Education 03-10-2018

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11

What is the original average age of..

N. Vinaykumar Reddy Director, IACE, Hyderabad.

Model Questions 1. A and B invest some amount of money in the ratio 5:6 for same period in a business. At the end of the year, they decided to donate 25% of the profit to a temple. Out of remaining 80% was to be reinvested and the rest of the profit was divided in the ratio of their capital. If the difference in their share is Rs. 2200. Find the profit. (Approx.) a) Rs. 154000 b) Rs. 262000 c) Rs. 116000 d) Rs. 161333 e) Rs. 141542 2. A class has certain number of students and teachers. If one teacher having age of 33 years is added, the average age of the class will increase by 1 year and

Key & Solutions 1) d; Let the profit be Rs. 100.

Amount left after donation = 75 Amount left after investment 75 ×

20 = 15 100

Now again, Let the amount investment = Rs X.

left

after

6X 5X − = 2200.

11 11

X = 24200.

15% of total profit = amount left after investment Total profit = 24200 ×

100 = 161333.33 15

2) c; Given, Let number of students and teachers be y and the original average age of the class be x years.

So, the total age of the class = xy years.

If one teacher having age of 33

f¯]lÆý‡ÌŒæ çÜtyîl‹Ü & C…yìlĶæ$¯Œæ íßæçÜtÈ 1. f™èlç³Æý‡^èl…yìl. gê¼™é-I a) Ð]l*â¶æÑM>W²Ñ${™èl… b) §ólÒ ^èl…{§ýlVýS$ç³¢… c) çßæÝë¢Ä¶æ¬Æó‡Ó§ýl… d) Ëçœ$gê™èlMýS gê¼™é-II i) ÑÔ>Q§ýl™èl$¢yýl$ ii) çœËM>ç³Å iii) Ð]lÆ>çßæÑ$íßæÆý‡$yýl$ iv) M>ã§éçÜ$ 1) a-i, b-ii, c-iii, d-iv 2) a-iv, b-i, c-ii, d-iii 3) a-iii, b-iv, c-i, d-ii 4) a-ii, b-iii, c-iv, d-i

if one teacher having age of 38 years is removed, the average age of the class will decrease by 2. What is the original average age of the class? a) 28 years b) 30 years c) 24 years d) 36 years e) None of these Directions (Q.No.3-5): There are 3 bags containing 3 colored balls - Red, Green and Yellow.

Bag 1 contains: 24 green balls. Red balls are 4 more than blue balls. Probability 4 of selecting 1 red ball is 13

Bag 2 contains:

7

Total balls are 8 more than 13 of balls in bag 1. Probability of selecting 1 red ball is 1/3. The ratio of green balls to blue balls is 1:2 Bag 3 contains: Red balls equal total number of green and blue balls in bag 2.

Green balls equal total number of years is added, the average age of the class will increase by 1 year.

So, xy + 33 = (x+1)(y+1) ⇒ xy + 33 = xy + x + y + 1 ⇒ x + y = 32 ……(i) And, if one teacher having age of 38 years is removed, the average age of the class will decrease by 2.

Then, xy − 38 = (x − 2)(y − 1) ⇒ xy − 38 = xy − x − 2y + 2 ⇒ x + 2y = 40 ….(ii) Multiplying eq.(i) by 2, we get 2x + 2y = 64 ….(iii) Subtracting eq.(ii) from eq.(iii), we get 2x + 2y − x − 2y = 64 − 40 ⇒ x = 24 ∴ The original average age of the class = 24 years.

3) d; Let red = x, so blue = x −4 x

4

So (24 + x + ( x − 4)) = 13 Solve, x = 16 So bag 1: red = 16, green = 24, blue = 12 NEXT:

IBPS PO Prelims Quantitative Quantitative al i c e Aptitude Aptitude Sp

useful for

All Bank Exams

green and red balls in bag 2.

Probability of selecting 1 blue 3 ball is 14

3. 1 ball each is chosen from bag 1 and bag 2, What is the probability that 1 is red and other blue?

15 128 17 c) 135 16 e) 109

21 115 25 d) 117

a)

b)

4. Some green balls are transferred bag 2: total = 8 +

7 × 52 = 36 13

green and blue = y and 2y. Let red balls = z So z + y + 2y = 36........(i) 1 Now Prob. of red = 3 z 1 So 36 = 3

Solve, z = 12 From (1), y = 8 So bag 2: red = 12, green = 8, blue = 16 NEXT: bag 3: red = 8+16 = 24, green = 12+8 = 20 Blue prob. = So

3 14

a 3 = (24 + 20 + a) 14

Solve, a = 12 So bag 3 : red = 24, green = 20, blue = 12 Now probability that 1 is red and other blue:: 16 16 12 12 25 × + × = 52 36 52 36 117

from bag 1 to bag 3. Now probability of choosing a blue ball from bag 3 becomes 3/16. Find the number of remaining balls in bag 1. a) 60 b) 58 c) 52 d) 48 e) 44 5. Green balls in ratio 4:1 from bags 1 and 3 respectively are transferred to bag 4. Also 4 and 8 red balls from bags 1 and 3 respectively.

Now probability of choosing gre en ball from bag 4 is

5 . Find the 11

number of green balls in bag 4? a) 12 b) 15 c) 10 d) 9 e) 11 6. Verma has a total of Rs. 24,000.

And in that, he lends Rs. 6,000 at 7/ % per annum simple interest 2 and Rs. 8,000 at 6% per annum simple interest. He lends the remaining money at a certain rate of interest so that he gets total annual interest of Rs. 3200 at the end of a year. The rate of interest per annum, at which the remain4) e; blue balls in bag 3 are 12 Let x green balls are transferred.

So 12 3 = 56 + x 16

[56 was number of

balls in bag 3 before transfer] Solve, x = 8 So remaining number of balls in bag 1 = 52 − 8 = 44 5) c; 4x and x = 5x green balls 4 + 8 = 12 red balls So

5x 5 = 5 x + 12 11

Solve, x = 2 5 × 2 = 10 green balls 6) b; For first loan SI

PNR 6000 × 7 ×1 = × 2 = 210 100 100

For Second loan = 8000×6/100 = 480 Total interest = 3200 So, for the third loan SI =3200 − (480 + 210) = 2510 Rate of interest for third loan

ing money is lent, is (Approx.)? a) 10% b) 25% c) 15% d) 30% e) 22% Directions (Q. No. 7-11): What approximate value should come in place of question mark (?) in the following questions?

7. ?% of ( (15.85)× 25.02 + 219.85) = 224.11 a) 50 b) 45 c) 80 d) 70 e) 60 8. 2171 ÷ 14 + 24.03 × 4.97 = ? a) 175 b) 275 c) 325 d) 450 e) 225 9. ( 499 × 12.0 2) ÷ (443) + 1.992 =?2 a) 9 b) 37 c) 17 d) 13 e) 27 10. 59.98% of 599.85 × 0.801 + 92 = ? a) 144 b) 272 c) 380 d) 108 e) 94 11.

(15.88 × 7 + 52.05 + 13 × 7.01) = ?

a) 40 d) 16

b) 32 e) 8

2510 ×

c) 24

100 = 25.1% ≈ 25% 10000

7) d; ?% of ( (15.85)× 25.02 + 219.85) = 224.11 or,

? × (4 × 25 + 220) = 224 100

or, ? × 320 ≈ 224 ×100 ∴? ≈

224 × 100 = 70 320

8) b; ? = 2171 ÷ 14 + 24.03 × 4.97 ≈ 2170 ÷ 14 + 24 × 5 ≈ 155 + 120 = 275 9) c; ?2= ( 499 ×12.0 2) ÷ (443) + 1.992 ≈ (500 × 12) ÷ 21+ (2)2 ≈ 285+4 = 289 ∴ ? = √289 = 17 10) c; ? = 59.98% of 599.85 × 0.801 + 92 ≈ 60% of 600 × 0.801 + 92 ≈ 288 + 92 = 380 11) d; ? = (15.88 × 7 + 52.05 + 13 × 7.01) =

16 × 7 + 52 + 13 × 7 ≈ 256 ≈ 16

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OÐðlG-‹Ü-B-ÆŠ‡ h-ÌêÏ l º$«§ýlÐéÆý‡… l AMøtºÆŠæ l 3 l 2018

10

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18

3

yìl; 3 ⇒ 32 = 9, 92 = 81, 812 = 6561 M>ºsìæt ? Ý릯]l…ÌZ 9 Ð]lçÜ$¢…¨. yìl; 22 × 2 = 44, 22 + (2 × 7) = 36 11 × 2 = 22, 11 + (1 × 7) = 18 44 × 2 = 88, 44 + (4 × 7) = 72 ∴ M>ÐéÍÞ¯]l çÜ…QÅ 88 yìl; 4 G§ýl$Æý‡$V> 40 ⇒ 4 “ 10 = 40 9 G§ýl$Æý‡$V> 90 ⇒ 9 “ 10 = 90 20 G§ýl$Æý‡$V> ⇒ 20 “ 10 = 200 ∴ M>ÐéÍÞ¯]l çÜ…QÅ 200 íÜ; 13 + 19 = 32 = 8

5.

