Estudo do sinal - BioS

Page 1

ESTUDO DO SINAL Professor: Arist贸teles


f

g

f = x + 2  x + 2 = 0  x = -2 a=1 g = 2x - 1  2x - 1 = 0  x = 1/2 a=2

Estudo do sinal de f.g: c.a m.a -2 + + + + + + + + + + f: c.a m.a 1/2 + + + + g: f.g :

+ -2

- 1/2

+

S = { x  IR; x < -2 ou x > 1/2} Obs: f.g > 0


Estudo do sinal de f.g.h: f

g

h

c.a m.a 2/3+ + + + + + + + + f: c.a m.a -1 + + ++ + + + + + + + + + g: c.a m.a 3 - - - + + + + + + + + + + + + h:

f = 3x - 2  3x - 2 = 0  x = 2/3 a=3 g = x + 1  x + 1 = 0  x = -1 a=1 h =3-x 3-x=0 x=3 -1 - 2/3 + + f.g.h : a = -1

f.g.h < 0  S = { x  IR; -1 < x < 2/3 ou x > 3}

3

-


f

g

f = 3x + 1  3x + 1 = 0  x = -1/3 a=3 g = 2x - 5  2x - 5 = 0  x = 5/2 a=2

Estudo do sinal de f.g: c.a m.a -1/3 - + + ++ + + + + + + + + + f: c.a m.a 5/2 + + + + g: -1/3 5/2 + + f.g:

f.g  0  S = { x  IR; x  -1/3 ou x ≥ 5/2}


f

g

c.a m.a 95 95 - - - - - - - - - 3 + + + 3+ + + f:  f: 80 m.a c.a-3/2 80 +++-3/2 + + + + + + + + + + + ++ + + + + g:  g:


3+++ f: 95

-3/2

80

g : ++++ + + ++ + + + + 95 80

f.g: 95 80

-

-3/2

- 3

+

f . g < 0 S = { x  IR; x < 3 e x  -3/2}


3x  4 3x  4 3x  4  2(1  x) 2 2 0 0 1 x 1 x 1 x f

3x  4  2  2 x 5x  2 0 0 1 x 1 x

Estudo do sinal de f/g:

f = 5x + 2  5x + 2 = 0 x = -2/5 a=5

c.a m.a 1 g : +++++++ + + + - - -

g

g = 1 - x  1 - x  0 x  1 a = -1

c.a m.a -2/5 f : - - - - + + ++ + + + +

f.g:

-

-2/5

f / g  0  S = { x  IR; x  -2/5 ou x > 1}

+

1

-


g

f

3x  2   x  3 4x  1 1 x 4  x3 x4  2x  1 1 x 2 -1/2

f: g:

1/4

f  g:

1/4 -1/2 -1/2

1/4

f  g = { x  IR; -1/2  x  1/4}


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