2007.13.07 Университет по архитектура, строителство и геодезия - София

Page 1

13.07.2007 . 1 f(x)= 2 2cos x − 3a.2cos x + 2a 2 , ) (2 ) (2 ) (2

) ) )

f(x)=0

a=1 f(x)=0

-

? f(x).

-

2 ,

.

1,

1

1

. ) (2

)

2,

J

2

.

) (3

) r

) (2

1,

2

γ OA , = 2sin OB2 2 OB2 .OC2 r : = = R, α β γ OA 4sin sin sin 2 2 2

1

1

J

R OA1 3 = AO 3

)

OC1 = 3 −1. OC

π π , 6

3

π 2

.

.

3 ABCDM a) (3

2ϕ .

)

) (2

)

) (2

)

ABCD, VABCDM = −2h3

,

,

cos 2ϕ 3cos 2 ϕ tg 2ϕ R= h 2

,

cos ϕ =

MN=h

3 .A 7

α α.






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