**

16

5.

20 × 6 = 120; 20 × 5 = 100 G; A + F = 1 + 6 = 7 C + H = 3 + 8 = 11 D + K = 4 + 11 = 15 C¨ 7, 11, 15 .. Æý‡*ç³…ÌZ E…¨. A…sôæ JMýS Üç …QÅMýS$ 4 MýSÍí³™ól ™èlÆ>Ó™èl çÜ…QÅ Ð]lÝù¢…¨. ™èlÆ>Ó™èl Æ>ÐéÍÞ¯]l çÜ…QÅ 19.

I ¯]l$…_ Ð]l*{™èlÐól$ 9+10 = 19 Ð]lÝù¢…¨.

J yìl; A = 1, E = 5 ⇒ 5 – 1 = 4 H = 8, N = 14 ⇒ 14 – 8 = 6 T = 20, L = 12 ⇒ 20 – 12 = 8 8 ™èlÆ>Ó™èl 10 Æ>ÐéÍ. Bç³¯Û l] Ï ¯]l$…_ O = 15, E = 5 ⇒ 15 – 5 = 10. M>ºsìæt çÜÐ]l*«§é¯]l… O. ¼; 6 + 2 + 3 + 2 = 13 132 → 169 & 1 = 168 (Ð]l$«§ýlÅÌZ¨) 5 + 1 + 2 + 3 = 11 112 → 121 & 1 = 120 (Ð]l$«§ýlÅÌZ¨) 3 + 5 + 4 + 2 = 14 142 → 196 & 1 = 195 ∴ M>ÐéÍÞ¯]l çÜ…QÅ 195

2)

1) B

A B

T H 50

C

B A

MìS…¨ {†¿¶æ$gêM>Æý‡ ç³rtMýS… ABCD¯]l$ 3) 4) ¡çÜ$Mø…yìl. §é° Ð]lÊyýl$ Ð]l¬RêË$ ADB, C B A C ABC, ACD˯]l$ Ð]lÆý‡$çÜV> 3B, 1V, 2IË™ø çÜ*_õÜ¢, ¯éË$Vø Ð]l¬QOÐðl$¯]l 13. MìS…¨ ÐésìæÌZ AÆý‡¦Ð]l…™èlOÐðl$¯]l AÐ]l$ÇMýS? BCDMýS$ Ü ç Ç´ùÄôæ$ JMýS Üç *_MýS H¨? a) AMýSÆý‡×îæĶæ$ çÜ…QÅË$ D b) ç³NÆ>~…M>Ë$ c) ÐéçÜ¢Ð]l çÜ…QÅË$ 3B A 2I d) çÜçßæf çÜ…QÅË$ 1V C B çÜOÆð‡¯]l fÐéº$¯]l$ G…í³MýS ^ólĶæ$…yìl.

60

70

80

90

90

96

100 106 112 119

94

104 111 118 127 137

98

114 123 133 144 157

100 119 124 141 154 168

17.

EÚù~{VýS™èl 98°FV> E¯]l²ç³#µyýl$, ™ólÐ]l$ÌZ çÜVýSr$ Ð]l*Æý‡$µ Æó‡r$:

1) 1.4 3) 1.075 18. ™ólÐ]l$ 80%V>

2) 1.50 4) 1.75

E¯]l²ç³#µyýl$ EÚù~{VýS™èlÌZ çÜVýSr$ Ð]l*Æý‡$µ Æó‡r$:

Byýl$™èl*

2) 44 4) 40 V¯]l$ Byýl° 2) 4 4) 6

çÜÐ]l*«§é¯éË$

2) 3;

5 × 10 10 × 20 = 25 : = 100 : 2 2 15 × 26 30 × 15 = 115 : = 225 2 2

3) 2; 4 × 5 × 6 − 7 × 8 = 64 3 × 4 × 5 − 6 × 7 = 18 5 × 6 × 7 − 8 × 9 = 138 4) 1; 5. 4; 4 × 3 × 2 = 24 5 × 7 × x = 140 ⇒ x = 4

2 2 2

ѧéÅÆý‡$¦Ë

2

= 4 × 2 ×2 = 16 17) 3; 98o F =

157 − 114 43 = = 1.075 90 − 50 40

18) 2; 80%  →

(19-22)

154 − 112 42 = = 4.2 100 − 90 10

F

C

20

x 30 5 x 8 25 V

100 − (20 +8 +5+25 +30) = 100 − 88 − 12 F+C =

12 = 6; C + V = 6 2

19) 4; 20) 3; 21) 2; 22) 4

10

 3,  2018- 

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   �� �   �. �   ��  � �.  � �  �.  � .. 569� .

  ‘’ ? 

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  (370-398) �

 �,  �� ‘��’  .   �.

  (398-440) �

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      

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�� ��. ��  �   ��. � � �  ‘�’ �. � �� � ( �) � �� �. ��  �� � �  � � ,  � � �. � � � �� �  (��)� �.  ‘    ’   .  ��  � � � �,  ��   �  �� �.   �  11 , 16 �� �� �.  ‘�’     ‘�� ’  � ��.  � �� �.   ,    ��.  �,  � �� �  �  �.

  � �

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   (510-525) � �

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� � �.  ‘ � � �� ’  �� .  ‘�’  .  � �� � ,  �� ��.

   (525-555) � �

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    �.  �� � �  �  �. �� �  ‘’ �� �.  � � (�) �   

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 �� � ��.   �� ��, �� �, � ��� �.   -    -   ���     . �, �  � �.  -    -    ��- �    � �� , , � �� (),  ��� �. �, ��  � �� �, �, ��, , �, �,� �� ��, , �,  �  � �  � .   � �   �� �  ��  ... � � �.  ��  � � � ��� ��.   ��   � � �� ��.  ��,  �  .  �   � �. � � � �� �� �  � �. �� �   � . �� � �� � � �� �.  �� � ‘� ’   � � ��.  �  ��.  (�� �� )  ��.

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�� � � �  �� . ��� � �� ��� �. �� � ��   ‘� �’ �� . � �� ��  �� �.

 

1.   ?

1) �� 2) � 3) � 4) �  2.     ?

1) �� 2) � 3) � 4) � 3. ,      ?

1) � 2)  3) � 4) �-3 4.   ?

1) � 2) � 3)  4)  5.         ?

1) � 2) � � 3)  4)  6.      ?

1)  2)  3)  4)  7.      ?

1)  2) � 3)  4) � 8.           ?

1) � 2) � �  3)  � 4)  9.        ?

1) ��� 2) �� 3) �� 4) �� 10.     ?

1)  2) � 3)  4) � 1-1, 7-3,

2-2, 8-2,

 3-3, 9-1,

4-4, 5-2, 10-4

6-1,

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 3,  2018- 

Find the values of x and y STATISTICS

B.Laxminarayana Maths Senior Faculty Hyderabad 9849386253

10th Class Special 4 MARKS QUESTIONS

2 MARKS QUESTIONS

1 MARK QUESTIONS

PRACTICE QUESTIONS

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Eligibility: Graduate or post- graduate candidates with proven academic excellence planning to pursue Ph.D. for three years, M.Sc. or M.Litt. for two years, or any one year post- graduate course offered by the university can apply for the call.

Prizes & Rewards: Scholar will be provided university composition fee, 17,500 dollers for 12 months as maintenance allowance, one economy class airfare at beginning and end of the course, inbound visa costs and immigration health charges.

m) H√s¡T _) JsêíX¯j·T+ dæ) ∫qïù|>∑T &ç) ô|<ä›ù|>∑T 11. ª|æ‘êÔX¯j·T+µ (Gall blader)@ nej·Te+˝À uÛ≤>∑+? m) #·s¡à+ _) yÓT<ä&ÉT dæ) ø±˝Òj·T+ &ç) ø√¢eT+ 12. ÄVü‰s¡+ n‘·´~Ûø£+>± @ uÛ≤>∑+˝À Js¡íeTe⁄‘·T+~? m) H√s¡T _) JsêíX¯j·T+ dæ) ∫qïù|>∑T &ç) ô|<ä› ù|>∑T 13. ô|’‘·´s¡dü+ e\¢ Js¡íeTj˚T´ |ü<ës¡ú+? m) ø=e⁄«\T _) |æ+&ç|ü<ës¡ú+ dæ) Ábı{°Hé\T &ç) ô|’y˚Mø±e⁄ 14. ªm+≥]ø˘ »«s¡+µ @ nej·TyêìøÏ dü+ã+~Û+∫+~? m) ∫qïù|>∑T _) ø±˝Òj·T+ dæ) ø√¢eT+ &ç) #·s¡à+ 15. ªnMT_j·÷dædtµ @ nej·Tyêìï Á|üuÛ≤$‘·+ #˚düTÔ+~? m) ô|<ä›ù|>∑T _) ø±˝Òj·T+ dæ) ∫qïù|>∑T &ç) ø√¢eT+ 16. ªø£ìu≤*»+µ (dü«C≤‹ uÛÑø£åD)qT Á|ü<ä]Ù+#˚ J$? m) >∑TÁs¡+ _) sê#·Hê>∑T dæ) m\Tø£ &ç) |æ*¢ 17. M{Ï˝À ø°≥ø±Vü‰s¡ yÓTTø£ÿ (ÇHÓ‡øϺy√s¡dt)? m) f…ø√ºHê _) Á&Üdæsê dæ) nqø±]¶j·T+ &ç) nC≤&çs¡ø±º 18. nMT_j·÷dædt (&ûôd+Á{°) yê´~Û ø£*–+#˚ ø±s¡ø£+? m) u≤´ø°º]j·÷ _) yÓ’s¡dt dæ) Áb˛{ÀCÀyê &ç) •©+Á<Ûä+ 19. ø£˝sê yê´~Û ø±s¡ø£+? m) u≤´ø°º]j·÷ _) yÓ’s¡dt dæ) Áb˛{ÀCÀyê &ç) •©+Á<Ûä+ 20. ø=e⁄«\qT Js¡í+ #˚ùd m+C…’yéT? m) ô||æ‡Hé _) ≥j·T*Hé dæ) nyÓTÆ˝ÒCŸ &ç) ˝…’ù|CŸ 21. øÏ+~ yê{Ï˝À <ä+‘ê\T ˝Òì Je⁄\T? m) #˚|ü\T _) ø£|üŒ dæ) ‘êuÒ\T &ç) bÕeTT\T 22. <ä+‘ê\ô|’ ªmHê$T˝Ÿµ Äs√>∑´+>± @s¡Œ&É&ÜìøÏ Last Date to apply: October 10, 2018 Application: Applications can be made online only and 500 words statement is also expected by the candidate on about their fit with the Gates Cambridge programme.

