In sufficient rotation capacity is required in the splice and the criteria mentioned above are not

valid, it is possible to take the value of 2/3 of the plastic bending resistance as the elastic bending resistance. The bending resistance of the splice would then be

FtwRd  580.90909 kN

2

MjRd 3

 224.61818m kN

The resistance of the splice is the least of the resistances calculated above: FRd  Ft1Rd

FRd  1187.68424 kN

FRd  Ft2Rd

FRd  712.46841 kN

FRd  Ft3Rd

FRd  813.2 kN

FRd  FcfRd

FRd  1257.75862 kN

FRd  FtwRd

FRd  580.90909 kN

The criterion for the calculation method to valid:

FRd 3.8 BtRd1

 0.75195

FRd 3.8 BtRd1

 1.0

Ok

Failure to respect the bearings of the supporting elements during the realization

Connections in steel structures Connections in steel structures


152 132

Connections in steel structures Using the beam profile WI500-8-15x250, design the joint shown in the adjacent figure.

condition at steel beam supports. By contrast Resistance on the basis of material strength:the element may be fixed in its plane to transmit

The steel grade is S355J2G3. The joint is subject to shear force Vsd at the ultimate limit state. Joints between structural line elements, in one plane, may be classified as simple connections,

bending but allow rotation about its axis. Note that if pinned or fixed joints are made between Vsd tp  and an immovable  tp support 7.437 then mm that end of the element may not move translationally an element fy  or rotate inbpspace, as distinct from a movement which is merely relative to the member on the

 Vsd  connections, 600 kN  fy or 355 MPa  M0 as1.1 k  0.43also  tknown mm as sliding as pin pinned connections fixed connections, rigid f  15as

 M0

connections. A simple connection allows rotation and movement in any direction except fu  510 MPa   bp  250 mm  Mw  1.25 a  5 mm  H  600 mm downwards and only transmits shear force that acts downwards at a support. A sliding 235the MPa connection along line of the and rotation and only transmits  hw  Hallows  2 tfmovement hwelement  0.57 m     0.66197  b  360 shear mm fy force. A pinned connection allows rotation but no translational movement, it transmits shear

other side of the joint. Fixed joints, or nearly fixed joints, between two members are said to

and axial forces but not bending moment. A fixed connection does not allow translational

provided a semi-rigid connection either to a support or another member is to measure the becomebycritical.

movement or rotation and transmits shear, axial forces, bending and torsional moment.

rotation at the joint as the bending moment on the joint is varied.

provide continuity so that there is little or no rotation between the members at the joint and the Resistance against local buckling: members behave as if no joint existed. However, the joint is not necessarily fixed in space and may rotate about aofsupport for example. A way of characterising degree of fixity or stiffness The thickness the end-plate is chosen so that the resistance the against local buckling does not

b

Figure bellow defines the strength, stiffness and deformation capacity of a beam-to-column tp b tp  p  0.673 connection28.4 designed the beam) into the column. M-φ curves in general ( 28.4 0.673  k   kto transfer a moment from  

non-linear, for practical application, it is necessary to idealise the M-φ curves. The rotation capacity is a measure of the deformation that can be obtained before failure somewhere in the b is the width of an outstand plate element. connection causes a drop in the moment resistance. b For strength, the following classes can be tdistinguished: tp  p  0.04339m ( 28.4  0.673 )    k  nominally pinned MRd ≤ 0,25 Mpl.Rd

Sabah Shawkat © 0,25 Mpl.Rd < MRd < Mpl.Rd

partial-strength

full-strength MRd ≥ M pl.Rd when the end-plate is in the middle of an I-profile (subpanels of equal size), the following full-strength if obtained rotation capacity is condition is for the thickness of the end-plate: not checked tp  where

MRd a

Is the throat thickness of the weld

The nominal ultimate tensile strength of the weaker part joint Column web in shear, compression and tension fu  510 In practice it isMPa often difficult to fabricate fixed connections and some rotation may take place

between the element on one side of the joint and that on the other. Such a joint is known as a semi-rigid strictly of most joints which are described Is the and, design shearspeaking strength is ofthe thecondition weld fvwd connection as being fixed or rigid. A moment connection could be described as one which although only Is the appropriate correlation factor  w  0.9 w semi-rigid approaches the behaviour of a fixed connection and transfers a substantial bending moment. Note that connections may be fabricated for particular requirements so that, for Is the partial safety factor  Mw example, they may allow rotation in the plane of the elements but prevent twisting about the axis of the element thus allowing torsional moments to be transmitted. This is a common

bp

MRd ≥ 1,2 Mpl.Rd

tp  0.01506 m

tp  16 mm ( 38.23)   k is the design moment resistance of the connection

Mpl.Rd is the design strength of the beam (full plastic moment). Connection weld of the end-plate The twin fillet weld between the end-plate and the web is assumed to be effective. The following condition is obtained for the throat thickness of the weld: fu

fvwd 

3  w  Mw

fvwd  261.732 MPa

Vsd aw  2.01089 mm aw  Moment-rotation 2 hw fvwdcharacteristic of a semi-rigid joint with enough plastic rotation capacity For stiffness, the classification is as follows:

Connections Connectionsininsteel steelstructures structures Connections Connectionsininsteel steelstructures structures


153

On the basis of the cooling rate of the weld, the result is  aw 

tp mm

 0.5

aw  3.5

aw  4 mm

then aw will be

Column Bracket: The thickness of the bracket is normally 30-50mm. Its width is taken as equal to that of the endplate of the beam. Its depth is determined by the connection welds. Vertical welds and the lower horizontal weld are taken to be load-bearing. the upper surface has to be flat so that the endplate of the beam is able to rest on it. The following condition is obtained for the bracket depth: hk 

Vsd 2 a fvwd

bp 2

hk  104.242 mm

hk  200 mm

Sabah Shawkat © Some beam - to – column joints

1. The pinned joints in Fig. a) and b) are normally used when an I-beam is to be joined to a column. 2. The joint in Fig. a) is faster and more economical to make than the joint in Fig. b). 3. The rotation at the beam end is, however, larger in the case of the joint in Fig. a). 4. A typical pinned joint between a rafter and column is shown in Fig. c) 5. A rigid joint shown in Fig. d)

Connections in steel structures Connections in steel structures


154 132

Connections in steelwe structures In This example try to explain the geometrical and mechanical properties of ordinary bolts

condition at attachment steel beam -supports. By contrast the element may be fixed in its plane to transmit Detail of Steel Beam to Steel Column. bending but allow rotation about its axis. Note that if pinned or fixed joints are made between

and describes their behaviour in shear, tension or combined shear and tension. Joints between connections, structural linebolts elements, in one plane, loads may be classified as to simple connections, In structural are used to transfer from one plate another. We explain

an Data: element and an immovable support then that end of the element may not move translationally

as here sliding connections, pin loaded or pinned where bolts areas used, by:connections as fixed connections, also known as rigid

or rotate in space, as distinct from a movement which is merely relative to the member on the Steel  "s 235" fy  235 MPa fu  360 MPa  m0  1.1  m1  1.1  m2  1.3 other side of the joint. Fixed joints, or nearly fixed joints, between two members are said to

connections. A simple connection allows rotation and movement in any direction except downwards and force only transmits shear force that acts downwards at a support. A sliding 1. Shear

5 or no rotation between the members at the joint and the provide continuity so that little E there 2.1 is   10 MPa

connection movement the of line the element and on rotation and only plates. transmits The loadallows is transmitted intoalong and out theofbolts by bearing the connected Theshear forces

members behave as if no joint existed. However, the joint is not necessarily fixed in space and

force. A bolts pinned rotation shear. but no translational movement, it transmits shear in the areconnection transmittedallows by transverse and axial forces but not(only bending 2. Tension force M) moment. A fixed connection does not allow translational

may rotate about a support for example. A way of characterising the degree of fixity or stiffness Steel =orS235 provided by a semi-rigid connection either to a support another member is to measure the

movement or rotation and transmits shear, axial moment. by axial In the case of moment loading (M) only, theforces, tensionbending part ofand the torsional load is transmitted

rotation at the joint as the bending moment on the joint is varied. t=40mm

8.8 and 10.9.

Figure bellow defines the strength, stiffness and deformation capacity of a beam-to-column E=210000MPa connection designed to transfer a moment from the beam into the column. M-φ curves in general 2 M10 58 mmthe non-linear, for practical application, it is necessary to =idealise M-φ curves. The rotation M12 = 84 mm2 2 capacity is a measure of the deformation that can be obtained M16 = 157 before mm failure somewhere in the 2 connection causes a drop in the moment resistance.M20 = 245 mm2 M24 = 353 mm For strength, the following classes can be distinguished: M30 = 561 mm2 mm2 nominally pinned MRd ≤M37 0,25=M459 pl.Rd

According to Euro-code 3, the design yield stress fyb and the design ultimate stress fub of the

full-strength

usual bolts are as given in Table below.

full-strength if rotation capacity is Except for fitted bolts or where low-clearance or oversize holes are specified, the nominal not checked MRd ≥ 1,2 Mpl.Rd clearance in standard holes shall be: where

tension in the bolt. 3. Combined tension and shear force (M and V) In the case of combined moment (M) and transverse loading (V), the bolts may be required to transmit a combination of transverse shear and axial tension.

Sabah Shawkat ©

Bolts and nuts are available in steels of minimum tensile strengths up to about 1370 MPa. The grade of the bolts is indicated by two numbers. The most common grades are 4.6, 5.6, 6.5, 6.8,

partial-strength 0,25connection Mpl.Rd < MRd < Mpl.Rd Bolted beam-to column

Mechanical properties of bolts Grade fyb (MPa) fub (MPa)

4.6 240 400

5.6 300 500

6.5 300 600

6.8 480 600

8.8 640 800

10.9 900 1000

Column web in shear, compression and tension design fyb can be derivedfixed fromconnections the grade byand multiplying the first by the In The practice it isyield oftenstress difficult to fabricate some rotation maynumber take place secondthe number times 10. The ultimate is the first number times 100 (stresses between element on one side design of the joint and stress that onfubthe other. Such a joint is known as a in MPa).connection and, strictly speaking is the condition of most joints which are described semi-rigid grade areAused most connection frequently. could be described as one which although only as Bolts being of fixed or 8.8 rigid. moment semi-rigid approaches the behaviour of a fixed connection and transfers a substantial bending moment. Note that connections may be fabricated for particular requirements so that, for example, they may allow rotation in the plane of the elements but prevent twisting about the axis of the element thus allowing torsional moments to be transmitted. This is a common

MRd ≥ Mpl.Rd

is the design moment resistance of the connection MRd 1mm for M12 and M14 bolts Mpl.Rd is the design strength of the beam (full plastic moment). 2mm for M16 to M24 bolts 3mm for M27 and larger bolts. Holes will be formed by drilling or punching. Punching holes in steelwork is much faster than drilling but some cracking may appear in the material and therefore, in some cases, holes will not be punched full size but must be punched 2mm diameter less than full size and then reamed. A = πd2/4 The area of the threaded part that is used in design formulae is called the stress area As: Moment-rotation characteristic of a semi-rigid joint with enough plastic rotation capacity As = πds2 /4 For stiffness, the classification is as follows:

Connections Connectionsininsteel steelstructures structures Connections Connectionsininsteel steelstructures structures


155

The diameter ds are somewhat larger than the diameter of the core, because of the fact that a

The coefficient 0,5 is the result of a statistical evaluation based on a very large number of

rupture plane always includes at least one thread.

test results. It appears that bolts of these grades are less ductile and that the rupture occurs

ds is the mean value between the core diameter (dc) and the flank diameter (df) of the thread;

suddenly. 2. For the shear plane passing through the unthreaded portion of the bolt:

the flank diameter is the mean value between the core diameter and the nominal diameter (d):

Fv,Rd = 0,6 fub A /γ Mb df

dc  d

ds

2

df  dc

Vsd  300kN

Design shearing force:

2

fub  800MPa

Strength grade of Bolt 8.8:

fvb  640MPa

Resistance to shear for one shear plane: 2

Bolt core area:

As  157mm

Partial safety factor:

Diameters of bolts 0.6 fub As

Mb  1.45

Sabah Shawkat © Fv.Rd 

The value of As for common bolt diameters is given in table below: Nominal diameter db (mm)

Nominal area A (mm2)

Stress area As (mm2)

8 10 12 14 16 18 20 22 24 27 30

50,3 78,5 113 154 201 254 314 380 452 573 707

36,6 58,0 84,3 115 157 192 245 303 353 459 561

The design shear resistance of a bolt (FvRd) in normal conditions, per shear plane, is:

FvRd = 0,5 fub As /γMb

for strength grades 4.8, 5.8, 6.8 and 10.9

d  16mm

d0  18mm

Bore diameter:

The thickness of the front plate:

t =12mm

Distances from the ends and edges :

e1  2 d0

e1  36 mm

Force direction: Perpendicular to the direction of force:

e2  1.5 d0

e2  27 mm

Hole spacing: p1  3.5 d0

Force direction

Perpendicular to the direction of force

for strength grades 4.6, 5.6 and 8.8

Fv.Rd  51.972kN 

Mb

Bolt diameter:

1. For the shear plane passing through the threaded portion of the bolt: FvRd = 0,6 fub As / γMb

p1  1 fub    1.0  3d0 3 d0 4 fu  

 e1

 min

Fb.Rd 

 2.5  fu d t 

Mb

Connections in steel structures Connections in steel structures

p1  63 mm

p1=3.5 d0

p1  63 mm

 0.667

Fb.Rd  79.448 kN


156 132

Connections in Bolts: steel structures Number of Vsd n  Joints between structural line elements, inn one plane, may be Iclassified as M16 simple suggest 6x connections,  5.772 min Fv.Rd Fb.Rd as sliding connections, as pin or pinned connections as fixed connections, also known as rigid connections. simple connection allows rotation and movement in any direction except DetermineAthe desired height of face plate: downwards and only transmits shear force that acts downwards at a support. A sliding Aw fy connection element Awof thetw.p dc and rotation and only transmits shear Vpl.Rdallows movement along the line 3  m1 force. A pinned connection allows rotation but no translational movement, it transmits shear

and axial forces but not bending moment. A fixed connection does not allow translational tw.p  12.5mm Wall thickness of steel beam movement or rotation and transmits shear, axial forces, bending and torsional moment. Vsd  3  m1 hc.d  hc.d  194.579 mm tw.pfy

Specify the depth of the face plate 220 mm

hcd  210mm

Carrying capacity fillet welds:

condition at steel beam supports. By contrast the element may be fixed in its plane to transmit Av.net fy but allow rotation about bending its axis. Note that if pinned or fixed joints are made between  0.653  0.914 A f an element and an immovable support then that end of the element may not move translationally v u or rotate in space, as distinct from a movement which is merely relative to the member on the fy Av.net If side of the joint. Fixednot considering weakening of the effective area of the shear, other joints, or nearly fixed joints, between two members are said to fu Av provide continuity so that there is little or no rotation between the members at the joint and the otherwise members behave as if no joint existed. However, the joint is not necessarily fixed in space and Deal = Not considering weakening the effective area of the shear may rotate about a support for example. A way of characterising the degree of fixity or stiffness

Av fy connection either to a support or another member is to measure the provided by a semi-rigid Vpl.Rd  310.824 kN Vpl.Rd  rotation at the joint 3 bending moment on the joint is varied.  m1as  the Figure bellow defines the strength, stiffness and deformation capacity of a beam-to-column Condition  "front plate suits" if Vfrom  V connection designed to transfer a moment beam pl.Rdthe sd into the column. M-φ curves in general non-linear, for practical it "isotherwise necessary to idealise the M-φ curves. The rotation "Face application, plate does not capacity is a measure of the deformation that can be obtained before failure somewhere in the Condition = front plate satisfies connection causes a drop in the moment resistance.

Sabah Shawkat ©

(connecting the steel beam to the front panel) We suppose the depth of weld

aw  4mm

weld length:

Lw  2 220mm

Factor for adequate strength steel grade:

w

Partial safety factor of welded joints:

Fw.Rd 

fu awLw

 w 

w 3

 0.8

w  1.5

Fw.Rd  304.841 kN

For strength, the following classes can be distinguished:

MRd ≤ 0,25 Mpl.Rd

nominally pinned

0,25 Mpl.Rd < MRd < Mpl.Rd

partial-strength

MRd ≥ Mpl.Rd

full-strength

full-strength if rotation capacity is

MRd ≥ 1,2 Mpl.Rd

not checked where MRd

is the design moment resistance of the connection

Mpl.Rd

is the design strength of the beam (full plastic moment).

Condition 

"Weld Pass" if Fw.Rd  Vsd Column web in shear, compression and tension "The weld was " otherwise In practice it is often difficult to fabricate fixed connections and some rotation may take place

between the element one side of the joint and that on the other. Such a joint is known as a Condition = Weldon Pass semi-rigid connection and, strictly speaking is the condition of most joints which are described as being fixed orofrigid. A moment Assessment the face plate onconnection the shear: could be described as one which although only semi-rigid approaches the behaviour of a fixed connection and transfers a substantial bending 3 2 Av.net  t  hcd  d0 Av.net  2.304  10 mm moment. Note that connections may be fabricated for particular requirements so that, for

Two layers’ steel shelter structure using circular hollow sections

example, they may allow rotation in the plane of the elements but prevent twisting about the 2 A  t hcd  Av 2520 mm v axis of the element thus allowing torsional moments to be transmitted. This is a common

Moment-rotation characteristic of a semi-rigid joint with enough plastic rotation capacity For stiffness, the classification is as follows:

Connections Connectionsininsteel steelstructures structures Connections Connectionsininsteel steelstructures structures


157

Single sided beam-to-column joint configuration, bolted end-plate connection

e 

2 e  0.05 m

To be evaluated: Design moment resistance, initial stiffness Data 3

2

IPE270

A270  4.59 10 mm

HEB180

Ac  6.53 10 mm

3

2

Material S335

6

4

Iy270  57.9 10 mm 6

4

Iyc  38.3 10 mm  M0

bc  w

 tfc fyc   mplfc  0.25    M0 

 iy270  112 mm

mplfc  16.415 kN

 iyc  76.6 mm

 1

 M1

2

 1

4M20  8.8

p  60

 u  10 mm

 w  80 mm

Sabah Shawkat © Beam:

 hc  180 mm

 tfc  14 mm

tfc  14 mm

hwc  hc  2 tfc  2 rc hwc  0.122 m Avc  Ac  2 bc tfc   twc  2 rc  tfc 2

 Avc 2029 mm

 0.8 rc 2  m 23.75 mm m 

3

Wplyb  484 10 mm 

 1

 twb  6.6 mm

Level arm

twc  8.5 mm

 rc  15 mm

z  hb  u 

tfb

w  twc

3

bc  180 mm   fyc  335 MPa

 M0

p  70 mm 

tfb  10.2 mm

 u  10 mm

fyb  335 MPa 

Equivalent T-stub tension Column:

 hb  270 mm

McRd 

2

p

Wplyb fyb  M0

z  0.2049 m

McRd  162.14 m kN

End plate: bp  180 mm 

a w  3 mm

af  5 mm

w  80 mm

fyp  335 MPa 

mp 

w  twb 2

 0.8  2 aw

Connections in steel structures Connections in steel structures

 tp  18 mm


158 132

condition steel beam supports. By contrast the element may be fixed in its plane to transmit Tensionatresistance:

Connections in steel  mmstructures mp 33.31

mp2  p  u  tfb  0.8  2 af Joints between structural line elements, in one plane, may be classified as simple connections, as sliding mp2 connections, 44.14 mm as pin or pinned connections as fixed connections, also known as rigid connections. A simple connection allows rotation and movement in any direction except bp  w ep  and only transmits shear force that acts downwards at a support. A sliding downwards 2 connection allows movement along the line of the element and rotation and only transmits shear 0.05 m connection allows rotation but no translational movement, it transmits ep A pinned force. shear and axial forces but2 not bending moment. A fixed connection does not allow translational tp fyp   mplp  or0.25 movement rotation and transmits shear, axial forces, bending and torsional moment.  M0

mplp  27.135 kN

or rotate in space, asA distinct from a movement which is merely relative to the member on the 0.6 fub s20 FvRd  94.08 kN FvRd  other side of the joint. Fixed joints, or nearly fixed joints, between two members are said to Mb Lb  tfc  tp so0.5  hthere hnut 4mm Lb  52.4 mm  or2 no bolt  is provide continuity that little rotation between the members at the joint and the

members behave as if no joint existed. However, the joint is not necessarily fixed in space and Column web ina shear: may rotate about support for example. A way of characterising the degree of fixity or stiffness provided by a semi-rigid connection either to a support or another member is to measure the

rotation at the joint as the bending moment on the joint is varied. 0.9 Avc fycw Figure bellow  defines the strength, stiffness and deformation capacity of a beam-to-column VwcRd 3  M0 connection designed to transfer a moment from the beam into the column. M-φ curves in general non-linear, for353.19027 practical kN application, it is necessary to idealise the M-φ curves. The rotation VwcRd 

Alpha factor for effective lengths mp

bending but allow 0.9 fubrotation As20 about its axis. Note that if pinned or fixed joints are made between F  141.12 kN FtRd  an element and an immovable supporttRd then that end of the element may not move translationally Mb

capacity is a measure of the deformation that can be obtained before failure somewhere in the Assumption   1 connection causes a drop in the moment resistance. VwcRd FRd1  the following classes can be distinguished: For strength,

Sabah Shawkat ©

1



1

 0.3998

mp  ep

nominally FRd1 pinned 353.19027 kN partial-strength Stiffness coefficient

mp2

2



2

 0.52989

MRd ≤ 0,25 Mpl.Rd

0,25 Mpl.Rd < MRd < Mpl.Rd

full-strength  z 204.9 mm h  z full-strength if rotation capacity is

mp  ep

MRd ≥ Mpl.Rd

h 204.9 mm  not checked MRd ≥ 1,2 Mpl.Rd 0.38 Avc where k1   k1 3.76 mm  h is the design moment resistance of the connection MRd

Mpl.Rd Column web in shear, compression and tension In practice it is often difficult to fabricate fixed connections and some rotation may take place

Bolts:the element on one side of the joint and that on the other. Such a joint is known as a between 2

 fub  connection 800 MPa and, Astrictly 245 mm is the condition  Mb of1.25  tfc are 14 described mm semi-rigid most joints which s20  speaking as being fixed or rigid. A moment connection could be described as one which although only tp 18 mm  h hnut  14.8 mm bolt  10 mm semi-rigid approaches the behaviour of a fixed connection and transfers a substantial bending

moment. Note that connections may be fabricated for particular requirements so that, for

example, they may allow rotation in the plane of the elements but prevent twisting about the axis of the element thus allowing torsional moments to be transmitted. This is a common

is the design strength of the beam (full plastic moment).

Component N2-Column web in compression Resistance: tfb  0.0102 m

af  0.005 m

tp  0.018 m

tfc  0.014 m

 s  12 mm

u  0.01 m

Moment-rotation characteristic of a semi-rigid joint with enough plastic rotation capacity

For stiffness, the classification is as follows:

Connections Connectionsininsteel steelstructures structures Connections Connectionsininsteel steelstructures structures


159

beffcwc

mintfb  2 af  2  2 tp  5  tfc  s

tfb  2 af  2  2 tp  5  tfc  s  0.19034 m

1

tfb  af  2  tp  u  5  tfc  s  0.17527 m

beffcwc  tfb  af  2  tp  u  5  tfc  s



beffcwc  0.17527 m

1 twc   1  1.3  befftwc   A vc  

FRd3   befftwc twc 

Reduction factors to account for compression stresses and instability fywc  335 MPa

 dc  92 mm 2

 Avc 2029 mm

twc  0.0085 m

E  210 GPa

kwc

  p  0.932  



beffcwc  0.17527 m

kwc  1

 M1

1

1

0.7 befftwc twc

twc   1  1.3  beffcwc   A vc  

2

 0.55611

 0.76677

p

1

 0.673

 

1

 1

0.7 beffcwc twc

in this example only bolt row 1 is considered for tension forces lefftfc  befftwc n

fywc

lefftfc  0.1575 m

 

see column web in tension

 bp  w 

 bp  w

2

2

mine 1.25 m 

 

FRd2  382.68231 kN

 M1

n 

e  0.05 m

 0.05 m

 bp  w 2

1.25 m  0.02969 m

n  0.05 m

Component N4-Column flange in bending Model1 Complete yielding of the flange k2  8.55 mm

Fi

k1 E i

lefftfc  0.1575 m

FfcRdt1 

Component N3 - column web in tension m  0.02375 m

e  0.05 m

fywc  335 MPa

twc  0.0085 m

m

Resistance: min( 2  m 4 m  1.25 e)

4 lefftfc mplfc

FfcRdt1  435.43 kN

befftwc

Component N5-End plate in bending

Bolt rows considered

 0.76677

Stiffness coefficient

 3.14159

k3  7.68 mm

hwc

Sabah Shawkat © Etwc

p

Column web in compression:

FRd3  343.88 kN

 M0

Component N4-Column flange in bending

1

hwc

fywc

2

FRd2  kwc   beffcwc twc 

k2 

 0.79912

1

2

Stiffness coefficient k3 

beffcwc dc fywc

befftwc  0.1575 m

 comRd   min 1.0 1.7   fzwc  

befftwc  4 m  1.25 e

4 m  1.25 e  0.1575 m

2  m  0.14923 m

Connections in steel structures Connections in steel structures


160 132

Connections steel structures Mode2 boltinfailure with yielding of the flange

 BtRd  141.1 kN Joints between structural line elements, in one plane, may be classified as simple connections, 2 lefftfc m 2 pinned BtRd n connections as fixed connections, also known as rigid as sliding connections, asplfc pin or FfcRdt2  FfcRdt2  261.43356 kN m  n connections. A simple connection allows rotation and movement in any direction except

downwards andfailure only transmits shear force that acts downwards at a support. A sliding Mode 3 bolt

connection allows movement along the line of the element and rotation and only transmits shear FfcRdt3  2 BtRd FfcRdt3  282.2 kN force. A pinned connection allows rotation but no translational movement, it transmits shear

N4but column flange inmoment. bending A fixed connection does not allow translational andComponent axial forces not bending

movement or rotation and transmits shear, axial forces, bending and torsional moment. Resistance:

min FfcRd1 FfcRd2 FfcRd3

FRd4

FRd4  FfcRdt2

FRd4  261.43356 kN

Stiffness coefficient

or rotate in space, as distinct from a movement which is merely relative to the member on the McRd k1  are said to FRd7  otherFRd7 sideof the joint. Fixed joints, or 624.1 nearlykN fixedStiffness joints, coefficient between two members  hb  tfb provide continuity so that there is little or no rotation between the members at the joint and the Component N8as -Beam tensionHowever, the joint is not necessarily fixed in space and members behave if noweb jointinexisted.

mayResistance rotate about a support for example. A way of characterising the degree of fixity or stiffness lefftwbby alefftp mmor another member is to measure the provided semi-rigid connectionlefftwb either to 203.17 a support rotation at the joint as the bending moment on the joint is varied. fyb Stiffness coefficient kN k8  FRd8  lefftwb twb the strength, Fstiffness Rd8  449.2 Figure bellow defines and deformation capacity of a beam-to-column  M0

connection designed to transfer a moment from the beam into the column. M-φ curves in general Component tension it is necessary to idealise the M-φ curves. The rotation 10-Bolts in non-linear, for Npractical application,

0.9 lefftfc tfc

k4  29.03 mm

Sabah Shawkat ©

lefftp

m

3

min 2  mp  mp 

  mp lefftp

Model1

2  mp  0.20927 m

lefftp  0.20317 m

1.25 mp  0.04163 m

an Resistance element and an immovable support then that end of the element may not move translationally

capacity is a measure of the deformation that can be obtained before failure somewhere in the Resistance: connection causes a drop in the moment resistance. FRd10  2 BtRd FRd10  282.2 kN Lb  47.4 mm For strength, the following classes can be distinguished:

3

k4 

condition at steel beam supports. By contrast the element may be fixed in its plane to transmit Component N7-Beam flange and web in compression bending but allow rotation about its axis. Note that if pinned or fixed joints are made between

e  0.05 m

FepRd1 

FepRd2 

np

 mp

 0.20317 m

min ep 1.25 mp e

np  1.25 mp

ep  0.05 m

np  0.04163 m

Stiffness coefficient partial-strength

not checked Relevant component

4 lefftp mplp

FepRd1  662.09 kN

mp 2 lefftp mplp  2 BtRd np

FepRd2  303.91 kN mp  np Column web in shear, compression and tension FRd5 itmin  FepRd1 FepRd2 FepRd3 fixed connections FepRd1 662.09 kN may take place In practice is often difficult to fabricate andsome rotation Model2

MRd ≤ 0,25 Mpl.Rd As20 k0,25  10  M1.6 pl.Rd < MRd < Mpl.Rd k10  8.27 mm Lb full-strength MRd ≥ Mpl.Rd Design moment resistance: full-strength if rotation capacity is

nominally pinned

between theelement thejoint and that onFthe other. Such a joint is known as a 303.91 on kN one side of FRd5 FepRd2 FepRd2 Rd5  303.91 kN semi-rigid connection and, strictly speaking is the condition of most joints which are described N5-rigid. End plate in bending as Component being fixed or A moment connection could be described as one which although only

Design plastic moment resistance  M jRd  FRd z  MjRd 53.57 m kN Design plastic moment resistance

MjelRd 

semi-rigid Stiffnessapproaches coefficient the behaviour of a fixed connection and transfers a substantial bending

FRd  FRd4

moment. Note that connections may be fabricated for particular requirements so that, for 3 0.9 lefftp tp example, the plane k5  they may allow rotation k5 in 28.86 mm of the elements but prevent twisting about the 3 m axis of the element thus allowing torsional moments to be transmitted. This is a common p

MRd ≥ 1,2 Mpl.Rd

where FRd4  261.43 kN FRd4  FfcRdt2 FfcRdt2  261.43 kN is the design moment resistance of the connection MRd Column flange in bending kNdesign strength FRd  261.43 Mpl.Rd is the of the beam (full plastic moment).

2 3

MjRd

Moment-rotation characteristic of a semi-rigid joint with enough plastic rotation capacity  MjelRd 35.71 m kN For stiffness, the classification is as follows:

Connections Connectionsininsteel steelstructures structures Connections Connectionsininsteel steelstructures structures


161

Stiffnes

E  210 GPa

Initial stiffness

 k1 3.76 mm

k2  8.55 mm

k4 29.03 mm   k5 28.86 mm

Calculate the resistance of the joint shown in the adjacent figure. The joint is subject to a shear

h  0.2049 m

force Vsd. The primary beam is of WI800-15-20x300 and the secondary beam of WI700-1015x250, both of S355J2G3 grade. Angle sections L100x10 of S355J0 grade and bolts of M20

k3  7.68 mm

8.8 are to be used in the joint.  Vsd  700 kN

k10  8.27 mm

e1  60 mm   e2  50 mm

d0  22 mm

p1  70 mm   P2  70 mm

E h

Sjini 

1 k1

1 k2

1 k3

2

1 k4

1 k5

1

hprimary  800 mm

Sjini  12542.72 m kN

Sj 

Sjini

tfprimary  20 mm

Twprimary  10 mm

 tp  8 mm

 t  15 mm

d  20 mm

 a1  50 mm

 a2  50 mm

a3  105 mm

hp  600 mm

 fub  800 MPa  fu  510 MPa

fy  355 MPa

 M0

 1.1

2

Sj  6271.36 m kN

k  0.5

n  6

Sabah Shawkat ©

Secant stiffness

bprimary  300 mm

hsecondary  700 mm bsecondary  250 mm tfsecondary  15 mm twsecondary  10 mm

k10

e  65 mm

because the bolts are in one row.

fu

Is the ultimate tensile strength of the relevant part.

t

Is the thickness of the relevant part

Connections in steel structures Connections in steel structures

 Mb

 1.25


162 132

Connections in steel structures Primary beam - angle section:

condition at steel beam supports. By contrast the element may be fixed in its plane to transmit

Shear resistance of the bolts

maxor ( 12tfixed 150mm ) bending but allow rotation about its axis. Note thateif pinned joints are made between 1max

Joints between structural line elements, in one plane, may be classified Vsdas simple connections, 2  FvRd  120.6 kN FvRd   As  245 mm as sliding connections, as pin or pinned connections as fixed connections, 10 also known as rigid

1.2 d 0 an element and an immovable support then that end eof1min the element may not move translationally

connections. A simple connection allows rotation and movement in any direction except (kN) force that acts downwards at a support. A sliding Shear resistance of atransmits bolt FvRd shear downwards and only Bolt M16 and M20 M24 M30 connection allows movement along the line of the elementM12 and rotation only transmits shear

other side of the joint. Fixed joints, or nearly fixedp joints,3.0between two members are said to  d0 1min

2

stress area (mm allows ) 84,3 movement, 157 245 it transmits 353 561 force.Tensile A pinned connection rotation but no translational shear Shear resistance F per shear plane if the grade vRd and axial forces but not bending moment. A fixed connection does not allow translational shear or plan passes theshear, threaded 8.8 bending 32,4 and 60,3torsional 94,1 moment. 135,6 215,4 movement rotation andthrough transmits axial forces, portion of the bolt 10.9 33,7 62,8 98,0 141,2 224,4 Cross-section area of the unthreaded shank (mm)

113

201

314

452

707

shear plane passes through the unthreaded 8.8

43,4

77,2

120,6 173,7

271,4

shank of the bolt

45,2

90,4

125,7 181,0

282,8

Shear resistant FvRd per shear plane if the grade 10.9

e

1.5 d

e2max

max( 12t 150mm)

0 2min or rotate in space, as distinct from a movement which is merely relative to the member on the

p 1max min(the 14t 200mm ) provide continuity so that there is little or no rotation between members at the joint and the e3min 1.5 d 0 members behave as if no joint existed. However, the joint is not necessarily fixed in space and p 2max

min( 14t 200mm)

may rotate about a support for example. A way of characterising the degree of fixity or stiffness e4

1.5 d 0

provided bythe a semi-rigid either to a support or another member is to measure the Key to symbols ofconnection the bolt distances is varied. the diameter of the bolt hole d 0 is rotation at the joint as the bending moment on the joint and spacing F shows the direction of the force Figure bellow defines the strength, stiffness and deformation capacity of a beam-to-column t is lesser of the thicknesses of the connection designed to transfer a moment from the beam into the column. M-φ curves in general connected parts non-linear, for practical application, it is necessary to idealise the M-φ curves. The rotation capacity is a measure of the deformation that can be obtained before failure somewhere in the Minimum and recommended bolt distances and spacing: connection causes a drop in the moment resistance. e2 p1 p2 e1 Bolt Hole do For strength, the following classes can be distinguished: (mm) (mm) (mm) (mm) (mm) nominally pinned MRd ≤ 0,25 Mpl.Rd d minim. rec. minim. rec. minim. rec. minim. rec. o (mm) <M <M partial-strength 0,25 M

Sabah Shawkat ©

Normally, high-strength bolts of 8.8 and 10.9 grades are used. Those of 8.8 grades can be

considered as basic grade bolts. There are still other grades, but they are not normally in use. The ultimate tensile strength and the yield strength are obtained as follows: 2

2

Ultimate tensile strength: fub = 10 * 100 N/mm = 1000 N/ mm

fyb = 1000 * 0.9 N/mm2 = 900 N/mm2

Yield strength:

pl.Rd

Rd

pl.Rd

M12 13 16 30 full-strength M16 if rotation 18 22 full-strength capacity is 40

20MRd ≥ M 25pl.Rd 27 30

M20 not checked whereM24

80

78

80

33the design 40moment 75resistance 50 of the 60 73 is connection

100

99

100

M30

22

27

50

26

32

60

29

40

39

40

40

55

54

55

33 40Mpl.Rd 49 MRd ≥ 1,2 39 50 58

70

66

70

The recommended bolt sizes are M12, M16, M20, and M30. Intermediate sizes (M14, M22

MRd

and M27) exist according to strands, but they may not be available. These are bolts of a size

Mpl.Rd is the design strength of the beam (full plastic moment). Angle section:

larger than M30 (e.g. M36), but they are to be avoided, because smaller bolts cab be handled Column web in shear, compression and tension more easily and faster on site. In practice it is often difficult to fabricate fixed connections and some rotation may take place The grades of nuts must correspond with the grades of the bolts. The nut grades between the element on one side of the joint and that on the other. Such a joint is known as a corresponding to high-strength bolts are 8 and 10. semi-rigid connection and, strictly speaking is the condition of most joints which are described as being fixed or rigid. A moment connection could be described as one which although only Positioning bolts semi-rigid approaches the behaviour of a fixed connection and transfers a substantial bending Bearing resistance shall be calculated as follows: moment. Note that connections may be fabricated for particular requirements so that, for  2.5  fu d t  FbRd they  may allow rotation  example, in the plane of the elements but prevent twisting about the

 Mb

axis of the element thus allowing torsional moments to be transmitted. This is a common

 e1

min



p1

 3 d0 3 d0



  

fub fu p1 3 d0

1 4

 1 fub  1.0  4 fu 



 1.56863

 0.81061

e1

d0 

 2.72727

 1

Moment-rotation of a semi-rigid joint with enough plastic rotation fu d tp  Vsd capacity  2.5  characteristic FbRd   FbRd  132.29091 kN FbRd  OK  is as follows: For stiffness, the classification  10 Mb  

Connections Connectionsininsteel steelstructures structures Connections Connectionsininsteel steelstructures structures


163

Web of the beam:

 p1

min

 3 d0

  

p1

3 d0

FbRd 

 1 fub  1.0  4 fu 

1

4

Connection in double shear

fub

fu

 1

 2.5  fu d t   2   Mb 

FbRd   

 0.81061

 2.5  fu d t   

 Mb

Secondary Beam - angle section:

2

2

 Ip

2

  

x1  120 mm

z  200 mm

 Ip  2  x  x1  z

2

112000mm

 0.81061



fub

e1

3 d0

fu

 1

 0.90909

FvRd  2 FvRd

2

Avnet   hp  n d0 t

 fy  2   Av  6264.70588 mm  fu 

FbSd  142.17128 kN

FvRd  241.2 kN

FbRd  278.18182 kN

 Av 9000 mm

 Av  hp t

2  Vsd   z     Msd   Ip   6  

FbRd 

Vsd 10

OK

2

 Avnet 7020 mm

 fy   Av  fu 

Avnet  

The holes do not reduce the shear resistance:

FvRd  FbSd

Bearing resistance: Distance e1 is calculated in the direction of the force resultant FbSd. It is, however, possible to use the smallest of the edge distances:

 fy  1   3   M0

VplRd  Av 

VplRd  1676.9401 kN

VplRd  Vsd

The tension resistance of a bolt-plate assembly, BtRd, shall be taken as the smaller of the tension resistance of the bolt and the punching shear resistance of the bolt head and the nut. The tension

Angle section:

resistance of a bolt shall be calculated as follows:

p1  1 fub    1.0      3 d0 3 d0 4 fu 

 e1

min

 1.56863

4



Shear resistance of the angle sections:

Shear resistance of the bolts - connection in double shear:

1

Sabah Shawkat © Msd  45.5 m kN

2

p1 3 d0

 2.5  fu d t     Mb 

Shear force resultant: FbSd 

 e1  p1  1 fub    1.0   3 d0  3 d0 4 fu 

min

FbRd  

Moment due to eccentricity  Msd  Vsd e

OK

Web of the beam:

FbRd  248.04545 kN

 x  40 mm

 Vsd   2  10 

FbRd  

FbRd  556.36364 kN

 Vsd    2  140kN  10 

OK

10



 0.81061

Vsd

FbRd  

p1 3 d0

1 4

 1.56863

fub



 0.90909

fu

FtRd

0.9 

fub 

Mb

As

Connections in steel structures Connections in steel structures


164 132

Connections in steel structures Tension resistance of a bolt FtRd:

fixed its plane transmit condition at steel beam supports. By calculated contrast theusing element may be The values in this table have been the basic value in in EC3, Mb = to 1,25,

Bolt M12 M16 M20 M24 M30 Joints between structural line elements, in one plane, may be classified as simple connections, Grade 8.8 48,6 90,4 141,1 203,3 323,1 as sliding connections, as pin or pinned connections as fixed connections, also known as rigid Grade 10.9 60,7 113,0 176,4 254,2 403,9 connections. A simple connection allows rotation and movement in any direction except The values in this table have been calculated using the basic value in EC3, Mb = 1,25. downwards and only transmits shear force that acts downwards at a support. A sliding

bending but allow rotation about its axis. Note that if pinned or fixed joints are made between M2 = 1,25 an element and an immovable support then that end of the element may not move translationally

The punching resistance ofthe theline boltofhead and the nut be calculated as follows: connection allowsshear movement along the element andshall rotation and only transmits shear force. A pinned connection allows rotation but no translational movement, it transmits shear fu 0.6 but dmnot tp bending moment. A fixed connection does not allow translational and Baxial pRd forces  Mb movement or rotation and transmits shear, axial forces, bending and torsional moment.

the bolt is subject to bothfrom sheara and tensionwhich force the following provision holdon true: or If rotate in space, as distinct movement is merely relative to theshall member the other side of the joint. Fixed joints, or nearly fixed joints, between two members are said to Fvsd Ftsd   1there is little or no rotation between the members at the joint and the provide continuity so that FvRd 1.4 FtRd members behave as if no joint existed. However, the joint is not necessarily fixed in space and may rotate about a support for example. A way of characterising the degree of fixity or stiffness

Resistance the end ofconnection the secondary beam: provided by aof semi-rigid either to a support or another member is to measure the rotation at the joint as the bending moment on the joint is varied.

Bending moment in section I-I: stiffness and deformation capacity of a beam-to-column Figure bellow defines the strength,

Where tp

is the thickness of the plate under the bolt head or the nut

dm

is the smaller of the following values:

connection designed to transfer a moment from the beam into the column. M-φ curves in general non-linear, for practical application, it is necessary to idealise the M-φ curves. The rotation  bprimary M   10 mm MIsd  112 m kN Isd  Vsd  2 capacity is a measure  of the deformation  that can be obtained before failure somewhere in the

Sabah Shawkat © the mean of the across points dimension and across flats dimension of the bolt head. The mean of the across points dimension and across flats dimension of the nut.

8,8

10,9

8,8

10,9

M20 8,8

M24

full-strength if rotation capacity is fy MelRd  210.031 m kN  MelRd  WTel  Mpl.Rd MelRd  MIsd not checked MRd ≥ 1,2

10,9

8,8

10,9

M30 8,8

 M0

where

10,9

6 7 in shear, 9 9 10and tension 11 13 13 16 Column web compression S275 4 5 6 8 8 9 9 11 11 13 In practice it is often difficult to fabricate fixed connections and some rotation may take place S235

3

partial-strength 0,25 Mpl.Rd < MRd < Mpl.Rd Bending resistance in section I-I full-strength MRd ≥ Mpl.Rd

Limit thickness (mm) for the punching shear resistance of the bolt head or the nut M16

3

WTel  650.8 10 mm

MRd ≤ 0,25 Mpl.Rd

nominally pinned

The punching shear resistance of the bolt head determines the tension resistance, if the 1.5 fub As  M2 following condition holds true: tp   dm fu  Mb

M12

connection causes a drop in the moment resistance. 2 4 4  AT  8070 mm IT  25963.1 10 mm For strength, the following classes can be distinguished:

5

S335the element 4 6 and 6that on the 8 other.8Such a 9joint is known 9 between on5one side5of the joint as11a S275N 5 6 7 8 8 10 10 12 12 15 semi-rigid connection and, strictly speaking is the condition of most joints which are described S355N 4 rigid. A 5 moment 5 connection 7 7 be described 8 8 one which 10 although 10 12 as being fixed or could as only

OK

is theindesign resistance of the connection MRd Shear resistance sectionmoment I-I: Mpl.Rd is the design strength of the beam (full plastic moment). AIv   hsecondary  2tfsecondary  30 mm twsecondary

 fy  1   3   M0

VplRd  AIv 

2

 AIv 6400 mm

VplRd  1192.49074 kN

VplRd  Vsd

Combined bending and shear resistance in section I-I:

S420N approaches 4 5 behaviour 5 of a6fixed connection 6 7 and transfers 7 9 9 bending 11 semi-rigid the a substantial S355MNote 4that connections 5 6 may be7 fabricated 7 for particular 8 8 requirements 10 10 that, for 12 moment. so S420Mthey may 4 allow 5 rotation 5 in the 7plane of7the elements 8 12 example, but8 prevent10twisting9 about the

4 5 allowing 5 torsional 6 moments 6 7 9This is a9 common 11 axisS460M of the element thus to7be transmitted.

Vsd  0.5 VplRd 0.5 VplRd  596.24537 kN Moment-rotation characteristic of a semi-rigid joint with enough plastic rotation capacity

For stiffness, the classification is as follows:

Connections Connectionsininsteel steelstructures structures Connections Connectionsininsteel steelstructures structures


165

The shear force reduces the bending resistance The simplified method is used (reduced strength is used for the whole profile)

  2 

Vsd

 VplRd

Lveff   hp  2 a1  L1  L2

2

 1

 fu   hp  2 a1  a1  a3  n d0    0.75135 m  fy 

 0.03028

 fy  1   3   M0

VeffRd  twsecondary Lveff 

 MIsd 112 m kN

MelVRd  MelRd ( 1   )

MelVRd  203.67104 m kN

Lveff  606.02817 mm VeffRd  1129.19215 kN

Lveff  L3 VeffRd  Vsd

Some typical connections are illustrated in figure below. Bolts and welds in connections should

MelVRd  MIsd

be able to resist the beam reaction and any relevant moment due to the eccentricity of the force to the centre line of the connecting components.

Shear resistance in the force crossing the holes: AIvnet   hsecondary  2tfsecondary  30 mm   n d0 twsecondary 2

Sabah Shawkat ©

A 5080 mm Ivnet

 fy   AIv  fu 

AIvnet  

 fy  2   AIv  4454.90196 mm  fu 

The holes do not reduce the shear resistance. The shear resistance has already been calculated in section I-I.

Shear rupture resistance of the beam end: d0  0.022 m

d  0.02m L1  a1

L1  50 mm

 fu    fy 

L2   a2  k d0 

L2  56.03 mm

L3   hp  2 a1  a1  a3

L3  655 mm

L1  5 d

5 d  0.1 m

Some typical connections beam – to - beam joints

 fu  L3   hp  2 a1  a1  a3  n d0   f  y

Connections in steel structures Connections in steel structures


166 132

Connections in steel structures

condition at steel beam supports. By contrast the element may be fixed in its plane to transmit bending but allow rotation about its axis. Note that if pinned or fixed joints are made between

Joints between structural line elements, in one plane, may be classified as simple connections,

an element and an immovable support then that end of the element may not move translationally

as sliding connections, as pin or pinned connections as fixed connections, also known as rigid

or rotate in space, as distinct from a movement which is merely relative to the member on the

connections. A simple connection allows rotation and movement in any direction except

other side of the joint. Fixed joints, or nearly fixed joints, between two members are said to

downwards and only transmits shear force that acts downwards at a support. A sliding

provide continuity so that there is little or no rotation between the members at the joint and the

connection allows movement along the line of the element and rotation and only transmits shear

members behave as if no joint existed. However, the joint is not necessarily fixed in space and

force. A pinned connection allows rotation but no translational movement, it transmits shear

may rotate about a support for example. A way of characterising the degree of fixity or stiffness

and axial forces but not bending moment. A fixed connection does not allow translational

provided by a semi-rigid connection either to a support or another member is to measure the

movement or rotation and transmits shear, axial forces, bending and torsional moment.

rotation at the joint as the bending moment on the joint is varied. Figure bellow defines the strength, stiffness and deformation capacity of a beam-to-column connection designed to transfer a moment from the beam into the column. M-φ curves in general non-linear, for practical application, it is necessary to idealise the M-φ curves. The rotation capacity is a measure of the deformation that can be obtained before failure somewhere in the

Sabah Shawkat © connection causes a drop in the moment resistance.

For strength, the following classes can be distinguished:

MRd ≤ 0,25 Mpl.Rd

nominally pinned partial-strength

0,25 Mpl.Rd < MRd < Mpl.Rd

MRd ≥ Mpl.Rd

full-strength

full-strength if rotation capacity is

MRd ≥ 1,2 Mpl.Rd

not checked where MRd

is the design moment resistance of the connection

Mpl.Rd

is the design strength of the beam (full plastic moment).

Column web in shear, compression and tension In practice it is often difficult to fabricate fixed connections and some rotation may take place between the element on one side of the joint and that on the other. Such a joint is known as a semi-rigid connection and, strictly speaking is the condition of most joints which are described as being fixed or rigid. A moment connection could be described as one which although only semi-rigid approaches the behaviour of a fixed connection and transfers a substantial bending moment. Note that connections may be fabricated for particular requirements so that, for example, they may allow rotation in the plane of the elements but prevent twisting about the bolt distances spacings This is a common axis of the element thus Incorrect allowing production torsional moments to beand transmitted.

Realizationsofbalcony familyjoint home using I steel profiles Moment-rotation characteristic a semi-rigid with enough plastic rotation capacity For stiffness, the classification is as follows:

Connections Connectionsininsteel steelstructures structures Connections Connectionsininsteel steelstructures structures


167

on the basis of tension resistance, shear resistance and the combined tension and shear

Joint to the foundation The foundation of a building shall be designed to carry the working load with adequate factor of safety. Dead load, imposed load and wind load should be assessed in accordance with the Building (Construction) Regulations and the relevant codes of practice.

resistance. In some cases, the situation under the erection period may be the critical load case. in this case, the holding-down bolts are chosen on the basis of buckling resistance. A column base connection always consists of a plate welded to the foot of the column and

The allowable capacity of the soil/rock under working loads where any foundation is founded

bolted down to the foundations. A second, usually rather thicker, steel plate is normally

shall be the lesser of:

incorporated into the top of the foundation, as illustrated in figure below. It helps both to locate

(a) the ultimate capacity for bearing, bond or friction with an adequate factor of safety against

the foot of the column accurately and in spreading the load into the weaker (concrete or

failure; or

masonry) foundation material.

(b) the value in relation to bearing, bond or friction such that the maximum deformation or movement induced to the foundation under working loads can be tolerated by the building, any other building, structure, land, street and services A welded column is normally joined to the foundation by using holding-down bolts. It may be necessary to strengthen the base of the column. The thickness of the base plate may be reduced by using stiffeners. However, it is often more economical to make the base plate thicker and

Sabah Shawkat ©

abandon the stiffeners. A dowel profile welded on the under-side of the base plate is designed

to carry the shear force either in one or both directions with reference to the principal axes. in

this case, the holding-down bolts can be designed for tension or compression (buckling

Some column joints to the foundation

resistance) applied under the erection period only. in order to get the bearing pressure more

evenly distributed on the foundation, it is possible to use stiffening. This method of strengthening is used in heavily loaded hollow section columns.

Joint of an axially loaded column to the foundation

In the case of an axially loaded column, the resistance of the foundation against bearing pressure due to axial force must be checked. The bearing pressure gives rise to a bending moment in the

base plate, the value of which determines the size of the base plate as follows: tp 

A welded column- joined to the foundation or to the RC slab by using holding-down bolts.

6 Msd  M0 beff fy

Where

Msd

is the bending moment applied to the base plate

beff

is the effective width of the base plate

fy

is the yield strength of the base plate

The design of the holding-down bolts and foundation must comprise different load cases to be checked. In order to determine the resistance of the foundation, the load case causing the highest bearing pressure on the foundation has to be ascertained. The holding-down bolts are chosen

Connections in steel structures Connections in steel structures


168 132

Connections in steel structures

be fixed in strength its plane of to the transmit condition By contrast element maycompressive is =beam fck / supports. γc is the design value the of the cylinder fcd at steel

Joints between structural line elements, in one plane, may be classified as simple connections,

bending but allow rotation about its axis. Note that if pinned or fixed joints are made between concrete an element and an immovable support then that end of the element may not move translationally is the characteristic cylinder compressive strength of the concrete fck or rotate in space, as distinct from a movement which is merely relative to the member on the

as sliding connections, as pin or pinned connections as fixed connections, also known as rigid connections. A simple connection allows rotation and movement in any direction except downwards and only transmits shear force that acts downwards at a support. A sliding connection allows movement along the line of the element and rotation and only transmits shear force. A pinned connection allows rotation but no translational movement, it transmits shear and axial forces but not bending moment. A fixed connection does not allow translational movement or rotation and transmits shear, axial forces, bending and torsional moment.

other side of the joint. Fixed joints, or nearly fixed joints, between two members are said to The bearing area under the base plate. The width of the effective area is obtained as provide continuity so that there is little or no rotation between the members at the joint and the follows: members behave as if no joint existed. However, the joint is not necessarily fixed in space and may rotate about a support for example. A way of characterising the degree of fixity or stiffness fy c tpby  a semi-rigid connection either to a support or another member is to measure the provided 3 fj  M0 rotation at the joint as the bending moment on the joint is varied. Figure bellow defines the strength, stiffness and deformation capacity of a beam-to-column connection designed to transfer a moment from the beam into the column. M-φ curves in general non-linear, for practical application, it is necessary to idealise the M-φ curves. The rotation capacity is a measure of the deformation that can be obtained before failure somewhere in the

Sabah Shawkat © b b  c  c    1  3    1    1  c1  b b c  1 1  1  

connection causes a drop in the moment resistance.

For strength, the following classes can be distinguished:

MRd ≤ 0,25 Mpl.Rd

nominally pinned

The design bearing strength of the foundation is obtained as follows:

fj

partial-strength

0,25 Mpl.Rd < MRd < Mpl.Rd

MRd ≥ Mpl.Rd

full-strength

full-strength if rotation capacity is

Bjkj fcd

MRd ≥ 1,2 Mpl.Rd

not checked where

where

c

MRd

is the design moment resistance of the connection

Mpl.Rd

is the design strength of the beam (full plastic moment).

is the partial safety factor for concrete Column web in shear, compression and tension

In practice it is often difficult to fabricate fixed connections and some rotation may take place is 2/3 provided that the characteristic strength of the grout is not less than 0,2 Bj between the element on one side of the joint and that on the other. Such a joint is known as a times the characteristic strength of the concrete foundation and the thickness of semi-rigid connection and, strictly speaking is the condition of most joints which are described the grout is not greater than 0,2 times the smallest width of the steel base plate as being fixed or rigid. A moment connection could be described as one which although only semi-rigid approaches the behaviour of a fixed connection and transfers a substantial bending is a concentration factor, kj = 1 as a conservative default value (for more exact kj moment. Note that connections may be fabricated for particular requirements so that, for calculation refer to in EC3) example, they may allow rotation the plane of the elements but prevent twisting about the axis of the element thus allowing torsional moments to be transmitted. This is a common

Area in compression under base plate

Moment-rotation characteristic of a semi-rigid joint with enough plastic rotation capacity For stiffness, the classification is as follows:

Connectionsininsteel steelstructures structures Connections Connections Connectionsininsteel steelstructures structures


169

Incorrectly anchoring the baseplate to the foundation

Sabah Shawkat © Anchoring the steel plate into the reinforced concrete foundation-hinged connection

Incorrectly anchoring the baseplate to the foundation where the bolts is missing

Baseplate connections in simple construction are generally modelled as pins, and designed to transfer either concentric force (compression or tension) or a combination of axial and shear force (usually when the column is part of the bracing system). In some instances, they may, however, be designed to transmit also bending moments due to moderate load eccentricity, or for erection stability. The plate is always attached to the column by means of fillet welds. However, if the column carries only compression loads, direct bearing may be assumed, provided that the contact

Baseplate connection is generally modelled as pin

surfaces are machined or can be considered to be flat. No verification of the welds is then required. Machining may be omitted if loads are relatively small. Where there are moderate tension forces or no net tension the holding down bolts are usually cast into the foundation.

When tensile forces are significant, it is necessary to provide appropriate anchorage to the bolts. For example, threaded bolts may be used in conjunction with channel sections embedded in the concrete.

