π₯ 3 + ππ₯ 2 + ππ₯ + π = 0 ,
π₯ =π¦β
π¦ 3 + ππ¦ + π = 0 , π¦
π=πβ
π2 , 3
π=πβ
π
π
ππ 2π 3 + . 3 27
π¦1 , π¦2 , π¦3
π₯1 = π¦1 β
π , 3
π₯2 = π¦2 β
π , 3
π¦ 3 + ππ¦ + π = 0
π¦=π§β
π , 3π§
π π₯3 = π¦3 β . 3
π 3
π§3 β
π3 27π§ 3
+π =0
π§3 π§ 6 + ππ§ 3 β
π3 = 0. 27 π‘ = π§3
π‘ 2 + ππ‘ β
π π‘ = π§ 3 = β Β± βπ , 2
π3 =0, 27
π 2 π 3 π =( ) +( ) . 2 3
1 1 π = β + πβ3, 2 2
1 1 π2 = β β πβ3 , 2 2
π 3 π΄ = ββ + βπ , 2
π 3 π΅ = ββ β βπ , 2
π
π΄π΅ = β 3 π 3
(β 3)
π§ π΄, ππ΄, π2 π΄, π΅, ππ΅, π2 π΅. π
β3
π π΄π΅ = β , 3
π ππ΄ β π2 π΅ = β , 3
π π2 π΄ β ππ΅ = β . 3
π§
β π¦.
π 3π§
π¦=π§β
π 3π§
π¦ π¦2 = ππ΄ + π2 π΅,
π¦1 = π΄ + π΅,
π¦3 = π2 π΄ + ππ΅ ,
π 2 π3 Ξ =β , βπ = β + 4 27 108 Ξ = 4π3 + 27π2
Ξ>0
Ξ
βπ π¦1 π¦2 , π¦3 π¦1 = π΄ + π΅ , π¦2 = ππ΄ + π2 π΅ , π¦2 = π2 π΄ + ππ΅ .
Ξ<0
βπ
π¦1 = 2π , π¦2 = βπ β πβ3 , π¦2 = βπ + πβ3 . π
π 3
βπ΄ = π + ππ
Ξ=0
π π΄ = π΅ = β β2
3
βπ΅ = π β ππ
3 π π¦1 = 2ββ β2 , 3 π π¦2 = π¦3 = 2β β2 .
π=0
π₯ 3 + 6π₯ 2 + 2π₯ + 12 = 0 . π = 6, π = 2
π = 12
π2 62 π=πβ =2β = β10, 3 3
π
π
ππ 2π 3 6 β 2 2 β 63 π=πβ + = 12 β + = 24, 3 27 3 27
π¦ 3 β 10π¦ + 24 = 0 , Ξ Ξ = 4π3 + 27π2 = 4 β (β10)3 + 27 β 242 = 11552 , Ξ
βπ = β108 π¦1 π¦2 , π¦3
3 π 24 2888 3 β108 + 38β6 3 π΄ = ββ + βπ = ββ + β =β , 2 2 27 9
3 π 24 2888 3 β108 β 38β6 π΅ = ββ β βπ = ββ β β =β . 2 2 27 9 3
3 β108 + 38β6 3 β108 β 38β6 π¦1 = π΄ + π΅ = β +β = β4 . 9 9
3 3 1 1 β108 + 38β6 1 1 β108 β 38β6 π¦2 = ππ΄ + π2 π΅ = (β + πβ3) β + (β β πβ3) β , 2 2 9 2 2 9 1 1 = (1 β πβ3)(6 β β6) + (1 + πβ3)(6 + β6) , 6 6 = 2 + πβ2 . 3 3 1 1 β108 + 38β6 1 1 β108 β 38β6 π¦2 = π2 π΄ + ππ΅ = (β β πβ3) β + (β + πβ3) β , 2 2 9 2 2 9 1 1 = (1 + πβ3)(6 β β6) + (1 β πβ3)(6 + β6) , 6 6 = 2 β πβ2.
π₯ 3 + 6π₯ 2 + 2π₯ + 12 = 0 π₯1 = π¦1 β 2 = β6 , π₯2 = π¦2 β 2 = πβ2 , π₯3 = π¦3 β 2 = βπβ2 .