Website Link:

http://www.b4s.in/nava/GCG1

Inlaks Fine Arts Awards Category: Talent Based Scholarship: Inlaks Fine Arts Awards 2019 Description: The award intends to complement talented and budding artists who are recent graduates, postgraduates or final year students of visual arts, by financially assisting them so as to help them perform independently, anywhere in India Eligibility: Applicants below 30 years of age as on Dec 31, 2018, non-recipient of similar, government scholarship or award during the same period. In case, the applicant is not holding a formal degree in visual arts then he or she must have participated in an organized art

‘√&ÉŒ&˚ eT÷\ø£+? m) ø±*¸j·T+ _) bòÕdüŒ¤s¡dt dæ) ◊s¡Hé &ç) bò˛¢]Hé 23. e÷qe⁄&ç J$‘· ø±\+˝À ˇø£ÿkÕ] e÷Á‘·y˚T @s¡Œ&˚ <ä+‘ê\T? m) ≈£î+‘·ø±\T _) s¡<äìø£\T dæ) nÁ>∑#·s¡«Dø±\T &ç) #·s¡«Dø±\T 24. M{Ï˝À neX‚wü nej·Te+? m) C≤„q<ä+‘ê\T _) ñ+&É÷ø£+ dæ) s¡<äìø£\T &ç) ô|’e˙ï 25. M{Ï˝À neX‚wü nej·Te+? m) ø£|üŒ _) #˚|ü dæ) |üøÏå &ç) bÕeTT 26. øÏ+~ yê{Ï˝À ªs¡T∫µ>± |ü]>∑DÏ+#·ì~? m) r|æ _) #˚<äT dæ) ñ|ü⁄Œ &ç) ø±s¡+ 27. ª»sƒ¡s¡ ìs¡ZeT dü+e]Dϵ øÏ+~ e´edüú˝À uÛ≤>∑+>± ñ+≥T+~? m) s¡ø£ÔÁ|üdüs¡D _) XÊ«dü dæ) Hê&û &ç) Js¡í 28. »sƒ¡s¡ s¡dü+˝À ñ+&˚ ªôV’≤Á&√ø√¢]ø˘ ÄeT¢+µ (HCI) $~Û?

1. ÄVü‰s¡+˝Àì dü÷ø£åàJe⁄\qT HêX¯q+ #˚j·T&É+ 2. ô||æ‡Hé m+C…’yéTqT ñ‘˚Ôõ‘·+ #˚j·T&É+ 3. »sƒ¡s¡ s¡kÕìøÏ ÄeT¢ \ø£åD+ ø£*– ñ+&É&É+

kÕÿ\sYwæ|t\T exhibitions.

Prizes & Rewards: Awardees will be given cash prize if INR 3 Lacs for a year and an opportunity to attend an art residency programme within India for a period of four weeks during the course period.

Last Date to apply: October 08, 2018 Application: Interested candidate can send an online application via email to: gladys@inlaksfoundation.org Website Link: http://www.b4s.in/nava/IFA4

Facebook Fellowship Category: Research Based Scholarship: Facebook Fellowship Program 2018 Description: This call is open for students pursuing full time PhD in the field of computer science and engineering like Applied Statistics, AR/VR Photonics and Optics, Computational Social Science, Compute Storage and Efficiency,

m) 1 _) 3 dæ) 1, 2 &ç) 1, 2, 3 29. ªô||æ‡Héµ y˚{Ïì Js¡í+ #˚düTÔ+~?

1. |æ+&ç|ü<ësêú\T 2. ø=e⁄«\T 3. πø+Á<äø£ Äe÷¢\T 4. Áb˛{°Hé\T m) 1 _)1, 2 dæ) 1, 2 , 4 &ç) 4 30. ˝≤˝≤»\+˝À ñ+&˚ m+C…’yéT? 1. ˝…’k˛C…’yéT 2. ≥j·T*Hé 3. ô||æ‡Hé m) 1 _) 2 dæ) 1, 3 &ç) 1, 2 31. M{Ï˝À ªkÕ+–«y√s¡Héµ Je⁄\T @$?

1. »\>∑ 2. q‘·Ô 3. <√eT m) 1 _) 1, 3 dæ) 1, 2 &ç) 2, 3 32. M{Ï˝À |üP‹ø±Vü‰s¡T\T? 1. <√eT 2. •©+Á<Ûë\T 3.á>∑˝≤sê« m) 1 _) 1, 2 dæ) 2, 3 &ç) 1, 3

düe÷<ÛëHê\T 1.&ç 6._ 11.dæ 16._ 21.dæ 26.&ç 31._

2.&ç 7.m 12.dæ 17._ 22.&ç 27.&ç 32.dæ

3.dæ 8.dæ 13.&ç 18.dæ 23.&ç 28.&ç

4.m 9.&ç 14.m 19.m 24.&ç 29.&ç

5.&ç 10.&ç 15.m 20.&ç 25._ 30.&ç

Economics and Computation, Machine Learning, Networking and Connectivity, UX/Instagram Well-being etc. from a recognized university.

Eligibility: Students who are involved in an ongoing research related to one or more above-mentioned disciplines are considered eligible. Students need to be enrolled during the academic year when the fellowship is awarded.

Prizes &Rewards: Selected students will be privileged with tuition fee for two years or four semesters, one time payment of USD 37,000 as a research grant during each academic year, travel support of up to USD 5000 and paid visit to Facebook headquarters for the annual Fellowship Summit.

Last Date to apply: October 12, 2018 Application: Online application submission is required along with a 250word research summary describing the applicant s research.

WebsiteLink:

http://www.b4s.in/nava/FFP3 Courtesy: www.buddy4study.com / Call: 08448709545, 08527484563

10

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.

Q–ö˛$√Ö ∑ ∫$´ßÊ˛–ÈΔÊˇÖ 3 AM¯t∫ΔÊˇ$ 2018

www.andhrajyothy com

sÏ˝Gã‹Ì≥Gã‹Ì‹ {Vʸ*ã≥&4 –˛*yÊ˛Ãå˝ ı≥Á≥Δäˇ

(∞Ø˲≤sÏ˝ Á‹tyÓ˛ ô˲ΔÊˇ$–ÈΔˇ$$) 81. B{ı‹tÕƒÊ˝*ÃZ AÜÚ≥ßÊ˛™ Gô˲¢Δˇ$$Ø˲ Á≥ΔÊˇ”ô˲ ’QΔÊˇÖ GMʸPyÊ˛$Ö®?

G) J›Îfi Á≥ΔÊˇ”ôË˛Ö º) E{ßëãã≥ Á≥ΔÊˇ”ôË˛Ö Ì‹) {∫*ã‹ Á≥ΔÊˇ”ôË˛Ö yÏ˛) MˆÌ‹-ƒÊ˝*›˘P Á≥ΔÊˇ”ôË˛Ö 82. E{M¸Δˇ$$ب˛ÃZ∞ ∞M¯¥ÎÃå˝ ∞ÑÛ¸¥ÎÃZœ Mϸ֮–ÈsÏ˝ÃZ EØ˲≤®?

G) –ö˛*Ö-Vʸ-±ã‹ º) {M¯-–˛$Oså˝ Ì‹) M>Á≥Δäˇ yÏ˛) ∞-M¸Ãå˝ 83. Mʸ$ب˛À*ب˛ Á≥ΔÊˇ”ôÈÀ$, BÕب˛ ô˲Vä¸ –ö˛$´ßÊ˛≈ {¥ÎÖôÈ∞≤ H–ö˛$ÖsÍΔÊˇ$?