Connections in steel structures Connections in steel structures


170 132

In tensioninconnections the baseplate thickness is often dictated by the bending moments Connections steel structures

condition at steel beam supports. By contrast the element may be fixed in its plane to transmit

produced by the holding down bolts. The bending moments may require the use of stiffeners.

bending but allow rotation about its axis. Note that if pinned or fixed joints are made between

Joints between structural line elements, in one plane, may be classified as simple connections,

an element and an immovable support then that end of the element may not move translationally

as Joint sliding as pintoor pinned connections as fixed connections, also known as rigid ofconnections, a beam - column foundation

or rotate in space, as distinct from a movement which is merely relative to the member on the

connections. connection allows rotation movement direction except In the joint A of asimple beam-column to the foundation the and tension resistanceinofany the holding-down bolts downwards and onlyin transmits force thatofacts downwards at and a support. A sliding has to be checked addition toshear the resistance the steel base plate the foundation if the

other side of the joint. Fixed joints, or nearly fixed joints, between two members are said to

connection allowsbolts movement alongtothe line offorce. the element and rotation andofonly transmits shear holding-down are subject tensile in addition, the effect the shear force has to force. A pinned connection allows rotation but no translational movement, it transmits be taken account of. the thickness of the base plate has to be determined with respectshear to both

members behave as if no joint existed. However, the joint is not necessarily fixed in space and

andcompression axial forcesand buttension not bending sides. moment. A fixed connection does not allow translational movement or rotation and transmits shear, axial forces, bending torsionalfigure moment. the following equilibrium equations are obtained according to and the adjacent for the doubly

provided by a semi-rigid connection either to a support or another member is to measure the

Nc  Ns

rotation at the joint as the bending moment on the joint is varied.

connection designed to transfer a moment from the beam into the column. M-φ curves in general

beff yfj  As fyb

Msd  Nsd 0.5 ap   ap  d 

may rotate about a support for example. A way of characterising the degree of fixity or stiffness

Figure bellow defines the strength, stiffness and deformation capacity of a beam-to-column

symmetric I-profile located centrally with respect to the steel base plate: Nsd

provide continuity so that there is little or no rotation between the members at the joint and the

non-linear, for practical application, it is necessary to idealise the M-φ curves. The rotation

Nc ( d  0.5 y)

capacity is a measure of the deformation that can be obtained before failure somewhere in the

Sabah Shawkat ©

From the later equation, it is possible to calculate the depth of the concrete section in compression:

P

beff yfj ( d  0.5 y)

partial-strength

fBB full-strength

0.5 beff fj y  beff fj dy  Msd  Nsd  d  0.5 ap  2

beff fj d 

 beff fj d  2  2 beff fj Msd  Nsd  d  0.5 ap

tw

V S

V

VBB

P b  a1

2 b  e

2

1 VBB MRd 2

W BB

≤ 0,25 Mpl.Rd

0,25 Mpl.Rd 2 < MRd < Mpl.Rd

2

P a1  b  6

M BB

fAA

P a b 1  3 a e

2

ecpl.Rd MeRdR ≥ M

b  ep

2

6

fBB

0.5 b 1

36 EI

3

36 EI  K  b  c  L0

p p full-strength if rotation capacity is K represent the modulus of elasticity of the soil not checked MRd ≥ 1,2 Mpl.Rd

tf

6 Mbb b  ea

 10

2

24 e

where

beff fj where beff is the effective width of the steel base on the compression side. e1 e2

N

nominallyaxb pinned

Msd  Nsd  d  0.5 ap

y

connection causes a drop in the moment resistance. we calculate the pressure on the foundation For strength, the following classes can be distinguished: a

MRd

is the design moment resistance of the connection

Mpl.Rd

is the design strength of the beam (full plastic moment).

F

 e  1 mm  e Column web in0.75 shear, 0.75and  2 atension  h w 0.75 lweld  a  2  2 a compression I 2 2 e1  e2 In practice it is often difficult to fabricate fixed connections and some rotation may take place

a

a

verification of welded jointcolumn between the element on one sidefoundation of the jointvsand that on the other. Such a joint is known as a N M  h is the condition semi-rigid connection and, strictly speaking most joints which are described   of e  1.18   e I  a  2   l1 a1 1connection  2  h I  2 t fcould  a 2 l2 be as being fixed or rigid. hAI moment described as one which although only 2 2 semi-rigid approaches the jointbehaviour of aweb fixed connection and transfers a substantial bending verification of welded column

moment. Note that connections may be fabricated for particular requirements so that, for 2 2 N  T 1   1.4  1.8   prevent 0.8  1  twisting   allow  e plane of the elements but  example, they may rotation in the about the I  a   a   2 I3 a3 3  axis of the element thus allowing torsional moments to be transmitted. This is a common

Moment-rotation characteristic of a semi-rigid joint with enough plastic rotation capacity For stiffness, the classification is as follows: Joint of column to foundation

Connectionsininsteel steelstructures structures Connections Connections Connectionsininsteel steelstructures structures


171

Calculates the efforts in the plates fixed at the foundation

Definitions

Where

Allowable load. The maximum load that may be applied safely to a foundation after taking into

F is normal force

account its ultimate bearing capacity, negative skin friction, pile spacing, overall bearing capacity of the ground below the foundation and allowable settlement.

M is bending moment b is width of the plates

Allowable bearing pressure. The maximum allowable bearing pressure that may be applied at

h dimension to the massive subjected to M and F

the base of the foundation, taking into account the ultimate bearing capacity of the soil or rock,

Ar is total resistance section

h´3  3( L  h ) h´2  6m A  L h´  6m A  L h  r b r b    Calculate the compression stress of the concrete

the amount and kind of settlement expected and the ability of the structure to accommodate 0

such settlement. The allowable bearing pressure is a combined function of the site conditions, including all construction in the vicinity, and the characteristics of the proposed foundation/structure.

2 F L

c

 

b h´  h 

F L

h´ 

  h´    h´ b  h   3  2 c  1

3

Sabah Shawkat ©

Calculate the tension stress h´ b h  N 3 a  Ar h´ h 3

Verification of the plates of the column 1. next case A's position with ya = b/2

ep

4 F

 a  2 a  b   a    YA b   2. Case position B

ep

4 F

 a  2 a  b   a    YB b  YB  

The ground plan of the foundation made of steel profiles

Connections in steel structures Connections in steel structures


172 132

condition at steel beam supports. By contrast the element may be fixed in its plane to transmit Column-to –Foundation connections

Connections in steel structures

Joints between structural line elements, in one plane, may be classified as simple connections, as sliding connections, as pin or pinned connections as fixed connections, also known as rigid connections. A simple connection allows rotation and movement in any direction except downwards and only transmits shear force that acts downwards at a support. A sliding connection allows movement along the line of the element and rotation and only transmits shear force. A pinned connection allows rotation but no translational movement, it transmits shear and axial forces but not bending moment. A fixed connection does not allow translational movement or rotation and transmits shear, axial forces, bending and torsional moment.

bending but allow rotation about its axis. Note that if pinned or fixed joints are made between if a rigid column-to-foundation is assumed in the structural model the moments transferred into an element and an immovable support then that end of the element may not move translationally the foundation by the column must be accounted for when designing the holding down bolts or rotate in space, as distinct from a movement which is merely relative to the member on the and the base plate. If a pinned joint is assumed in the model, moments need not be taken into other side of the joint. Fixed joints, or nearly fixed joints, between two members are said to account. provide continuity so that there is little or no rotation between the members at the joint and the The holding down mustexisted. be designed such the thatjoint theyisarenot able to carry the construction loads members behave as ifbolts no joint However, necessarily fixed in space and therotate column is subjected thickness of the stage concrete layer takenorinto account may about a supportto. forThe example. A way of second characterising the degree ofisfixity stiffness when calculating the buckling length for the design of the holding down bolts. provided by a semi-rigid connection either to a support or another member is to measure the rotation at the jointinasthe themodel bending moment on the joint is varied. Column design building Figure bellow defines the strength, stiffness and deformation capacity of a beam-to-column Design the columns in a primary frames. The column-to-foundation is in this case assumed connection designed to transfer a moment from the beam into the column. M-φ curves in general rigid. The moment transferred from the column to the foundation must thus be taken into non-linear, for practical application, it is necessary to idealise the M-φ curves. The rotation account when designing the connection. The horizontal loads on the building are carried by the capacity is a measure of the deformation that can be obtained before failure somewhere in the bracing lattices, so the column are supported by the hinges at the upper end. The buckling length connection causes a drop in the moment resistance. of the columns can thus be obtained directly, given Lcy = 0,7 Lc. For strength, the following classes can be distinguished:

Sabah Shawkat © MRd ≤ 0,25 Mpl.Rd

nominally pinned

partial-strength 0,25 Mpl.Rd < MRd < Mpl.Rd Calculate the resistance of the foundation joint shown in the adjacent figure. The profile of the full-strength MRd ≥ Mpl.Rd column is WI700-15-20x400. Both the column and base plate material is S355J2G3 grade full-strength if rotation capacity is steel. not checked MRd ≥ 1,2 Mpl.Rd  af  6 mm tw  15 mm aw  4 mm  Mw  1.25  h  700 mm where MRd is the design the connection fck  30 MPa  tf  moment 20 mm resistance  M0  of 1.1 fu  510 MPa Mpl.Rd is the design strength of the beam (full plastic moment). Loading

Column web in shear, compression and tension

 N sd  950 kN

Msd  610 kN m

Vsd  250 kN

w

c

 0.9

 1.5

In practice it is often difficult to fabricate fixed connections and some rotation may take place between the element on one side of the joint and that on the other. Such a joint is known as a semi-rigid connection and, strictly speaking is the condition of most joints which are described as being fixed or rigid. A moment connection could be described as one which although only

Cross-section parameters: 6

4

Iy  2209.0 10 mm

3

3

2

Wely  6312.9 10 mm  A  25900 mm

semi-rigid approaches the behaviour of a fixed connection and transfers a substantial bending moment. Note that connections may fabricated particular requirements so that, for Realization of the be shelter of steelfor profiles for parking cars example, they may allow rotation in the plane of the elements but prevent twisting about the axis of the element thus allowing torsional moments to be transmitted. This is a common

Moment-rotation characteristic of a semi-rigid joint with enough plastic rotation capacity For stiffness, the classification is as follows:

Connectionsininsteel steelstructures structures Connections Connections Connectionsininsteel steelstructures structures


173

  perpendicular 2  3  perpendicular 2  134.84314 MPa fu 

fu  453.33 MPa

 w  Mw

408  MPa

 Mw

  parpendicular 2  3  parpendicular 2  

fu

OK

w  Mw

 parpendicular

fu  Mw

If the weld to be checked is part of a statically indeterminate structure, the size of the weld is determined on the basis of the deformability as follows (a twin fillet weld): 0.7  w

af  

Sizing of welds

2

tf

af  8.90955 mm

af  9 mm

Sabah Shawkat © Stress at the connection line between web and flange:

It is possible to transfer compressive stresses through bearing pressure, whereby the welds need not be designed for other than tensile and shear forces. Then there must be a tight

 x 

Msd  h  Nsd   tf   Iy  2  A

x

 54.45 MPa

contact between the base plate and the abutting end of the column. This must be mentioned in

Throat thickness of the weld:

the assembly drawing of the column.

 perpendicular

Stress on the centre-line of the flange:  II

Msd h  tf Nsd  x    2 Iy A

x

 57.2091 MPa





x

2  2 aw

tw

 perpendicular

Vsd

 II

2 aw  h  2 tf 

 72.19 MPa

 47.35 MPa

Compression of stresses: Throat thickness of the weld:  perpendicular

Stress in the twin fillet weld: x

tf

 perpendicular



 perpendicular

  perpendicular

2  2 af

 perpendicular

 67.42157 MPa

 perpendicular

 67.42157 MPa

 perpendicular

 perpendicular

2

2

2

2

2

 3   perpendicular    II 159.92 MPa

 3   perpendicular   II fu  Mw

OK

Connections in steel structures Connections in steel structures



2

fu w  Mw

 perpendicular

fu  453.33 MPa

 w  Mw

OK

 72.19 MPa

fu  408 MPa

 Mw


174 132

Chooseatribbed steel bolts 4xM36 the table of be thefixed manufacture. Thetocombined in its plane transmit condition steel beam supports. Byconforming contrast thetoelement may

Connections in of steel structures On the basis deformability:

0.7  w  awbetween  tw aw  6.68216 mm may be classified aw  7 as mmsimple connections, Joints structural line elements, in one plane, 2 as sliding connections, as pin or pinned connections as fixed connections, also known as rigid connections. A simple connection allows rotation and movement in any direction except Sizing of the base plate and holding - down bolts: downwards and only transmits shear force that acts downwards at a support. A sliding connection allows movement Dimensions of the plate: along the line of the element and rotation and only transmits shear force. A pinned connection allows rotation but no translational movement, it transmits shear ap  940 mm   s  120 mm b  460 mm e  60 mm  d  820 mm and axial forces but not bending moment. A fixed connection does not allow translational  e1  50 tp  forces, 60 mmbending fand 335 MPamoment.  w  transmits 300 mmshear, axial y torsional movement ormm rotation and

an of element and an immovable support then that end of the element may not move translationally the manufacturer. or rotate in space, as distinct from a movement which is merely relative to the member on the Thickness of the base plate on the compression side: other side of the joint. Fixed joints, or nearly fixed joints, between two members are said to j provide continuity so there is little or no rotation between the members at the joint and the 2 fthat  McSd  beff s  McSd  44.16 m kN tp  60 mm 2 members behave as if no joint existed. However, the joint is not necessarily fixed in space and may rotate about a support 6 McSd  M0 for example. A way of characterising the degree of fixity or stiffness tpc  either 43.49 to mm t  pc  tp member is to measure the pc provided by a semi-rigid connection a support or tanother beff fy rotation at the joint as the bending moment on the joint is varied. Figure bellow defines the strength, stiffness and deformation capacity of a beam-to-column Thickness of the base plate on the tension side: connection designed to transfer a moment from the beam into the column. M-φ curves in general ( s  e) application, it is necessary to idealise the M-φ curves. The rotation non-linear, for practical MtSd  11.21 m kN M tSd  N s  2 of the deformation that can be obtained before failure somewhere in the capacity is a measure

Strength of concrete C25/30:

 2  fck  fj    1   3  c

tensionbut and shear resistance should alsoNote be checked to see that if conforms to made the instructions bending allow rotation about its axis. that if pinned or fixed joints are between

fj  13.333 MPa

Sabah Shawkat © connection drop  m  ( scauses  e) a0.8 af in  the 2 moment resistance. m  49.82 mm For strength, the following classes can be distinguished:

Width of the bearing region:  c  tp 

fy

3 fj  M0

nominally Rd ≤ 0,25 Mpl.Rd leff  pinned 2 m  0.625 e  e1 lM eff  187.14 mm partial-strength 0,25 Mpl.Rd < MRd < Mpl.Rd

c  165.557 mm

beff  b

b  0.46 m

beff  0.46 m

Depth of the bearing region:

not checked

MpRd  where

d  0.82 m y1 

beff fj d 

full-strength  11.21 m kN MtSd full-strength if rotation capacity is

 beff fj d  2  2 beff fj Msd  Nsd  d  0.5 ap

MRd

2

leff tp fy

MRd ≥ Mpl.Rd

MRd ≥ 1,2 Mpl.Rd

MpRd  51.29 m kN

4  M0 is the design moment resistance of the connection

MpRd  MtSd

y1  1424.2 mm

Mpl.Rd is the design strength of the beam (full plastic moment). When tensile forces are significant, it is necessary to provide appropriate anchorage to the bolts.

Column web in shear, compression and tension d  difficult fj connections Msd  Nsd and 0.5 arotation  beff tofj dfabricate  2  2 beff  d some p   In practicebiteffisfjoften fixed may take place y2  y2 215.8 mm  f b eff j between the element on one side of the joint and that on the other. Such a joint is known as a

For example, threaded bolts may be used in conjunction with channel sections embedded in the

semi-rigid strictlymspeaking is the condition of most joints which are described  0.2158 y  y2connectionyand, as being fixed or rigid. A moment connection could be described as one which although only

produced by the holding down bolts. The bending moments may require the use of stiffeners.

beff fj

concrete. In tension connections the baseplate thickness is often dictated by the bending moments

semi-rigid approaches the behaviour of a fixed connection and transfers a substantial bending Forces on the compression and tension region: moment. Note that connections may be fabricated for particular requirements so that, for  N c  beff yfj N c  1323.546 kN example, they may allow rotation in the plane of the elements but prevent twisting about the Nofs theNelement  N s  373.546 kNmoments to be transmitted. This is a common axis torsional c  N sd thus allowing

Moment-rotation characteristic of a semi-rigid joint with enough plastic rotation capacity For stiffness, the classification is as follows:

Connectionsininsteel steelstructures structures Connections Connections Connectionsininsteel steelstructures structures


175

Calculate the joint resistance of a hollow section with dimensions 200x200x8. the steel grade used is S355J2H, and the design value for the compression resistance of concrete is 14 N/mm2. The base plate dimensions are a x b = 400x400. The steel grade used in the holding down bolts is S355. The column is subjected to the following loads: N sd  1600kN beff  400 mm   a1  100 mm

Msd  45 kN m

Vsd  120 kN

 fy  345 MPa

 fcd  14 MPa

d  350 mm

 a  400 mm

 M0

y2 

beff fcd d 

 beff fcd d  2  2 beff fcd Msd  Nsd (d  0.5 a ) beff fcd

y2  0.20608 m N c  beff y2 fcd 

N c  1154.02 kN

N s  N c  N sd

N s  445.98 kN

Holding down bolts are not subjected to tension

 1.1

Resistance of the holding down bolts Since the holding down bolts are not subjected to tension, the holding down bolts need be designed for shear only: As 

Vsd  3 1.1

As  0.00066m

2

Sabah Shawkat © fy

4bolts24

n  4

 24 mm

As 

 

2

0.78

4

4

As  0.001411 m

2

Base plate resistance

The value of the bending moment in the base plate at the column edge is as follows: 2

Msd 

beff a1 fcd

Msd  28 m kN

2

The thickness of the base plate is obtained by substituting the bending moment Msd into the First determine whether the holding down bolts are subjected to tension at the ultimate limit state:

y1 

beff fcd d 

y1  0.49392 m

 beff fcd d  2  2 beff fcd Msd  Nsd (d  0.5 a ) beff fcd

formula

tp  select

6 M sd  M0 b eff fy

6  M sd   M0

 tp  36 mm

Connections in steel structures Connections in steel structures

b eff  fy

 0.03659 m


176 132

Trusses and structures Connections in reticulated steel structures

condition at steel beam supports. By contrast the element may be fixed in its plane to transmit bending but allow rotation about its axis. Note that if pinned or fixed joints are made between

Stable assemblages of line individual tie and strut elements areclassified known asasreticulated structures. A Joints between structural elements, in one plane, may be simple connections,

an element and an immovable support then that end of the element may not move translationally

assemblage oforties and struts in twoasdimensions is knownalso as known a planeastruss as triangulated sliding connections, as pin pinned connections fixed connections, rigidand

of material and movement are more economical forof long or and heavy loads,and in spite of the extra costs connection allows along the line the spans element rotation only transmits shear

or rotate in space, as distinct from a movement which is merely relative to the member on the Removal of member from a determinate truss structure causes bending in members and other side of the joint. Fixed joints, or nearly fixed joints, between two members are said to collapse. provide continuity so that there is little or no rotation between the members at the joint and the A simple check for statically determinacy in a planar truss with pinned joints is given by: members behave as if no joint existed. However, the joint is not necessarily fixed in space and

of their fabrication. An essential point is but thatno thetranslational elements are always arranged in triangular force. A pinned connection allows rotation movement, it transmits shear

may rotate about a support for example. A way of characterising the degree of fixity or stiffness

which inherently stable,Aassuming none of thedoes angles the triangle is small. andconfigurations axial forces but notare bending moment. fixed connection notinallow translational

provided by a semi-rigid connection either to a support or another member is to measure the Where rotation at the joint as the bending moment on the joint is varied. n is the degree of indeterminacy which is zero for determinate structure and one or any Figure bellow defines the strength, stiffness and deformation capacity of a beam-to-column number above one for an indeterminate structure. connection designed to transfer a moment from the beam into the column. M-φ curves in general b is the number of bars in the truss structure, non-linear, for practical application, it is necessary to idealise the M-φ curves. The rotation r is the total number of reactive forces, being two for a pinned joint with a horizontal and capacity is a measure of the deformation that can be obtained before failure somewhere in the vertical reaction, three for a fixed support, which also has a moment reaction, and one connection causes a drop in the moment resistance. for a sliding support. For strength, the following classes can be distinguished: j is the number of joints including the joints at supports. nominally pinned MRd ≤ 0,25 Mpl.Rd If n is one or greater than one, then the truss is indeterminate and the forces in it cannot be found partial-strength 0,25 Mpl.Rd < MRd < Mpl.Rd out by consideration of equilibrium alone. If the degree of indeterminacy is less than zero, then full-strength MRd ≥ Mpl.Rd the arrangement of bars is inherently unstable and known as a mechanism. As already noted for full-strength if rotation capacity is the truss, a mechanism can be created by removal of a bar or a support restraint. not checked MRd ≥ 1,2 Mpl.Rd

consists, inAprinciple, of elementsallows connected by pin joints workingininany tension or compression connections. simple connection rotation and movement direction except see pictureand below. are shear often used place of rolled steel beams, they make downwards onlyTrusses transmits forceinthat acts downwards at a support. A better slidinguse

Comparing a beam to truss,axial bothforces, simplybending supported, horizontal top and bottom movement or rotation anda rectangular transmits shear, andthe torsional moment. beam members of the truss carry compression and tension respectively while diagonal and vertical elements serve to carry the shear force which is a maximum near supports. An important aspect of the design of plane trusses is that the top boom be stabilised to prevent buckling in the plane at right angles to the truss see picture below.

n

b  r  2 j

Sabah Shawkat © Top boom of truss restrained at ends and mid-span showing likely buckling mode and associated length between lateral supports,a.

where

Plane truss, top, and pinned-jointed model, bottom, which is determinate and used for preliminary analysis

Column web in shear, compression and tension In In practice it isthe often difficult to fabricate connections and some rotation may take place practice elements of the truss arefixed not usually connected by pure pin connections so that between the element one side ofinto thethe joint and thatalthough on the other. Suchisanot joint is known as a secondary bendingon is introduced members, the effect usually significant. semi-rigid connection is local the condition joints Individual elementsand, willstrictly also bespeaking subject to bending of if most any load is which appliedare at described right angles as anywhere being fixeddown or rigid. momentrather connection be described as oneThe which although onlyone theirAlength, than atcould the joints of the truss. removal of any semi-rigid behaviourtruss, of a fixed connection and transfers a substantialand bending member approaches of staticallythe determinate however, turns the truss into a mechanism loads to moment. that connections may be fabricated for particular requirements so that, for collapseNote see figure below. example, they may allow rotation in the plane of the elements but prevent twisting about the axis of the element thus allowing torsional moments to be transmitted. This is a common

MRd is the design moment resistance of the connection The truss to be designed is to support a roof which is only accessible for normal maintenance Mpl.Rd is the design strength of the beam (full plastic moment). and repair. The truss is 16 m span with 20° pitch. The dimensions of the truss are shown in the figure below. The imposed roof load due to snow is 1.05 kN/m2. The truss uses hollow sections for its tension chord, rafters, and internal members. The truss is fully welded. Truss analysis is carried out by placing concentrated loads at the joints of the truss. All of the joints are assumed to be pinned in the analysis and therefore only axial forces are carried by members.  1  20 deg

 2  90 deg

3  2  1

4  35 deg

Moment-rotation characteristic of a semi-rigid joint with enough plastic rotation capacity For stiffness, the classification is as follows:

Connectionsininsteel steelstructures structures Connections Connections Connectionsininsteel steelstructures structures


177

g  L1 Gd  cos 1

1

 Gd 18.93 kN m

 

Design value of combined actions on truss, for a purlin span of Lp  5.5 m 

 Fd  Gd  Lp

Fd  104.116kN 

Truss analysis due to forces Reaction force at support a

Ra  2 Fd

 Ra  208.231kN

At joint a Characteristic actions:

V

Permanent actions:

0

2

Self-weight of roof construction

g oroof  2 kN m

Fd   Fab  sin  1   RA   2  

Fd    2   Fab  sin  1  Ra 

Sabah Shawkat © 2

self-weight of services

g oservice  0.3 kN m

Total permanent actions

 go

2.3  kN  m

H

 2

Variable actions:

 Fab 456.621 kN

0

Fab  cos ( )  Fac

 

0

Fac  Fab  cos 1

 Fac 429.083kN 

2

imposed roof load

 q roof  1.05 kN m

Total imposed load

q roof  1.05 kN m 

At point b

2

V

Ultimate limit state (ULS): Partial factor for permanent actions

0

 

Partial factors actions:

Fbc  Fd  cos 1

0

 

Fbc   Fd  cos 1

 Fbc 97.837 kN

 G  1.35

Partial factor for variable actions

 Q  1.5

Reduction factor

  0.925

H

 

2

 g 4.447 kN m

Fbd  421.011 kN

 

Fbd  Fab  Fd  sin 1

At point c

Design value of obtained actions on purlins supported by truss For the distance of 4.0 m between purlins to centre

0

 Fbd  Fab  Fd  sin 1

Design value of combined actions: g    G g o   Q q roof

0

V

0

 

 

Fbc  sin 3  Fcd  sin 1

0

L1  4 m

Connections in steel structures Connections in steel structures

Fcd 

   

Fbc  sin 4 sin 1

  Fcd 164.075kN

0


178 132

Compression of the cross-section: condition at steelresistance beam supports. By contrast the element may be fixed in its plane to transmit

Connections H 0 in steel structures

 3 linecdelements,  4 in one plane,  3 as  4 connections, ac structural bc ce ac bc classified cd simple Jointscebetween may be F

F

 F  cos 

F

 cos 

0

F

 F

 F  cos 

F

 cos 

as sliding connections, as pin or pinned connections as fixed connections, also known as rigid

bending but allow rotation about its axis. Note that if pinned or fixed joints are made between  Fab 456.621 Fbd support  421.011  kN that end Fof  element 421.011 kNmay Fgf translationally 456.621 kN an element and an kN immovable then not move fd the

or rotate in space, member on the A ab  fy as distinct from a movement which Fab is merely relative to Fthe bd N



N

 0.466

 979.155kN 

 0.43

downwards and only transmits shear force that acts downwards at a support. A sliding

0Rd N0Rd N0Rd other 0Rd side of the joints, between two members are said to M0 joint. Fixed joints, or nearly fixed provide is little or no rotation between the members at the joint and the F F continuity so that there

Partial safety connection allowsfactor: movement along the line of1.1 the element and rotation transmits  M1  1 and only  M2  1.25 shear M0 

members N0Rdexisted. However, the joint is not necessarily fixed in space and N0Rd behave as if no joint

force. A pinned allows rotation Design of topconnection chords (members a-b, b-d,but d-f,no f-g)translational movement, it transmits shear and Maximum axial forces but not bending moment. design force (member a-b, f-g)A fixed connection does not allow translational

may rotate about support for example. A way ofischaracterising the degree of fixity or stiffness Therefore, the acompression design resistance adequate provided by a semi-rigid connection either to a support or another member is to measure the

movement or rotation and transmits shear, axial forces, bending and torsional moment.

rotation at the joint asresistance the bending moment on the joint is varied. Flexural buckling Figure bellow defines the strength,slenderness stiffness and capacity of a beam-to-column Determine the non-dimensional for deformation flexural buckling:

Fce 261.219kN  connections. A  simple connection allows rotation and movement in any direction except

 Fab 456.621 kN  Fbd 421.011 kN

Try

Fgf  Fab Ffd  Fbd

Fgf  456.621 kN

 0.466

non-linear,Afor practical application, it is necessary to idealise the M-φ curves. The Erotation  fy lab Lcr 1 s   L   1.0     Labcr before 4.257m failuresomewhere z abcr ab1 capacity isNa measure cos can   be obtained f in the i of the deformation that cr

z

1

1

Sabah Shawkat © fy

nominally pinned abcr

fy  355 MPa

Nabcr  1.373  10  kN

2 2

MRd ≥ Mpl.Rd

MRd ≥ 1,2 Mpl.Rd L abcr

not checked A  f ab y  ab  where N

 ab  0.886

abcr

b ab  160 mm

h ab  160 mm

tab  5 mm

2 In practice it is often difficult to fabricate  fixed connections and some rotation may take place Area A  3034 mm

ab

between the element on one side of the joint and that on the other. Such a joint is known as a semi-rigid connection and, strictly speaking is the condition of most joints which are described Classification of the cross-section: as being fixed or rigid. A moment connection could be described as one which although only cab  0.145m

MRd

iab

1

 ab1

 0.886

is the design moment resistance of the connection

Mpl.Rd is the design strength of the beam (full plastic moment). Determine the reduction factor due to buckling, use buckling curve a

Radius of gyration Column web in shear,  62.9 mm and tension iabcompression

 cab  h ab  3 tab

MRd ≤ 0,25 Mpl.Rd

0,25 Mpl.Rd < MRd < M3pl.Rd

full-strength if rotation capacity is

Section properties

Thickness

2

Labcr  1

full-strength

  0.814

Depth and width of section

2

A ab  fy  iab   ab1 partial-strength N 

t  16 mm

Yield strength 235 MPa

 ab1  76.409

Es  210 GPa

Steel grade S355 and thickness

 

y

connection causes a drop in the moment resistance.

For strength, the following classes can be distinguished:

Metal properties

e  0.81

Fbd  421.011 kN

semi-rigid approaches the behaviour of a fixed connection and transfers a substantial bending c

ab Note that connections may be fabricated forc particular requirements so that, for moment.  29 42 e  34.02  42 e Class 3 limit tab

gf

 0.43

connection designed to transfer a moment from the beam into the column. M-φ curves in general

Ffd  421.011 kN

square hollow section in S355 steel

160x160x

fd

t

example, they may allow rotation in the plane of the elements but prevent twisting about the axis of the element thus allowing torsional moments to be transmitted. This is a common

  0.21

  ab  0.5 1    ab  0.2   ab

 ab 

2

1  ab 

2

 ab   ab

2

 ab  0.964

 ab  0.743

Moment-rotation characteristic of a semi-rigid joint with enough plastic rotation capacity For stiffness, the classification is as follows:

Connectionsininsteel steelstructures structures Connections Connections Connectionsininsteel steelstructures structures


179

NbRd  Fab NbRd

 ab  A ab  fy

1

Following the same design process as above, the following resistances can be calculated:

 NbRd  800.58kN

 M1 Ok

Fab NbRd

Flexural buckling resistance:

 0.57

Determine the non-dimensional slenderness for flexural buckling: L bccr  1200 mm

Therefore, the design flexural buckling resistance of the selected 160x160x5 is satisfactory

 bc

A bc  fy

Lbccr

Nbccr

ibc

Design the bottom chords members (a-c, c-e, e-g)  bc1   

Maximum design force (member a-c and e-g) Fac 429.083kN  

 Fce 261.219kN 

Feg  Fac

 Feg 429.083kN 

1

Lbccr  1.2m

Lbccr  1.0 lbc

 bc1

2

Es

 bc1  76.409

fy

A bc  fy

 bc 

 bc  0.695

Nbccr

Nbccr  Lbccr ibc

A bc  fy  ibc   bc1

2

2 2

Lbccr  1 1

 bc1

  Nbccr 628.55kN

 0.695

Determine the reduction factor due to buckling, use buckling curve a The bottom chord will also be 160x160x5mm, S355. By inspection the design tension resistance

Sabah Shawkat ©   0.21

is equal to the design plastic resistance of the cross-section.

  bc  0.5 1    bc  0.2   bc

A ac  A ab

iac  iab

A ac  fy

NplRd   M0

 NplRd  979.155kN

NplRd  Fac

 bc 

Maximum design compression force

Fbc  97.837 kN

Ffe  Fbc

Ffe  97.837 kN

Maximum design compression force

Fcd  164.075kN 

Fed  Fcd

Fed  164.075kN 

2

1

 bc 

NbcRd 

Design the internal members (b-c, c-d, e-d, f-e):

2

 bc   bc

 bc  A bc  fy  M1

A bc  fy NplRd   M0

 bc  0.793  bc  0.85

2

 NbcRd  258.032kN

  NplRd 275.932kN

Fbc

NbcRd

Fbc

 0.379

NplRd  Fbc

NbcbRd

1

Ok

Ok

Serviceability limit state (SLS) Maximum length in compression is b-c and f-e

lfe  lbc

lbc  1200 mm

lfe  1.2m

EC provides suggested limits for vertical and horizontal deflections. The deflection should be checked under variable loads and that permanent loads should not be included.

Try b bc  60 mm

60x60x4 h bc  60 mm

Partial safety factor for actions:

in steel S355 2

2

tbc  4 mm  A bc  8.55 10  mm  ibc  2.26 10 mm

Partial safety factor for variable actions

 G  1.0

Design value of combined actions

f0  q roof   G

Design value of combined actions on truss

Connections in steel structures Connections in steel structures

Lp  5.5m

2

 f0 1.05 kN m


180 132

L1 structures Connections in steel  f0d  Lp  f0  cos 1

 

Design at ofsteel trusses condition beam supports. By contrast the element may be fixed in its plane to transmit

 f0d  24.583kN

Steps but in trusses bending allow design rotation about its axis. Note that if pinned or fixed joints are made between

connections. A simple connection allows rotation andspan/300 movement in any direction except The maximum allowable deflection is assumed to be

Task support then that end of the element may Illustration an element and an immovable not move translationally 1. Determination the loads in the or rotate in space, as distinct from a movement which is merely relative to the member on the structure. other side of the joint. Fixed joints, or nearly fixed joints, between two members are said to

downwards and only transmits Ltrussshear force that acts downwards at a support. A sliding

provide continuity so that there is little or no rotation between the members at the joint and the

300 the line of the element and rotation and only transmits shear connection allows movement along

members behave as if no joint existed. However, the joint is not necessarily fixed in space and

force. A pinned connection allows rotation but no translational movement, it transmits shear andConnections axial forces but not bending moment. A fixed connection does not allow translational

may rotate about a support for example. A way of characterising the degree of fixity or stiffness 2. Determine the height of the lattice. provided by a semi-rigid connection either to a support or another member is to measure the

The jointorresistances depend on the type axial of joint, the geometry of the joint and the forces in the movement rotation and transmits shear, forces, bending and torsional moment.

rotation at the joint as the bending moment on the joint is varied.

Joints between structural line elements, in one plane, may be classified as simple connections, as Deflection sliding connections, as pin or pinned connections as fixed connections, also known as rigid

 16 m Ltruss

d 

d  53.333 mm

members. It is unlikely that the joints in hollow section fabrications can carry as much as load as the members themselves, without expensive strengthening, which should be avoided.

Figure bellow defines the strength, stiffness and deformation capacity of a beam-to-column 3. Preliminary selection of the members. connection designed to transfer a moment from the beam into the column. M-φ curves in general

Joint resistance should be checked at the design stage, so that appropriate members can be

non-linear, for practical application, it is necessary to idealise the M-φ curves. The rotation

chosen to ensure that in addition to the members resisting the design load, the joints can also

capacity is a measure of the deformation that can be obtained before failure somewhere in the

transfer the member forces without strengthening.

connection causes a drop in the moment resistance.

Sabah Shawkat © For strength, the following classes can be distinguished:

nominally pinned MRd ≤ 0,25 Mpl.Rd 4. Determine the actual member forces. partial-strength 0,25 Mpl.Rd < MRd < Mpl.Rd MRd ≥ Mpl.Rd

full-strength

full-strength if rotation capacity is 5. Calculate the local resistance of not checkedjoints. MRd ≥ 1,2 Mpl.Rd where MRd

is the design moment resistance of the connection

Mpl.Rd

is the design strength of the beam (full plastic moment).

Column web in shear, compression and tension In practice it is often difficult to fabricate fixed connections and some rotation may take place

6. Calculate the deflection.

between the element on one side of the joint and that on the other. Such a joint is known as a semi-rigid connection and, strictly speaking is the condition of most joints which are described as being fixed or rigid. A moment connection could be described as one which although only semi-rigid approaches the behaviour of a fixed connection and transfers a substantial bending

7. Design the transverse support of the lattice and the purlin –to-lattice joints.

moment. Note that connections may be fabricated for particular requirements so that, for example, they may allow rotation in the plane of the elements but prevent twisting about the Realization of the ceiling of the hall from truss steel structures axis of the element thus allowing torsional moments to the be transmitted. This is a common

Moment-rotation characteristic of a semi-rigid joint with enough plastic rotation capacity For stiffness, the classification is as follows:

Connectionsininsteel steelstructures structures Connections Connections Connectionsininsteel steelstructures structures


181

N1Rd  N1sd

Y joint

Resistance of the joint:

A Y joint with a tension brace member

The resistance of the joint is thus N1Rd, which is > than the brace member axial force N1sd.

The joint geometry and loading are as follows: fy  355MPa  M0  1.1  Mj  1.1

Thus the brace member or the chord face have a sufficient resistance of the joint.

Brace member:

   48 deg

Chord member: 2

120x120x6

 A1  3364 mm

200x200x10

 b1  120 mm

 h1  120 mm

b0  200 mm

 t1  8 mm

N1sd  610 kN

tension

 h0  200 mm

t0  10 mm

 N0sd  1250kN



b0 h1

h0

 0.6



h1

 0.6

h0

The chord axial force N0sd influences the resistance of the joint in the form of the term kn: n 

 M0  Mj

compression

b1

b0

2

   35 deg 

b1

 A0  7257 mm

1.1

N 0sd

n  0.53372

A0 fy

N Rdchord  A1 



Ok

fy

 kn  1.3 

0.4 n

kn  0.94418

NRdchord  1085.655kN

 M0

Sabah Shawkat ©  0.6

Chord face yield:

 0.6

since β =0.6 less than 0.85 the chord face resistance must be checked: 2

N 1Rd 

fy t0

 2   4  1    k  1.1   n ( 1   ) sin(  )  sin(  )  Mj  M0 

N1Rd  424.85kN

The chord axial force N0sd influences the resistance of the joint in the form of the term kn:

n 

 M0  Mj

1.1

N 0sd

kn  1.3  n  0.53372 

A0 fy

N Rdchord  A1 

fy

N1Rd  NRdchord

0.4 n

Ok

kn  0.94418

NRdchord  1085.65455kN

N1Rd  N1sd

Does not

NRdchord  1085.655kN

 M0

In the case when we increase the angle between the brace member and the chord face then Chord face yield:

the resistance of the joint is thus N1Rd, which is remarkably less than the brace member

since β =0.6 less than 0.85 the chord face resistance must be checked:

axial force N1sd. A larger hollow section must be selected as the brace member or the chord face must be reinforced to obtain a sufficient resistance of the joint.

2

N 1Rd 

fy t0

 2   4  1    k  1.1  n ( 1   ) sin(  )  sin(  )  Mj  M0 

N1Rd  NRdchord



Ok

NRdchord  1085.65455kN

N1Rd  613.86kN N1sd  610kN

Connections in steel structures Connections in steel structures


182 132

Now we can calculate the chord resistance: condition at steel beam supports. Byweb contrast the element may be fixed in its plane to transmit

T joint in steel structures Connections A T joint with a compression brace member

bending but allow rotation about its axis. Note that if pinned or fixed joints are made between

Joints structural line elements, in one plane, may classified Thebetween joint geometry and loading are the following: fy be355 MPa as simple connections, as sliding as pin or pinned connections as fixed connections, also known as rigid Brace connections, member: Cord member:

an element and an immovable then that fb t0  2support h1  end 1.1of the element may not move translationally N1Rdchord  654.4kN N 1Rdchord    10 t0  or rotate in space, sin as (distinct from  )  sin (  ) a movement  M0 is merely relative to the member on the   Mjwhich

connections. A simple connection allows rotation and movement in any direction except 2 2  A1  3364 mm  A0  3364 mm 120x120x8 120x120x8 downwards and only transmits shear force that acts downwards at a support. A sliding compression  b1  120 mmmovement  h1along  120 N0sd and 480 kN and connection allows themm line of the element rotation only transmits shear

other side of the joint. Fixed joints, or nearly fixed joints, between two members are said to

compression  8 mm connection  M0  1.1  1.1but no N t1 A pinned force. allows Mj rotation translational movement, it transmits shear 1sd  380 kN

may rotate about a support for example. A way of characterising the degree of fixity or stiffness 2 10 b1 t0 beff  0.08m  0.12m beff member b1 beff by a semi-rigid connection provided either to ba 1support or another is to measure the b0 t1 rotation at the joint as the bending moment on the joint is varied. 1.1 Figure bellow definesthe capacity of a beam-to-column N1Rdbracebuckling fy strength, t1 2 h1 stiffness 4 t1  2 and beff deformation   M0  Mj connection designed to transfer a moment from the beam into the column. M-φ curves in general N1Rdbracebuckling  950.11kN non-linear, for practical application, it is necessary to idealise the M-φ curves. The rotation

and forces does allow  Eaxial  210 GPabut not bending moment. A fixed  120 mm  h0  not120 mm translational  t0  8 mm b0 connection movement or rotation and transmits shear, axial forces, bending and torsional moment. A1 fy   90deg N Rdbrace  1.1 b1   1   NRdbrace  1085.655kN b0 n 

 M0  Mj

1.1

N 0sd A0 fy

n  0.44213

provide continuity so that there is little or no rotation between the members at the joint and the Brace web buckling: members behave as joint existed. themember: joint is not necessarily fixed in space and Next, determine ifthenoeffective widthHowever, of the brace

capacity is a measure of the deformation that can be obtained before failure somewhere in the

Sabah Shawkat ©

 kn  1.3 

kn  1

0.4 n 

connection causes a drop Resistance of the joint:in the moment resistance. For The strength, the following classes can be the distinguished: chord web resistance determines resistance of the entire joint, which then is:

kn  1.12315

MRd ≤ 0,25 Mpl.Rd

nominally pinned

kn  1

governing failure mode (β = 0.85).

partial-strength 0,25 Mpl.Rd < MRd < Mpl.Rd N1Rdbracebuckling  950.10909kN N1sd  380kN NRdbrace  1085.655kN full-strength MRd ≥ Mpl.Rd N 1Rdbracebuckling full-strength capacity is N1sd Ok NRdbraceifrotation N1Rdbracebuckling  2.50029 N 1sd not checked MRd ≥ 1,2 Mpl.Rd N1Rdchord  654.4kN N1Rdchord  N0sd N0sd  480 kN OK where

Chord web buckling:

Mpl.Rd N0sd

Note that the term kn is not relevant in this example, since the chord face yield is not the

MRd N 1Rdchord is the design moment resistance of the connection  1.36333 is the design strength of the beam (full plastic moment).

The chord web buckling may be a relevant failure mode for the design, since β is 1.0. in using shear,buckling compression First, determine the Column bucklingweb stress curveand C: tension In practice it is often difficult to fabricate fixed connections and some rotation may take place fy  h0  1 C as a   the 3.46element   on 2  one side of the joint and that  0.58867  0.49 between on the other. Such a jointCurve is known  t0  E( sin(  ) )  semi-rigid connection and, strictly speaking is the condition of most joints which are described 2    fixed 0.5 1orrigid.  (  A moment 0.2)  connection   be 0.76849  as being could described as one which although only

 

1 semi-rigid approaches the behaviour of a fixed connection and transfers a substantial bending     0.79208 2 2 moment. Note may be fabricated for particular requirements so that, for   that  connections 

 

example, may allow rotation the plane of the elements but prevent twisting about the  fb  they fb in281.19 MPa  fy axis of the element thus allowing torsional moments to be transmitted. This is a common

When we changing the angle Θ from 90deg to 75deg,

90deg  1.2 then we obtain the 75deg

results as follow: 

 75deg

 kn  1.3 



0.4 n 

b1 b0

1

kn  1.12315

n 

kn  1

 M0  Mj

1.1

N 0sd A0 fy

n  0.44213

kn  1

in this example, theplastic chord rotation face yield is not the Note that the term kn is not relevant Moment-rotation characteristic of a semi-rigid joint withsince enough capacity governing failure mode (β = 0.85). For stiffness, the classification is as follows:

Connectionsininsteel steelstructures structures Connections Connections Connectionsininsteel steelstructures structures


183

Chord web buckling:

X joint

The chord web buckling may be a relevant failure mode for the design, since β is 1.0.

An X joint with compression brace members

First, determine the buckling stress using buckling curve C:

The joint geometry and loading are as follows: fy  355MPa

fy   h0 1   3.46   2    t0  E( sin(  ) ) 

2    0.5  1   (   0.2)     

1

 

2

 

 

2

 0.786

 0.59897

 0.49

 Mj

Curve C

Brace member:

Chord member:

180x180x8

200x200x10

 0.77713

fb   fy

fb  279.03MPa

 b1  180 mm  h1  180 mm

Now we can calculate the chord web resistance: fb t0  2 h1  1.1   10 t0  sin(  )  sin(  )   Mj  M0

N1Rdchord  690.07kN

 A1  5284 mm

t0  10 mm

 A0  7257 mm

fy

e  0 mm

1.1

N0sdchord  730kN

beff  0.08 m

b1  0.12m

N1Rdbracebuckling  fy t1 2 h1  4 t1  2 beff  

beff  b1

1.1  M0  Mj

 30deg



 0.9

b1

N1sdbrace  1320kN

b0

   0.5 

 0.9

b0

t0



h1 h0

 10

Chord face punching shear:

Resistance of the joint:

The chord face punching shear must be checked, since:

1   

The chord web resistance determines the resistance of the entire joint, which then is:

N1Rdbracebuckling  950.10909kN

N1sd  380kN

NRdbrace  N1Rdbracebuckling  N1sd Ok N1Rdchord  690.07kN

N0sd

Tension

kn  1

N1Rdbracebuckling  950.11kN

N 1Rdchord

2

Compression

Sabah Shawkat ©

2

b0 t1

 h0  200 mm

NRdbrace  1705.29kN

Next, determine the effective width of the brace member: 10 b1 t0

b0  200 mm 2

NRdbrace  A1 

Brace web buckling:

beff 

 1.1

 1.1  E  210 GPa

 t1  8 mm

N 1Rdchord 

 M0

 1.43765

N1Rdchord  N0sd

0.85    1  

NRdbrace  1085.655kN

N 1Rdbracebuckling N 1sd

bep 

 2.50029

N  0sd  480 kN

OK

10 t0 b1 b0

N 1Rdchordpunching 

 1   0.9   

1

bep  0.09m

b1  0.18m

bep  b1

 1.1  2 h1  b1  bep     M0  Mj 3 sin(  )  sin(  ) fy t0



N1Rdchordpunching  3689.26822kN

Connections in steel structures Connections in steel structures


184 132

Next check thebeam chord shear resistance: condition at steel supports. By contrast the element may be fixed in its plane to transmit

Chord face and chord web buckling: Connections in yield steel structures Joints structural line elements, in one mayface be classified simple Thebetween resistance of the joint is calculated for plane, the chord when β =as0.85 and connections, for the chord

bending but allow rotationfyabout Av its axis. 1.1 Note that if pinned or fixed joints are made between N1Rdchordshear  1513.65435kN N 1Rdchordshear   an element and an immovable then that end of the element may not move translationally  Mj  )  M0 3 sin(support

as sliding connections, as the pin resistance or pinned connections fixed connections, also known as rigid web when β =1. Then is determinedasby linear interpolation when β =0.9.

or rotate in space, as distinct from a movement which is merely relative to the member on the

connections.   0.85A simple connection allows rotation and movement in any direction except downwards and only transmits shear force that acts downwards at a support. A sliding 2 fy t0   1.1  2  N 1Rdjoint  movement along  the lineof4the  1element    knand connection allows rotation and only transmits shear ( 1   ) sin(  )  sin(  )  M0  Mj  force. A pinned connection allows rotation but no translational movement, it transmits shear N1Rdjoint  2215.7135kN NRdbrace  1705.29kN N1Rdjoint  NRdbrace and axial forces but not bending moment. A fixed connection does not allow translational

other side member of the joint. Fixed joints, or nearly fixed joints, between two members are said to Brace failure: provide so that there is little no rotation the members at the joint and the Alsocontinuity the effective width of the braceormember mustbetween be checked:

The chord resistance must be determined for both chord face and web, since 0.85    1

  1 or rotation and transmits shear, axial forces, bending and torsional moment. movement

 h0

 3.46 

 t0

 2 

fy 1  E( sin(  ) ) 

 

2    0.5  1   (   0.2)    

1



 1.15271

 1.39778

 0.49

Curve C

members behave as 2if no joint existed. However, the joint is not necessarily fixed in space and 10 b1 t0  beff 112.5mm b1ofcharacterising 180mm beff b1 of fixity or stiffness maybrotate for example. A way the  degree eff  about a support b0 t1 provided by a semi-rigid connection either to a support or another member is to measure the 1.1 rotation at the joint N1Rdbrace  fy as t1the  2 beff on  the joint isNvaried.  2 hbending 1Rdbrace  1427.74545kN 1  4 t1 moment  M0  Mj Figure bellow defines the strength, stiffness and deformation capacity of a beam-to-column N1sdbrace  1320kN connection designed to transfer a moment from the beam into the column. M-φ curves in general non-linear, for practical application, it is necessary to idealise the M-φ curves. The rotation

Resistance of joint:of the deformation that can be obtained before failure somewhere in the capacity is a measure

Sabah Shawkat © 

2

 2

 0.45696

The resistance the joint the smallest of the above values, that is: connection causes aofdrop in theismoment resistance.

 

fb   0.8 sin( ) fy

fb  64.89MPa

N 1Rdbrace For strength, the following classes can be distinguished: N1Rdbrace  N1sdbrace  1.08163 N1Rdchordpunching  3689.26822kN N nominally pinned MRd ≤ 0,25 Mpl.Rd 1sdbrace

partial-strength NRdbrace  1705.29kN

Now we can calculate the chord web resistance: N 1Rdchordweb 

fb t0  2 h1  1.1   10 t0  sin(  )  sin(  )   Mj  M0

N1Rdchordweb  967.42kN

Now determine the chord resistance by interpolation using the values calculated above:

N1Rdchord  N1Rdchordweb   NRdbrace  N1Rdchordweb  

( 1  0.9) 0.15

Column web in shear, compression and tension  N0sdchord N1Rdchord  1459.34kN N0sdchord 730kN N1Rdchord In practice it is often difficult to fabricate fixed connections and some rotation may take place Chord shear: between the element on one side of the joint and that on the other. Such a joint is known as a h0  sin(  ) h1 h0  1  of  most joints which are g   econnection    and, strictly   is the condition  0.03091 semi-rigid described 2 2  sin(  ) 2 sin(speaking ) 2 sin(  )  4 g as being fixed or rigid. A moment connection could be described 1as one which although only 2 3 t semi-rigid approaches the behaviour of a fixed connection and transfers 0a substantial bending 2 moment. be fabricated Av Note   connections b0 t0 Avmay  4061.82939 mmfor particular requirements so that, for  2 h0that

example, they may allow rotation in the plane of the elements but prevent twisting about the axis of the element thus allowing torsional moments to be transmitted. This is a common

0,25 Mpl.Rd< 2215.7135kN MRd < Mpl.Rd N1Rdjoint

N1sdbrace  1320kN

MRd ≥ Mpl.Rd N1Rdchordweb  967.42kN

full-strength N1Rdchordshear  1513.65435kN full-strength if rotation capacity is N1Rdbrace  1427.74545kN not checked

N1Rdchord  1459.34kN MRd ≥ 1,2 Mpl.Rd 45deg where  1.5 it means that we increase the Now we propose that the joint angle is 45deg 30deg MRd is the design moment resistance of the connection thenstrength the results willbeam be as(full follows. M angle aboutis1.5time the design of the plastic moment). pl.Rd

 45deg



b1 b0

 0.9



h1 h0

 0.9

   0.5 

b0

t0

 10

Chord face punching shear:

 1   

The chord face punching shear must be checked, since 0.85    1  

 1 1     0.9 characteristic of a semi-rigid joint with enough plastic rotation capacity Moment-rotation  

For stiffness, the classification is as follows:

Connectionsininsteel steelstructures structures Connections Connections Connectionsininsteel steelstructures structures


185

bep 

10 t0 b1

bep  0.09m

b0

b1  0.18m

Chord shear:

bep  b1

 

 1.1  2 h1  b1  bep   (  ) sin   M0  Mj 3 sin(  )  fy t0

N 1Rdchordpunching 

g   e 



h0  sin(  ) h1 h0    2  sin(  ) 2 sin(  ) 2 sin(  )

1



2

1

N1Rdchordpunching  2053.01751kN

4 g

 0.05127

2

3 t0

This increase of the angle joint cause the decrease of the value of N1Rdchordpunching about 0.55

Av   2 h0   b0 t0

2

Av  4102.5351mm

time or percent.

Chord face yield and chord web buckling:

Next check the chord shear resistance:

The chord resistance must be determined for both chord face and web, since

N 1Rdchordshear 

0.85    1

The resistance of the joint is calculated for the chord face when β = 0.85 and for the chord

fy Av 1.1  3 sin(  )  M0  Mj

N1Rdchordshear  1081.04144kN

Also the value N1Rchordshear will decrease about 0.71 percent

web when β=1. Then the resistance is determined by linear interpolation when β =0.9. 

 0.85

Sabah Shawkat © Brace member failure:

2

N 1Rdjoint 

fy t0

 2   4  1    k  1.1   n ( 1   ) sin(  )  sin(  )  M0  Mj 

N1Rdjoint  1245.91881kN

NRdbrace  1705.29kN

Also the effective width of the brace member must be checked:

N1Rdjoint  NRdbrace

the value of NRdbrace decrease about 0.73 time. 

 1

fy  h0  1  3.46   2    t0  E( sin(  ) ) 

 2

   0.5  1   (   0.2)    

1

 

2

 

 

10 b1 t0 b0 t1

beff  112.5mm

N1Rdbrace  fy t1 2 h1  4 t1  2 beff  

 0.96931

 1.15826 

2

fb   0.8 sin( ) fy

2

beff 

 0.49

Curve C

1.1

 M0  Mj

beff  b1

N1Rdbrace  1427.74545kN

N1sdbrace  1320kN

Resistance of joint:

 0.55794

The resistance of the joint is the smallest of the above values, that is:

fb  112.05MPa

N1Rdchordshear  N1sdbrace

N 1Rdchordshear

Now we can calculate the chord web resistance: fb t0  2 h1  1.1 N 1Rdchordweb    10 t0  sin(  )  sin(  )   Mj  M0

b1  180mm

N 1sdbrace

 0.81897

We see that the value N1Rdchordshear is < than the value N1sdbrace about 0.82, this it means

N1Rdchordweb  877.44kN

that the joint is not sufficient.

The value of N1Rdchord web will decrease about 0.90 time

Connections in steel structures Connections in steel structures


186 132

K joint in steel structures Connections

fixed in 0.25h its plane transmit condition atM0 steel supports. Byecontrast may0 bewhere  Mjbeam N 0sdchord e  0.25h 0.055m  0.015the m element 0  to n   bending but allow A0 fyabout its axis. Note that if pinned or fixed joints are made between 1.1 rotation

An K joint with compression and tension brace members A gapped Joint Joints betweenKstructural line elements, in one plane, may be classified as simple connections,

an element and an immovable supporteccentricity then that end of the element may not move translationally n  0.6461 is within the limits allowed

The joint geometry as andpin loading are as follows: as fixed connections, also known as rigid as sliding connections, or pinned connections

or rotate in space, as distinct from a movement which is merely relative to the member on the 0.4 n  k  1.3  other nside of the joint. Fixed joints, or nearly fixed joints, between two members are said to 

connections. simple connection in any direction except  fy  355A MPa  Mjrotation  1.1 and movement E  210 GPa M0  1.1 allows downwards and only transmits shear force that Chord acts downwards Brace member: member: at a support. A sliding connection allows movement along the line of the element and rotation and only transmits shear force. A pinned connection allows rotation but no 220x220x translational 160x160x8 10 movement, it transmits shear and axial forces but not bending moment. A fixed connection does not allow translational  b1  160 mm h1  160 mm b0  220 mm  h0  220 mm movement or rotation and transmits shear, axial forces, bending and torsional moment. 2 2  t1  8 mm  t0  10 mm A1  4644 mm  A0  8057 mm

 b2  160 mm  h2  160 mm

e  15 mm

N0sdchord  1680kN Compression

 t2  8 mm NRdbrace  A1 

fy

N1sdbrace  750kN

Compression

1.1

N2sdbrace  750kN

Tension

rotation at the joint as the bending moment on the joint is varied. Chord face yield: Figure bellow defines the strength, stiffness and deformation capacity of a beam-to-column First calculate the resistance by chord face yield: connection designed to transfer a moment from the beam into the column. M-φ curves in general i  1  2 non-linear, for practical application, it is necessary to idealise the M-φ curves. The rotation b 1  b1 h 1  h1 b 2  b1 h  h1 m  1 capacity is a measure of the deformation that2 can be obtained before failure somewhere in the m m  moment  connection causes a drop in the resistance.  bi  hi  For strength, the following2classes can be distinguished:  fy t0  i  1 1.1 i1 N1Rdchord  kn  M  pl.Rd  nominally pinned 8.9  MRd ≤ 0,25 2 m b0  M0  Mj sin(  )   partial-strength 0,25 Mpl.Rd < MRd < Mpl.Rd 2 fy t0  b1  hM 1 Rd ≥ Mpl.Rd 1.1 full-strength N 1Rdchordfaceyield  8.9    k n    (  )   M0  Mj sin 2  m b 0  full-strength if rotation capacity is 

Sabah Shawkat ©

NRdbrace  1498.75kN 1

provide continuity so that there is little or no rotation between the members at the joint and the kn  0.94464 members behave as if no joint existed. However, the joint is not necessarily fixed in space and Determine the resistance of the joint by brace member 1 only, since the brace members are may rotate about a support for example. A way of characterising the degree of fixity or stiffness of equal size and carrying equal loads. provided by a semi-rigid connection either to a support or another member is to measure the

 45deg  2  45deg

 45deg





b1 b0

h1 h0

 0.72727

 0.72727

not checked N1Rdchordfaceyield  925.55612kN

MRd ≥ 1,2 Mpl.Rd

where

The joint gap presented by the joint geometry is:

b0

Column web in shear, compression and tension   11    0.5  In practice it ist0often difficult to fabricate fixed connections and some rotation may take place h0 thatsin h1 is knownhas  2 Such a joint  and 2 a between the element on one joint on  the1 other.  1 side  of the  0.75  1  1    g   e     2 sin   sin  2  sin  2  sin  2            speaking is the condition 1 of most2 joints which1are described semi-rigid connection and, strictly

1  or rigid. A moment connection could be described as one which although only as beingfixed 1     0.90909    semi-rigid approaches the behaviourgof a23.72583 fixed connection and transfers a substantial bending mm So theNote chordthat punching shear may be fabricated for particular requirements so that, for moment. connections must be checked. example, they may allow rotation in the plane of the elements but prevent twisting about the axis of the element thus allowing torsional moments to be transmitted. This is a common

MRdChord shear: is the design moment resistance of the connection Mpl.Rd is the design strength the beam (full plastic moment). Obtain the following value for theofshear resistance of the entire chord: 

1

 1

2

4 g

 0.34289

2

3 t0

Av   2 h0   b0 t0 N 1Rdshear 

fy Av

1.1  3 sin(  )  Mj  M0

2

Av  5154.34828mm

N1Rdshear  1358.2kN

Moment-rotation characteristic of a semi-rigid joint with enough plastic rotation capacity For stiffness, the classification is as follows:

Connectionsininsteel steelstructures structures Connections Connections Connectionsininsteel steelstructures structures


187

Brace member failure:

Eccentricity is within the limits

The effective width of the brace member is:

Determine the resistance of the joint by brace member 1 only, since the brace members are of equal size and carrying equal loads.

