Resolução da questão 30 da página 17 da apostila do curso preparatório para o concurso da UFSM/2012.

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j)

MMC (5,4,10) = 20

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30) Sendo U = Q, resolva as equações:

)

a) 3x – 9 = 9  3x = 18  x = 6 b) x – 5 = -7  x = -7 + 5  x = -2 c) y – 6 = 5y + 8 y – 5y = 8 + 6  - 4y = 14 (-1)

k)

MMC (2,4) = 4

4y = -14 

d) 10x = 20 + 9x 10x – 9x = 20  x = 20 e) 5 – x – 20 = 5x – 10 – 7x - x – 5x + 7x = -10 + 20 - 5 x=5

l)

MMC (5,3) = 15

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(

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f) 2(x + 3) = 30 2x + 6 = 30  2x = 24  x = 12 (-1) g) 8 – 2(x + 5) = 5 + 3(2x + 4) 8 – 2x – 10 = 5 + 6x + 12 - 2x – 2 = 17 + 6x - 2x – 6x = 17 + 2 - 8x = 19 (-1)  8x = -19  x = -19/8

 x = -14

m)

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)

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 MMC (3,6,8) = 24

h) 3(2x + 4) = 4(x + 6) 6x + 12 = 4x + 24 6x – 4x = 24 – 12 2x = 12  x = 6 i) 4x – 10(x + 1) – 2(x – 2) = 0 4x – 10x – 10 -2x + 4 = 0 - 8x – 6 = 0 - 8x = 6 (-1) 8x = -6

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n)

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twitter: @pc_bernardo ou e-mail: paulocesar2102@gmail.com | gabarito: www.issuu.com/prof_bernardo

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