G) –ö˛$Ö-V¯-Õ-ƒÊ˝$-ب˛ Ô≥uÊˇ-øÊ˝*—$ º) kÖVÛ¸-«-ƒÊ˝$-ب˛ Áfl˝«-–È◊˝Ö Ì‹) ô˛Oµ-ßÊ˛–í˛$ Áfl˝«-–È◊˝Ö yÏ˛) sÍ«–í˛$ Áfl˝«-–È◊˝Ö 84. B{ÌúM>ÃZ Gô˲¢Δˇ$$Ø˲ Á≥ΔÊˇ”ôË˛Ö ı≥ΔÊˇ$?

G) M>-–˛$-ΔÊˇ*-ب˛ Á≥ΔÊˇ”ôË˛Ö º) MϸÕ-–ö˛$Ö-gÍΔ¯ Á≥ΔÊˇ”ôË˛Ö Ì‹) GÃZœ-Vʸ-ب˛ Á≥ΔÊˇ”ôË˛Ö yÏ˛) M¸ØÈ≈ Á≥ΔÊˇ”ôË˛Ö 85. AÀ›ÎPÃZ {∫*Mä¸fi, AÀ›ÎP {‘Û˝◊˝$À –ö˛$´ßÊ˛≈ EÖyÛ˛ EØ˲≤ô˲ øÊ˝*—$∞ H–ö˛$ÖsÍΔÊˇ$?

G) ∫ñÁfl˝-ô¨˛ Áfl˝«-–È◊˝Ö º) ı‹≤Mä¸ MˆÀÖ-ºƒÊ˝* Ô≥uÊˇ-øÊ˝*—$ Ì‹) Mˆ-ÀÖ-ºƒÊ˝* Ô≥uÊˇ-øÊ˝*—$ yÏ˛) ƒÊ˝$*-Mʸ-ب˛ Ô≥uÊˇ-øÊ˝*—$ 86. Á‹$Ô≥«ƒÊ˝$Δäˇ Á‹ΔÊˇÁ‹$fi {¥ÎÖôË˛Ö –ö˛$$Q≈ÖV> Mϸ֮–ÈsÏ˝ÃZ ßÛ˛∞∞ MʸÕW EÖ®?

G) ô˲-Vʸ-ΔÊˇÁ≥# ´ßëô˲$–ö˛#º) –˛$OM> £ëô˲$–ö˛# Ì‹) C-Ø˲$Á≥ ´ßëô˲$–ö˛# yÏ˛) ªÍ-M¸Ofiså˝ £ëô˲$–ö˛# 87. ÃÍsÏ˝Ø¨˛ A–˛$«M>ÃZ Aô˲≈Öô˲ fØ˲›ÎÖ{ßÊ˛ô˲ EØ˲≤ ßÛ˛‘Ë˝Ö?

G) ÁúN≈-Δ¯t-«M> º) {ªÒ˝-hÃå˝ Ì‹) Á≥ØÈ–ö˛* yÏ˛) –˛$-MϸfiM¯ 88. Mϸ֮ ßÛ˛∞ÃZ gÍMʸΔäˇ, G{ªZ Ø˲ßÊ˛$À$ øÍVʸÖ?

G) –˛$yÏ˛-sÙ˝-«-ƒÊ˝$-ب˛ Á≥«-–È-Áfl˝Mʸ –ö˛≈–ö˛Á‹¶ º) ªÍÕtMä¸ Á≥«-–È-Áfl˝Mʸ –ö˛≈–ö˛Á‹¶ Ì‹) AsÍœÖ-sÏ˝Mä¸ –ö˛$‡-Á‹-–ö˛$${ßÊ˛ Á≥«-–È-Áfl˝Mʸ –ö˛≈–ö˛Á‹¶ yÏ˛) Eô˲¢ΔÊˇ Á‹–ö˛$$-{ßÊ˛Á≥# Á≥«-–È-Áfl˝Mʸ –ö˛≈–ö˛Á‹¶ 89. B{ı‹tÕƒÊ˝*ÃZ∞ H Δ>ÁŸâÖÃZ A´®Mʸ AØ˲$¥ÎôË˛Ö {V>“$◊˝ fØÈøÍ EÖ®?

G) Ú≥Δäˇ¢ º) BÖ-sÏ˝-–˛$$∞ Ì‹) rÖ-Vä¸-Á‹t-ب˛ yÏ˛) hÖMä¸ 90. ô˲*ΔÊˇ$µ BÌ‹ƒÊ˝*ÃZ –¯Ãå˝{Áú–ö˛*så˝ ßÛ˛∞ {Á≥´ßëØ˲ ´ßëô˲$–ö˛#?

G) –ö˛*ÖVʸ-±Á‹$ º) BÖsÏ˝-–˛$$∞ Ì‹) rÖVä¸-Á‹t-ب˛ yÏ˛) hÖMä¸ 91. ßÊ˛Ñϸ◊˝&ô˲*ΔÊˇ$µ BÌ‹ƒÊ˝*ÃZ Ì‹ƒÊ˝*Ö Ô≥uÊˇøÊ˝*—$ –Û˛sÏ˝ –ö˛$´ßÊ˛≈ EÖ®?

G) Á‹Œ”-ب˛, –˛$M>ÖVä¸ –ö˛$´ßÊ˛≈ º) Ì‹sÍtÖVä¸, –˛$ØÈ–í˛$ Ø˲ßÊ˛$À –ö˛$´ßÊ˛≈ Ì‹) –˛$ØÈ–í˛$, –˛$M>ÖVä¸ Ø˲ßÊ˛$À –ö˛$´ßÊ˛≈ yÏ˛) C{ΔÊˇ-–ÈyÏ˛, Ì‹sÍtÖVä¸ Ø˲ßÊ˛$À –ö˛$´ßÊ˛≈ 92. ÃÍÖyä˛ Bãú ô˙fÖyä˛ ÃÙ˝Mä¸fi EØ˲≤®?

G) CÖV>œÖyä˛ º) ÌúØÈœÖyä˛ Ì‹) M¸Ø˲yë yÏ˛) Mˆ«ƒÊ˝* 93. øÍΔÊˇô˲ gÍ°ƒÊ˝$ M>Ö{V¸ã‹ ΔˇÖyÊ˛$V> H Á‹Ö–ö˛ô˲fiΔÊˇÖÃZ `ÕÖ®?

G) 1907 º) 1908 Ì‹) 1909 yÏ˛) 1910 94. 2018ÃZ ›Î”ô˲Ö{ô˲≈ ®Ø¯ô˲fi–È∞≤ ⁄ÎÔfl˝ßä˛ Á‹–ö˛*√ب˛ ®–ö˛ã‹V> {Á≥MʸsÏ˝Ö_Ø˲ Δ>ÁŸâÖ H®?

G) E-ô˲¢ΔÊˇ {Á≥ßÛ˛-‘¨˝ º) –ö˛$-´ßÊ˛≈-{Á≥-ßÛ˛-‘¨˝ Ì‹) Á≥ÖgÍªå˝ yÏ˛) Δ>f-›Î¶-ب˛ 95. Eô˲¢ΔÊˇ{Á≥ßÛ˛‘¨˝ÃZ∞ –˛$$VʸÃå˝ Á‹Δ>ƒå˝$ fÖÑʸب˛Mʸ$ A´®M>«MʸÖV> H ı≥ΔÊˇ$Ø˲$ {Á≥MʸsÏ˝Ö^ÈΔÊˇ$?

G) ©Ø¨˛-ßÊ˛-ƒÊ˝*-Ãå˝ E¥Î-´ßë≈ƒÊ˝$ º) ArÃå˝ º‡» –Ègå˝-ı≥Δˇ$$ Ì‹) A∫$™Ãå˝ MʸÃÍÖ yÏ˛) H©-M>ßÊ˛$ 96. Go What that ı≥ΔÊˇ$ô¯ ∏˘Ø¨˛ÃZØÛ˛ r*«fÖ V¸Oyä˛Ø˲$ ßÛ˛‘Ë˝ÖÃZØÛ˛ –˛$$ßÊ˛sÏ˝ ›Î«V> H Ø˲VʸΔÊˇÖÃZ B—ÁŸP«Ö^ÈΔÊˇ$?

G) …Ï˛Œœ º) B{V> Ì‹) ^˲ÖyÓ˛-Vʸ…ä˛ yÏ˛) y˛{‡-yÊ˛*-ب˛

97. BVÛ¸≤-ƒÊ˝*-Ì‹-ƒÊ˝*ÃZ –˛$$ßÊ˛sÏ˝ MʸœΔˇ$$-–Û˛$så˝ ^Û˛Ögå˝ Ú‹Ör-ΔäˇØ˲$ GMʸ$PyÊ˛ {¥ÎΔÊˇÖ-¿Ö-^ÈΔÊˇ$?

G) ÀM¯≤ º) –ö˛$±ÃÍ Ì‹) Ì‹ÖVʸ-Á≥NΔäˇ yÏ˛) ªÍÕ 98. øÊ˝Mϸ¢ EßÊ˛≈–ö˛$ ôˆÕ {Á≥^ÈΔÊˇMʸ$yÊ˛$/{Á≥Ü¥ÎßÊ˛Mʸ$yÊ˛$?