2

beff 

10 b1 t0

beff  0.09091m

b0 t1

b1  0.16m

N1Rdbrace  fy t1 2 h1  4 t1  b1  beff  

1.1  Mj  M0

beff  b1 N1Rdbrace  1391.36529kN

Chord face yield: First calculate the resistance by chord face yield: i  1  2

Chord punching shear:

b 1  b1

h 1  h1

In this case the chord punching shear resistance must also be taken into account  bep  10 t0 

b1

bep  0.07273m

b0

b1  0.16m

bep  b1

h 2  h1

m   m  bi  hi  2  fy t0  i  1 i1 8.9    kn  sin(  )  2 m b0 

N1Rdchord

 1.1  2 h1  b1  bep   (  ) sin   M0  Mj 3 sin(  )  fy t0

N 1Rdchordpunching 

b 2  b1



m  1

1.1  M0  Mj

2

N1Rdchordpunching  1805.7404kN

 b1  h1  1.1   k n     M0  Mj sin(  )  2 m b0  fy t0

Sabah Shawkat © N 1Rdchordfaceyield  8.9 

N1Rdchordfaceyield  755.71341kN

Resistance of the joint:

The chord face yield determines the resistance of the joint, which then is:

The value N1Rdchordfaceyield decrease about (1-0.816 = 0.184 times)

N1Rdchordfaceyield  925.55612kN

Chord shear:

N1sdbrace  750kN

N1Rdchordfaceyield  N1sdbrace

Obtain the following value for the shear resistance of the entire chord:

Ok

Now we changing the angles from 45deg. to 60deg, then we watching the changing of value of the forces. 1

 60deg

2

 60deg

1

 60deg

The joint gap presented by the joint geometry is:

h0  sin  1   2 h1 h2  g   e     2  sin  1 sin  2 2 sin  1 2 sin  2 

e  0.015 m

e  0.25h0

where

0.25h0  0.055m

1



 0.20953

2

3 t0

Av   2 h0   b0 t0 g  40.41452 mm

2

4 g

N 1Rdshear 

2

 Av 4860.964mm

fy Av 1.1  3 sin(  )  Mj  M0

N1Rdshear  1045.84kN

The value N1Rdshear decrease about (1-0.769 = 0.231 times)

Connections in steel structures Connections in steel structures


188 132

Brace member Connections in steelfailure: structures

A gapped K joint condition at steel beam supports. By contrast the element may be fixed in its plane to transmit

The effective width of the brace member is:

bending but allow rotation its are axis. that iffy pinned fixedjoints The joint geometry andabout loading as Note follows:  355or MPa 1.1made  Mj between  1.1 M0 are

2 Joints between structural line elements, in one plane, may be classified as simple connections, 10 b1 t0 beffor pinned 0.09091m b1  as 0.16m beff  b1also known as rigid b  eff connections, as pin as sliding connections fixed connections, b0 t1 connections. A simple connection allows rotation and movement in any direction except 1.1 N1Rdbraceat a1391.36529kN N1Rdbraceand  only fy t1transmits 2 h1  4 t1shear  b1 force beff that  acts downwards downwards support. A sliding  Mj  M0 connection allows movement along the line of the element and rotation and only transmits shear The value N1Rdbrace remained without changing because no place for angles in the force. A pinned connection allows rotation but no translational movement, it transmits shear above. and formulae axial forces but not bending moment. A fixed connection does not allow translational

an element and an immovable support then that end Chord of the element not move8translationally Brace member: member:may200x200x 150x150x8 or rotate in space, as distinct from a movement which is merely relative to the member on the  b1  110 mm  h1  110 mm b0  200 mm  h0  200 mm other side of the joint. Fixed joints, or nearly fixed joints, between two members are said to 2 2 t1  continuity t0 between  6 mm so that  8 mmthe members  A1  is4324  A0 at the 5924 mm provide there littlemm or no rotation joint and the members as if no joint is not fixed in space and  b2  behave 110 mm  h2  existed. 110 mmHowever, theNjoint  necessarily 1230kN Tension 0sdchord

movement or rotation and transmits shear, axial forces, bending and torsional moment. Chord punching shear:

may rotate about a support for example. A way degree ofCompression fixity or stiffness 2 of characterising N1sdbrace  the 430kN  t2  6 mm  A2  2403 mm provided by a semi-rigid connection either to a support or another member is to measure the Tension N2sdbrace  430kN fy rotation at the joint NRdbrace A1 as  the bending moment on the joint is varied. 1.1the strength, stiffness and deformation  1  50deg  2  50deg   50deg Figure bellow defines capacity of a beam-to-column

In this case the chord punching shear resistance must also be taken into account

NRdbrace  1395.47kN connection designed to transfer a moment from the beam into the column. M-φ curves in general

 bep  10 t0 

b1 b0

bep  0.07273m

b1  0.16m

bep  b1

non-linear, for practical application, it is necessary to idealise the M-φ curves. The rotation The joint overlap expressed by the joint is as follows: capacity is a measure of the deformation thatgeometry can be obtained before failure somewhere in the

fy t0  1.1  2 h1   b1  bep     M0  Mj 3 sin(  )  sin(  )

connection causes in the moment resistance. e 0.55 h0 0.55h0  0.11 m  e  60 mm a drop

Sabah Shawkat ©

N 1Rdchordpunching 

N1Rdchordpunching  1295.71008kN

The value N1Rdchordpunching decrease about (1-0.717 = 0.283 times) Resistance of the joint:

The chord face yield determines the resistance of the joint, which then is:

N1Rdchordfaceyield  755.71341kN

N1sdbrace  750kN

N1Rdchordfaceyield  N1sdbrace

Ok

Column web in shear, compression and tension In practice it is often difficult to fabricate fixed connections and some rotation may take place between the element on one side of the joint and that on the other. Such a joint is known as a

For (joint strength, the following classes beallowed) distinguished: eccentricity is within the can limits

nominally pinnedh MhRd ≤ 0,25 Mpl.Rd h2   0  sin  1   2 1  q   e      q  76.46683 mm partial-strength 0,25 M pl.Rd < MRd < Mpl.Rd 2  sin  1 sin  2 2 sin  1 2 sin  2   full-strength MRd ≥ Mpl.Rd q sin  1 The relative value of the overlap λ is:  ov  0.53252 ov  full-strength if rotation capacity is ov  h1 not checked MRd ≥ 1,2 Mpl.Rd Brace member failure: Now 0.5   ov  0.8 so the following value is obtained for the where MRdeffective width: is the design moment resistance of the connection 2 Mpl.Rd 10 isb1the t0 design strength of the beam (full plastic moment). beff  b0 t1

beff  0.05867m beff  b1 b1  0.11m 2

semi-rigid connection and, strictly speaking is the condition of most joints which are described as being fixed or rigid. A moment connection could be described as one which although only semi-rigid approaches the behaviour of a fixed connection and transfers a substantial bending moment. Note that connections may be fabricated for particular requirements so that, for example, they may allow rotation in the plane of the elements but prevent twisting about the axis of the element thus allowing torsional moments to be transmitted. This is a common

beov 

10 b1 t2

beov  b1

b2 t1

beov  0.06m

N1Rdbrace  fy t1  2 h1  4 t1  beff  beov  

1.1  M0  Mj

N1Rdbrace  609.3kN

Resistance of the joint: The resistance of the joint is Resistance of thecharacteristic joint: Moment-rotation of a semi-rigid joint with enough plastic rotation capacity sufficient, since N1Rdbrace is > than N1sd. For stiffness, the classification is as follows:

Connectionsininsteel steelstructures structures Connections Connections Connectionsininsteel steelstructures structures


189

A lower corner joint in a lattice structure

A T or a Y joint

The resistance of the lattice´s lower corner can be determined using the formulae for

The joint geometry and loading are as follows:

 fy  355MPa

overlapped joints which consider the lower chord as continuous Figure below.

 M0

 1.1

 Mj

 1.1

E  210 GPa

The resistance of the joint can be determined for the lower corner with the following joint

Brace member:

Chord member:

members:

168.3x8

219.1x12

 fy  355MPa

 1.1

 M0

 1.1

 Mj

E  210 GPa

Brace member:

Chord member:

110x110x6

160x160x10

 b1  110 mm

 h1  110 mm 2

 t1  6 mm

 A1  2403 mm

N  Rd  A1  1

fy

NRd  775.51kN

1.1

 90deg

2

2

b0  160 mm

 h0  160 mm

t0  10 mm

 A0  5657 mm

N  Rd  A1  2

N0sdchord  1420kN

Tension

N1sdbrace  670kN

Compression

np

 47deg

 pEd

Npsd

b2  b0

The following overlap value is obtained:  

 q   e 

q sin  1 h1

 ov

i

 pEd

 M0   Mj

fz0

1.1

 90deg

N1sdbrace  560kN

Compression

Npsdchord  1320kN

Compression

 N psd



 A 0  fz0

M 0sd W el  fz0

  

is the chord compression stress due to force Npsd and bending moment M0sd

N0sd  N iSd cos  i

is the angle between the brace

M0sd is the bending moment of the chord

Now  ov  0.8 so the following value is obtained

fy0

is the yield resistance of

d0

is the diameter of the chord

d1

is the diameter of the brace

for the effective width is obtained: 2

beov  b1

1.1

member and the chord

 0.81623

Brace member failure:

beff  b1

 M0   Mj

member

The relative value of the overlap λov is: 

NRd  1300.27kN

Nisd is the axial force of the brace

q  89.78499 mm

 ov

fy 1.1

N0sd is the axial force of the chord

h1 h2 sin  1   2      2  sin  1 sin  2 2 sin  1 2 sin  2 

h0 

t0  12 mm

Sabah Shawkat ©

h2  h0 t2  t0

 e  0 mm

d0  219.1mm  A0  7807mm 

 t1  8 mm

The joint must be design in such a manner that eccentricity:

2

d1  168.3mm  A1  4029 mm

beov 

10 b1 t2 b2 t1

beov  0.11458m

the chord 1.1 N1Rdbrace  fy t1 2 h1  4 t1  beff  beov    M0  Mj

N1Rdbrace  814.4kN NRd  N1Rdbrace

NRd  775.51364kN N1Rdbrace  814.4kN

member

Connections in steel structures Connections in steel structures


190 132

Connections M0 in steel  Mj structures N psdchord np   fy A0 1.1

A X joint condition at steel beam supports. By contrast the element may be fixed in its plane to transmit

np  0.52391

bending but allow rotation about its axis. Note that if pinned or fixed joints are made between

Joints between structural line2elements, in one plane, may be classified as simple connections,  kp  1.0  0.3  np  np kp  0.76048 as sliding connections, as pin or pinned connections as fixed connections, also known as rigid d1 d0 connections. A simple connection allows rotation and movement any direction except  0.76814  in9.12917    d0 2 t0 downwards and only transmits shear force that acts downwards at a support. A sliding connection allows movement along the line of the element and rotation and only transmits shear force. A pinned connection allows rotation but no translational movement, it transmits shear Chord face yield: and The axialresistance forces but not joint bending moment. of the determined byAthefixed chordconnection face yield does is: not allow translational movement or rotation and transmits shear, axial forces, bending and torsional moment. 2

N 1Rdchordface 

fy t0

sin(  )

2 0.2  2.8  14.2    kp 

1.1  M0  Mj

N1Rdchordface  614.84kN

The joint geometry and loading arethen as follows: an element and an immovable support that end of the element may not move translationally or rotate space, from a movement to the member on the fy  in355 MPaas distinct  M0  1.1  Mj which  1.1 is merely E relative 210 GPa other side of the joint. Fixed joints, or nearly fixed joints, between two members are said to provide continuity between the members at the joint and the Chord member: Brace member:so that there is little or no rotation members behave as if no joint existed. However, the joint 193.7x12 is not necessarily fixed in space and 168.3x8 may rotate about a support for example. A way of characterising the degree of fixity or stiffness 2 2 d1  168.3mm  d0  193.7mm  A1  4029 mm  A  6850mm  provided by a semi-rigid connection either to a 0support or another member is to measure the  t1  at8the mmjoint as the bending moment on tthe 12 mm   90deg 0 joint rotation is varied. Figure bellow defines the strength, stiffness and deformation capacity of a beam-to-column Compression fy N1sdbrace  490kN N  Rd  A1  connection designed the beam into the column. curves in general 1.1 to transfer a moment from N Compression  1620 kN M-φ psdchord

non-linear, practical application, it is necessary to idealise the M-φ curves. The rotation NRd  for 1300.27kN capacity is a measure of the deformation that can be obtained before failure somewhere in the

Sabah Shawkat © connection causes a drop in the moment resistance.  M0  Mj  pEd  M0  Mj  N psd M0sd  For strength, the following classes can be np   distinguished:   fz0 1.1 1.1 z0 Rd ≤W el fz0Mpl.Rd  A0 fM nominally pinned 0,25

Chord punching shear:

partial-strength

The chord punching shear resistance is given by:

N1Rdchorpunching 

fy t0  d1  1  sin(  )  2 3  2  sin(  )

  1.1 N  1182.2kN    M0  Mj 1Rdchorpunching

Resistance of the joint: The resistance of the joint is the smallest of the above values: Column web in shear, compression and tension

N1Rdchordface  614.8404kN  N1sdbrace N1sdbrace 560kN In practice it is often difficult to fabricateNfixed connections and some rotation maytake place 1Rdchordface

MRd ≥ Mpl.Rd

full-strength if rotation capacity is  M0  Mj N psdchord np   not checked fy A0 1.1

MRd ≥ 1,2 Mpl.Rd

where np  0.73281 MRd is the design moment resistance of the connection

as being fixed or rigid. A moment connection could be described as one which although only

Mpl.Rd is the design strength of the beam (full plastic moment). 2  kp  1.0  0.3  np  np

kp  0.61906

between the element on one side of the joint and that on the other. Such a joint is known as a semi-rigid connection and, strictly speaking is the condition of most joints which are described

0,25 Mpl.Rd < MRd < Mpl.Rd

Npsd N0sd  N iSd cos  i full-strength



d1 d0

 0.86887

semi-rigid approaches the behaviour of a fixed connection and transfers a substantial bending moment. Note that connections may be fabricated for particular requirements so that, for example, they may allow rotation in the plane of the elements but prevent twisting about the axis of the element thus allowing torsional moments to be transmitted. This is a common

Moment-rotation characteristic of a semi-rigid joint with enough plastic rotation capacity For stiffness, the classification is as follows:

Connectionsininsteel steelstructures structures Connections Connections Connectionsininsteel steelstructures structures


191

Chord face yield:

An overlapped K joint

The resistance of the joint determined by the chord face yield is:

The joint geometry and loading are as follows:

 fy  355MPa 2

N 1Rdchordface 

fy t0  1.1 5.2    k p   M0  Mj sin(  )  1  0.81  

N1Rdchordface  505.04kN

 M0

 1.1

 Mj

Chord member:

193.7x12 5

Compression member 2

2

t1  6.3mm   1  45 deg

fy t0  d1  1  sin(  )  1.1 N1Rdchorpunching       2 3  2  sin(  )  M0 Mj

152x6 3

d1  152 mm  A1  2884mm

 t0  12.5 mm

The chord punching shear resistance is given by:

E  210 GPa

Brace member:

d0  193.7mm  A0  7116 mm 

Chord punching shear:

 1.1

N1Rdchorpunching  1182.2kN

  2  55 deg

N  1Sd  720 kN

Compression

 N 2Sd  610 kN

Tension

N  pSd  750 kN

Compression

N 1Rd  A1 

fy 1.1

N1Rd  930.75kN

Tension member

Sabah Shawkat © 127x6 3

2

 A2  2389mm

Resistance of the joint:

 np 

The resistance of the joint is the smallest of the above values

N1Rdchordface  505.03794kN

N1Rdchordface  N1sdbrace

N1sdbrace  490kN

1.1 N pSd  1 fy A0

np  0.32658

t2  6.3 mm N 2Rd  A2 

 kp  1.0  0.3  np  np

 d2  127 mm

fy

1.1

N2Rd  771kN

2

kp  0.87003

 d1  d2



 0.72019

2 d 0

 

 e1  35 mm



 

20 mm

 9.685

e1  0.25d0

0.25d0  0.04842m

q   e1 

d0

Ok

sin  1   2 d1 d2      2  sin  1 sin  2 2 sin  1 2 sin  2 

d0 

Connections in steel structures Connections in steel structures

q  39.17295 mm


192 132

Chord face Connections in yield: steel structures

An overlapped K joint condition at steel beam supports. By contrast the element may be fixed in its plane to transmit

The chord face yield resistance for the compression is given by:

The joint geometry andabout loading as Note follows: bending but allow rotation its are axis. that if pinned or fixed joints are made between

Joints between structural line elements, in one plane, may be classified as simple connections,

an element andMPa an immovable end1.1 of the element fy  355  M0support  1.1 thenthat E  may 210 not GPamove translationally Mj 

as sliding connections, as pin or1.2 pinned  connections as fixed connections, also known as rigid 0.024  0.2   kg  1.82901  kg   1  connections. A simple connection allows rotation and movement in any direction except   q

or rotate space, as distinct from a movement which is merely relative to the member on the Braceinmember: Chord member:

1.33

 2 t  0 shear downwards and only1 transmits  force that acts downwards at a support. A sliding e  

connection allows movement along the line of the element and rotation and only transmits shear 2 fy t0 1.1 force. A pinned connection allows movement, it transmits shear N 1Rdchordface  ( 1.8 rotation 10.2  )but kgno kp translational   M0  Mj sin  1 and axial forces but not bending moment. A fixed connection does not allow translational N1Rdchordface  1037.88kN movement or rotation and transmits shear, axial forces, bending and torsional moment. For the tension member, the corresponding resistance is:

 sin  1    sin  2 

N2Rd  895.92kN

N 2Rd  N 1Rdchordface 

other133x6 side of joints, between two members are said to 3 the joint. Fixed joints, or nearly fixed193.7x12 provide continuity so that there is little or no rotation between the members at the joint and the 2 2  d  133 mm  d0  193.7mm  A1  2508 mm  A  6850mm members behave as if no joint1 existed. However, the 0joint is not necessarily fixed in space and   6.3 mma support for example. A way of characterising t0  12 mm the degree of fixity or stiffness t1rotate may about provided by a semi-rigid connection either to a support todeg measure the fy  1 or33another deg member   2  is46 N1Rd  809.4kN N 1Rd  A1  rotation at the joint is varied. 1.1as the bending moment on the joint Compression N  720 kN 1Sd

Figure bellow defines the strength, stiffness and deformation capacity of a beam-to-column N2Sd  600.5kN Tension connection designed to transfer a moment from the beam into the column. M-φ curves in general Compression  800kN NpSd non-linear, for practical application, it is necessary to idealise the M-φ curves. The rotation

Chord punching shear:

N pSd of the deformation that can be obtained before failure somewhere in the capacity is1.1 a measure  np   1 fy Aa0drop in the moment resistance. connection causes

The chord punching shear resistance for the compression is given by:

For strength, the following classes can be distinguished: np  0.36188

N 1Rdchorpunching 

nominally pinned MRd ≤ 0,25 Mpl.Rd 2  kp  1.0  0.3  np  np partial-strength 0,25 Mpl.Rd < MRd < Mpl.Rd kp  0.85215 full-strength MRd ≥ Mpl.Rd

Sabah Shawkat © fy t0  d1  1  sin  1    1.1   2  sin  1 2   M0  Mj 3



N1Rdchorpunching  1898.63kN

For the tension member, the corresponding resistance is:

fy t0  d2  1  sin  2    1.1 N 2Rdchorpunching    2  sin  2 2   M0  Mj 3



N2Rdchorpunching  1259.65kN Column web in shear, compression and tension In practice it is often difficult to fabricate fixed connections and some rotation may take place Resistance of the on joint: between the element one side of the joint and that on the other. Such a joint is known as a The resistance of the joint is thespeaking smallestisofthe thecondition above values: semi-rigid connection and, strictly of most joints which are described Compression as being fixed or member: rigid. A moment connection could be described as one which although only

N1Rdchordface  1037.88247kN  N1Sd N1Sd asubstantial 720kN bending 1Rdchordface semi-rigid approaches the behaviour of aNfixed connection and transfers moment. Note that connections may be fabricated for particular requirements so that, for Tension member: example, may allow rotation in the N plane of Nthe  895.91882kN N2Sd twisting 610kNabout the N2Rd they 2Rd  2Sdelements but prevent axis of the element thus allowing torsional moments to be transmitted. This is a common

full-strength  d1if rotation capacity is   0.68663   not checkedd0 where

MRd ≥ 1,2 Mpl.Rd

d0  9.685 is the design moment resistance of the connection 20 mm M is the design strength the beam (full plastic moment). pl.Rd  e1  40.0mm e1  0.55dof 0 

MRd



0.55d0  0.10654m

 

q   e1 

Ok

sin  1   2 d1 d0      2  sin  1 sin  2 2 sin  1 2 sin  2 

d0 

q  114.29583 mm

Moment-rotation characteristic of a semi-rigid joint with enough plastic rotation capacity For stiffness, the classification is as follows:

Connectionsininsteel steelstructures structures Connections Connections Connectionsininsteel steelstructures structures


193

Chord face yield: The chord face yield resistance for the compression is given by:

 kg  

0.2

0.024 

1 

  

 

1.2

kg  2.14992

 q 1.33   2 t   0 

1 e

2

N 1Rdchordface 

fy t0

sin  1

( 1.8  10.2  ) kg kp 

1.1  M0  Mj

N1Rdchordface  1376.22kN For the tension member, the corresponding resistance is:

 sin  1    sin  2 

N2Rd  1041.99kN

N 2Rd  N 1Rdchordface 

Sabah Shawkat ©

Chord punching shear:

The chord punching shear resistance for the compression is given by: N 1Rdchorpunching 

fy t0  d1  1  sin  1    1.1   2  sin  1 2   M0  Mj 3



N1Rdchorpunching  2432.41kN

For the tension member, the corresponding resistance is: N 2Rdchorpunching 

fy t0  d0  1  sin  2   2  sin  2 2 3

 1.1    M0  Mj 

N2Rdchorpunching  2260.47kN Resistance of the joint: The resistance of the joint expressed by the brace member is: Compression member:

N1Rdchordface  1376.21874kN N1Rdchordface  N1Sd

N1Sd  720kN

Tension member:

N2Rd  1041.98662kN

N2Rd  N2Sd

N2Sd  600.5kN

Connections in steel structures Connections in steel structures


Sabah Shawkat © Fire design / protection Unprotected steel structure Steelwork insulated by fire protection material Calculate the resistance of column in a fire situation Hollow section exposed to fire on three sides Hollow section exposed to fire on two opposite sides Hollow section exposed to fire on two adjacent sides


Sabah Shawkat ©


196 196

Fire design / protection Fire design / protection

strength modulus of elasticity decrease at elevated temperatures. Moreover, whole TheThe strength andand modulus of elasticity decrease at elevated temperatures. Moreover, thethe whole steel cross-section heats during fire. Normally steel structures have protected steel cross-section heats up up during fire. Normally thethe steel structures have to to be be protected

structural engineer is not specifically involved in the design active protection, or in TheThe structural engineer is not specifically involved in the design forfor active firefire protection, or in layouts compartment sizes escape routes. These aspects under guidance thethe layouts forfor firefire compartment sizes andand escape routes. These aspects fallfall under thethe guidance of the architect integral of building design. A structural engineer must aware of the architect andand areare an an integral partpart of building design. A structural engineer must be be aware

against fire, demonstrated calculations structures capable against fire, or or hashas to to be be demonstrated by by calculations thatthat thethe structures areare capable of of withstanding in an unprotected state required time. withstanding firefire in an unprotected state forfor thethe required time. stress-strain relationship elevated temperature presented figure above. Three TheThe stress-strain relationship at at elevated temperature is is presented in in figure above. Three

of what is intended in this respect however, as fire safety design requires integrated approach of what is intended in this respect however, as fire safety design requires an an integrated approach

reduction factors relative to the yield strength have been defined steel. factor . The The reduction factors relative to the yield strength have been defined forfor steel. TheThe factor kp,k.p,

members of the design team. by by all all members of the design team.

effective yield strength corresponds strain modified reduction factor effective yield strength corresponds to to thethe strain y,The modified reduction factor y,The

required level of fire performance structures is typically given in terms a reaction TheThe required level of fire performance forfor structures is typically given in terms of aofreaction to to

used in calculations where deformation of the appropriate structure to be taken k,kis used in calculations where thethe deformation of the appropriate structure hashas to be taken ,is

classification a fire resistance rating, as given in the Building Regulations. firefire classification andand a fire resistance rating, as given in the Building Regulations.

account. modulus of elasticity in fire condition is obtained using factor intointo account. TheThe modulus of elasticity in fire condition is obtained using factor kE,kE,

Fire resistance is typically presented a duration time. resistance element Fire resistance is typically presented as as a duration of of time. TheThe firefire resistance of of an an element (wall, floor roof) a measure ability withstand effects more (wall, floor or or roof) is aismeasure of of its its ability to to withstand thethe effects of of firefire in in oneone or or more

situations, temperature steel increases together with temperature In In firefire situations, thethe temperature of of thethe steel increases together with thethe temperature of of thethe

ways as follows: ways as follows:

gases in fire component. temperature of the steel increases, strength deformation gases in fire component. AsAs thethe temperature of the steel increases, its its strength andand deformation properties transformed. According their structures have different resistance properties areare transformed. According to to their use,use, structures have different firefire resistance

Structural ‘loadbearing capacity’ to maintain design loads under 1. 1.Structural ‘loadbearing capacity’ to maintain thethe design loads under firefire (R)(R)

requirement (e.g. requirements bearing capacity compartment). requirement (e.g. requirements forfor bearing capacity andand compartment).

Sabah Shawkat ©

Integrity’ of the element which is the resistance to fire penetration 2. 2.Integrity’ of the element which is the resistance to fire penetration (E)(E)

In the situations, temperature of the steel members increases slower than of the In the firefire situations, thethe temperature of the steel members increases slower than thatthat of the firefire

Insulation’ which is the resistance transfer heat face element 3. 3.Insulation’ which is the resistance to to thethe transfer of of heat to to thethe face of of thethe element

compartment. development distribution steel temperature depends shape compartment. TheThe development andand distribution of of steel temperature depends on on thethe shape of of

remote metal components such as nails, screws bolts remote forfor thethe firefire (I) (I) metal components such as nails, screws andand bolts

steel member thermal properties. It is always necessary calculate steel thethe steel member andand its its thermal properties. It is always necessary to to calculate thethe steel

temperature increases, strength modulus of elasticity of the steel changes. AsAs thethe temperature increases, thethe strength andand thethe modulus of elasticity of the steel changes.

temperature required resistance period, since a steel member may reach temperature up up to to thethe required firefire resistance period, since a steel member may reach its its

o o However, room temperature values yield strength used to 400 yield C. C. TheThe yield However, thethe room temperature values forfor yield strength cancan be be used up up to 400

maximum temperature during a point where compartment temperature starts maximum temperature during firefire at at a point where thethe firefire compartment temperature starts

strength corresponds a total elongation modulus elasticity is constant strength corresponds to to a total elongation of of 2%.2%. TheThe modulus of of elasticity is constant up up to to

decreasing according parametric model. using a fire retardant material, decreasing according to to thethe parametric firefire model. ByBy using a fire retardant material, thethe

o o 100100 C. C.

evolution of steel temperature slowed down, which lengthens resistance period. evolution of steel temperature cancan be be slowed down, which lengthens thethe firefire resistance period. Often it is necessary protect steel components order slow down increase Often it is necessary to to protect steel components in in order to to slow down thethe increase in in temperature during fire. temperature during fire. Several retardant methods applicable with allow sections Structural steelwork Several firefire retardant methods areare applicable forfor useuse with allow sections Structural steelwork must either protected or designed in such a way as avoid to avoid premature failure of the structure must either be be protected or designed in such a way as to premature failure of the structure when exposed to fire. when exposed to fire. Fire protection may given to structural steelwork members Fire protection may be be given to structural steelwork members by by thethe useuse of:of: a) Intumescent paints a) Intumescent paints b) Mineral boards b) Mineral boards c) Concrete encasement. c) Concrete encasement.

Stress-strain relationship at elevated temperatures Stress-strain relationship at elevated temperatures

Firedesign design Fire Fire Firedesign design


197

For the engineers, there is a responsibility to specify materials, and to provide details that: a.

reduce the potential for fire ignition

b. limit the spread of fire c.

stop the passage of hot gases and smoke

An appropriately designed building will allow people remote from the seat of a fire to escape

Fire design can be based on either the standard time – temperature curve common to all fire situation or on parametric temperature-time curve. An alternative method for calculating the evolution of temperature in fire compartment is the parametric model presented in Euro-code 1, section 2.2. This model also accounts for openings in the fire compartment, the thermal properties of the wall materials and the magnitude of the

and provide a building from which the fire service can deal with the fire safely and effectively.

fire load in determining the development of the temperature. The parametric model can be used

Structural fire safety is achieved either by what is called ‘passive protection’ e.g. fire resistant

if the fire compartment area is less than 100 m2, there are no openings in the fire compartment

lining boards and/or ‘active protection’ e.g. smoke ventilation, alarm systems and sprinklers.

ceiling, and the height of the fire compartment does not exceed 4m. The temperature of the fire

For the structural engineer, the material choice within the structural solution will influence the

compartment increases as long as there is flammable material. Finally, the temperature reaches

passive and active fire protection strategy.

a maximum value of max after which the fire compartment temperature starts decreasing.

Steel structures can be protected against fire by insulating them or increasing their heat retention capacity. Structural solutions can also be used to increase the fire resistance period. In addition to the cost of materials, installation and maintenance costs should be considered when selecting the fire retardant method

Sabah Shawkat ©

Fire retardation by (mineral wool boards, vermiculite boards, calcium silicate boards, plaster

board and profiled elements, wood fibre plaster boards, cement cellulose boards, sprayed

boards, sprayed vermiculite, fire retardant paints, concrete infill of hollow section, water infill of hollow sections, placing columns outside the fire compartment, placing columns outside the wall).

There are two broad standards for the design methods of fire resistance of buildings: prescriptive and performance-based.

Temperature-time curve in standard and parametric fire models

A prescriptive method defines a structural fire design fairly precisely in terms of the materials used, shape and size of structural elements, thickness of fire protection materials and construction details etc.

The heat retention capacity of hollow sections can be improved for instance with concrete infill.

Traditionally, the design recommendations are mainly based on the experience with identical

Hollow sections are efficient in fire design, since their section factor (the ratio of fire-exposed

or similar standard fire tests. This concept works very well in a static situation but inhibits

area to unit mass) is smaller than that of open sections. In addition, hollow sections with their

innovation and development of construction industry. It can become very restrictive in

rounded corners are well-suited for fire –retardant painting.

situations where designs need to evolve to meet architectural or aesthetic requirements. For

Unfortunately, a fire heated structural element in a building does not behave in an isolation

these reasons, the prescriptive designs have been evolving for many years towards the

manner. The continuity and interaction of the heated elements to the rest of the building

performance-based designs.

inevitably cause additional thermal stresses. Their softening due to elevated temperatures will

Factors affecting the development of a real fire include the mode of combustion, the shape of

reduce their stiffness and lead to load redistribution.

fire compartment, the magnitude and type of fire load, the supply of air needed for combustion and the fire extinguishing system. However, the models used in practical design are simpler.

Fire design Fire design


198 196

Fire design / protection Unprotected steel structure The increase of temperature in an unprotected steel structure is calculated as follows: Am The structural engineer is not specifically involved in the design for active fire protection, or in V compartment sizes and escape routes. These aspects fall under the guidance the layouts for fire

 al hneta t c  a of the architectaand are an integral part of building design. A structural engineer must be aware

of what is intended in this respect however, as fire safety design requires an integrated approach A by all m members of the design team. is the section factor for unprotected steel members (m-1), but not less than 10 m-1 V The required level of fire performance for structures is typically given in terms of a reaction to fire classification and a fire resistance rating, as member given in per the unit Building Regulations. is the exposed surface area of the length m2/ m Am Fire resistance is typically presented as a duration of time. The fire resistance of an element 3/m) the volume of the of member per unit length (mthe V floor or isroof) (wall, is a measure its ability to withstand effects of fire in one or more wayscdas follows: is the specific heat of steel (J/kg K) is the design value of the net flux per unit area (W/under m2) fire (R) hnetdStructural 1. ‘loadbearing capacity’ to heat maintain the design loads

The strength and modulus of elasticity decrease at elevated temperatures. Moreover, the whole is theheats ambient gas temperature of the steel member (oC) have to be protected g steel cross-section up during fire. Normally the steel structures against fire, or has to be demonstrated by calculations that the structures are capable of is the surface temperature of the steel member (oC) m withstanding fire in an unprotected state for the required time. The stress-strain relationship at elevated temperature is presented in figure above. Three The radiative net heat flux reduction factors relative to the yield strength have been defined for steel. The factor kp,. The 8 hnetr yield 273the   res 5.67 10   4 strain   m y,273  4   r  to effective strength corresponds The modified reduction factor k,is used in calculations where the deformation of the appropriate structure has to be taken is the configuration factor, 1 into account. The modulus of elasticity in fire conditionisobtained using factor kE, is the resultant emissivity,  res  0.50  res In fire situations, the temperature of the steel increases together with the temperature of the temperature of the environment of the and member (oC),  rin fire component.is gases Asthe theradiation temperature of the steel increases, its strength deformation whichAccording may be represented by the gas temperature θ g fire resistance properties are transformed. to their use, structures have different requirement (e.g. requirements for bearing capacity and compartment). the surfaceof temperature of the member (oC)  mfire situations, the is In the temperature the steel members increases slower than that of the fire

Sabah Shawkat ©

2. Integrity’ of the element which is the resistance to fire penetration (E) t is the time interval (s), but not more than 5 s 3. Insulation’ which is the resistance to the transfer of heat to the face of the element

kgas nails, screws and bolts remoteisforthe theunit firemass (I) metal components such ,  a of steel a 7850  3 As the temperature increases, the strength and the modulus of elasticity of the steel changes. m

compartment. The development and distribution of steel temperature depends on the shape of 8 2 K4) Stefanproperties. Boltzmann Itconstant (W/m 67 member 10 the 5steel and is itsthe thermal is always necessary to calculate the steel

The design value oftothe met heat flux of 2%. The modulus of elasticity is constant up to strength corresponds a total elongation

temperature to theJ/kg required resistance a steel The value up Ca=600 K mayfire be taken as theperiod, specificsince heat value of member steel, or itmay mayreach be its maximum temperature during fire at a point where the fire compartment temperature starts calculated more accurately as follows: decreasing according to the parametric fire model. By using a fire retardant material, the

100ohC. netd

3 2 down, which 6 3 o resistance period. o evolution temperature can10 be slowed the for 20 Ca of 425steel  0.773  a  1.69  a  2.22 10  alengthens Cfire   a  600 C

However, the room temperature values for yield strength can be used up to 400oC. The yield  nc hnetc

  nr hnetr

 nc

is the factor to account for different national types of test

hnetc

is the net heat flux due to convection (W/m2)

 nr

is a factor to account for different national types of test,

Often it is necessary to protect steel components in order to slow down the increase in 13002 o o for 600 C   a  735 C Ca 666  fire. temperature during 738   a Several fire retardant methods are applicable for use with allow sections Structural steelwork 17820or designed in such a wayoas to avoid premature o mustCeither545 be protected failure of the structure for 735 C   a  900 C  a  a  731 when exposed to fire.

knetr

is the net heat flux due to radiation (W/m3)

for Ca 650 900 C   a  1200 C Fire protection may be given to structural steelwork members by the use of:

o

a) Intumescent paints Where θ a is the steel temperature b) Mineral boards

The convective net heat flux hnetc c

 c  g

  m

c) Concrete encasement.

W

is the coefficient of heat transfer by convection   c  25  2 Stress-strain relationship at elevated temperatures m K fire

in standard

Firedesign design Fire Fire Firedesign design

o


199

Steelwork insulated by fire protection material The temperature increase in an insulated steel member is calculated as follows. p

Ap  gt   at  10   at   t   e  1    gt Ca  a V  1 3 Ap cp  p  dp  ca  a V dp

Ap V

but

  at

 0

is the section factor for steel members insulated by fire protection material (m-1)

is the inner surface area of the fire protection material per unit length of the member Ap (m2/m)

Sabah Shawkat ©

V

is the volume of the member per unit length (m3/m)

ca

is the specific heat of steel (J/kg K), 600J/kg K

cp

is the specific heat of the fire protection material (J/kg K) 1000J/kg K

dp

is the thickness of the fire protection material (m)

t

is the time interval (s), but not more than 30 s

 at

is the steel temperature (oC)

 gt

is the ambient gas temperature (oC)

 gt

is the increase of the ambient gas temperature (oC) during the time interval Δ t

p

is the thermal conductivity of the fire protection material (W/m K) 0,25W/m K

a

is the unit mass of steel (kg/m3) 7850 kg/m3

p

is the unit mass of the fire protection material (kg/m3) 140kg/m3

State of construction after fire

Fire design Fire design


200 196

The moisture in fire protection material delays the rise of the steel temperature until the moisture Fire design / protection

development of theoftemperature for bothatthe unprotected and the fire-protected TheThe strength and modulus elasticity decrease elevated temperatures. Moreover, theprofile whole as

evaporates. During the time delay, it can be assumed that the steel temperature stays at 100oC,

well as for the fire compartment one hour in fire is presented following steel cross-section heats up duringduring fire. Normally thestandard steel structures have to in bethe protected

the engineer moistureisinnot thespecifically fire protection material getsdesign out through the fire surface oppositeortointhe Thebecause structural involved in the for active protection,

figure.fire, Theortemperature thecalculations unprotected that profile calculatedare from the formula against has to be development demonstratedofby theisstructures capable of

The for delay can be calculated the routes. following formula: thefire. layouts firetime compartment sizes andfrom escape These aspects fall under the guidance

withstanding fire in state for the required time. Δ θ at. of an theunprotected fire-protected profile from the formula Δ θ at and that

of the architect and2are an integral part of building design. A structural engineer must be aware pp  p dp of what tv is intended in this respect however, as fire safety design requires an integrated approach 5  p by all members of the design team.

effective yield strength corresponds to the strain y,The modified reduction factor

The stress-strain relationship at elevated temperature is presented in figure above. Three reduction factors relative to the yield strength have been defined for steel. The factor kp,. The

The required level of fire performance for structures is typically given in terms of a reaction to pp is theand moisture of rating, the fireasprotection material as a Regulations. percentage by weight. firewhere classification a fire content resistance given in the Building

k,is used in calculations where the deformation of the appropriate structure has to be taken

After the delay time, the presented steel temperature is assumed to develop theanformula Fire resistance is typically as a duration of time. The fireaccording resistancetoof element

In The fire following situations, values the temperature steel increases together with the temperature of the are used inofthethe calculation:

(wall, floor or roof) is a measure of its ability to withstand the effects of fire in one or more p

ways as follows: dp

Ap  gt   at  10   at   t   e  1    gt Ca  a V  1 3 1. Structural ‘loadbearing capacity’ to maintain the design loads under fire (R)

into account. The modulus of elasticity in fire condition is obtained using factor kE,

gases in fire component. As the temperature of the steel increases, its strength and deformation kN kN fy have 355 different MPa  Gk  45 Q   40  to their L use, 6 mstructures properties are transformed. fire resistance k1According m m requirement (e.g. requirements for bearing capacity and compartment).  GA 1  the 1.35 ofQthe  steel 1.5 members  Mfi  1  M1  1.1 than that of the fire G  In the firesituations, temperature increases slower

Sabah Shawkat ©

2. Integrity’ of the element which is the resistance to fire penetration (E)

3. Insulation’ which is the resistance to the transfer of heat to the face of the element remote for the fire (I) metal components such as nails, screws and bolts

compartment. The development and distribution of steel temperature depends on the shape of  tf  20 mm bf  250 mm tw  10 mm  the steel member and its thermal properties. It is always necessary to calculate the steel

As the temperature increases, the strength and the modulus of elasticity of the steel changes.

tf hsince m member may reach its  h  800up mm H required  800 mm temperature to the fire hresistance a steel w  h  2period, w  0.76

However, the room temperature values for yield strength can be used up to 400oC. The yield

maximum temperature during fire at a point where the fire compartment temperature starts Am  2.33 m Am  3 bf  4 tf  2 hw  2 tw decreasing according to the parametric fire model. By using a fire retardant material, the

strength corresponds to a total elongation of 2%. The modulus of elasticity is constant up to 100oC.

2 evolution temperature can be slowedVdown, which V  2ofbsteel   0.0176 m lengthens the fire resistance period. f tf  hw tw Often it is necessary to protect steel components in order to slow down the increase in

Schematic picture of the influence of the moisture content in the fire protection material on the steel temperature development.

temperature during fire. Several fire retardant methods are applicable for use with allow sections Structural steelwork must either be protected or designed in such a way as to avoid premature failure of the structure when exposed to fire.

Calculate the bending and shear resistances of the WI800-10-20x250 profile for the fire situation, when the required resistance to fire is 60 minutes. Lateral-torsional buckling of the

Fire protection may be given to structural steelwork members by the use of:

profile is prevented. The cross-section is loaded by the permanent load gk and by the variable

a) Intumescent paints

load qk .and the span length is L. The cross-section is protected with mineral fibre batts and it

b) Mineral boards c) Concrete encasement.

is exposed to fire on three sides according to the figure shown below. The steel grade is S355J2G3.

Stress-strain relationship at elevated temperatures

The temperature – time curve according to the ISO 834 standard

Firedesign design Fire Fire Firedesign design


201

Am V

 132.38636m

1

 ca  700 

J

  c  25 

kg K

W 2

m K

  a  7850 

kg m

3

700 oC according to the figure shown below. The following values for the reduction factors are obtained: ky   0.230

 1.0

 res

  p  0.25 

W

 0.50

t

  p  140 

m K

cp  1000   5 s 

kg m

3

 nc

 1

 nr

J kg K

kx  0.167

kE  0.130

 dp  0.020 m

 1

Next the cross-section classification is verified:



235 MPa kE fy kx

 0.71785

hw tw

 76

hw tw

 124 

section class 3

Sabah Shawkat ©

124   89.0133

Reduction factors for steel strength and modulus of elasticity at elevated temperature

The values of the adaptation factors for the resistance calculation are taken as k1  0.7

and

 a  4 mm

fyd 

fyf

bw

After one hour of fire, the temperature of the unprotected profile is 939 oC and that of the fire-

tw

 5.71716

 74.86863

protected one is 600. The reduction factors of the strength and the modulus of elasticity in the fire-protected cross-section are obtained using the value corresponding to the temperatures of

Fire design Fire design

 1.1

fyf  355 MPa

fyd  322.72727 MPa

c

throat thickness of the neck weld

 bw  H  2  tf  Flange

tf Web

k2  1.0

2 a

bw  0.74869 m

Compression

Bending

c 

 bf

 tw 2

hw  H  2 tf

 c  7.3 t  f  bw tw

 67.5

 2 a

c  0.11434m hw  0.76 m

Class 1

Class 2


202 196

0.00005 at Moreover, the whole The strength and modulus of elasticitydecrease  0.005  166666.66666667   elevated temperatures.

The entire/ protection flange is effective. Calculate the effective width of the web Fire design

235 k  23.9     0.81362 The structural engineer is not355 specifically involved in the design for active fire protection, or in the layouts for fire compartment sizes and escape routes. These aspects fall under the guidance bw

of the architect and design. A structural engineer must be aware tw are an integral part of building p  0.22    p  of what is intended in this respect however, as fire safety design requires an integrated approach 2 28.4   k p by all members of the design team.   p  0.663 The required level of fire performance for1.00798 structures is typically given in terms of a reaction to fire classification and a fire resistance rating, as given in the Building Regulations.

  0.6 beff‘loadbearing be2  0.22982 m to maintain the design loads under fire (R) be2 Structural 1. capacity’ The depth of the ineffective region: 2. Integrity’ of the element which is the resistance to fire penetration (E)

withstanding fire in an for the required time.  166666.66666667   0.005  unprotected state  0.00395  The stress-strain relationship at elevated temperature is presented in figure above. Three The depth of the tension side: reduction factors relative to the yield strength have been defined for steel. The factor kp,. The

effective yield corresponds to the strain y,The modified reduction factor  Rstrength i

where the deformation of the appropriate structure has to be taken k,is used  iin calculations  et  0.40039 m et    A into account. Theimodulus of elasticity in fire condition is obtained using factor kE,

 

Fire resistance is typically presented as a duration fire resistance of cross-section: an element The compression region and the tension region ofofthetime. webThe are equal in the gross (wall, floor or roof) is a measure of its ability to withstand the effects of fire in one or more hw waysbeff as follows:    beff  0.38303 m be1  0.4 beff be1  0.15321 m 2

steel cross-section fire. Normally structures have to be protected  0.0061 heats  m 2 up during  0.00198  m 3the steel  188983208.01320994  mm4 Ai  Ri  Ii        of 0.00153 0.00108 2997140.04875064 against fire, or has to be demonstrated by calculations that the structures are capable

 i

 

The depth of the compression side: In fire situations, the temperature of the steel increases together with the temperature of the gases component. As the temperature ecin fire  H et ec  0.39961ofmthe steel increases, its strength and deformation The centroid axis shifts down by properties are transformed. According to their use, structures have different fire resistance requirement (e.g. requirements for bearing capacity and compartment). H eM  0.00039 m eM   et In  the fire situations, the temperature of the steel members increases slower than that of the fire 2 The effective second moment and of area about theofnew centroid axis: depends on the shape of compartment. The development distribution steel temperature

Sabah Shawkat ©

3. Insulation’ hw which is the resistance to the transfer of heat to the face of the element2 bneg   be1  be2 bneg  0.00303 m Aw  tw  H  2 tf  Aw  0.0076m remote2 for the fire (I) metal components such as nails, screws and bolts As the temperature increases, the strength and the modulus of elasticity of the steel changes. 2 2 A  A  2 Af  Aw Af  0.005 m A  0.0176 m f  tf bf However, the room temperature values for yield strength can be used up to 400oC. The yield strength to a total elongation of 2%. The modulus of elasticity is constant up to i  1corresponds  4 100oC.  b 1  250 mm h 2 

H 2

tf 2

z1  0.01 m

 Ai 

10 mm

b 3  10 mm

 be2  h 1 h 2 609.82 mm

h 4  tf

z1 

 b2 

b i h i

h 1  tf

b 4  250 mm

h 3  be1  h 3 153.213 mm

h2 2

 z3  H  tf 

z2  0.32491 m

R i  A i zi

h3

 z4  H 

2

z3  0.70339 m

 Ii 

1 12

b i  h i 

its thermal properties. It is always necessary to calculate the steel 4 Ai  zi 2  et2  Ai  Ieffy  0.00188872m required fire resistance period, since a steel member may reach its  

  i

i

 i

maximum temperature during fire at a point where the fire compartment temperature starts decreasing according to the parametric fire model. By using a fire retardant material, the If the yield strength of the web were 355 MPa, the moment resistance would be evolution of steel temperature can be slowed down, which lengthens the fire resistance period. Often it is necessary Ieffy to protect steel components in order to slow down the increase in MRD  1525.35521 m kN M  RD  fyd  temperature duringecfire.

The value of MRd ismethods obtainedare forapplicable the bending to theStructural theory of steelwork elasticity at Several fire retardant forresistance use with according allow sections theeither normal must be temperature. protected or designed in such a way as to avoid premature failure of the structure

h 4  0.02 m

 z2  tf 

the steel member and Ieffy  Ii  temperature up to the

tf

Theexposed reduction when to factor fire. of the design load, when the combination factor of the variable load

z4  0.79 m

 11  0.7 Fire protection may be given to structural steelwork members by the use of:  GAGk   11Q k1  fi   fi  0.60455 a) Intumescent paints  GGk   Q Q k1 b) Mineral boards

3

c) Concrete encasement. The reduction factor above has been calculated using the partial safety factors. The values for

2

each country have to be checked in the relevant National Application Document NAD

Stress-strain relationship at elevated temperatures

Firedesign design Fire Fire Firedesign design


203

The bending moment at the ultimate limit state:

The shear force at ultimate limit state:

  GGk   QQk1 L2

Msd  543.375 m kN 8 The bending moment in the fire situation:

Msd 

 fiMsd Mfi Ed 

   GGk   QQk1 L  2  

Vsd  

Vsd  362.25 kN

MfiEd  328.5 m kN

The shear force in fire situation: Vfi Ed 

 fiVsd

VfiEd  219 kN

The shear resistance in the fire situation:  M1

 VfiRd  kx VRd 

 Mfi

k1 k2

VfiRd  325.149 kN

VfiRd  VfiEd

OK

Sabah Shawkat ©

Because the shear resistance in the fire situation is more than twice the design shear force in the fire situation, it is not necessary to study the interaction between the moment and the shear force to the resistance. Moreover, the maximum values of the moment and the shear force appear in different cross-sections.

The reduction factor for the design load level in the fire situation as a function of the ratio between the principal variable load and the permanent loading.

for the fire situation at time t=0 regarding both the bending moment and the shear force.

The bending resistance in the fire situation:

kx  0.167

MRD  1525.35521 m kN

Calculate the critical temperature of the cross-section. The degrees of utilization are calculated

M  fi0Rd  MRD k1  0.7

k2  1

 0M



 M1

MfiRd  kx MRD

 Mfi

k1 k2

MfiRd  400.29679 m kN

MfiRd  MfiEd OK

The value of VRd is obtained for the shear resistance at the normal temperature.

 Mfi

MfiEd

VfiEd Vfi0Rd

 VRd  1239 kN

Fire design Fire design

Mfi0Rd  1677.89073 m kN

 0M

Mfi0Rd

V fi0Rd  VRd 

 0V 

 M1

 M1  Mfi

 0.19578

Vfi0Rd  1362.9 kN

 0V

 0.16069


204 196

Fire design The value/ protection of the critical temperature of the cross-section is obtained according to the bending

temperatures. Moreover, TheCalculate strength the andresistance modulus of of elasticity column 190x190x7 decrease attoelevated axial loads in the building shownthe in whole the steel cross-section heats during fire. Normally the steel have to adjacent figure. In a fireupsituation, the compressive load on astructures hollow section is be protected

resistance as: The structural engineer involved in the design for active fire protection, or in  is not 1specifically   acr  757.90289  acr  39.19 ln  1   482  3.833and escape routes. These aspects fall under the guidance the layouts for fire compartment sizes  0.9674  0V  of the architect and are an integral part of building design. A structural engineer must be aware

against fire, or has to be demonstrated by calculations that the structures are capable of  Efld  670 kN N flED  Efld N flED  670 kN withstanding fire in an unprotected state for the required time. The stress-strain relationship at elevated temperature is presented in figure above. Three

of what is intended in this respect however, as fire safety design requires an integrated approach

reduction factors relative to the yield strength have been defined for steel. The factor kp,. The

by all members of the design team.

effective yield strength corresponds to the strain y,The modified reduction factor

The required level of fire performance for structures is typically given in terms of a reaction to

k,is used in calculations where the deformation of the appropriate structure has to be taken

fire classification and a fire resistance rating, as given in the Building Regulations.

into account. The modulus of elasticity in fire condition is obtained using factor kE,

Fire resistance is typically presented as a duration of time. The fire resistance of an element (wall, floor or roof) is a measure of its ability to withstand the effects of fire in one or more

In fire situations, the temperature of the steel increases together with the temperature of the

ways as follows:

gases in fire component. As the temperature of the steel increases, its strength and deformation properties are transformed. According to their use, structures have different fire resistance

1. Structural ‘loadbearing capacity’ to maintain the design loads under fire (R)

Sabah Shawkat ©

2. Integrity’ of the element which is the resistance to fire penetration (E)

3. Insulation’ which is the resistance to the transfer of heat to the face of the element remote for the fire (I) metal components such as nails, screws and bolts

As the temperature increases, the strength and the modulus of elasticity of the steel changes.

o cross-section

Critical steel temperature a function of the degreecan of utilization However, the room temperature as values for yield strength be used upoftothe 400 C. The yield strength corresponds to a total elongation of 2%. The modulus of elasticity is constant up to 100oC.

requirement (e.g. requirements for bearing capacity andsection compartment). Column hollow

In the fire situations, the temperature of the steel members increases slower than that of the fire The fire resistance period required for the building is 15 min. The steel grade used is S355J2H compartment. The development and distribution of steel temperature depends on the shape of and the buckling length of the column is Lfl. The temperature evolution in the fire compartment the steel member and its thermal properties. It is always necessary to calculate the steel is determined with standardfire time-temperature curve. temperature up to thetherequired resistance period, since a steel member may reach its maximum temperature during L t  15fire at a point where the fire compartment temperature starts ft  5 m decreasing according to the parametric fire model. By using a fire retardant material, the evolution of steel temperature can be slowed down, which lengthens the fire resistance period. The temperature of the fire compartment varies with time. In ISO - 834, this is expressed with Often it is necessary to protect steel components in order to slow down the increase in the following formula: temperature during fire.   g  fire 20retardant  345 log ( 8 t  1are ) applicable  g for  738.56095 Several methods use with allow sections Structural steelwork

must either be protected or designed in such a way as to avoid premature failure of the structure when exposed toof fire. Development temperature in unprotected hollow section The temperature increase of unprotected steel is obtained as follow": Fire protection may be given to structural steelwork members by the use of: m a) IntumescentApaints

V

b) Mineral  al boards hneta t ca  a c) Concrete encasement. Stress-strain relationship at elevated temperatures Industrial hall using I and rectangular steel hollow sections

Fire Firedesign design Fire Firedesign design


205

hnetr

8

  res 5.67 10

4 4   g  273    m  273  Am

hnetc

 c  g

  m

hnetd

 nc hnetc

  nr hnetr

V

 at

ca  a

hnetd t

Cross-section factors in design, hollow section exposed to fire on all sides

The temperature- time curve according to the ISO 834 standard Development of temperature in unprotected hollow section

Sabah Shawkat ©

The temperature increase of unprotected steel is obtained as follow: Am  al

V

ca  a

hneta t

 b  190 mm  h  190 mm

t  7 mm

 fy  355 MPa

r1  5mm

 M0

 1.1

A m  2  b  h  4 r0   r0 

Am V

 146.81576m

  c  25   t 

5 s

r0  10mm 2

V  2 t ( b  h  2 t )  ( 4   )  r0  r1

2

Hollow section

1

W

2

 1.0

 res

m K  nc

 1

 nr

 1

 0.50

 cp  1000 

 ca  600  J kg K

  p  0.25 

J kg K

Square rectangular

or

Am

Ap

V

V

2 b  h  4 r0    r0

Circular

d d t  t

Fire design Fire design

2 (b  h ) 2

W m K

2t  ( b  h  2 t )  4 ( 4   )   r0  ri 

2

2

2t(b  h  2t)  4(4   )r0  ri  2

2


206 196

Fire designbelow / protection Figure presents the evolution of unprotected 190x190x7 hollow section in a standard

of what is intended in this respect however, as fire safety design requires an integrated approach

The strength and modulus of elasticity decrease at elevated temperatures. Moreover, the whole Ap 2 steelVcross-section have to be 1protected  150.20893m  0.00506 mheats up during fire. Normally the steel structures V against fire, or has to be demonstrated by calculations that the structures are capable of J W  dp  200 mm  ca  600fire  in an unprotected   p  0.25  t  5 withstanding state for the required time. kg K m K The stress-strain kgrelationship at elevatedkgtemperature is presented J in figure above. Three  cp  1000    p  150    a  7850  3 3 reduction factors forK steel. The factor kp,. The m relative to the yield strength m have been defined kg

by all members of the design team.

effective yield strength corresponds to the strain y,The modified reduction factor

The required level of fire performance for structures is typically given in terms of a reaction to

isparameter used in calculations wherewith the deformation the appropriate structure has to be taken k,The ϕ is determined the followingofformula

fire classification and a fire resistance rating, as given in the Building Regulations.

into account. The modulus of elasticity in fire condition is obtained using factor kE, Ap cp  p   0.95674   dp  ca  a V In fire situations, the temperature of the steel increases together with the temperature of the

fire. The curve is calculated using the formula above with time steps of 5 seconds. The conforming to the required resistance periodfire (15 protection, min) is Themaximum structuraltemperature engineer is not specifically involved in fire the design for active or in the layouts fire compartment sizes and escape routes. These aspects fall under the guidance  amax for673C of the architect and are an integral part of building design. A structural engineer must be aware

Fire resistance is typically presented as a duration of time. The fire resistance of an element (wall, floor or roof) is a measure of its ability to withstand the effects of fire in one or more ways as follows: 1. Structural ‘loadbearing capacity’ to maintain the design loads under fire (R)

gases in fire component. As the temperature of the steel increases, its strength and deformation By replacing the values of material properties and the parameter ϕ in the formula above, the properties are transformed. According to their use, structures have different fire resistance following expression is obtained: requirement (e.g. requirements for bearing capacity and compartment).

