VENTILATION STUDY CALCULATION Room area = LxW = 8.4 x 4.2 = 35.3 m2 = 115.8 ft3 by seventh schedule, accommodation is under purpose group vii, therefore occupant loads is 1.5 per sqm = 7.18 per sqft by third schedule, it requires 0.14m3 of air per minutes per occupants = 4.94 CFM per occupant
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No. of occupants = 115.8(room area in ft) / 7.18 = 0.294 Ventilation, CFM = 115.8 x 4.94 = 572 CFM
air conditioner
Natural Ventilation/ opening Cool Wind Hot Wind
By law, clause-39, natural ventilation minimum requirement of 5% for natural ventilation
THERMAL ZONING The area with direct sunlight zoning will gain more hear, whereas the best zone for user is the maximum illumination zone as it has moderate temperature and adequate lightings
PROFESIONAL ARCHITECT
CFM to Tons 1 Ton of Cooling = 400 CFM 1 Ton of Cooling = 12000 BTU/hr 572(ventilation, CFM) / 400 CFM = 1.43Tons 13,389,600 / 12000 BTU/hr = 1115.8 BTU/hr Cooling capacity of the air conditioner selected is 12000 BTU/hr Hence, No. of Unit Required = 115.8 / 12000 = 13,389,600 Proposed wall mounted air conditioner 1 unit of wall mounted series air conditioner is provided
UBBL
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Calculation for Natural Ventilation required = Total floor area x 5% = 35.3 m2 x 5% = 1.06 m2 Natural Ventilation provided = 2.32 m2 > (1.06m2)
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................................................ CIVIL AND STRUCTURAL ENGINEERING