G) Δ>–ö˛*-Ø˲ÖßÊ˛ º) Δ>–ö˛*-Ø˲$f Ì‹) ØÈ–ö˛$-ßÛ˛–ö˛ yÏ˛) MʸΩΔäˇ 99. H Á‹Ö–ö˛ô˲fiΔÊˇÖÃZ øÍΔÊˇô˲ ^˛OØÈ {Á≥´ßëØ˲ –ö˛$Ö{ô˲$À$ Á≥Ö^˲÷À Á≥{ô˲ÖÚ≥O Á‹Öô˲M>À$ ^Û˛‘ÈΔÊˇ$?

G) 1954 º) 1953 Ì‹) 1952 yÏ˛) 1956 100.CÖy¯&^˛OØÈ ƒÊ˝$$ßÊ˛ÆÖ H Á‹Ö–ö˛ô˲fiΔÊˇÖÃZ f«WÖ®?

G) 1962 º) 1961 Ì‹) 1963 yÏ˛) 1964 101. 1971ÃZ ßÛ˛∞ —–ö˛$$Mϸ¢ M¯Á‹Ö ¥ÎMϸ›Î¶Ø¨˛Mʸ$ –ö˛≈ÜΔÛˇMʸÖV> øÍΔÊˇô¨˛ ¥˘sÍœyÏ˛Ö®?

G) ∫ÖV>œ-ßÛ˛-‘¨˝ º) AgÍ-ßä˛-Mʸ-÷√Δäˇ Ì‹) Ì‹ƒÊ˝*-_-ب˛ yÏ˛) Á≥NÖ^¨˛ 102. H A–˛$«M> A´ßÊ˛≈Ñʸ$yÊ˛$ Ø˲*≈yÓ˛Ãå˝ ¥ÎÀÔ‹∞ {Á≥–Û˛‘Ë˝Ú≥sÍtyÊ˛$?

G) E{y¯-—-Àfi-ب˛ º) ΔÊˇ*gå˝-–˛Ãå˝z Ì‹) A{∫Áfl˝Ö ÕÖMʸ-ب˛ yÏ˛) gÍΔäˇj –ÈÌŸÖ-Vʸt-ب˛ 103. A›˘ÖÃZ gÍ°ƒÊ˝$ ¥˚ΔÊˇ«hÁ‹tΔäˇ(Gب˛BΔäˇÌ‹) Mϸ Á‹Ö∫Ö´®Ö_Ø˲ 2–ö˛ ô˲$® –ö˛$$›ÎΔˇ$$ßëØ˲$ {Á≥øÊ˝$ô˲”Ö H Δ¯kØ˲ {Á≥MʸsÏ˝Ö_Ö®?

G) 2018 lÃÒ˝O 26 º) 2018 lÃÒ˝O 28 Ì‹) 2018 lÃÒ˝O 24 yÏ˛) 2018 lÃÒ˝O 30 104. ØțΠ2018 BVʸÁ‹$t 12Ø˲ Á‹*ΔÊˇ$≈∞Ú≥O A´ßÊ˛≈ƒÊ˝$ØË˛Ö ^Û˛ƒÊ˝$yÊ˛Ö M¯Á‹Ö —fƒÊ˝$–ö˛Öô˲ÖV> {Á≥–Û˛‘Ë˝Ú≥sÏ˝tØ˲ {Á≥ƒÒ˝*VÊ¸Ö H®?

G) B®ô˲≈ Gب˛&1 º) ¥Î-ΔÊˇ√Δäˇ {¥˘ªå˝ ›˚ΔÊˇ≈-ب˛ Ì‹) ¥Î-ΔÊˇPΔäˇ ›˘ÃÍΔäˇ {¥˘ªå˝ yÏ˛) y˛ÃÍt&4 {¥˘ªå˝ 105. 18–ö˛ ‘Ë˝ôÈ∫ÆÖÃZ A–˛$«M>ÃZ Á≥#sÏ˝tØ˲"ÕÖ_ÖVä¸" AØÛ˛ Á≥ßÊ˛Ö CsÓ˝À CÖyÏ˛ƒÊ˝*ÃZ GMʸ$P–ö˛V> —∞Ì≥›˘¢Ö®.ÕÖ_ÖVä¸ AÖsÙ˝ AΔÊˇ¶Ö?

G) A-Á‹-Áfl˝ØË˛Ö º) A-´ßë≈-Ü√-Mʸ-–ÈßÊ˛Ö Ì‹) E-{Vʸ-–ÈßÊ˛ {ı≥ΔÊˇ◊˝ yÏ˛) –ö˛$*Mʸ Áfl˝ô˲≈À$ 106. ßÛ˛‘Ë˝ÖÃZ –ö˛$*Mʸ Ìfl˝ÖÁ‹, –ö˛$*MʸÀ$ ¥ÎÀµyÛ˛ Áfl˝ô˲≈-ÀØ˲$ ∞ƒÊ˝$Ö-{ÜÖ-^˲-yë-∞Mϸ –ö˛*ΔÊˇY-ßÊ˛-ΔÊˇÿ-M>-ÀØ˲$ ΔÊˇ*¥˜Ö-®Ö^È-À∞ Ì≥sÏ˝-ÁŸØ˲$œ ßëQÀ$ ^Û˛Ì‹-Ø˲-–ÈΔÊˇ$?

G) ô˛-Áfl˝-Ô‹-ب˛ Á≥NØÈ-–ÈÃÍ º) ô˲$-⁄ÎΔäˇ V>Ö´© Ì‹) Δ>-i–í˛ V˙ªÍ yÏ˛) 1, 2 107. Mϸ֮-–È-sÏ˝ÃZ ı≥gå˝-ı≥Δˇ$$ {Á≥øÊ˝$ô˲” Áfl˝ƒÊ˝*ÖÃZ fΔÊˇVʸ-∞® H®?

G) Á‹”ΔÊˇ~ ^˲ô˲$-ΔÊˇ$¬h º) Á‹ΔÊˇ” ’Ñ>- A¿-ƒÊ˝*-ب˛ Ì‹) G–ö˛$-Δˇj±fi —´®ÖÁ≥# yÏ˛) 1998 ¥˘{RÍ-ب˛ A◊˝$ Á≥»-ÑʸÀ$ 108. MÛ¸Ö{ßÊ˛ ÁflZÖ–ö˛$Ö-{Ü-ô˲”-‘ÈQ CsÓ˝-–ö˛À —yÊ˛$-ßÊ˛À ^Û˛Ì‹Ø˲ gÍ°ƒÊ˝$ —Á≥ô˲$¢ Á‹*`ÃZ –˛$$ßÊ˛sÏ˝ ΔˇÖyÊ˛$ ›Î¶ØÈÃZœ ∞Õ-_Ø˲ Δ>⁄Îâ-ÃÙ˝—?

G) –ö˛$-‡-Δ>ÁŸâ, MÛ¸ΔÊˇ‚Ê˝ º) –ö˛$‡-Δ>ÁŸâ, Á≥’a-ªÒ˝Ö-V>Ãå˝ Ì‹) MÛ¸ΔÊˇ‚Ê˝, MʸΔ>~-rMʸ yÏ˛) Á≥-’a-ªÒ˝Ö-V>Ãå˝, MÛ¸ΔÊˇ‚Ê˝ 109. –ö˛$Áfl˝-ßëΔˇ$$ Ø˲© fÃÍÀ —–ÈßÊ˛Ö H Δ>{⁄ÎtÀ –ö˛$´ßÊ˛≈ Ø˲yÊ˛$-›˘¢Ö®?

G) Mʸ-Δ>~-r-Mʸ&-V¯-–È&-–ö˛$-‡-Δ>ÁŸâ º) Mʸ-Δ>~-r-Mʸ&-V¯-–È&-ô˲-—$-‚Ê˝-ØÈyÊ˛$ Ì‹) –ö˛$-‡-Δ>-ÁŸâ&-Mʸ-Δ>~-r-Mʸ&-–ö˛$-´ßÊ˛≈-{Á≥-ßÛ˛‘å˝ yÏ˛) MʸΔ>~-r-Mʸ&-–ö˛$-‡-Δ>-ÁŸâ&-BÖ-{´ßÊ˛-{Á≥-ßÛ˛‘å˝ 110. D‘ÈØ˲≈ Δ>{⁄ÎtÃZœ Á≥«-{‘Ë˝-–ö˛$À A¿-–ö˛ñ-®ÆMϸ EßÛ˛™-’Ö_Ø˲ D‘ÈØ˲≈ Δ>⁄ÎâÀ ¥Î«-{‘È-—$Mʸ A¿-–ö˛ñ®™ Á≥£Ê˛M>∞≤ MÛ¸Ö{ßÊ˛Ö GÁ≥µ-sÏ˝-–ö˛-ΔÊˇMʸ$ ¥˜yÏ˛-WÖ-_Ö®?

G) 2019 º) 2022 Ì‹) 2020 yÏ˛) 2024 111. ∫Áfl˝-–ö˛$± Δ>f≈Ö —_e-Ø˲≤Öô¯ 1526ÃZ G∞≤ Á‹$ÃÍ¢-ØÛ˛r$œ HΔÊˇµ-yëzΔˇ$$?