Sabah Shawkat ©

2. Integrity’ of the element which is the resistance to fire penetration (E)

In the fire situations, the temperature of the steel members increases slower than that of the fire p

3. Insulation’ which is the resistance to the transfer of heat to the face of the element remote for the fire (I) metal components such as nails, screws and bolts

As the temperature increases, the strength and the modulus of elasticity of the steel changes. Increase in temperature of unprotected hollow sections protected with mineral wool boards However, the room temperature values for yield strength can be used up to 400oC. The yield (t = 15corresponds min) of dimensions strength to a total190x190x7 elongation of 2%. The modulus of elasticity is constant up to o 100Development C. of temperature in a protected hollow section

A column of 190x190x7 is protected with 200 mm mineral wool boards. The temperature increase of the fire protected steel structure conforms with the following formula p

 at

Ap  gt   at  10    t   e  1    gt Ca  a V  1 3 dp

A p  2 ( b  h )

Ap  0.76 m

2

2 t ( b  h  2 t )  ( 4   )  r0  r1

temperature during fire. Figurefire above showsmethods the increase in temperature of awith 190x190x7 hollowStructural section protected with Several retardant are applicable for use allow sections steelwork 200mm woolor boards during a standard fire. is calculated formula must eithermineral be protected designed in such a way as to The avoidcurve premature failure using of the the structure above with time steps of 5 seconds. The maximum temperature conforming to the required fire when exposed to fire. resistance period (15 min) is: Fire protection may be given to structural steelwork members by the use of: amax 301oC a) Intumescent paints

Stress-strain relationship at elevated temperatures 2 2 V  2 t ( b  h  2 t )  ( 4   )  r0  r1

Ap decreasing according material, the dp  1 to the parametric fire  1 model. By using a10fire retardant   t  0.00015 time  e  1   0.1004 ca  aof V  evolution steel temperature can be slowed down, which lengthens the fire resistance period. 1 Often it is necessary3 to protect steel components in order to slow down the increase in

c) Concrete encasement.

maximum  p temperature during fire at a point where the fire compartment temperature starts

b) Mineral boards

2

Ap  gt   and dp development  10 of steel temperature depends on the shape of compartment. The at distribution  at   t   e  1    gt Ca  aandV its thermal  the steel member properties. It is always necessary to calculate the steel 1 3 temperature up to the required fire resistance period, since a steel member may reach its

Fire Firedesign design Fire Firedesign design


207

Calculate the compression resistance of the box column, where the length of the column is

Calculating structural strength When calculating the compression resistance, the changes in the steel strength and modulus of elasticity caused by temperature during fire resistance period. The adaptation factors for strength and the modulus of elasticity kEθ and kyθ.

5m. Steel S355J2G3 is the material used. Classification of the cross-section, when the effect of the welds is not taken into account:

 h  190 mm

 tf  7 mm

tw  7 mm

hw  h

 b  190 mm

 bf  b  2 tf

fy  355 MPa

 M1

hw  0.19 m

 1.1

 M0

 1.1

The strength of hollow section in tension is given by the following formula:  Mft

 1

Lft  5 m

 ft

  y

 ft

 0.67706

Buckling length L cy  5 m

A

 1

 0.34

L cz  5 m

E  210000 MPa

The column can resist at 15 (min) fire if a 150mm layer of mineral wool is used, because the Flange

compression resistance at 301oC is

bf ky protected  1.0  ft

  y

kEprotected  0.7990  0.87525

fy   ft   A kyprotected   1.2   Mft

Efld  670 kN

b

 25.143

tf

Class 1

 26.8

Sabah Shawkat ©  ft

NftRd  

kEprotected  0.7990

tf

Web

N ftRd  1026.31871 kN

N ftRd  Efld

hw tw

hw

Class 3

 34.2

tw

 27.143

The cross-sectional parameters:

  

Lft  iy

ky protected fy

kEprotected E



 0.97917

An unprotected column does not meet the fire resistance requirements, because the compression

2

A  w  tw hw

 Aw 1330 mm

A  f  tf bf

 Af 1232 mm

area of the web

2

area of the flange

2

 A  2 Aw  2 Af

 A 5124 mm

resistance at 673 oC ky unprotected  0.2948

kEunprotected  0.17860

fy   ft   A kyunprotected   1.2   Mft

NftRd  

Efld  670 kN

 ft

  y

 ft

 0.87525

Iy 

N ftRd  302.55876 kN N ftRd  Efld

Iz 

2 tw hw 12 2 tf bf 12

Fire design Fire design

3

3

2 bf tf

3

12 3

2 hw tw 12

 h tf    2 2

2

4

 2 Af 

 b tw    2 2 

 2 Aw 

Iy  28641452mm

2

4

Iz  32179252 mm


208 196

Fire design /Iyprotection iy  A

iy  74.76407 mm

The structural engineer is not specifically involved in the design for active fire protection, or in Iz iz  for fire compartment iz sizes 79.24711 mm routes. These aspects fall under the guidance the layouts and escape A of the architect and are an integral part of building design. A structural engineer must be aware Resistance based on the strength of the cross-section: of what is intended in this respect however, as fire safety design requires an integrated approach

The strength and modulus of elasticity decrease at elevated temperatures. Moreover, the whole 1  y  0.67706 y  1  y  2 up2 during fire. Normally the steel structures have to be protected steel cross-section heats  y   y  y against fire, or has to be demonstrated by calculations that the structures are capable of withstanding fire in anfunprotected state for the required time. y N ybRd  1119.62in kNfigure above. Three   ybRd   y A The N stress-strain relationship at elevated temperature is presented  M1

reduction factors relative to the yield strength have been defined for steel. The factor kp,. The effective yield strength Buckling about z-axis:corresponds to the strain y,The modified reduction factor

by all members of fthe y design team. N plRd  1653.655 kN N plRd  A  The required level of fire performance for structures is typically given in terms of a reaction to  M0

k,is used in calculations where the deformation of the appropriate structure has to be taken

fire classification and a fire resistance rating, as given in the Building Regulations.

into account. The modulus of elasticity in fire condition is obtained using factor kE,

Fire resistanceofisthe typically presented as flexural a duration of time. The fire resistance of an element Resistance cross-section to the buckling: (wall, floor or roof) is a measure of its ability to withstand the effects of fire in one or more b h ways fas follows: Buckling curve b regarding both axes  27.143 25.14286 tw tf

Lcz  fy   z  0.82574  z      A E temperature of the steel increases together with the temperature of the  iz the In fire situations,

1. Structural ‘loadbearing capacity’ to maintain the design loads under fire (R)

gases in fire component. As the temperature of the steel increases, its strength and deformation properties aretransformed. According structures   z  0.5 z  0.9473 have different fire resistance    z2 to their use, 1     z  0.2 requirement (e.g. requirements for bearing capacity and compartment).

Sabah Shawkat ©

Buckling aboutofy-axis: 2. Integrity’ the element which is the resistance to fire penetration (E)

3. Insulation’ which is the resistance to the transfer of heat to the face of the element

remote for the fire (I) metal components such as nails, screws and bolts Lcy  increases, fy  As the temperature the strength and the modulus of elasticity of the steel changes.  y  0.87525  y      A  i   Etemperature  However, the yroom values for yield strength can be used up to 400oC. The yield strength corresponds to a total elongation of 2%. The modulus of elasticity is constant up to o  100 C.y  0.5  1     y  0.2   y 

2

y

In the fire situations, 1 the temperature of the steel members increases slower than that of the fire  z  0.70844 z  1  z  compartment. The development and distribution of steel temperature depends on the shape of 2 2  z   z  z the steel member and its thermal properties. It is always necessary to calculate the steel temperature up to the required fire resistance period, since a steel member may reach its fy N zbRd 1171.521 kN N    z A  during fire at a point where maximum the fire compartment temperature starts zbRd temperature  M1

decreasing according to the parametric fire model. By using a fire retardant material, the evolution of steel temperature can be slowed down, which lengthens the fire resistance period.

 0.99782

Often it is necessary to protect steel components in order to slow down the increase in y

1

 y

y

N  ybRd   y A 

2

 y

fy  M1

2

y

 0.67706

y

 1

temperature during fire. Several fire retardant methods are applicable for use with allow sections Structural steelwork must either be protected or designed in such a way as to avoid premature failure of the structure when exposed to fire.

N ybRd  1119.62 kN

Fire protection may be given to structural steelwork members by the use of:

Buckling about y-axis:

a) Intumescent paints b) Mineral boards

 fy   y      A  iy E Lcy

y

 0.87525

c) Concrete encasement.

Stress-strain relationship at elevated temperatures   y  0.5  1     y  0.99782   y  0.2   y2 

Fire Firedesign design Fire Firedesign design


209

Sabah Shawkat ©

Fire design Fire design


210 196

Fire designsection / protection Hollow exposed to fire on three sides

temperatures. Moreover, the whole TheHollow strength and modulus decrease at elevated section exposedof toelasticity fire on two opposite sides steel cross-section heats up during fire. Normally the steel structures have to be protected against fire, or has to be demonstrated by calculations that the structures are capable of

The structural engineer is not specifically involved in the design for active fire protection, or in

withstanding fire in an unprotected state for the required time.

the layouts for fire compartment sizes and escape routes. These aspects fall under the guidance

The stress-strain relationship at elevated temperature is presented in figure above. Three

of the architect and are an integral part of building design. A structural engineer must be aware of what is intended in this respect however, as fire safety design requires an integrated approach

reduction factors relative to the yield strength have been defined for steel. The factor kp,. The

by all members of the design team.

effective yield strength corresponds to the strain y,The modified reduction factor

The required level of fire performance for structures is typically given in terms of a reaction to

k,is used in calculations where the deformation of the appropriate structure has to be taken

fire classification and a fire resistance rating, as given in the Building Regulations.

into account. The modulus of elasticity in fire condition is obtained using factor kE,

Fire resistance is typically presented as a duration of time. The fire resistance of an element (wall, floor or roof) is a measure of its ability to withstand the effects of fire in one or more

In fire situations, the temperature of the steel increases together with the temperature of the

ways as follows:

gases in fire component. As the temperature of the steel increases, its strength and deformation properties are transformed. According to their use, structures have different fire resistance

1. Structural ‘loadbearing capacity’ to maintain the design loads under fire (R)

requirement (e.g. requirements for bearing capacity and compartment).

Sabah Shawkat ©

2. Integrity’ of the element which is the resistance to fire penetration (E)

In the fire situations, the temperature of the steel members increases slower than that of the fire

3. Insulation’ which is the resistance to the transfer of heat to the face of the element

compartment. The development and distribution of steel temperature depends on the shape of

remote for the fire (I) metal components such as nails, screws and bolts

the steel member and its thermal properties. It is always necessary to calculate the steel

As the temperature increases, the strength and the modulus of elasticity of the steel changes.

temperature up to the required fire resistance period, since a steel member may reach its

However, the room temperature values for yield strength can be used up to 400oC. The yield

maximum temperature during fire at a point where the fire compartment temperature starts

strength corresponds to a total elongation of 2%. The modulus of elasticity is constant up to

decreasing according to the parametric fire model. By using a fire retardant material, the

100oC.

evolution of steel temperature can be slowed down, which lengthens the fire resistance period.

Hollow Section

Am

Ap

V

V

Often it is necessary to protect steel components in order to slow down the increase in Am Ap Hollow Section temperature during fire. V

V

Rectangular with

b  2 h  6 r0  2   r0

non-exposed short

2 2 2 t  ( b  h  2 t)  ( 4   )   r0  ri   

Several fire retardant methods are applicable for use with allow sections Structural steelwork

b  2 h 2 t  ( b  h  2 t )  ( 4   )   r0  ri  2

2

side Rectangular with

2 b  h  6 r0  2   r0

non-exposed long

2 2 2 t  ( b  h  2 t)  ( 4   )   r0  ri   

2 b  h 2 t  ( b  h  2 t )  ( 4   )   r0  ri  2

2

side Square

b  2 h  6 r0  2   r0 2 t  ( b  h  2 t)  ( 4   )   r0  ri  2

b  2 h 2

2 t  ( b  h  2 t)  ( 4   )   r0  ri

 Stress-strain relationship at elevated temperatures

2

2

must Rectangular either be protected 4 r a  way 2   r as with or designed 2 hinsuch  to avoid premature failure2 hof the structure whennon-exposed exposed to fire. short

0

0

2 t  ( b  h  2 t )  ( 4   )   r0  ri  2

2

2 t ( b  h  2 t)  ( 4   )   r0  ri 

2

2

2 t  ( b  h  2 t )  ( 4   )   r0  ri

2

2

 side Fire protection may be given to structural members by the use of: 2 b Rectangular with 2 b  4 rsteelwork 0  2   r0  2 2 a) Intumescent paints 2 2 2 t ( b  h  2 t)  ( 4   )   r0  ri  non-exposed long 2 t  ( b  h  2 t )  ( 4   )   r0  ri      b) Mineral boards side c) Concrete encasement. 2 h Square 2 h  4 r  2   r 

Fire Firedesign design Fire Firedesign design

0

0

2 t  ( b  h  2 t )  ( 4   )   r0  ri  2

2


211

Hollow section exposed to fire on two adjacent sides

Sabah Shawkat ©

Hollow Section

Square or rectangular

Am

Ap

V

V

b  h  4 r0  1.5  r0

2t  ( b  h  2 t )  ( 4   )   r0  ri  2

(b  h )

2

2 t  ( b  h  2 t )  ( 4   )   r0  ri

2

2

Fire design Fire design


Sabah Shawkat ©


Sabah Shawkat © Composite slab Composite Steel Concrete Ceilings


Sabah Shawkat ©


226 224

Composite slab Determination M plech with the maximum stresses in the extreme chord of the sheet:

The roof structure is designed as a roof system "Hoesch" (supporting plates). Material Characteristics:

Introduction

fy

M m.max M sheet M md.max  fy This example the composite the second storey that is   W y.a demonstrates the design of M sheet  floor slab  on M W y.a W y.a M W y.a  supported by the composite. Verification is needed for both the construction stage (non-

composite stage) and constructed stage (composite stage). Although generally checks at the

M sheet  20.50 kN m

non-composite on two M continuous spans, for simplicity only a single span case Determination ofstage M slabare at 1based m linear: slab M p.max  M sheet will be considered here. M slab

53.80 kN m

Design and evaluate the composite steel-concrete slab on a span is L, the distance of the ceiling

is L1, the thickness of the concrete slab is h, the imposed load on the ceiling is v. The reinforcement will be designed in one rib, the ribs are spaced apart by 750mm, the moment Floorbeslab and material should recalculated to aproperties-design width of 0.75m. of composite slab: M slab.0.75

(-) DesignCeramic of reinforcement ribs slab: paving to concrete1,35 CementMglue 1,35 Input data: doska.0.75  40.351  kNm

gd

(kN / m2)

(kN / m2)

0,2

0,27

0,08 M slab.0.75

0,108

yd

fyd  356.522  MPa

1.15

fctm  1.2MPa

The floor slab should be designed for both construction stage and composite stage fcyl f cd  17  MPa  fcd  0.85  1.5 metal decking acts as formwork and has to support its own During the construction stage, the

fycd  356.522MPa

weight, wet concrete, and construction loads. The resistance of the metal decking during the construction stage needs to concrete be verified at the ultimate andthe serviceability limit state Distance from the edge of the cross-section along axis of the reinforcement: g

2

 g

 g 2.892  kN  m

g

2

 g o.d

 g ms.d 3.904  kN  m

ms.n height o.n of the concrete ms.n cross section: d  220mm ms.d Effective in of service stage – live part loadof+ the floor layers TheLoad depth the compression concrete

2 2   0.0774   d g x  0.017m x u g ps.d 0.8  g xs.d  v d xu  0.0147.274 m  kN  m   g s.n  xv gps.d g ps.n n ps.n 5.24  kN  m

Design of roofing sheets and reinforced concrete slab: M dim  Ipropose plate 2 b d  d  fcd

Hoesch: Depth mm b d1.5  0.825m

d  0.22m

  0.059

  0.01737

Sabah Shawkat ©

Cement fry CSFE

M dim

 40.351

kN  m

Thermal insulation

h py  280mm l  7m

gn



40.35 kN m

410MPa Load - reinforced concrete slab + sheet metal f 

f cyl  30  MPa

b py  75mm

Nobasil l st ceiling  750 mm false

M dim

1,35

0,9

1,215

0,06

0,081

0,15

0,2025

1,24

1,674

1,35

2,7

3,645

1,35

0,192

0,2592

2,892

3,9042

1,35

l  7000mm

h d  75mm

1,35

lst  0.75m

Reinforced concrete slab

Hoesch plate Imposing load

1,4

4

5,6

2

Effective sheet width "bd": 2

m  1g s.d  6 1.674  2 kN   0.13

 b d3  0.5  lst

2

A st 

b d  xu  fcd

2

2R20

 A st 5.359  cm

fyd

Sheet metal:

2

A str

2

6.28 cm

d

20 mm

g plechu  0.192  kN  m

Cross-sectional characteristics of the current 1m: Check the degree of reinforcement of the concrete cross section: 3

 W y.a  68348  mm b avrge 122.5mm  M  1.1

4

4

Iy.a  1030  f10 mm 1 ctm  st.min 

Ea  210000  MPa  fy  235  MPa

3 fyd

slab + sheet

The load takes over the sheet, we consider the construction supports

2

2

kN 0.45m m  v d  b 5.6  kN  b d1 g o.d  1  h3.9042 bd1  2  m l d d2

b d3  0.375m

The required reinforcement area will be:

The actual depth of the compression part of the concrete: b  1.0  m Effective load width: 

2

g o.n  2.892  kN  m  v  4.0  kN  m b dI min b d1 b d2 b d3 n

A req  5.35  cm 

A str Assessment of the construction stage - reinforced concrete  st  st  0.018 st.max  0.02 h py  b avrage

Load - floor layers, reinforced concrete slab, live load g s.n  1.24  kN  m

2

A req    b d  d  fcd

b d  2  b d3  b py

b d2  0.91m

A str  fyd xu q ms.n  g ms.n  bxu b d  fcd

b d  0.825m

Compositeslab slab Composite Composite Compositeslab slab

 420 1  d  MPa 104.81  mm 3.904  kN  m 1 15.94  mm 2.892xu.lim q ms.n   kN  m q  gxu.lim q ms.d ms.d  b  525 MPa  ms.d fyd


225

Verification at ULS

Assessment of the service stage - floor layer +live load

The maximum bending moment from the calculation design load above the support: M  md.max  5.9  kN  m

Reaction in the supports:

Rmd.k  5.10  kN

Rmd.s  17.0  kN

A part of the load takes over the sheet and a part of it reinforced concrete slab: Load width: b  1.0 m

q ps.n  g ps.n  b

1

q ps.n 5.24  kN  m

q ps.d  g ps.d  b

1

q ps.d 7.274  kN  m 

L  7.0  m Sheet profile length: 

Assessment for the ULS: reinforced concrete slab + sheet + live loads + floor layers

Sabah Shawkat ©

Stress in the extreme cross-section of the sheet metal: sheet

Mmdmax W ya

sheet

86.323 MPa

Reactions from the calculation load: floor layers + live load + sheet metal + reinforced concrete slab

Verification at SLS – sheet metal + reinforced concrete slab Maximum deflection from characteristic load:

fmax  3.8  mm

Reaction in supports: sheet metal + reinforced concrete slab R mn.s  12.6  kN

Rmn.k  3.8  kN

flim 

0.5  L 250

1

Rmd.s  17  kN

 q ps.d 7.274  kN  m

Rpd.k 

q ps.d  L 2

Rmd.s 2

 Rpd.k 33.959  kN

Reactions from characteristic load: f lim  14  mm

floor layers + live load + sheet metal + reinforced concrete slab: R mn.s 12.6  kN

2

 q ps.n 5.24m  kN  m

Rpn.k 

q ps.n  L 2

Rmn.s 2

Rpn.k 24.64  kN 

Maximum bending moment: (part of the bending transmits the sheet and the rest of the reinforced concrete slab) M p.max 

1 8

2

 q ps.d  L 

Composite slab Composite slab

R md.s  L 4

M p.max  74.303 kN  m


226 226

Determination with maximum stresses in the extreme chord of the sheet: Determination with thethe maximum stresses in the extreme chord of the sheet: M plech M plech M sheet M m.max M m.maxM sheet     W y.a  M M W y.a W y.a W y.a fy fy

M md.max  fy fy Mmd.max   M sheet W y.a      M sheet   Wy.a  M M W y.a W y.a    

Material Characteristics: Material Characteristics: 410MPa 410MPa fyd fyd   1.151.15

 30MPa  MPa f  30 cyl cylf

fcylfcyl MPa  fycdfycd MPa  356.522  fcd  0.85  356.522 fcd  0.85   1.5 1.5

M sheet  20.50 M sheet  20.50  kNkN m m

fyd fyd  356.522  MPa  356.522  MPa

 1.2MPa fctmfctm  1.2MPa

 17  MPa f cdf cd 17  MPa

Determination of M m linear: M slab Determination of M at 1atm1 linear: slabslab M slabM p.max M p.max M sheet  Msheet Distance from edge of the concrete cross-section along axis of the reinforcement: Distance from thethe edge of the concrete cross-section along thethe axis of the reinforcement:

M slab53.80 53.80 M slab  kNkN m m

reinforcement designed in one spaced apart 750mm, moment TheThe reinforcement willwill be be designed in one rib,rib, thethe ribsribs areare spaced apart by by 750mm, thethe moment should recalculated a width of 0.75m. should be be recalculated to atowidth of 0.75m.

 220mm Effective height of the concrete cross section: d d 220mm Effective height of the concrete cross section:

depth of the compression of the concrete TheThe depth of the compression partpart of the concrete  0.0774   0.0774

M slab.0.75  kNkN M slab.0.7540.35 40.35 m m

x x d  d

M dim M dim    2 2 b d b dd  d fcd  fcd

Design of reinforcement to concrete slab: Design of reinforcement to concrete ribsribs slab: Input data: M doska.0.75 Input data: M dimM slab.0.75 M slab.0.75 M doska.0.75 40.351  40.351  kNm M dim  kNm

 0.017m x x0.017m

x u x u 0.80.8 x x

 0.22m b d bd 0.825m  0.825m d d0.22m

 0.014 xu xu 0.014 m m

 0.059  0.059

  0.01737  0.01737

Sabah Shawkat © A req  fcd A req   b d b dd  dfcd

 40.351kNkN m m MM dimdim 40.351

 7000mm  280mm b pyb py  75mm h d hd 75mm  75mm l l 7000mm h pyh py  280mm  75mm

2 2

A req A req   5.35   5.35  cm cm

required reinforcement area TheThe required reinforcement area willwill be:be:

l  l7m7 ml st l st 750750 mmmm

 fcd b d b dxu xufcd 2 2 2R20 A stA   cm cm 2R20 5.359 A st  f f stA st5.359 yd yd

 0.75m lst lst0.75m

2 2

A strA str 6.286.28  cm cm

20 mm d d 20 mm

Check degree of reinforcement of the concrete cross section: Check thethe degree of reinforcement of the concrete cross section: b avrge 122.5mm 122.5mm b avrge

 st  st

Effective sheet width Effective sheet width "bd"b ":d":

 

b d3  0.5  b d3  0.5  lst lst

 0.018  st.max  st st0.018  st.max 0.02  0.02

actual depth of the compression of the concrete: TheThe actual depth of the compression partpart of the concrete:

 

bd2 b d3 b dIb dIminmin b d1bd1 b d2 b d3

 1  0.130.13 b d1  0.45m b d1   1   1h d h d b d1b d1  0.45m 2  1 6 6  2

A strA str  b avrage h pyhpy b avrage

1 fctm 1 fctm  st.min  st.min   3 f3yd fyd

b d2b d2  2   2l  l

 0.91m b d2b d2  0.91m

A strAstr fyd fyd xu xu b d bfcd d  fcd

 0.375m b d bd 2 2b d3  b d3  0.825m b d3b d3  0.375m  bpyb py b d bd 0.825m

Compositeslab slab Composite Composite Compositeslab slab

15.94  mm xu xu15.94  mm

 d  MPa 420420  d  MPa xu.lim104.81 104.81  mm xu.lim  mm xu.lim xu.lim  MPa  fyd 525525  MPa  fyd


227

Calculation of load bearing moment "Mu"

 sv 

 lst 750  mm

35  mm

h s  211.5  mm

Determination Iy.i (moment of inertia of the ideal cross-section where the reinforcement is Mu

Mu

A st.r  fyd  d e.r 

 xu.r       2  u

A str  fyd  d  

  2 

replaced by concrete using the working coefficient "n"):

M dim  40.351  kNm

working coefficient:

 xu 

M u  47.47 kN  m

Mu

47.47 kN m

 xb

Note: A 75 mm thick concrete slab needs to be reinforced with a mesh across the entire surface and must be verify due to bending moment between the two ribs as bearing slab reinforced on

 Lv  L  2  32.5mm  0.5  b p

In the middle of the span: Construction stage:

L  7m

Lv  6.635m

fm  0mm

Bf

q pn  Lv Bf

4

2

Rmn.s  Lv

A b  h s  A s.i  s v A b  A s.i

z1  149.4  mm

 z2 62.1  mm

Ea  Iy.a  Ei  Iy.i

Iy.i.0.75 

 1  l  x 3  l  x  z 2  0.5  A  z 2  A  z  s 2  st b st b 2  s.i 1 s.i  1 v  12  4

Iy.i.0.75  3.449  10  mm

1

8

4

Iy.i  4.598  10  mm

0.75

4 Overall bending stiffness of the cross section: Bf  Ea  Iy.a  Ei  Iy.i Bf 9.635  MPa  m

48  Bf

- is the total flexural stiffness of the cross-section, expressed as the sum of the bending

E a  210000  MPa

7

Service stage:

fp 

Total deflection:

4

Iy.a  1.030  10  mm

5 384

Ei  16250  MPa

q ps.n  Lv

4

Bf

 f 

Limit deflection:  Ei  0.5  Ec

z1 

 A s.i 8116  mm

Moment of inertia at 1m normal:  Iy.i  Iy.i.0.75 

3

rigidity of the sheet and the concrete slab with ribs Bf

 A b 14966  mm

8

Service stage - floor layers + utility loads + reaction from reinforced concrete and sheet metal:

0.8

Sabah Shawkat ©

More precise determination of the ceiling Length according to the manufacturer HEB 360:

5

xu.r

2

 A b  lst  xb

 z2  hs  z1

Assessment for the SLS:

384

n  12.923

0.5  Ec

20.0  mm

A s.i  n  A st.skut

one-way with a span 0,75m

fp

Es

Determining the depth of the compression concrete area: xb 

Assessment of concrete cross-section due to bending moment:

b p  300mm

n 

R mn.s  Lv

3

48  B f

f  21.7  mm

fm  fp

Lv flim  250

flim  26.5  mm

Design of composite beam:

Note: Only the compression area of concrete is considered in the calculation of the moment of inertia, because cracks are created in the tensile part and this reduces the bending stiffness of the cross-section. In fact, however, the tension concrete area contributes to the overall flexural

The width of the sheet metal: The length of the beam:

lp

Preliminary design of the beam:

stiffness of the cross section, then this calculation is on the safety side.

Composite slab Composite slab

b pl.d





8.4

 h pr 

1 20

7.0 m

m  lp

h pr  0.42m

fp  21.7  mm


228 226

 d 315  mm c   b p  t w  0.5 Material Characteristics:

I suggest a beam HEB 360 Determination with the maximum stresses in the extreme chord of the sheet: M plech fI. y

Stage - the load is transferred only by a steel beam in the centre of the span M m.max M sheet M md.max  fy supported   M sheet      W y.a M W y.a W y.a y.aload   Mslab, W  Load: floor layers, sheet metal + reinforced concrete live M sheet 20.50 kNmm 2 g s.n 1.24  kN

2

2

g s.d  1.674  kN  m

g o.n  2.892  kN  m

Determination of M slab at 1 m linear: 2

g o.d  3.904  kN  m

M slab

53.80 kN m

kN

kN

kN  q n 20.244  m

kN

6 4 fctm  1.2MPa Iy  432  10 mm

y

d f cd  17   MPa bended section:

  25.2

tw

determined thatcross-section we use a plastic layers + sheet metal Distance from by theClass edge 1of. It thefollows concrete alongcalculation. the axis ofFloor the reinforcement: + reinforced concrete slab Effective height of the concrete cross section: d  220mm 1 the concrete 2 of 2 The M depth of1 the compression part d  8  g s.d  b pl.d  lp  8  g o.d  b pl.d  lp x    d

fy M  W  pl.Rd M dim pl  mo   2 b d  d  fcd

x u  0.8  x

x  0.017m

M pl.Rd

 572.545

b d  0.825m

M d  344.386 kN  m

 kNm

xu  0.014 m

M max.I  61.5  kNm

d  0.22m

  0.059

  0.01737

Sabah Shawkat © M dim

 40.351  kNm

M slab.0.75

Assessment of the serviceability limit state 2(SLS):

Maximum bending moment of the beam in stage I: Mdmax  37.3  kN  m

M dim  40.351 kN  m M max.I  61.5  kNm

h py  280mm l  7m

MPa

fyd  356.522  MPa f

fcyl fycd 356.522MPa  limited  fcd  of 0.85 The slenderness the web 1.5

  0.0774

Total design loads per 1m of beam: sheet + reinforced concrete slab:  q d  g o.d  b pl.d Design of reinforcement to concrete ribs slab:  q d 27.328  Input data: Mmdoska.0.75

235

410MPa f MPa 103mm3fyd   m   2680 cylW pl30 1.15

The cross sectional web is determined by Class 1 and the cross-sectional area is also

M slab M p.max  M sheet 2 2  v n  4.0  kN  m  v d  5.6  kN  m

Beam- self weight HEB 360: q pr.n  1.42  q pr.d 1.917  q pr.d  q pr.n   f m m The reinforcement will be designed in one rib, the ribs are spaced apart by 750mm, the moment Total characteristic loads per 1m of beam: sheet + reinforced concrete slab: should be recalculated to a width of 0.75m.  q n  g o.n  b pl.d M slab.0.75 40.35 kN m

c  143.75  mm

b py  75mm

A req    b d  d  fcd

kN q d 27.328   m

l  7000mm

h d  75mm

A req  5.35  cm 

f lim 

lp

400 The required reinforcement area will be:

l st  750 mm

fmax  0.184mm

b d  xu  fcd 2 2R20 AII.  cm A st 5.359 Stage f- beam as  composite structure st  yd

lst  0.75m

A str

f lim 21  mm

2

6.28 cm

d

20 mm

Layers + Reduced long-term live load + Sheet and reinforced concrete slab

kN kN Check degree reinforcement concrete A -the dead load of - floor layers: of the q nII.et  1.24 cross section: q dII.et  1.674 2

Live load: uniform b avrge 122.5mm

1 fctm

2

m

m

 st.min live load  of the roofs and floors is permitted to change: at beams, frame 3 fyd

2 2 and beam A slabs, without the ceiling with a load area A in m greater than 36 m , reduces by

str

 st

the hcoefficients: py  b avrage

Effective sheet width "bd": Design of the beam HEB 360:  1  6

 2  0.13

b dI

 b d1   1  h d

min b d1 b d2 b d3 b d1  0.45m

1  0.5327

The actual depth of the compression part of the concrete: Reduced value of the live load (but not less than 50% of the value):

 b d2   2  l

b d2  0.91m

Classification of cross-section HEB 360 subjected to bending:  b d3h  0.5360mm  lst p

 st  0.018 2  st.max  0.02 3m A  8398.784 m  1  0.5  A

 0.375m t  b  2  b  b py t bd 22.5mm  0.825m b p bd3300mm w d12.5mm d3 f

xu

A str  fyd

xu b d  fcd v n.red  1  v n

 d  hp  2  tf

Compositeslab slab Composite Composite Compositeslab slab

420 d  MPa xu.lim xu.lim kN525 MPa  fyd kN v v n.red 2.131  2 n 4 2 m m

15.94 mm

104.81 mm


229

v d.red 2.983 

v d.red  1  v d

kN

 v d 5.6 

2

m

Long-term imposed load: v dl.d  0.5  v d.red  v dl.n 1.065 

2

+ Reduced imposed load:

m

 v dl.d 1.492 

kN

v dl.n  0.5  v n.red

2

m

kN

M max.III

1 8

2 1 2  q dl.III.et.a  lp   q pr.d  lp 8

kN 2

m

v kr.n  0.5  v n.red

E

a

c

2

Ecm  32500MPa

m

Long-term component of imposed load II. stage: q dl.II.et  v dl.d  q dII.et kN

q dl.II.et.a  22.16 

q dl.II.et.a  q dl.II.et  b pl.d

2

m

 c  1.5

c

a 

Ec

Ec

1

Ea

Ea

n

Ea

fck  25MPa

210000



MPa

Moment of inertia for the long-term component: b eff  bstr if b eff  b str b eff if b eff  b str

m

4

 Ec  0.5  Ecm

n II 

Ec  1.625  10  MPa

q nl.II.et

2.305 

kN m

b eff  2

2

Lo

b eff  2.1m

8

3

2

Maximum bending moment in the mid-span of the beam in II. stage:

A HEB  18.1  10 mm

Layers + reduced long-term imposed loads + reaction from sheet metal and reinforced

h p  360 mm

Ea

n II  12.923

Ec

b str  4200mm

6

4

Iy.HEB  432  10 mm

Lo  lp

h p1



kN m

M max.II  439.207

1

M max.II 

2

 kNm

8

205 mm

1 Ra   g o.d  b pl.d  lp 2

R a  114.778

h

short-term component of the imposed load III. stage: q kr.III.et  1.492  kN 2

m

2

m

q dl.III.et.a  q kr.III.et  b pl.d

zcgi.II 

p The ideal moment of inertia: zcgi.II  87.521  mm 2

2

2

1  h  b eff  h    h   n II  p 2

A HEB  b eff  h 

1 n II

h 2

 zcgi.II   hp 129.979  mm

2 hp   1 1 1 h 3 Iy.iII  Iy.HEB  A HEB   zcgi.II     b eff  h   b eff  h     zcgi.II  h p  2  12 n II n II  2  

q kr.IIIn.et  v kr.n q dl.III.et.a  10.442 

hp

 zcgi.II 267.521  mm

We consider the short-term load under which we understand 50% of the imposed load. The

q kr.III.et  v kr.d

A i.II  0.03m

A HEB 

Centre of gravity of cross section:

kN

III. Stage: self-weight of the beam + reduced short-term of imposed load

kN

2

Ideal area:  A i.II  A HEB  b eff  h  n II

1 2  q dl.II.et  b pl.d  lp   Ra  lp 4

b eff  2.1m

h  75mm

1

 22.16 m 

q kr.IIIn.et  1.065 

Ec

Sabah Shawkat ©

q nl.II.et  v dl.n  q nII.et

q dl.II.et.a

c

Ea

kN

Long-term component of imposed load (characteristic) II. stage:

concrete slab:

a

Cross-section characteristics II. stage:

kN

 3.166  q dl.II.et

M max.III  109.003  kNm

Calculation of the composite structure:

2

m

Short-term imposed load: v kr.d  0.5  v d.red  v kr.d 1.492   v kr.n 1.065 

Maximum bending moment at the mid-span of the beam in III. Stage: self-weight of the beam

kN

kN

4 4

Iy.iII  7.823  10

m

Composite slab Composite slab

m


230 226

2 Determination maximum stresses in the extreme of the sheet: M plech with the Resulting cross-sectional characteristics II. stage: A i.II  0.03mchord  zcgi.II 267.521  mm 4 4 fy I M m.max  10M sheet m y.iII  7.823   M W y.a W y.a Cross-sectional characteristics III.

M md.max  fy M sheet      W y.a M W  stage: Ecm  32500  MPa y.a  c  1.5 Ea  210000MPa

f ck  25 MPa M sheet  20.50 kN m

M slab

410MPa

fyd  356.522  MPa

1.15

Maximum bending moment infII. stage:

fycd  356.522MPa

cyl  fcd  0.85  1.5

b eff 

53.80 kN m

Ea The reinforcement will be designed in 4one rib, the ribs are spaced apart by 750mm, the moment Ec  Ecm

Ecm  3.25  10  MPa

should be recalculated to a width of 0.75m.

n III  6.462

Ec

1

8

4

b str  4.2m

2

m

Lo  lp

d  Effective height of themoment concrete section:Qdl III Maximum bending incross III. stage: long-term load II. stage et.a220mm

The depth of the compression part of the concrete 1  10.442  q dl.III.et.a

kN

m x    d

  0.0774

Lo M slab.0.75 b eff  2 40.35 kN m b eff  2.1m 8

q dl.II.et.a 22.16m 

lp  8.4m

kN

2 Distance from edge of along the axis of the reinforcement:  the  q dl.II.et  bthe  lp  cross-section Ra  lp M max.II M max.II 439.207  kNm pl.d concrete

b str if b eff  b str b eff if b eff  b str

n III 

1

fctm  1.2MPa

R a  114.778 kN f cd  17  MPa

M p.max  M sheet

Moment of inertia for the long-term component:

M max.III 

8 x  0.017m

2 1 2  q dl.III.et.a  lp   q pr.d  lp 8

Moment of inertia in stage I: Iy.iI  Iy.HEB

b eff  2.1m

x u  0.8  x

 

z yia.I

d  0.22m

b d  0.825m

2

b d  d of  fcd Moment inertia in II. stage: Iy.iII  7.823  10 4 m4

h  75mm

h  205mm h s  360mm Input data: M doska.0.75 M dim M slab.0.75  40.351 p1  kNm 1 2 Ideal area: A i.III  A HEB  b eff  h  A i.III  0.03m M dim  40.351 kN  m n II

M  max.III 109.003  kNm xu  0.014 m

4 4

Iy.iI  4.32  10

Distance of center of gravity, point A in stage I: M dim

3 2 6 4 Iy.HEB  432  10 mm A HEB 18.1  10 mm to concrete ribs slab: Design of  reinforcement



m

h p  0.5 z yia.I 180  mm

  0.059

  0.01737

Sabah Shawkat ©

h py  280mm

b py  75mm

h d  75mm

 750 of mm Centrel stof gravity cross section: zcgi.III 

l  7m

m

61.5  kNm fyd  f 30  MPa max.I cylM

q dlII.eta long-term load II. Stage

Determination of M slab at 1 m linear: M slab

kN Material Characteristics: Maximum bending moment in stage I: qd long-term load of stage I q d 27.328 

Distance A req    b dof the d  fcentre cd

l  7000mm hp 1 h  b eff  h    h   A HEB  n III  p 2 2

lst  0.75m

1 A HEB  b eff  h  n III

h

2

h 2

 zcgi.III  hp 92.684  mm

m

Resulting cross-sectional III. stage: A  0.03m2  zcgi.III 304.816  mm Effective sheet width "bd": characteristics b dI min b d1 b d2 b d3  i.III 4 4

 b d1   1  h d

Cross-sectional assessment:  b d3  0.5  lst

b d1  0.45m

b d2   2  l

Assessment of steel beam: Point A

b d3  0.375m

b d  2  b d3  b py

d

u

cd

fyd  m0  1.15

4 4

m 10 0.13  1Iy.iIII  6 9.348  2 

4 4 inertia in III.area stage: TheMoment required of reinforcement willIy.iIII be:  9.348  10 m

The bcentre of gravity, point A in III. stage: x f

2 2 hp   1 1 1 h 3 Iy.iIII  Iy.HEB  A HEB   zcgi.III     b eff  h   b eff  h      zcgi.III  h p  2  12 n III n III  2  

Iy.iIII  9.348  10

 zyia.II 267.521  mm

A st 

 zcgi.III 304.816  mm

p The ideal moment of inertia: zcgi.III   124.816  mm

2 of gravity, A req  point 5.35  A cmin the second. stage: zyia.II  zcgi.II 

b d2  0.91m

zyia.III  zcgi.III 2 2R20 A str  A st 5.359  cm fy  204.348  MPa  m0

zyia.III  304.816  mm 2 d 20 mm 6.28 cm

Check the degree of reinforcement of the concrete cross section: M max.I M max.II M max.III fy A   zyia.I   zyia.II  zyia.III  204.348  MPa 1 fctm I Iy.iI  m0 Ist.min b avrge 122.5mm y.iII  y.iIII 3 fyd  A 211.37 A str  MPa  st  st  0.018  st.max  0.02 h py  b avrage Mmax.I  AI   zyia.I Condition does not satisfied: AI  25.625MPa Iy.iI

The actual M depth of the compression part of the M concrete: max.III AIII   zyia.III A str  fyd Iy.iIII xu xu 15.94 mm b d  fcd AIII  35.543MPa

b d  0.825m

Compositeslab slab Composite Composite Compositeslab slab

max.II  zyia.II AII  149.27MPa Iy.iII 420  d  MPa xu.lim 104.81 mm 525 MPa  fyd

AII 

xu.lim

A  AI  AII  AIII

A  210.438MPa


231

Concrete Assessment: Point B

4

Distance of centre of gravity, point B in II. stage: zyib.III   h p  h   zcgi.III z yib.III

 130.184  mm

 fIII 

zyib.II  h p  h  zcgi.II B 

M max.II Iy.iII

bIII 

bII 

zyib.II  167.479  mm

M max.III 1 1  zyib.II    zyib.III  n II Iy.iIII n III

Mmax.III Iy.iIII Mmax.II Iy.iII

1  zyib.III  n III

1  zyib.II  n II

 B  9.626

 MPa

5 384

q kr.III.et  b pl.d  lp

B  9.581MPa

B  bII  bIII

f II  17.372  mm

4

Ea  Iy.iIII

fIII  3.448  mm

Total deflection:  fmax  fI  fII  fIII lp Limit deflection: f lim  400

bIII  2.349MPa

bII  7.231MPa

3

q dl.II.et  b pl.d  lp Ra  lp 1 5 fII     48 Ea  Iy.iII Ea  Iy.iII 384

fmax  21.615  mm

f lim  21  mm

Design of shear connection: we will consider rigid composite structure - shear connection is stressed by shear force

Marking the stress on the composite beam HEB 360

- we propose uniform distribution of shear connectors

Sabah Shawkat ©

h - height of shear connectors and after welding (L - 5 mm) d – shear connectors diameter h tr  3.d

We suppose:

Lt – length of shear connectors, d – diameter of shear connectors, bo width of beam, hp1-height

of ribs above the beam:

d  12.7mm

Lt  50mm

b 0  300mm

h p1  1.5mm

h tr  Lt  5mm 

Assessment of the serviceability of limit state (SLS): fmax  flim fmax

ls

Load capacity of shear connection:

400

fu  340MPa

fI  fII  fIII

Deflection of the first stage: steel-reinforced concrete slab:  q d 27.328 

kN

 3.25  10

kN 2

 1.492  q kr.III.et

fck  25  MPa

 MPa

kN

1 fck  Ecm  v

2

RRd  0.29    d 

m

Deflection in the third stage: reduced imposed:

4

  1

m

Deflection in the second stage: floor layers + reduced imposed long-term load:  3.166  q dl.II.et

E cm

 v  1.25

RRd  0.8  fu 

 d

2

m

Composite slab Composite slab

4

2

1 v

R Rd  33.729  kN

R Rd

 27.565

 kN


226 232

Reduce valueMof shear connection capacity: for ribs perpendicular to of beam Determination with the maximum stresses in the extreme chord the sheet: plech b h  0.7    0    tr   1   h   fy kt  M m.max   hMsheet N  r   p1   p1  

W y.a

M

maximum distance of shear connectors: 410MPa

3

 kt 4.06  10 fy M md.max M sheet      W y.a M W y.a  

W y.a

1 kt  0.85   Nrat 12 m linear: M min kt of 0.7Mifslab Determination slab kt  min kt kN 0.85 M sheet 20.50  m if Nr

M slab

Spacing of shear connectors: Material Characteristics:

PRd.x  RRd  kt

fycd  356.522MPa

 PRd.x 23.43  kN

f cd

h  0.075m fctm  1.2MPa

 17  MPa

Distance from the edge of the concrete cross-section along the axis of the reinforcement:

Thestage: reinforcement will be designed in one rib, the ribs are spaced apart by 750mm, the moment Vzrecalculated  S.s should be to a width of 0.75m.

Effective height of the concrete cross section:

q dl.II.et  3.166 

kN

kN  q dl.II 13.296  m

q dl.II  q dl.II.et  b str

2

m

Design of reinforcement to concrete ribs slab: q dl.II  L VzIIdata:  Input 2 M doska.0.75

d  220mm

The depth of the compression part of the concrete   0.0774

Iyi 40.35 kN m

II. Stage:

fcyl  fcd  0.85  1.5

6  h  450  mm fyd  356.522  MPa 2.5  d  31.75  mm

M p.max  M sheet

53.80 kN m

T

1.15

minimum distance of shear connectors:

The longitudinal shear force per unit length: we have to calculate the force for II. Stage, III.

M slab.0.75

fyd 

f cyl  30  MPa

x    d

M dim

 

2

b d  d  fcd

M dim  MkN  40.351 V zII kNm 46.535 slab.0.75

x u  0.8  x

x  0.017m

d  0.22m

b d  0.825m

xu  0.014 m

  0.059

  0.01737

Sabah Shawkat ©

III. Stage: M dim  40.351

A req    b d  d  fcd

kN  m

kN kN q7000mm h pyq kr.III.et  280mm1.492bpy  75mmq kr.II  h d q 75mm b str l  kr.II 6.265  m kr.III.et 2 m l  7 m l st  750 mm VzIII 21.927  kN  lst  0.75m

Cross Section II. stage:

TII 

Iy.iII

1 n III kN

 TII 95.324  m

kN Effective widthT"bd149.175 ":  b dI T  TIIsheet   TIII m

 1  6

 2  0.13

 b d1   1  h d

TIII 

VzIII  SyIII Iy.iIII

min b d1 b d2 b d3

b d3  0.375m

Composite roof slab using sheet metal profile TheDesign required reinforcement area will be:rib of slab: of shear reinforcement to the

2

h  b eff  h    h p1  zcgi.III  h s  2 

Material b d  characteristics: xu  fcd 2 2 2R20 A st  d A 6.28 cm  A st 5.359  cm f Steel V 10425: fyd  375MPa str Steel R 10505: fcd  17.0MPa yd

 1.602

L

SyIII  2.296L kN

 TIII 53.851  m

b d1  0.45m

b d  2  b d3  b py

fcttm  1.2MPa

fycd  375MPa

20 mm fssd  450MPa

fsscd  420MPa

Check the degree of reinforcement of the concrete cross section:

Input data: width of the shear cross section " b q" f

b avrge

122.5mm

height of shear cross

 stthe

A str

1 ctm  st.min  section " h q3" fydh q  280mm

b q  122.5mm

diameter of the bearing reinforcement of the support: " d s"  st  longitudinal 0.018  st.max  0.02

h py  b avrage

d s  20mm

preliminary design of the diameter of the stirrups " d ss " d ss  8  mm The actual depth of the compression part of the concrete: The depth of the compression part of concrete cross-section " xu " xu  0.014  m

Number of shear connectors on 1m of the beam:

 b d3  0.5  lst

q kr.II  L

h 1  b eff  h    h p1  zcgi.II  h p  S yII SyII  n II 2 

Cross Section III. stage: SyIII  VzII  SyII

VzIII 

2

A req  5.35  cm 

b d2 T 2  l n tr  PRd.x b d  0.825m

b d2  0.91m 1  n tr 6.367  m

xu

A str  fyd

420 d  MPa

xu 15.94 Cover reinforcement " tb" mm tb x22  mm u.lim 525 MPa  fyd b d  fcd

Cross-sectional characteristics: cross-sectional area " A b"

Composite Compositeslab slab Composite Compositeslab slab

xu.lim

104.81 mm 2

A b  h q  b q A b 0.034  m


233

- shear reinforcement coefficient

the distance of the centre of gravity of the drawn reinforcement from the edge of the cross-

s

section " ast "

bq, hq -the dimensions of the shear cross section

ast  tb  d ss  d s  0.5

ast  40  mm

Effective cross-sectional height " h e"

h e  h q  ast

h e  240  mm

Level arm of internal forces " zb "

zb  h e  xu  0.5

zb  233.189  mm

Qbu

1 3

 b q  h q   q  fctm

q

h  n  f  s

Shape cross-sectional coefficient "  f " Cross sectional height factor "  h "

We evaluate the shear from the external load:

 h 

1.4 

-at a distance h / 2 from the front of the supports for the pre-stressed elements, wherein h is

the height of the cross-section near of the support

1.0 if h q  0.6m 2 3

 h  1.213

1

 hq  m

Coefficient of normal force in the cross-section "  n"

- in the support post (column) for the frame members

Shear reinforcement coefficient "  s ":

- to the Qred value for the beam elements Reliability condition (shear resistance) of structure:

s

1  50 b   stw   stmin

 stw

- shear reinforcement consisting of reinforcement intersecting the shear crack

 stmin

- the minimum degree of the longitudinal reinforcement

Sabah Shawkat ©

Qu

- the transverse force on the bearing capacity in the examined section

kp  0

Qd

- transverse force from external extreme load qd

Area of tensile concrete reinforcement in the band 0.25*h from the tension chord of the

Qd

- increase or decrease the transverse force Qd in the section of the variable height

cross section " A st "

2

A st  5.359cm

2

A sw  0cm

element if the height does not change Qd = 0 Qpd

- the calculating transverse force on an oblique or curved pre-tensioning reinforcement

Area of longitudinal reinforcement in the band (+)(-)0.25h about the middle of the cross

Qbu

- load capacity of concrete

section height " A sw"

Qssu - bearing capacity of the stirrups

 stw 

Qsmu - load capacity of shear mesh Qu  Qd  Q d  Qpd

Qd  145.154  kN

Q d  0kN

 stmin

Qpd  0kN Qu

A st  2  A sw  kp  A p bq  hq 1 3

Qbu  Qssu  Qsmu

Load-bearing capacity of concrete in an inclined shear crack:

 stmin 

1 3

fctm A st

kp  A p  Rpd  p0t2  fyd  A st  kp  A p A st  kp  A p

fctm

A st

3

  stmin 1.067  10

fyd  A st  kp  A p

h

- Load-bearing capacity of concrete in an inclined shear crack: h > 0.6m...h = 1.0

f

- cross section shape factor, case for us f = 1.0

Coefficient of effect of anchoring the longitudinal tensile reinforcement Ast behind the oblique

n

-coefficient of normal force in cross-section

shear crack "  b"

Composite slab Composite slab


226 234

Determination the maximum the extremeb is chord the sheet: - if the reinforcement is anchored to lbd stresses then thein coefficient equalof"1.0" M plech with

- if reinforcement is not anchored lbd but ls is then a coefficient b calculates: M m.max M sheet M md.max  fy   M sheet      W y.a M W y.a W y.a  W y.a ls  M 

The force they have to carried by stirrups " Qs":

fy

 b 

1.0 if lbd  ls

b

b  1

ls  kN m M sheet  20.50 if l  ls lbd of bd Determination M slab at

1 m linear:

M slab

 s  0.728 M slab 53.80 kN m

 s  50   b   stw   stmin

lbd

M p.max  M sheet

n

f

concrete cross-section " Qbu"

1

Qbu   b q  h q   q  fctm Q bu Design of reinforcement to concrete ribs slab: 3 Qu  Qd  Q d  Qpd Input data: M doska.0.75

c  cmax if cof the cmax c  0.233m d  220mm Effective height concrete cross section: if c  cmin The depthcmin of the compression part of the concrete c otherwise   0.0774 x    d

s

MLoad 40.35of kNnon-reinforced m capacity slab.0.75

410MPa

Distance from the edge cross-section of the reinforcement: The minimum lengthofofthe theconcrete shear crack " cmin": along cmin the zb axiscmin  0.233m

 s  1

should berecalculated        to a width of 0.75m. h

Qs  Qd  Qbu Qs  128.507kN fyd  356.522  MPa fctm  1.2MPa 1.15 1.2   n  b q  fctm 2 4 c  d c  2.214  10 m Length of shear crack " c": fcyl Qs f  17  MPa fycd  356.522MPa  fcd  0.85  cd 1.5 0.18  fcd  h q Maximum length of shear crack " cmax": cmax  cmax  0.588m  q  fctm

fyd 

f cyl  30  MPa

ThePartial reinforcement will be designed in one rib, the 750mm, the moment coefficient" f  1 ribs  nare  1spaced  b apart 1 by s 1 q" :  h  1.213 q

SimpleCharacteristics: design of shear reinforcement: Material

x u  0.8  x

x  0.017m

xu  0.014 m

The force to be carried by the "n" shear stirrups " Nss ": Nss  A ss  fssd  Nss 45.239  kN

 16.647 kN

M dim

 

c b Nss0.825m

2 of the stirrups: s d Distance s b d  d  fcd

2.5  Qbu  41.617kN M dim M slab.0.75  40.351  kNm

Qs

d  0.22m s s  82.091  mm

  0.059

  0.01737

Sabah Shawkat ©

M dim

 40.351

h py  280mm

 

 floor s s  A req  b d ss d  cm fcd

kN  m

b py  75mm

Bearing capacity of stirrups:

l  7000mm

h d  75mm

The proposal on the minimum degree of stirrups:

l Minimum  7 m l st degree  750ofmm reinforcement lstThe  0.75m simplified  ssmin 

2

4  fssd

b d  xu  fcd  A stQ u  Qbu  Qssu fyd

4

  q.1

b avrge

4 if 450mm  b q  2  tb  d ss  900mm

s s  400mm

s s.max  0.18m

ss

 2   0.13 b s

ssmin

q

s s.max  min 0.75  h e 400mm

s s.max  0.75  h e

 1A  6

b dI

min b d1 b d2 b d3

2

2

A ss  0.25    n  d ss  A ss 1.005  cm  b d3  0.5  lst b d3  0.375m b d  2  b d3  b py

0.75h e  0.18m s s  s s.max

2b  b d1   1  h d  bbd1  0.45m   2  l ssmin  q  s s 0.147  cm d2

s

Q ssu

 131.865 kN

2 Q u 5.359  148.512   cm A st

kN 2R20

A str

2

6.28 cm

d

Qbu  16.647  kN

20 mm

 st.min 

122.5mm

1 fctm

3 fyd 18MPa if fcd  18MPa A str  st fcd otherwise  st  0.018  st.max  0.02 h py  b avrage 1 Qumax   b q  h q  fcd Qumax  194.367kN 3 Rbd 

Structural principles for the positioning of the stirrups:

Effective "bd:": The areasheet of thewidth stirrups

ss

Check the degree of reinforcement of the concrete cross section: Assessment of limit capability of pressure diagonals: fcd  18MPa

n=2

2 if b q  2  tb  d ss  450mm

s s  0.75  h e

Nss  c

 ssmin 6.667  10

The number of cuts relative to the width of the beam: n 

Qssu 

The required reinforcement area will be: Load capacity of the reinforced concrete cross section: Qd  145.154  kN

stirrups "  ssmin"

method of calculation is considered beam:

fctm

2 s s  0.08m A req  5.35  cm 

b d2  0.91m

Q d  145.154 kN

The actual depth of the compression part of the concrete: xu

A str  fyd b d  fcd

xu

15.94 mm

xu.lim

420 d  MPa 525 MPa  fyd

xu.lim

104.81 mm

We fasten the shear reinforcement at the top edge of the mesh slab.

b d  0.825m

Composite Compositeslab slab Composite Compositeslab slab


235

Composite Steel Concrete Ceilings

a) Reinforced steel profile 11 002R, reverse (concrete filled with narrow ribs)

Design and evaluate the composite steel-concrete ceiling on a span L, including the assessment of the sheet metal profile as a lost formwork. The distance of the ceilings is L1, the thickness of the concrete slab is h, the imposed load on the ceiling v, the ceilings are not supported during the construction.

b s1  84mm

b s2  116mm

4

b s1  s 4

3

Ia  131  10 mm

Characteristics of materials:

h 2  80mm

 s  63.1  mm

h 2  80mm

3

h 2p 

W ael  28.72  10 mm

 h  h 1  h 2p

2

h2 h 2p  0.02942m

b s1  b s2

h 1  50mm

3

h  0.07942m

 b  25kNm

PENV 1994-1-1 – Concrete C25/30 f ctkom  1.40  MPa

fcko  10  MPa

 fck  20  MPa

2

 fctm  fctkom 

 fck     fcko 

3

fctm  2.22  MPa

Scheme for calculating the mean thickness of the concrete slab

 c  1.5

 0.7  fctm fctk005

fctk005  1.56  MPa

fctk095  1.3  fctm

fctk095  2.89  MPa

 Ecm  29  GPa

Dead - profile 12 101

Sabah Shawkat ©

Limit bending stress for concrete in compression: fcd  0.85

fck c

Steel 235: fyp  235MPa  mo  1.1

Span:

L  7m

. The load is considered to be on width b of sheet profile: b = 1m

gosvsz  0.1133  kN  m

fcd  11.33 MPa

  1.35

godvsz  gosvsz  

g 0.15  kN  m odvsz

2

The self- weight of the concrete mix (the measured rib thickness):

fy  235MPa

fu  360MPa

 M1  1.1

 a  1.15

g osc   b  h

E a  210 GPa

h def 

L 24

gsstale  gosvsz  b  gosc  b

godc 2.68  kN  m 

vs  1.50  kN  m

gdstale  godvsz  b  godc  b

1

g 2.83  kN  m dstale

2

 v  1.5

Mael  Wael  ULS assessment: 