G) 3 º) 4 Ì‹) 5 yÏ˛) 2 112. ÚflO˝ßÊ˛-Δ>-ªÍßä˛ Ø˲VʸΔÊˇ ›Î¶Á≥-Mʸ$yÊ˛$?

G) “Δäˇ –ö˛$Áfl˝-–ö˛$√ßä˛ Á‹Δˇ$$≈ßä˛ º) A∫$™ÃÍœ Mʸ$ô˲$ªå˝ ⁄Î Ì‹) –ö˛$Áfl˝-–ö˛$√ßä˛ Mʸ$Œ Mʸ$ô˲$-ªå˝⁄Î yÏ˛) ⁄Î AªÍæã‹ 113. –ö˛*ßÊ˛Ø˲≤, AMʸPØ˲≤ V¯ÃZPÖyÊ˛ “´ßÊ˛$ÃZœ H Á‹Ö–ö˛-ô˲fiΔÊˇÖÃZ Áfl˝ô˲≈Mʸ$ Vʸ$ΔÊˇ-ƒÊ˝*≈ΔÊˇ$?

G) 1672 º) 1675

Ì‹) 1686 yÏ˛) 1688 114. "ßÊ˛ {Á‹tVʸ$Ãå˝ Bãú –˛$O ÃÒ˝Oãú" Á≥#Á‹¢Mʸ ΔÊˇ^˲-Δˇ$$ô˲?

G) Ø˛{Áfl˝î º) Ü-ÀMä¸ Ì‹) –ö˛$Ö-yÛ˛ÃÍ yÏ˛) ªÍ-ب˛ MÓ¸ –ö˛$*ب˛ 115. "–ö˛*ب˛-Á‹*-ب˛' AØÛ˛ Á≥ßÊ˛Ö H øÍÁŸ Ø˲$Ö_ –ö˛_aÖ®?

G) {XMä¸ º) A-ΔÊˇ-ºMä¸ Ì‹) ÃÍ-sÏ˝-ب˛ yÏ˛) Á‹Ö-Á‹PñôË˛Ö 116. "ßÊ˛ Ìfl˝ÖßÊ˛*' BÖVʸœ ®Ø˲-Á≥-{ÜMʸ Á‹Ö¥Î-ßÊ˛-Mʸ$yÊ˛$?

G) M>-–Û˛« ∫–í˛$gÒ˝O º) B-Δäˇ.-—-fƒÊ˝$ ‘Ë˝ÖMʸΔäˇ Ì‹) G.-sÏ˝.-f-ƒÊ˝$ÖÜ yÏ˛) –ö˛$$Mʸ$Ößä˛ Á≥ßÊ˛√-ØÈ-øÊ˝Øå˛ 117. ô˛À$Vʸ$ ®Ø˲-Á≥-{ÜMʸ "Ø˲–ö˛$ı‹¢ ô˛ÀÖ-V>◊˝' Á‹Ö¥Î-ßÊ˛Mʸ$yÊ˛$?

G) M¸.-{÷-∞-–Èã‹ º) MʸsÍt ‘Û˝QΔäˇ ΔˇyÏ˛z Ì‹) GÖ.—.-‘ÈÌ‹à yÏ˛) yÏ˛.›Î-Δˇ$$-ªÍªÍ 118. V>Ö´©i AÖô˲-Δ>ô˲√ ΔÊˇÑʸ-Mʸ$-yÏ˛V> G–ö˛-«∞ Ì≥Õ-^Û˛–ÈΔÊˇ$?

G) Ì‹.-Δ>-f-V¯-¥ÎÀ ^È« º) ΔÊˇ“Ö-{´ßÊ˛-ØÈ£ä˛ u>Vʸ*Δäˇ Ì‹) —.Á≥-sÙ˝Ãå˝ yÏ˛) h.M¸.-V¯-QÃÙ˝ 119. ªÒ˝ÖV>Ãå˝ —øÊ˝-f-Ø˲Ø˲$ {ºsÏ˝ãŸ {Á≥øÊ˝$ô˲”Ö EÁ≥-Á‹Ö-Áfl˝«Ö-^˲$-MˆØ˲≤ Á‹Ö–ö˛-ô˲fiΔÊˇÖ?

G) 1919 º) 1917 Ì‹) 1914 yÏ˛) 1911 120. Δ˙À-ô¨˛ ^˲rtÖ A–ö˛$-ÃZœMϸ –ö˛_aØ˲ Á‹Ö–ö˛-ô˲fiΔÊˇÖ?

G) 1931 º) 1919 Ì‹) 1920 yÏ˛) 1942 121. ∫ÖMϸÖ-^˲Ö{ßÊ˛ b˲sZ-¥Î-´ßë≈ƒÊ˝$ BØ˲Ö-ßÊ˛-–ö˛$-uäˇØ˲$ ΔÊˇ_Ö-_Ø˲ Á‹Ö–ö˛-ô˲fiΔÊˇÖ?

G) 1858 º) 1892 Ì‹) 1882 yÏ˛) H-©-M>ßÊ˛$ 122. GØ˲$-–ö˛*-–ö˛$$À –ö˛*ΔˇPså˝ GMʸPyÊ˛ EÖ®?

G) f-Ø˲-V>–ö˛$ º) Ø˲-Àœ-VˆÖyÊ˛ Ì‹) –ö˛-ΔÊˇÖ-VʸÃå˝ yÏ˛) Á‹*-Δ>≈-ı≥r 123. B«¶Mʸ gÍ°-ƒÊ˝$-–È-ßë-∞Mϸ –ö˛$*À-Á≥#-ΔÊˇ$-ÁŸ$-∞V> Vʸ$«¢ÖÁ≥# ¥˜Ö®-Ø˲-–ÈΔÊˇ$?

G) º-Ì≥-ب˛ ^˲Ö{ßÊ˛-¥ÎÃå˝ º) º.-V¯-QÃÙ˝ Ì‹) BΔäˇ.-Ì‹.-ßÊ˛-ô¨˛ yÏ˛) –ö˛$-ßÊ˛-ب˛-–˛*-Áfl˝-ب˛ –ö˛*À-“ƒÊ˝$ 124. 1921 –˛*¥Îœ ÜΔÊˇ$-Vʸ$-ªÍr$ Ú≥À$œ-º-MϸØ˲ {¥ÎÖô˲Ö?

G) A›ÎfiÖ º) MÛ¸-ΔÊˇ‚Ê˝ Ì‹) Á≥Ö-gÍªå˝ yÏ˛) ªÒ˝Ö-V>Ãå˝ 125. øÍΔÊˇ-ô˲-ßÛ˛-‘È-∞Mϸ ›Î”ô˲Ö{ô˲≈Ö –ö˛_a-Ø˲-Á≥#µyÊ˛$ M>Ö{V¸ã‹ A´ßÊ˛≈-Ñʸ$yÊ˛$?

G) GÖ.-M¸.-V>Ö´© º) f-–ö˛-Áfl˝-Δäˇ-ÃÍÃå˝ Ø˛{Áfl˝î Ì‹) gÒ˝.-º.-Mʸñ-Á≥-ÃÍ∞ yÏ˛) Á‹-Δ>™Δäˇ Á≥sÙ˝Ãå˝ 126. VʸßÊ˛Δäˇ ¥Î»t {Á≥´ßëØ˲ M>Δ>≈-ÀƒÊ˝$Ö EØ˲≤ Ø˲VʸΔÊˇÖ?

G) –ö˛*›˘P º) ªÒ˝-«œ-ب˛ Ì‹) ‘È-ب˛-{∏Î-∞fi-›˘P yÏ˛) Mʸ-Δ>_ 127. Mϸ֮-–È-«ÃZ –ö˛$*yÊ˛$ Δ˙Öyä˛ sÙ˝∫$Ãå˝ Á‹–ö˛*-–Û˛-‘ÈÃZœØ˲* ‡f-ΔˇO-Ø˲-–ÈΔÊˇ$?

G) º.-BΔäˇ. AÖªÙ˝-ßÊ˛PΔäˇ º) GÖ.-GÖ.-–ö˛*-À-“ƒÊ˝$ Ì‹) –ö˛-Àœøå˝ ø̓å˝$ Á≥sÙ˝Ãå˝ yÏ˛) G–ö˛ΔÊˇ* M>ßÊ˛$ 128. øÍΔÊˇô˲ ›Î”ô˲Ö{ô˲≈ ¥˘Δ>-rÖÃZ "—f-ƒÊ˝$–˛* ÃÙ˝ßë –ö˛$ΔÊˇ-◊˝–˛*' AØÛ˛ ‘Ë˝Mϸ¢-–ö˛$Ö-ô˲-–˛$OØ˲ ∞ØÈßÊ˛Ö C_a-Ø˲–ÈΔÊˇ$?

G) V>Ö´© º) Ø˛{Áfl˝î Ì‹) Ü-ÀMä¸ yÏ˛) Á‹$-øÍã-Ÿ-^˲Ö-{ßÊ˛-ªZã‹ 129. H ^˲rtÖ {Á≥M>ΔÊˇÖ –˛$$ßÊ˛-sÏ˝-›Î« G∞≤-MʸÀ$ ∞ΔÊˇ”Ìfl˝Ö-^ÈΔÊˇ$?

G) CÖ-yÏ˛-ƒÊ˝$-ب˛ M˙∞fiÃå˝ ^˲rtÖ 1909 º) øÍΔÊˇô˲ {Á≥øÊ˝$ô˲” ^˲rtÖ 1919 Ì‹) 1935 ^˲rtÖ yÏ˛) øÍΔÊˇô˲ ›Î”ô˲Ö{ô˲≈ ^˲rtÖ 1947 130. øÍΔÊˇ-ô˲-ßÛ˛-‘Ë˝ÖÃZ BÖV>œ∞≤ –˛$$ßÊ˛-sÏ˝-›Î-«V> {Á≥–Û˛-‘Ë˝Ú≥-sÏ˝tØ˲ Vʸ–ö˛-ΔÊˇ≤Δäˇ fØ˲-ΔÊˇÃå˝?

G) ÃÍΔäˇz MʸΔÊˇj-ب˛ º) ÃÍΔäˇz –˛$M>ÃÒ˝ Ì‹) ÃÍΔäˇz ªÒ˝ÖsÏ˝ÖVä¸ yÏ˛) ÃÍΔäˇz ıfl˝Ì‹tÖVä¸fi 131. V>Ö´©i –˛$$ßÊ˛r Á‹ôÈ≈-{VʸÁfl˝ EßÊ˛≈-–ö˛*∞≤ GMʸPyÊ˛ {¥ÎΔÊˇÖ-¿Ö-^ÈΔÊˇ$?

G) ^˲Ö-¥Î-ΔÊˇ-ب˛ º) ªÍ-Δ¯zÕ Ì‹) ßÊ˛ÖyÏ˛ yÏ˛) ∫-Δ¯yë 132. 1942 Mϸ”så˝ CÖyÏ˛ƒÊ˝* EßÊ˛≈-–ö˛$ÖÃZ ØÈΔˇ$$-MʸV> G–ö˛-«∞ Ì≥Õ-^Û˛-–ÈΔÊˇ$?

G) yë-MʸtΔäˇ A∞-Ω-Ú‹Öså˝ º) Á‹$^Û˛ôÈ MʸñÁ≥-ÃÍ∞ Ì‹) A-ΔÊˇ$◊ä˝ AÁ‹ãú AŒ yÏ˛) Á‹Δ¯-f± ØÈƒÊ˝$$yÊ˛$

133. øÍΔÊˇ-ô˲-ßÛ˛-‘Ë˝ÖÃZ H Δ>ÁŸâÖ –˛$$ßÊ˛sÏ˝ øÍ⁄Î-ƒÊ˝$$Mʸ¢ Δ>ÁŸâÖV> Vʸ$«¢ÖÁ≥# ¥˜Ö®Ö®?

G) Á≥-’a-ªÒ˝Ö-V>Ãå˝ º) BÖ-{´ßÊ˛-{Á≥-ßÛ˛-‘¨˝ Ì‹) ô˲-—$-‚Ê˝-ØÈyÊ˛$ yÏ˛) Á≥Ö-gÍªå˝ 134. Mϸ֮-–È-sÏ˝∞ fô˲-Á≥-ΔÊˇaÖyÏ˛ 1) ∞‘Ë˝ÿ∫™Ö ´ßÊ˛”∞ °{–ö˛ô˲ G.15yÏ˛º 2) Vʸ$Á‹-Vʸ$Á‹ ´ßÊ˛”∞ °{–ö˛ô˲ º.16yÏ˛º 3) ›Î´ßë-ΔÊˇ◊˝ Á‹ÖøÍ-ÁŸ◊˝ ´ßÊ˛”∞ °{–ö˛ô˲ Ì‹.0yÏ˛º 4) ô˲$¥ÎMϸ ı≥À$yÊ˛$ ´ßÊ˛”∞ °{–ö˛ô˲ yÏ˛.140yÏ˛º G) 1&G, 2&º, 3&Ì‹, 4&yÏ˛ º) 1&Ì‹, 2&G, 3&º, 4&yÏ˛ Ì‹) 1&yÏ˛, 2&G, 3&Ì‹, 4&º yÏ˛) 1&Ì‹, 2&º, 3&G, 4&yÏ˛ 135. Mϸ֮-–È-sÏ˝∞ fô˲-Á≥-ΔÊˇaÖyÏ˛ 1) Á‹–ö˛$-ô˲À ßÊ˛ΔÊˇµ◊˝Ö G.¥ÎΔÊˇÿ” —ÃZ–ö˛$Ö 2) Á≥#sÍ-M>ΔÊˇ ßÊ˛ΔÊˇµ◊˝Ö º.D-G-ب˛-sÏ˝ yëMʸtΔÊˇ$œ 3) Mʸ$ÖøÍ-M>ΔÊˇ ßÊ˛ΔÊˇµ◊˝Ö Ì‹.«-ƒÊ˝$-Δ䡖ö˛N≈ —${ΔÊˇΔäˇ 4) —$£ë≈ {Á≥Ü-ºÖ∫Ö yÏ˛.ô˛-ΔÊˇ-“$ßÊ˛ Á≥rtÃÙ˝Ö G) 1&G, 2&º, 3&Ì‹, 4&yÏ˛ º) 1&yÏ˛, 2&º, 3&Ì‹, 4&G Ì‹) 1&G, 2&Ì‹, 3&º, 4&yÏ˛ yÏ˛) 1&yÏ˛, 2&Ì‹, 3&º, 4&G 136. Mϸ֮-–È-sÏ˝ÃZ Á‹«-M>∞ fô˲?

G) —-ßÊ˛$≈-ô¨˛ –˛*rΔäˇ & –˛$ORÙ˝Ãå˝ ∏ÎΔÊˇyÛ˛ º) —ßÊ˛$≈-ô¨˛ fØ˲-ΔÛˇ-rΔäˇ & –˛$ORÙ˝Ãå˝ ∏ÎΔÊˇyÛ˛ Ì‹) —ßÊ˛$≈-ô¨˛ &—ÕƒÊ˝$Ö ∫Δäˇzfi yÏ˛) Ú≥O–Û˛“ M>–ö˛# 137. KyÊ˛À –Û˛V>∞≤ ØÈså˝À$ ÃÙ˝ßë ØÈsÏ˝-MʸÃå˝ –˛$O‚Ê˝œÃZ MˆÀ$-›Î¢ΔÊˇ$. AΔˇ$$ôÛ˛ JMʸ ØÈså˝?

G) 1.652/Mϸ.-“$./VʸÖ. º) 1.852/Mϸ.-“$./VʸÖ. Ì‹) 1.452/Mϸ.-“$./VʸÖ. yÏ˛) 1.952/Mϸ.-“$./VÊ¸Ö 138. Mϸ֮-–È-sÏ˝∞ fô˲-Á≥-ΔÊˇaÖyÏ˛ 1) BV>j-ÕMä¸ B–ö˛$œÖ G.Ì‹-Δ>-–ö˛$-ΔÊˇ-MʸÀ$ ôˆÀ-WÖ-^˲yÊ˛Ö 2) A–˛*√-∞ƒÊ˝$Ö ÚflO˝{yë-M¸Ofiyä˛ º.{X-k-–ö˛$-ΔÊˇ-MʸÀ$ ôˆÀ-WÖ-^˲yÊ˛Ö 3) Ø˲{Ü-M>–ö˛$œÖ Ì‹.ı≥-À$yÊ˛$ ¥˚yÊ˛Δäˇ ô˲ƒÊ˝*» 4) M>Õ¤ƒÊ˝$Ö ÚflO˝{yë-M¸Ofiyä˛ yÏ˛.Ωœ-_ÖVä¸ ¥˚yÊ˛Δäˇ ô˲ƒÊ˝*» G) 1&G, 2&º, 3&Ì‹, 4&yÏ˛ º) 1&º, 2&G, 3&Ì‹, 4&yÏ˛ Ì‹) 1&G, 2&º, 3&yÏ˛, 4&Ì‹ yÏ˛) 1&yÏ˛, 2&Ì‹, 3&º, 4&G 139. Mϸ֮-–È-sÏ˝∞ fô˲-Á≥-ΔÊˇaÖyÏ˛?

1.GÌ‹-sÏ˝Mä¸ B–ö˛$œÖ G.r-–ö˛*r, ¥ÎÀ-Mʸ*ΔÊˇ 2.ÃÍMϸtMä¸ B–ö˛$œÖ º.∞–ö˛$√ ØÈ«Öf 3.Ì‹{sÏ˝Mä¸ B–ö˛$œÖ Ì‹.–˛-∞-VʸΔäˇ 4.BV>j-ÕMä¸ B–ö˛$œÖ yÏ˛.Ú≥-ΔÊˇ$Vʸ$ G) 1&G, 2&º, 3&Ì‹, 4&yÏ˛ º) 1&Ì‹, 2&yÏ˛, 3&G, 4&º Ì‹) 1&Ì‹, 2&yÏ˛, 3&º, 4&G yÏ˛) 1&º, 2&yÏ˛, 3&G, 4&Ì‹ 140. GÀ-M>â-ب˛ —ßÊ˛$≈-ßë-–Û˛‘Ë˝ Á≥«-–ö˛*◊˝Ö e = G) 1.602x10 C º) 1.602x10 C Ì‹) 1.602x10 C º) 1.602x10 C 141. Mϸ֮-–È-sÏ˝ÃZ Á‹«-M>-∞® H®?