1

fyp a

vd  vs   v

 vd 2.25  kN  m

2

Mael  5.869  kN  m

We calculate the elastic moment according to the old standard: Rd  190  MPa 

Mel  Wael  Rd

Mel  5.46  kN  m

The ratio between the old and the new standard is 7%: L1  2.0m Steel concrete ceiling

2

Live load during concreting:

h def  0.29167m

Scheme of ceiling loading

godc    gosc

  1.35

gsstale  2.1  kN  m

L1  2.5m

2

 g2  gdstale  vd  b

Composite slab Composite slab

g3  gdstale  vd  b

g1  g3

Mael Mel

 1.08

L2  2.0m

L3  2.0m

 g1 5.08  kN  m

1


226 236

L L Material Characteristics: Profile 12 102: g osvsz  g osvsz 1 2   2 

Bending moments themaximum supports: stresses in the extreme chord of the sheet: Determination with the M plechabove Given

3

3

3

3

fy M m.max M md.max L1 M sheet L2 L2  L3  fy M c L2 g 1   g 2  2M b L1  L2  M M a L1  M b L2 g 2  g 3W  2M c L2  L3  M d L3 sheet 4  4y.a M W y.a 4 W y.a4 M W y.a    Mb  Mb  2.03  kN  m Mc  2.03  kN  m    Find  Mb Mc  Mc  20.50 kN m M sheet

m1 

53.80 kN m

1 2  g1  L1  8 2

 Ma  Mb    2  

fcyl L  L1  2   0.85  fycd  356.522MPa fcd  1.51.35  gosc  gosc   

1 40.35 kN2 m m3   g3  L3  8

 Mb  Mc   

m2  0.51  kN  m

 Mc  Md    2  

m3  1.53  kN  m

Input data:

 gosc 3.97  kN  m

Mb  2.03  kN  m

M doska.0.75

 40.351

h py  280mm

Mael  Mb M dim

 40.351  kNm

gosstale  gosnosnik  gosvsz  gosc

Mel  Mb  Mel 5.46  kN  m

gosstale  4.56  kN  m

1

d  220mm

1 The gdepth compression of the concrete  the godnosnik  godvsz part  godc godstale  6.15  kN  m odstale of

 L1  L2    2 

dim

 

x u  0.8  x

x  concreting: d x  0.017m during

vs  vs   M

 v  1.4

vd   v  vs

b d  0.825m

2

b d  d  fcd

xu  0.014 m

vs 3  kN  m 

d  0.22m

1

1

 vd 4.2  kN  m

  0.059 2

M sd   g odstale  v d L 8 2 A req  5.35  cm M sd  W  module:  fy 

Maximum bending moment:

M slab.0.75

A req    b d  d  fcd

kN  m

b py  75mm

Required cross-sectional

l  7000mm

h d  75mm

suppose IPE 270 TheWe required reinforcement area will be:

l st  750 mm

Assessment of the SLS (deflection only from dead load)

The calculation of bending moment over supports due to dead load: 1

2

 gsstale  L1

10 1 2 M2   gsstale  L2 16

Mb  0.84  kN  m

M1 

1

11

M2  0.52  kN  m

alebo

  0.01737

xm  L1

1

33

16

xm  0.84307m f 

g sstale L1

4

 st The

185Ea Ia

1

Max."bthe": allowable deflection will be: f  L1 fmax  0.008m Effective sheet width b dI min b d1 b d2 b d3  max d 250 a) Beam:

Load:

 b d1   1  h d Construction stage - the

b d1  0.45m

steel beam

Dead – self-weight (we suppose IPE 270)

 b d3  0.5  lst

b d3  0.375m

gosnosnik  0.361  kN  m

1

a

b d  2  b d3  b py

  1.35

b d2   2  l

f  fmax

b d2  0.91m

 Msd 63.42  kN  m 3

W  0.00031035m

6

4

Iy  57.9  10 mm 2 A str 6.28 cm

MplRd  98.9  kN  m

 A  4590  mm d

MplRd  Msd

M  Msd

A str

stress on the beam in extremecross-sectional fibres:  stthe  0.018 st.max  0.02

h py  b avrage

1 2  godstale  L  M 37.69  kN  m 8

The actual depth of the compression part of the concrete: xu

M A str  f yd  d  MPa hnmon  87.86462MPa 420  Rd  hnmon xu.lim xu hnmon 15.94 mm W 525 MPa  fyd b d  fcd ely dnmon  hnmon dnmon  87.86462MPa

b d  0.825m

1 godnosnik    gosnosnik godnosnik  0.49  kN  m

Composite Compositeslab slab Composite Compositeslab slab

20 mm

Msd  63.42  kN  m

Check the degree of reinforcement of the concrete cross section: or

M 

 2  0.13

Wply  fyp

1 fctm

f  0.00066m

 1  6

MplRd 

  b avrge 122.5mm  M  Wely  Rd  M st.min 90.09 3kN fyd m

Maximum deflection at first span: xm  0.422L1 xm  0.844m

ULS:

2

 gsstale  L1  M1 0.76 m  kN

1

   1.15

3 3 3 3 xu  f10 d 484 cd mm W  429 2 10 mm W b 2R20 A st ply  A st ely 5.359  cm fyd

lst  0.75m

Mb  

1

1

Sabah Shawkat ©

M dim

l  7m

 17  MPa

Effective height of the concrete cross section:

Live  0.0774 loads

Design of reinforcement to concrete ribs slab:  Mael 5.87  kN  m

f

fctm  1.2MPa

cd  g   godc osc

2

godc 5.36  kN  m 

m1  1.53  kN  m

m2 be  recalculated  g2  L2  to  a width of 0.75m.  should 8 2 M slab.0.75

fyd  356.522  MPa

Distance from the edge of the concrete cross-section along the axis of the reinforcement:

The reinforcement will be designed in one rib, the ribs are spaced apart by 750mm, the moment 1



1.15 Concrete load due toydself-weight:

Determination of M at slab at 1 m linear: M slab Bending moments the mid-span of the beam:M p.max  M sheet M slab

f

f cyl  30  MPa

g odvsz  g osvsz 

410MPa

Rd 104.81 210MPa xu.lim  mm

2


237

Assessment of cross-section:

4

SLS: Deflection due to dead load: Maximum deflection: fmax 

L

f 

5 g osstale L

fmax  0.028m

250

f  0.01172m

Ea Iy

384

Carrying capacity of steel beam in shear: 2

t w  6.6mm h  270mm

f  fmax

VplRd  A v

2. The load due to service stage transfers to the composite beam

A a  4590mm

fy

2

A v  1.04h t w

A v  0.00185m

VplRd  218.65048kN

3 a

Load: Dead – Self-weight (estimate IPE 270): 1

  1.35

g osnosnik  0.361kNm

g 0.23  kN  m osvsz

g odnosnik   g osnosnik

1

godnosnik  0.49  kN  m

1

VSŽ 12 101: gosvsz  gosvsz

godvsz  gosvsz  

  b  24  kN  m

3

Self-weight of concrete:  gosc   b  h 

Scheme of composite beam

 L1  L2     2 

0.5VplRd  109.32524kN

Qd  0.5VplRd

Effective width of the slab:

b eff  2

The beam is suitable

Sabah Shawkat ©

 gosc 3.81  kN  m

godc  gosc  

  1.35

1

 godc 5.15  kN  m

gosstale  gosnosnik  gosvsz  gosc gosstale  4.4  kN  m

1

godstale  godnosnik  godvsz  godc

1

godstale  5.94  kN  m

vsdl  0.75  kN  m

 L1  L2     2 

determined as the smallest value of the terms: b B

 s  1.4

vddl  vsdl   s

 vddl 2.1  kN  m

 2  L1  L2  vsuzitne  2  kN  m     2 

vduzitne  5.6  kN  m

 s  1.4

vduzitne  vsuzitne   s

1

B  2m

B  L1

b  0.3L

gs  gosstale  vsdl  vsuzitne

gd  godstale  vddl  vduzitne

1

1

 gd 13.64  kN  m 1 2 Maximum bending moment:   gd  L Msd  83.54  kN  m Msd  8

Maximum shearing force:

Qd 

1 2

gd L

L  7m

0.3L  2.1m

for one row of composite connectors on the beam b  12 h 1  h 2p  b n

b 12 h 1  h 2p  b n  0.95304m 

953  mm

When joining a concrete slab with a steel beam, the condition can be considered: b s1  s

In sum:

 gs 9.9  kN  m

1

b n  0m

- Service:

b eff  1.75m

8

The effective width of the plate-shaped perpendicular to the longitudinal axis of the ceiling is

1

Live load - long-term: floor, ceiling 2

L

h 1  kh.2 

1 200

H

H  h1  h2  h

Qd  47.73887kN

Composite slab Composite slab

kh2

h 2p

H  0.4m

h 2p  1 200

2

h2

b s1  b s2

H  0.002m

h 2p  0.02942m h 1  h 2p 

1 200

H

h 1  h 2p  0.07942m


226 238

Determination Mplech with the maximum stresses in the extremefy chord of the sheet: Aa Position of the neutral axis ( shear capacity):

fy

M

M m.max W y.a

M sheet

M sheet 

W y.a

a

x 

x  0.04729m

M md.max fck   fy 0.85   W y.a    b effW y.a c   M

M slab

M slab

410MPa Assessment of the deflection of the composite beam under the assumption of an elastic action. f

f cyl  30  MPa



f

 356.522  MPa

f

 1.2MPa

yd yd ctm 1.15 An effective modulus of elasticity of concrete is considered with the effect of creep of

concrete: fycd  356.522MPa

M sheet  20.50 kN m

Determination of M slab at 1 m linear:

Material Characteristics: SLS Serviceability limit state:

fcyl E´c cm  fcd 0.5E 0.85 1.5

E´c  14500MPa f cd  17  MPa

Ea

M p.max  M sheet

n´  14.48276 Working coefficient: n´  E´c Distance from the edge of the concrete cross-section along the axis of the reinforcement:

53.80 kN m

Ea

The reinforcement will be designed in one rib, the ribs are spaced apart by 750mm, the moment should be recalculated to a width of 0.75m. M slab.0.75

n k  d  220mm - for short-term n k  7.77778 Effective height ofeffects the concreteEcross section: b  27GPa

The depth of the compression part of the concrete - for long-term effects   0.0774

40.35 kN m

x    d E´b 

 cr  3

Stress distribution in cross section. Design of reinforcement to concrete ribs slab: Input data: M doska.0.75  40.351  kNm slab.0.75 x´  The depth of compression area according M todim old M standard:

M dim

 

x u  0.8  x

x  0.017m

1 1   cr

E´b  6750MPa

Eb

b  0.825m - according 2 to PENV 1994-1-1d

A a Rd

Eb

n d 

d  0.22m

xu  0.014 m

Ea

n d  31.11111

E´b

  0.059

  0.01737

b d  d  fcd

Sabah Shawkat ©

M xdim

 40.351

 0.52991

b fcd

x´  0.08924m

kN  m

x´ 7000mm h pyThe  280mm  75mm 75mm pythe d the influence bof thicknesshof concretel slab and of

l terms 7 m of l st coefficients  750 mm :

 

lst  0.75m

1

H  1   600   0.002 mm 

the reinforcement is calculated in   0.71429

E 2 a Epretv  13500MPa pretv  A req   0.5E b d b d  Efpretv A req  n5.35 cm  cd Epretv

To simplify calculations, thewill average The required reinforcement area be: value of the modulus of elastic modulus can be 1 1 considered: gosstale  vsdl 5.9  kN  m vsuzitne  4  kN  m b d  xu  fcd

A st 

fy a

h  x    2 

n 

MplRd  231.07 kN m

Msd  83.54 kN  m

MplRd  Msd

 1  6

 b d3  0.5  lst

b dI

x´ 

2

min b d1 b d2 b d3

b d1  MplRd b d1  0.45m 1  hd 1.06365 satisfies M plRd´ b d3  0.375m

MplRd´  217.24  kN  m

b d  2  b d3  b py

A str

2

6.28 cm

d

b d2   2  l

b d2  0.91m

20 mm

n  21.68

 st

A str

h py  b avrage

h1 1 fctm  h 1  h 1  h 2  h 1 b eff A 3 fyd a  2 n´ 2  (SLS): e  1 Aa  h 1 b eff  st  0.018  st.max  0.02 n´

 st.min 

e  0.12861m

The actual depth of the compression part of the concrete:

 2  0.13

Beam IPE 270

122.5mm

Neutral Axis Position

MplRd´  Aa  Rd  h  According to old standard:   M 83.54  kN  m

gosstale  vsdl  nd  vsuzitne  nk gosstale  vsdl  vsuzitne

2R20

Check the degree of reinforcement of the concrete cross section: b avrge

Beam IPE 270 is satisfactory

sd Effective sheet width "bd":

2

 A st 5.359  cm

fyd

Bend assessment (at load bearing moment) according to ENV 1994-1-1 M plRd  A a 

n pretv  15.55556

xu

A str  fyd b d  fcd

b d  0.825m

Composite Compositeslab slab Composite Compositeslab slab

xu

15.94 mm

xu.lim

420 d  MPa 525 MPa  fyd

xu.lim

104.81 mm


239

the average value of the ratio of elastic modulus: n  21.68327

b  0.953m

A bi 

PENV 1994-1-1 A bi´  h 1

b

2

2

A ik  10716.42857mm

The effective area of the welded mesh is neglected:

 h1  h b h 1   A a   h 1  h 2 n pretv  2  2  1

e´ 

1 n pretv

e

e´  0.16894m

b h1  A a

PENV 1994-1-1

h

2

2

A i  A bi  A a

A i  6787.54646mm

2

The average value of n:

Sabah Shawkat © 2

 h 1  h 2  e´ 

2  h   1 b h 13  b h 1  e´  1   n pretv  12 2  

1

Ii  0.0002094m

4

Ii´  0.00016436m

4

5

 vsdl  vsuzitneL

384

Ea Ii

5

 vsdl  vsuzitneL4

384

Ea Ii´

f  0.00391m

Ii

Ii´

fmax 

L 300

h

2

 h2 

h1

Syd  A bid rbo  A a 

h

h

2

b h1 nd

f  fmax

A bik 

h 2  0.08m

rbo  240mm

2

h h Syk  A bik rbo  A a     2 2

fmax  0.02333m

2

h 1  0.05m A a  0.00459m

centre of gravity of the steel part of the cross section of composite beam:

 Syi  A bi rbo  A a  f´  0.00498m

b  0.953m

Distance of centre of gravity compression area of the concrete part of the cross section of the

 1.27405

2

Ideal concrete area: short-term loads:

long-term loads: A bid 

Static moment to axis y1:

rbo 

PENV 1994-1-1 f´ 

2

4

Deflection due to imposed load: f 

A i´  7653.21429 mm

 A i´  A bi´  A a

2 2  h1   h 11  3 Ii  Iy  A   h 1  h 2  e  b eff h 1  b eff h 1  e   n´  12 2 2  

Ii´  Iy  A 

A id  6121.60714 mm

 A id  A bid  A a

 0.76131

Moment of inertia of ideal cross-section:

PENV 1994-1-1

2

A bi  2197.54646mm

n

A bi´  3063.21429mm

n pretv

Location of the neutral axis: A ik  A bik  A a

PENV 1994-1-1

h1 b

h

2

h

3

Syk  1470342.85714mm 3

Syd  367585.71429mm

3

Syi  527411.14920767mm

2

PENV 1994-1-1

b h1 nk 2

2

Syi´  A bi´ rbo  A a 

h

2

A bik  6126.42857mm

h

2

Location of centre of gravity:

A bid  1531.60714mm

Composite slab Composite slab

3

Syi´  735171.42857mm

Short- term load:

rok 

Syk Aik

rok  137.20456mm


226 240

Long term load: Determination M plech with the maximum stresses in the extreme chord of the sheet: Syd M m.max M sheet rod  rod  60.04726mm  A id  M W y.a W y.a

fy

Syi Mrmd.max  ro   fy o  77.70277mm M sheet Ai    W y.a M W y.a  

f 30   MPa cylW ybhk

H

M slab

M slab

 rok

410MPa 1.15

3

fyd  356.522  MPa W ybhk  1635774.64736 mm

fctm  1.2MPa

fcyl  fcd  0.85  1.5

cross-section of an ideal long-term:

M p.max  M sheet

h Distance the edge of the cross-section along the axis of the reinforcement:  y hd  from  rod y hdconcrete  0.07495m 2

The reinforcement will be designed in one rib, the ribs are spaced apart by 750mm, the moment

Effective height of the concrete cross section: d  220mm Section modulus: for The depth of the compression part of theIydconcrete W yodd 

n d  31.11111

should be recalculated to a width of 0.75m.

  0.0774 x    d 3 W yohd  1655016.90748mm

40.35 kN m

M dim beam: Composite

Design of reinforcement to concrete ribs slab: Input data:

2

fyd 

fycd  356.522MPa

53.80 kN m

M slab.0.75

Iyk h

f cd  17  MPa The distance of the lower part of the steel fibres from the neutral axis of the composite beam

PENV 1994-1-1 M sheet  20.50 kN m Syi´ Determination of M slab 1 m linear: ro´  ro´ at  96.06048mm A i´

Material Characteristics: Composite beam:

 

W ybhd 

2

b d  d  fcd

3

W yohd 

W yodd  635989.75953482mm

y dd x  0.017m

x u  0.8  x

Iyd

xu  0.014 m

3

W ybhd  605251.99925704mm d  0.22m   0.059

b d  0.825m h H  rod 2

  0.01737

Sabah Shawkat ©

M dim

M doska.0.75

M dim

 40.351  kNm

M slab.0.75

 40.351 kN  m Schematic diagram of the neutral axis of the ideal cross section.

h py  280mm Moment of

b py of  the 75mm h d  75mm inertia ideal cross-section tol  y-y7000mm centre of gravity:

l  7 m l st  750 mm 2 2 Iyk  Iy  A a rok  A bik  rbo  rok  lst  0.75m 2

Iyd  Iy  A a rod  A bid  rbo  rod  2

Iyi  Iy  A a ro  A bi  rbo  ro 

composite b  x beam: f

A st   yh 

4

Iyd  124048057.758mm

2

4

2

2

4

Iyi´  163720223.436mm

2

 ro

y d  0.2127m

2

 A st 5.359  cm y h  0.0573m

2R20

2

A str

6.28 cm

d

Iyi 3 W yod  W yod  674637.99689334mm 1 fctm y d   st.min 3 fyd

A str 3  st W yoh  2504438.08776mm  st  0.018 h py  b avrage

 st.max

W yoh 

 0.02

composite beam:

composite beam: Short-term Effective sheet width "bd":  Section  2  0.13 for 1  6 Modules:

 b d3  0.5  lst

d u cd h f ydro 2

n  21.68327 b avrge 122.5mm

The distance of the lower part of the steel fibres from the neutral axis of ideal cross-section of

n k  7.77778

 yd 

h

y hk b2.20456mm dI min b d1 b d2 b d3

The actual depth of the compression part of the concrete:

 b d1   1  h d b d1  0.45m b d2   2  l Iyk 3 W yodk  W yodk  767968.55641mm y dk b d3  0.375m b d  2  b d3  b py b d  0.825m

20 mm

Section modulus value)offor: Check the degree of(average reinforcement the concrete cross section:

Iyi  143497369.508mm

PENV 1994-1-1 Iyi´  Iy  A a ro´  A bi´  rbo  ro´ 

of composite beam:

2

A reqof the 5.35steel   cm fibres from the neutral axis of ideal cross-section lower part

TheThe required reinforcement be:steel fibres from the neutral axis of ideal cross-section of distance of the upperarea part will of the

4

Iyk  209044542.292mm

2

A req  distance   b d  d of  fcd The the

Iyd y hd

b d2  0.91m Iyk W yohk  y hk

Iyi W ybh  A str  fyd h H  xro xu u 2 b d  fcd

3

W yohk  94823742.04082mm

Composite Compositeslab slab Composite Compositeslab slab

15.94 mm

3

W ybh  766147.83983007mm 420 d  MPa xu.lim xu.lim 525 MPa  fyd

104.81 mm

Iyi yh


241

PENV 1994-1-1 W yod´ 

Iyi´

3

yd

Composite beam:

Iyi´

W ybh´  H

SLS (Design value): Short-term: vduzitne  5.6  kN  m

h 2

8

3

W yoh´  2857384.52707mm

yh

3

 ro´

1

M1 

2

M1  34.3 kN  m

od  211.69847MPa

Rd  210MPa

od  Rd

not satisfies

oh  121.22261MPa

Rd  210MPa

od  Rd

satisfies

o´d  dnmon  d´ 

o´d  196.40241MPa

Rd  210MPa

Rd  o´d

 o´h  hnmon  h´

o´h  58.62704MPa

Rd  210MPa

Rd  o´h

satisfies satisfies

The stress in the concrete slab:

Mpr  83.54 kN  m

M pr

Sabah Shawkat © b 

Normal stress on the composite beam:

d 

M 1  34.3mkN

M1

h 

W yodk

d  44.66329MPa

Long-term:

stresses in the lower part of the steel beam where the steel beam is composite:

PENV 1994-1-1

1 2  vduzitne  L 8

M2  49.24 kN  m

 Mpr  M1  M2

n k  7.77778

the lower part of the steel beam in the construction stage where only the steel beam and the

oh  hnmon  h

  godstale  vddl  L

Short-term:

The total stresses in the bottom of the steel beam are calculated as the sum of the stresses in

 od  dnmon  d

1

godstale  vddl 8.04  kN  m 1

Check the stress at the bottom of the steel beam:

Iyi´

W ybh´  969105.52523959mm

Long-term:

M2 

W yoh´ 

W yod´  769713.64679246mm

d 

M2

h 

W yodd

  d 77.43  MPa

M1

b 

W yohk

h  0.36172MPa

M2

b 

W yohd

 h  29.75  MPa

M1

b  5.0289MPa

b  5.0289MPa

 ad   fcd

ad  8.09524MPa

According to NAD:

n k  W ybhk

b  2.69597MPa

n  W ybh

b´ 

M pr

b´  5.54183MPa

n pretv  W ybh´

b´  5.54183MPa

b  ad

satisfies

M2

nd  Wybhd

 b  2.62  MPa

Average value: d 

M pr W yod

d  123.83384MPa

h 

M pr

W yoh

h  33.35799MPa

b 

M pr n  W ybh

b  5.0289MPa

Calculation of composite:

PENV 1994-1-1 d´ 

M pr W yod´

d´  108.53779MPa

Resulting cross-sectional stress.

For joining a reinforced steel sheet with steel beams, the steel connectors are welded together h´ 

M pr

W yoh´

h´  29.23758MPa

b´ 

M pr n pretv  W ybh´

with parallel welded profiled trapezoidal sheets. s  0.0631m

b´  5.54183MPa

Composite slab Composite slab

h 2  0.08m

Rt  110MPa

m  1

r3  200mm


226 242

Material Characteristics: The spacing of the shear connectors will be half the width of the beam:

Determination with 2h 2 sheet: 4r3 of M h2 h 2 the maximum stresses in the extreme chord X the d  if 2  1.0 plech 2  2.53566 then s M m.max

fy

 Rt m s

s

L at  0.5 f MPa trnov cyl  30  N

M sheet

M md.max  fy     M    W y.a 2  MMaximum W y.a bending W y.amoment: M  1 g sheet  W y.a sd dL  M Msd= 83.54 kN m 8 M sheet  20.50 kN m

1

Maximum shearing force: Qd  g d L Qd  47.73887kN Determination of M slab at 1 m linear: 2 M slab M p.max  M sheet M slab

PENV 1994-1-1

Qmin  0kN

d  0.02m

 v  1.3

Qd  Qmin

4 x    d

Decides: 2

PRk2 M0.29d fck Ecm dim   2 b d  d  fcd

2

Vpriem  23.86943kN  40.351  kNm

A b  h 1 b A b  0.04765m M dim M slab.0.75

p

o

Load capacity in full slab: Effective height of of the the connector concrete cross section: PRk1  0.8fu

40.35 kN m

r

PRk1  77.9115kN

X

 1.31327m

x  0.017m

x u  0.8  x

PRk2  88.34297kN

PRk1  77.9115kN d  0.22m

b d  0.825m

2

d  220mm

2 The depth of the compression part of the concrete PRk1 d

  0.0774

Average value of horizontal shear force Design of reinforcement to concrete ribs slab:

xu  0.014 m PRd    0.059

PRk1 v

PRd  59.93192kN   0.01737

Sabah Shawkat © 2 M doska.0.75

2 h py  280mm

2 b py  75mm

l st  750 mm

The required reinforcement area will be:

is determined depending on the construction procedure. For beams without temporary supports

lst  0.75m

in the construction stage: X 

A st 

kN

kt 

Total horizontal shear force transferred by one shear connector: X r3

4r3 X 2h 2

 0.01866m

1 m

 11.86526kN

The area of one connector: A t  

d  20mm

U

2

d

2

4

2h 2

r3

U "b13.62862kN A t Rt width U  sheet Effective b dI d":

 68.14311m kN min b d1 b d2 b d3

 1N  6A R 2  0.13 b963.9kN  0.45m Nael   d1   1  h d Nb bd1Nael ael a d

U

b d3  0.375m Ntrnov  70.72615

2R20

A str

r3

X

b d2F   2N l ct

b d  2  b d3  b py

kt  0.27606

PRdr  PRd kt

fcd 1 f kNkt 1 ctm  st.min MPa 1000 3 fyd

b

b d2  0.91m

2

6.28 cm

A str

 st

 0.018

st half of the beam: st.max The hnumber of pins on one py  b avrage Qd

  2.01MPa

xu

A str  fyd Ntr n b d  fcd PRdr

b d  0.825m

Composite Compositeslab slab Composite Compositeslab slab

xu

15.94 mm n  13.42

d

Ntr 

 0.02

1

L

s

xu.lim or

420 d  MPa

Ntr f 525 MPa yd n  Ntr1

20 mm

PRdr  16.54496kN

Ntr1  11.37543kN

2 x of the compression part of the2concrete: The actual depth b o  H   2 

The number of shear connectors on one half of the beam:  b d3  0.5  lF stct Ntrnov  U

2

A t  0.00031m

 

1

0.7 b o h t  h p

d Ntr1  30.6 b avrge 122.5mm2 mm

Carrying capacity of one shearing connector: s

2

 A st 5.359  cm

f

h h p reinforcement of the concrete cross section: Check the Ndegree of r p

The required diameter of the shaft:  Rt m s

b d  xu  fcd

yd resistance of the ribbed slab: The reduced

1

X  59.32631m

n Iyi

A req  5.35  cm 

l  7000mm

h d  75mm

The horizontal shear force per unit length of the steel and concrete sections of the cross section

Vpriem A b rb

2

A req    b d  d  fcd

 h 40.351h 1  kN  m Mr dim  h2  rb  0.1623m   ro b  

l  7m

 17  MPa

fu  310  MPa

h t  h 1  h 2  10mm

2

should be recalculated to a width of 0.75m.

Vpriem 

f cd

fctm  1.2MPa

Distance from the edge of the concrete s  0.0631m N  1cross-section b  s along the axish ofthe h reinforcement: h  0.08m

The reinforcement will be designed in one rib, the ribs are spaced apart by 750mm, the moment

Input data:

fyd  356.522  MPa

fcyl fycd  356.522MPa  fcd  0.85  Connector of diameter: 1.5

53.80 kN m

M slab.0.75

at  0.04949m 410MPa fyd  1.15

Ntr  221.98kN

xu.lim 104.81 mm n  19.51


243

b

2  bm 

b

with

sheet

perpendicular

to

profiles

its

located

longitudinal

3

 bk  2  bm   6 

bk  2  bm  h

    h1  k  h2  

 bm

Beam

l 10

2

Effective width of the concrete beams of the

b

edge beam (sheet profiles placed parallel to the beam axis).

axis The position of the profiles in the sheet plate

(1 - steel beam, 2 - sheet profile, 3 - concrete

B 2

 bm

slab, 4 – shear connectors). 12.7 15.8  d 0.4 0.5  D 25.0 31.3   hD 8.00.3 8.00.3   d 3.0 0.1 4.0 0.1  1   0.2  0.2 1.5  v 1.5

   0.3  12.0   0.1  4.0   0.2  1.5  18.2

0.5

31.3

Inner and outer beams with sheet profiles perpendicular to the longitudinal axis of the beams (1 - inner beam, 2 - end beam, 3 - sheet profile, 4 - concrete slab, 5 – shear

 

bs 

bs 

h

b  bs   12 

h

   h1  k  h2 

Sabah Shawkat © connectors).

Effective width of the concrete beam of the Effective width of the concrete beam of the internal beam (sheet profiles perpendicular to edge beam (sheet profiles perpendicular to the longitudinal axis of the beam). the longitudinal axis of the beam).

b  6  h1  k  h2 

bn 2

b

bs   12 

   h1  k  h2 

Beam with sheet profiles parallel to the longitudinal axis of the beams (1 - steel

beam, 2 - sheet profile, 3 - concrete slab, 4 –

B3

shear connectors).

2

b  12  h1  k  h2  bn b

1 2

 B1  B2

b  0.3  l

Effective width of the concrete beam of the internal beam (sheet profiles arranged

Inner and outer beams with sheet profiles parallel to the longitudinal axis of the beams (1 -

parallel to the beam axis). b

inner beam, 2 - edge beam, 3 - sheet profile, 4 - additional sheet metal, 5 - ply profile, 6 -

0.3  l

concrete slab, 7 – shear connectors)

Composite slab Composite slab


226 244

Determination M plech with the maximum stresses in the extreme chord of the sheet: fy M

M m.max W y.a

M sheet

M sheet 

W y.a

M md.max  fy   W   W y.a y.a   M

Determination of M slab at 1 m linear: M slab

M p.max  M sheet Expansion of

concrete slab, 5 - thorn). The reinforcement will be designed in one rib, the ribs are spaced apart by 750mm, the moment should be recalculated to a width of 0.75m.

fyd  356.522  MPa

1.15

fcyl  fcd  0.85  1.5

f cd

Concrete slab (1 - sheet profile, 2 - pre- slabs, 4 – shear connectors, 5 - reinforcements Input data: M doska.0.75  40.351  kNm M dim M slab.0.75 concrete layer of concrete slab, in ribs made of two profiles, 6 - reinforcement M3dim  40.351 kN m plate within the in ribs made of two profiles, reinforcement at - reinforcement of the

 17  MPa

r1  3  d d  220mm

Effective height of the concrete cross section:

The depth of the compression part of the concrete x    d

M dim

 

d  0.22m

b d  0.825m

2

b d  d  fcd

r1  40  mm

x u  0.8  x

x  0.017m

Axis distance of the shear connectors

(1 - steel beams, 2 - sheet profiles, 3 - concrete

fctm  1.2MPa

Distance from the edge of the concrete cross-section along the axis of the reinforcement:

  0.0774

40.35 kN m

Design of reinforcement to concrete ribs slab:

r3  3  d

r2  1.5  d

r3  6  h

r3  40  mm

xu  0.014 m

  0.059

  0.01737

Sabah Shawkat ©

h pywidth  280mm of the l  7m

410MPa

Diameter of shear connectors

concrete slab (1 - beam, 2 -

sheet profile, 3 - additional sheet metal, 4 -

53.80 kN m

M slab.0.75

fyd 

f cyl  30  MPa fycd  356.522MPa

M sheet  20.50 kN m

M slab

Material Characteristics:

top l the 7000mm

b py  75mm h d  75mm effective width b).

lst  0.75m

Location

shear connectors). The–required reinforcement area will be:

the

additional

partition

Length of sheet profiles.

reinforcement (1 - addition reinforcement, 2

 2  0.13

b dI

 b d1   1  h d

Length of connectors (1 - beam, 2 - sheet

min b d1 b d2 b d3

b d1  0.45m profile,

Effective width of the internal beam of the concrete beam (sheet sections parallel to the

2  l b d2 40.91m 3 b d2 - concrete slab, – shear

connector).

 b d3  0.5  lst b d3  0.375m b d  2  b d3  b py beam axis) with additional sheet metal parts.

reinforcement of the slab, 5 – shear

2

2R20

2

A str 6.28 connectors ).  cm

d

20 mm

Check the degree of reinforcement of the concrete cross section:

 st

Effective sheet width "bd":

beam, 2 - profile, 3 - concrete slab, 4 -

 A st 5.359  cm

fyd

b avrge

– shear connectors, 3 - beam).

 1  6

b d  xu  fcd

A st 

of

2

A   5.35  cm

req (1 - beam, 2 panel profile Anchoring of the flashing profile to - sheet profile, 3 - profile, 4 - concrete slab, 5 reinforcement of the concrete slab (1 -

surface of the concrete slab, 9 -

additional partition reinforcement).

l st  750 mm

A req    b d  d  fcd Reinforced concrete

 st.min 

122.5mm

A str

1 fctm 3 fyd

 st  0.018

h py  b avrage

 st.max

 0.02

The actual depth of the compression part of the concrete: Cross-sectional area of the composite beam. xu

A str  fyd b d  fcd

xu

15.94 mm

xu.lim

420 d  MPa xu.lim 104.81 mm 525 MPa The  fydposition of the neutral axis of the cross-

section

b d  0.825m

Composite Compositeslab slab Composite Compositeslab slab


245

Reinforced concrete sheet with sheet metal profiles (1 - steel beam, 2 - sheet profile, 3 - concrete slab, 4 – shear connectors, 5 reinforcement in plate ribs, 6 - reinforcement

at the top surface of the concrete slab).

h

y

5

Ai

resp y

Neutral axis position of the cross-section (neutral axis in the concrete cross-section).

f t Rd

fy

fy

f yd

Mo 0.8 

fu v

v

 f ctk 0.05

0.7  f ctm

 f ctk 0.95

1.3  f ctm

M1

f ud

1.3  v

fu

Ii

f cd

0.30  0.85 

 f ck 3

f ck c

zo zc

1.25 ( EC4 )

nkr

E´c s

Up

c

1.3 d  t  Rp

yd

n Ii yc

1

M2

2

f ctm

5

 A s Ic

A ci

n

n

2 2   zc  Is  A s   zs

Sabah Shawkat © Wc

n 2

Wod

f yd

A ci

Ao 

Io  A o   zo 

Ii

ha

n

Ii

Woh

yh

Ii

Ws

zs

 A ci  zco  A s  zso

Ai

zco  zo zs Es Ec

ndl 1

1 

l

l

Es E´c

zso  zo

 Ec y

 0.00018 nd

h  x

Np Up

 n2   d2  1.1 Rt  n

1.5 d

Np nd  A t

c

l 2

 Vx c

nn  A t

  V

Vx

Composite slab Composite slab


-

Sabah Shawkat © Lightweight structures - Definition of lightweight structures - The art of tensegrity - Attachment of the stiffener to the steel beam - Detail of the support cables on the pylon - Detail of the support bearing cables on the pylon - Detail of the stiffener connection to column on the bar


-

Sabah Shawkat ©

-


248 248

Lightweight structures Lightweight structures Architects engineers executives of services to reap intellectual property of previous Architects andand engineers areare executives of services to reap thethe intellectual property of previous

constructions. clients' demands high nowadays, there a demand temporary, forfor temporary, constructions. TheThe clients' demands areare high nowadays, there is is a demand

generations. They studying, improving discovering. They creators new generations. They areare studying, improving andand discovering. They areare thethe creators of of new

transformable solutions offer sliding lightweight constructions ranging from simple transformable solutions thatthat cancan offer sliding lightweight constructions ranging from simple

spaces, forms structures constantly improving. This creative activity connects spaces, forms andand structures thatthat areare constantly improving. This creative activity connects

sliding marquee solutions staircases, which disappear pressing button (Khalifa sliding marquee solutions to to staircases, which disappear by by pressing thethe button (Khalifa

architects engineers their way to the of "Prof. Frei Otto. architects andand engineers on on their way to the art art of "Prof. Frei Otto.

International Stadium). Tensile integrity systems being developed today NASA International Stadium). Tensile integrity systems areare being developed today forfor NASA andand

Lightweight structures used in various forms variations seen in broad spectrum Lightweight structures used in various forms andand variations cancan be be seen in broad spectrum useuse

form unprecedented options blame. form unprecedented options forfor blame.

current market. These structures, developed over years, together with advances on on thethe current market. These structures, developed over thethe years, together with advances in in

Talking about modern systems steel, wire membrane merit. And these Talking about modern systems of of steel, wire andand membrane hashas its its merit. And thatthat these

material engineering technology, continue progress now integral material engineering andand technology, continue to to progress andand areare now an an integral partpart of of

systems at the of the current building options. Limits given physical properties systems areare at the toptop of the current building options. Limits areare given by by thethe physical properties

architectural creation. architectural creation.

laws material construction system. These must fully taken account andand laws of of thethe material andand thethe construction system. These must be be fully taken intointo account

Architectural lightweight structures now seen in different shapes sizes. They may Architectural lightweight structures cancan now be be seen in different shapes andand sizes. They may

used creation modern system. practice, most often encounter andand used in in thethe creation of of thethe modern system. In In practice, wewe most often encounter thethe

internal, external, permanent, temporary, large, small, supported, membranes filled with be be internal, external, permanent, temporary, large, small, supported, membranes filled with air air

following issues: following issues:

or stretched. New subgroups of these constructions - shell structures, tensile-integrity structures or stretched. New subgroups of these constructions - shell structures, tensile-integrity structures - are also very current. These unique forms have played important contemporary - are also very current. These unique forms have played an an important rolerole in in contemporary

• bars (struts) systems - stable problems of compressive bent bars, • bars (struts) systems - stable problems of compressive andand bent bars,

architecture, interior design various cultural events since time they first appeared in the architecture, interior design andand various cultural events since thethe time they first appeared in the

• cables systems - prestress, stiffness of the structure, necessity of solving theory order, • cables systems - prestress, stiffness of the structure, necessity of solving thethe theory II. II. order,

1960s world-famous German architect engineer Frei Otto. 1960s by by thethe world-famous German architect andand engineer Frei Otto.

• membrane systems - prestress, dynamic resistance, large deformation solutions. • membrane systems - prestress, dynamic resistance, large deformation solutions.

Sabah Shawkat ©

present, light constructions designed constructed independently geographic At At present, light constructions areare designed andand constructed independently of of thethe geographic

location. They transform space have subtle elegant quality. addition location. They transform thethe space andand have so so subtle andand elegant quality. In In addition to to

providing basic functions such shading shutdown, they important functional providing basic functions such as as shading andand shutdown, they areare an an important andand functional element construction amphitheatres, sports stadiums, airports, courtyards, building element in in thethe construction of of amphitheatres, sports stadiums, airports, courtyards, building facades, parks, seafront interiors. facades, parks, seafront andand interiors.

Designing lightweight constructions to meet criteria a complex task. Every is visible Designing lightweight constructions to meet all all criteria is aiscomplex task. Every partpart is visible constructive, relying proper functioning of all parts. example, diaphragm fabrics andand constructive, relying on on thethe proper functioning of all parts. ForFor example, diaphragm fabrics developed to meet requirements high tensile strength, long with a high modulus areare developed to meet thethe requirements forfor high tensile strength, long lifelife with a high modulus elasticity. surface layer applied material ensures fabric resistance against of of elasticity. TheThe surface layer applied to to thethe material ensures fabric resistance against weathering dirt, provides resistance to UV radiation non-combustible properties. weathering andand dirt, provides resistance to UV radiation andand hashas non-combustible properties.

Tensile membrane architecture a highly sophisticated medium offers unique qualities Tensile membrane architecture is aishighly sophisticated medium thatthat offers unique qualities forfor architects, designers engineers therefore provides unlimited opportunities design as well architects, designers andand engineers therefore provides unlimited opportunities forfor design as well as experiment with form create alternative solutions to every design challenges. as experiment with form andand create alternative solutions to every dayday design challenges. This is made possible fundamental flexibility lightweight nature composite This is made possible duedue to to thethe fundamental flexibility andand lightweight nature of of composite membranes. Membrane structures often referred to textile as textile structures. However, actual membranes. Membrane structures areare often referred to as structures. However, thethe actual membrane construction is far removed from classic tent. main difference is its exact membrane construction is far removed from thethe classic tent. TheThe main difference is its exact geometric shape. functioning membrane structure, exact geometric criteria geometric shape. ForFor thethe functioning of of thethe membrane structure, thethe exact geometric criteria must computed. basic criterion is maintain to maintain concavity convexity main must be be computed. TheThe basic criterion is to thethe concavity andand convexity of of thethe main directions membrane surface. Following principle, about basic four directions of of thethe membrane surface. Following thisthis principle, wewe cancan talktalk about thethe basic four types of membranes: types of membranes:

think it important to explore new trends in lightweight constructions, among which WeWe think it important to explore new trends in lightweight constructions, among which wewe

saddle-shaped (hyperbolic paraboloid) 1. 1.saddle-shaped (hyperbolic paraboloid)

include: cancan include:

ridge-valley shape 2. 2.ridge-valley shape

1. Lightweight designs designed with regard to sustainability 1. Lightweight designs designed with regard to sustainability

arch shape 3. 3.arch shape

2. Modular light constructions 2. Modular light constructions

conical shape, 4. 4.conical shape,

3. Sliding light constructions 3. Sliding light constructions Designers benefits mass production simple structures, such "umbrella" Designers seesee thethe benefits of of mass production of of simple structures, such as as an an "umbrella" thatthat reproduciblecomponents. components.Savings Savingsfrom froma modular a modularstrategy strategylead leadto tocost-effective cost-effective hashasreproducible

Lightweightstructures structures Lightweight Lightweight Lightweightstructures structures


249

with a specific shape. Thus, lightweight structures, in place of stiffness of the material, derive their resistance from their shape and may therefore be denoted as shape-active. One of the main design steps of lightweight constructions is therefore the design of a shape that is controlled by the required stress state. The specificity in the design of light structures is the fact that the result of the shape analysis (process shape search), the areas are curved in two directions, which are generally positively evaluated aesthetically and represent a very non-traditional form of revitalization of the public Another criterion of lightweight membrane construction is its prestress. The correct geometric

architecture in the Central European space. For this reason, the location of the planned

shape and prestress guarantees its stability, stiffness and dynamic resistance. At the same time,

workplace at AFAD is more than adequate. However, in many practical cases, in the world,

it allows the structure to resist the effects on which it was designed, rain, wind and snow.

lightweight and large-scale structures are the only structural layer of objects. Its role is, besides

The basic geometric shape of the membrane system emerges from the surface of the hyperbolic paraboloid

aesthetic criteria, to combine architectural, static and facade functions and, moreover, to provide a pleasant interior of the building. This step combines the role of architect and engineer, naturally deducting the requirement for multidisciplinary qualification of a designer. The unification of the role of architect and engineer in designing lightweight constructions is also a

Sabah Shawkat ©

top trend in top foreign workplaces and is known, for example, under the Archineer brand. The our archineer team aims to train such specialists, who will be able to apply in artistic and technical practice thanks to the interdisciplinary integration of knowledge.

The shell structures, once reinforced concrete, are now parameterized (Robotic Fabrications), converted to various non-traditional material concepts (Timber Shells). A great challenge for today's architects is global warming, membrane structures are increasingly seen in our territory and will be an integral part of sustainable climate solutions for public spaces, parks. We therefore consider this issue to be very topical and important. The ambition of the Engineering Cabinet is to prepare the basis for a new training program lightweight

construction,

which

is

not

yet

adequate

in

Slovakia.

Easy

constructions are specific by optimizing the built-in material. This is achieved by minimizing or completely eliminating bending stress. This special case can only be achieved on structures

Lightweight structures Lightweight structures

Lightweight structure-tensegrity shell


250 248

The naturestructures of the research and development of the project Lightweight Research will take place in a hybrid form of practical and theoretical approach. It will include Architects and engineers are executives of services to reap the intellectual property of previous analytical and design phase. generations. They are studying, improving and discovering. They are the creators of new

ParticipatingThe in workshops, lectures,are conferences and annotated will be for heldtemporary, constructions. clients' demands high nowadays, there istours a demand invited top professionals transformable solutions that can offer sliding lightweight constructions ranging from simple

spaces, formsIt and structurestothat are constantly improving. creative activity connects of Research: is necessary initiate a wide research activityThis focused on the concentration

sliding marqueeconstruction solutions tois staircases, disappear by pressing buttonbuilding (Khalifaand Lightweight one of thewhich popular architectural forms ofthetoday's International Stadium). Tensiletointegrity systems are being developed todayshape. for NASA and design. They appeal mainly their untraditional solutions and exceptional The concept

architects and engineers on theirdevelopment way to the artand of "Prof. Frei Otto. information on the historical the current state of the issue. Based on current research by researchers fromforms the foreign environment schools specializing Lightweight structures usedmainly in various and variations can beand seen in broad spectrum in usethis field. (ITKE University of Stuttgart Institute of Building Structures and Structural Design, on the current market. These structures, developed over the years, together with advances in ETH Zurich - Department of Civil, continue Environmental and Geomatic Engineering). Studies material engineering and technology, to progress and are now an integral part ofwill form the starting point for further research. architectural creation. Architectural lightweight structures candesign now be seen infor different shapes and sizes. They may Data Collecting: Collecting reliable methods light constructions will be confronted be with internal, external, permanent, temporary, large, small, supported, membranes filled with physical outputs in the form of models. The proposal methods will then be elaboratedairand or stretched. of these constructions structures, tensile-integrity structures presented New to thesubgroups professional public. The results- shell will be confronted at local and international - are also very current. These unique forms have played an important role in contemporary level. The Engineering Cabinet also has the task of elaborating and developing a generic architecture, interior design andlightweight various cultural events since time they firstboth appeared in theand methodology of designing constructions andthe offering it for academic

form options forisblame. of unprecedented lightweight construction particularly interesting for the needs of architects or designers from Form main of plussteel, of lightweight theirAnd ease,that airiness Talking aboutFinding. modern The systems wire and constructions membrane hasinclude its merit. theseand tremendous flexibility. Compared to traditional conventional designs, they make it easier systems are at the top of the current building options. Limits are given by the physical properties to withand a minimum number system. of support elements. Another significant advantage andoverlap laws oflarge the areas material the construction These must be fully taken into account is their design variability, which provides almost unlimited possibilities for searching and used in the creation of the modern system. In practice, we most often encounter thefor originalissues: and elegant forms. following

• bars (struts) systems - stable problems of compressive and bent bars, The main objectives of our project can be summarized as follows: • cables systems - prestress, stiffness of the structure, necessity of solving the theory II. order, - to focus on the field of design and implementation of light structures and to establish

Sabah Shawkat ©

1960s by the world-famous architect and engineerarchitecture. Frei Otto. commercial practice as anGerman alternative to contemporary At present, light constructions are designed and constructed independently of the geographic Lectures: They will be presented in an interactive way. Within lectures we will ensure a broad location. They transform the space and have so subtle and elegant quality. In addition to professional cross-section that will be guaranteed by professionals in the given field. providing basic functions such as shading and shutdown, they are an important and functional Workshops: The core of the research will be based on work with students of AFAD and CTU element in the construction of amphitheatres, sports stadiums, airports, courtyards, building in Prague. Than Practical lectures on lectures will be used by students to practice their new facades, parks, seafront and interiors. knowledge. Workshops will be led by lecturers who will direct students' thinking and creative Designing lightweight constructions to meet all criteria is a complex task. Every part is visible activity in the form of criticism and discussion. The outputs of the workshops will focus on and constructive, relying on the proper functioning of all parts. For example, diaphragm fabrics precise physical models, which will then be processed, analyzed and ranked in research outputs. are developed to meet the requirements for high tensile strength, long life with a high modulus

The collected input applied data willtobe the graphically and presented. Research of Exhibition: elasticity. The surface layer materialprocessed ensures fabric resistance againstthe work thatand willdirt, be provides taken from the workshops, the applied works and the work of the weathering resistance to UV radiation andsemestral has non-combustible properties. team of solvers, will be presented at the exhibition in the form of models and graphical outputs. We think it important to explore new trends in lightweight constructions, among which we

international cooperation in this field, resistance, large deformation solutions. • membrane systems - prestress, dynamic - to create a specialized training and consulting centre for both students and the professional Tensile membrane architecture is a highly sophisticated medium that offers unique qualities for public, focusing on activities related to the correct design and realization of lightweight architects, designers and engineers therefore provides unlimited opportunities for design as well structures, as experiment with form and create alternative solutions to every day design challenges. - present the results at local and international conferences and workshops as well as create This is made possible due to the fundamental flexibility and lightweight nature of composite online outputs and organize events with the participation of top experts in the field, membranes. Membrane structures are often referred to as textile structures. However, the actual - to compile a book publication on lightweight structures for both students and specialists. membrane construction is far removed from the classic tent. The main difference is its exact geometric shape. For the functioning of the membrane structure, the exact geometric criteria must be computed. The basic criterion is to maintain the concavity and convexity of the main directions of the membrane surface. Following this principle, we can talk about the basic four types of membranes: 1. saddle-shaped (hyperbolic paraboloid)

One of the main goals of the project is the book publication of all stages and canPublications: include:

2. ridge-valley shape

phases research. 1. Lightweight designs designed with regard to sustainability

3. arch shape

2. Modular light constructions Expert and Consultation Center: Creating a specialized expert group to serve as a source of 3. Sliding light constructions relevant information and consulting center in designing and constructing lightweight

4. conical shape,

constructions be oneofofmass the forms of final output andsuch willas bean a prerequisite for Designers see thewill benefits production of research simple structures, "umbrella" that phases ofcomponents. research on this issue. from a modular strategy lead to cost-effective hasfurther reproducible Savings

Lightweightstructures structures Lightweight Lightweight Lightweightstructures structures


251

The art of tensegrity The members of a tensegrity structure are either always in tension or always in compression.

thought of as sections of rigid tubing which maintain the separation of two points. The tensile

The tensile members are usually cables or rods, while the compression members are strut

members are continuously connected to each other and to the ends of the compression members

sections. Key contributions to the early development of tensegrity structures appear to have

while the compression members are only connected to tensile members and not to other

come from several people. Some historians claim Latvian artist Karl Ioganson exhibited a

compression members.

tensegrity prism in Moscow already in the year 1920. Ioganson’s work was destroyed in the

The results of our design process are presented also graphically. In order to determine the

mid-1920’s by the Soviet regime, but photographs of the exhibition survived. The word

equilibrium position the lengths of the struts are specified, which are assumed to be all the same,

“tensegrity” (a contraction of “tensile-integrity”) was coined by the American entrepreneur

together with the stiffness of the top ties (assumed equal), bottom ties (assumed equal),

Buckminster Fuller. In the article "Snelson for the invention of Tensegrity" in Lalvani96,

connecting ties (assumed equal).

tensegrity pioneer Kenneth Snelson also quotes Russian constructivists whose members were loganson as inspiration for his work. Kenneth Snelson also remembered David Geiger's "Cabledome" technology and Matthys Levy's space triangulated tensegrity dome technology, which provided many creative and practical applications of tensegrity in practice. Campbell94 discloses a description of these two compositions which are dependent on the peripheral anchor for their structural integrity.

The qualities of tensegrity structures which make the technology attractive for human use are their resilience and their ability to use materials in a very economical way. These structures very effectively capitalize on the ever increasing tensile performance modern engineering has been able to extract from construction materials. In tensegrity structures, the ethereal (yet strong) tensile members predominate, while the more material-intensive compression members

Sabah Shawkat ©

All tensegrities are prestressed under tension; they are self–supporting and independent of

gravity. But the weight of the structure also adds to the prestress. All components are

are minimized. Thus, the construction of buildings, bridges and other structures using tensegrity principles could make them highly resilient and very economical at the same time.

dynamically linked such that forces are translated instantly everywhere; a change in one part is

I think that part of the reason that the beauty and construction of tensegrity did not come into

reflected throughout the whole structure.

practice, even in circles where there was a strong interest in the practical application of

The stability of prismatic tensegrity structures is not only determined by the connectivity

tensegrity, is the clear lack of professional and intelligent workers as well as the precise tools

manner of the members, but also sensitive to the height/radius ratio and the stiffness/prestress

for realizing their design and creation.

ratio.

The main shortcomings and problems of practical application of tensegrity technology for

Our team of structural designers started to deal with this kind of fine art of structure in the year 2008. Together with the students we try to bring fresh ideas into the field and create different

the practice these artists have identified are:

models of tensegrities. In this chapter could be found various model used for living and for

1. Low Load Response - "Relatively high deformation and low material efficiency compared

pleasure as furniture, table lamps or toys. We pay attention not only to the structure itself, but

to conventional, geometrically rigid structures."

also to details, aesthetic and the elegance of the models. Each node of the structures is connected by two horizontal cables within its own horizontal plane, and is connected by one vertical cable and one strut to nodes in the other plane. The thick and thin lines denote, respectively, cables that can only carry tension, and struts that carry compression. These structures are called super stable. In the model structures shown in this chapter, the tensile members are usually cables or rods,

2. The complexity of the production of details - spherical and domical structures are complicated in particular to produce details of joints as well as the selection of suitable material for their realization, these factories can lead to production difficulties. All the models shown in this appendix have been made by the author by means of Tensegrity elements.

while the compression members are sections of tubing or U profiles. The tensile members can be thought of as cables which pull two points together, while the compression members can be

Lightweight structures Lightweight structures


252 248

Lightweight structures Architects and engineers are executives of services to reap the intellectual property of previous

constructions. The clients' demands are high nowadays, there is a demand for temporary,

generations. They are studying, improving and discovering. They are the creators of new

transformable solutions that can offer sliding lightweight constructions ranging from simple

spaces, forms and structures that are constantly improving. This creative activity connects

sliding marquee solutions to staircases, which disappear by pressing the button (Khalifa

architects and engineers on their way to the art of "Prof. Frei Otto.

International Stadium). Tensile integrity systems are being developed today for NASA and

Lightweight structures used in various forms and variations can be seen in broad spectrum use

form unprecedented options for blame.

on the current market. These structures, developed over the years, together with advances in

Talking about modern systems of steel, wire and membrane has its merit. And that these

material engineering and technology, continue to progress and are now an integral part of

systems are at the top of the current building options. Limits are given by the physical properties

architectural creation.

and laws of the material and the construction system. These must be fully taken into account

Architectural lightweight structures can now be seen in different shapes and sizes. They may

and used in the creation of the modern system. In practice, we most often encounter the

be internal, external, permanent, temporary, large, small, supported, membranes filled with air

following issues:

or stretched. New subgroups of these constructions - shell structures, tensile-integrity structures - are also very current. These unique forms have played an important role in contemporary

• bars (struts) systems - stable problems of compressive and bent bars,

architecture, interior design and various cultural events since the time they first appeared in the

• cables systems - prestress, stiffness of the structure, necessity of solving the theory II. order,

1960s by the world-famous German architect and engineer Frei Otto.

• membrane systems - prestress, dynamic resistance, large deformation solutions.

Sabah Shawkat ©

At present, light constructions are designed and constructed independently of the geographic

location. They transform the space and have so subtle and elegant quality. In addition to

providing basic functions such as shading and shutdown, they are an important and functional element in the construction of amphitheatres, sports stadiums, airports, courtyards, building facades, parks, seafront and interiors.

Designing lightweight constructions to meet all criteria is a complex task. Every part is visible and constructive, relying on the proper functioning of all parts. For example, diaphragm fabrics are developed to meet the requirements for high tensile strength, long life with a high modulus of elasticity. The surface layer applied to the material ensures fabric resistance against weathering and dirt, provides resistance to UV radiation and has non-combustible properties.

Tensile membrane architecture is a highly sophisticated medium that offers unique qualities for architects, designers and engineers therefore provides unlimited opportunities for design as well as experiment with form and create alternative solutions to every day design challenges. This is made possible due to the fundamental flexibility and lightweight nature of composite membranes. Membrane structures are often referred to as textile structures. However, the actual membrane construction is far removed from the classic tent. The main difference is its exact geometric shape. For the functioning of the membrane structure, the exact geometric criteria must be computed. The basic criterion is to maintain the concavity and convexity of the main directions of the membrane surface. Following this principle, we can talk about the basic four types of membranes:

We think it important to explore new trends in lightweight constructions, among which we

1. saddle-shaped (hyperbolic paraboloid)

can include:

2. ridge-valley shape

1. Lightweight designs designed with regard to sustainability

3. arch shape

2. Modular light constructions

4. conical shape,

3. Sliding light constructions Designers see the benefits of mass production of simple structures, such as an "umbrella" that has reproducible components. Savings from a modular strategy lead to cost-effective Tensegrity foot Bridge M1 over Morava river- Design systems- Parametric Modelling

Tensegrity foot Bridge M1 over Morava river- Design systems- Parametric Modelling

Lightweightstructures structures Lightweight Lightweight Lightweightstructures structures


253

Sabah Shawkat © Tensegrity foot Bridge M2 over Morava river- Design systems- Parametric Modelling

Tensegrity foot Bridge M3 over Morava river- Design systems- Parametric Modelling

Lightweight structures Lightweight structures


254 248

Lightweight structures Architects and engineers are executives of services to reap the intellectual property of previous

constructions. The clients' demands are high nowadays, there is a demand for temporary,

generations. They are studying, improving and discovering. They are the creators of new

transformable solutions that can offer sliding lightweight constructions ranging from simple

spaces, forms and structures that are constantly improving. This creative activity connects

sliding marquee solutions to staircases, which disappear by pressing the button (Khalifa

architects and engineers on their way to the art of "Prof. Frei Otto.