G) ô˛-Àœ∞ M>ÖÜ ——´ßÊ˛ ΔÊˇÖVʸ$-À$V> —yÏ˛-¥˘-–ö˛-yë∞≤ M>ÖÜ —ÑÛ¸-Á≥◊˝Ö AÖsÍΔÊˇ$ º) Fßë-ΔÊˇÖVʸ$ M>ÖÜ —^˲-ÀØË˛Ö GMʸ$P–ö˛, GΔÊˇ$–ö˛# ΔÊˇÖVʸ$ M>ÖÜ —^˲-ÀØË˛Ö ô˲Mʸ$P–ö˛ Ì‹) Fßë-ΔÊˇÖVʸ$ M>ÖÜ ô˲ΔÊˇÖ-Vʸ-ß˛OΔÊˇÉ≈Ö ô˲Mʸ$P–ö˛, GΔÊˇ$Á≥# ΔÊˇÖVʸ$ M>ÖÜ ô˲ΔÊˇÖ-Vʸ-ß˛OΔÊˇÉ≈Ö GMʸ$P–ö˛ yÏ˛) GΔÊˇ$-Á≥#-ΔÊˇÖVʸ$ –ö˛{MÓ¸-øÊ˝-–ö˛Ø˲ Vʸ$◊˝MÊ¸Ö GMʸ$P–ö˛, FßëΔÊˇÖVʸ$ –ö˛{MÓ¸-øÊ˝-–ö˛Ø˲ Vʸ$◊˝MÊ¸Ö ô˲Mʸ$P–ö˛ 142. Mϸ֮-–È-sÏ˝∞ fô˲-Á≥-ΔÊˇaÖyÏ˛ 1. MʸÖÁ≥Ø˲ Á≥«-—$Ü G.Úfl˝-ΔäˇtjÀ$ 2. ¥˚Ø˲@-Á≥#Ø˲≈Ö º.¥Î-Á‹PÃå˝ 3. ô˲ΔÊˇÖ-Vʸ-ß˛OΔÊˇÉ≈Ö Ì‹.Ú‹-MʸØ˲$ 4. B–ö˛-ΔÊˇ¢-Ø˲-M>ÀÖ yÏ˛.“$-rΔäˇ G) 1&º, 2&G, 3&yÏ˛, 4&Ì‹ º) 1&G, 2&º, 3&Ì‹, 4&yÏ˛ Ì‹) 1&º, 2&G, 3&Ì‹, 4&yÏ˛ yÏ˛) 1&yÏ˛, 2&G, 3&º, 4&Ì‹ 143. ÚflO˝{y¯-“$-rΔäˇ ÃÙ˝ßë yÛ˛±fi-sZ-“$-rΔäˇ EÁ≥-ƒÒ˝*-WÖ_ Mϸ֮ ßÛ˛∞∞ MʸØ˲$-M¯P-–ö˛^˲$a?

G) –ö˛Á‹$¢-–ö˛#À ›ÎÖ{ßÊ˛ô˲ º) {ßÊ˛–ÈÀ ›ÎÖ{ßÊ˛ô˲ Ì‹) –ö˛Á‹$¢ {ßÊ˛–ö˛≈-Δ>’ yÏ˛) {ßÊ˛–ÈÀ Áú$Ø˲-Á≥-«-–ö˛*◊˝Ö -19

19

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The Purpose of Reading Reading Skill Reading is the most important skill at higher stages of learning. Reading means understanding what the writer has said. To understand a written text the reader should have the knowledge of morphology, syntax and semantics.

William S.Grey said 'reading is the process of sight,sound, sense'. Reading is a process of recognising the written or printed symbols.It involves accuracy in recognising letters, chunks,words, and phrases and sentences apart from summary.

The Purpose of Reading We read for different purposes like,

Reading for Pleasure ◆

It is not for learning anything, it is only for pleasure reading magazines, brochures,novels, personal letters, comics,jokes. .etc.

Scanning: It is reading for specific information. It is reading the passage quickly to search for specific information. Itis an activity in which we find and a particular piece of information.

Examples: ◆ Finding the names of character in a story, names and numbers in a telephone directory. ◆ Looking for a word in adictionary. ◆ Looking for the new words in a story. ◆ Looking for particular in a book. ◆ Looking to an index to find out a specific topic and a page number in a book. ◆ Looking for the required information of train arrival, departs. ◆ Looking for a player's individual score in a score board. ◆ Looking for a specific information like country/location/figures [inform] in maps and graphs.

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Promotes faster reading. ◆ Improves eye span. ◆ Promotes better understanding of the text. ◆ It is less tiring. ◆ Natural ◆ Gummidelli We apply this at Mahender higher stages of PGT in English learning. ◆ TSWRS/JC, Applied in reading Yellareddy. for information, reading for details, reading to answer questions, summarise,quick evaluation, to make notes...etc.

William S.Grey divided the methods of teaching reading into twocategories. Mainly 1. Synthetic method. 2. Analytical method.

1. Synthetic Methods: ◆

TGT& PGT Gurukulam Exam English Pedagogy

Reading for Survival We read bills, receipts, labels, directions, travel schedules,names of places, sign boards…etc.

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Reading for Study ◆

We read textbooks,glossaries,dictionaries,summary of the paper, biographies, charts,diagrams,graphs, reference books.etc.

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Reading for Official Purposes ◆

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We read notice boards, minutes of the meetings, business letters, circulars, reports professional journals,catalogues,workshop guidelines at work place. There is always a co-ordination between what we read and why we read.

Ability to recognise words, phrases in English script.

To use ones knowledge and experience of the world to understand and make prediction of a text.

To retrieve [get] the information presented in the passage.

To distinguish the main ideas from subsidiary [secondary] ideasto get theinformation.

To understand /guess the meanings of unknown words.

To recognise discourse markers liketherefore, however, that is. etc.

To understand the relations with in the sentence and text.

To make notes.

To get the gist of the passage.

To understand the implied informs/meaning.

To know how to use an index/table of contents.

To use/dictionarythesaurus.

To read silently and quickly.

To recognise the topic sentence.

To recognise the mood of the writer.

Strategies of Reading Skimming: It is the process of reading to get an overallidea, globalidea, thesummary or understand the passage. In the process of skimming we pick up only important points. We go through the text to get the gist of it. We do not look fordetails. Buttry to frame the overall impression of the passage.

Reading newspaper headlines, reading the table of contents, reading the abstracts given at the beginning of a research paper,etc. come under this category.

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Intensive Reading It is a process of reading for detailed examination of the text to get complete meaning or comprehend the passage completely. ◆ It is a reading based on accuracy. ◆ It involves, ability to read quickly and silently. ◆ -to comprehend the passage thoroughly. ◆ -to summarise the text. ◆ -to participate in a discussion based a reading a book. ◆ -it covers a wide range of information.

And it is higher level activity. ◆ Applied in comprehension, makingnotes, reading text books, readingquestionpaper, reading circulars and notices.

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Extensive Reading ◆

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Reading for getting information. It involves speed reading.

Applied in reading supplementary reader, storybooks, magazines, newspapers, novels. etc.

It provides a better exposure to English.

And improves word power.

Mainly used for pleasure reading.

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Loud Reading ◆ ◆ ◆

It is reading loudly.

Reading gives important to sound.

Applied to inform audience, to read minutes of the meeting, to give instructions, to make announcements,to read news, to improve reading skill, to improve pronunciation.

Silent Reading ◆ ◆

Gives important to meaning a sense.

It is reading silently without moving lips in order to know the meaning.

Advantages:

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The Alphabet Method: The learners first learn the namesof letters in the alphabetical order. The letters are combine to formsyllables, syllables to words to process, phrases to sentences The Phonic Method: It was introduced by David jones.

It believes that sounds of the letters produce words not the names of the letters.

The Syllabic Method: It uses syllabic units to teach reading skill.

Syllables are combined to form words and sentences.

The sounds of letters and syllables are taught through comparison of words.

Analytical Methods: The Word Method: It is also called 'see and say' method Introduced by Comenius.

He believed that words can be learnt easily when they are presented along with pictures.

The word is taken as the basic unit of teaching a learning.

When a word is learnt or taught the other details of the words like letters, syllables and sounds are also presented.

So it believes in picture to teach reading skill.

The Phrase Method: It believes that phases are more meaningful than words and it believes in combinations of words and phrases.

The Sentence Method: It believes that the sentence is the true unit in language.It also believes that a sentence expresses a whole thought and it offers continuity of meaning from the context.

It avoids/prevents word by word reading.

Sentence-phrase-words-syllablessounds/letters.

The Story Method: Improvised method of reading and it is a natural development of sentences in the form of a story as a unit of teaching reading.

Provides a complete unit of thought than a sentence and takes the reader through theentire series of events with beginning, middle and end.

It believes that the reading skill is developed like the following.

Story- sentence, phrases, words, syllabus, sounds/ letters.

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