International Stadium). Tensile integrity systems are being developed today for NASA and

Lightweight structures used in various forms and variations can be seen in broad spectrum use

form unprecedented options for blame.

on the current market. These structures, developed over the years, together with advances in

Talking about modern systems of steel, wire and membrane has its merit. And that these

material engineering and technology, continue to progress and are now an integral part of

systems are at the top of the current building options. Limits are given by the physical properties

architectural creation.

and laws of the material and the construction system. These must be fully taken into account

Architectural lightweight structures can now be seen in different shapes and sizes. They may

and used in the creation of the modern system. In practice, we most often encounter the

be internal, external, permanent, temporary, large, small, supported, membranes filled with air

following issues:

or stretched. New subgroups of these constructions - shell structures, tensile-integrity structures - are also very current. These unique forms have played an important role in contemporary

• bars (struts) systems - stable problems of compressive and bent bars,

architecture, interior design and various cultural events since the time they first appeared in the

• cables systems - prestress, stiffness of the structure, necessity of solving the theory II. order,

1960s by the world-famous German architect and engineer Frei Otto.

• membrane systems - prestress, dynamic resistance, large deformation solutions.

Sabah Shawkat ©

At present, light constructions are designed and constructed independently of the geographic

location. They transform the space and have so subtle and elegant quality. In addition to

providing basic functions such as shading and shutdown, they are an important and functional element in the construction of amphitheatres, sports stadiums, airports, courtyards, building facades, parks, seafront and interiors.

Designing lightweight constructions to meet all criteria is a complex task. Every part is visible and constructive, relying on the proper functioning of all parts. For example, diaphragm fabrics are developed to meet the requirements for high tensile strength, long life with a high modulus of elasticity. The surface layer applied to the material ensures fabric resistance against weathering and dirt, provides resistance to UV radiation and has non-combustible properties.

Tensile membrane architecture is a highly sophisticated medium that offers unique qualities for architects, designers and engineers therefore provides unlimited opportunities for design as well as experiment with form and create alternative solutions to every day design challenges. This is made possible due to the fundamental flexibility and lightweight nature of composite membranes. Membrane structures are often referred to as textile structures. However, the actual membrane construction is far removed from the classic tent. The main difference is its exact geometric shape. For the functioning of the membrane structure, the exact geometric criteria must be computed. The basic criterion is to maintain the concavity and convexity of the main directions of the membrane surface. Following this principle, we can talk about the basic four types of membranes:

We think it important to explore new trends in lightweight constructions, among which we

1. saddle-shaped (hyperbolic paraboloid)

can include:

2. ridge-valley shape

1. Lightweight designs designed with regard to sustainability

3. arch shape

2. Modular light constructions

4. conical shape,

3. Sliding light constructions Designers see the benefits of mass production of simple structures, such as an "umbrella" that has reproducible components. fromrivera modular strategy Parametric lead to cost-effective Tensegrity foot Bridge M4Savings over Morava Design systemsModelling

Tensegrity foot Bridge M4 over Morava river- Design systems- Parametric Modelling

Lightweightstructures structures Lightweight Lightweight Lightweightstructures structures


255

Sabah Shawkat © Tensegrity foot Bridge M5 over Morava river- Design systems- Parametric Modelling

Tensegrity foot Bridge M5 over Morava river- Design systems- Parametric Modelling

Lightweight structures Lightweight structures


256 248

Lightweight structures Architects and engineers are executives of services to reap the intellectual property of previous

constructions. The clients' demands are high nowadays, there is a demand for temporary,

generations. They are studying, improving and discovering. They are the creators of new

transformable solutions that can offer sliding lightweight constructions ranging from simple

spaces, forms and structures that are constantly improving. This creative activity connects

sliding marquee solutions to staircases, which disappear by pressing the button (Khalifa

architects and engineers on their way to the art of "Prof. Frei Otto.

International Stadium). Tensile integrity systems are being developed today for NASA and

Lightweight structures used in various forms and variations can be seen in broad spectrum use

form unprecedented options for blame.

on the current market. These structures, developed over the years, together with advances in

Talking about modern systems of steel, wire and membrane has its merit. And that these

material engineering and technology, continue to progress and are now an integral part of

systems are at the top of the current building options. Limits are given by the physical properties

architectural creation.

and laws of the material and the construction system. These must be fully taken into account

Architectural lightweight structures can now be seen in different shapes and sizes. They may

and used in the creation of the modern system. In practice, we most often encounter the

be internal, external, permanent, temporary, large, small, supported, membranes filled with air

following issues:

or stretched. New subgroups of these constructions - shell structures, tensile-integrity structures - are also very current. These unique forms have played an important role in contemporary

• bars (struts) systems - stable problems of compressive and bent bars,

architecture, interior design and various cultural events since the time they first appeared in the

• cables systems - prestress, stiffness of the structure, necessity of solving the theory II. order,

1960s by the world-famous German architect and engineer Frei Otto.

• membrane systems - prestress, dynamic resistance, large deformation solutions.

Sabah Shawkat ©

At present, light constructions are designed and constructed independently of the geographic

location. They transform the space and have so subtle and elegant quality. In addition to

providing basic functions such as shading and shutdown, they are an important and functional element in the construction of amphitheatres, sports stadiums, airports, courtyards, building facades, parks, seafront and interiors.

Designing lightweight constructions to meet all criteria is a complex task. Every part is visible and constructive, relying on the proper functioning of all parts. For example, diaphragm fabrics are developed to meet the requirements for high tensile strength, long life with a high modulus of elasticity. The surface layer applied to the material ensures fabric resistance against weathering and dirt, provides resistance to UV radiation and has non-combustible properties.

Tensile membrane architecture is a highly sophisticated medium that offers unique qualities for architects, designers and engineers therefore provides unlimited opportunities for design as well as experiment with form and create alternative solutions to every day design challenges. This is made possible due to the fundamental flexibility and lightweight nature of composite membranes. Membrane structures are often referred to as textile structures. However, the actual membrane construction is far removed from the classic tent. The main difference is its exact geometric shape. For the functioning of the membrane structure, the exact geometric criteria must be computed. The basic criterion is to maintain the concavity and convexity of the main directions of the membrane surface. Following this principle, we can talk about the basic four types of membranes:

We think it important to explore new trends in lightweight constructions, among which we

1. saddle-shaped (hyperbolic paraboloid)

can include:

2. ridge-valley shape

1. Lightweight designs designed with regard to sustainability

3. arch shape

2. Modular light constructions

4. conical shape,

3. Sliding light constructions Designers see the benefits of mass production of simple structures, such as an "umbrella" that Design systemsParametric tower has reproducible components. Savings from aModelling-Sightseeing modular strategy lead to cost-effective

Lightweight Lightweightstructures structures Lightweight Lightweightstructures structures

Design systems- Parametric Modelling-Sightseeing tower


257

Sabah Shawkat © Design systems- Parametric Modelling-Tensegrity structures Tensegrity art - Parametric Modelling

Lightweight structures Lightweight structures


258 248

Lightweight structures Architects and engineers are executives of services to reap the intellectual property of previous

constructions. The clients' demands are high nowadays, there is a demand for temporary,

generations. They are studying, improving and discovering. They are the creators of new

transformable solutions that can offer sliding lightweight constructions ranging from simple

spaces, forms and structures that are constantly improving. This creative activity connects

sliding marquee solutions to staircases, which disappear by pressing the button (Khalifa

architects and engineers on their way to the art of "Prof. Frei Otto.

International Stadium). Tensile integrity systems are being developed today for NASA and

Lightweight structures used in various forms and variations can be seen in broad spectrum use

form unprecedented options for blame.

on the current market. These structures, developed over the years, together with advances in

Talking about modern systems of steel, wire and membrane has its merit. And that these

material engineering and technology, continue to progress and are now an integral part of

systems are at the top of the current building options. Limits are given by the physical properties

architectural creation.

and laws of the material and the construction system. These must be fully taken into account

Architectural lightweight structures can now be seen in different shapes and sizes. They may

and used in the creation of the modern system. In practice, we most often encounter the

be internal, external, permanent, temporary, large, small, supported, membranes filled with air

following issues:

or stretched. New subgroups of these constructions - shell structures, tensile-integrity structures - are also very current. These unique forms have played an important role in contemporary

• bars (struts) systems - stable problems of compressive and bent bars,

architecture, interior design and various cultural events since the time they first appeared in the

• cables systems - prestress, stiffness of the structure, necessity of solving the theory II. order,

1960s by the world-famous German architect and engineer Frei Otto.

• membrane systems - prestress, dynamic resistance, large deformation solutions.

Sabah Shawkat ©

At present, light constructions are designed and constructed independently of the geographic

location. They transform the space and have so subtle and elegant quality. In addition to

providing basic functions such as shading and shutdown, they are an important and functional element in the construction of amphitheatres, sports stadiums, airports, courtyards, building facades, parks, seafront and interiors.

Designing lightweight constructions to meet all criteria is a complex task. Every part is visible and constructive, relying on the proper functioning of all parts. For example, diaphragm fabrics are developed to meet the requirements for high tensile strength, long life with a high modulus of elasticity. The surface layer applied to the material ensures fabric resistance against weathering and dirt, provides resistance to UV radiation and has non-combustible properties.

Tensile membrane architecture is a highly sophisticated medium that offers unique qualities for architects, designers and engineers therefore provides unlimited opportunities for design as well as experiment with form and create alternative solutions to every day design challenges. This is made possible due to the fundamental flexibility and lightweight nature of composite membranes. Membrane structures are often referred to as textile structures. However, the actual membrane construction is far removed from the classic tent. The main difference is its exact geometric shape. For the functioning of the membrane structure, the exact geometric criteria must be computed. The basic criterion is to maintain the concavity and convexity of the main directions of the membrane surface. Following this principle, we can talk about the basic four types of membranes:

We think it important to explore new trends in lightweight constructions, among which we

1. saddle-shaped (hyperbolic paraboloid)

can include:

2. ridge-valley shape

1. Lightweight designs designed with regard to sustainability

3. arch shape

2. Modular light constructions

4. conical shape,

3. Sliding light constructions Designers see the benefits of mass production of simple structures, such as an "umbrella" that Tensegrity art -Design systems- Parametric Modelling has reproducible components. Savings from a modular strategy lead to cost-effective

Lightweight Lightweightstructures structures Lightweight Lightweightstructures structures

Tensegrity art -Design systems- Parametric Modelling


withstand large structural shocks like earthquakes. Thus, they could be desirable in areas where earthquakes are a problem. Much interesting theoretical work has come from the University of 259

California at San Diego. Fuller's primary interest was adapting the technology to the development of spherical and domical structures with architectural applications in mind. He also used tensegrity structures to make some philosophical points. As an architect, Emmerich was also interested in architectural applications and designed at least one dome as well. An early exception to this dearth of information on tensegrity calculating was Hugh Kenner's excellent work Geodesic Math which went into an exact technique for the very simple tensegrity prism and outlined an approximate technique for dealing with some simple spherical structures. These domes could encompass very large areas with only minimal support at their perimeters. In a spherical configuration, tensegrity designs could be useful in an outer-space context as superstructures for space stations. Their extreme resilience makes tensegrity structures able to withstand large structural shocks like earthquakes. Thus, they could be desirable in areas where earthquakes are a problem. Much interesting theoretical work has come from the University of California at San Diego.

Sabah Shawkat © Tensegrity dome- Design systems- Parametric Modelling

Tensegrity dome- Design systems- Parametric Modelling

Tensegrity dome- Design systems- Parametric Modelling Lightweight structures Lightweight structures


260 248

Lightweight structures Architects and engineers are executives of services to reap the intellectual property of previous

constructions. The clients' demands are high nowadays, there is a demand for temporary,

generations. They are studying, improving and discovering. They are the creators of new

transformable solutions that can offer sliding lightweight constructions ranging from simple

spaces, forms and structures that are constantly improving. This creative activity connects

sliding marquee solutions to staircases, which disappear by pressing the button (Khalifa

architects and engineers on their way to the art of "Prof. Frei Otto.

International Stadium). Tensile integrity systems are being developed today for NASA and

Lightweight structures used in various forms and variations can be seen in broad spectrum use

form unprecedented options for blame.

on the current market. These structures, developed over the years, together with advances in

Talking about modern systems of steel, wire and membrane has its merit. And that these

material engineering and technology, continue to progress and are now an integral part of

systems are at the top of the current building options. Limits are given by the physical properties

architectural creation.

and laws of the material and the construction system. These must be fully taken into account

Architectural lightweight structures can now be seen in different shapes and sizes. They may

and used in the creation of the modern system. In practice, we most often encounter the

be internal, external, permanent, temporary, large, small, supported, membranes filled with air

following issues:

or stretched. New subgroups of these constructions - shell structures, tensile-integrity structures - are also very current. These unique forms have played an important role in contemporary

• bars (struts) systems - stable problems of compressive and bent bars,

architecture, interior design and various cultural events since the time they first appeared in the

• cables systems - prestress, stiffness of the structure, necessity of solving the theory II. order,

1960s by the world-famous German architect and engineer Frei Otto.

• membrane systems - prestress, dynamic resistance, large deformation solutions.

Sabah Shawkat ©

At present, light constructions are designed and constructed independently of the geographic

location. They transform the space and have so subtle and elegant quality. In addition to

providing basic functions such as shading and shutdown, they are an important and functional element in the construction of amphitheatres, sports stadiums, airports, courtyards, building facades, parks, seafront and interiors.

Designing lightweight constructions to meet all criteria is a complex task. Every part is visible and constructive, relying on the proper functioning of all parts. For example, diaphragm fabrics are developed to meet the requirements for high tensile strength, long life with a high modulus of elasticity. The surface layer applied to the material ensures fabric resistance against weathering and dirt, provides resistance to UV radiation and has non-combustible properties.

Tensile membrane architecture is a highly sophisticated medium that offers unique qualities for architects, designers and engineers therefore provides unlimited opportunities for design as well as experiment with form and create alternative solutions to every day design challenges. This is made possible due to the fundamental flexibility and lightweight nature of composite membranes. Membrane structures are often referred to as textile structures. However, the actual membrane construction is far removed from the classic tent. The main difference is its exact geometric shape. For the functioning of the membrane structure, the exact geometric criteria must be computed. The basic criterion is to maintain the concavity and convexity of the main directions of the membrane surface. Following this principle, we can talk about the basic four types of membranes:

We think it important to explore new trends in lightweight constructions, among which we

1. saddle-shaped (hyperbolic paraboloid)

can include:

2. ridge-valley shape

1. Lightweight designs designed with regard to sustainability

3. arch shape

2. Modular light constructions

4. conical shape,

3. Sliding light constructions Designers see the benefits of mass production of simple structures, such as an "umbrella" that has reproducible components. Savings from a modular strategy lead to cost-effective

Lightweight Lightweightstructures structures Lightweight Lightweightstructures structures


261

Sabah Shawkat ©

Lightweight structures Lightweight structures


262 248

Lightweight structures Attachment of the stiffener to the steel beam

Bracing TR 168,3/10:

Architects and engineers are executives of services to reap the intellectual property of previous

d  168.3mm

t1  12mm

constructions. The clients' high nowadays, there is a demand for temporary, The depth of steel plate: demands t2  are 10mm

spaces, forms and structures that are constantly improving. This creative activity connects

transformable solutions that can offer sliding lightweight constructions ranging from simple Nsd A 3 2  0.063m  2.535  10 mm Height of steelsolutions plate: to staircases, h  A  sliding marquee which A disappear by pressing the buttonh (Khalifa

Input_Steel  "Steel Son 235" if way Steel to "s architects and engineers their the235" art of "Prof. Frei Otto.

International Stadium). Tensile integrity  m0 systems are being developed today for NASA and

Lightweight structures various "Steelused S 355"in if Steel forms "s 355"and variations can be seen in broad spectrum use

form unprecedented options for blame. Design of the welding attachment of the stiffener to the sheet metal plate:

"Nespravne triedy ocele !!!" otherwise on the current market. Thesezadanie structures, developed over the years, together with advances in

Talking about modern systems of steel, wire and membrane has its merit. And that these

material engineering and technology, continue to progress and are now an integral part of

systems  are 0.9 at the top of the current building options. Limits are given by the physical properties

Enter_Steelcreation.  "Steel S 355" architectural

and laws of the material and the construction system. These must be fully taken into account

generations. They are studying, improving and discovering. They are the creators of new

"Steel S 275" if Steel

t  40mm

"s 275"

E  210000MPa

t

fy

w

Architectural lightweight structures can now be seen in different shapes and sizes. They may

and used in the creation of the modern system. In practice, we most often encounter the

fy  ( 235MPa ) ifpermanent, Steel "s 235"  t  40mm be internal, external, temporary, large, small, supported, membranes filled with air

following issues: 0.85 if Steel

( 215MPa ) if Steel

"s 235"  40mm  t  100mm

( 275MPa ) if Steel

"s 275"  t  40mm

or stretched. New subgroups of these constructions - shell structures, tensile-integrity structures - are also (very current. These unique forms have played an important role in contemporary 255MPa ) if Steel "s 275"  40mm  t  100mm architecture, interior various  t cultural 40mm events since the time they first appeared in the ( 355MPa ) ifdesign Steel and "s 355"

 w 

0.8 if Steel

"s 235"

0.9 if Steel

"s 355"

"s 275"

• bars (struts) systems - stable problems of compressive and bent bars, • cables systems - prestress, stiffness of the structure, necessity of solving the theory II. order,

Sabah Shawkat ©

1960s by

40mm  tand  100mm ( 335MPa ) if Steel German "s 355"  the world-famous architect engineer

Frei Otto.

a  3mm if t max-prestress, 10mm • membrane systems dynamic resistance, large deformation solutions.

At present, light constructions are designed and constructed independently of the geographic fu  They ( 360MPa ) if Steel the"sspace 235" and t  40mm location. transform have so subtle ( 340MPa ) if Steel "s 235"  40mm  t  100mm

and elegant quality. In addition to

providing basic functions such as shading and shutdown, they are an important and functional ( 430MPa ) if Steel

"s 275"  t  40mm

element in( 410MPa the construction of amphitheatres, sports stadiums, airports, courtyards, building ) if Steel "s 275"  40mm  t  100mm facades, parks, seafront and interiors. ( 510MPa ) if Steel "s 355"  t  40mm

t criteria 100mm is a complex task. Every part is visible 490MPa ) if Steel "s 355" to40mm Designing (lightweight constructions meetall

and constructive, relying on the proper functioning of all parts. For example, diaphragm fabrics  m0  1.1toifmeet Steel the"srequirements 235"  m1  for1.1 if Steel 235" long 1.3with if Steel 235" are developed high tensile"sstrength, a high"smodulus m2 life 1.15 if Steel

"s 275"

1.15 if Steel

"s 275"

1.3 if Steel

"s 275"

1.3 if Steel

"s 355"

of elasticity. The surface layer applied to the material ensures fabric resistance against 1.2 if Steel

"s 355"

1.2 if Steel

"s 355"

weathering and dirt, provides resistance to UV radiation and has non-combustible properties. WeEntry thinkvalues: it important to explore new trends in lightweight constructions, among which we can include:

Steel  "s 355"

fy  355MPa

 m0  1.2

fu  510MPa

1. Lightweight designs designed with regard to sustainability 

 m1  1.2

 1.3

m2 2. Modular light constructions Proposal of joints plate: 3. Sliding light constructions

4mm if 11mm  t max  20mm

Tensile membrane architecture is a highly sophisticated medium that offers unique qualities for 5mm if 21mm  t max  30mm

architects, designers and engineers therefore provides unlimited opportunities for design as well 6mm if t max  30mm

as experiment with form and create alternative solutions to every day design challenges. This is made possible due to the fundamental flexibility and lightweight nature of composite membranes. Membrane structures are often referred to as textile structures. However, the actual membrane construction is far removed from the classic tent. The main difference is its exact a  4 mm effective weld height  Mw  1.5 geometric shape. For the functioning of the membrane structure, the exact geometric criteria must be computed. The basic criterion is to maintain the concavity and convexity of the main Stress due to force Nsd directions of the membrane surface. Following this principle, we can talk about the basic four Nsd types of membranes: Stress due to force Nsd:  II 4 a l 1. saddle-shaped (hyperbolic paraboloid) fu

2. ridge-valley shape 3. arch shape Maximum permissible welding stress: 4. conical shape, L 

The design of stiffener: Designers see strength the benefits of mass production of simple structures, such as an "umbrella" that

Nsd   w  Mw 4 a

fu

has The reproducible components. Savings N from a750kN modular strategy lead to cost-effective design strength of bracing: sd

Lightweight Lightweightstructures structures Lightweight Lightweightstructures structures

3

L  0.215m

 II

3

 w  Mw

L 

fu

Nsd 4 a l

3

 w  Mw

40mm if L  40mm ( 6 a) if 40mm  L  6 a L otherwise


263

Welding evaluation by equalizing stress:

kol  0kPa

 II 

Nsd

Then we have to change the welding length, or decrease the angle between the bracing

 II  218.11MPa

4 a L

member with beam, thus from 75o to approximately 25o. Design of the welding attachment of the stiffener to the sheet metal plate:

f

u   2   2   2  kol II      kol w Mw

 kol  0kPa

  75deg

Nsd  750kN Verification 

"weld is satisfactory"

"wel does not"

if

  2   2   2  kol II      kol w Mw

Nsd

 rov     75deg

a  4 mm

a 2 L

 0.707

a 2 L

kol 

 0.707

Fwy

2

2

kol  3  kol  3  rov 

2

Fwx  194.114kN

Fwy

 kol  

fu

2

2

kol  3  kol  3  rov  853.884MPa

Verification 

Fwy  Nsd  sin ( )

 rov  132.563MPa

kol 

Fwy  724.444kN

Fwy 2 a L

kol  181.111MPa

2 a L

 0.707

Fwy  Nsd  sin ( )

Fwy  724.444kN

"weld is satisfactory" "weld does not"

if

Fwy 2 a L

fu  w  Mw

2

2

kol  3  kol  3  rov  367.024MPa

Verification 

  kol 

 kol  128.046MPa

 w  Mw

 rov  308.408MPa kol  421.356MPa

2 a L

 w  Mw

L  0.215m

2

Nsd

fu

2

Sabah Shawkat © 2

Assessment of the welding:

 rov  

2

kol  3  kol  3  rov 

Fwx  194.114kN

 Fwx  Nsd  cos ( )

Nsd  750kN

2

Assessment of the welding:

fu

Design of welding of the connection plate to the beam:

 Fwx  Nsd  cos ( )

L  400 mm

f

u   2   2   2  kol II      kol w Mw

if

Verification  "weld is satisfactory"

Design force:

a  5 mm

"weld is satisfactory" "weld does not"

 0.707

 kol  297.899MPa Verification  "weld is satisfactory"

 377.778MPa

fu fu   2 2 2  kol  3  kol  3  rov       kol   w Mw  Mw 

otherwise

Verification  "weld does not"

Lightweight structures Lightweight structures

if

fu

 w  Mw

 377.778MPa

fu fu   2 2 2  kol  3  kol  3  rov    kol    w  Mw Mw  

otherwise


264 248

Detail of structures the support cables on the pylon Lightweight

Design of tensile force: Nsd

Architects and engineers are executives of services to reap the intellectual property of previous Ocel  "s 355"

Fsd.1  5200kN

t  40mm

E  210000MPa

generations. They are studying, improving and discovering. They are the creators of new spaces, forms and structures that are constantly improving. This creative activity connects Entry values: architects and engineers on their way to the art of "Prof. Frei Otto. Ocel  "s 355" Lightweight structures used in various forms and variations can be seen in broad spectrum use fy  355MPa

fu  510MPa

on the current market. These structures, developed over the years, together with advances in

constructions. The clients' demands are high nowadays, there is a demand for temporary, The design normal force of the tensile cross-sectional load determined as less of the values transformable solutions that can offer sliding lightweight constructions ranging from simple Npl, Rd and Nu, Rd sliding marquee solutions to staircases, which disappear by pressing the button (Khalifa International systems are being developed for NASAfrom: and The designStadium). of normalTensile force ofintegrity the unbroken cross-sectional load shalltoday be determined form unprecedented options for blame.

fy  A  Npl.Rd Npl.Rd  27031.771kN  Talking about modern systems of steel, wire m0

and membrane has its merit. And that these

architectural creation.

systems are at the top of the current building options. Limits are given by the physical properties The design of bearing normal force of the weakened cross section is determined from: and laws of the material and the construction system. These must be fully taken into account

Architectural lightweight structures can now be seen in different shapes and sizes. They may

u and the of the modern In practice, we most often encounter the Nused in  A creation   0.9   27100.419kN N system.

THYSSEN F be internal, external, permanent, temporary, large, small, supported, membranes filled with air cable 100 mm or stretched. New subgroups of these constructions - shell structures, tensile-integrity structures

following issues:

 m1 engineering 1.2  m2 and 1.3 technology, continue to progress and are now an integral part of material  Mp  1.45

 m0  1.2

diameter of the pin: - areThe also very current. These unique forms have played an important role in contemporary d  172mm

architecture, interior design and various cultural events since the time they first appeared in the

u.Rd

f net  m2

u.Rd

 pl.Rd - stable u.Rd  problems t.Rd • barst.Rd (struts) systems of compressive and bent bars, N

 min N

N

N

 27031.771kN

 - prestress, assessment "Conformes"stiffness if Nsd of N t.Rdstructure, necessity of solving the theory II. order, • cables systems the

Sabah Shawkat ©

Plate 1960s by thickness: the world-famous German architect and engineer Frei Otto. t = 85 mm At present, light constructions are designed and constructed independently of the geographic

location. They transform the space and have so subtle and elegant quality. In addition to

providing basic functions such as shading and shutdown, they are an important and functional f

ysports stadiums, airports, courtyards, building element in the construction of  Famphitheatres, Bruising plate pin: FbRd  5369.069kN bRd  1.5 t d   Mp facades, parks, seafront and interiors.

Designing lightweight constructions to meet all criteria is a complex task. Every part is visible assessment 

"Conformes" if FbRd  Fsd.1

and constructive, relying on the proper functioning of all parts. For example, diaphragm fabrics "does not"

otherwise

are developed to meet the requirements for high tensile strength, long life with a high modulus assessment The  "Conformes" of elasticity. surface layer applied to the material ensures fabric resistance against

weathering and dirt, provides resistance to UV radiation and has non-combustible properties. Assessment of cross-sectional subjected to tensile stress: We think it important to explore new trends in lightweight constructions, among which we Design of tensile force: Nsd  Fsd.1 can include: The width of plate: b p  t 1. Lightweight designs designed with regard to sustainability The height of plate: h p  1075mm 2. Modular light constructions 2 A  0.091m area of unbroken cross-section: A  b p  h p 3. Sliding light constructions 2 The area of weakened cross-section: A net  0.077m A net  A  d  t Designers see the benefits of mass production of simple structures, such as an "umbrella" that sd  Nt.Rd has Nreproducible components. Savings from a modular strategy lead to cost-effective

"does not"

otherwise

• membrane systems - prestress, dynamic resistance, large deformation solutions. assessment  "Conformes"

Tensile membrane architecture is a highly sophisticated medium that offers unique qualities for architects, designers and engineers therefore provides unlimited opportunities for design as well Assessment of corner weld on join metal: as experiment with form and create alternative solutions to every day design challenges. Eccentricity: e  165mm This is made possible due to 1the fundamental flexibility and lightweight nature of composite membranes. Membrane structures are often referred to as textile structures. However, the actual   37deg Inclination of the force: membrane construction is far removed from the classic tent. The main difference is its exact Design force: Fsd.1  5200kN geometric shape. For the functioning of the membrane structure, the exact geometric criteria must be computed. The basic criterion is to maintain the concavity and convexity of the main directions of the membrane surface. Following this principle, we can talk about the basic four decomposition of force into individual directions y and z: types of membranes: 3 1. saddle-shaped (hyperbolic paraboloid) F FHsd1  4.153  10 kN Hsd1  Fsd.1  cos ( )

2. ridge-valley shape F  shape Fsd.1  sin ( ) 3. arch Vsd1

3

FVsd1  3.129  10 kN

4. conical shape, Partial safety factor:

 Mw  1.5

Coefficient of strength class:

 w  0.9

Lightweight Lightweightstructures structures Lightweight Lightweightstructures structures


265

fu

design strength of the weld in the shear: fvwRd 

3  w  Mw

fvwRd  218.11MPa

Detail of the support bearing cables on the pylon Design of the K1 joint

effective welding height: a  6mm design resistance of the unit length of the weld: FvwRd  fvwRd  a Effective welding length: number of welds:

kN FvwRd  1308.661 m

Fsd.1  4100kN Fsd.2  4100kN Fsd.3  2000kN

lu1  2043mm

Fsd.4  1700kN

n  4

 fu 510 MPa

components of individual stresses:

 fy 355 MPa

Steel  "s 355" t  40mm

FVsd1

 II 

 m0  1.2

n

 II  63.824MPa

lu1 a

 M 1  FHsd1  e1

1

T  

4 2

 m2  1.3 1

2

 Mp  1.45

Sabah Shawkat © W zvar 

M 1  685.229kNm

 M1



 m1  1.2

 W zvar

W zvar  4.174L

E  210000MPa

Cable THYSSEN 100 mm

FHsd1  lu1 a

6

 a lu1

 

 T  T T  88.912MPa 

 T  88.912MPa

Screw core area

d  172mm

The thickness of the plate

t1  90mm

Comparative stress: 2

2

assessment 

"Conformes" if "does not"

suppression the plate K1:

fu

2

T  3  T  3  II  209.385MPa

 w  Mw

 377.778MPa

 FbRd  1.5 t1 d  

fu 2 2 2 T  3  T  3  II   w  Mw

otherwise

"Conformes" if T   Mw

assessment  "Conformes"

"satisfactory"

 FbRd  5684.897kN

if FbRd  Fsd.1 otherwise

Verification  "satisfactory"

fu

"does not"

Mp

"does not change the design proposal"

assessment  "Conformes"

assessment 

Verification 

fy

fu  Mw

 340MPa

suppression the plate K2

 FbRd  1.5 t 1 d  

otherwise

Verification 

"satisfactory"

fy Mp

if FbRd  Fsd.3

"It is inappropriate to modify the design of the joint" Verification  "satisfactory"

Lightweight structures Lightweight structures

 FbRd  5684.897kN

otherwise


266 248

Lightweight structures Assessment of cross-sectional tensile stress K1

Verification 

"satisfactory" "does not"

if Nsd12  Nt.Rd

otherwise

Architects engineers Designand tensile force: are executives of services to reap the intellectual property of previous

constructions. The clients' demands are high nowadays, there is a demand for temporary,

generations. They are studying, improving and discovering. They are the creators of new

transformable solutions that can offer sliding lightweight constructions ranging from simple

 N  F

F

3

N

 8.2  10 kN

sd.2 spaces,sd12 forms sd.1 and structures thatsd12 are constantly improving. This creative activity connects

architects and engineers on their way to the art of "Prof. Frei Otto. Plate width: b p  90mm Lightweight structures used in various forms and variations can be seen in broad spectrum use The height of the platter in the considered location: h p  2300mm on the current market. These structures, developed over the years, together with advances in The area of not weakened cross-section: material engineering and technology, continue to progress and are now an integral part of 2

A  0.207m

A  b p  h pcreation.  architectural

Architectural lightweight structures can now be seen in different shapes and sizes. They may The areaexternal, of weakened cross-section be internal, permanent, temporary, large, small, supported, membranes filled with air A

A A  d  t

 0.192 m

2

netof these constructions - shell structures, tensile-integrity structures net or stretched. New 1subgroups

- are also very current. These unique forms have played an important role in contemporary Nsd12  Nt.Rd

architecture, interior design and various cultural events since the time they first appeared in the

Verification  "satisfactory"

sliding marquee solutions to staircases, which disappear by pressing the button (Khalifa Assessment of cross-sectional tensile stress K2: International Stadium). Tensile integrity systems are being developed today for NASA and tensile force: formDesign unprecedented options for blame. 3

  10 and  kN membrane has its merit. And that these  Nsd34  Fsd.3  Fsd.4systems Nsd34 Talking about modern of steel,3.7wire

systems are at the top of the current building options. Limits are given by the physical properties  90mm and Plate laws width: of the material and the construction system. These must bebpfully taken into account and used in the creation of the modern system. In practice, we most often encounter the The height of the platter in the considered location: h p  1745mm following issues: 2

A  0.157m Area of not weakened cross-section: A  b p  hp • bars (struts) systems - stable problems of compressive and bent bars, 2 Area of weakened cross-section: A net  0.142m A net  A  d  t 1 • cables systems - prestress, stiffness of the structure, necessity of solving the theory II. order, Nsd34  Nt.Rd

Sabah Shawkat ©

Nsd12 1960s by the world-famous German architect and engineer Frei Otto. - design tensile force

At present, light constructions are designed and constructed independently of the geographic - the design normal force of the tensile cross-sectional load determined as less Nt.Rd location. They transform the space and have so subtle and elegant quality. In addition to of the values Npl, Rd and Nuas , Rdshading and shutdown, they are an important and functional providing basic functions such element in the construction of amphitheatres, sports stadiums, airports, courtyards, building

facades, parks,normal seafront and of interiors. The design force the not weakened cross-sectional load shall be determined from: Designing lightweight constructions to meet all criteria is a complex task. Every part is visible

- design tensile force Nsd34 Tensile membrane architecture is a highly sophisticated medium that offers unique qualities for - the design normal force of the tensile cross-sectional load determined as less of Nt.Rd architects, designers and engineers therefore provides unlimited opportunities for design as well Rd and Nucreate , Rd alternative solutions to every day design challenges. The valueswith Npl, form as experiment and designpossible normal due forcetoofthe thefundamental not weakened cross-sectional load shallnature be determined fro ThisThe is made flexibility and lightweight of composite fy membranes. Membrane structures are often referred to as textile structures. However, the actual Npl.Rd  A  

Npl.Rd  46460.625kN 

fy

m0 membrane construction is far removed from the classic tent. The main difference is its exact

 m0

The design normal load force of the cross structure, section is the determined from: criteria geometric shape. For the functioning ofweakened the membrane exact geometric

 A  relying on the proper Npl.Rd and constructive, functioning  61237.5kN  of all parts. For example, diaphragm fabrics Npl.Rd

are developed to meet the requirements for high tensile strength, long life with a high modulus of The elasticity. surface layerofapplied to the cross material ensures fabric resistance against design The normal load force the weakened section is determined from: weathering and dirt, provides resistance to UV radiation and has non-combustible properties. fu

Nu.Rd  0.9 A net  Nu.Rd  67621.292kN  We think it importantto explore new trends in lightweight constructions, among which we m2

can include:

• membrane systems - prestress, dynamic resistance, large deformation solutions.

fu basic criterion is to maintain the concavity and convexity of the main must be computed. The  Nu.Rd  0.9 A net 

Nu.Rd  49985.1kN 

 m2 directions of the membrane surface. Following this principle, we can talk about the basic four

types of membranes: N

 min N

N

N

 46460.625kN 

pl.Rd u.Rd t.Rd 1.t.Rd saddle-shaped (hyperbolic paraboloid)

2. ridge-valley shape

1. Lightweight designs designed with regard to sustainability

 "satisfactory" if Nsd34  Nt.Rd Verification 3. arch shape

2. Modular light constructions

"does not" otherwise 4. conical shape,

Nt.Rd  min Npl.Rd Nu.Rd

Nt.Rd  61237.5kN 

3. Sliding light constructions N

N

3

 N 8.2  10  kN

sd sd12 sd12 Designers see the benefits of mass production of simple structures, such as an "umbrella" that

Verification  "satisfactory"

has reproducible components. Savings from a modular strategy lead to cost-effective

Lightweight Lightweightstructures structures Lightweight Lightweightstructures structures


267

Assessment of the corner welding on the joint plate at the terminal side K1: Eccentricity:

Verification 

e1  123mm   40deg

Diversion of forces:

fu if T   Mw

"It is inappropriate, modify the design "

otherwise

Verification  "Satisfactory"

3

Design force:

"Satisfactory"

Nsd12 8.2  10  kN 

Decomposition of force into individual directions y and z: Assessment of corner welding on the joint plate at the terminal side K2 and K3:  FHsd1  Nsd12  sin ( )

3

FVsd1  Nsd12  cos ( )

3

Fsd.3 2  10  kN  3

3

FHsd1  5.271  10  kN

Fsd.4 1.7  10  kN 

FVsd1  6.282  10  kN

Partial reliability factor:

coefficient of strength class

 Mw  1.5

Design strength of the weld in the shear: Effective welding height:

fvwRd 

fu 3  w  Mw

- eccentricity:  w  0.9

design force

f  vwRd 218.11MPa

kN

number of welds:

lu1  2300mm

Components of individual stresses:

 M 1  FHsd1  e1

 II 

n

 a lu1

 

FHsd4  1.202  10  kN

F Vsd4  Fsd.4  cos 1

 

FVsd4  1.202  10  kN

 

FHsd3  1.813  10  kN

 

FVsd3  845.237kN 

F Hsd4  Fsd.4  sin 1

2

  II  136.556MPa

lu1 a

F Hsd3  Fsd.3  sin 2

F Vsd3  Fsd.3  cos 2

M 1  648.316kNm 

Partial reliability factor:

2

Wzvar  8.817L

3

3

3

 Mw  1.5

Design strength of the weld in the shear:

FHsd1  1  M1  T     lu1 a 2 2  W zvar  2

Fsd.3  2000 kN

Decomposition of force into individual directions y and z:

m

FVsd1

6

F sd.4 1700 kN

2

 T  107.021MPa

 T  T

fu  377.778MPa   w  Mw

2

3  II 318.993MPa  T  3  T 

  T 107.021MPa 

Effective welding height:

"Satisfactory"

if

2

2

fu

T  3  T  3  II   w  Mw

"It is inappropriate, modify the design " Verification  "Satisfactory"

2

coefficient of strength class:

fvwRd 

Effective welding length:

fu

 w  0.9

 f vwRd 218.11MPa

3  w  Mw

a  8mm

Design resistance of the unit length of the weld:

Comparative stress: Verification 

2  65deg

Sabah Shawkat ©

Effective welding length:

1

1  45deg

a  10mm

Design resistance of the unit length of the weld: FvwRd  fvwRd  a  FvwRd 2181.101

W zvar 

- diversion of forces: e2  389mm

e1  352mm

lu1  1745mm

FvwRd  fvwRd  a

kN  FvwRd 1744.881 m

number of welds:

n  2

FVsd4 FVsd3

 II 

n

lu1 a

  II  73.328MPa

otherwise  M 1  FHsd4  e1

Lightweight structures Lightweight structures

 M 1  423.133kNm

M 2  FHsd3  e2

 M 2 705.107kNm 


268 248

Lightweight structures W zvar 

1

 a lu1

Detail of the stiffener connection to column on the bar

2

W zvar  4.06L

6 engineers are executives of services to reap the intellectual property of previous Architects and

Entry values:The clients' demands are high nowadays, there is a demand for temporary, constructions.

generations. They are studying, and discovering. They are the creators of new Fimproving FHsd3 M2 1  M1 Hsd4 T        T  174.599MPa  improving. spaces, forms structures are This creative activity connects  a constantly lu1 a W zvar W zvarthat lu1 2 2 and  architects and engineers on their way to the art of "Prof. Frei Otto.

Steel  "s 355"  40mm transformable solutions that tcan offer sliding lightweight constructions ranging from simple

f

u variations can be seen in broad spectrum use Lightweight structures used in various forms and  340MPa   174.599MPa     T

T

T

Mw on the current market. These structures, developed over the years, together with advances in

material engineering Comparative stress:and technology, continue to progress and are now an integral part of architectural creation.

f

sliding marquee solutions to staircases, which disappear by pressing the button (Khalifa  fy 355 MPa

 m0  1.2

International Stadium). Tensile integrity systems are being developed today for NASA and   m1  1.2 fu 510 MPa form unprecedented options for blame. 5

 E 2.1  10  MPa

 m2  1.3

Talking about modern systems of steel, wire and membrane has its merit. And that these systems are at the top of the current building options. Limits are given by the physical properties  m0  1.1 if Steel "s 235" and laws of the material and the construction system. These must be fully taken into account 1.15 if Steel

"s 275"

u 2 2 2 Architectural lightweight structures can now be  seen in different 377.778MPa  shapes and sizes. They may T  3  T  3  II 371.579MPa 

and used in1.2 theif creation the modern system. In practice, we most often encounter the Steel "sof 355"

be internal, external, permanent, temporary, large, small, supported, membranes filled with air

following issues:

 w  Mw

or stretched. New these constructions - shell structures, tensile-integrity structures Components ofsubgroups individualof stresses - are also very current. These unique forms have played an important role in contemporary architecture, interior design and various cultural events since the time they first appeared in the

1.1 if Steel

 m1 

"s 235"

1.15 if Steel

"s 275" • bars (struts) systems - stable problems of compressive and bent bars, 1.2 if Steel

"s 355"

• cables systems - prestress, stiffness of the structure, necessity of solving the theory II. order, 1.3 if Steel

 m2 

"s 235"

Sabah Shawkat ©

1960s by the world-famous German architect and engineerf Frei Otto. 2

2

2

u

 "Satisfactory" if T  3  T  3  II  At Verification present, light constructions are designed and constructed    independently of the geographic w Mw

location. They transform the space and and elegant quality. In addition to "It is inappropriate, modify thehave designso " subtle otherwise

providing basic functions such as shading and shutdown, they are an important and functional Verification  "Satisfactory"

element in the construction of amphitheatres, sports stadiums, airports, courtyards, building facades, parks, seafront and interiors. fu Verification 

"Satisfactory"

Designing lightweight

if T  Mw constructions to meet

all criteria is a complex task. Every part is visible

is inappropriate, modify the design " otherwise and constructive, "It relying on the proper functioning of all parts. For example, diaphragm fabrics

areVerification developed to meet the requirements for high tensile strength, long life with a high modulus "Satisfactory" of elasticity. The surface layer applied to the material ensures fabric resistance against weathering and dirt, provides resistance to UV radiation and has non-combustible properties. We think it important to explore new trends in lightweight constructions, among which we

"s 275" dynamic resistance, large deformation solutions. if Steel • membrane 1.3 systems - prestress, 1.3 if Steel

"s 355"

Tensile membrane architecture is a highly sophisticated medium that offers unique qualities for architects, designers and engineers therefore provides unlimited opportunities for design as well Design of steel plate: as experiment with form and create alternative solutions to every day design challenges. ThisDesign is made possible due to the fundamental flexibility and lightweight nature of composite force o stiffener: Nsd  1500.0kN membranes. Membrane structures are often referred to as textile structures. However, the actual d  398mm Stiffener: TR159/8 t  70mm membrane construction is far removed from the1 classic tent. The main difference is its exact geometric shape.t For the functioning of the membrane structure, the exact geometric criteria Plate depth: 2  20mm must be computed. The basic criterion is to maintain the concavity and convexity of the main N

A 3 2 sd directions of the membrane wehcan basic four h the 0.127m A  5.07this  10principle,  mm  talk about Plate height: A  surface. Following t fy types of membranes:  m0

can include:

1. saddle-shaped (hyperbolic paraboloid) Design of the welding attachment of the stiffener to the steel plate: 2. ridge-valley shape

1. Lightweight designs designed with regard to sustainability

3. arch shape

2. Modular light constructions

4. conical 0.85 shape, if Steel

 w 

3. Sliding light constructions

0.8 if Steel

0.9 if Steel

"s 235"

has reproducible components. Savings from a modular strategy lead to cost-effective

Lightweight Lightweightstructures structures Lightweight Lightweightstructures structures

 Mw  1.5

3mm if t max  10mm 4mm if 11mm  t max  20mm

"s 355"

Designers see the benefits of mass production of simple structures, such as an "umbrella" that  w  0.9

a 

"s 275"

5mm if 21mm  t max  30mm

6mm if t max  30mm

t max  max t1 t 2


269

Effective welds height:

Nsd

a  6 mm

Stress due to force Nsd:

 II

 II 

Nsd

Maximum permissible welding stress: Nsd   w  Mw 4 a L1 

 II

3

4 a l

 w  Mw

3

 Nper 

 w  Mw

W h 

L1  286.55 mm

L1 otherwise

Welding evaluation by equalizing the stress: Nsd

Nkol a Ls

M

z W 3

 sin ( )

Nper  176.052kN 

per  0kPa

W d 

 per  0kPa

I z3

I z1

 h 

W h  1.759L

 d 

W d  12.98L

Nsd

 NII 

 I

Nper a Ls

Nper a Ls

4

1 12

 cos ( ) NII 331.105kN 

 a Ls

M

3 4

3

I  2.726  10

m

5

h  1.102  10  kPa

Wh

M

3

d  4.003  10  kPa

Wd

5

Sabah Shawkat ©  per  h  0.707

f

fu  377.778MPa   w  Mw

2   2   2   II  218.11MPa  per  per 

if

2  2   2   per   II  114.538MPa  per

4

 per  h  0.707

 per  7.79  10  kPa

fu  377.778MPa   w  Mw

f

u   2   2   2  per II      per w Mw

f

u   2  3  2  3  2  per II      per w Mw

f

u   2   2   2  per II      per w Mw

Assessment 

Assesment  "confirmes"

Design of the welding of the connecting plate to the column:

Ls  1760mm

u   2   2   2  per II      per w Mw

if

u   2   2   2  per II      per w Mw

Assessment  "complies"

z1  210mm

z2  385mm

f

"complies" if

"does not"

3 Design force:  Nsd 1.5  10  kN

a  6mm

4

per  7.79  10  kPa

Comparative stress:

fu  377.778MPa   w  Mw

"confirmes" if

"does not"

  28deg

4

 II  2.181  10  kPa

u   2   2   2  per II      per w Mw

Assesment 

Nsd

3

40mm if L1  40mm

4 a L1

 M 164.446kNm M  Nper  z1  NII z2

( 6 a) if 40mm  L1  6 a

 II 

4

 II  3.135  10  kPa

fu

Nsd

 L1  286.553mm

fu

 cos ( ) a Ls

4 a l fu

L1 

4

z3  1550mm

Lightweight structures Lightweight structures

f


248

Lightweight structures Architects and engineers are executives of services to reap the intellectual property of previous

constructions. The clients' demands are high nowadays, there is a demand for temporary,

generations. They are studying, improving and discovering. They are the creators of new

transformable solutions that can offer sliding lightweight constructions ranging from simple

spaces, forms and structures that are constantly improving. This creative activity connects

sliding marquee solutions to staircases, which disappear by pressing the button (Khalifa

architects and engineers on their way to the art of "Prof. Frei Otto.

International Stadium). Tensile integrity systems are being developed today for NASA and

Lightweight structures used in various forms and variations can be seen in broad spectrum use

form unprecedented options for blame.

on the current market. These structures, developed over the years, together with advances in

Talking about modern systems of steel, wire and membrane has its merit. And that these

material engineering and technology, continue to progress and are now an integral part of

systems are at the top of the current building options. Limits are given by the physical properties

architectural creation.

and laws of the material and the construction system. These must be fully taken into account

Architectural lightweight structures can now be seen in different shapes and sizes. They may

and used in the creation of the modern system. In practice, we most often encounter the

be internal, external, permanent, temporary, large, small, supported, membranes filled with air

following issues:

or stretched. New subgroups of these constructions - shell structures, tensile-integrity structures - are also very current. These unique forms have played an important role in contemporary

• bars (struts) systems - stable problems of compressive and bent bars,

architecture, interior design and various cultural events since the time they first appeared in the

• cables systems - prestress, stiffness of the structure, necessity of solving the theory II. order,

1960s by the world-famous German architect and engineer Frei Otto.

• membrane systems - prestress, dynamic resistance, large deformation solutions.

Sabah Shawkat ©

At present, light constructions are designed and constructed independently of the geographic

location. They transform the space and have so subtle and elegant quality. In addition to

providing basic functions such as shading and shutdown, they are an important and functional element in the construction of amphitheatres, sports stadiums, airports, courtyards, building facades, parks, seafront and interiors.

Designing lightweight constructions to meet all criteria is a complex task. Every part is visible and constructive, relying on the proper functioning of all parts. For example, diaphragm fabrics are developed to meet the requirements for high tensile strength, long life with a high modulus of elasticity. The surface layer applied to the material ensures fabric resistance against weathering and dirt, provides resistance to UV radiation and has non-combustible properties.

Tensile membrane architecture is a highly sophisticated medium that offers unique qualities for architects, designers and engineers therefore provides unlimited opportunities for design as well as experiment with form and create alternative solutions to every day design challenges. This is made possible due to the fundamental flexibility and lightweight nature of composite membranes. Membrane structures are often referred to as textile structures. However, the actual membrane construction is far removed from the classic tent. The main difference is its exact geometric shape. For the functioning of the membrane structure, the exact geometric criteria must be computed. The basic criterion is to maintain the concavity and convexity of the main directions of the membrane surface. Following this principle, we can talk about the basic four types of membranes:

We think it important to explore new trends in lightweight constructions, among which we

1. saddle-shaped (hyperbolic paraboloid)

can include:

2. ridge-valley shape

1. Lightweight designs designed with regard to sustainability

3. arch shape

2. Modular light constructions

4. conical shape,

3. Sliding light constructions Designers see the benefits of mass production of simple structures, such as an "umbrella" that has reproducible components. Savings from a modular strategy lead to cost-effective

Lightweight structures Lightweight Lightweightstructures structures


Sabah Shawkat © Membrane structures Table properties of membrane structures Force density method Mohr circle of stress

Lightweight structures


272 248

Lightweight structures Prospect for European Guidance for the Structural Design of Tensile Membrane Structures

Euro code

The following table is are not executives a standard but a projecttomaster document. Architects and engineers of services reap the intellectual property of previous

for temporary, constructions. The of clients' demands are high nowadays, demand Strength values PVC-coated polyester fabrics not directlythere linkedistoa the stress verification in the

generations. They are studying, improving and discovering. They are the creators of new

transformable solutions that can offer sliding lightweight constructions ranging from simple ULS

spaces, formsofand structures thatwith arePVC constantly Typology polyester fabrics coatingimproving. This creative activity connects

sliding marquee solutions to staircases, which Type disappear by pressing the button (Khalifa I Type II Type III Type IV

architects andType engineers on their wayIto the art of "Prof. II Frei Otto.

Standard integrity Value warp/weft warp/weft International Stadium). Tensile systems are beingwarp/weft developed today for NASA and Parameter warp/weft

III

IV

Lightweight structures used in various forms and variations can be seen in broad spectrum use

form unprecedented options for blame. EN 1875-3 Tear

Weightmarket. in g/m2These structures, 750/9001developed1050 1050/12501 on the current over the years, together with 1350/18501 advances in

1) 170/170 280/280 450/450 750/750 Method B Strength 1100/1100 Talking about [N] modern systems of steel, wire and membrane has its merit. And that these

material engineering and technology, continue to progress and are now an integral part of 3) and weft lightweight in (N/5cm)structures 2800/2800 Architectural can now be 4200/4000 seen in different5600/5600 shapes and sizes.8000/7000 They may

systems are at the top of the current building options. Limits are given by the physical properties EN ISO 2411 100 110 120 130 Adhesion1) 140 and laws of the material and the construction system. These must be fully taken into account [N/5cm] and 1)used in the creation of the modern system. In practice, we most often encounter the

(kN/m)permanent, temporary, 56/56 112/112 160/140 be internal,and external, large, 84/80 small, supported, membranes filled with air

following issues: 2)

Tensile strength architectural creation.in warp

Tear strength in warp of these constructions - shell structures, tensile-integrity structures or stretched. New subgroups 3) (N/5cm)These 300/280 800/650 1200/1100 - are and alsoweft veryincurrent. unique forms have550/500 played an important role in contemporary

(62°) 4)2)

This values are given as mean values.

Accompanying the Euro code development, a new biaxial test standard is currently under

development in CEN/TC 248/problems WG 4 which aims to substitute the method • bars (struts) systems - stable of compressive and bent bars, of EN 1875-3 in the future.

andinterior (kN/m)design and various 6/5,6 cultural events 11/10since the time 16/13 24/22 architecture, they first appeared in the

• cables systems - prestress, stiffness of the structure, necessity of solving the theory II. order,

elongation German 15/20 15/20 Frei Otto. 15/25 1960s Ultimate by the world-famous architect and engineer

• membrane systems - prestress, dynamic resistance, large deformation solutions.

Euro code

Sabah Shawkat © 15/25

(%)constructions are designed and constructed independently of the geographic At present, light

Minimum of thethe space and have so subtle and elegant quality. In addition to location. They width transform

weldsfunctions (cm) 3 4 they are an important 4 4 providing basic such as shading and shutdown, and functional element the construction Lightinpassing at 500nm, of amphitheatres, sports stadiums, airports, courtyards, building facades, parks, seafront and interiors.13 translucent white colour

9.5

8

5

2 Every part is visible Designing lightweight to2meet all criteria task. Reaction to fireconstructionsM2 M22is a complexM2 M22

and 1)constructive, relying on the proper functioning of all parts. For example, diaphragm fabrics The two values indicate an order of magnitude. are developed to meet the requirements for high tensile strength, long life with a high modulus 2) Classification according to French standards NF P92-503 and NF P92-507. Class M2 of elasticity. The surface layer applied to the material ensures fabric resistance against corresponds to class Bs2, d0 in EN 13501-1. weathering and dirt, provides resistance to UV radiation and has non-combustible properties. 3) Strength values are given as mean values.

PES/PVC-fabrics

Strength values architecture of PVC-coated fabrics directlymedium linked tothat the stress in the ULS Tensile membrane is polyester a highly sophisticated offersverification unique qualities for Parameter Standard Valuetherefore Type I Type II opportunities Type III Type IV Type V architects, designers and engineers provides unlimited for design as well warp/weft warp/weft warp/weft warp/weft warp/weft as experiment with form and create alternative solutions to every day design challenges. Mean

2750/2750

4000/4000

5500/5000

7500/6500

Strength

EN ISO

value

55/55

80/80

110/100

150/130

185/160

[N/5cm]

1421

5%

2500/2500

3500/3500

5000/4500

6750/6000

8500/7250

[kN/m]

fractal

50/50

70/70

100/90

135/120

170/145

Seam

percentage

Tensile

membranes. Membrane structures are often referred to as textile structures. However, the actual membrane construction is far removed from the classic tent. The main difference is its exact

geometric shape. For the functioning of the membrane structure, the exact geometric criteria must be computed. The basic criterion is to maintain the concavity and convexity of the main strength at

EN ISO

of the

directions surface. Following talk about the basic four1) 23°Cof the membrane 1421 respective ≥ 90%this principle, ≥ 90% we ≥can 90% ≥ 90% ≥ 80% types of membranes:

tensile

We think it important to explore new trends in lightweight constructions, among which we

1. saddle-shaped (hyperbolic paraboloid) strength

can include:

2. Seam ridge-valley shape percentage

1. Lightweight designs designed with regard to sustainability

strength EN ISO 3. arch atshape

of the

2. Modular light constructions

1421 4. 70°C conical shape,

respective

3. Sliding light constructions

≥ 70%

tensile

Designers see the benefits of mass production of simple structures, such as an "umbrella" that has reproducible components. Savings from a modular strategy lead to cost-effective

9250/8000

This is made possible due to the fundamental flexibility and lightweight nature of composite

strength 1)

Higher values might be possible, but maybe not economical.

Lightweight Lightweightstructures structures Lightweight Lightweightstructures structures

≥ 70%

≥ 70%

≥ 60%

≥ 55%


273

The material model has five parameters: Ε 1:1 w and Ε 1:1 f are the reference values of warp

PTFE-coated glass fibre fabrics (Glass/PTFE-fabrics)

and fill Young’s moduli given for the 1:1 load ratio, ΔΕw and ΔΕf represent the variation of warp and fill Young’s moduli on the whole range of load ratios, and the Poisson’s ratio νwf.

French recommendations

All five parameters are estimated so that the difference between experimental and modelled

The following table is not a standard but a project master document.

data is minimized.

Table 2: Typology of glass fabrics with PTFE coating Type

I 2

Weight in g/m

Tensile strength in warp and

II

III

IV

800

1050

1250

1500

3500/3000

5000/4400

6900/5900

7300/6500

weft 2) in (N/5cm) and (kN/m)

70/60

100/88

138/118

146/130

Tear strength in warp and weft

300/300

300/300

400/400

500/500

6/6

6/6

8/8

10/10

in (N/5cm) 2) and (kN/m) Ultimate elongation (%)

3-12

3-12

3-12

3-12

Light passing at 500nm,

12-18

12-18

10-16

10-16

translucent white colour

Sabah Shawkat ©

Reaction to fire

M21)

M21)

M21)

M21)

NOTE Packing has an important impact on the properties of the material. 1)

Classification according to French standards NF P92-503 and NF P92-507. Class M2 is

correspondent to class Bs2, d0 in EN 13501-1. 2)

Strength values are given as mean values.

Estimated parameters for the non-linear material model

Manufacturer and reference EW 1:1 Ef 1:1 EW Ef wf (polyester type) (kN/m) (kN/m) (kN/m) (kN/m) (kN/m) Mehler Texnologies Valmex 653.2 444.5 521.2 403.7 0.327 FR700(I) Mehler Texnologies Valmex 882.0 679.6 803.8 437.6 0.263 FR900(II) Mehler Texnologies Valmex 1200.0 881.7 941.2 782.5 0.318 FR1000(III) Mehler Texnologies Valmex 1374.1 1003.4 1204.7 981.7 0.314 FR1400(IV) Ferrari Precontrant 702 (I) 635.3 661.9 295.0 168.5 0.196 Ferrari Precontrant 1002 (II) 830.2 976.0 766.7 123.9 0.213 Ferrari Precontrant B1617 (II) 865.8 707.5 662.9 662.5 0.308 An almost linear relationship was experimentally found between elastic moduli Ef and Ew (subscripts w and f represent the warp and fill directions)

Lightweight structures Lightweight structures


274 248

Lightweight structures Membranes

Geometric shape of the membrane

Architects andstructures engineersare areoften executives of to services to reap the intellectual property of previous Membrane referred as textile structures. However, the actual membrane generations. They areremoved studying, improving andtent. discovering. are the creators new construction is far from the classic The mainThey difference is its exact of geometric spaces, andfunctioning structures that aremembrane constantlystructure, improving. activity connects shape.forms For the of the theThis exactcreative geometric criteria must be architects andThe engineers on their way to the art the of "Prof. Frei and Otto.convexity of the main directions computed. basic criterion is to maintain concavity of the membrane surface. this principle, we can aboutinthe basic four types Lightweight structures used inFollowing various forms and variations cantalk be seen broad spectrum use of membranes: on the current market. These structures, developed over the years, together with advances in

temporary, constructions. The clients' are high system nowadays, therefrom is athe demand The basic geometric shapedemands of the membrane emerges surfacefor of the hyperbolic transformable solutions that can offer sliding lightweight constructions ranging from simple paraboloid. We can describe this area by mathematics: sliding marquee solutions to staircases, which disappear by pressing the button (Khalifa 2

2

2

2

x Stadium). y International Tensile integrity systems are being developed today for NASA and z( xy )  a b options for blame. form unprecedented For an area with parallel curvature margins and a rectangular plan, we can define the following Talking about of modern systems andmarginal membrane has its merit. Andresult that these dimensions the areas Lx, Ly,offx,steel, and fywire . Under conditions: then they

material engineering and technology, continue to progress and are now an integral part of • saddle-shaped (hyperbolic paraboloid) architectural creation. • conical shape, Architectural lightweight structures can now be seen in different shapes and sizes. They may

systems are at the top of the current building options. Limits are given by the physical properties

Wave shape, be •internal, external, permanent, temporary, large, small, supported, membranes filled with air

following issues: then coefficients result

or stretched. New subgroups of these constructions - shell structures, tensile-integrity structures • vault shape. - are also very current. These unique forms have played an important role in contemporary Another criterion lightweight membrane its time prestress. The appeared correct geometric architecture, interior of design and various culturalconstruction events sinceisthe they first in the

Lx

formaterial xand the fx of the y construction 0 and zlaws system. These must be fully taken into account 2

and used in the creation ofLzthe modern system. In practice, we most often encounter the z

for

fx

y

2

x

0

• bars (struts) systems - stable problems of compressive and bent bars, •

2

a cables

2

Lx

systems 4 f x

2

b prestress,

Ly

2

stiffness of the structure, necessity of solving the theory II. order,

4 fy

Sabah Shawkat ©

shape guarantees its architect stability, and stiffness and dynamic 1960s byand the prestress world-famous German engineer Frei Otto.resistance. At the same time, it allows the structure to resist the effects on which it was rain, wind snow. At present, light constructions are designed and constructeddesigned, independently of theand geographic location. They transform the space and have so subtle and elegant quality. In addition to

providing basic functions such as shading and shutdown, they are an important and functional element in the construction of amphitheatres, sports stadiums, airports, courtyards, building facades, parks, seafront and interiors.

Designing lightweight constructions to meet all criteria is a complex task. Every part is visible and constructive, relying on the proper functioning of all parts. For example, diaphragm fabrics are developed to meet the requirements for high tensile strength, long life with a high modulus of elasticity. The surface layer applied to the material ensures fabric resistance against weathering and dirt, provides resistance to UV radiation and has non-combustible properties.

4 f

4 f

x 2 ylarge 2 • membrane systems - prestress, dynamic z( xy ) resistance, x   y deformation solutions. after fitting we get: 2

Lx

Ly

2

Tensile membrane architecture is a highly sophisticated medium that offers unique qualities for Let's take a look at the length coordinates that will then:

architects, designers and engineers therefore provides unlimited opportunities for design as well x

y

Lx

Ly

  create alternative solutions to every day design challenges. as experiment with form and

This is made possible due to the2 fundamental flexibility and lightweight nature of composite 2 membranes. Membrane structures are often referred to as textile structures. However, the actual 2 2 After simplifying the expression we get:

z(   )

fx   fy  

membrane construction is far removed from the classic tent. The main difference is its exact geometric shape. For the functioning of the membrane structure, the exact geometric criteria must be computed. The basic criterion is to maintain the concavity and convexity of the main directions of the membrane surface. Following this principle, we can talk about the basic four types of membranes:

We think it important to explore new trends in lightweight constructions, among which we

1. saddle-shaped (hyperbolic paraboloid)

can include:

2. ridge-valley shape

1. Lightweight designs designed with regard to sustainability

3. arch shape

2. Modular light constructions

4. conical shape,

3. Sliding light constructions Designers see the benefits of mass production of simple structures, such as an "umbrella" that has reproducible components. Savings from a modular strategy lead to cost-effective

Lightweight Lightweightstructures structures Lightweight Lightweightstructures structures


275

Membrane Material Assessment

membrane in tension is 2,300-4,500 N / 5 cm. If glass fibres are used as the support material,

Modern membrane systems are manufactured from different types of textile membranes. These

the tensile strength of such a membrane will be 3,500-7,500 N / 5 cm.

are produced as composite materials and almost always consist of a bearing woven core and a surface film. The supporting core has a bearing function and therefore transfers the force to the membrane. The surface film has a protective function, ensuring waterproofness and tightness of the membrane.

General area of hyperbolic paraboloid

Sabah Shawkat © ETFE (Ethylene Tetrafluoroethylene)

ETFE is a fluorocarbon - a basic polymer (fluoropolymer) type of plastic. It has been designed as a material with high corrosion resistance and resistance over a wide range of temperatures. It was used for example for the pneumatic panels of the "Allianz Arena" football stadium, or for the "National Water Sports Centre" - the world's largest construction made of ETFE membrane. Also on panels of "Tropical Island" 20 000 m2 in Germany. Because ETFE has excellent mechanical stiffness and chemical resistance with which it can compete with polytetrafluoroethylene (PTFE). In addition, ETFE has high energy radiation resistance and can withstand moderately high temperatures for a long period of time. The strength of the ETFE

Textile membranes used in construction can be divided into several groups according to the

membrane in tension is about 1200 N / 5 cm and ETFE foil 430-500 N / 5 cm.

chemical composition: PVC (Polyvinylchloride) PTFE (Polytetrafluoroethylene)

Teflon is a synthetic fluoropolymer, has a very wide application in industry and construction. It has a high resistance to chemicals and an extremely low friction coefficient. The most famous PTFE membrane material is Gore-Tex. The largest PTFE construction can be termed the "Hubert H. Humphrey Metrodom" roof in Mineapolis with an area of approximately 80,000 m2 where a double-layered membrane with a glass fibre construction is used. Strength of the PTFE

PVC is less rigid and more deformable but also more resistant to mechanical deformations. It has a lower lifetime compared to PTFE material. The carrier material of these membranes is polyester or aramid fibre. The advantage is the lowest price of all materials used and lower flammability. Strength of PVC membrane in tension in combination with polyester carrier fibre is 3,000-9,800 N / 5 cm and aramid carrier fibre 7,000-24,500 N / 5 cm.

Lightweight structures Lightweight structures


276 248

Silicone Lightweight structures silicone is a very progressive material, used in combination with a glass fibre construction. It Architects and engineers are executives of services to reap the intellectual property of previous has a high service life of over 30 years, a third of the PTFE material and, as with the only generations. They are studying, improving and discovering. They are the creators of new material used, its smoke is not toxic. Silicone is mainly used in combination with glass fibre spaces, forms and structures that are constantly improving. This creative activity connects and the tensile strength of such a membrane is 3,500-6,000 N / 5 cm. architects and engineers on their way to the art of "Prof. Frei Otto. Lightweight structures used in various forms and variations can be seen in broad spectrum use Models forThese Modelling Membranes on Material the current market. structures, developed over the years, together with advances in material engineering andpatterns technology, to are progress and are nowmaterial an integral part ofand The material or work of the continue membranes the transfer of real behaviour architectural creation. the approximate view of their modelling. Due to the width of the range of materials used and Architectural lightweight structures can are nowmodelled be seen differ. in different shapes and maythe their design, the ways in which they The simplest waysizes. is to They interpret be membrane internal, external, permanent, temporary, large, small, supported, membranes filled with air material as isotropic material, with a constant modulus of elasticity and a Poison or stretched. New interpellation subgroups of these constructions shell structures, tensile-integrity constant. This has its significant -drawbacks mainly with regard tostructures the texture - are also very current. These unique forms have played an important role in contemporary structure. A more accurate model can be considered an anisotropic orthogonal - orthotropic architecture, interiorBy design events the time first appeared material model. this and we various are ablecultural to capture thesince distance of they material propertiesininthetwo

Advantages of a Tensile Fabric Building Structure (Pros and Cons of tensile Structures) 1. The installation tension membrane structures isthere oftenisfaster and more for cost-effective temporary, constructions. The clients'ofdemands are high nowadays, a demand in comparison to traditional structures. The other factor that clearly puts fabricsimple ahead of transformable solutions that can offer sliding lightweight constructions ranging from

other materials its staircases, clear span which capabilities, Sincebythepressing fabric has amazing tensile sliding marquee solutionsis to disappear thethis button (Khalifa capacity, the effect is to reduce the supporting framework to a minimum number International Stadium). Tensile integrity systems are being developed today for NASA and of supports, all working as a whole system. form unprecedented options for efficiently blame.

Talking about modern systems of steel, wire and membrane has its merit. And that these 2. Due to the translucency tensile fabric building structures provide an abundance of systems are at the top of the current building options. Limits are given by the physical properties daytime light underneath, making it an inviting and comfortable space below. The and laws of the material and the construction system. These must be fully taken into account unique properties of light reflectance and transmission also offer exciting possibilities and used in the creation of the modern system. In practice, we most often encounter the for lighting after dark. following issues: • bars (struts) systems - stable problems of compressive and bent bars, 3. Due to the unique flexible properties of the fabric membrane, tensile membrane • cables systems - prestress, stiffness of the structure, necessity of solving the theory II. order, structures offer architects, designers and engineers an a wide opportunity to investigate • membrane systems prestress, dynamicelegant resistance, deformation solutions. with shape -and create visually and large cone-shaped structures.

Sabah Shawkat ©

1960s by the world-famous perpendicular directions. German architect and engineer Frei Otto. At present, light constructions are designed and constructed independently of the geographic

location. They transform the space and have so subtle and elegant quality. In addition to

Hyper-elastic Materialsuch Model providing basic functions as shading and shutdown, they are an important and functional

element in the construction of amphitheatres, sports stadiums, airports, courtyards, building Hyper-elasticity is a phenomenon when the body returns to its original state after deformation. facades, parks, seafront and interiors. The dependence between tension and relative transformation can be described by a non-linear Designing lightweight constructions to meet all criteria is a complex task. Every part is visible curve. Both the load and the relief run along the same curve. Constitutive models for such and constructive, relying on the proper functioning of all parts. For example, diaphragm fabrics materials are derived from the deformation energy potential, based on the assumption of are developed to meet the requirements for high tensile strength, long life with a high modulus isotropic deformation. It is also necessary to consider that the hyper-elastic materials are almost of elasticity. The surface layer applied to the material ensures fabric resistance against incompressible thus their Poisson constant = 0.5. A typical example of hyper-elastic material weathering and dirt, provides resistance to UV radiation and has non-combustible properties. is rubber. It is also possible to model almost all carbon polymers, glass fibres and, last but not

Tensile membrane architecture is a highly sophisticated medium that offers unique qualities for 4. Tensile structures have demonstrated low maintenance projects architects, designersmembrane and engineers therefore provides unlimitedasopportunities for design as wellfor investors, but ifand properly and installed are virtually immune to damage and as experiment with form create engineered alternative solutions to every day design challenges. weathering. This is made possible due to the fundamental flexibility and lightweight nature of composite membranes. Membrane structures are often referred to as textile structures. However, the actual 5. Due to uniqueiscombination design properties, structure, and is environment, membrane construction far removedoffrom thematerials classic tent. The main difference its exact longevity andfunctioning durability of membrane structures beengeometric proven to criteria withstand geometric the shape. For the oftensile the membrane structure, thehas exact harsh and extreme climates and environments. must be computed. The basic criterion is to maintain the concavity and convexity of the main directions of the membrane surface. Following this principle, we can talk about the basic four types of membranes:

Weleast, thinkbiomaterials it important (blood to explore new trends in lightweight among which we vessels, muscles). The most constructions, commonly used constitutive material

1. saddle-shaped (hyperbolic paraboloid)

canmodels include: are:

2. ridge-valley shape

1. Lightweight designs designed with regard to sustainability • Neo-Hook model, 2. Modular light constructions • Mooney-Rivlin model, 3. Sliding light constructions

3. arch shape 4. conical shape,

• Ogden's Designers seemodel. the benefits of mass production of simple structures, such as an "umbrella" that has reproducible components. Savings from a modular strategy lead to cost-effective

Lightweight Lightweightstructures structures Lightweight Lightweightstructures structures


277

Sabah Shawkat ©

Lightweight structures Lightweight structures


278 248

Lightweight structures Architects and engineers are executives of services to reap the intellectual property of previous

constructions. The clients' demands are high nowadays, there is a demand for temporary,

generations. They are studying, improving and discovering. They are the creators of new

transformable solutions that can offer sliding lightweight constructions ranging from simple

spaces, forms and structures that are constantly improving. This creative activity connects

sliding marquee solutions to staircases, which disappear by pressing the button (Khalifa

architects and engineers on their way to the art of "Prof. Frei Otto.

International Stadium). Tensile integrity systems are being developed today for NASA and

Lightweight structures used in various forms and variations can be seen in broad spectrum use

form unprecedented options for blame.

on the current market. These structures, developed over the years, together with advances in

Talking about modern systems of steel, wire and membrane has its merit. And that these

material engineering and technology, continue to progress and are now an integral part of

systems are at the top of the current building options. Limits are given by the physical properties

architectural creation.

and laws of the material and the construction system. These must be fully taken into account

Architectural lightweight structures can now be seen in different shapes and sizes. They may

and used in the creation of the modern system. In practice, we most often encounter the

be internal, external, permanent, temporary, large, small, supported, membranes filled with air

following issues:

or stretched. New subgroups of these constructions - shell structures, tensile-integrity structures - are also very current. These unique forms have played an important role in contemporary

• bars (struts) systems - stable problems of compressive and bent bars,

architecture, interior design and various cultural events since the time they first appeared in the

• cables systems - prestress, stiffness of the structure, necessity of solving the theory II. order,

1960s by the world-famous German architect and engineer Frei Otto.

• membrane systems - prestress, dynamic resistance, large deformation solutions.

Sabah Shawkat ©

At present, light constructions are designed and constructed independently of the geographic

location. They transform the space and have so subtle and elegant quality. In addition to

providing basic functions such as shading and shutdown, they are an important and functional element in the construction of amphitheatres, sports stadiums, airports, courtyards, building facades, parks, seafront and interiors.

Designing lightweight constructions to meet all criteria is a complex task. Every part is visible and constructive, relying on the proper functioning of all parts. For example, diaphragm fabrics are developed to meet the requirements for high tensile strength, long life with a high modulus of elasticity. The surface layer applied to the material ensures fabric resistance against weathering and dirt, provides resistance to UV radiation and has non-combustible properties.

Tensile membrane architecture is a highly sophisticated medium that offers unique qualities for architects, designers and engineers therefore provides unlimited opportunities for design as well as experiment with form and create alternative solutions to every day design challenges. This is made possible due to the fundamental flexibility and lightweight nature of composite membranes. Membrane structures are often referred to as textile structures. However, the actual membrane construction is far removed from the classic tent. The main difference is its exact geometric shape. For the functioning of the membrane structure, the exact geometric criteria must be computed. The basic criterion is to maintain the concavity and convexity of the main directions of the membrane surface. Following this principle, we can talk about the basic four types of membranes:

We think it important to explore new trends in lightweight constructions, among which we

1. saddle-shaped (hyperbolic paraboloid)

can include:

2. ridge-valley shape

1. Lightweight designs designed with regard to sustainability

3. arch shape

2. Modular light constructions

4. conical shape,

3. Sliding light constructions Designers see the benefits of mass production of simple structures, such as an "umbrella" that has reproducible components. Savings from a modular strategy lead to cost-effective

Lightweight Lightweightstructures structures Lightweight Lightweightstructures structures


279

Sabah Shawkat ©

Lightweight structures Lightweight structures


280 248

Lightweight structures Architects and engineers are executives of services to reap the intellectual property of previous

constructions. The clients' demands are high nowadays, there is a demand for temporary,

generations. They are studying, improving and discovering. They are the creators of new

transformable solutions that can offer sliding lightweight constructions ranging from simple

spaces, forms and structures that are constantly improving. This creative activity connects

sliding marquee solutions to staircases, which disappear by pressing the button (Khalifa

architects and engineers on their way to the art of "Prof. Frei Otto.

International Stadium). Tensile integrity systems are being developed today for NASA and

Lightweight structures used in various forms and variations can be seen in broad spectrum use

form unprecedented options for blame.

on the current market. These structures, developed over the years, together with advances in

Talking about modern systems of steel, wire and membrane has its merit. And that these

material engineering and technology, continue to progress and are now an integral part of

systems are at the top of the current building options. Limits are given by the physical properties

architectural creation.

and laws of the material and the construction system. These must be fully taken into account

Architectural lightweight structures can now be seen in different shapes and sizes. They may

and used in the creation of the modern system. In practice, we most often encounter the

be internal, external, permanent, temporary, large, small, supported, membranes filled with air

following issues:

or stretched. New subgroups of these constructions - shell structures, tensile-integrity structures - are also very current. These unique forms have played an important role in contemporary

• bars (struts) systems - stable problems of compressive and bent bars,

architecture, interior design and various cultural events since the time they first appeared in the

• cables systems - prestress, stiffness of the structure, necessity of solving the theory II. order,

1960s by the world-famous German architect and engineer Frei Otto.

• membrane systems - prestress, dynamic resistance, large deformation solutions.

Sabah Shawkat ©

At present, light constructions are designed and constructed independently of the geographic

location. They transform the space and have so subtle and elegant quality. In addition to

providing basic functions such as shading and shutdown, they are an important and functional element in the construction of amphitheatres, sports stadiums, airports, courtyards, building facades, parks, seafront and interiors.

Designing lightweight constructions to meet all criteria is a complex task. Every part is visible and constructive, relying on the proper functioning of all parts. For example, diaphragm fabrics are developed to meet the requirements for high tensile strength, long life with a high modulus of elasticity. The surface layer applied to the material ensures fabric resistance against weathering and dirt, provides resistance to UV radiation and has non-combustible properties.

Tensile membrane architecture is a highly sophisticated medium that offers unique qualities for architects, designers and engineers therefore provides unlimited opportunities for design as well as experiment with form and create alternative solutions to every day design challenges. This is made possible due to the fundamental flexibility and lightweight nature of composite membranes. Membrane structures are often referred to as textile structures. However, the actual membrane construction is far removed from the classic tent. The main difference is its exact geometric shape. For the functioning of the membrane structure, the exact geometric criteria must be computed. The basic criterion is to maintain the concavity and convexity of the main directions of the membrane surface. Following this principle, we can talk about the basic four types of membranes:

We think it important to explore new trends in lightweight constructions, among which we

1. saddle-shaped (hyperbolic paraboloid)

can include:

2. ridge-valley shape

1. Lightweight designs designed with regard to sustainability

3. arch shape

2. Modular light constructions

4. conical shape,

3. Sliding light constructions Designers see the benefits of mass production of simple structures, such as an "umbrella" that has reproducible components. Savings from a modular strategy lead to cost-effective

Lightweight Lightweightstructures structures Lightweight Lightweightstructures structures


281

Sabah Shawkat ©

Lightweight structures Lightweight structures


282 248

Lightweight structures Architects and engineers are executives of services to reap the intellectual property of previous

constructions. The clients' demands are high nowadays, there is a demand for temporary,

generations. They are studying, improving and discovering. They are the creators of new

transformable solutions that can offer sliding lightweight constructions ranging from simple

spaces, forms and structures that are constantly improving. This creative activity connects

sliding marquee solutions to staircases, which disappear by pressing the button (Khalifa

architects and engineers on their way to the art of "Prof. Frei Otto.

International Stadium). Tensile integrity systems are being developed today for NASA and

Lightweight structures used in various forms and variations can be seen in broad spectrum use

form unprecedented options for blame.

on the current market. These structures, developed over the years, together with advances in

Talking about modern systems of steel, wire and membrane has its merit. And that these

material engineering and technology, continue to progress and are now an integral part of

systems are at the top of the current building options. Limits are given by the physical properties

architectural creation.

and laws of the material and the construction system. These must be fully taken into account

Architectural lightweight structures can now be seen in different shapes and sizes. They may

and used in the creation of the modern system. In practice, we most often encounter the

be internal, external, permanent, temporary, large, small, supported, membranes filled with air

following issues:

or stretched. New subgroups of these constructions - shell structures, tensile-integrity structures - are also very current. These unique forms have played an important role in contemporary

• bars (struts) systems - stable problems of compressive and bent bars,

architecture, interior design and various cultural events since the time they first appeared in the

• cables systems - prestress, stiffness of the structure, necessity of solving the theory II. order,

1960s by the world-famous German architect and engineer Frei Otto.

• membrane systems - prestress, dynamic resistance, large deformation solutions.

Sabah Shawkat ©

At present, light constructions are designed and constructed independently of the geographic

location. They transform the space and have so subtle and elegant quality. In addition to

providing basic functions such as shading and shutdown, they are an important and functional element in the construction of amphitheatres, sports stadiums, airports, courtyards, building facades, parks, seafront and interiors.

Designing lightweight constructions to meet all criteria is a complex task. Every part is visible and constructive, relying on the proper functioning of all parts. For example, diaphragm fabrics are developed to meet the requirements for high tensile strength, long life with a high modulus of elasticity. The surface layer applied to the material ensures fabric resistance against weathering and dirt, provides resistance to UV radiation and has non-combustible properties.

Tensile membrane architecture is a highly sophisticated medium that offers unique qualities for architects, designers and engineers therefore provides unlimited opportunities for design as well as experiment with form and create alternative solutions to every day design challenges. This is made possible due to the fundamental flexibility and lightweight nature of composite membranes. Membrane structures are often referred to as textile structures. However, the actual membrane construction is far removed from the classic tent. The main difference is its exact geometric shape. For the functioning of the membrane structure, the exact geometric criteria must be computed. The basic criterion is to maintain the concavity and convexity of the main directions of the membrane surface. Following this principle, we can talk about the basic four types of membranes:

We think it important to explore new trends in lightweight constructions, among which we

1. saddle-shaped (hyperbolic paraboloid)

can include:

2. ridge-valley shape

1. Lightweight designs designed with regard to sustainability

3. arch shape

2. Modular light constructions

4. conical shape,

3. Sliding light constructions Designers see the benefits of mass production of simple structures, such as an "umbrella" that has reproducible components. Savings from a modular strategy lead to cost-effective

Lightweight Lightweightstructures structures Lightweight Lightweightstructures structures


283

1. Iteration step

Force density method- updated reference strategy Determine iteratively the equilibrium position (xp, yp) of the point p using the Force Density Method, as initial trial position for the iteration and do 3 iteration steps. xk  7m

Evaluation the force density for each element (cable) Si

h

qi

yk  3m

li

li

h

2

x h  x   y h  y  i i  k  k

h

2

l i 

 xk  xi 2   yk  yi 2

2. Draw a convergence diagram for: -The xp coordinate

S´i

q i 

-The yp coordinate

qi 

li

0.596

Horizontal axis: iteration steps, vertical axis: respective entity

i  1  2

x1  5m

xi 

Boundarie

0.606

-The resulting cable forces

x2  10m

yi 

y1  5m

y2  3m

li 

kN

8.246

Note that the quantities xp, yp, l1, l2 refer to the still unknown equilibrium configuration. The coordinates xp and yp are the independent variables (unknowns). Solve the equations granting the equilibrium in both vertical and horizontal directions

Sabah Shawkat © 5

m

10

Cable force:

5

m

Equilibrium conditions:

3

xk

cos i

S´1  5kN

S´2  4kN

S´i  5 4

kN

li

y h  y  i  k

h

sin i

h

cos i 

li

-0.97

1.043

-0.894

  Sicos i   qi  xk 

h

h

i

Ry

  Sisin i   qi  yk

Rxi 

h

h

yk  3 m

-0.576

h

sin i 

 xi

h

 yi

Ryi 

i

-0.576

li

i

 qi  xk  xi

Rxi 

xk

i

i

Initial trial point:

cos i 

h

sin i 

0.849

Rx

xk  7 m

m

6.708

m

kN

Ryi  -8.428 -8.428

Lightweight structures Lightweight structures

 qi  yk  yi i

kN

 yk  yi li


284 248

Iterate steps 1. And 2. until convergence Lightweight structures

Evaluation of the new force densities:

Architects and engineers executives of services to reap the intellectual Equilibrium conditionsare using the assumption of constant force densities:property of previous generations. They are studying, improving and discovering. They are the creators of new K xp yp xk  7 m spaces, forms and structures that are constantly improving. This creative activity connects

architects and engineers on their way to the art of "Prof. Frei Otto.

Given structures used in various forms and variations can be seen in broad spectrum use Lightweight

 

 

xk  x1market.  q 2  These xk  xstructures, 0 xk  Find xk years, together q 1 current on the developed over the with xk  7.479 m advances in 2 material engineering and technology, continue to progress and are now an integral part of Rx q1  xk  x1  q2  xk  x2 yk  3 m architectural creation. Given Architectural lightweight structures can now be seen in different shapes and sizes. They may q 1  yk  y1  q 2  yk  y2 0 yk  Find yk yk  4.008m be internal, external, permanent, temporary, large, small, supported, membranes filled with air

 

or stretched. New subgroups of these 2 2 constructions - shell structures, tensile-integrity structures xk  xi  yk  yi l i  - are also very current. These unique forms have played an important role in contemporary li  qi  architecture, interior design and various cultural events since the time they first appeared in the 2.67 m kN 0.606  1960s by the world-famous German 2.715architect and engineer Frei Otto. m 0.596 At present, light constructions are designed and constructed independently of the geographic

 

constructions. S´i The clients' demands are high nowadays, there is a demand for temporary, q i  qi  transformable l i solutions that can offer sliding lightweight constructions ranging from simple kN sliding marquee solutions to staircases, 1.873  which disappear by pressing the button (Khalifa m 1.473 International Stadium). Tensile integrity systems are being developed today for NASA and form unprecedented options for blame. xk yk  yi cos i  sin i  cos i  sin i  Talking about l imodern systems of steel, l i wire and membrane has its merit. And that these

2.801

-0.371

2.755

0.371

systems are at the top of the current building options. Limits are given by the physical properties and laws of the material and the construction system. These must be fully taken into account andEquilibrium used in theconditions: creation of the modern system. In practice, we most often encounter the following issues: xk  7.479m • bars (struts) systems - stable problems of compressive and bent bars, Given

    Rx q1systems  xk  x1- prestress,  q2  xkdynamic  x2 resistance, ylarge m • membrane deformation solutions. k  4.008

q 1  systems xk  x1 -prestress, q 2  xk stiffness x2 0 of the structure,xk  Findofxksolving thexktheory • cables necessity II.m order,  7.202

Sabah Shawkat ©

location. They transform the space and have so subtle and elegant quality. In addition to Actual cable forces Si  q i l i Si  providing basic functions such as shading and shutdown, 1.619·103they N are an important and functional 3 1.619·10 element in the construction of amphitheatres, sports stadiums, airports, courtyards, building

facades, parks, seafront and interiors. 2. Iteration step Designing lightweight constructions to meet all criteria is a complex task. Every part is visible andUpdate constructive, relying on the proper functioning of all parts. For example, diaphragm fabrics of reference configuration: are developed to meet the requirements for high tensile strength, long life with a high modulus The deformed configuration of the last step is now the reference configuration. of elasticity. The surface layer applied to the material ensures fabric resistance against xk  7.479 m has non-combustible properties. weathering andmdirt, provides resistance to UVyradiation k  4.008and

 

2 to explore new 2 We think trends inl i lightweight constructions, among which we  l i  it important xk  xi  yk  yi 2.67 m can include:

2.715

1. Lightweight designs designed with regard to sustainability 2. Modular light constructions

Given Tensile membrane architecture is a highly sophisticated medium that offers unique qualities for

 

q 1  ykdesigners  y1  qand 0 yk ykfordesign 4.119mas well 2  yengineers architects, providesyunlimited k  y2 therefore k  Findopportunities

as experiment with form and create alternative solutions to every day design challenges. 2 2 li  x  xi  y  yi qi  l i  This is made kpossible duekto the fundamental flexibility and lightweight nature of composite 2.371 m kN  membranes. Membrane structures are often referred3.014 to as textile structures.1.873 However, m the actual 1.473 membrane construction is far removed from the classic tent. The main difference is its exact

 

geometric For the functioning the membrane structure, the exact geometric criteria Si  lof Actual shape. cable forces Si  i q i must be computed. The basic criterion is to maintain the 4.44·10 concavity 3 Nand convexity of the main 4.44·10 directions of the membrane surface. Following this principle, we3 can talk about the basic four

types of membranes: 1. saddle-shaped (hyperbolic paraboloid) Convergence is achieved since the deformed configuration is identical with the reference 2. ridge-valley shape configurations. 3. arch shape 4. conical shape,

3. Sliding light constructions Designers see the benefits of mass production of simple structures, such as an "umbrella" that has reproducible components. Savings from a modular strategy lead to cost-effective

Lightweightstructures structures Lightweight Lightweight Lightweightstructures structures


285

Determine iteratively the equilibrium position (xp, yp) of the point p using the Force Density

xp  4 yp  2

x1  2m

x2  6 m

x3  4 m

y1  2m

y2  4 m

y3  7 m

2. Draw a convergence diagram for:

A ( 2 2)

xi  2

yi 

m

2

x3 y3

6

4

4

7

S´2  6kN

S´3  5kN

S´i 

kN

5

Initial trial point:

P xp yp

A ( 4 2)

xp  4m

yp  2 m

l i 

h

 yp  yi li

 xi

h

i

  Sisin i   qi  yp 

h

h

h

 yi

i

 q i  xp  xi

Ryi 

Rxi 

 qi  yp  yi i

Ryi 

-0.243

kN

sin i 

cos i 

kN

-9.243

li

h

 xp  xi 2   yp  yi 2

2

q i 

S´i li

h

2

(h

1.414

-0.707

-0.243

-9.243

0.8

-1

Given

2 2.121 1

kN  m

    0 q1  xp  x1  q2  xp  x2  q3  xp  x3

2

 

xp  4.047m

 

yp  3.805m

xp  Find xp

Rx

yp  2 m

m

xp  4 m

q 1  xp  x1  q 2  xp  x2  q 3  xp  x3

 xp  xi 2   yp  yi 2

iteration)step

li 

P xp yp

0

2

kN  m

qi  2.121

yp  Find yp

1

qi 

0

-9.243

l i 

x  x   y  y  i i  p  p h

2

-0.243

q 1  yp  y1  q 2  yp  y2  q 3  yp  y3

Define the force density for each element (cable)

li

h

Given

1. Iteration step

h

  Sicos i   qi  xp

3. Iterate steps 1. And 2. until convergence:

6

qi

-1

C ( 4 7)

4

Si

0.8

i

m

sin i 

li

Sabah Shawkat © 

B( 6 4)

Cable force: S´1  4kN

h

0 -0.707

Rxi 

x1 y1

xp

cos i 

h

sin i 

i

respective entity

X1  1

li

1.414

Ry

Horizontal axis: iteration steps, vertical axis:

h

i

The resulting cable forces

sin i

2

Rx

-The xp coordinate -The yp coordinate -

x2 y2

li

y h  y  i  p

h

cos i 

i  1  3

Boundaries:

xp

cos i

Method, as initial trial position for the iteration and do 5 iteration steps.

Si  q i l i

2.828

Si  5.459·103 4.163·103

5

3.196·103

Solve the equations granting the equilibrium in both vertical and horizontal directions

Lightweight structures Lightweight structures

N

li  2.729 1.962 3.196

m


286 248

2. Iterationstructures step Lightweight

3. Iteration step

 

2

2

Architects andm engineers executives of lservices reap the intellectual property xp  4.047 yp are  3.805 m l i  of previous xto i  p  xi  yp  yi 2.729 m of new generations. They are studying, improving and discovering. They are the creators 1.962

 

2 2 constructions. The clients' xp  4.523m yp demands 4.29m are l ihigh l i  for temporary,  nowadays, xp  xi there yp is  yai demand transformable solutions that can offer sliding lightweight constructions ranging 3.407from m simple

spaces, forms and structures that are constantly improving. This creative activity connects

sliding marquee solutions to staircases, which disappear by pressing the 1.505 button (Khalifa

architects and engineers on their way to the art of "Prof. Frei Otto.

International Stadium). Tensile integrity systems are being developed today for NASA and

3.196

2.76

S´istructures used in various forms and variations can be seen in broad spectrum use Lightweight q i  qi  l i market. These structures, developed over the years, together with advances in on the current kN 1.466  material engineering and3.058 technology, m continue to progress and are now an integral part of

form unprecedented options for blame. S´i q i  qi  l i modern systems of steel, wire and membrane has its merit. And that these Talking about kN 1.174  systems are at the top of the current building options. Limits are given by the physical properties m 3.986

architectural creation.

and laws of the material and the construction system. These must be fully taken into account 1.811

1.565

Architectural lightweight structures can now be seen in different shapes and sizes. They may Solve the equations granting the equilibrium in both vertical and horizontal directions be internal, external, permanent, temporary, large, small, supported, membranes filled with air xp subgroups of these yp constructions yi or stretched. New - shell structures, tensile-integrity structures cos i  sin i  cos i  sin i  l l i forms have played an important role in contemporary - are also very i current. These unique 1.483 0.661

2.063since the time -0.1 architecture, interior design and various cultural events they first appeared in the

and used in the creation of the modern system. In practice, we most often encounter the Solve the equations granting the equilibrium in both vertical and horizontal directions following issues: xp yp  yi  i  systems - stable sin i  cos(struts) • bars problems of compressive cos i and  bent bars, sin i  li li

1.328

0.672

• cables systems - prestress, stiffness of the structure,3.005 necessity of solving the theory II. order, 0.192

Sabah Shawkat © 1.267

1960s by the world-famous German architect and engineer Frei Otto.

-1

1.639

-0.982

• membrane systems - prestress, dynamic resistance, large deformation solutions.

At present, light constructions are designed and constructed independently of the geographic xp  4.047m location. They transform the space and have so subtle and elegant quality. In addition to

4.523m architecture is a highly sophisticated medium that offers unique qualities for xp membrane Tensile

providing basic functions such as shading and shutdown, they are an important and functional q 1  xp  x1  q 2  xp  x2  q 3  xp  x3 0 xp  Find xp xp  4.523m element in the construction of amphitheatres, sports stadiums, airports, courtyards, building

q 1  xp  xwith  xcreate 0 xp  day Finddesign xp challenges. xp  4.807m as experiment form to every 1  q 2  xpand 2  qalternative 3  xp  x3 solutions

Given

    Rx parks, q1  xseafront q2interiors.  xp  x2  q3  xp  x3 facades, p  x1 and

 

yp  3.805m

Designing Given lightweight constructions to meet all criteria is a complex task. Every part is visible

 

and qconstructive, relying on the proper functioning 0of all parts. example, fabrics yp For  Find yp diaphragm yp  4.29 m 1  yp  y1  q 2  yp  y2  q 3  yp  y3 are developed to meet the requirements for high tensile strength, long life with a high modulus of elasticity. The surface layer 2 applied to the material ensures fabric resistance against 2 qi  xp  xi  yp  yi li  l i  weathering and dirt, provides resistance to UV radiation and has non-combustible properties. kN 3.407 m 1.466  1.505 constructions, among which mwe We think it important to explore new trends in lightweight 3.058

 

can include:

2.76

1. Lightweight designs designed with regard to sustainability Si  l i q i Si  2. Modular light constructions 3. Sliding light constructions

4.993·103

1.565

architects, Given designers and engineers therefore provides unlimited opportunities for design as well

 

This is made possible due to the fundamental flexibility and lightweight nature of composite

membranes. as textile However, the actual Rx q1Membrane  xp  x1 structures q2  xp are x2often  q3referred  xp  xto yp structures. 4.29m 3 membrane construction is far removed from the classic tent. The main difference is its exact Given

 

geometric structure, the exact criteria q 1  ypshape.  y1 For q 2 the ypfunctioning  y2  q 3  of ypthe  ymembrane 0 yp  Find yp geometric yp  4.443 m 3 must be computed. The basic criterion is to maintain the concavity and convexity of the main directions of the membrane surface. Following this principle, we can talk about the basic four 2 2 qi  l  xp  xi  yp  yi li  typesi of membranes: kN 3.721 m 1.174  1. saddle-shaped (hyperbolic paraboloid) 1.273 m 3.986 2. ridge-valley shape 2.682

 

1.811

3. arch shape 4. conical l i q i shape, Si 

N

Si 

4.602·103

4.368·103

4.319·103

5.073·103

Designers see the benefits of mass production of simple structures, such as an "umbrella" that has reproducible components. Savings from a modular strategy lead to cost-effective

Lightweightstructures structures Lightweight Lightweight Lightweightstructures structures

4.857·103

N


287

4. Iteration step xp  4.807m

yp  4.443m

 xp  xi 2   yp  yi 2

l i 

5. Iteration step

li  3.721

m

1.273

xp  4.951m

yp  4.45m

 xp  xi 2   yp  yi 2

l i 

2.682

q i 

qi 

li

1.075 4.715

kN m

S´i

q i 

qi 

li

xp li

xp  4.807m

5.257

sin i 

 yp  yi

cos i 

li

kN m

1.837

Solve the equations granting the equilibrium in both vertical and horizontal directions

sin i 

1.292

0.656

3.777

0.348

1.792

-0.954

cos i 

xp

sin i 

li

 yp  yi

cos i 

li

sin i 

Sabah Shawkat © 1.291

0.639

4.338

0.394

1.819

-0.937

xp  4.951m

    0 q1  xp  x1  q2  xp  x2  q3  xp  x3

 

q 1  xp  x1  q 2  xp  x2  q 3  xp  x3

xp  Find xp

Rx

yp  4.443m

xp  4.951m

Given

    0 q1  xp  x1  q2  xp  x2  q3  xp  x3

q 1  yp  y1  q 2  yp  y2  q 3  yp  y3

 xp  xi 2   yp  yi 2

li  3.835

0

qi 

m

1.075

1.141

4.715

2.722

Si  l i q i

Si  4.123·103

 

yp  Find yp

yp  4.45m

 

q 1  xp  x1  q 2  xp  x2  q 3  xp  x3

xp  Find xp

Rx

yp  4.45m

Given

Given

l i 

1.043

Solve the equations granting the equilibrium in both vertical and horizontal directions

m

1.141

1.865

Given

3.835 2.722

S´i

cos i 

li 

q 1  yp  y1  q 2  yp  y2  q 3  yp  y3

l i 

 xp  xi 2   yp  yi 2

kN  m

li  3.883

0

qi 

m

1.043

1.052

5.257

2.779

1.865

Si  l i q i

Si  4.05·103

N

5.531·103

5.381·103

5.106·103

5.075·103

Lightweight structures Lightweight structures

 

yp  Find yp

1.837

N

kN m

xp  5.036m

yp  4.421m


288 248

6. Iterationstructures step Lightweight

Determine iteratively the equilibrium position (xp, yp) of the point p using the Force Density

 

2

2

Architects andm engineers executives of previous xp  5.036 yp are  4.421 m lproperty lof xp toxreap ypintellectual  yi i services i  the i  3.883 m generations. They are studying, improving and discovering. They are the creators of new 1.052

spaces, forms and structures that are constantly improving. This creative activity connects 2.779

architects and engineers on their way to the art of "Prof. Frei Otto.

S´istructures used in various forms and variations can be seen in broad spectrum use Lightweight q i  qi  l i market. These structures, developed over the years, together with advances in on the current kN 1.03  material engineering and technology, continue to progress and are now an integral part of m 5.703

architectural creation. 1.799 Architectural lightweight structures can now be seen in different shapes and sizes. They may Solve the equations granting the equilibrium in both vertical and horizontal directions be internal, external, permanent, temporary, large, small, supported, membranes filled with air or stretched. New subgroups of these constructions - shell structures, tensile-integrity structures ypforms  yi have played an important role in contemporary - are also veryxpcurrent. These unique cos i  sin i  cos i  sin i  li i architecture, interior design and variouslcultural events since the time they0.624 first appeared in the 1.297

Method, as initial trial position for the and do 5 there iteration constructions. The clients' demands are iteration high nowadays, is asteps. demand for temporary, transformable that can offer sliding lightweight constructions ranging from simple xp  4 ypsolutions  4 sliding marquee solutions to staircases, which disappear by pressing the button (Khalifa 2. Draw a convergence diagram for: International Stadium). Tensile integrity systems are being developed today for NASA and -The xp coordinate -The yp coordinate form unprecedented options for blame. -The resulting cable forces Talking about axis: modern systems of vertical steel, wire Horizontal iteration steps, axis:and membrane has its merit. And that these systems are at the top of the current building options. Limits are given by the physical properties respective entity and laws x1 and  2the m construction x2  5msystem. These must be fully taken into account i  of 1  the 5 material and used in the creation of the modern system. In practice, we most often encounter the x3  5m x4  3 m x5  2 m following issues: y1  2m y2  2m y3  8m • barsy(struts) systemsy- stable  11m  8mproblems of compressive and bent bars, 4

5

Boundaries: x1 yof ( 2 2) necessity of solving the theory II. order, • cables systems - prestress, structure, X1  1 stiffness 1 the A

Sabah Shawkat ©

4.786 Frei Otto. 1960s by the world-famous German architect and engineer 1.812

0.4

-0.928

At present, light constructions are designed and constructed independently of the geographic

location. They transform the space and have so subtle and elegant quality. In addition to xp  5.036m providing basic functions such as shading and shutdown, they are an important and functional Given

element in the construction of amphitheatres, sports stadiums, airports, courtyards, building q 1  xp  x1  q 2  xp  x2  q 3  xp  x3 0 xp  Find xp xp  5.095m facades, parks, seafront and interiors. Rx qlightweight  q2  xp  x2to meet  q3 all xpcriteria  x3 is a complex yp  4.421 m Every part is visible Designing task. 1  xp  x1 constructions

 

 

 

and Given constructive, relying on the proper functioning of all parts. For example, diaphragm fabrics

 

are developed meet the requirements for high tensile strength, long lifeywith ya high modulus q 1  yp  yto 0 yp  Find 1  q 2  yp  y2  q 3  yp  y3 p p  4.391m of elasticity. The surface layer applied to the material ensures fabric resistance against 2 2 q i non-combustible properties. l i  and xp dirt, xi provides  yp  resistance yi i  radiation and has weathering to lUV kN 3.911 m 1.03  We think it important to explore new trends in0.986 lightweight constructions, m among which we

can include:

 

5.703

2.829

1.799

1. Lightweight designs designed with regard to sustainability Si  l i light q i constructions Si  2. Modular 4.029·103 N 3. Sliding light constructions 3

xi systems - yprestress, • membrane dynamic resistance, large deformation solutions. i  2 m 2 m Tensile membrane architecture is a highly sophisticated medium that offers unique qualities for 5 2 5 8 architects, designers and engineers therefore provides unlimited opportunities for design as well 3

11

2

8

as experiment with form and create alternative solutions to every day design challenges. This is made possible due to the fundamental flexibility and lightweight nature of composite

membranes. are often referred to as textile structures. However, the actual x2Membrane y2 B(structures 5 2) membrane construction is far removed from the classic tent. The main difference is its exact x3 y3 C ( 5 8) geometric shape. For the functioning of the membrane structure, the exact geometric criteria x y D( 3 11) X5  5 X  4 must be4 computed. 4The4basic criterion is to maintain the concavity and convexity of the main

x5 yof ( 2 8) directions membrane surface. Following this principle, we can talk about the basic four 5 the E types of membranes: Cable force: S´  3kN S´  5kN S´  4kN S´  5kN S´  6kN 1

2

1. saddle-shaped (hyperbolic paraboloid) S´i  2. ridge-valley shape 3 kN

3

4

3. arch shape 5

4 4. conical shape, 5

5.621·10

6

3

Designers see the benefits of mass production5.09·10 of simple structures, such as an "umbrella" that has reproducible components. Savings from a modular strategy lead to cost-effective

Initial trial point:

Lightweightstructures structures Lightweight Lightweight Lightweightstructures structures

P xp yp

A (4 4)

xp  4 m

yp  4 m

5


289

1. Iteration step Define the force density for each element (cable) Si

h

qi

li

li

h

2

x h  x   y h  y  i i  p  p

h

 xp  xi 2   yp  yi 2

l i 

S´i

q i 

1.061

kN m

0.97

 

2.828

m

2.236

xp

cos i

li

cos i 

0.97

0

xp  3.635m

yp  4 m Given

yp  yi

 

yp  5.204m l i 

q 1  yp  y1  q 2  yp  y2  q 3  yp  y3  q 4  yp  y  q 5  yp  y5 4

yp  Find yp

 xp  xi 2   yp  yi 2

0

qi  1.061

li

2.236

kN m

Sabah Shawkat © 1.342

 S cos h  i   i

i

q h  x h  x  i  i  p

  Sisin i   qi  yp 

h

i

h

 yi

 q i  xp  xi

Ryi 

i

-7.603

 qi  yp  yi

7.787

3.112

3.019

5.831

4.123

3.239

4.346

h

qi

cos i 

sin i 

1.414

0.707

2.305

-7.603

1.789

0.894

2.305

-7.603

0.97

-0.97

2.305

-7.603

0.566

-0.99

2.305

-7.603

0.894

-0.894

Iterate steps 1. And 2. until convergence

3.815

kN

2. Iteration step Define the force density for each element (cable)

i

kN

Si 

3.483

i

Ryi 

m

3.597

i

h

Si  q i l i

li 

-0.894

kN

0.97

-0.99

2.305

0.707

-0.97

0.894

Rxi 

0.894

0.566

Rxi 

li

0.707

1.789

Ry

li

h

sin i 

sin i 

1.414

Rx

sin i

h

cos i 

q1  xp  x1  q2  xp  x2  q3  xp  x3  q 4  yp  x4  q 5  yp  x5   

Rx

4.123

Solve the equations granting the equilibrium in both vertical and horizontal directions xp

xp  Find xp

li 

4.472

1.342

q 1  xp  x1  q 2  xp  x2  q 3  xp  x3  q 4  xp  x4  q 5  xp  x5

7.071

0.707

y h  y  i  p

xp  4 m

h = iteration step

2.236

h

Given

2

qi 

li

P xp yp

q i 

Si li

h

S´i li

li

2

x h  x   y h  y  i i  p  p

h

qi  0.834 1.436

kN  m

1.286 0.858 1.852

Lightweight structures Lightweight structures

2

li  3.597 3.483 3.112 5.831 3.239

l i 

m

 xp  xi 2   yp  yi 2


290 248

Solve the equations Lightweight structures granting the equilibrium in both vertical and horizontal directions Architects and engineers are executives the intellectual property of previous h  y h  y of services to reap xp yp  yi xp p i  cos    i  are the creators of new generations. improving and idiscovering.sinThey cos i They aresinstudying, i h h li li spaces, formsliand structures thatli are constantly improving. This creative activity connects

h  S"Prof.  h h  cos i and  engineers sinon architects tox the art of i their way R i  Otto. qi  xp  xi  icos Frei 1.011

0.891

i

i

Lightweight in various forms and variations can be seen in broad spectrum use 1.044 structures used 0.92

2 

2

q i high  nowadays, l i  xp The  xi clients'  yp demands  yi l i there is a demand for temporary, constructions. are kN 4.475 m  0.834lightweight transformable solutions that can offer sliding constructions ranging from simple 4.515 m 1.436 sliding marquee solutions to staircases, which disappear2.354 by pressing the button (Khalifa 1.286

4.783 International Stadium). Tensile integrity systems are being developed today for NASA and 0.858 2.276 form unprecedented options for blame. 1.852

0.623 -0.994 material engineering and technology, continue to progress and are now an integral part of

q i l i modernSsystems Si about Talking of steel, wire and membrane has its merit. And that these i  3.732 kN systems are at the top of the current building options. Limits are given by the physical properties

architectural creation.

and laws of the material and the construction system. These must be fully taken into account

-0.899 structures, developed over the years, together with advances in on the 1.168 current market. These 1.122

-0.863

6.482 3.026

h beseen in different shapes and sizes. They may Architectural lightweight  S sin h  structures q hcan  now Ry i   i  i  yp  yi be internal, iexternal, permanent, temporary, large, small, supported, membranes filled with air i

and used in the creation 4.102 of the modern system. In practice, we most often encounter the

or stretched. tensile-integrity structures Rxi  New Ryi   yp structures,  yi  qsubgroups q- ishell i  xp  xi  of these constructions  - are also very played an important role in contemporary i current. These unique forms have i Rxi  interior design  the time they firstsin  i  in the Ryand cos isince i  various cultural events architecture, appeared 1.222 kN -6.472 kN 1.011 0.891 1960s by the world-famous German architect and engineer Frei Otto.

3. Iteration step Define theproblems force density for each element (cable): • bars (struts) systems - stable of compressive and bent bars,

 

 

following issues:

4.217

• cables systems - prestress, stiffness of the structure, necessity of solving the theory II. order,

Sabah Shawkat ©

1.222

-6.472

1.044

0.92

At present, are designed and constructed independently of the-0.899 geographic 1.222 light constructions -6.472 1.168 1.222 location. They 1.222

transform

the-6.472 space -6.472

and have so

0.623 and subtle 1.122

elegant quality.

In-0.994 addition -0.863

to

providing basic functions such as shading and shutdown, they are an important and functional

element in the construction of amphitheatres, airports, courtyards, building 3. Iterate steps 1. And 2. until convergence sports P xpstadiums, yp xp  3.635 m facades, parks, seafront and interiors. Given

Designing all criteria is a complex task. Every part is visible q 1  xp lightweight  x1  q 2  constructions xp  x2  q 3to  xmeet 0 p  x3  q 4  xp  x4  q 5  xp  x5 and constructive, relying on the proper functioning of all parts. For example, diaphragm fabrics xp  Findtoxpmeet the xphigh  3.44 m strength, long life with a high modulus l i requirements  are developed for tensile

 

3.597 m of elasticity. The surface layer applied to the material ensures fabric resistance against 3.483

weathering and dirt, provides resistance to UV radiation and has non-combustible properties. 3.112 5.831

We think it important to explore 3.239 new trends in lightweight constructions, among which we can include: Rx q1  xp  x1  q2  xp  x2  q3  xp  x3  q 4  yp  x4  q 5  yp  x5  1. Lightweight designs designed with regard to sustainability yp  5.204m 2. Modular light constructions

3. Sliding Given light constructions q 1  yp  y1  q 2  yp  y2  q 3  yp  y3  q 4  yp  y  q 5  yp  y5 0 4 Designers see the benefits of mass production of simple structures, such as an "umbrella" that

 

Sisystems -h prestress,hdynamic 2 2 • membrane solutions. h 2 2  x  x   resistance,  y h  y large deformation li qi l i  xp  xi  yp  yi i i  p  p h li Tensile membrane architecture is a highly sophisticated medium that offers unique qualities for

 

architects, designers and engineers therefore provides unlimited opportunities for design as well S´i q i  q i  and create alternative l i  solutions to every day design challenges. as experiment with form li kN 4.475 m This is made possible due  fundamental flexibility and lightweight nature of composite 0.67to the 4.515 m membranes. Membrane1.107 structures are often referred to as textile structures. However, the actual 2.354 1.699

4.783 membrane construction is far removed from the classic tent. The main difference is its exact 1.045

geometric shape. For the functioning of the2.276 membrane structure, the exact geometric criteria 2.636 must be computed. The basic criterion is to maintain the concavity and convexity of the main Solve the equations granting the equilibrium in both vertical and horizontal directions directions of the membrane surface. Following this principle, we can talk about the basic four h types of membranes: y h  y  xp xp i  p cos i  cos  sin  1. saddle-shaped (hyperbolic paraboloid) i i h h li li li 2. ridge-valley shape Rxi  sin i  cos i  q i  xp  xi  3. arch shape 0.769

0.947

1.461

-0.749

0.719

-0.996

1.511

-0.775

4. 0.762 conical shape, 0.938

has yreproducible Savings from a modular strategy lead to cost-effective yp  6.237 m p  Find yp components.

Lightweightstructures structures Lightweight Lightweight Lightweightstructures structures

  i

sin i  Ryi 

 yp  yi li

 q i  yp  yi i


291

Rxi 

Ryi 

kN

0.842

-5.089

sin i 

cos i 

kN

0.769

0.842

-5.089

0.762

0.938

0.842

-5.089

1.461

-0.749

0.842

-5.089

0.719

-0.996

0.842

-5.089

1.511

-0.775

3. Iterate steps 1. And 2. until convergence

P xp yp

4. Iteration step Define the force density for each element (cable):

0.947

Si

h

qi

li

h

q i 

xp  3.44m

li S´i

2

x h  x   y h  y  i i  p  p

h

qi 

li

0.586 0.957

Given

li 

kN  m

5.225 1.98

 

xp  Find xp

li  4.475

1.69

3.551

xp  3.322m

m

4.065

1.23

0

 xp  xi 2   yp  yi 2

l i 

m

5.122

2.02

q 1  xp  x1  q 2  xp  x2  q 3  xp  x3  q 4  xp  x4  q 5  xp  x5

2

Solve the equations granting the equilibrium in both vertical and horizontal directions

4.515 2.354 4.783 2.276

cos i

li

h

cos i 

yp  6.237m Given

q 1  yp  y1  q 2  yp  y2  q 3  yp  y3  q 4  yp  y  q 5  yp  y5 4

 

yp  Find yp

l i 

0

sin i

qi  0.67 1.107 1.699 1.045 2.636

Si  3.433

kN

kN m

li 

li

cos i 

h

Rxi 

sin i 

0.649

0.966

0.636

0.947

1.678

-0.531

0.817

-0.997

1.966

-0.623

Rxi 

yp  6.948m

 xp  xi 2   yp  yi 2

Si  q i l i

y h  y  i  p

h

xp

 yp  yi

sin i 

li

li

Sabah Shawkat © 

q1  xp  x1  q2  xp  x2  q3  xp  x3  q 4  yp  x4  q 5  yp  x5   

Rx

xp

0.872

-3.212

kN

i

0.649

-3.212

0.636

0.872

-3.212

1.678

5.225

0.872

-3.212

0.817

1.98

0.872

-3.212

1.966

m

 qi  yp  yi

cos i 

0.872

5.122

Ryi 

i

Ryi 

kN

 qi  xp  xi

4.065 1.69

3. Iterate steps 1. And 2. until convergence: P xp yp

xp  3.322m

Given

5.786 3.365 4.249

q 1  xp  x1  q 2  xp  x2  q 3  xp  x3  q 4  xp  x4  q 5  xp  x5

4.454

Lightweight structures Lightweight structures

0


292 248

 

Lightweight structures xp  Find xp

xp  3.218m m Architects and engineers are executives of services to reap the intellectual property of previous

li 

5.122 5.225

cos i 

Rxi 

sin i 

0.588 constructions. 0.572

The

0.975 clients' 0.948

 qi  xp  xi

Ryi 

 q i  yp  yi

i for temporary, demands arei high nowadays, there is a demand

generations. They are studying,1.98 improving and discovering. They are the creators of new 4.065 spaces, forms and structures that are constantly improving. This creative activity connects

transformable solutions that can offer sliding lightweight constructions ranging from simple

architects and engineers on their way to the art of "Prof. Frei Otto.

2.317 Stadium). -0.48 International Tensile integrity systems are being developed today for NASA and

1.69

Rx q1 structures  xp  x1 used  q2in  xvarious  q3  and xp variations x3  q 4can x4 inqbroad x5  use 5  yp  p  x2 forms Lightweight spectrum   ypbeseen 

on the current market. These structures, developed over the years, together with advances in yp  6.948m material engineering and technology, continue to progress and are now an integral part of Given architectural creation.

           or stretched. New subgroups of these constructions - shell structures, tensile-integrity structures 2 2 Si  q i l i Si  l i   xp  xi   yp  yi q i  li  - are also very current. These unique forms have played an important role in contemporary 

Architectural  y2  q 3can  ypnow  y3beseen q 4  in yp different  y  qshapes y5 sizes. 0 They may q 1  yp  ylightweight 1  q 2  ypstructures 5  yp and 4 be internal, external, permanent, temporary, large, small, supported, membranes filled with air yp  Find yp yp  7.333m

kN 5.47 m 3.204 kN 0.586  5.623 5.381in the architecture, interior design and various culturalm events since the time they first appeared 0.957

1.691

-0.351

sliding0.876 marquee solutions -0.998 to staircases, which disappear by pressing the button (Khalifa form unprecedented options for blame. Ryi  cos i  Rxi  sin i  0.895 kN -1.609 kN 0.588 Talking about modern systems of steel, wire and membrane has its0.975 merit. And that these 0.895

-1.609

0.572

0.948

systems0.895 are at the top of the current Limits are given by the physical properties -1.609 building options. 1.691 -0.351 0.895 0.876These must be -0.998 and laws of the material and-1.609 the construction system. fully taken into account 0.895 -0.48 and used in the creation of-1.609 the modern system.2.317 In practice, we most often encounter the

following issues: 3. Iterate steps 1. And 2. until convergence Given

P xp yp

xp  3.218m

• bars (struts) systems - stable problems of compressive and bent bars,

q 1  xp  x1  q 2  xp  x2  q 3  xp  x3  q 4  xp  x4  q 5  xp  x5 0 • cables systems - prestress, stiffness of the structure, necessity of solving the theory II. order,

Sabah Shawkat ©

1.903 1960s by the world-famous German architect 2.02 and engineer Frei Otto.

3.844

3.674

4.519

1.23 and constructed independently of the geographic At present, light constructions are designed 1.389 4.931 3.551 location. They transform the space and have so subtle and elegant quality. In addition to

providing basicstep functions such shading andfor shutdown, they (cable): are an important and functional 5. Iteration Define the as force density each element

element in the construction of amphitheatres, sports stadiums, airports, courtyards, building Si 2 2 h h h h 2 2 facades, li and interiors. xp  xi   yp  yi qi parks, seafront l i  xp  xi  yp  yi h l Designing lightweight constructions to meet all criteria is a complex task. Every part is visible i S´i and qconstructive, relying of all parts. For example, diaphragm fabrics q i  on the proper functioning li  i  l i are developed to meet the requirements for high strength, long life with a high modulus kN 5.47 tensile m 0.548  5.623 m of elasticity. The surface layer applied to the material ensures fabric resistance against 0.889

 

1.903

weathering and dirt, provides 2.102 resistance to UV radiation and has non-combustible properties. 1.361

3.674

1.389 We think it important to explore new trends in lightweight constructions, among which we 4.321

can include: Solve the equations granting the equilibrium in both vertical and horizontal directions 1. Lightweight designs designed with regard to sustainability

 

xp  Find xp x  3.121m li  • membrane systems - prestress, dynamic presistance, large deformation solutions. 5.47 m 5.623 Tensile membrane architecture is a highly sophisticated medium that offers unique qualities for 1.903

architects, designers and engineers therefore provides unlimited opportunities for design as well 3.674

as experiment with form and1.389 create alternative solutions to every day design challenges. This is made possible due to the fundamental flexibility and lightweight nature of composite Rx q1  xp  x1  q2  xp  x2  q3  xp  x3  q 4  yp  x4  q 5  yp  x5  membranes. Membrane structures are often referred to as textile structures. However, the actual

membrane construction is far removed from the classic tent. The main difference is its exact yp  7.333 m geometric shape. For the functioning of the membrane structure, the exact geometric criteria Given

must be computed. The basic criterion is to maintain the concavity and convexity of the main y1 membrane  q 2  yp  surface. y2  q 3Following  yp  y3 this  q 4principle,  yp  y we  qcan y5 0 basic four q 1  ypof the 5  ytalk directions the p  about

4

types of membranes: y  Find yp yp  7.507m 1.p saddle-shaped (hyperbolic paraboloid)

 

2. ridge-valley shape

h h 2. Modular light xp yp  yi xp constructions  yp  yi cos i  sin i   sin  cos 3. Slidingi light hconstructionsi h li li li li Designers see the benefits of mass production of simple structures, such as an "umbrella" that

l i arch shape xp  xi 3.

 2   yp  yi 2

4. conical shape,

has reproducible components. Savings from a modular strategy lead to cost-effective

Lightweightstructures structures Lightweight Lightweight Lightweightstructures structures

qi  0.548 0.889 2.102 1.361 4.321

kN  m

li  5.62 5.819 1.943 3.495 1.224

m


293

Si  q i l i

Si 

6. Iteration step Si

h

qi

h

q i 

5.62

5.175

5.819

4.084

1.943

4.756

3.495

5.29

1.224

2

x h  x   y h  y  i i  p  p

h

xp  3.041m

m

2

l i 

xp  xi

  2

 yp  yi

2

0.534 0.859

li 

kN m

5.62

m

Given

5.819

3.495

1.431

1.224

4.901

q 1  yp  y1  q 2  yp  y2  q 3  yp  y3  q 4  yp  y  q 5  yp  y5 4

1.943

2.059

 

yp  Find yp

yp  7.584m

h

cos i

li

h

sin i

y h  y  i  p li

0.555

Rxi 

0.98

0.536

0.946

1.606

-0.254

0.893

-0.999

2.549

-0.402

Rxi  0.78

kN

xp cos i  li

h

sin i 

cos i 

Ryi 

 q i  xp  xi

Ryi 

i

0.534

li

0.859

cos i 

 qi  yp  yi

0.536

0.946

1.606

-0.254

0.78

-0.754

0.893

-0.999

0.78

-0.754

2.549

-0.402

3. Iterate steps 1. And 2. until convergence Given

4.123 4.887

0.98

P xp yp

5.494

xp  3.121m

q 1  xp  x1  q 2  xp  x2  q 3  xp  x3  q 4  xp  x4  q 5  xp  x5

0

Lightweight structures Lightweight structures

5.681 5.918 2.003 1.121

4.901

Si 

li 

3.416

1.431

sin i 

0.555

kN  m

2.059

5.085

-0.754

qi 

3.032

-0.754

 xp  xi 2   yp  yi 2

i

0.78

l i 

Si  q i l i

kN

-0.754

 yp  yi

sin i 

0.78

0

Sabah Shawkat ©

Solve the equations granting the equilibrium in both vertical and horizontal directions xp

q1  xp  x1  q2  xp  x2  q3  xp  x3  q 4  yp  x4  q 5  yp  x5 

Rx

yp  7.507m

qi 

li

li 

Define the force density for each element (cable): li

li S´i

 

xp  Find xp

kN

3.082

kN

m


294 248

Mohr´s circle of stress Lightweight structures

max 

2

b 

b  4 c 2 The

2

min 

max  7.202

b  b  4 c

min  0.798

demand for temporary,

Architects and engineers are executives of services to reap the intellectual property of previous

constructions.

generations. They are studying, improving and discovering. They are the creators of new

transformable solutions that can offer sliding lightweight constructions ranging from simple

spaces, forms and structures that are constantly improving. This creative activity connects

sliding marquee solutions to staircases, which disappear by pressing the button (Khalifa

architects and engineers on their way to the art of "Prof. Frei Otto.

International Stadium). Tensile integrity systems are being developed today for NASA and

Lightweight structures used in various forms and variations can be seen in broad spectrum use

clients' demands are high nowadays, there is

2a

form unprecedented options for blame.

on the current market. These structures, developed over the years, together with advances in

Talking about modern systems of steel, wire and membrane has its merit. And that these

material engineering and technology, continue to progress and are now an integral part of

systems are at the top of the current building options. Limits are given by the physical properties

architectural creation.

and laws of the material and the construction system. These must be fully taken into account

Architectural lightweight structures can now be seen in different shapes and sizes. They may

and used in the creation of the modern system. In practice, we most often encounter the

be internal, external, permanent, temporary, large, small, supported, membranes filled with air

following issues:

or stretched. New subgroups of these constructions - shell structures, tensile-integrity structures - are also very current. These unique forms have played an important role in contemporary architecture, interior design and various cultural events since the time they first appeared in0 the   1 Solution of the principal stress eigenvalue problem:    0 I  n 0 n n   1960s by the world-famous German architect and engineer Frei Otto.  0 At Characteristic present, light polynomial: constructions are designed and constructed independently of the geographic

• bars (struts) systems - stable problems of compressive and bent bars, • cables systems - prestress, stiffness of the structure, necessity of solving the theory II. order,

Sabah Shawkat ©

location. They transform the space and have so subtle and elegant quality. In addition to

 11  2basic  22  6 such 12  2.5 and 12  12 they21 12important and functional providing functions as shading shutdown, arean

element in the construction of amphitheatres, sports stadiums, airports, courtyards, building

facades, parks, seafront and interiors.  11  0 12  2  det  (  lightweight 0  I)  ( 11  22 ( 12) part is visible 02all criteria 0  11 22 Designing constructions is a)  complex task. Every   21 22  0to  meet   and constructive, relying on the proper functioning of all parts. For example, diaphragm fabrics are developed to meet the requirements for high tensile strength, long life with a high modulus 2  )  0  layer 11 22applied  ( 12) to  det   fabric 0 of elasticity. surface resistance against 02  (11The 22  the 2  tr 0ensures  0material  weathering and dirt, provides resistance to UV radiation and has non-combustible properties. Analytical solution. Principal stresses: We think it important to explore new trends in lightweight constructions, among which we can include: Characteristic polynomial of the eigenvalue 1. Lightweight designs designed with regard to problem: sustainability

• membrane systems - prestress, dynamic resistance, large deformation solutions. Tensile membrane architecture is a highly sophisticated medium that offers unique qualities for architects, designers and engineers therefore provides unlimited opportunities for design as well as experiment with form and create alternative solutions to every day design challenges. This is made possible due to the fundamental flexibility and lightweight nature of composite membranes. Membrane structures are often referred to as textile structures. However, the actual membrane construction is far removed from the classic tent. The main difference is its exact geometric shape. For the functioning of the membrane structure, the exact geometric criteria must be computed. The basic criterion is to maintain the concavity and convexity of the main directions of the membrane surface. Following this principle, we can talk about the basic four types of membranes: Analytical solution. Principal stress directions: 1. saddle-shaped (hyperbolic paraboloid) 2. ridge-valley shape

2. Modular light constructions 3. Sliding light constructions  11 12      n 0  n 0 b  ( 11  22) b 8 det  (   0  I) det   I    0 0 n  21 22    0 n Designers see the benefits of mass production of simple structures, such as an "umbrella" that

0 Ishape n 0 min  0.798 3.  arch 4. conical shape, n  11 12   1 0   1     min     21 22   0 1   n2 

has reproducible 2components. Savings from2 a modular strategy lead to cost-effective 11 22  ( 12)

c  11 22  ( 12)

c  5.75

Lightweightstructures structures Lightweight Lightweight Lightweightstructures structures

I

n 0   0 n

  min I n

0

 11 12      1 0    1.202 2.5    min  0 1   2.5 5.202  21 22     

n 1  1


295

1   n2 

( 1.202 2.5 )  

1

n min 

b 

2

 2

1  n2 1 2

 2

1  n2

n min 

0

 0.901     0.433

1.202 1  2.5 n 2

1   n2 



1.202

n 2 

0

a 

2.5

Plan stress state and principal stresses: A membrane is subjected to a shear deformation. The material itself can be assumed to behave linear elastic (the stress - strain relationship can

1 2

n 2  0.481

 2

1  n2

a  0.901

be described with the Hooke an law for the plane stress state.) Material parameters: Strain state at point P referring to the given local coordinate system:

 n 2 b  0.433

reference configuration

n max 

b    a

or

n max 

 0.433    0.901

 11  0.01

  11      22   22  0.02   0.05      

2 12

 12

 21   0.4 E  0.200

kN 2

mm

1. Determine the stress state at point P referring to the given local coordinate system

Sabah Shawkat © 2. Evaluate the principal stresses and their directions 3. Determine the principal strains

(Hint: A principal strain state is defined by vanishing shear deformation. You can use the

inverse relationship of the Hooke an law to determine the principal strains from the principal stresses)

Extra question: Are the realistic?

(Consider the characteristic mechanical behaviour of membranes) Hooke an law for the plane stress state: 1. Determine stresses:

  11      22      

C 

or

  11      22   2    12 

C

0  1  0  1   2  1 1 0 0  2 E

   

 11     22     12 

C is the so called constitutive or elasticity matrix (in general it is a fourth-order elasticity tensor) E represents the Young´s modulus

Lightweight structures Lightweight structures


296 248

The Plane Stress Problem

Lightweight structures ν the poisons ratio Architects of services to reap the intellectual property of previous 0    1 are executives  11  and engineers  11   4.286   11     They  0 1  E   generations. and discovering. are the creators of new  22   They are studying, improving   22   22    5.714  MPa 2  1       This  creative  structures 0 0 spaces, that are constantly improving. 3.571 12forms1 and  activity connects     2     12   architects and engineers on their way to the art of "Prof. Frei Otto. The invers relationship is as follows: Lightweight structures used in various forms and variations can be seen in broad spectrum use   11   11   1  over0 theyears, together  with  advances in on the current market. These structures, developed 1  1  0  C  C   1    22    22  and are now an integral part of E  material engineering and technology, continue to progress  2      0 0 2 ( 1   )  12   12  architectural creation. The strain in the thickness direction can be determined as: Architectural lightweight structures can now be seen in different shapes and sizes. They may    be internal,  33  external,    temporary,  small, supported, membranes filled with air     permanent,      large,  E  11 22  1    11 22 or stretched. New subgroups of these constructions - shell structures, tensile-integrity structures 2. Determine principal stress: - are also very current. These unique forms have played an important role in contemporary  0 and 12 various   11design architecture, interior appeared in the 2 cultural events since the time2 they first 2 det   0I  0   11  22 0  1122  12  0  tr0  det 0          1960s by the world-famous German 22 0 architect and engineer Frei Otto.  21 2 location. space and have so subtle and elegant quality. In addition to 0  They 22  0  the 11  transform  11 22   12  0 providing basic functions such as shading and shutdown, they are an important and functional

element in the construction of amphitheatres, 2sports stadiums, airports, courtyards, 2building B  10 MPa C  11.735MPa  B  11  22 C  11 22   12    facades, parks, seafront and interiors.

Designing lightweight constructions to meet all criteria is a complex task. Every part is visible B

2

2

B  4 C

B  B  4 C

  8.642  MPa 02 diaphragm 1.358 MPa fabrics 01 and constructive, relying on the02 proper functioning of all parts. For example, 01  2

2

are developed to meet the requirements for high tensile strength, long life with a high modulus 3. Determine principal stress directions: of elasticity. The surface layer applied to the material ensures fabric resistance against 

is a 2D problem. The stresses in the z direction are considered to be negligible. sliding marquee solutions to staircases, which disappear by pressing the button (Khalifa zzsystems yz are 0 International Stadium). Tensile integrity developed today for NASA and xz being The stress-strain compliance relationship for an isotropic material becomes: form unprecedented options for blame.

Talking about modern systems of steel, wire and membrane has its merit. And that these   xx    1  options.  0 Limits 0 0 given  building   byxxthe systems are at the top of the current are  physical properties  yy    1  0 0 0   yy  and laws of the material and system. These must   be fully taken into account   the  construction 0 0 0   0   zz     1 most often encounter the and used in the creation of the modern system. In practice, we 0 0  0  yz   0 0 0 1       0 0 0 following issues: 0 1   0   0    zx   0 0 1     0 0 0  xy  • bars (struts) systems - stable of compressive and bent bars,  xyproblems  The three zero stress entries in the stress vector indicate that we can ignore their associated • cables systems - prestress, stiffness of (i.e. the structure, solving theory II. order, columns in the compliance matrix columns necessity 3, 4, andof5). If wethe also ignore the rows

Sabah Shawkat ©

At present, light constructions are designed and constructed independently of the geographic 2

The plane stress analysisdemands refers to are the high problems where there the thickness of thefor structure is very temporary, constructions. The clients' nowadays, is a demand small compared to other of the structure in the XY plane. The planefrom stresssimple problem transformable solutions thatdimensions can offer sliding lightweight constructions ranging

 8.642 MPa

 4.286 MPa

 5.714 MPa

 3.571 MPa

01 11 resistance to UV 22 12 weathering and dirt, provides radiation and has non-combustible properties.

We think to explore new trends in lightweight constructions, among which we   11 itimportant 12   1 0    n 1   0   11 12      1 0    4.356 3.571   MPa  01     01 0 1 can include:  12 22   12 22   0 1   n 2   0     3.571 2.928 1. Lightweight designs designed with regard to sustainability 4.356 MPa  n n 1  1 4.356 MPa  n 1  3.571 MPa n 2 0 2. Modular light constructions

n 2 

1

( 3.571 MPa )

n 2  1.22

3. Sliding light1constructions  n1   0.634  0.773 n 01    n 01   n 02     n2  0.773 2 2    0.634    of mass production of simple structures, n 1 the  nbenefits Designers see such as an "umbrella" that 2 has reproducible components. Savings from a modular strategy lead to cost-effective

associatedsystems with the- prestress, strain components with z-subscripts, the compliance matrix reduces to a • membrane dynamic resistance, large deformation solutions. simple 3x3 matrix, Tensile membrane architecture is a highly sophisticated medium that offers unique qualities for    xx  0   xx   1 unlimited   provides  opportunities for design as well architects, designers and engineers therefore 1    1 0    yy    yy    E as experiment with form and create alternative solutions to every day design challenges.   0 0 0   xy    xy  This is made possible due to the fundamental flexibility and lightweight nature of composite membranes. Membrane are often referred as textile However, the actual The stiffness matrix structures for plane stress is found by to inverting thestructures. plane stress compliance matrix, and is given by, membrane construction is far removed from the classic tent. The main difference is its exact geometric shape. For the functioning structure, the exact geometric criteria  of the membrane  xx    xx   xx   1  0   xx       and  convexity of the main E must be computed. The basic criterion is to maintain the concavity        1 0  yy   yy   yy   yy   2     of 1the   principle,   membrane directions this we can talk about the basic four     Following  0 0 1 surface.  xy   xy   xy   xy  types of membranes: 1. saddle-shaped (hyperbolic paraboloid) If:   xx  0.015   0.025  xy  0.022 2. ridge-valley shape yy

  0.4

E  0.200

kN 2

mm

Stresses: in-plane stress field forms a tensor defined by three independent components: 3. arch The shape xx , yy and xy 4. conical shape,   xx   1  0   xx    E   1 0     yy   yy      1   2  0 0 1        xy   xy 

Lightweightstructures structures Lightweight Lightweight Lightweightstructures structures

 xx   

   yy 

   xy 

 5.952

   7.381 MPa

   3.143


297

The force density method The Force Density method is popular among space structure designers and the method was developed at the end of the 1960s by German engineers Linkwitz and Schek for the determination of cable net structures or for the initial equilibrium problem of the cable roofs at the Olympic Games in 1972 hosted by Munich. Their goal was to determine a geometry that would be sufficiently rigid without the addition of load ballasts, geometry that would be built easily and would efficiently carry the loads over long distances using subtle elements. This method became very popular rapidly and designers began to work on researches from various countries, which caused expansion and variation. Prestressed cable-nets structure and textile membranes are characterised by the inherent interaction between their geometry and stress distribution. This relationship between the form and forces makes it impossible to directly design such structures as is the case with conventional structures.

Sabah Shawkat ©

Assumption for using this method is that, that the creating elements of the analysed structure, must be straight and must be pin-joined to each other or to the supporting structure, which is fulfilled in this case. First, a graph of a network is drawn and all nodes are numbered from 1 to Ns, and all the elements are numbered from 1 to m. The Nf nodes which are to be fixed

points are taken at the end of the sequence. All the other nodes N are considered as free. Thus the total number of nodes is Ns= N + Nf. Then the connectivity matrix Cs is constructed with the aid of the graph. Each element j has the node numbers k and l (from k to l).

Looking at the geometric model of a typical node of the net, it is clear that this node will be in a steady position, if the resulting force effect of the members will be in equilibrium with the external load in the node. On this basis, it is possible to construct the equilibrium rule for the node as follows: The element between the nodes i and j will be denoted by (i, j). The nodes that are linked with elements by the node i will be called "neighbours" to node i, and the set of their labels will be denoted by Ni. Nf ∪ Ns means the set of those elements which are either in Nf, or in Ns, or in both

Nf ∩ Ns means the set that contains all those elements that Nf and Ns have in common

Lightweight structures Lightweight structures


298 248

Lightweight structures Architects and engineers are executives of services to reap the intellectual property of previous

constructions. The clients' demands are high nowadays, there is a demand for temporary,

generations. They are studying, improving and discovering. They are the creators of new

transformable solutions that can offer sliding lightweight constructions ranging from simple

spaces, forms and structures that are constantly improving. This creative activity connects

sliding marquee solutions to staircases, which disappear by pressing the button (Khalifa

architects and engineers on their way to the art of "Prof. Frei Otto.

International Stadium). Tensile integrity systems are being developed today for NASA and

Lightweight structures used in various forms and variations can be seen in broad spectrum use

form unprecedented options for blame.

on the current market. These structures, developed over the years, together with advances in

Talking about modern systems of steel, wire and membrane has its merit. And that these

material engineering and technology, continue to progress and are now an integral part of

systems are at the top of the current building options. Limits are given by the physical properties

architectural creation.

and laws of the material and the construction system. These must be fully taken into account

Architectural lightweight structures can now be seen in different shapes and sizes. They may

and used in the creation of the modern system. In practice, we most often encounter the

be internal, external, permanent, temporary, large, small, supported, membranes filled with air

following issues:

or stretched. New subgroups of these constructions - shell structures, tensile-integrity structures - are also very current. These unique forms have played an important role in contemporary

• bars (struts) systems - stable problems of compressive and bent bars,

architecture, interior design and various cultural events since the time they first appeared in the

• cables systems - prestress, stiffness of the structure, necessity of solving the theory II. order,

1960s by the world-famous German architect and engineer Frei Otto.

• membrane systems - prestress, dynamic resistance, large deformation solutions.

Sabah Shawkat ©

At present, light constructions are designed and constructed independently of the geographic

location. They transform the space and have so subtle and elegant quality. In addition to

providing basic functions such as shading and shutdown, they are an important and functional element in the construction of amphitheatres, sports stadiums, airports, courtyards, building facades, parks, seafront and interiors.

Designing lightweight constructions to meet all criteria is a complex task. Every part is visible and constructive, relying on the proper functioning of all parts. For example, diaphragm fabrics are developed to meet the requirements for high tensile strength, long life with a high modulus of elasticity. The surface layer applied to the material ensures fabric resistance against weathering and dirt, provides resistance to UV radiation and has non-combustible properties.

Tensile membrane architecture is a highly sophisticated medium that offers unique qualities for architects, designers and engineers therefore provides unlimited opportunities for design as well as experiment with form and create alternative solutions to every day design challenges. This is made possible due to the fundamental flexibility and lightweight nature of composite membranes. Membrane structures are often referred to as textile structures. However, the actual membrane construction is far removed from the classic tent. The main difference is its exact geometric shape. For the functioning of the membrane structure, the exact geometric criteria must be computed. The basic criterion is to maintain the concavity and convexity of the main directions of the membrane surface. Following this principle, we can talk about the basic four types of membranes:

We think it important to explore new trends in lightweight constructions, among which we

1. saddle-shaped (hyperbolic paraboloid)

can include:

2. ridge-valley shape

1. Lightweight designs designed with regard to sustainability

3. arch shape

2. Modular light constructions

4. conical shape,

3. Sliding light constructions Designers see the benefits of mass production of simple structures, such as an "umbrella" that has reproducible components. Savings from a modular strategy lead to cost-effective

Lightweightstructures structures Lightweight Lightweight Lightweightstructures structures


299

The equilibrium equations for the free nodes for the x-, y- and z-directions are written as T

( C )  ( U )  ( L)

1

S

 F x

T

( C) ( V) ( L)

1

 Fy

S

T

( C) ( W) ( L)

1

S

 Fz

By using the force-to-length ratios for the elements, i.e. the force densities, are written as: T

( C) ( U) q

 Fx

T

( C) ( V) q

 Fy

 Fz

T

( C) ( W) q

where the vector q, of length m. is described as: (q )

( L)

1

( S)

We write down the matrix expression of equation of equilibrium to the shape: The connectivity matric Cs for the structure is define by (i = 1,2,…Ns).

( U) q

( Q) ( u)

( V) q

( Q ) ( v )

( W) q

( Q) ( w)

at the stage when we have a single initial set geometry, it is necessary to create the connectivity matric Cs. This matrix represents. the number of columns are the number of nodes and the

we can translate equations of equilibrium into shape:

number of rows is the number of members, each row will have 1, -1 and 0, depending on the

Sabah Shawkat ©

node in which the node starts its 1 and its end we denote -1. all other cells in the row will be zero.

For purposes of a further calculation, it is convenient to note that the connectivity matric Cs is

based on two partial C-matrices, including nodes that can change their position during the

T

     Fx

T

     Fx

T

     Fx

(C) (Q)(C)(x)  (C)(Q) Cf  xf

( C) ( Q) ( C) ( y)  ( C) ( Q)  Cf  yf ( C) ( Q) ( C) ( z)  ( C) ( Q)  Cf  zf

calculation, and Cf that contains only nodes re-assisting the support.

By defining the positioning vectors xs, ys, zs from which are again based on the partial vectors related to the free node x, y, z and related to the fixed node xf, yf, zf , we can calculate the vector

after the introduction of substitution

(D)

 Df

T

(C) (Q) (C)

 

T

( C) ( Q)  Cf

displacement of each node, in all directions of the global coordinate system,

Cs

continue to shape

 C Cf

(D) (x)

where C and Cf contains the free and fixed nodes, respectively. Denoting the vectors containing

u

Cs xs

C x  Cf xf

v

Cs ys

C y  Cf yf

w

Cs zs

C z  Cf zf

( D) ( y)

 Fy  Df  yf

( D) ( z)

 Fz  Df  zf

from which we express the node's final position

the coordinates of the n free nodes x, y, z, and similarly for the Nf fixed nodes xf, yf, zf, the coordinate differences for each element can be written as:

 Fx  Df  xf

( x)

 Fx  Df   xf  ( D)

( z)

 Fz  Df   zf  ( D)

Lightweight structures Lightweight structures

1

1

( y)

 Fy  Df   yf  ( D)

1


300 248

The equilibrium equations described above represent the linear system of equations, after the Lightweight structures solution we obtain the equilibrium of the position of the nodes. By introducing a force density Architects and engineers are executives of services to reap the intellectual property of previous coefficient (q) a set of otherwise non-linear equations was modified to allow it generations. They are studying, improving and discovering. They are the creators of new solution in one computed step. However, this method of solution is spaces, forms and structures that are constantly improving. This creative activity connects highly difficult for programming. architects and engineers on their way to the art of "Prof. Frei Otto. The force structures density method commonly used incan engineering find spectrum the equilibrium Lightweight used in(FDM), various isforms and variations be seen intobroad use shape of a structure consisting of a network of cables with different elasticity properties on the current market. These structures, developed over the years, together with advanceswhen in

2 

2 

2

xj  xi  yj  yi  zj  zi l ( i j ) l xi yi zi xj yj zj constructions. The clients' demands are high nowadays, there is a demand for temporary, transformable solutions that can offer sliding lightweight constructions ranging from simple zj  zi  xj  xi  yj  yi        sliding marquee (Khalifa  Si j solutions  to0 staircases, which  Si j  disappear  0by  pressingthe Si jbutton   0 l l l i j  i j  i j   Stadium).  integrity systems     International Tensile are being developed j Ni j Ni j Ni today for NASA and

form unprecedented options for blame. -- Si,j is the force value in the element (i, j), with positive orientation from the node i toward Talking about the node j, modern systems of steel, wire and membrane has its merit. And that these

stress engineering is applied. While shape analysis of tensile structures is anow geometrically material and technology, continue to progress and are an integral non-linear part of problem, the FDM linearizes the equations analytically by using the force density ratio for each architectural creation.

systems at γi,j the top the current building options. are of given the physical properties -- αi,j,are βi,j, are of angles between coordinate axesLimits and axis the by element (i, j), oriented from

cable element, q = S /L,structures where S and are the forcein and length of a cable element respectively. Architectural lightweight canLnow be seen different shapes and sizes. They may method relies permanent, on the assumption that large, the ratio of tension forcemembranes to length offilled eachwith cableaircan be The internal, external, temporary, small, supported,

and used in the creation of the modern system. In practice, we most often encounter the

be constant, transforming a system of non-linear- shell equations to a set of linear equations which or stretched. New subgroups of these constructions structures, tensile-integrity structures can be solved directly. - are also very current. These unique forms have played an important role in contemporary architecture, interior and density various cultural since the timestudied they first appeared in thethe The properties of design the force method events were subsequently thoroughly and 1960s by the world-famous German architect and engineer Frei Otto. method could be implemented in an efficient way by applying special sparse matrix techniques

andi toward laws ofj,the material and the construction system. These must be fully taken into account following issues: • bars (struts) systems - stable problems of compressive and bent bars, • cables systems - prestress, stiffness of the structure, necessity of solving the theory II. order,

Sabah Shawkat ©

At for present, light are designed and to constructed independently of theup geographic solving theconstructions resulting equations. It proved be a powerful tool for setting and solving

location. They transform the space have so networks subtle and elegant quality. In addition to the equations of equilibrium for and prestressed and structural membranes, without providing basic functions such as shading and shutdown, they are an important and functional requiring any initial coordinates of the structures. element in the construction of amphitheatres, sports stadiums, airports, courtyards, building The essential ideas are as follows. Pin-joined network structures assume the state of equilibrium facades, parks, seafront and interiors. when internal forces S and external forces F are balanced Designing lightweight constructions to meet all criteria is a complex task. Every part is visible

the compilation of on a computational program, of equations equilibrium be converted andFor constructive, relying the proper functioning all parts.ofFor example, can diaphragm fabricsinto following arethe developed to form: meet the requirements for high tensile strength, long life with a high modulus of elasticity. The surface layer applied to the material ensures fabric resistance against

Equilibrium free node i resistance to UV radiation and has non-combustible properties. weathering and of dirt, provides We think it important to explore new trends in lightweight constructions, among which we j ∈ Ni means j is an element of the set Ni can include:

1. Lightweight 0 0  Si designs  Stoi sustainability j cos i designed j  j cos i j   with regard  2. Modular j Ni light constructions

j Ni

 Si j cos i j 

• membrane systems - prestress, dynamic resistance, large deformation solutions. Tensile membrane architecture is a highly sophisticated medium that offers unique qualities for architects, designers and engineers therefore provides unlimited opportunities for design as well as experiment with form and create alternative solutions to every day design challenges. This is made possible due to the fundamental flexibility and lightweight nature of composite

of thestructures element (i,j). li,j is the length membranes. Membrane are often referred to as textile structures. However, the actual The nonlinear algebraic equation system obtained membrane construction is far removed fromwill thebeclassic tent. The main difference is its exact xj  xiof the membrane geometric shape. For the functioning the exact geometric criteria   structure,  Si j   0 must be computed. The basic and convexity of the main 2 criterion is2 to maintain2 the concavity   xj  xi  yj  yi  zj  zi  j Ni   directions of the membrane surface. Following this principle, we can talk about the basic four

j Ni

3. Sliding light constructions xj  xi yj  yi zj  zi cos i see cos i production cosstructures, j the benefits of mass j i j Designers of simple as an "umbrella" that l i j l i j l i such j has where reproducible components. Savings from a modular strategy lead to cost-effective

 

types of membranes:

y  yi  1. saddle-shaped (hyperbolicj paraboloid) Si j  2 2  2. ridge-valley shape xj  xi  yj  yi  zj  zi j Ni 

0 

 

3. arch shape

4. conical shape,

j Ni

 Si j   

 

 

Lightweight Lightweightstructures structures



   xj  xi 2   yj  yi 2   zj  zi 2 zj  zi

i ∈ Nf means i is an element of the set Nf

Lightweightstructures structures Lightweight

 

2

0

 

0

 


301

If the relationships Si,j / li,j in the equilibrium system are denoted qi,j, the system becomes Si j

q ( i j )

 xj  xi   yj  yi 2   zj  zi 2 2

are called force densities

q i j  zj  zi

q i j  yj  yi

j Ni

0

q i j  xj  xi

0

j Ni 0

j Ni

Force densities qi,j can be set instead of force values Si,j.

qij. xj  xi  qik  xk  xi  qil xl  xi  qim xm  xi  Fxi

0

Sabah Shawkat ©

qijxj  qijxi  qik xk  qik xi  qilxl  qilxi  qimxm  qimxi  Fxi

xi  qij  qik  qil  qim  qijxj  qik xk  qilxl  qimxm  Fxi

xi  qij  qik  qil  qim

xi

0

0.

qijxj  qik xk  qilxl  qimxm  Fxi

 qijxj  qikxk  qilxl  qimxm  Fxi  qij  qik  qil  qim

what is possible for the general network topology write as follows: n



xi

n



xj qij  Fxi

j1

yi

n

qij

j1

n

  zjqij  Fzi

yj qij  Fyi

j1

zi

n

j1

qij

j1

n

qij

j1

This suggests that the equilibrium position of each node in the space is a function of the average position of its neighbours, where the great coefficient is the force density of the bristles seizing the solved nodes.

Lightweight structures Lightweight structures


302 248

Lightweight structures Architects and engineers are executives of services to reap the intellectual property of previous To illustrate the properties of the linear force densities a simple example will now be given. generations. They are studying, improving and discovering. They are the creators of new Consider the structure bellow with all fixed nodes in the x-y plane. spaces, and Initialforms position of structures free nodes that are constantly improving. This creative activity connects architects and engineers on their way to the art of "Prof. Frei Otto. 0  1 0  1  2  0   structures  used    forms and variations can be seen in broad spectrum use Lightweight in various x   0  y   0  z   0  on the current market. structures,  1  0 These   0  developed over the years, together with advances in       1 material 2engineering and technology,     0  continue to progress and are now an integral part of architectural creation.of fixed nodes (supports): The initial position Architectural  0  lightweight  2  structures 2can  now be seen in different shapes and sizes. They may       0 0 0    be internal, external, permanent, temporary, large, small, supported, membranes filled with air xf  y f  zf   2  2  0 or stretched. of these 2constructions - shell structures, tensile-integrity structures  2  New subgroups  0        - are also very current. These unique forms have played an important role in contemporary architecture, interior design and various cultural events since the time they first appeared in the

constructions. The clients' demands are high nowadays, there is a demand for temporary, Matrix of continuity transformable solutions that can offer sliding lightweight constructions ranging from simple 1 0 0 0 0  0 0   1 0 disappear sliding marquee solutions to staircases, which   by pressing the button (Khalifa 0 1 0 0 0   1 0 0 0  International Stadium). Tensile integrity systems are being 1 0 0 0 0   0 1 0 0  developed today for NASA and  1 0 1 0 options  0 0 0 0 form unprecedented for blame. 0      0 1 1 0 0  0 0 0 0 Talking about has its merit. And that these  0 and 0 0  systems of steel, wire 0 1 0 modern 0 membrane 1 0  C   Cf     0 are given by the physical properties 0 0at 0the 1top0of the current building 0 1 0Limits systemsare options.    1 1 0  0 0 0   0system. and laws 0of0 the material and the construction These must be fully taken into account  0 0 1 0 1  0 0 0 0  in the creation  of the modern system.   and used In practice, we most often encounter the 1 0 0 0 0    0 0 1 0  following issues: 0 0 0 1 0   0 0 0 1  0 0 0 0 1   0 0 0 1      • bars (struts) systems - stable problems of compressive and bent bars, External Load of Free Nodes:

• cables systems - prestress, stiffness of the structure, necessity of solving the theory II. order,

Sabah Shawkat ©

1960s by the world-famous German architect and engineer Frei Otto.

At present, light constructions are designed and constructed independently of the geographic

location. They transform the space and have so subtle and elegant quality. In addition to

providing basic functions such as shading and shutdown, they are an important and functional element in the construction of amphitheatres, sports stadiums, airports, courtyards, building facades, parks, seafront and interiors.

Designing lightweight constructions to meet all criteria is a complex task. Every part is visible

and constructive, relying on the proper functioning of all parts. For example, diaphragm fabrics A simple cable structure with zero external loads. The arrows indicate the directions of elements. are developed to meet the requirements for high tensile strength, long life with a high modulus of elasticity. The surface layer applied to the material ensures fabric resistance against weathering and dirt, provides resistance to UV radiation and has non-combustible properties. We think it important to explore new trends in lightweight constructions, among which we can include: 1. Lightweight designs designed with regard to sustainability 2. Modular light constructions

0  0  systems - prestress,  0  resistance, large deformation solutions. • membrane dynamic        0  0  0 Fx  membrane Fyarchitecture   0  Fzahighly Tensile is  0  0  sophisticated medium that offers unique qualities for  0  0  0 architects, designers and engineers therefore provides unlimited opportunities for design as well        0  0  0 as experiment with form and create alternative solutions to every day design challenges.

Force Density Coefficient of Prestress:

This is made possible due to the fundamental flexibility and lightweight nature of composite 0 0 0 0 0 0 0 0 0 0  1 0 Membrane membranes. structures are  often referred to as textile structures. However, the actual 0 1 0 0 0 0 0 0 0 0 0 0  membrane construction is far removed from the classic tent. The main difference is its exact  0 0 1 0 0 0 0 0 0 0 0 0  0 shape.  of the membrane structure, the exact geometric criteria geometric 0 0 1 For 0 0 the 0 0functioning 0 0 0 0   0 0 0 0 1 0 0 0 0 0 0 0   is to maintain the concavity and convexity of the main must be computed. The basic criterion  0 0 0 0 0 1 0 0 0 0 0 0 directions Q   of the membrane surface. Following this principle, we can talk about the basic four  0 0 0 0 0 0 1 0 0 0 0 0 types ofmembranes: 0 0 0 0 0 0 0 1 0 0 0 0  0 0 0 0 0 0 (hyperbolic  0 0 1 0 0 0paraboloid) 1. saddle-shaped   0 0 0 0 0 0 0 1 0 0 0 0   2. ridge-valley shape  0 0 0 0 0 0 0 0 0 0 1 0 3. arch shape  0 0 0 0 0 0 0 0 0 0 0 1   4. conical shape,

3. Sliding light constructions

Designers see the benefits of mass production of simple structures, such as an "umbrella" that

has reproducible components. Savings from a modular strategy lead to cost-effective

Lightweightstructures structures Lightweight Lightweight Lightweightstructures structures


303

Design stiffness matrix:

3 0  T D  C  Q C   1 0  0

0 1 0 3 1 0 1 4 1 0 1 3 0 1 0

0

 1  1  T Df  C  Q Cf   0 0  0

  0  1  0   3 

1 0 0 1 0

0

1 0 0 1

Calculation of new position of free nodes

  0  0  1   1  0

Calculation of new position of free nodes:

 0.333    1  1 x  D   Fx  Df  xf    1   1     1.667

For different force density values we get different resulting shapes of this structure. it is seen that

 1     1.667 1 y  D   Fy  Df  y f    1   0.333    1 

 1    1 1 D   Fz  Df  zf    1   1    1

Design stiffness matrix

i  1  12

q  1 i

 q1   q2  df   0  0   0 

q

3

0

0

q

0

0

q 0

7

0 q

    0  q  11  q  12  0 0

6

10

3 1 0 1 4 1 0 1 0

of that element. the opposite holds for decrease in the force density, even more emphasised with negative values. For elements 1-3, 5-12 have q = 1 and element 4 has q = 9 q

3

0

0

  0   0  q  11  q  12 

Sabah Shawkat ©

0 1 0

0 1 3

for a single element an increase in the force density relative to the others results in a construction

 q 1   q 2  d f   0  0   0 

0  q1  q3  q4  q q q 0  2 5 6  q  q q d   4 5 4  0 0   0 0 

3 0  d   1 0  0

 0.333  1   1  1   1.667  1       1 1 1 x  d   Fx  d f  xf    1  y  d   Fy  d f  y f    1  z  d   Fz  d f  zf    1   1   0.333  1        1.667  1   1

0

  0  1  0   3 

q q

5

q q

 1  1  df   0  0   0

8

q

9

8

q q q

8

7

8

0

9

1

0

0

0

1

0

0

0

0

1

0

1

0

1 1

      

    q  9  0  q q q  9 10 12  0

0

q q q 5

0

0

4

11

0

q

0

0

q

7

0

6

0

q

10

0  q1  q3  q4  q q q 0  2 5 6  q  q q d   4 5 4  0 0   0 0 

 11   0 d   9  0   0

0

9

0

0

3

1

0

0

    1 12  1  1  0 1 3 0   0 1 0 3 

Lightweight structures Lightweight structures

q q

5

q q

8

q

9

7

8

0

9

 1   1 df   0  0   0

8

q q q

8

1

0

0

0

1

0

    q  9  0  q q q  9 10 12  0

0

q q q 5

0

0

4

   0 0 0  1 0 1   0 1 1 

11


304 248

Lightweight structures Architects and engineers are executives of services to reap the intellectual property of previous Calculation of new position of free nodes generations. They are studying, improving and discovering. They are the creators of new  0.6   1   1  0.911that are constantly improving.  1.667 This creative activity  1 connects spaces, forms and structures       1 1 1 x  d and   Fxengineers  d f  xf   on 0.733 y  dto the   Fyart  dof 1  Otto. z  d   Fz  d f  zf    1   way architects their f  y"Prof. f    Frei  0.911  0.333  1  in various forms and variations     Lightweight structures used use  1.578  1 can be seen in broad spectrum  1 on the current market. These structures, developed over the years, together with advances in material engineering and technology, continue to progress and are now an integral part of For elements 1‐3, 5‐12 have q = 1 and element 4 has q = ‐0.2 architectural creation. 0   q 1 q 3 0  lightweight structures  Architectural can now be seen in different shapes and sizes. They may  q 2 0 q 6 0   temporary, large, small, supported, membranes filled with air be internal, external, permanent, 0  0 0 d f   0 or stretched. subgroups of these constructions - shell structures, tensile-integrity structures  New 0 q 0 q  7 11   - are also very current. These  0 0 q 10 q 12  unique forms have played an important role in contemporary   architecture, interior design and various cultural events since the time they first appeared in the 0 0 0 q q q   qthe 3 4 4 1960s by German architect and engineer Frei Otto.  1 world-famous  0 q 0 0 q  q  q   light constructions 2 5 6are designed 5 and constructed independentlyof the geographic At present,   q q q q q q q q  d   In addition to 5 4 and 5 have 8 9so subtle 8 and elegant9 quality. location. They 4 transform the space   0 0 q q q 0 q providing 7 8 they 11 are an important  basic functions such as shading8 and shutdown,  and functional   q  q  q courtyards, 0 of amphitheatres, q airports, 0 elementin the0 construction sports stadiums, building 9 9 10 12 

constructions. The clients' demands are high nowadays, there is a demand for temporary, For interior elements 4-5, 8-9 have q = 1 and edge elements 1,2,3,6,7,10,11,12 have q = 6 transformable solutions that can offer sliding lightweight constructions ranging from simple 0  0  q 1 q 3 solutions sliding marquee to   staircases, which disappear by pressing the button (Khalifa  q 2 0 q 6 0  International Stadium). Tensile integrity systems are being developed today for NASA and     0 0 0 0  formdfunprecedented options for blame.  0 q 0 q  7 11   Talking about of steel, wire and membrane has its merit. And that these q systems 0modern q  0 10 12   systems are at the top of the current building options. Limits are given by the physical properties and laws of the material and the construction system. These must be fully taken into account 0 0 0 q q q   q 1in the 3 creation 4 and used of the modern4 system. In practice, we most often encounter the   0 q 0 0 q  q  q   issues:  2 5 6 5 following   q q q q q q q q d    4 5 4 5 8 9 8 9 • bars (struts) systems - stable problems of compressive and bent bars,   0 0 q q q 0 q 8 7 8 11    theory II. order, q  q the 0 - prestress, 0 stiffness of the qofsolving q structure, necessity 0 • cables systems 9 9 10 12  

Sabah Shawkat ©

facades, parks, seafront and interiors. 0 0.2 0 0  1 0 0   1.8lightweight  1 to Designing constructions meet all     criteria is a complex task. Every part is visible 0 3 1 0 0 1 0 1 0  on the proper functioning  and dconstructive, relying of all parts. For example, diaphragm fabrics   0.2 1 2.8 1 1  d f   0 0 0 0      are developed tensile strength, long life with a high modulus 0 0 to1meet 3 the 0 requirements 0 1 for 0 high 1     1 surface 0 3  layer 0 1 to 1  the material ensures fabric resistance against  0 0 The  0 applied of elasticity. weathering and dirt, provides resistance to UV radiation and has non-combustible properties. Calculation of new position of free nodes

We think it important to explore new trends in lightweight constructions, among which we  0.167  1   1       can include: 1.167 1.667      1 1 1 1 d f  xf  designed y  dregard   Fy to  dsustainability x  d   Fx designs  1.5  with 1. Lightweight f  y f    1  z  d   Fz  d f  zf    1   1.167   0.333  1 2. Modular light constructions        1.833   1   1 3. Sliding light constructions

• membrane systems - prestress, dynamic resistance, large deformation solutions.  13 0 1 0 0   6 6 0 0   0 13 1 0 0   6 0 6 0  Tensilemembrane architecture is a highly sophisticated medium that offers unique qualities for    d   1 1 4 1 1  df   0 0 0 0  architects, designers and engineers therefore provides unlimited opportunities for design as well  0 0 1 13 0   0 6 0 6   and create alternative  as experiment with form solutionsto every day design challenges.  0 0 1 0 13   0 0 6 6  This is made possible due to the fundamental flexibility and lightweight nature of composite membranes. Membrane structures are often referred to as textile structures. However, the actual

membrane construction is far removed from the classic tent. The main difference is its exact Calculation of new position of free nodes geometric shape. For the functioning of the membrane structure, the exact geometric criteria

must be computed. The basic criterion is to maintain the concavity and convexity of the main  0.077  1  we can talk about the  1 basic four  directions of the membrane surface. Following this principle,       1 1.923      1 types of membranes: 1 1 1 x  d   Fx  d f  xf    1  y  d   Fy  d f  y f    1  z  d   Fz  d f  zf    1  1. saddle-shaped (hyperbolic paraboloid)  1   0.077  1        1.923  1   1 2. ridge-valley shape

3. arch shape 4. conical shape,

Designers see the benefits of mass production of simple structures, such as an "umbrella" that has reproducible components. Savings from a modular strategy lead to cost-effective

Lightweightstructures structures Lightweight Lightweight Lightweightstructures structures


305

The calculation of stiffness and stiffness matrix.

Assemble the bar elements 1 and 2 in one stiffness matrix according to figure in a: k1 0   u1   k1    k1  k1  k2 k2   u 2  0  u  k2 k2    3

 F1     F2  F   3

According to the figure in b, then the stiffness matrix we can indicate as:  k1 k1 0   u 1      k1 k1 0    u 2      0 0 0   u3 

According to the figure in c, then the stiffness matrix we can indicate as:

 k1  k2 k2  u2    k2 k2   u 3    

 F2   F3   

Boundary conditions figure in c, then the stiffness matrix we can indicate as:

Sabah Shawkat ©

k k ( A  E)  11 12   1     L  k21 k22   0    ( A  E)

Fi

L ( A  E)

Fj

L

 Fi   Fj   

u ( A  E)  1 1   i      L  1 1  u j  

 Fi   Fj   

 k1  k2 k2  u2    k2 k2   u 3    

0   P

 ui  uj

 u i  u j

Element 1- bar element: ( A  E) L

 k1 k1   u 1    k1 k1   u 2    



 F1   F2   

k1 u 1

F1

k2 u 2

F2

k1

F1 u1

Element 2 - bar element:

 k2 k2   u 2    k2 k2   u 3    

 F2   F3   

k2

F2 u2

Lightweight structures Lightweight structures


306 248

Lightweight structures Architects and engineers are executives of services to reap the intellectual property of previous

constructions. The clients' demands are high nowadays, there is a demand for temporary,

generations. They are studying, improving and discovering. They are the creators of new

transformable solutions that can offer sliding lightweight constructions ranging from simple

spaces, forms and structures that are constantly improving. This creative activity connects

sliding marquee solutions to staircases, which disappear by pressing the button (Khalifa

architects and engineers on their way to the art of "Prof. Frei Otto.

International Stadium). Tensile integrity systems are being developed today for NASA and

Lightweight structures used in various forms and variations can be seen in broad spectrum use

form unprecedented options for blame.

on the current market. These structures, developed over the years, together with advances in

Talking about modern systems of steel, wire and membrane has its merit. And that these

material engineering and technology, continue to progress and are now an integral part of

systems are at the top of the current building options. Limits are given by the physical properties

architectural creation.

and laws of the material and the construction system. These must be fully taken into account

Architectural lightweight structures can now be seen in different shapes and sizes. They may

and used in the creation of the modern system. In practice, we most often encounter the

be internal, external, permanent, temporary, large, small, supported, membranes filled with air

following issues:

or stretched. New subgroups of these constructions - shell structures, tensile-integrity structures - are also very current. These unique forms have played an important role in contemporary

• bars (struts) systems - stable problems of compressive and bent bars,

architecture, interior design and various cultural events since the time they first appeared in the

• cables systems - prestress, stiffness of the structure, necessity of solving the theory II. order,

1960s by the world-famous German architect and engineer Frei Otto.

• membrane systems - prestress, dynamic resistance, large deformation solutions.

At present, light constructions are designed and constructed independently of the geographic According to a location. They transform the space and have so subtle and elegant quality. In addition to

Tensile membrane architecture is a highly sophisticated medium that offers unique qualities for

Sabah Shawkat ©

1  functions such as 1 shading  providing basic and shutdown, they are an important and functional u N u  N u N N 1

2

2

2

1 1

2 2

element in the construction of amphitheatres, sports stadiums, airports, courtyards, building Cantilever beam- Example facades, parks, seafront and interiors. u

 0 mm

u

 10  mm

1 lightweight constructions 2 Designing to meet all criteria is a complex task. Every part is visible

and constructive, on the proper functioning of all of parts. example, diaphragm if we want relying to find the displacement in the middle the For Cantilever beam where fabrics  0 Each node has athe shape function for high tensile strength, long life with a high modulus are developed to meet requirements

of elasticity.1 The   surface layer applied to the material ensures fabric resistance against N1  0.5 N1  weathering and2 dirt, provides resistance to UV radiation and has non-combustible properties. N2 

1 

N2  0.5

architects, designers and engineers therefore provides unlimited opportunities for design as well as experiment with form and create alternative solutions to every day design challenges. This is made possible due to the fundamental flexibility and lightweight nature of composite membranes. Membrane structures are often referred to as textile structures. However, the actual membrane construction is far removed from the classic tent. The main difference is its exact geometric shape. For the functioning of the membrane structure, the exact geometric criteria must be computed. The basic criterion is to maintain the concavity and convexity of the main directions of the membrane surface. Following this principle, we can talk about the basic four types of membranes:

2 We think it important to explore new trends in lightweight constructions, among which we

1. saddle-shaped (hyperbolic paraboloid)

can include: Value of shape function varies from 0 to1, sum of all shape functions is 1

2. ridge-valley shape

1. Lightweight designs designed with regard to sustainability

3. arch shape

2. Modular light constructions

4. conical shape,

N1  N2  1

Shape function = 1 at its node, =0 at all other nodes 3. Sliding light constructions u  5 mm of simple structures, such as an "umbrella" that u  see N1  uthe N2  u 2 of mass production Designers 1  benefits

has reproducible components. Savings from a modular strategy lead to cost-effective

Lightweightstructures structures Lightweight Lightweight Lightweightstructures structures


307

Sabah Shawkat ©

Lightweight structures Lightweight structures


308 248

Lightweight structures Architects and engineers are executives of services to reap the intellectual property of previous

constructions. The clients' demands are high nowadays, there is a demand for temporary,

generations. They are studying, improving and discovering. They are the creators of new

transformable solutions that can offer sliding lightweight constructions ranging from simple

spaces, forms and structures that are constantly improving. This creative activity connects

sliding marquee solutions to staircases, which disappear by pressing the button (Khalifa

architects and engineers on their way to the art of "Prof. Frei Otto.

International Stadium). Tensile integrity systems are being developed today for NASA and

Lightweight structures used in various forms and variations can be seen in broad spectrum use

form unprecedented options for blame.

on the current market. These structures, developed over the years, together with advances in

Talking about modern systems of steel, wire and membrane has its merit. And that these

material engineering and technology, continue to progress and are now an integral part of

systems are at the top of the current building options. Limits are given by the physical properties

architectural creation.

and laws of the material and the construction system. These must be fully taken into account

Architectural lightweight structures can now be seen in different shapes and sizes. They may

and used in the creation of the modern system. In practice, we most often encounter the

be internal, external, permanent, temporary, large, small, supported, membranes filled with air

following issues:

or stretched. New subgroups of these constructions - shell structures, tensile-integrity structures - are also very current. These unique forms have played an important role in contemporary

• bars (struts) systems - stable problems of compressive and bent bars,

architecture, interior design and various cultural events since the time they first appeared in the

• cables systems - prestress, stiffness of the structure, necessity of solving the theory II. order,

1960s by the world-famous German architect and engineer Frei Otto.

• membrane systems - prestress, dynamic resistance, large deformation solutions.

Sabah Shawkat ©

At present, light constructions are designed and constructed independently of the geographic

location. They transform the space and have so subtle and elegant quality. In addition to

providing basic functions such as shading and shutdown, they are an important and functional element in the construction of amphitheatres, sports stadiums, airports, courtyards, building facades, parks, seafront and interiors.

Designing lightweight constructions to meet all criteria is a complex task. Every part is visible and constructive, relying on the proper functioning of all parts. For example, diaphragm fabrics are developed to meet the requirements for high tensile strength, long life with a high modulus of elasticity. The surface layer applied to the material ensures fabric resistance against weathering and dirt, provides resistance to UV radiation and has non-combustible properties.

Tensile membrane architecture is a highly sophisticated medium that offers unique qualities for architects, designers and engineers therefore provides unlimited opportunities for design as well as experiment with form and create alternative solutions to every day design challenges. This is made possible due to the fundamental flexibility and lightweight nature of composite membranes. Membrane structures are often referred to as textile structures. However, the actual membrane construction is far removed from the classic tent. The main difference is its exact geometric shape. For the functioning of the membrane structure, the exact geometric criteria must be computed. The basic criterion is to maintain the concavity and convexity of the main directions of the membrane surface. Following this principle, we can talk about the basic four types of membranes:

We think it important to explore new trends in lightweight constructions, among which we

1. saddle-shaped (hyperbolic paraboloid)

can include:

2. ridge-valley shape

1. Lightweight designs designed with regard to sustainability

3. arch shape

2. Modular light constructions

4. conical shape,

3. Sliding light constructions Designers see the benefits of mass production of simple structures, such as an "umbrella" that has reproducible components. Savings from a modular strategy lead to cost-effective

Lightweightstructures structures Lightweight Lightweight Lightweightstructures structures


309

Literature

[1]

[14] Lewis, W.J. - Tension Structures — Form and Behaviour, Thomas Telford Ltd, London, 2003

Adriaenssens, S., Block, P., Veenendaal, D., Williams, C. - Shell structures for architecture: Form finding and optimization, Routledge, 2014

[15] Nouri-Baranger, T. – Computational methods for Tension-Loaded Structures, Arch. Comput. Meth. Engng. Vol. 11, 2, 143-186, 2004

[2]

Argyris, J. H., Angelopoulos, T., Bichat, B. - A general method for the shape finding of lightweight tension structures, Comput. Meth. Appl. Mech. Engng 3, 135-149 1974

[16] P. Block, J. Ochsendorf - Thrust network analysis: a new methodology for threedimensional equilibrium, Journal of the International Association for Shell and Spatial Structures 48 (3) (2007) 167–173

[3]

Barnes, M.R. - Form-finding and analysis of tension space structures by dynamic relaxation: Ph.D. thesis, City University, London, 1977

[4]

E. Ramm, K.U. Bletzinger, R. Reitinger - Shape optimization of shell structures, IASS Bull. 34, 103–121, 1993

[5]

[17] P.G. Smith, E.L. Wilson - Automatic design of shell structures, ASCE Journal of Structural Division (1971) 191–201. [18] Scheck, H.-J. - The force density method for form finding and computation of general networks. In Computer Methods in Applied Mechanics and Engineering, Vol. 3, pages 115–134, 1974

E. Ramm – Shape finding of concrete shell roofs, Journal of International Association for Shell and Spatial Structures, IASS, Vol. 45, n. 144, pages 29-39, 2004

[6]

[7]

Haber, R.B., Abel, J.F. - Initial equilibrium solution methods for cable reinforced membranes, Part I and II. Computers Methods in Applied Mechanical Engineering, 30, 263–289 et 285–30, 1982

[8]

K. Ishii, Membrane Structures in Japan, SPS Publ. Co., Tokyo, 1995

[9]

Kilian, A., Ochsendorf, J. - Particle-spring systems for structural form finding, Journal of the International Association for Shell and Spatial Structures, IASS, Vol. 46, n. 147, 2005

[19] Tabarrok, B., Qin, Z. - Nonlinear Analysis of Tension Structures, Computers and Structures, Vol. 45, No. S/6, pp. 913-984, 1992

Sabah Shawkat ©

G. N. Vanderplaats - Multidisciplinary design optimization. Vanderplaats Research & Development, Inc., 2007

[10] K.U. Bletzinger, M. Firl, J. Linhard, R. Wüchner - Optimal shapes of mechanically motivated surfaces. In Computer Methods in Applied Mechanics and Engineering, 2008 [11] K.U. Bletzinger, R. Wüchner, F. Daoud, N. Camprubi - Computational methods for form finding and optimization of shells and membranes. In Computer Methods in Applied Mechanics and Engineering, Vol. 194, pages 3438–3452, 2005 [12] K.U. Bletzinger – Structural Optimization, Lecture Notes, TU Munich, 2014 [13] K.-U. Bletzinger, E. Ramm - Structural optimization as tool for shape design, in: C. Hirsch, et al., (Eds.), Numerical Methods in Engineering '92, Elsevier, Amsterdam, New York, 1992, pp. 465–477

Lightweight structures Lightweight structures


Sabah Shawkat ©

Lightweight Steel Structures ©

Assoc. Prof. Dipl. Ing. Sabah Shawkat, MSc, PhD. 1. Edition 2019 Published by Tribun EU, s.r.o. Cejl 892/32 Brno tel.: +420 543210089 ISBN 978-80-263-1458-5 Printed in Czech Republic


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